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  • Remove duplicates from a list of nested dictionaries

    - by user2924306
    I'm writing my first python program to manage users in Atlassian On Demand using their RESTful API. I call the users/search?username= API to retrieve lists of users, which returns JSON. The results is a list of complex dictionary types that look something like this: [ { "self": "http://www.example.com/jira/rest/api/2/user?username=fred", "name": "fred", "avatarUrls": { "24x24": "http://www.example.com/jira/secure/useravatar?size=small&ownerId=fred", "16x16": "http://www.example.com/jira/secure/useravatar?size=xsmall&ownerId=fred", "32x32": "http://www.example.com/jira/secure/useravatar?size=medium&ownerId=fred", "48x48": "http://www.example.com/jira/secure/useravatar?size=large&ownerId=fred" }, "displayName": "Fred F. User", "active": false }, { "self": "http://www.example.com/jira/rest/api/2/user?username=andrew", "name": "andrew", "avatarUrls": { "24x24": "http://www.example.com/jira/secure/useravatar?size=small&ownerId=andrew", "16x16": "http://www.example.com/jira/secure/useravatar?size=xsmall&ownerId=andrew", "32x32": "http://www.example.com/jira/secure/useravatar?size=medium&ownerId=andrew", "48x48": "http://www.example.com/jira/secure/useravatar?size=large&ownerId=andrew" }, "displayName": "Andrew Anderson", "active": false } ] I'm calling this multiple times and thus getting duplicate people in my results. I have been searching and reading but cannot figure out how to deduplicate this list. I figured out how to sort this list using a lambda function. I realize I could sort the list, then iterate and delete duplicates. I'm thinking there must be a more elegant solution. Thank you!

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  • How to move list items from two lists (from different areas) to one specific list by clicking the li

    - by pschorr
    I've been having some issues setting up a list of items and moving them between each other. Is it possible to have multiple lists, with a link inside each item to move it to a specified list? i.e. List of actions with a plus next to the action, click the plus and move to a specified box? Furthermore, would it be possible to then load a lightbox (code would have to be inline I'd guess) from that page and move those names to the specific list as well? Example Images Thanks much! More broad view of my efforts so far... The initial issue being that I could not use listboxes due to their being rendered natively inside each individual browser. Through listboxes I was able to set this up, but with a trigger via the code below (found on stackoverflow). While it gave me partial functionality it did not get the target I was looking for. document.getElementById('moveTrigger').onclick = function() { var listTwo = document.getElementById('secondList'); var options = document.getElementById('firstList').getElementsByTagName('option'); while(options.length != 0) { listTwo.appendChild(options[0]); } } I then moved onto jqueryui's sortable and it's ability to connect multiple, and most important, style-able lists and to be dragged between each other. This works for the side by side tables, but it does not offer the usability I was looking for overall. So, I've come to where I'm unsure as to where to move forward. While I can get around PHP, I wouldn't know where to start with this one personally. I'm open to any and all options! Thanks much!

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  • Flex custom list selection not highlighting

    - by aip.cd.aish
    I want to create a custom list in Flex for an interface prototype. The list is supposed to have an image and 3 text fields. This is what I have done so far, the control displayed is what I want. But, when I click on one of the items, the item does not appear (visually) to be selected. I was not sure how I would implement this. Here is my code so far: <s:List width="400" height="220" dataProvider="{arrColl}" alternatingItemColors="[#EEEEEE, white]"> <s:itemRenderer> <fx:Component> <mx:Canvas height="100"> <mx:Image height="90" width="120" source="{data.imageSource}"></mx:Image> <mx:Label left="125" y="10" text="{data.title}" /> <mx:Label left="125" y="30" text="{data.type}" /> <mx:Label left="125" y="50" text="{data.description}" /> </mx:Canvas> </fx:Component> </s:itemRenderer> </s:List>

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  • Appending unique values only in a linked list in C

    - by LuckySlevin
    typedef struct child {int count; char word[100]; inner_list*next;} child; typedef struct parent { char data [100]; inner_list * head; int count; outer_list * next; } parent; void append(child **q,char num[100],int size) { child *temp,*r,*temp2,*temp3; parent *out=NULL; temp = *q; temp2 = *q; temp3 = *q; char *str; if(*q==NULL) { temp = (child *)malloc(sizeof(child)); strcpy(temp->word,num); temp->count =size; temp->next=NULL; *q=temp; } else { temp = *q; while(temp->next !=NULL) { temp=temp->next; } r = (child *)malloc(sizeof(child)); strcpy(r->word,num); r->count = size; r->next=NULL; temp->next=r; } } This is my append function which I use for adding an element to my child list. But my problem is it only should append unique values which are followed by a string. Which means : Inputs : aaa bbb aaa ccc aaa bbb ccc aaa Append should act : For aaa string there should be a list like bbb->ccc(Not bbb->ccc->bbb since bbb is already there if bbb is coming more than one time it should be increase count only.) For bbb string there should be list like aaa->ccc only For ccc string there should be list like aaa only I hope i could make myself clear. Is there any ideas? Please ask for further info.

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  • Handling Apache Thrift list/map Return Types in C++

    - by initzero
    First off, I'll say I'm not the most competent C++ programmer, but I'm learning, and enjoying the power of Thrift. I've implemented a Thrift Service with some basic functions that return void, i32, and list. I'm using a Python client controlled by a Django web app to make RPC calls and it works pretty well. The generated code is pretty straight forward, except for list returns: namespace cpp Remote enum N_PROTO { N_TCP, N_UDP, N_ANY } service Rcon { i32 ping() i32 KillFlows() i32 RestartDispatch() i32 PrintActiveFlows() i32 PrintActiveListeners(1:i32 proto) list<string> ListAllFlows() } The generated signatures from Rcon.h: int32_t ping(); int32_t KillFlows(); int32_t RestartDispatch(); int32_t PrintActiveFlows(); int32_t PrintActiveListeners(const int32_t proto); int64_t ListenerBytesReceived(const int32_t id); void ListAllFlows(std::vector<std::string> & _return); As you see, the ListAllFlows() function generated takes a reference to a vector of strings. I guess I expect it to return a vector of strings as laid out in the .thrift description. I'm wondering if I am meant to provide the function a vector of strings to modify and then Thrift will handle returning it to my client despite the function returning void. I can find absolutely no resources or example usages of Thrift list< types in C++. Any guidance would be appreciated.

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  • Working with a list, performing arithmetic logic in Python

    - by haea ohoh
    Suppose I have made a large list of numbers, and I want to make another one which I will add, pairwise, with the first list. Here's the first list, A: [109, 77, 57, 34, 94, 68, 96, 72, 39, 67, 49, 71, 121, 89, 61, 84, 45, 40, 104, 68, 54, 60, 68, 62, 91, 45, 41, 118, 44, 35, 53, 86, 41, 63, 111, 112, 54, 34, 52, 72, 111, 113, 47, 91, 107, 114, 105, 91, 57, 86, 32, 109, 84, 85, 114, 48, 105, 109, 68, 57, 78, 111, 64, 55, 97, 85, 40, 100, 74, 34, 94, 78, 57, 77, 94, 46, 95, 60, 42, 44, 68, 89, 113, 66, 112, 60, 40, 110, 89, 105, 113, 90, 73, 44, 39, 55, 108, 110, 64, 108] And here's B: [35, 106, 55, 61, 81, 109, 82, 85, 71, 55, 59, 38, 112, 92, 59, 37, 46, 55, 89, 63, 73, 119, 70, 76, 100, 49, 117, 77, 37, 62, 65, 115, 93, 34, 107, 102, 91, 58, 82, 119, 75, 117, 34, 112, 121, 58, 79, 69, 68, 72, 110, 43, 111, 51, 102, 39, 52, 62, 75, 118, 62, 46, 74, 77, 82, 81, 36, 87, 80, 56, 47, 41, 92, 102, 101, 66, 109, 108, 97, 49, 72, 74, 93, 114, 55, 116, 66, 93, 56, 56, 93, 99, 96, 115, 93, 111, 57, 105, 35, 99] How might I generate the arithmatic addition logic, processing each pairwise value one by one (A[0] and B[0], through A[99], B[99]) and producing the list C (A[0] + B[0] through A[99]+ B[99])?

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  • Creating a dictionary with list of lists in Python

    - by ghbhatt
    I have a huge file (with around 200k inputs). The inputs are in the form: A B C D B E F C A B D D I am reading this file and storing it in a list as follows: text = f.read().split('\n') This splits the file whenever it sees a new line. Hence text is like follows: [[A B C D] [B E F] [C A B D] [D]] I have to now store these values in a dictionary where the key values are the first element from each list. i.e the keys will be A, B, C, D. I am finding it difficult to enter the values as the remaining elements of the list. i.e the dictionary should look like: {A: B C D; B: E F; C: A B D; D: 0} I have done the following: inlinkDict = {} for doc in text: adoc= doc.split(' ') docid = adoc[0] inlinkDict[docid] = inlinkDict.get(docid,0) + {I do not understand what to put in here} Please help as to how should i add the values to my dictionary. It should be 0 if there are no elements in the list except for the one which will be the key value. Like in example for 0.

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  • Major Analyst Report Chooses Oracle As An ECM Leader

    - by brian.dirking(at)oracle.com
    Oracle announced that Gartner, Inc. has named Oracle as a Leader in its latest "Magic Quadrant for Enterprise Content Management" in a press release issued this morning. Gartner's Magic Quadrant reports position vendors within a particular quadrant based on their completeness of vision and ability to execute. According to Gartner, "Leaders have the highest combined scores for Ability to Execute and Completeness of Vision. They are doing well and are prepared for the future with a clearly articulated vision. In the context of ECM, they have strong channel partners, presence in multiple regions, consistent financial performance, broad platform support and good customer support. In addition, they dominate in one or more technology or vertical market. Leaders deliver a suite that addresses market demand for direct delivery of the majority of core components, though these are not necessarily owned by them, tightly integrated, unique or best-of-breed in each area. We place more emphasis this year on demonstrated enterprise deployments; integration with other business applications and content repositories; incorporation of Web 2.0 and XML capabilities; and vertical-process and horizontal-solution focus. Leaders should drive market transformation." "To extend content governance and best practices across the enterprise, organizations need an enterprise content management solution that delivers a broad set of functionality and is tightly integrated with business processes," said Andy MacMillan, vice president, Product Management, Oracle. "We believe that Oracle's position as a Leader in this report is recognition of the industry-leading performance, integration and scalability delivered in Oracle Enterprise Content Management Suite 11g." With Oracle Enterprise Content Management Suite 11g, Oracle offers a comprehensive, integrated and high-performance content management solution that helps organizations increase efficiency, reduce costs and improve content security. In the report, Oracle is grouped among the top three vendors for execution, and is the furthest to the right, placing Oracle as the most visionary vendor. This vision stems from Oracle's integration of content management right into key business processes, delivering content in context as people need it. Using a PeopleSoft Accounts Payable user as an example, as an employee processes an invoice, Oracle ECM Suite brings that invoice up on the screen so the processor can verify the content right in the process, improving speed and accuracy. Oracle integrates content into business processes such as Human Resources, Travel and Expense, and others, in the major enterprise applications such as PeopleSoft, JD Edwards, Siebel, and E-Business Suite. As part of Oracle's Enterprise Application Documents strategy, you can see an example of these integrations in this webinar: Managing Customer Documents and Marketing Assets in Siebel. You can also get a white paper of the ROI Embry Riddle achieved using Oracle Content Management integrated with enterprise applications. Embry Riddle moved from a point solution for content management on accounts payable to an infrastructure investment - they are now using Oracle Content Management for accounts payable with Oracle E-Business Suite, and for student on-boarding with PeopleSoft e-Campus. They continue to expand their use of Oracle Content Management to address further use cases from a core infrastructure. Oracle also shows its vision in the ability to deliver content optimized for online channels. Marketers can use Oracle ECM Suite to deliver digital assets and offers as part of an integrated campaign that understands website visitors and ensures that they are given the most pertinent information and offers. Oracle also provides full lifecycle management through its built-in records management. Companies are able to manage the lifecycle of content (both records and non-records) through built-in retention management. And with the integration of Oracle ECM Suite and Sun Storage Archive Manager, content can be routed to the appropriate storage media based upon content type, usage data or other business rules. This ensures that the most accessed content is instantly available, and archived content is stored on a more appropriate medium like tape. You can learn more in this webinar - Oracle Content Management and Sun Tiered Storage. If you are interested in reading more about why Oracle was chosen as a Leader, view the Gartner Magic Quadrant for Enterprise Content Management.

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  • How to update data in the user information list when using FBA

    - by Flo
    I've got to support a SharePoint web application which uses FBA with a custom membership and a custom role provider to authenticate the user against two different LDAPs. The user data are only stored in the user information lists. The SSP user profiles are not used. Now one of the users got married and therefore her surname got changed in the LDAP (the one where her information are stored). But this change doesn't get provisioned into the user information list. I wondering what option I have to provision changes of user data to the user information list. I've already tried to update the last name of the user manually, but it seems as if certain information like surname, first name are not editable in the user information list. I tried to edit them as a site administrator. So what option do I have to solve this problem? Being able to edit the information per hand would also be a solution but of course not the most preferred one.

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  • Searching a large list of words in another large list

    - by Christian
    I have a list of 1,000,000 strings with a maximum length of 256 with protein names. Every string has an associated ID. I have another list of 4,000,000,000 strings with a maximum length of 256 with words out of articles and every word has an ID. I want to find all matches between the list of protein names and the list of words of the articles. Which algorithm should I use? Should I use some prebuild API? It would be good if the algorithm runs on a normal PC without special hardware.

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  • Make list from two database items

    - by unnamet
    I want to make a list from some data that I have in my database. The first two sets of data in my database are first name and last name. I want my list to show both first and last name instead of now where it only shows the first name. How do I do that? My code looks like this: private void fillData() { Cursor contactCursor = mDbHelper.fetchAllReminders(); startManagingCursor(contactCursor); String[] from = new String[]{DbAdapter.KEY_FIRST}; int[] to = new int[]{R.id.contactlist}; SimpleCursorAdapter contacts = new SimpleCursorAdapter(this, R.layout.list, contactCursor, from, to); setListAdapter(contacts); }

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  • Python 3: unpack inner lists in list comprehension

    - by Beau Martínez
    I'm running the following code on a list of strings to return a list of its words: words = [re.split('\\s+', line) for line in lines] However, I end up getting something like: [['import', 're', ''], ['', ''], ['def', 'word_count(filename):', ''], ...] As opposed to the desired: ['import', 're', '', '', '', 'def', 'word_count(filename):', '', ...] How can I unpack the lists re.split('\\s+', line) produces in the above list comprehension? Naïvely, I tried using * but that doesn't work. (I'm looking for a simple and Pythonic way of doing; I was tempted to write a function but I'm sure the language accommodates for this issue.)

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  • Converting array to list in Java

    - by Alexandru
    How do I convert an array to a list in Java? I used the Arrays.asList() but the behavior (and signature) somehow changed from 1.4.2 to 1.5.0 and most snippets I found on the web use the 1.4.2 behaviour. For example: int[] spam = new int[] { 1, 2, 3 }; Arrays.asList(spam) on 1.4.2 returns a list containing the elements 1, 2, 3 on 1.5.0 returns a list containing the array spam In many cases it should be easy to detect, but sometimes it can slip unnoticed: Assert.assertTrue(Arrays.asList(spam).indexOf(4) == -1);

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  • Comparing two List<MyClass> in C#

    - by Matt
    I have a class called MyClass This class inherits IEquatable and implements equals the way I need it to. (Meaning: when I compare two MyClass tyupe objects individually in code, it works) I then create two List: var ListA = new List<MyClass>(); var ListB = new List<MyClass>(); // Add distinct objects that are equal to one another to // ListA and ListB in such a way that they are not added in the same order. When I go to compare ListA and ListB, should I get true? ListA.Equals(ListB)==true; //???

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  • Sorting list of URLs by length in Jython

    - by Eef
    Hi, I am writing a Jython script to sort a list of URLs. I have a list that looks like this: http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 The pipe and the comma separates the path from the amount of files that are under that path. Is it possible some how use Jython to order the URLs by length, so it would end up look like the below list: http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 http://www.domain.com/folder1/folder2/folder3/|,1 Hope you guys get what I mean, any help would be appreciated. Cheers

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  • Racket list in struct

    - by Tim
    I just started programming with Racket and now I have the following problem. I have a struct with a list and I have to add up all prices in the list. (define-struct item (name category price)) (define some-items (list (make-item "Book1" 'Book 40.97) (make-item "Book2" 'Book 5.99) (make-item "Book3" 'Book 20.60) (make-item "Item" 'KitchenAccessory 2669.90))) I know that I can return the price with: (item-price (first some-items)) or (item-price (car some-items)). The problem is, that I dont know how I can add up all Items prices with this. Answer to Óscar López: May i filled the blanks not correctly, but Racket mark the code black when I press start and don't return anything. (define (add-prices items) (if (null? items) (+ 0 items) ; Here I don't really know what to write for a 0. ; I tried differnt thnigs like null and this version. (+ (item-price (first some-items)) (add-prices (item-price (rest some-items))))))

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  • Java anagram recursion List<List<String>> only storing empty lists<Strings>

    - by Riff Rafffer
    Hi In this recursion method i am trying to find all anagrams and add it to a List but what happens when i run this code is it just returns alot of empty Lists. private List<List<String>> findAnagrams(LetterInventory words, ArrayList<String> anagram, int max, Map<String, LetterInventory> smallDict, int level, List<List<String>> result) { ArrayList<String> solvedWord = new ArrayList<String>(); LetterInventory shell; LetterInventory shell2; if (level < max || max == 0) { Iterator<String> it = smallDict.keySet().iterator(); while (it.hasNext()) { String k = it.next(); shell = new LetterInventory(k); shell2 = words; if (shell2.subtract(shell) != null) { anagram.add(k); shell2 = words.subtract(shell); if (shell2.isEmpty()) { //System.out.println(anagram.toString()); it prints off fine here result.add(anagram); // but doesnt add here } else findAnagrams(shell2, anagram, max, smallDict, level + 1, result); anagram.remove(anagram.size()-1); } } } return results; }

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  • how to add enum value to list

    - by netmajor
    I have enum: public enum SymbolWejsciowy { K1 , K2 , K3 , K4 , K5 , K6 , K7 , K8 } and I want to create list of this enum public List<SymbolWejsciowy> symbol; but in my way to add enum to List: 1. SymbolWejsciowy symbol ; symbol.Add(symbol = SymbolWejsciowy.K1); 2. symbol.Add(SymbolWejsciowy.K1); I always get Exception Object reference not set to an instance of an object. What i do wrong :/ Please help :)

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  • Remove first 'n' elements from list without itterating

    - by Eldhose M Babu
    I need an efficient way of removing items from list. If some condition happens, I need to remove first 'n' elements from a list. Can some one suggest the best way to do this? Please keep in mind: performance is a factor for me, so I need a faster way than itterating. Thanks. I'm thinking of a way through which the 'n'th item can be made as the starting of the list so that the 0-n items will get garbage collected. Is it possible?

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  • c# Generic List

    - by user177883
    I m populating data for different entities into set of lists using generic lists as follows : List<Foo> foos .. List<Bar> bars .. I need to write these lists to a file, i do have a util method to get the values of properties etc. using reflection. What i want to do is: using a single method to write these into files such as: void writeToFile(a generic list) { //Which i will write to file here. } How can i do this? I want to be able to call : writeToFile(bars); writeToFile(foos);

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  • Python: Indexing list for element in nested list

    - by aquateenfan
    I know what I'm looking for. I want python to tell me which list it's in. Here's some pseudocode: item = "a" nested_list = [["a", "b"], ["c", "d"]] list.index(item) #obviously this doesn't work here I would want python to return 0 (because "a" is an element in the first sub-list in the bigger list). I don't care which sub-element it is. I don't care if there are duplicates, e.g., ["a", "b", "a"] should return the same thing as the above example. Sorry if this is a dumb question. I'm new to programming.

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  • Taking a comma separated list and creating a unordered list

    - by mmsa
    I've got a simple list which is generated by a checkbox list. The generated code is simply this white,blue,red,black I need to use jquery to wrap each of these elements in a < li tag. How do you go through the list and use the comma as a separator? I also will need to delete the comma. Sometime there will be 1 item, sometimes 3, etc. Thanks in advance!

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  • JSF: how to update the list after delete an item of that list

    - by Harry Pham
    It will take a moment for me to explain this, so please stay with me. I have table COMMENT that has OneToMany relationship with itself. @Entity public class Comment(){ ... @ManyToOne(optional=true, fetch=FetchType.LAZY) @JoinColumn(name="REPLYTO_ID") private Comment replyTo; @OneToMany(mappedBy="replyTo", cascade=CascadeType.ALL) private List<Comment> replies = new ArrayList<Comment>(); public void addReply(NewsFeed reply){ replies.add(reply); reply.setReplyTo(this); } public void removeReply(NewsFeed reply){ replies.remove(reply); } } So you can think like this. Each comment can have a List of replies which are also type Comment. Now it is very easy for me to delete the original comment and get the updated list back. All I need to do after delete is this. allComments = myEJB.getAllComments(); //This will query the db and return updated list But I am having problem when trying to delete replies and getting the updated list back. So here is how I delete the replies. Inside my managed bean I have //Before invoke this method, I have the value of originalFeed, and deletedFeed set. //These original comments are display inside a p:dataTable X, and the replies are //displayed inside p:dataTable Y which is inside X. So when I click the delete button //I know which comment I want to delete, and if it is the replies, I will know //which one is its original post public void deleteFeed(){ if(this.deletedFeed != null){ scholarEJB.deleteFeeds(this.deletedFeed); if(this.originalFeed != null){ //Since the originalFeed is not null, this is the `replies` //that I want to delete scholarEJB.removeReply(this.originalFeed, this.deletedFeed); } feeds = scholarEJB.findAllFeed(); } } Then inside my EJB scholarEJB, I have public void removeReply(NewsFeed comment, NewsFeed reply){ comment = em.merge(comment); comment.removeReply(reply); em.persist(comment); } public void deleteFeeds(NewsFeed e){ e = em.find(NewsFeed.class, e.getId()); em.remove(e); } When I get out, the entity (the reply) get correctly removed from the database, but inside the feeds List, reference of that reply still there. It only until I log out and log back in that the reply disappear. Please help

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  • Python: create a function to modify a list by reference not value

    - by Jonathan
    Hey all- I'm doing some performance-critical Python work and want to create a function that removes a few elements from a list if they meet certain criteria. I'd rather not create any copies of the list because it's filled with a lot of really large objects. Functionality I want to implement: def listCleanup(listOfElements): i = 0 for element in listOfElements: if(element.meetsCriteria()): del(listOfElements[i]) i += 1 return listOfElements myList = range(10000) myList = listCleanup(listOfElements) I'm not familiar with the low-level workings of Python. Is myList being passed by value or by reference? How can I make this faster? Is it possible to somehow extend the list class and implement listCleanup() within that? myList = range(10000) myList.listCleanup() Thanks- Jonathan

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