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  • Looping in Python and keeping current line after sub routine [migrated]

    - by Brendan
    I've been trying to nut out an issue when looping in python 3. When returning from sub routine the "line" variable has not incremented. How do I get the script to return the latest readline from the subsroutine? Code below def getData(line): #print(line) #while line in sTSDP_data: while "/service/content/test" not in line: line = sTSDP_data.readline() import os, sys sFileTSDP = "d:/ess/redo/Test.log" sTSDP_data = open(sFileTSDP, "r") for line in sTSDP_data: if "MOBITV" in line: getData(line) #call sub routine print(line)

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  • Automating release management and CI on python projects under mercurial VCS

    - by ms4py
    I have a set of Python projects which are under the mercurial VCS. I would like to automate the following tasks: Run the test suite for every commit (CI). Make a source distribution for every commit, which has a tag in mercurial. This is regarded as a new release. Copy the distribution to a special repository. There is Jenkins as a proposal for similar questions, but I'm not sure if it can handle the release management like intended.

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  • To make or not to make...python-nautilus a dependency?

    - by George Edison
    That is the question! Okay, all silliness aside, I really am forced to make a difficult decision here. My application is written in C++ and allows other scripts to invoke methods via XML-RPC. One of these scripts is a Nautilus extension written in Python. The extension is packaged with the rest of the application and copied to the appropriate place when installed (/usr/share/nautilus-python/extensions). Now the problem is that the Nautilus extension requires the python-nautilus package to be installed to be operational. So therefore I have three options: Make the python-nautilus package a dependency. This option will ensure that anyone who installs my package will be able to use the Nautilus extension. However, this option will not be attractive to XFCE or KDE users - a ton of python-nautilus's dependencies will be installed on their machines and take up a lot of space - even if they never use Nautilus. Put the python-nautilus package in the suggests: or recommends: field. This option provides the end-user with a way to avoid installing the python-nautilus package (by providing the --no-install-suggests or --no-install-recommends argument to apt-get). However, this won't work when the user installs the package in the Software Center. (I always get mixed up as to which of those two fields are installed by default.) Prompt the user when the application is installed or first launched. This option is more complicated than the others but offers the best compromise between making it easy for the user to install python-nautilus (without going into a technical explanation) and not installing it when the user doesn't need it (or want it). I guess the best way to implement this is a simple prompt that invokes apt-get if the user would like the package installed. Don't install the package at all. This option ensures that nobody has python-nautilus installed on their machine unless they want it. However, this also means that my Nautilus extension will simply not run on the end-user's machine unless they manually install the package. Which of these options seems the best choice? Have I missed any pros and cons for each of the options?

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  • How do I change my PYTHONPATH to make 3,2 my default Python instead of 2.7.2?

    - by max
    I have python3.2 located in /usr/lib/python3.2. I am not sure if that means it's installed but I assume it is for now. Some facts about my system: $ which python /usr/local/bin/python When I type python in terminal I get the following $ python Python 2.7.2 (default, Dec 19 2011, 11:12:13) [GCC 4.4.3] on linux2 Type "help", "copyright", "credits" or "license" for more information. Then to find the path I do >>> sys.info >>> sys.path ['', '/usr/local/lib/python2.7/site-packages/setuptools-0.6c11-py2.7.egg', '/usr/local/lib/python2.7/site-packages/pip-1.0.2-py2.7.egg', '/usr/local/lib/python2.7/site-packages/PIL-1.1.7-py2.7-linux-x86_64.egg', '/usr/local/lib/python27.zip', '/usr/local/lib/python2.7', '/usr/local/lib/python2.7/plat-linux2', '/usr/local/lib/python2.7/lib-tk', '/usr/local/lib/python2.7/lib-old', '/usr/local/lib/python2.7/lib-dynload', '/usr/local/lib/python2.7/site-packages'] So knowing all of this, how do I change my default system python from 2.7.2 to 3.2?

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  • Learning python, what to learn next to build a site?

    - by user1476145
    Hi everyone thanks for your help. I am currently learning python now through Think Python: How to Think Like a Computer Scientist. It is a great book, and is free online. I will learn more about python through Udacity and books online. After I learn python, what will I need to learn next to build a site? I want to build an interactive photo site. I will have to learn HTML. Do any of you know a good book or web site to learn HTML? I need to learn how to have python in HTML. As you know, I am using an editor now, but I need to learn how to use python to build a site. I am sorry that I am so ignorant. I just need some good books to read or courses to take. thank you so much, Luke

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  • Converting lib from other language to python and Rights issue

    - by Arruda
    If I take a program, and basically translate its source from some language to python, with some small changes, can I do a entirely my new lib or I have to make a "version" of the old one? would this be a copy of the first or a new lib based in the ideas of the first? OBS: Consider the original lib is using Apache License v2 Not sure if well explained, but I can't see for now how to make it more clear.

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  • Syntax error in Maya Python Script [on hold]

    - by Enchanter
    Ok this error is immensly frustrating as it is obviously a simple syntax issue. Basically I've written two lines of maya script in python designed to create a list of the names of all the joints of a model currently selected in the model viewer. Here are the two lines of script: import maya.cmds joints = ls(selection = true, type = 'joint') Upon compiling the code the script editor is saying there is a syntax error in the second line, but I do not see any reason why this code should not execute?

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  • Prettify working using python idle but not when using python script

    - by Loclip
    So when I use print soup.prettify() on idle it's prettifying my html but when I calling the script from server the prettify() not working #!/usr/bin/python import cgi, cgitb, urllib2, sys from bs4 import BeautifulSoup styles = [] i = 1 site = "www.example.com" page = urllib2.urlopen(site) soup = BeautifulSoup(page) table = soup.find('table', {'class' :'style5'}) alltd = table.findAll('td') allspans = table.findAll('span') while i<55: styles.append("style" + str(i)) i+=1 for td in alltd: if any(x in td["class"] for x in styles): td["class"] = "align" for span in allspans: span.replaceWithChildren() print "Content-type: text/html" print print "<!DOCTYPE html>" print "<html>" print "<head>" print '<meta http-equiv="content-type" content="text/html; charset=utf-8">' print '<link rel="stylesheet" href="lightbox/css/lightbox.css" type="text/css" media="screen">' print '<style type="text/css">' print "body {background-color:#b0c4de;}" print '.align {text-align: center;}' print "</style>" print "</head>" print "<body>" print table.pretiffy() print "</body>" print "</html>"

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  • Mac OS X: Update Python for Shell

    - by Nathan G.
    So, I see similar questions, but none of the answers work for me. I updated Python to 3.1.3 from 2.6.1. Everything works, except: When I type python into Terminal, I get: Python 2.6.1 (r261:67515, Jun 24 2010, 21:47:49) [GCC 4.2.1 (Apple Inc. build 5646)] on darwin Type "help", "copyright", "credits" or "license" for more information. >>> So, how do I change the version of Python that runs in the Shell? I've tried the script that they provide. It adds their directory to my $PATH, but it still doesn't change the version that'd displayed from Terminal. Here's what I get when I echo $PATH: /Library/Frameworks/Python.framework/Versions/3.1/bin:/Library/Frameworks/Python.framework/Versions/3.1/bin:/Library/Frameworks/Python.framework/Versions/3.1/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/usr/X11/bin It appears that the script provided has added their directory for every time I ran the script (I tried it a few times, naturally). I'll gives links to caps of what is in the other relevant folders it mentions: /Library/Frameworks/Python.framework/Versions/3.1/bin /usr/local/bin /usr/bin Thakns in advance for any ideas!

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  • Cant fetch production db results using Google app engine remote_api

    - by Alon
    Hey, im trying to work out with /remote_api with a django-patch app engine app i got running. i want to select a few rows from my online production app locally. i cant seem to manage todo so, everything authenticates fine, it doesnt breaks on imports, but when i try to fetch something it just doesnt print anything. Placed the test python inside my local app dir. #!/usr/bin/env python # import os import sys # Hardwire in appengine modules to PYTHONPATH # or use wrapper to do it more elegantly appengine_dirs = ['myworkingpath'] sys.path.extend(appengine_dirs) # Add your models to path my_root_dir = os.path.abspath(os.path.dirname(__file__)) sys.path.insert(0, my_root_dir) from google.appengine.ext import db from google.appengine.ext.remote_api import remote_api_stub import getpass APP_NAME = 'Myappname' os.environ['AUTH_DOMAIN'] = 'gmail.com' os.environ['USER_EMAIL'] = '[email protected]' def auth_func(): return (raw_input('Username:'), getpass.getpass('Password:')) # Use local dev server by passing in as parameter: # servername='localhost:8080' # Otherwise, remote_api assumes you are targeting APP_NAME.appspot.com remote_api_stub.ConfigureRemoteDatastore(APP_NAME, '/remote_api', auth_func) # Do stuff like your code was running on App Engine from channel.models import Channel, Channel2Operator myresults = mymodel.all().fetch(10) for result in myresults: print result.key() it doesnt give any error or print anything. so does the remote_api console example google got. when i print the myresults i get [].

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  • python pdb not breaking in files properly?

    - by YGA
    Hi Folks, I wish I could provide a simple sample case that occurs using standard library code, but unfortunately it only happens when using one of our in-house libraries that in turn is built on top of sql alchemy. Basically, the problem is that this break command: (Pdb) print sqlalchemy.engine.base.__file__ /prod/eggs/SQLAlchemy-0.5.5-py2.5.egg/sqlalchemy/engine/base.py (Pdb) break /prod/eggs/SQLAlchemy-0.5.5-py2.5.egg/sqlalchemy/engine/base.py:946 Is just being totally ignored, it seems, by pdb. As in, even though I am positive the code is being hit (both because I can see log messages, and because I've used sys.settrace to check which lines in which files are being hit), pdb is just not breaking there. I suspect that somehow the use of an egg is confusing pdb as to what files are being used (I can't reproduce the error if I use a non-egg'ed library, like pickle; there everything works fine). It's a shot in the dark, but has anyone come across this before? Thanks, /YGA

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  • Python - CSV: Large file with rows of different lengths

    - by dassouki
    In short, I have a 20,000,000 line csv file that has different row lengths. This is due to archaic data loggers and proprietary formats. We get the end result as a csv file in the following format. MY goal is to insert this file into a postgres database. How Can I do the following: Keep the first 8 columns and my last 2 columns, to have a consistent CSV file Add a Column to the file. 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0, img_id.jpg, -50 1, 2, 3, 4, 5, 0,0,0,0,0,0,0,0,0,0,0 img_id.jpg, -50

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  • Using httplib2 in python 3 properly? (Timeout problems)

    - by Sho Minamimoto
    Hey, first time post, I'm really stuck on httplib2. I've been reading up on it from diveintopython3.org, but it mentions nothing about a timeout function. I look up the documentation, but the only thing I see is an ability to put a timeout int but there are no units specified (seconds? milliseconds? What's the default if None?) This is what I have (I also have code to check what the response is and try again, but it's never tried more than once) h = httplib2.Http('.cache', timeout=None) for url in list: response, content = h.request(url) more stuff... So the Http object stays around until some arbitrary time, but I'm downloading a ton of pages from the same server, and after a while, it hangs on getting a page. No errors are thrown, the thing just hangs at a page. So then I try: h = httplib2.Http('.cache', timeout=None) for url in list: try: response, content = h.request(url) except: h = httplib2.Http('.cache', timeout=None) more stuff... But then it recreates another Http object every time (goes down the 'except' path)...I dont understand how to keep getting with the same object, until it expires and I make another. Also, is there a way to set a timeout on an individual request? Thanks for the help!

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  • Generating permutation in Python with specific rule

    - by twfx
    Let say a=[A, B, C, D], each element has a weight w, and is set to 1 if selected, 0 if otherwise. I'd like to generate permutation in the below order 1,1,1,1 1,1,1,0 1,1,0,1 1,1,0,0 1,0,1,1 1,0,1,0 1,0,0,1 1,0,0,0 Let's w=[1,2,3,4] for item A,B,C,D ... and max_weight = 4. For each permutation, if the accum weight has exceeded max_weight, stop calculation for that permutation, move to next permutation. For eg. 1,1,1 --> 6 > 4, exceeded, stop, move to next 1,1,1 --> 6 > 4, exceeded, stop, move to next 1,1,0,1 --> 7 > 4 finished, move to next 1,1,0,0 --> 3 finished, move to next 1,0,1,1 --> 8 > 4, finished, stop, move to next 1,0,1,0 --> 4 finished, move to next 1,0,0,1 --> 5 > 4 finished, move to next 1,0,0,0 --> 1 finished, move to next [1,0,1,0] is the best combination which does not exceeded max_weight 4 My questions are What's the algorithm which generate the required permutation? Or any suggestion I could generate the permutation? As the number of element can be up to 10000, and the calculation stop if the accum weight for the branch exceeds max_weight, it is not necessary to generate all permutation first before the calculation. How can the algo in (1) generate permutation on the fly?

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  • How to build sqlite for Python 2.4?

    - by Verrtex
    I would like to use pysqlite interface between Python and sdlite database. I have already Python and SQLite on my computer. But I have troubles with installation of pysqlite. During the installation I get the following error message: error: command 'gcc' failed with exit status 1 As far as I understood the problems appears because version of my Python is 2.4.3 and SQLite is integrated in Python since 2.5. However, I also found out that it IS possible to build sqlite for Python 2.4 (using some tricks, probably). Does anybody know how to build sqlite for Python 2.4? As another option I could try to install higher version of Python. However I do not have root privileges. Does anybody know what will be the easiest way to solve the problem (build SQLite fro Python 2.4, or install newer version of Python)? I have to mention that I would not like to overwrite the old version version of Python. Thank you in advance.

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  • How is the 'is' keyword implemented in Python?

    - by Srikanth
    ... the is keyword that can be used for equality in strings. >>> s = 'str' >>> s is 'str' True >>> s is 'st' False I tried both __is__() and __eq__() but they didn't work. >>> class MyString: ... def __init__(self): ... self.s = 'string' ... def __is__(self, s): ... return self.s == s ... >>> >>> >>> m = MyString() >>> m is 'ss' False >>> m is 'string' # <--- Expected to work False >>> >>> class MyString: ... def __init__(self): ... self.s = 'string' ... def __eq__(self, s): ... return self.s == s ... >>> >>> m = MyString() >>> m is 'ss' False >>> m is 'string' # <--- Expected to work, but again failed False >>> Thanks for your help!

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  • Python try...except comma vs 'as' in except

    - by peter
    What is the difference between ',' and 'as' in except statements, eg: try: pass except Exception, exception: pass and: try: pass except Exception as exception: pass Is the second syntax legal in 2.6? It works in CPython 2.6 on Windows but the 2.5 interpreter in cygwin complains that it is invalid. If they are both valid in 2.6 which should I use?

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  • importing files in python

    - by Yosy
    I have that file structure- Blog\DataObjects\User.py Blog\index.py I want to import the function(say_hello) at User.py from index.py. I am trying this code - from Blog.DataObjects.User import say_hello say_hello() And I have that error - Traceback (most recent call last): File "index.py", line 1, in <module> from Blog.DataObjects import User ImportError: No module named Blog.DataObjects

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  • python __getattr__ help

    - by Stefanos Tux Zacharakis
    Reading a Book, i came across this code... # module person.py class Person: def __init__(self, name, job=None, pay=0): self.name = name self.job = job self.pay = pay def lastName(self): return self.name.split()[-1] def giveRaise(self, percent): self.pay = int(self.pay *(1 + percent)) def __str__(self): return "[Person: %s, %s]" % (self.name,self.pay) class Manager(): def __init__(self, name, pay): self.person = Person(name, "mgr", pay) def giveRaise(self, percent, bonus=.10): self.person.giveRaise(percent + bonus) def __getattr__(self, attr): return getattr(self.person, attr) def __str__(self): return str(self.person) It does what I want it to do, but i do not understand the __getattr__ function in the Manager class. I know that it Delegates all other attributes from Person class. but I do not understand the way it works. for example why from Person class? as I do not explicitly tell it to. person(module is different than Person(class) Any help is highly appreciated :)

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  • Python with PIL and Libjpeg on Leopard

    - by thescreamingdrills
    I'm having trouble getting pictures supported with PIL - it throws me this: "IOError: decoder jpeg not available" I installed PIL from binary, not realizing I needed libjpeg. I installed libjpeg and freetype2 through fink. I tried to reinstall PIL using instructions from http://timhatch.com/ (bottom of the page) "* Download PIL 1.1.6 source package and have the Developer Tools already installed * Patch setup.py with this patch so it can find the Freetype you already have. (patch -p0 < leopard_freetype2.diff) * sudo apt-get install libjpeg if you have fink (otherwise, build by hand and adjust paths)" But I'm still getting the same error. I'm on Leopard PPC.

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  • insert multiple elements in string in python

    - by Anurag Sharma
    I have to build a string like this { name: "john", url: "www.dkd.com", email: "[email protected]" } where john, www.dkd.com and [email protected] are to be supplied by variables I tried to do the following s1 = "{'name:' {0},'url:' {1},'emailid:' {2}}" s1.format("john","www.dkd.com","[email protected]") I am getting the following error Traceback (most recent call last): File "<stdin>", line 1, in <module> KeyError: "'name" Dont able to understand what I am doing wrong

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  • importing files at python

    - by Yosy
    I have that file strudctue- Blog\DataObjects\User.py Blog\index.py I want to import the function(say_hello) at User.py from index.py. I am trying this code - from Blog.DataObjects.User import say_hello say_hello() And I have that error - Traceback (most recent call last): File "index.py", line 1, in from Blog.DataObjects import User ImportError: No module named Blog.DataObjects

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