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  • Which Python XML library should I use?

    - by PulpFiction
    Hello. I am going to handle XML files for a project. I had earlier decided to use lxml but after reading the requirements, I think ElemenTree would be better for my purpose. The XML files that have to be processed are: Small in size. Typically < 10 KB. No namespaces. Simple XML structure. Given the small XML size, memory is not an issue. My only concern is fast parsing. What should I go with? Mostly I have seen people recommend lxml, but given my parsing requirements, do I really stand to benefit from it or would ElementTree serve my purpose better?

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  • Forward slash problem in xsl and xsql

    - by Peter Kaleta
    Hi I have simple xsql <?xml version="1.0" encoding="utf-8"?> <?xml-stylesheet type="text/xsl" href="zad1.xsl" ?> <page xmlns:xsql="urn:oracle-xsql" connection="java:comp/env/jdbc/mondialDS"> <xsql:query max-rows="-1" null-indicator="no" tag-case="lower" rowset-element="continents"> select name as continent from mondial_user.Continent order by 1 </xsql:query> </page> which gives me a list of continents with "australia/oceania" among them i use XSL on above xsql : <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <!-- Root template --> <res> <xsl:template match="/continents"> <xsl:for-each select="row"> <re> <xsl:value-of select="continent"/> </re> </xsl:for-each> </xsl:template> </res> </xsl:stylesheet> Firefox throws an error on "wrong formated xml document" with: AfricaAmericaAsiaAustralia/OceaniaEurope -----------------------------------^ Help appreciated.

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  • Parse error in application web.xml

    - by saloni
    I am making a simple servlet program and when i started my tomcat I m getting the error "java.lang.IllegalArgumentException:" and Parse error in application web.xml. and in web.xml http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" sample Samplelass SampleClass SampleClass /sample sample/page/form.jsp

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  • Writing the output of IEnumerable<XElement> to a XML File

    - by Googler
    HI folks , This is my code to read two xml files and merge their elemnts. I want to write the output to an xml file. This is my code. IEnumerable<XElement> list0 = doc.Descendants(node1).Concat(doc2.Descendants(node2)); foreach (XElement el in list0) Console.WriteLine(el); Instead of writing to the console i need to write it to a xml file. Output is also in the xml format.How to achieve this. Can anyone pls give me a code or method to achiev this.

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  • XML over HTTP with JMS and Spring

    - by Will Sumekar
    I have a legacy HTTP server where I need to send an XML file over HTTP request (POST) using Java (not browser) and the server will respond with another XML in its HTTP response. It is similar to Web Service but there's no WSDL and I have to follow the existing XML structure to construct my XML to be sent. I have done a research and found an example that matches my requirement here. The example uses HttpClient from Apache Commons. (There are also other examples I found but they use java.net networking package (like URLConnection) which is tedious so I don't want to use them). But it's also my requirement to use Spring and JMS. I know from Spring's reference that it's possible to combine HttpClient, JMS and Spring. My question is, how? Note that it's NOT in my requirement to use HttpClient. If you have a better suggestion, I'm welcome. Appreciate it. For your reference, here's the XML-over-HTTP example I've been talking about: /* * $Header: * $Revision$ * $Date$ * ==================================================================== * * Copyright 2002-2004 The Apache Software Foundation * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. * ==================================================================== * * This software consists of voluntary contributions made by many * individuals on behalf of the Apache Software Foundation. For more * information on the Apache Software Foundation, please see * <http://www.apache.org/>. * * [Additional notices, if required by prior licensing conditions] * */ import java.io.File; import java.io.FileInputStream; import org.apache.commons.httpclient.HttpClient; import org.apache.commons.httpclient.methods.InputStreamRequestEntity; import org.apache.commons.httpclient.methods.PostMethod; /** * * This is a sample application that demonstrates * how to use the Jakarta HttpClient API. * * This application sends an XML document * to a remote web server using HTTP POST * * @author Sean C. Sullivan * @author Ortwin Glück * @author Oleg Kalnichevski */ public class PostXML { /** * * Usage: * java PostXML http://mywebserver:80/ c:\foo.xml * * @param args command line arguments * Argument 0 is a URL to a web server * Argument 1 is a local filename * */ public static void main(String[] args) throws Exception { if (args.length != 2) { System.out.println( "Usage: java -classpath <classpath> [-Dorg.apache.commons."+ "logging.simplelog.defaultlog=<loglevel>]" + " PostXML <url> <filename>]"); System.out.println("<classpath> - must contain the "+ "commons-httpclient.jar and commons-logging.jar"); System.out.println("<loglevel> - one of error, "+ "warn, info, debug, trace"); System.out.println("<url> - the URL to post the file to"); System.out.println("<filename> - file to post to the URL"); System.out.println(); System.exit(1); } // Get target URL String strURL = args[0]; // Get file to be posted String strXMLFilename = args[1]; File input = new File(strXMLFilename); // Prepare HTTP post PostMethod post = new PostMethod(strURL); // Request content will be retrieved directly // from the input stream // Per default, the request content needs to be buffered // in order to determine its length. // Request body buffering can be avoided when // content length is explicitly specified post.setRequestEntity(new InputStreamRequestEntity( new FileInputStream(input), input.length())); // Specify content type and encoding // If content encoding is not explicitly specified // ISO-8859-1 is assumed post.setRequestHeader( "Content-type", "text/xml; charset=ISO-8859-1"); // Get HTTP client HttpClient httpclient = new HttpClient(); // Execute request try { int result = httpclient.executeMethod(post); // Display status code System.out.println("Response status code: " + result); // Display response System.out.println("Response body: "); System.out.println(post.getResponseBodyAsString()); } finally { // Release current connection to the connection pool // once you are done post.releaseConnection(); } } }

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  • How to execute PHPUnit?

    - by user1280667
    PHPUnit can execute script like this: phpunit --log-junit classname filename.php (i need the XML report , for my continus integreation platform) but my problem is that i work with a MVC framework and all pages are called through pathofproject/indexCLI.php module=moduleName class=className ect with 3 arguments in total(when i use the shell commande and path/index.php argum=... with url) so i cant call phpunit pathofproject/indexCLI.php module=moduleName class=className . So i think to a lot of solution , i hope you can help me to use one of them. first how can i use phpunit commande with this type of calling, because i cant do it because he is waiting a classname and a filename (default comportement) if it possible !! when i call the same link in shell like this : php path/indexCLI.php module="blabla" ect ... i have the result of assertion in my consol , but cant use XML Junit option , can i do it ? my last solution is to call the link in a navigator like mozzila , but i dont know how to say to phpunit runner to chose XML report and not HTML report. the aim for me , is to have a XML report .

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  • using php to check if xml is atom or rss

    - by guest86
    i'm writing a php code which has to determine if given xml is in "atom" or "rss" format. After observing atom and rss xml files, i decided classify xml based on a root element. If root element is "<feed" it's an atom xml. If it's "<rss" it's not an atom. How can i perform that check using DOM? So far i have: $dom->loadXML($resp); $feed = $dom->getElementsByTagName("feed"); but it's not working quite right....

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  • Java/JAXB: Unmarshall Xml to specific subclass based on an attribute

    - by Frothy
    Is it possible to use JAXB to unmarshall xml to a specific Java class based on an attribute of the xml? <shapes> <shape type="square" points="4" square-specific-attribute="foo" /> <shape type="triangle" points="3" triangle-specific-attribute="bar" /> </shapes> I would like to have a List of Shape objects containing a triangle and a square, each with their own shape-specific attribute. IE: abstract class Shape { int points; //...etc } class Square extends Shape { String square-specific-attribute; //...etc } class Triangle extends Shape { String triangle-specific-attribute; //...etc } I'm currently just putting all attributes in one big "Shape" class and it's less than ideal. I could get this to work if the shapes were properly named xml elements, but unfortunately I don't have control of the xml I'm retrieving. Thanks!

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  • How to solve docbuiler saxexception: unexpected end of document?

    - by user211992
    I have a service that gives some car information in an xml format. <?xml version="1.0" encoding='UTF-8'?> <car> <id>5</id> <name>qwer</name> </car> <car> <id>6</id> <name>qwert</name> </car> Now the problem that I'm having is that my DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); Document doc = docBuilder.parse(xml); Sometimes throws a SAXException (sometimes it works just fine, but when I reboot the server (still in development) I sometimes keep getting it) with as cause SAXException: unexpected end of document. But when I place a bufferreader there to see what it's receiving and I copy the value into an xml document and I open it in firefox/ie it looks just fine.

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  • Loading attribute in XPATH, problem

    - by Nguyen Quoc Hung
    I've got a question about loading attribute in XPATH. I write short XML code to test: <?xml version="1.0" encoding="iso-8859-1"?> <?xml-stylesheet type="text/xsl" href="testDate.xsl"?> <element attribute="1/1/2100"> Hung </element> My XSL code: <?xml version="1.0" encoding="iso-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <!--Handle the document: set up HTML page--> <xsl:template match="/"> <html> <head> </head> <body> This is a test <xsl:value-of select="element@attribute"/> </body> </html> </xsl:template> </xsl:stylesheet> Why it produces an error when loading the stylesheet? Would you please help me explain this? Thank you

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  • Android XmlSerializer limitation?

    - by Rexb
    Hi all, My task is just to get an xml string using XmlSerializer. Problem is that it seems like the serializer stops adding any new element and/or attribute to the xml document when it reaches certain length (perhaps 10,000 char?). My questions: have you experience this kind of problem? What could be possible solutions? Here is my sample test code: public void doSerialize() throws XmlPullParserException, IllegalArgumentException, IllegalStateException, IOException { StringWriter writer = new StringWriter(); XmlSerializer serializer = XmlPullParserFactory.newInstance().newSerializer(); serializer.setOutput(writer); serializer.startDocument(null, null); serializer.startTag(null, "START"); for (int i = 0; i < 20; i++) { serializer.attribute(null, "ATTR" + i, "VAL " + i); } serializer.startTag(null, "DATA"); for (int i = 0; i < 500; i++) { serializer.attribute(null, "attr" + i, "value " + i); } serializer.endTag(null, "DATA"); serializer.endTag(null, "START"); serializer.endDocument(); String xml = writer.toString(); // value: until 493rd attribute int n = xml.length(); // value: 10125 } Any help will be greatly appreciated.

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  • ArrayCollection loop through for matching items

    - by charlie
    Hi I hope someone can help me..... i am trying to build a dynamic form for a questionnaire module. Building on some previous posts I am using the process similar to that in question "http://stackoverflow.com/questions/629021/how-to-generate-a-formmxform-dynamically-in-flex" i have managed to prove out the fact of extending the XML to include a calendar, combobox etc. my problem is that now need to get the data from an ArrayCollection rather than from an xml file. I am looking to loop through the AC and where type = "text" render a textinput field, where a type ="calendar" render a Calendar etc etc. my code so far just looking at a textinput field (and sorry for all the comments included ;) is:- [Bindable] public var AC:ArrayCollection = new ArrayCollection( [ {type:'text', direction:'horizontal', tooltip:'test tooltip', label:'my textbox label', id:'1'}, {type:'text', direction:'horizontal', tooltip:'another tooltip', label:'another label', id:'2'} ]); private function init():void { var form:Form = new Form(); for each(var elements:XML in AC) { switch( [email protected]()) { case "text": var fi:FormItem = new FormItem(); // fi.toolTip = elements.tooltip.toString(); // fi.required = getglobalprofile.required.toString(); // fi.direction = getglobalprofileb[i].@direction; var li:Label = new Label(); // li.text = getglobalprofileb[i].@label; // li.width = 100; var ti:TextInput = new TextInput(); ti.text = "test"; ti.width = 200; form.addChild(fi); fi.addChild(li); fi.addChild(ti); // break; } } this.addChild( form); } ]] <mx:Form id="form" name="form"> </mx:Form> if you are interested in the working xml version (rendering only) let me know and i will post this as well

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  • Object reference not set to an instance of an object.

    - by Lambo
    I have the following code - private static void convert() { string csv = File.ReadAllText("test.csv"); string year = "2008"; XDocument doc = ConvertCsvToXML(csv, new[] { "," }); doc.Save("update.xml"); XmlTextReader reader = new XmlTextReader("update.xml"); XmlDocument testDoc = new XmlDocument(); testDoc.Load(@"update.xml"); XDocument turnip = XDocument.Load("update.xml"); webservice.singleSummary[] test = new webservice.singleSummary[1]; webservice.FinanceFeed CallWebService = new webservice.FinanceFeed(); foreach(XElement el in turnip.Descendants("row")) { test[0].account = el.Descendants("var").Where(x => (string)x.Attribute("name") == "account").SingleOrDefault().Attribute("value").Value; test[0].actual = System.Convert.ToInt32(el.Descendants("var").Where(x => (string)x.Attribute("name") == "actual").SingleOrDefault().Attribute("value").Value); test[0].commitment = System.Convert.ToInt32(el.Descendants("var").Where(x => (string)x.Attribute("name") == "commitment").SingleOrDefault().Attribute("value").Value); test[0].costCentre = el.Descendants("var").Where(x => (string)x.Attribute("name") == "costCentre").SingleOrDefault().Attribute("value").Value; test[0].internalCostCentre = el.Descendants("var").Where(x => (string)x.Attribute("name") == "internalCostCentre").SingleOrDefault().Attribute("value").Value; MessageBox.Show(test[0].account, "Account"); MessageBox.Show(System.Convert.ToString(test[0].actual), "Actual"); MessageBox.Show(System.Convert.ToString(test[0].commitment), "Commitment"); MessageBox.Show(test[0].costCentre, "Cost Centre"); MessageBox.Show(test[0].internalCostCentre, "Internal Cost Centre"); CallWebService.updateFeedStatus(test, year); } It is coming up with the error of - NullReferenceException was unhandled, saying that the object reference not set to an instance of an object. The error occurs on the first line test[0].account. How can I get past this?

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  • Getting a certain node using DataSet

    - by MarceloRamires
    I have the following XML <xml> <ObsCont xCampo="field1"> <xTexto>example1</xTexto> </ObsCont> <ObsCont xCampo="field2"> <xTexto>example2</xTexto> </ObsCont> <ObsCont xCampo="field3"> <xTexto>example3</xTexto> </ObsCont> <field>information</field> </xml> Is there a way to get the content of "xTexto" inside the ObsCont that has "field2" value for the attribute xCampo using DataSet ? It would be desireable to have a single liner like the following: DataSet ds = new DataSet(); ds.ReadXml(StrArquivoProc); ds.Tables["xml"].Rows[0]["field"].ToString(); //field == "information" If I use the same method I'm not specifying that I want the one with the desired attribute.

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  • Removing google mail markers with jquery after getting them from xml

    - by sebastian
    Hi there, I'm trying to create a page that contains a google map. The map is filled with markers from an xml file. I just can't figure out how to remove "old" markers, that don't match the latest user input. At the moment my js stops after the very first xml item. The clearList.push(marker); is supposed to put the generated marker away for later usage. When the user hits the search button I want all markers to be gone and use clearMarkers();. Maybe someone here can help Sebastian Here is my JavaScript: $(document).ready(function() { $("#map").css({height: 650}); var clearList = []; var myLatLng = new google.maps.LatLng(52.518143, 13.372879); MYMAP.init('#map', myLatLng, 11); $("#showmarkers").click(function(e){ clearMarkers(); MYMAP.placeMarkers('markers.xml'); }); }); function clearMarkers() { $(clearList).each(function () { this.setmap(null); }); clearList = []; } var MYMAP = { map: null, bounds: null } MYMAP.init = function(selector, latLng, zoom) { var myOptions = { zoom:zoom, center: latLng, mapTypeId: google.maps.MapTypeId.HYBRID } this.map = new google.maps.Map($(selector)[0], myOptions); this.bounds = new google.maps.LatLngBounds(); } MYMAP.placeMarkers = function(filename) { $.get(filename, function(xml){ $(xml).find("marker").each(function(){ // read values from xml for searching var platzart = $(this).find('platzart').text(); var ort = $(this).find('ort').text(); var open = $(this).find('open').text(); if (platzart =="Kunstrasen" && $('#kunstrasen').attr('checked') || platzart =="Rasen" && $('#rasen').attr('checked') || platzart =="Tartan" && $('#tartan').attr('checked') || platzart =="Boltzplatz" && $('#boltzplatz').attr('checked') ){ // read values from xml for additional info var name = $(this).find('name').text(); var plz = $(this).find('plz').text(); var note = $(this).find('note').text(); var adress = $(this).find('adress').text(); // create a new LatLng point for the marker var lat = $(this).find('lat').text(); var lng = $(this).find('lng').text(); var point = new google.maps.LatLng(parseFloat(lat),parseFloat(lng)); // extend the bounds to include the new point MYMAP.bounds.extend(point); // create new marker var marker = new google.maps.Marker({ position: point, map: MYMAP.map }); clearList.push(marker); // add onclick overlay var infoWindow = new google.maps.InfoWindow(); var html='<strong>'+name+'</strong.><br />'+platzart; google.maps.event.addListener(marker, 'click', function() { infoWindow.setContent(html); infoWindow.open(MYMAP.map, marker); }); } MYMAP.map.fitBounds(MYMAP.bounds); }); }); } Thanks in advance

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  • Call Web Service from https and parse responded xml data in Java

    - by Nirmal
    Hello All.. I need to get connect with https url, send my request schema and I will get some xml response from web service. For https url connection I am using : HttpURLConnection con = (HttpURLConnection)myurl.openConnection(); con.setDoOutput(true); con.setDoInput(true); con.setUseCaches(false); InputStream ins = con.getInputStream(); con.setRequestProperty("Content-type","text/xml"); So, from above code I am getting responded XML from server. Now my question is which would be best parser for me to parse responded xml data to my Simple Java Object. I have goggled alot on that, and getting various solutions but I have confuse for choosing appropriate one. if anybody have suggestion with some sample example, then please provide.. Thanks in advance...

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  • xml to xsd to c# class - C# 3.0, .net 3.5

    - by uno
    Following this articlelink text one of the comments from 'zanoni' said he did it this way Using .NET 3.5: [XmlRoot] public class EmailConfiguration { [XmlElement] public string DataBoxID { get; set; } [XmlElement] public DefaultSendToAddressCollectionClass DefaultSendToAddressCollection { get; set; } } public class DefaultSendToAddressCollectionClass { [XmlElement] public string[] EmailAddress { get; set; } } How would I get my class to be as what he described? I ran the xsd tool and it is in the fashion as what shane posted in the above link [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")] [System.SerializableAttribute()] [System.Diagnostics.DebuggerStepThroughAttribute()] [System.ComponentModel.DesignerCategoryAttribute("code")] [System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true)] [System.Xml.Serialization.XmlRootAttribute(Namespace="", IsNullable=false)] public partial class EmailConfiguration : object, System.ComponentModel.INotifyPropertyChanged { private string dataBoxIDField; private EmailConfigurationDefaultSendToAddressCollection[] defaultSendToAddressCollectionField; /// <remarks/> [System.Xml.Serialization.XmlElementAttribute(Form=System.Xml.Schema.XmlSchemaForm.Unqualified)] public string DataBoxID { get { return this.dataBoxIDField; } set { this.dataBoxIDField = value; this.RaisePropertyChanged("DataBoxID"); } }

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  • updating multiple nodes in xml with xquery and xdmp:node-replace

    - by morja
    Hi all, I wnat to update an XML document in my xml database (Marklogic). I have xml as input and want to replace each node that exists in the target xml. If a node does not exist it would be great if it gets added, but thats maybe another task. My XML in the database: <user> <username>username</username> <firstname>firstname</firstname> <lastname>lastname</lastname> <email>[email protected]</email> <comment>comment</comment> </user> The value of $user_xml: <user> <firstname>new firstname</firstname> <lastname>new lastname</lastname> </user> My function so far: declare function update-user ( $username as xs:string, $user_xml as node()) as empty-sequence() { let $uri := user-uri($username) return for $node in $user_xml/user return xdmp:node-replace(fn:doc($uri)/user/fn:node-name($node), $node) }; First of all I cannot iterate over $user_xml/user. If I try to iterate over $user_xml I get "arg1 is not of type node()" exception. But maybe its the wrong approach anyway? Does anybody maybe have sample code how to do this?

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  • zend-framework navigation

    - by ulduz114
    i have this xml file for Creating a container , if i want create a db for save this items and and create container from db how should i do ? <?xml version="1.0" encoding="utf-8"?> <config> <nav> <logout> <label>logout</label> <controller>authentication</controller> <action>logout</action> <resource>logout</resource> </logout> <login> <label>login</label> <controller>authentication</controller> <action>login</action> <resource>login</resource> </login> <test> <label>test</label> <uri>#</uri> <resource>test</resource> <pages> <list> <label>list</label> <controller>tset</controller> <action>listtest</action> </list> <archive> <label>archive</label> <controller>myarchive</controller> <action>archive</action> </archive> </pages> </test> </nav> </config> and code in bootsrap $navContainerConfig = new Zend_Config_Xml(APPLICATION_PATH . 'navigation.xml', 'nav'); $navContainer = new Zend_Navigation($navContainerConfig);

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  • Is XSLT worth investing time in and are there any actual alternatives?

    - by Keeno
    I realize this has been a few other questions on this topic, and people are saying use your language of choice to manipulate the XML etc etc however, not quite fit my question exactly. Firstly, the scope of the project: We want to develop platform independent e-learning, currently, its a bunch of HTML pages but as they grow and develop they become hard to maintain. The idea: Generate up an XML file + Schema, then produce some XSLT files that process the XML into the eLearning modiles. XML to HTML via XSLT. Why: We would like the flexibilty to be able to easy reformat the content (I realize CSS is a viable alternative here) If we decide to alter the pages layout or functionality in anyway, im guessing altering the "shared" XSLT files would be easier than updating the HTML files. So far, we have about 30 modules, with up to 10-30 pages each Depending on some "parameters" we could output drastically different page layouts/structures, above and beyond what CSS can do Now, all this has to be platform independent, and to be able to run "offline" i.e. without a server powering the HTML Negatives I've read so far for XSLT: Overhead? Not exactly sure why...is it the compute power need to convert to HTML? Difficult to learn Better alternatives Now, what I would like to know exactly is: are there actually any viable alternatives for this "offline"? Am I going about it in the correct manner, do you guys have any advice or alternatives. Thanks!

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  • Why does WebSharingAppDemo-CEProviderEndToEnd sample still need a client db connection after scope c

    - by Don
    I'm researching a way to build an n-tierd sync solution. From the WebSharingAppDemo-CEProviderEndToEnd sample it seems almost feasable however for some reason, the app will only sync if the client has a live SQL db connection. Can some one explain what I'm missing and how to sync without exposing SQL to the internet? The problem I'm experiencing is that when I provide a Relational sync provider that has an open SQL connection from the client, then it works fine but when I provide a Relational sync provider that has a closed but configured connection string, as in the example, I get an error from the WCF stating that the server did not receive the batch file. So what am I doing wrong? SqlConnectionStringBuilder builder = new SqlConnectionStringBuilder(); builder.DataSource = hostName; builder.IntegratedSecurity = true; builder.InitialCatalog = "mydbname"; builder.ConnectTimeout = 1; provider.Connection = new SqlConnection(builder.ToString()); // provider.Connection.Open(); **** un-commenting this causes the code to work** //create anew scope description and add the appropriate tables to this scope DbSyncScopeDescription scopeDesc = new DbSyncScopeDescription(SyncUtils.ScopeName); //class to be used to provision the scope defined above SqlSyncScopeProvisioning serverConfig = new SqlSyncScopeProvisioning(); .... The error I get occurs in this part of the WCF code: public SyncSessionStatistics ApplyChanges(ConflictResolutionPolicy resolutionPolicy, ChangeBatch sourceChanges, object changeData) { Log("ProcessChangeBatch: {0}", this.peerProvider.Connection.ConnectionString); DbSyncContext dataRetriever = changeData as DbSyncContext; if (dataRetriever != null && dataRetriever.IsDataBatched) { string remotePeerId = dataRetriever.MadeWithKnowledge.ReplicaId.ToString(); //Data is batched. The client should have uploaded this file to us prior to calling ApplyChanges. //So look for it. //The Id would be the DbSyncContext.BatchFileName which is just the batch file name without the complete path string localBatchFileName = null; if (!this.batchIdToFileMapper.TryGetValue(dataRetriever.BatchFileName, out localBatchFileName)) { //Service has not received this file. Throw exception throw new FaultException<WebSyncFaultException>(new WebSyncFaultException("No batch file uploaded for id " + dataRetriever.BatchFileName, null)); } dataRetriever.BatchFileName = localBatchFileName; } Any ideas?

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  • Validate XML instance document against WSDL

    - by Ice09
    Hi, I can easily validate a XML document against a XML Schema, eg. with XMLSpy or programmatically. Is it possible to do this with a WSDL file? It does not seem possible with XMLSpy or any other XML tool I know. For me the only possibility right now is to do it programmatically, eg. by generating Java code from the WSDL and starting a request, which is then marshalled correctly. If there is no tool / easy programmatic approach, is there a tool which can extract XML Schema from the WSDL? Best

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  • Parsing CSV File to MySQL DB in PHP

    - by Austin
    I have a some 350-lined CSV File with all sorts of vendors that fall into Clothes, Tools, Entertainment, etc.. categories. Using the following code I have been able to print out my CSV File. <?php $fp = fopen('promo_catalog_expanded.csv', 'r'); echo '<tr><td>'; echo implode('</td><td>', fgetcsv($fp, 4096, ',')); echo '</td></tr>'; while(!feof($fp)) { list($cat, $var, $name, $var2, $web, $var3, $phone,$var4, $kw,$var5, $desc) = fgetcsv($fp, 4096); echo '<tr><td>'; echo $cat. '</td><td>' . $name . '</td><td><a href="http://www.' . $web .'" target="_blank">' .$web.'</a></td><td>'.$phone.'</td><td>'.$kw.'</td><td>'.$desc.'</td>' ; echo '</td></tr>'; } fclose($file_handle); show_source(__FILE__); ?> First thing you will probably notice is the extraneous vars within the list(). this is because of how the excel spreadsheet/csv file: Category,,Company Name,,Website,,Phone,,Keywords,,Description ,,,,,,,,,, Clothes,,4imprint,,4imprint.com,,877-466-7746,,"polos, jackets, coats, workwear, sweatshirts, hoodies, long sleeve, pullovers, t-shirts, tees, tshirts,",,An embroidery and apparel company based in Wisconsin. ,,Apollo Embroidery,,apolloemb.com,,1-800-982-2146,,"hats, caps, headwear, bags, totes, backpacks, blankets, embroidery",,An embroidery sales company based in California. One thing to note is that the last line starts with two commas as it is also listed within "Clothes" category. My concern is that I am going about the CSV output wrong. Should I be using a foreach loop instead of this list way? Should I first get rid of any unnecessary blank columns? Please advise any flaws you may find, improvements I can use so I can be ready to import this data to a MySQL DB.

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  • Where to place log4j.xml

    - by Farid
    Hi , How can we specify were log4j has to look at when trying to find its xml configuration file ? It seems that by default, log4j looks into the root of a class folder, I can say that using the debug log4j functionality and running my application from the IDE. However, I don't have any class folder in my jar anymore. And the log4j.xml file is at the root of the jar. I have already tried to set the option -Dlog4j.configuration=log4j.xml but it doesn't work. Here is the global structure of my application at the moment : com lib meta-inf log4j.xml Thanks !

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