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  • Function parameter types in Python

    - by Leif Andersen
    Unless I'm mistaken, creating a function in python works like this def my_func(param1, param2): /*stuff*/ However, you don't actually give the types of those parameters. Also, if I remember, python is a strongly typed language, as such, it seams like python shouldn't let you pass in a parameter of a different type then the function creator expected. However, how does python know that the user of the function is passing in the proper types? Or will the program just die if it's the wrong type, assuming the function actually uses the parameter? Or do you have to specify the type/I'm missing something? Thank you.

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  • Cakephp Function in mode not executing

    - by Rixius
    I have a function in my Comic Model as such: <?php class Comic extends AppModel { var $name = "Comic"; // Methods for retriving information. function testFunc(){ $mr = $this->find('all'); return $mr; } } ?> And I am calling it in my controller as such: <?php class ComicController extends AppController { var $name = "Comic"; var $uses = array('Comic'); function index() { } function view($q) { $this->set('array',$this->Comic->testFunc()); } } ?> When I try to load up the page; I get the following error: Warning (512): SQL Error: 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'testFunc' at line 1 [CORE/cake/libs/model/datasources/dbo_source.php, line 525] Query: testFunc And the SQL dump looks like this: (default) 2 queries took 1 ms Nr Query Error Affected Num. rows Took (ms) 1 DESCRIBE comics 10 10 1 2 testFunc 1064: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'testFunc' at line 1 0 So it looks like, instead of running the testFunc() function, it is trying to run a query of "testFunc" and failing...

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  • Help with function in string

    - by draice
    I have a variable, emailBody, which is set to a string stored in a database emailBody = DLookup("emailBody", "listAdditions", "Id = " & itemType) The string icludes an IIf function (which includes a dlookup function). ?emailBody The new commodity is" & Iif(dlookup("IsVague", "CommodityType", "Description= " & newItem)="1", "vague.", "not vague.") How do I properly format the string so that the function will be evaluated and the result stored in the string?

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  • how do i return arraylist from a function?

    - by KoolKabin
    Hi guys, I learnt example from msdn to populate a listbox control with arraylist. http://msdn.microsoft.com/en-us/library/1818w7we(v=VS.100).aspx I want to create a function which will give return the USStates arraylist and use the returned value as datasource for listbox1 Dim USStates As New ArrayList() USStates.Add(New USState("Alabama", "AL")) USStates.Add(New USState("Washington", "WA")) USStates.Add(New USState("West Virginia", "WV")) USStates.Add(New USState("Wisconsin", "WI")) USStates.Add(New USState("Wyoming", "WY")) ListBox1.DataSource = USStates ListBox1.DisplayMember = "LongName" ListBox1.ValueMember = "ShortName I tried creating a function like: Public Shared Function FillList() As ArrayList() Dim USStates As New ArrayList() USStates.Add(New USState("Alabama", "AL")) USStates.Add(New USState("Washington", "WA")) USStates.Add(New USState("West Virginia", "WV")) USStates.Add(New USState("Wisconsin", "WI")) USStates.Add(New USState("Wyoming", "WY")) return usstates end function but it says error: Value of type 'System.Collections.ArrayList' cannot be converted to '1-dimensional array of System.Collections.ArrayList'.

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  • python simple function error ?

    - by abhilashm86
    Here's a simple function to do simple math operations, when i call this from other program using import, output i get is none. When i remove def function, everything is working fine. What's the problem with defining this function? I'm new to python. def calci(a, op, b): if op == '+': c = a + b elif op == '-': c = a-b elif op == '*': c= a*b elif op =='/': if(b == 0): print('can\'t divide') c = a/b print('value is',c) return c result = calci(12,'+', 12) print(result) nter code here

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  • function pointer error

    - by Codeguru
    Can anybody help me with this simple code?? include using namespace std; void testFunction(){ cout<<"This is the test function 0"< void testFunction1(){ cout<<"This is the test function 1"< void testFunction2(){ cout<<"This is the test function 2"< int main(){ //fp=testFunction; (*fp[testFunction1])(); //cout<<"Addrees of the function pointer is:"<<*fp; } Iam getting the following error: error: invalid types `void (*[3])()[void ()()]' for array subscript|

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  • Javascript: variable in outer function not changed by inner function

    - by Weng-Lock Mok
    I am having a small issue with what I believe is probably my misunderstanding of Javascript closures. I have this piece of code -- getStdOpts: function(tbl, filt) { var vals = new Array(); this.srvs.getStdOptions( { tbl: tbl }, { 'ok': function(rsp) { for (var i in rsp) { vals.push({ value: rsp[i].id, text: rsp[i].descr }); } } } ); return vals; } In essence, although the inner function inside the getStdOptions call ('ok': function...) pushes new values into the vals array, when accessed from outside the call, the vals array is empty. When accessed from within the inner function, vals contains all the elements as expected. Would really appreciate any help I can get on this matter.

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  • Deleting object in function

    - by wrongusername
    Let's say I have created two objects from class foo and now want to combine the two. How, if at all possible, can I accomplish that within a function like this: def combine(first, second): first.value += second.value del second #this doesn't work, though first.value *does* get changed instead of doing something like def combine(first, second): first.value += second.value in the function and putting del second immediately after the function call?

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  • checkUnique function?

    - by Chris Leah
    Hey, so I have created a function to check the DB for unique entries, but when I call the function it doesn't seem to work and gives me a fatal error any ideas from the function or do you wish to see the sign up page calling it. Thanks :) //Check for unique entries function checkUnique($table, $field, $compared) { $query = $mysqli->query('SELECT '.$mysqli->real_escape_string($field).' FROM '.$mysqli->real_escape_string($table).' WHERE "'.$mysqli->real_escape_string($field).'" = "'.$mysqli->real_escape_string($compared).'"'); if(!$query){ return TRUE; } else { return FALSE; } } The page calling it..... if (!empty($_POST['username']) && !empty($_POST['password']) && $_POST['password']==$_POST['password_confirm'] && !empty($_POST['email']) && validateEmail($_POST['email']) == TRUE && checkUnqiue('users', 'email', $_POST['email']) == TRUE && checkUnique('users', 'username', $_POST['username']) == TRUE)

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  • Question about member function pointers in a heirarchy

    - by Jesse Beder
    I'm using a library that defines an interface: template<class desttype> void connect(desttype* pclass, void (desttype::*pmemfun)()); and I have a small heirarchy class base { void foo(); }; class derived: public base { ... }; In a member function of derived, I want to call connect(this, &derived::foo); but it seems that &derived::foo is actually a member function pointer of base; gcc spits out error: no matching function for call to ‘connect(derived* const&, void (base::* const&)())’ I can get around this by explicitly casting this to base *; but why can't the compiler match the call with desttype = base (since derived * can be implicitly cast to base *)? Also, why is &derived::foo not a member function pointer of derived?

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  • Understanding an interesting array update/replace function

    - by dave
    I'm a PHP amateur. This array function is an adaption of a function I noticed while reading this article. I thought this was an interesting type of array function, but I have a question about the way it works. my_func( array( 'sky' => 'blue' ) ); function my_func( array $settings = array() ) { $settings = $settings + array( 'grass'=>'green','sky'=>'dark' ); print_r( $settings ) ; // outputs: Array ( [sky] => blue [grass] => green ) } but..................... my_func( array( 'sky' => 'blue' ) ); function my_func( array $settings = array() ) { $settings = array( 'clock'=>'time' ) ; $settings = $settings + array( 'grass'=>'green','sky'=>'dark' ); print_r( $settings ) ; // outputs: Array ( [clock] => time [grass] => green [sky] => dark ) } Why does [sky] not equal 'blue' in the second instance? Thanks.

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  • How to fix MySQL CREATE FUNCTION query?

    - by Liutas
    I want to add mysql function: CREATE FUNCTION `chf_get_translation`(translation_id INT, site_lang INT) RETURNS text CHARSET utf8 BEGIN DECLARE translation TEXT; SELECT title INTO translation FROM chf_translations WHERE key_id = translation_id AND lang_id = site_lang; RETURN translation; END But get error: 1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 3 What can be wrong with this function?

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  • variable names in function definition, call and declaration

    - by yCalleecharan
    Hi, I see C books that use the same variable names in the function definition, calling function and declaration. Others use the same variable names in the calling function and in the declaration/prototype but a different one in the definition as in: void blabla(int something); //prototype blabla(something) // calling function inside main after something has been initialized to int void blabla(int something_else) //definition I have two questions: What convention is best to use in C?; Does the convention apply regardless whether a value is being passed "by-value" or if it's being passed by a pointer? Thanks a lot...

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  • Attach fancybox/lightbox/idontknowbox function on an element

    - by tanathos
    I'm developing a jquery gallery, and I want to parametrize the highlighter function to support any kind of lightboxes (fancybox for example). In my defaults I did something like: $.fn.mygallery.defaults = { functionHighlighter: null } so in the code, creating the item, I'll check this property, and if it's setted to a function, I want to call it on the element: if ((typeof opt.functionHighlighter) === "function") { opt.functionHighlighter.call(link); } where link is the anchor element containing the miniature image, with href setted to the original image. In my idea, when the plugin is called, I set the function with: $("#gallery").mygallery({ functionHighlighter: $.fancybox }); but the "call" on the functionHighlighter executes directly the fancybox, that returns an empty area. What I want to emulate is the execution of link.fancybox(); that correctly builds the plugin on link. Any ideas?

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  • Pass function as parameter in PHP

    - by Casidiablo
    Hello everybody! I've been wondering whether is possible or not to pass a function as parameter in PHP; I want something like when you're programming in JS: object.exampleMethod(function(){ // some stuff to execute }); What I want is to execute that function somewhere in exampleMethod. Is that possible in PHP? Thank you so much.

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  • Interface function C#

    - by user181421
    Hello, I have a function which implement an interface. something like this: string IMyInterface.MyFunction() { do something; } This function is available outside of my class. All working perfect. Now I also need to call this function from another LOCAL non public function. like this: void Func2() { string s; s = MyFunction(); } The problem is I get this error: "the name MyFunction does not exist in the current context local" Any help will be appreciated. TY.

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  • Returning char* in function

    - by Devel
    I have function: char *zap(char *ar) { char pie[100] = "INSERT INTO test (nazwa, liczba) VALUES ('nowy wpis', '"; char dru[] = "' )"; strcat(pie, ar); strcat(pie, dru); return pie; } and in main there is: printf("%s", zap( argv[1] ) ); When compiling I get the warning: test.c: In function ‘zap’: test.c:17: warning: function returns address of local variable How should I return char* propertly?

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  • function prototype declarations

    - by sandy101
    I am practice the function in c and come across to the program .... #include<stdio.h> int main() { float a=15.5; char ch ='C'; printit(a,ch); return 0; } printit(a,ch) { printf("%f\n%c",a,ch); } I want to know that why the above program compile and not give the error as i understood so for is ... The function in c must be declared with the specific prototype (but this program does not contain the prototype) why the program give the output 'x'for the char variable ? can the function in c are capable of accepting the value without being declared about type in parameters like what has done in the function declaration ?

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  • function with array variable

    - by mtokoly
    How do I pass an array through a function, for example: $data = array( 'color' => 'red', 'height' => 'tall' ); something($data); function something($data) { if ($data['color'] == 'red') { // do something } } how can I get the function to recognize $data[color] and $data[height]?

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  • how to load a page and then run a jquery function

    - by Khawar
    on master page i put this code to load page in same master page and then run jqeury function i m trying this $(document).ready(function() { $("#mainContactLink").click(function() { $(body).open("about-us.aspx", self); $(" #abtContacts").fadeIn(1000).siblings("div").fadeOut(100); $(" #abtContacts").siblings(); }); }); its not working.. any idea ?

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  • calling a function from another function in python

    - by user1040503
    I have written this function that takes to strings in order to see if they are anagrams: def anagram_check(str_x, str_y): x = string1.replace(" ","") y = string2.replace(" ","") lower1 = x.lower() lower2 = y.lower() sorted1 = sorted(lower1) sorted2 = sorted(lower2) if sorted1 == sorted2: return True else: return False this function works fine, the problem is that now I need to use this function in another function in order to find anagrams in a text file. I want to print a list of tuples with all the anagrams in it. this is what i have done so far def anagrams_finder(words_num): anagrams = [] f = open("words.txt") a = list(f) list1 = ([s.replace('\n', '') for s in a]) list2 = ([i.lower() for i in list1]) list3 = list2[0:words_num] #number of words from text that need to be checked. for i in list3: .... I tried using for loops, while loops, appand.... but nothing seems to work. how can I use the first function in order to help me with the second? Please help...

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  • PHP getimagesize is not working when is called from a function in function.php (Wordpress)?

    - by janoChen
    PHP getimagesize is not working when is called from a function in function.php. function.php: add_action('wp_head', 'get_image_size'); function get_image_size() { global $width; // I thought this would solve the problem but it didn't global $height; // I thought this would solve the problem but it didn't list($width, $height, $type, $attr) = getimagesize($options['logo']); echo "Image width " .$width; echo "<BR>"; echo "Image height " .$height; echo "<BR>"; } $options['logo'] is returning http://localhost/wordpress/wp-content/uploads/2010/12/logo4.png so the image is being displayed. I also did var_dump to $width and $height but they didn't show up. Any suggestions?

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