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  • SQL SERVER – Finding Different ColumnName From Almost Identitical Tables

    - by pinaldave
    I have mentioned earlier on this blog that I love social media – Facebook and Twitter. I receive so many interesting questions that sometimes I wonder how come I never faced them in my real life scenario. Well, let us see one of the similar situation. Here is one of the questions which I received on my social media handle. “Pinal, I have a large database. I did not develop this database but I have inherited this database. In our database we have many tables but all the tables are in pairs. We have one archive table and one current table. Now here is interesting situation. For a while due to some reason our organization has stopped paying attention to archive data. We did not archive anything for a while. If this was not enough we  even changed the schema of current table but did not change the corresponding archive table. This is now becoming a huge huge problem. We know for sure that in current table we have added few column but we do not know which ones. Is there any way we can figure out what are the new column added in the current table and does not exist in the archive tables? We cannot use any third party tool. Would you please guide us?” Well here is the interesting example of how we can use sys.column catalogue views and get the details of the newly added column. I have previously written about EXCEPT over here which is very similar to MINUS of Oracle. In following example we are going to create two tables. One of the tables has extra column. In our resultset we will get the name of the extra column as we are comparing the catalogue view of the column name. USE AdventureWorks2012 GO CREATE TABLE ArchiveTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100)); CREATE TABLE CurrentTable (ID INT, Col1 VARCHAR(10), Col2 VARCHAR(100), Col3 VARCHAR(100), ExtraCol INT); GO -- Columns in ArchiveTable but not in CurrentTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' GO -- Columns in CurrentTable but not in ArchiveTable SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'CurrentTable' EXCEPT SELECT name ColumnName FROM sys.columns WHERE OBJECT_NAME(OBJECT_ID) = 'ArchiveTable' GO DROP TABLE ArchiveTable; DROP TABLE CurrentTable; GO The above query will return us following result. I hope this solves the problems. It is not the most elegant solution ever possible but it works. Here is the puzzle back to you – what native T-SQL solution would you have provided in this situation? Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology

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  • MySQL "ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150)"

    - by Ankur Banerjee
    Hi, I was working on creating some tables in database foo, but every time I end up with errno 150 regarding the foreign key. Firstly, here's my code for creating tables: CREATE TABLE Clients ( client_id CHAR(10) NOT NULL , client_name CHAR(50) NOT NULL , provisional_license_num CHAR(50) NOT NULL , client_address CHAR(50) NULL , client_city CHAR(50) NULL , client_county CHAR(50) NULL , client_zip CHAR(10) NULL , client_phone INT NULL , client_email CHAR(255) NULL , client_dob DATETIME NULL , test_attempts INT NULL ); CREATE TABLE Applications ( application_id CHAR(10) NOT NULL , office_id INT NOT NULL , client_id CHAR(10) NOT NULL , instructor_id CHAR(10) NOT NULL , car_id CHAR(10) NOT NULL , application_date DATETIME NULL ); CREATE TABLE Instructors ( instructor_id CHAR(10) NOT NULL , office_id INT NOT NULL , instructor_name CHAR(50) NOT NULL , instructor_address CHAR(50) NULL , instructor_city CHAR(50) NULL , instructor_county CHAR(50) NULL , instructor_zip CHAR(10) NULL , instructor_phone INT NULL , instructor_email CHAR(255) NULL , instructor_dob DATETIME NULL , lessons_given INT NULL ); CREATE TABLE Cars ( car_id CHAR(10) NOT NULL , office_id INT NOT NULL , engine_serial_num CHAR(10) NULL , registration_num CHAR(10) NULL , car_make CHAR(50) NULL , car_model CHAR(50) NULL ); CREATE TABLE Offices ( office_id INT NOT NULL , office_address CHAR(50) NULL , office_city CHAR(50) NULL , office_County CHAR(50) NULL , office_zip CHAR(10) NULL , office_phone INT NULL , office_email CHAR(255) NULL ); CREATE TABLE Lessons ( lesson_num INT NOT NULL , client_id CHAR(10) NOT NULL , date DATETIME NOT NULL , time DATETIME NOT NULL , milegage_used DECIMAL(5, 2) NULL , progress CHAR(50) NULL ); CREATE TABLE DrivingTests ( test_num INT NOT NULL , client_id CHAR(10) NOT NULL , test_date DATETIME NOT NULL , seat_num INT NOT NULL , score INT NULL , test_notes CHAR(255) NULL ); ALTER TABLE Clients ADD PRIMARY KEY (client_id); ALTER TABLE Applications ADD PRIMARY KEY (application_id); ALTER TABLE Instructors ADD PRIMARY KEY (instructor_id); ALTER TABLE Offices ADD PRIMARY KEY (office_id); ALTER TABLE Lessons ADD PRIMARY KEY (lesson_num); ALTER TABLE DrivingTests ADD PRIMARY KEY (test_num); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Instructors FOREIGN KEY (instructor_id) REFERENCES Instructors (instructor_id); ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ALTER TABLE Lessons ADD CONSTRAINT FK_Lessons_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); ALTER TABLE Cars ADD CONSTRAINT FK_Cars_Offices FOREIGN KEY (office_id) REFERENCES Offices (office_id); ALTER TABLE Clients ADD CONSTRAINT FK_DrivingTests_Clients FOREIGN KEY (client_id) REFERENCES Clients (client_id); These are the errors that I get: mysql> ALTER TABLE Applications ADD CONSTRAINT FK_Applications_Cars FOREIGN KEY (car_id) REFERENCES Cars (car_id); ERROR 1005 (HY000): Can't create table 'foo.#sql-12c_4' (errno: 150) I ran SHOW ENGINE INNODB STATUS which gives a more detailed error description: ------------------------ LATEST FOREIGN KEY ERROR ------------------------ 100509 20:59:49 Error in foreign key constraint of table practice9/#sql-12c_4: FOREIGN KEY (car_id) REFERENCES Cars (car_id): Cannot find an index in the referenced table where the referenced columns appear as the first columns, or column types in the table and the referenced table do not match for constraint. Note that the internal storage type of ENUM and SET changed in tables created with >= InnoDB-4.1.12, and such columns in old tables cannot be referenced by such columns in new tables. See http://dev.mysql.com/doc/refman/5.1/en/innodb-foreign-key-constraints.html for correct foreign key definition. ------------ I searched around on StackOverflow and elsewhere online - came across a helpful blog post here with pointers on how to resolve this error - but I can't figure out what's going wrong. Any help would be appreciated!

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  • CSS: Labels in table columns

    - by hello
    Hello. BACKGROUND: I would like to have small labels in columns of a table. I'm using some implemented parts of HTML5/CSS3 in my project, and this section specifically is for mobile devices. While both facts are not necessarily relevant, the bottom line is that I don't have to support Internet Explorer or even Firefox for that matter (just WebKit). THE PROBLEM With my current CSS approach, the vertical padding of the cell comes from the <span element (set to display: block with top/bottom margins), which contains the "value" of the column. As a result there's no padding when the <span> is empty or missing (no value) and the label is not in place. The "full" coulmns should give you the idea of where I want the labels to be, even if there's no value, and the <span> is not there. I realize that I could use "non-breaking-space", but I would really like to avoid it. I wonder if any of you have a fix / better way to do this? current code is below. Thank you for any help. <!DOCTYPE html> <html lang="en"> <head> <title>ah</title> <style> body { width: 320px; } /* TABLE */ table { width: 100%; border-collapse: collapse; font-family: arial; } th, td { border: 1px solid #ccc; border-width: 0px 0px 1px 1px; } th:last-child, td:last-child { border-right-width: 1px; } tr:first-child th { border-top-width: 1px; background: #efefef; } /* RELEVANT STUFF */ td { padding: 3px; } td sup { display: block; } td span { display: block; margin: 3px 0px; text-align: center; } </style> </head> <body> <table> <tr> <th colspan="3">something</th> </tr> <tr> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span>any content</span></td> <td><sup>some label</sup><span></span></td><!-- No content, just a label --> </tr> </table> </body> </html>

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  • PHP: table structure

    - by A3efan
    I'm developing a website that has some audio courses, each course can have multiple lessons. I want to display each course in its own table with its different lessons. This is my sql statement: Table: courses id, title Table: lessons id, cid (course id), title, date, file $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; Can someone help me with the PHP code? This is the I code I have written: mysql_select_db($database_config, $config); mysql_query("set names utf8"); $sql = "SELECT lessons.*, courses.title AS course FROM lessons INNER JOIN courses ON courses.id = lessons.cid GROUP BY lessons.id ORDER BY lessons.id" ; $result = mysql_query($sql) or die(mysql_error()); while ($row = mysql_fetch_assoc($result)) { echo "<p><span class='heading1'>" . $row['course'] . "</span> </p> "; echo "<p class='datum'>Posted onder <a href='*'>*</a>, latest update on " . strftime("%A %d %B %Y %H:%M", strtotime($row['date'])); } echo "</p>"; echo "<class id='text'>"; echo "<p>...</p>"; echo "<table border: none cellpadding='1' cellspacing='1'>"; echo "<tr>"; echo "<th>Nr.</th>"; echo "<th width='450'>Lesso</th>"; echo "<th>Date</th>"; echo "<th>Download</th>"; echo "</tr>"; echo "<tr>"; echo "<td>" . $row['nr'] . "</td>"; echo "<td>" . $row['title'] . "</td>"; echo "<td>" . strftime("%d/%m/%Y", strtotime($row['date'])) . "</td>"; echo "<td><a href='audio/" . rawurlencode($row['file']) . "'>MP3</a></td>"; echo "</tr>"; echo "</table>"; echo "<br>"; } ?>

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  • How to Navigate Directly From One Table to Another in Word 2013

    - by Lori Kaufman
    Jumping to a specific page in Word is a common task and easy to do using the Find and Replace dialog box. You can also use this same tab to jump from one table directly to the next table in your document. Your cursor does not have to be in a table to jump to the next table. Put the cursor in any paragraph or table and press F5 or use the Ctrl + G keystroke combination to open the Find and Replace dialog box. The Go To tab is automatically selected. Select Table from the Go to what list and click Next. The next table in your document is selected and the Find and Replace dialog box stays open.    

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  • T-SQL User-Defined Functions: the good, the bad, and the ugly (part 4)

    - by Hugo Kornelis
    Scalar user-defined functions are bad for performance. I already showed that for T-SQL scalar user-defined functions without and with data access, and for most CLR scalar user-defined functions without data access , and in this blog post I will show that CLR scalar user-defined functions with data access fit into that picture. First attempt Sticking to my simplistic example of finding the triple of an integer value by reading it from a pre-populated lookup table and following the standard recommendations...(read more)

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  • Subquery using derived table in Hibernate HQL

    - by Vladimir
    I have a Hibernate HQL question. I'd like to write a subquery as a derived table (for performance reasons). Is it possible to do that in HQL? Example: FROM Customer WHERE country.id in (SELECT id FROM (SELECT id FROM Country where type='GREEN') derivedTable) (btw, this is just a sample query so don't give advices on rewriting it, is just the derived table concept I'm interested in) Thanks.

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  • ExtJS: Adding table inside a dynamically added tab

    - by esskar
    Hi, i'm fairly new to ExtJS. I adopted some examples and added the functionality to add tabs to a tab-control by clicking on some link. so far so good. now i want to load a ExtJS table into on of the new tabs. the items (rows, columns) are defined in a database on the server side. can you give me some hints how to add the table automatically when the tab is created?

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  • SQLite3, "ALTER TABLE" and durability

    - by Bill
    I'd like to run some ALTER TABLE statements on a sqlite3 database. What happens if the user kills the process or the power is cut while the ALTER TABLE is running? Will the database be left in a corrupt intermediate state?

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  • Table-Valued Parameter in Stored Procedure and the Entity Framework 4.0

    - by Fabio
    Hi there, I have a stored procedure called 'GetPrices' with a Table-Valued Parameter called 'StoreIDs' and I would like to call it from my Entity Framework. But when I try to add the Stored Procedure to the EDM, i get the following error: The function 'GetPrices' has a parameter 'StoreIDs' at parameter index 2 that has a data type 'table type' which is not supported. The function was excluded. Is there any workaround this? Any thoughts? Fabio

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  • Flex: How to most effectively tavere a table column

    - by Maik
    I have a table "template" which is used in various "instances". All instances have checkboxes in the second column (for record-delete). What would be the most effective way of traversing the table and check if at least one checkbox is selected (to enable a "delete" button)? Thanks! Maik

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  • table with black outer, but grey inner border

    - by Jan-Frederik Carl
    Hello, I want to create a html table with a 1pt black outer border and the same border around every td. Should look like this (only the borders, of course) link text I use <table border="1" style="border-collapse:collapse; border-color:Black; border-style:solid; border-width:1pt"> As a result I get a black outer, but grey inner borders.

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  • mysql create table help with unique

    - by Matt
    I'm trying to create a table, and can't figure out how to assign two columns to be unique.. I know how to alter a table thats already created, but how do you do it in the create.. im after a create if not exist col1 TEXT, col2 TEXT, col3 TEXT unique(col1, col2) ^very rough basic but you get the idea

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  • [solved] PHP-called hyperlink stopped showing when CSS table implemented

    - by Luke
    EDIT: Solved - was not flutter's tag stripping, should work as advertised. I'm using Flutter (which creates custom fields) in Wordpress to display profile information entered as a Post. Before I implemented the CSS tables the link showed up and was clickable. Now I get nothing returned, even when I try to call the link outside the table. If you know anything about this, here's my code in the index.php file and I remain available for any questions. <?php if (in_category('Profile')) { ?> <table id="mytable" cellspacing="0"> -snip- <tr> <th class="row1" valign="top">Website </td> <td>Link: <a href="<?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?>"> <?php echo get_post_meta($post->ID, 'FrWebsite', $single=true) ?></a></td> </tr> -snip- </table> Thanks, L Edit: @Josh - there is a foreach looping construct in the table and it is reading and displaying the code correctly, I see what you're getting at now: <tr> <th class="row2" valign="top">Specialities </td> <td class="alt" valign="top"><?php $my_array = get('Expertise'); $output = ""; foreach($my_array as $check) { $output .= "<span>$check</span><br/> "; } echo $output; ?></td> </tr> Edit - @Josh - here's the old code as far as I can remember it, there was no major difference just a <td> tag where there now stands a <th>, there wasn't the class="" and there was no "Link:" and FrWebsite was called Website, but it still didn't work when called Website so I changed to see if that was the error. <tr> <td width="200" valign="top">Website </td> <td><a href="<?php echo get_post_meta($post->ID, 'Website', $single=true) ?>"><?php echo get_post_meta($post->ID, 'Website', $single=true) ?></a></td> </tr>

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  • create a text table with php using fixed width font

    - by Hintswen
    I want to write a PHP script to output some data as a plain-text table using spaces to get the data into columns (just like the Linux top command). I can't use a HTML table as the script output will be saved to disk and viewed in a plain-text editor. Is there anything available that can do this automatically (format the data into columns)?

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  • SQLite3 table not accepting INSERT INTO statements. The table is created, and so is the database, but nothing is passed into it

    - by user1460029
    <?php try { //open the database $db = new PDO('sqlite:music.db'); $db->exec("DELETE from Music;"); $db->exec("INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Whatd I Say', 'Ray Charles', '1956');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Smells Like Teen Spirit.', 'Nirvana', '1991');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Hey Jude', 'The Beatles', '1968');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Johnny B. Goode', 'Chuck Berry', '1958');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Good Vibrations', 'The Beach Boys', '1966');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Respect', 'Aretha Franklin', '1967');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Whats Going On', 'Marvin Gaye', '1971');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Imagine', 'John Lennon', '1971');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('(I Cant Get No) Satisfaction', 'Rolling Stones', '1965');" . "INSERT INTO Music(Title, Author, ReleaseDate) VALUES ('Like A Rolling Stone', 'Bob Dylan', '1965');"); //now output the data to a simple html table... //example of specifier --> WHERE First=\'Josh\'; <-- print "<table border=1>"; print "<tr><td>Title</td><td>Author</td><td>Y.O.P.</td></tr>"; $result = $db->query('SELECT * FROM Music '); foreach($result as $row) { print "<td>".$row['Title']."</td>"; print "<td>".$row['Author']."</td>"; print "<td>".$row['ReleaseDate']."</td></tr>"; } print "</table>"; $db = NULL; } catch(PDOException $e) { print 'Exception : '.$e->getMessage(); } ?> I am not sure why nothing is being inserted into the table. The file 'music.db' exists in the right path. For the record, I can only use SQlite3, no SQL allowed. PHP is allowed, so is SQLite3.

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  • Keeping a certain row or column in an HTML table fixed

    - by WarDoGG
    I have huge amounts of data populating an HTML <table> having more than 200 rows and 200 columns. However, when i scroll the page horizontally or vertically to view the data, the header columns (like th for instance) go beyond the page. How can i scroll through the table and still keep the top row and leftmost column fixed so that i will always know what data im seeing.

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  • ALTER TABLE error

    - by Travis
    Can someone explain to me why I am receiving the following error? I want to rename the column "exerciseID" to "ID" in a mysql table using the following syntax. ALTER TABLE `exercises` CHANGE `exerciseID` `ID` INT( 11 ) NOT NULL AUTO_INCREMENT However I receive the following error: MySQL said: #1025 - Error on rename of './balance/#sql-de_110e' to './balance/exercises' (errno: 150) Any suggestions would be much appreciated

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  • Which Oracle table uses a sequence?

    - by Jaú
    Having a sequence, I need to find out which table.column gets its values. As far as I know, Oracle doesn't keep track of this relationship. So, looking up for the sequence in source code would be the only way. Is that right? Anyone knows of some way to find out this sequence-table relationship?

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  • SQL DROP TABLE foreign key constraint

    - by Polly Hollanger
    If I want to delete all the tables in my database like this, will it take care of the foreign key constraint? If not, how do I take care of that first? GO IF OBJECT_ID('dbo.[Course]','U') IS NOT NULL DROP TABLE dbo.[Course] GO IF OBJECT_ID('dbo.[Student]','U') IS NOT NULL DROP TABLE dbo.[Student]

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