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  • Preg Expression to identify classes/ids in a CSS file that have no contents

    - by dclowd9901
    I'm in the process of updating some old CSS files in our systems, and we have a bunch that have lots of empty classes simply taking up space in the file. I'd love to learn how to write Regular expressions, but I just don't get them. I'm hoping the more I expose myself to them (with a little more cohesive explanation), the more I'll end up understanding them. The Problem That said, I'm looking for an expression that will identify text followed by a '{' (some have spaces in between, and some do not) and if there are no letters or numbers between that bracket and '}' (spaces don't count), it will be identified as a matching string. I suppose I can trim the whitespace out of the doc before I run a regular expression through it, but I don't want to change the basic structure of the text. I'm hoping to return it into a large <textarea>. Bonus points for explaining the characters and their meanings, and also an expression identifying lines in the copy without any text or numbers, as well. I will likely use the final expression in PHP script. tl;dr: Regular Expression to match: .a_class_or #an_id { /* if there aren't any alphanumerics in here, this should be a matching line of text */ }

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  • Regular expression to match maximium of five words.

    - by KhanS
    I have a regular expression ^[a-zA-Z+#-.0-9]{1,5}$ which validates that the word contains alpha-numeric characters and few special characters and length should not be more than 5 characters. How do I make this regular expression to accept a maximum of five words matching the above regular expression.

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  • Regular expression for checking website url

    - by Linto davis
    I need to check the web address, using regular expression. if user type url as www.test.com http://www.test.com https://www.test.com i have a regular expression like /^(http\:\/\/[a-zA-Z0-9_-]+(?:.[a-zA-Z0-9_-]+)*.[a-zA-Z]{2,4}(?:\/[a-zA-Z0-9_]+)*(?:\/[a-zA-Z0-9_]+.[a-zA-Z]{2,4}(?:\?[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)?)?(?:\&[a-zA-Z0-9_]+\=[a-zA-Z0-9_]+)*)$/ but it will only allow the second option only. how can i modify the regular expression so that , it should accept 1st and 3rd option too

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  • Visual Studio expression containing a term named "by" cannot be evaluated in the watch window

    - by Andrei Pana
    Consider my C++ code below: int _tmain(int argc, _TCHAR* argv[]) { int by = 10; printf("%d\n", by); int bx = 20; printf("%d\n", (by + bx)); return 0; } which works fine. The funny thing is with the "by" variable. If I try to add a watch for a simple expression that contains by, the result will be CXX0030: Error: expression cannot be evaluated. For example, on a breakpoint on return 0, if I add the following watches I get the results mentioned: by : 10 bx : 20 by + 5 : CXX0030: Error: expression cannot be evaluated bx + 5 : 25 by + bx : CXX0030: Error: expression cannot be evaluated (by) + bx : 30 by + (bx) : CXX0030: Error: expression cannot be evaluated bx + (by) : CXX0014: Error: missing operrand This happens on VS2010, VS2008 on multiple computers. So, more out of curiosity, what is happening with "by"? Is it some kind of strange operator? Why doesn't bx get the same treatment? (I've tried google on this but it is quite difficult to get some relevant hits with terms like "by")

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  • Determining whether values can potentially match a regular expression, given more input

    - by Andreas Grech
    I am currently writing an application in JavaScript where I'm matching input to regular expressions, but I also need to find a way how to match strings to parts of the regular expressions. For example: var invalid = "x", potentially = "g", valid = "ggg", gReg = /^ggg$/; gReg.test(invalid); //returns false (correct) gReg.test(valid); //returns true (correct) Now I need to find a way to somehow determine that the value of the potentially variable doesn't exactly match the /^ggg$/ expression, BUT with more input, it potentially can! So for example in this case, the potentially variable is g, but if two more g's are appended to it, it will match the regular expression /^ggg$/ But in the case of invalid, it can never match the /^ggg$/ expression, no matter how many characters you append to it. So how can I determine if a string has or doesn't have potential to match a particular regular expression?

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  • Help with Linq Expression - INotifyPropertyChanged

    - by Stephen Patten
    Hello, I'm reading the source code from the latest Prism 4 drop and am interested in solving this problem. There is a base class for the ViewModels that implements INotifyPropertyChanged and INotifyDataErrorInfo and provides some refactoring friendly change notification. protected void RaisePropertyChanged<T>(Expression<Func<T>> propertyExpresssion) { var propertyName = ExtractPropertyName(propertyExpresssion); this.RaisePropertyChanged(propertyName); } private string ExtractPropertyName<T>(Expression<Func<T>> propertyExpresssion) { if (propertyExpresssion == null) { throw new ArgumentNullException("propertyExpression"); } var memberExpression = propertyExpresssion.Body as MemberExpression; if (memberExpression == null) { throw new ArgumentException("The expression is not a member access expression.", "propertyExpression"); } var property = memberExpression.Member as PropertyInfo; if (property == null) { throw new ArgumentException("The member access expression does not access property.","propertyExpression"); } if (!property.DeclaringType.IsAssignableFrom(this.GetType())) { throw new ArgumentException("The referenced property belongs to a different type.", "propertyExpression"); } var getMethod = property.GetGetMethod(true); if (getMethod == null) { // this shouldn't happen - the expression would reject the property before reaching this far throw new ArgumentException("The referenced property does not have a get method.", "propertyExpression"); } if (getMethod.IsStatic) { throw new ArgumentException("The referenced property is a static property.", "propertyExpression"); } return memberExpression.Member.Name; } and as an example of it's usage private void RetrieveNewQuestionnaire() { this.Questions.Clear(); var template = this.questionnaireService.GetQuestionnaireTemplate(); this.questionnaire = new Questionnaire(template); foreach (var question in this.questionnaire.Questions) { this.Questions.Add(this.CreateQuestionViewModel(question)); } this.RaisePropertyChanged(() => this.Name); this.RaisePropertyChanged(() => this.UnansweredQuestions); this.RaisePropertyChanged(() => this.TotalQuestions); this.RaisePropertyChanged(() => this.CanSubmit); } My question is this. What would it take to pass an array of the property names to an overloaded method (RaisePropertyChanged) and condense this last bit of code from 4 lines to 1? Thank you, Stephen

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  • What is the regular expression for valdating a 'price' in a jtextfield

    - by wniroshan
    I want to validate a jtextfield as user inputs a price of some item. I have a perfectly working code which beeps and discard if user inputs some character that doesnt match the regular expression.(for regular expression "[0-9]+" it accepts any number of digits and beeps if a letter is given as input) But the problem is I want to validate an input like "12500.00". Format should be any number of digits before decimal point and two digits after the decimal point. eg: ddd.dd I tried the following regular expression. But the i doesnt allow user to input "." character. It allows user to input any number of digits but when "." key is pressed input is not accepted. here is the regular expression I used. "[0-9]+ | [0-9]+. | [0-9]+.[0-9]{1} | [0-9]+{2}" important: user input is validated character by character as the user inputs them to the jtextfield.

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  • how to prevent white spaces in a regular expression regex validation

    - by Rees
    i am completely new to regular expressions and am trying to create a regular expression in flex for a validation. using a regular expression, i am going to validate that the user input does NOT contain any white-space and consists of only characters and digits... starting with digit. so far i have: expression="[A-Za-z][A-Za-z0-9]*" this correctly checks for user input to start with a character followed by a possible digit, but this does not check if there is white space...(in my tests if user input has a space this input will pass through validation - this is not desired) can someone tell me how i can modify this expression to ensure that user input with whitespace is flagged as invalid?

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  • Precompile Lambda Expression Tree conversions as constants?

    - by Nathan
    It is fairly common to take an Expression tree, and convert it to some other form, such as a string representation (for example this question and this question, and I suspect Linq2Sql does something similar). In many cases, perhaps even most cases, the Expression tree conversion will always be the same, i.e. if I have a function public string GenerateSomeSql(Expression<Func<TResult, TProperty>> expression) then any call with the same argument will always return the same result for example: GenerateSomeSql(x => x.Age) //suppose this will always return "select Age from Person" GenerateSomeSql(x => x.Ssn) //suppose this will always return "select Ssn from Person" So, in essence, the function call with a particular argument is really just a constant, except time is wasted at runtime re-computing it continuously. Assuming, for the sake of argument, that the conversion was sufficiently complex to cause a noticeable performance hit, is there any way to pre-compile the function call into an actual constant?

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  • What does this regex expression do?

    - by Ranjeet
    Hi All, I am looking after fixing a bug and there I find this expression:- directoryPath = Regex.Replace(directoryPath, "[^\\w\\.@-]", ""); but as a result of the expression all the high ascii characters in directory path are messed up, I am not good at regex and dont know about it but for now I have to fix the issue . Can someone please explain me what this regular expression does?

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  • Exiting from the Middle of an Expression Without Using Exceptions

    - by Jon Purdy
    Is there a way to emulate the use of flow-control constructs in the middle of an expression? Is it possible, in a comma-delimited expression x, y, for y to cause a return? Edit: I'm working on a compiler for something rather similar to a functional language, and the target language is C++. Everything is an expression in the source language, and the sanest, simplest translation to the destination language leaves as many things expressions as possible. Basically, semicolons in the target language become C++ commas. In-language flow-control constructs have presented no problems thus far; it's only return. I just need a way to prematurely exit a comma-delimited expression, and I'd prefer not to use exceptions unless someone can show me that they don't have excessive overhead in this situation. The problem of course is that most flow-control constructs are not legal expressions in C++. The only solution I've found so far is something like this: try { return x(), // x(); (1 ? throw Return(0) : 0); // return 0; } catch (Return& ret) { return ref.value; } The return statement is always there (in the event that a Return construct is not reached), and as such the throw has to be wrapped in ?: to get the compiler to shut up about its void result being used in an expression. I would really like to avoid using exceptions for flow control, unless in this case it can be shown that no particular overhead is incurred; does throwing an exception cause unwinding or anything here? This code needs to run with reasonable efficiency. I just need a function-level equivalent of exit().

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  • is it the right reqular expression

    - by girish
    i have following regular expression but it's not working properly it takes only three values after @ sign but i want it to be any number length "/^[a-zA-Z0-9_.-]+\@([a-zA-Z0-9-]+.)+[a-zA-Z0-9]{2,4}$/" this@thi This is validated this@this It is not validating this expression Can you please tell me what's the problem with the expression... Thanks

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  • Fluent Nhibernate expression to select on flagged enum

    - by mbalkema
    I have a domain entity that has a flagged enum as a property. The flagged enum is the target audience for the these entities. The user then has a flagged enum value of the entities they should see. I am trying to figure out the correct expression to select entities that meet the target audience for the user. public class File { public virtual TargetAudience TargetAudience { get; set; } } [Flags] public enum TargetAudience { Audience1 = 1, Audience2 = 2, Audience3 = 4, Audience4 = 8 } Expression: (This works when performed on a IList<File>, but doesn't work on a query to the database.) public Expression<Func<File, bool>> Expression { get { return ((x.TargetAudience & UserTargetedAudience) > 0); } } Any suggestions would be helpful.

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  • How to use the LINQ where expression?

    - by NullReference
    I'm implementing the service \ repository pattern in a new project. I've got a base interface that looks like this. Everything works great until I need to use the GetMany method. I'm just not sure how to pass a LINQ expression into the GetMany method. For example how would I simply sort a list of objects of type name? nameRepository.GetMany( ? ) public interface IRepository<T> where T : class { void Add(T entity); void Update(T entity); void Delete(T entity); void Delete(Expression<Func<T, bool>> where); T GetById(long Id); T GetById(string Id); T Get(Expression<Func<T, bool>> where); IEnumerable<T> GetAll(); IEnumerable<T> GetMany(Expression<Func<T, bool>> where); } public virtual IEnumerable<T> GetMany(Expression<Func<T, bool>> where) { return dbset.Where(where).ToList(); }

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  • Regular expression help

    - by user268375
    I need a regular expression for which: the string is alphanumeric and have exactly 6 characters in the first half followed by hyphen(optional) followed by optional 4 characters:(cannot have more than 4 characters in the second half) so any of the following is valid 11111A 111111-1 111111-yy yyyyy-989 yyyyyy-9090 I have ^[a-zA-Z0-9]{5}(-[a-zA-Z0-9]{1,3})?$ as the regex expression what if i want to add another condition stating that the first half cannot have all zeros and also the whole expression cannot have zeros so 00000 or 00000-000 is invalid

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  • Create LINQ to entities OrderBy expression on the fly

    - by AyKarsi
    I'm trying to add the orderby expression on the fly. But when the query below is executed I get the following exception: System.NotSupportedException: Unable to create a constant value of type 'Closure type'. Only primitive types ('such as Int32, String, and Guid') are supported in this context. The strange thing is, I am query exactly those primitive types only. string sortBy = HttpContext.Current.Request.QueryString["sidx"]; ParameterExpression prm = Expression.Parameter(typeof(buskerPosting), "posting"); Expression orderByProperty = Expression.Property(prm, sortBy); // get the paged records IQueryable<PostingListItemDto> query = (from posting in be.buskerPosting where posting.buskerAccount.cmsMember.nodeId == m.Id orderby orderByProperty //orderby posting.Created select new PostingListItemDto { Set = posting }).Skip<PostingListItemDto>((page - 1) * pageSize).Take<PostingListItemDto>(pageSize); Hope somebody can shed some light on this!

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  • Dreamweaver regular expression substitution followed by number

    - by mark
    Hi. I'm using Dreamweaver to update copyright dates across my site. I want to preserve the existing spacing (or lack thereof) between years. Examples: © 2002-2008 should update to © 2002-2009 © 2003 - 2008 should update to © 2003 - 2009 This is the regular expression I'm using to accomplish this in Dreamweaver's find & replace function Find: ©\s*(\d{4}\s*-\s*)\d{3}[^9] Replace: © $1 2009 Here's the PROBLEM: This expression works, but has that that extra space between the hyphen and 2009. If I write the replace expression without the space, as © $12009 then dreamweaver looks for the 12,009th substitution in the find expression, and, not finding one, prints $12009. Any ideas?

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  • Alter Regular Expression to Return 2 Values Instead of 3 from userAgent String

    - by Jay
    I've taken a regular expression from jQuery to detect if a browser's engine is WebKit and gets it's version number, it returns 3 values extracted from the userAgent string: webkit/….…, webkit and ….… [“….…” being the version number]. I would like the regular expression to return just 2 values: webkit and ….…. I'm rubbish at regular expressions, so please can you give an explanation of the expression with your answer. The regular expression I'm currently working with and wish to improve is: /(webkit)[\/]([\w.]+)/. I appreciate all your help, thanks in advance!

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  • Regular expression required

    - by KhanS
    I have a regular expression "^[a-zA-Z+#-.0-9]{1,5}$" which validates that the word contains alpha-numeric characters and few special characters and length sould not be more than 5 characters. How do I make this regular expression to accept a maximum of five words matching the above regular expression.

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  • How to pass a Lambda Expression as method parameter with EF

    - by Registered User
    How do I pass an EF expression as a method argument? To illustrate my question I have created a pseudo code example: The first example is my method today. The example utilizes EF and a Fancy Retry Logic. What I need to do is to encapsulate the Fancy Retry Logic so that it becomes more generic and does not duplicate. In the second example is how I want it to be, with a helper method that accepts the EF expression as an argument. This would be a trivial thing to do with SQL, but I want to do it with EF so that I can benefit from the strongly typed objects. First Example: public static User GetUser(String userEmail) { using (MyEntities dataModel = new MyEntities ()) { var query = FancyRetryLogic(() => { (dataModel.Users.FirstOrDefault<User>(x => x.UserEmail == userEmail))); }); return query; } } Second Example: T RetryHelper<T>(Expression<Func<T, TValue>> expression) { using (MyEntities dataModel = new (MyEntities ()) { var query = FancyRetryLogic(() => { return dataModel.expression }); } } public User GetUser(String userEmail) { return RetryHelper<User>(<User>.FirstOrDefault<User>(x => x.UserEmail == userEmail)) }

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  • two line label with expression

    - by metasequoia
    I'd like to write an axis label over two lines with an expression() statement. However, plotmath and expression won't allow this (e.g. subscript appear on the far right). I found this discussion circa 2005 of a similar issue but the work around that they offer doesn't translate to my application in ggplot2. A recent question addressed a a different permutation of multi-line expression statements, but again the work around provided doesn't apply here. Example: p <- ggplot(mtcars,aes(x=wt,y=mpg))+ geom_point()+ xlab(expression(paste("A long string of text goes here just for the purpose \n of illustrating my point Weight "[reported]))) try(ggsave(plot=p,filename=<some file>,height=4,width=6)) yields an image where subscript "reported" is kicked out to the right when I'd like it to sit next to the previous word.

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