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  • Model validation with enumerations

    - by Robert Koritnik
    I'm using DataAnnotations attributes to validate my model objects. My model class looks similar to this: public class MyModel { [Required] public string Title { get; set; } [Required] public List<User> Editors { get; set; } } public class User { public int Id { get; set; } [Required] public string FullName { get; set; } [Required] [DataType(DataType.Email)] public string Email { get; set; } } My controller action looks like: public ActionResult NewItem(MyModel data) { //... } User is presented with a view that has a form with: a text box with dummy name where users enter user's names. For each user they enter, there's a client script coupled with ajax that creates an <input type="hidden" name="data.Editors[0].Id" value="userId" /> for each user entered (enumeration index is therefore not always 0 as written here), so default model binder is able to consume and bind the form without any problems. a text box where users enter the title Since I'm using Asp.net MVC 2 RTM which does model validation instead of input validation I don't know how to avoid validation errors. The thing is I have to use BindAttribute on my controller action. I would have to either provide a white or a black list of properties. It's always a better practice to provide a white list. It's also more future proof. The problem My form works fine, but I get validation errors about user's FullName and Email properties since they are not provided. I also shouldn't feed them to the client (via ajax when user enters user data), because email is personal contact data and is not shared between users. If there was just a single user reference on MyModel I would write [Bind(Include = "Title, Editor.Id")] But I have an enumeration of them. How do I provide Bind white list to work with my model?

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  • mvc presentation model best-practices

    - by Andrew Florko
    Hello, everybody How do you usually convert business objects to presentation? For example: Business object Person { Id, FirstName, LastName, Patronymic ... } should be presented as "LastName F. P. " in html layout. We use Presentation classes hierarchy to represent data ready for output from Business model. Questions: Will you keep presentation model completely separated from Business Model. For example, can strong-typed views (MVC ASP.NET) aggregate formatted business data as well as raw business objects (that leads toward <%=Html.Encode(PersonHelper.ToShort(Model.Person))% html layout injections) What architecture layer do you choose for conversion (mvc controllers that formats business data from business layer, for instance). Thank you in advance

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  • Custom Validation Attribute with Custom Model Binder in MVC 2

    - by griegs
    I apologise for the amount of code I have included. I've tried to keep it to a minimum. I'm trying to have a Custom Validator Attribute on my model as well as a Custom Model binder. The Attribute and the Binder work great seperately but if I have both, then the Validation Attribute no longer works. Here is my code snipped for readability. If I leave out the code in global.asax the custom validation fires but not if I have the custom binder enabled. Validation Attribute; public class IsPhoneNumberAttribute : ValidationAttribute { public override bool IsValid(object value) { //do some checking on 'value' here return true; } } Useage of the attribute in my model; [Required(ErrorMessage = "Please provide a contact number")] [IsPhoneNumberAttribute(ErrorMessage = "Not a valid phone number")] public string Phone { get; set; } Custom Model Binder; public class CustomContactUsBinder : DefaultModelBinder { protected override void OnModelUpdated(ControllerContext controllerContext, ModelBindingContext bindingContext) { ContactFormViewModel contactFormViewModel = bindingContext.Model as ContactFormViewModel; if (!String.IsNullOrEmpty(contactFormViewModel.Phone)) if (contactFormViewModel.Phone.Length > 10) bindingContext.ModelState.AddModelError("Phone", "Phone is too long."); } } Global asax; System.Web.Mvc.ModelBinders.Binders[typeof(ContactFormViewModel)] = new CustomContactUsBinder();

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  • Django anonymous user in model

    - by jack
    I have a model defined as below: class Example(models.Model): user = models.ForeignKey(User, null=True) other = models.CharField(max_length=100) The problem is Django refuses to assign django.contrib.auth.models.AnonymousUser directly to Example.user as null field so everytime I have to check if request.user.is_authenticated() ans assign Example.user = None manually. Is there a default value for AnonymousUser to use in a model field?

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  • zend framework can't find Model classes ?

    - by user284503
    Yall: I have a simple question, it might be a simple configuration issue, but I have a Model defined, and when I try to access it from a controller it fails. The Model is in the model directory, and when I look at the quickstart app, it seems like this should work. Here is my model: <?php class Application_Model_User { protected $_user; protected $_password; protected $_userId; // very simple right } ?> My controller just stops.. here is the controller code: <?php class UserController extends Zend_Controller_Action { public function init() { } public function indexAction() { // display login form $users = new Application_Model_User(); echo "test never echos.. stopped above ? weird huh.."; // fails before .. } ?> Thank you everyone,

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  • Alloy MVC Framework Titanium Network (Model)

    - by flyingDuck
    I'm trying to authenticate using the Model in Alloy. I have been trying to figure this problem out since yesterday. If anybody could help me, I'd really appreciate it. So, I have a view login.xml, then a controller login.js. The login.js contains the following function: var user = Alloy.Models.user; //my user.js model function login(e) { if($.username.value !== '' && $.password.value !== ''){ if(user.login($.username.value, $.password.value)){ Alloy.createController('home').getView().open(); $.login.close(); } }else{ alert('Username and/or Password required!'); } } Then in my user.js model, it's like this: extendModel : function(Model) { _.extend(Model.prototype, { login: function(username, password) { var first_name, last_name, email; var _this = this; var url = 'http://myurl.com/test.php'; var auth = Ti.Network.createHTTPClient({ onerror: function(e){ alert(e.error); }, onload: function(){ var json = this.responseText; var response = JSON.parse(json); if(response.logged == true){ first_name = response.f_name; last_name = response.l_name; email = response.email; _this.set({ loggedIn: 1, username: email, realname: first_name + ' ' + last_name, email: email, }); _this.save(); }else{ alert(response.message); } }, }); auth.open('POST', url); var params = { usernames: username, passwords: password, }; auth.send(params); alert(_this.get('email')); //alert email }, }); When I click on login in login.xml it calls the function login in index.js. So, now my problem is that, when I click the button for the first time, I get an empty alert from alert(_this.get('email')), but then when I click the button the second time, everything works fine, it alerts the email. I have no idea what's going on. Thank you for the help.

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  • Proper design a Model-Controller in Cocoa?

    - by legege
    Hi, I'm trying to design a simple Cocoa application and I would like to have a clear and easy to understand software architecture. Of course, I'm using a basic MVC design and my question concerns the Model layer. For my application, the Model represents data fetched on the Internet with a XML-RPC API. I'm planning to use Core Data to represent a locally fetched version. How should the data be loaded initially? I'm reading the Cocoa Design Pattern book, and they talk about a Model-Controller that is centric to the Model. How would that be done? Thanks!

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  • symfony 1.4: doctrine build model warning

    - by tigerstyle
    Hi volks, I copied my sources from my lokal dev (everything works fine) to my repository and from there I did a checkout on my remote dev. Now when I try to build everything I get this error: devel:/var/www/myproject# ./symfony doc:build-model doctrine generating model classes file+ /tmp/doctrine_schema_48726.yml Warning: file_get_contents(/var/www/myproject/lib/model/doctrine//base/BaseAdvert.class.php): failed to open stream: No such file or directory in /var/www/myproject/lib/vendor/symfony/lib/plugins/sfDoctrinePlugin/lib/task/sfDoctrineBuildModelTask.class.php on line 77 Do you know what the problem could be? Thx for your answers :)

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  • List of models in Model in MVC

    - by arri
    I have two models: class ModelIn{ public string FirstName { get; set; } public string LastName { get; set; } public string Address { get; set; } } class ModelOut{ public ModelOut(){ People = new List<ModelIn>();} public List<ModelIn> People { get; private set;} public string Country { get; set; } } And I have Controller editing ModelOut: public ActionResult People() { ... return View(SomeModelOutInstanceWith3People); } [HttpPost] public ActionResult(ModelOut m) { ... } In view I have sth like: <% using (Html.BeginForm()) { %> <%: Html.EditorFor(m => Model.Country) %> <% for(int i = 0; i < Model.People.Count; ++i){ %> <%: Html.EditorFor(m => Model.People[i].FirstName) %> <%: Html.EditorFor(m => Model.People[i].LastName) %> <%: Html.EditorFor(m => Model.People[i].Address) %> <% } %> <input type="submit" /> <% } %> It works all OK, but in post action I have empty ModelOut m. I can see in logs that data is sent correctly. I have tried everything, nothing works.

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  • Django model help

    - by dotty
    Does anyone have any clue why this doesn't work as expected. If i use the python shell and do team.game_set or team.games It returns an error AttributeError: 'Team' object has no attribute 'game' If i create a Game object and call game.home_team it returns the correct team object Heres my model class Team(models.Model): name = models.CharField(blank=True, max_length=100) class Game(models.Model): home_team = models.ForeignKey(Team, related_name="home_team")

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  • Codeigniter: Check where model is loaded from?

    - by qwerty
    I'm having the strangest thing ever right now. I "disabled" a model because i don't need to access it ever again. I did so by echoing out an error string in the __construct() and right after that die(). That way i would notice if i ever loaded the model, even by mistake, which should never happen. Alright? The problem is, the model is not loaded ANYWHERE in the entire project, but it still gets loaded for some reason. It's not auto loaded, that's for sure. Is it possible to track down where a model is loaded? Like which line it happens etc?

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  • Implementing a Cakephp Model using an Array

    - by Zubin
    The CakePHP Cookbook states that a Model can use a file (csv for example) instead of an actual database table but I couldn't find any implementation for it. I was wondering if it is possible to use an Array of data as a model in CakePHP since I have a fairly static set of data which is important to me in a relationship with another table but it doesn't make a whole lot of sense to create a complete table for it. Is it possible to implement a CakePHP Model using an Array?

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  • Error Handling in Model (MVC)

    - by Andre
    I was wondering what the excepted standard is for handling errors in the Model. Currently I have 'setError' and 'getError' methods that's in use by all my Models. This means I'm only concerned with whether a call to a method in my Model is true or false. If it's false then I would use $this-model-getError() in my Controller. Additionally I'm contemplating setting up a separate file that contains all my errors. One file per model, also wanted to have thoughts on this.

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  • Formating a date field in the Model (Codeigniter)

    - by Landitus
    Hi, I', trying to re-format a date from a table in Codeigniter. The Controller is for a blog. I was succesfull when the date conversion happens in the View. I was hoping to convert the date in the Model to have things in order. This is the Model: class Novedades_model extends Model { function getAll() { $this->db->order_by('date','desc'); $query = $this->db->get('novedades'); if($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } } return $data; } } This is part of the controller $this->load->model('novedades_model'); $data['records'] = $this->novedades_model->getAll(); Here's the date conversion as it happens in the View. This is inside the posts loop: <?php foreach($records as $row) : ?> <?php $fdate = "%d <abbr>%M</abbr> %Y"; $dateConv = mdate($fdate, mysql_to_unix($row->date)); ?> <div class="article section"> <span class="date"><?php echo $dateConv ;?></span> ... Keeps going ... How can I convert the date in the Model? Can I access the date key and refactor it?

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  • What is the difference (if any) between Html.Partial(view, model) and Html.RenderPartial(view,model)

    - by Stephane
    Other than the type it returns and the fact that you call it differently of course <% Html.RenderPartial(...); %> <%= Html.Partial(...) %> If they are different, why would you call one rather than the other one? The definitions: // Type: System.Web.Mvc.Html.RenderPartialExtensions // Assembly: System.Web.Mvc, Version=2.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 // Assembly location: C:\Program Files (x86)\Microsoft ASP.NET\ASP.NET MVC 2\Assemblies\System.Web.Mvc.dll using System.Web.Mvc; namespace System.Web.Mvc.Html { public static class RenderPartialExtensions { public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, ViewDataDictionary viewData); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, object model); public static void RenderPartial(this HtmlHelper htmlHelper, string partialViewName, object model, ViewDataDictionary viewData); } } // Type: System.Web.Mvc.Html.PartialExtensions // Assembly: System.Web.Mvc, Version=2.0.0.0, Culture=neutral, PublicKeyToken=31bf3856ad364e35 // Assembly location: C:\Program Files (x86)\Microsoft ASP.NET\ASP.NET MVC 2\Assemblies\System.Web.Mvc.dll using System.Web.Mvc; namespace System.Web.Mvc.Html { public static class PartialExtensions { public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, ViewDataDictionary viewData); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, object model); public static MvcHtmlString Partial(this HtmlHelper htmlHelper, string partialViewName, object model, ViewDataDictionary viewData); } }

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  • (Quaternion based) Trouble moving foward based on model rotation

    - by ChocoMan
    Using quaternions, I'm having trouble moving my model in its facing direction. Currently the model moves can move in all cardinal directions with no problems. The problem comes when I rotate the move as it still travelling in the direction of world space. Meaning, if I'm moving forward, backward or any other direction while rotating the model, the model acts like its a figure skater spinning while traveling in the same direction. How do I update the direction of travel proper with the facing direction of the model? Rotates model on Y-axis: Yaw = pController.ThumbSticks.Right.X * MathHelper.ToRadians(speedAngleMAX); AddRotation = Quaternion.CreateFromYawPitchRoll(yaw, 0, 0); ModelLoad.MRotation *= AddRotation; MOrientation = Matrix.CreateFromQuaternion(ModelLoad.MRotation); Moves model forward: // Move Forward if (pController.IsButtonDown(Buttons.LeftThumbstickUp)) { SpeedX = (float)(Math.Sin(ModelLoad.ModelRotation)) * FWDSpeedMax * pController.ThumbSticks.Left.Y * (float)gameTime.ElapsedGameTime.TotalSeconds; SpeedZ = (float)(Math.Cos(ModelLoad.ModelRotation)) * FWDSpeedMax * pController.ThumbSticks.Left.Y * (float)gameTime.ElapsedGameTime.TotalSeconds; // Update model position ModelLoad._modelPos += Vector3.Forward * SpeedZ; ModelLoad._modelPos += Vector3.Left * SpeedX; }

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  • import txt files using excel interop in C# (QueryTables.Add)

    - by kite
    Hi all, I am trying to insert text files into excel cell using Querytables.Add; no error, but the worksheet is empty. except for the single cell manipulation using Value2 property. I already using macro to record the object used. Can you help me on this(I am using vs2008, C# , excel 2003 and 2007; both shown empty cell). Below is my code; thanks for your help Application application = new ApplicationClass(); try { object misValue = Missing.Value; wbDoc = application.Workbooks.Open(flnmDoc, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue, misValue); wsRefDocBudgetOwner = (Worksheet)wbDoc.Worksheets[2]; Range lRange = wsRefDocBudgetOwner.get_Range("B2", "B25"); var temp2 = wsRefDocBudgetOwner.QueryTables; var temp = temp2.Add(@"TEXT;d:\temp\config ssas.txt", lRange, Type.Missing); //temp.RefreshStyle = XlCellInsertionMode.xlInsertDeleteCells; //temp.RefreshOnFileOpen = true; wsRefDocBudgetOwner.get_Range("B1", "B1").Value2 = "Lgfdgast adsffdafadfads"; wbDoc.Save(); //wbDoc.SaveAs(flnmDoc2, misValue, misValue, misValue, misValue, misValue, XlSaveAsAccessMode.xlExclusive, // misValue, misValue, misValue, misValue, misValue); wbDoc.Close(Missing.Value, Missing.Value, Missing.Value); } finally { application.Quit(); }

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  • Import / include assigned variables in Jinja2

    - by Brian M. Hunt
    In Jinja2, how can one access assigned variables (i.e. {% set X=Y %}) within files incorporated with include? I'd expect the following to work given two Jinja2 files: A.jinja: Stuff {% include 'B.jinja' -%} B has {{ N }} references B.jinja: {% set N = 12 %} I'd expect that A.jinja, when compiled with Jinja2, would produce the following output: Stuff B has 12 references However, it produces: Stuff B has references I'd be much obliged for any input as to how to access the Jinja2 variables, such as N above, in the file that includes the file where N is set. Thank you for reading. Brian

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  • How to import data in SQL Compact Edition?

    - by Peter
    I don't seem to find a tool for it, nor an odbc driver. Thanks UPDATE : I'm aware of the sql scripting possibilities. But than again : how to script a sql 2k table? (not just ddl, but data also?) Of course you can write this all by yourself, but importing data into CE cannot be such a hassle, or can it ? UPDATE2 : I don't seem to be able to choose the right dialect for inserting

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  • Import XCode project inside another XCode project

    - by bruno
    I imported an XCode project inside another XCode project. I dragged and dropped project B inside project A like in How to Call Xcode Project In Another Xcode Project.......? Next, i imported a class from project B in project A, so i could use a method but i gave me an error "ClassTemp.h' file not found". From what i´ve read this should have worked. Do i have to do some kind of configuration for it to work?

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  • How to import and export only data of whole database in access 2007

    - by DiegoMaK
    Hi, I have two identical databases with same structure, database a in computer a and database b in computer b. The data of database a*(a.accdb)* and database b*(b.accdb)* are different. then in database a i have for example ID:1, 2, 3 and in database B i Have ID:4,5,6 Then i need merge these databases data in only one database(a or b, doesn't matter) so the final database looks like. ID:1,2,3,4,5,6 I search an easy way to do this. because i have many tables. and do this by union query is so tedious. I search for example for a backup option for only data without scheme as in postgreSQl or many others RDBMS, but i don't see this options in access 2007. pd:only just table could be duplicate values(i guess that pk doesn't allow copy a duplicate value and all others values will be copied well). if i wrong please correct me. thanks for your help.

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