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• SQL SERVER – 3 Challenges for DBA and Smart Solutions

  - by Pinal Dave

  Developer’s life is never easy. DBA’s life is even crazier. DBA’s Life When a developer wakes up in the morning, most of the time have no idea what different challenges they are going to face that day. Of course, most of the developers know the project and roadmap, which they are working on. However, developers have no clue what coding challenges which they are going face for that day. DBA’s life is even crazier. When DBA wakes up in the morning – they often thank that they were not disturbed during the night due to server issues. The very next thing they wish is that they do not want to challenge which they can’t solve for that day. The problems DBA face every single day are mostly unpredictable and they just have to solve them as they come during the day. Though the life of DBA is not always bad. There are always ways and methods how one can overcome various challenges. Let us see three of the challenges and how a DBA can use various tools to overcome them. Challenge #1 Synchronize Data Across Server A Very common challenge DBA receive is that they have to synchronize the data across the servers. If you try to manually write that up, it may take forever to accomplish the task. It is nearly impossible to do the same with the help of the T-SQL. However, thankfully there are tools like dbForge Studio which can save a day and synchronize data across servers. Read my detailed blog post about the same over here: SQL SERVER – Synchronize Data Exclusively with T-SQL. Challenge #2 SQL Report Builder DBA’s are often asked to build reports on the go. It really annoys DBA’s, but hardly people care about it. No matter how busy a DBA is, they are just called upon to build reports on things on very short notice. I personally like to avoid any task which is given to me accidently and personally building report can be boring. I rather spend time with High Availability, disaster recovery, performance tuning rather than building report. I use SQL third party tool when I have to work with SQL Report. Others have extended reporting capabilities. The latter group of products includes the SQL report builder built-in todbForge Studio for SQL Server. I have blogged about this earlier over here: SQL SERVER – SQL Report Builder in dbForge Studio for SQL Server. Challenge #3 Work with the OTHER Database The manager does not understand that MySQL is different from SQL Server and SQL Server is different from Oracle. For them everything is same. In my career hundreds of times I have faced a situation that I am given a database to manage or do some task when their regular DBA is on vacation or leave. When I try to explain I do not understand the underlying the technology, I have been usually told that my manager has trust on me and I can do anything. Honestly, I can’t but I hardly dare to argue. I fall back on the third party tool to manage database when it is not in my comfort zone. For example, I was once given MySQL performance tuning task (at that time I did not know MySQL so well). To simplify search for a problem query let us use MySQL Profiler in dbForge Studio for MySQL. It provides such commands as a Query Profiling Mode and Generate Execution Plan. Here is the blog post discussing about the same: MySQL – Profiler : A Simple and Convenient Tool for Profiling SQL Queries. Well, that’s it! There were many different such occasions when I have been saved by the tool. May be some other day I will write part 2 of this blog post. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, SQL Utility, T SQL Tagged: Devart, SQL Tool

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• fetch_all or fetch_assoc MySQLi statement

  - by all-R

  Hi, is it possible to use the fetch_all(), fetch_assoc() etc. from the the MySQLi_Result class with a prepared statement from the MySQLi_STMT class? I've done it using the query() method in the Mysqli class (and by escaping trough mysqli_real_escape_string()), but not using statements with binding parameters. I'm considering using PDO thanks!

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• Is this possible to join tables in doctrine ORM without using relations?

  - by piemesons

  Suppose there are two tables. Table X-- Columns: id x_value Table Y-- Columns: id x_id y_value Now I dont want to define relationship in doctrine classes and i want to retrieve some records using these two tables using a query like this: Select x_value from x, y where y.id="variable_z" and x.id=y.x_id; I m not able to figure out how to write query like this in doctrine orm EDIT: Table structures: Table 1: CREATE TABLE IF NOT EXISTS `image` ( `id` int(11) NOT NULL AUTO_INCREMENT, `random_name` varchar(255) NOT NULL, `user_id` int(11) NOT NULL, `community_id` int(11) NOT NULL, `published` varchar(1) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=259 ; Table 2: CREATE TABLE IF NOT EXISTS `users` ( `id` int(11) NOT NULL AUTO_INCREMENT, `city` varchar(20) DEFAULT NULL, `state` varchar(20) DEFAULT NULL, `school` varchar(50) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=20 ; Query I am using: $q = new Doctrine_RawSql(); $q ->select('{u.*}, {img.*}') ->from('users u LEFT JOIN image img ON u.id = img.user_id') ->addComponent('u', 'Users u') ->addComponent('img', 'u.Image img') ->where("img.community_id='$community_id' AND img.published='y' AND u.state='$state' AND u.city='$city ->orderBy('img.id DESC') ->limit($count+12) ->execute(); Error I am getting: Fatal error: Uncaught exception 'Doctrine_Exception' with message 'Couldn't find class u' in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php:290 Stack trace: #0 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php(240): Doctrine_Table- >initDefinition() #1 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Connection.php(1127): Doctrine_Table->__construct('u', Object(Doctrine_Connection_Mysql), true) #2 C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\RawSql.php(425): Doctrine_Connection- >getTable('u') #3 C:\xampp\htdocs\fanyer\doctrine\models\Image.php(33): Doctrine_RawSql- >addComponent('img', 'u.Image imga') #4 C:\xampp\htdocs\fanyer\community_images.php(31): Image->get_community_images_gallery_filter(4, 0, 'AL', 'ALBERTVILLE') #5 {main} thrown in C:\xampp\htdocs\fanyer\doctrine\lib\Doctrine\Table.php on line 290

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• MySql multiple selects batching in .net

  - by Amith George

  I have a situation in my application. For each x-axis point in my chart, I am plotting 5 y-axis values. To calculate each of these 5 values, I need to make 4 different queries. Ie, for each x-axis point I need to fire 20 sql queries. Now, I need to plot 40 such points in the my chart. Its resulting in a pathetic performance where it takes close to a minute to get all the data back from the database. Each of 4 different queries consists of a join between 2 tables. One has only 6 rows. The other close to 10,000. Each of the 4 queries has different WHERE clauses, so they are different queries. For each point in the x-axis, only the values for the where clauses change. I have tried combining each of the 4 queries into one big string. Basically batch the four selects. These are again batched for each y-axis value. So, for each x-axis point, I am now firing one big command that consists of 20 different select statements. Technically, I should be experiencing a big performance boost, right? Instead of hitting the db 40x5x4 = 800 times, I am now hitting it just 40 times. But instead of taking 60 seconds, it taking 50-55 seconds... not much of a help. I am using MySql 5.1, and the 6.1 version of its .Net connector. What can I do to improve the performance? Edit: One of the 4 queries is as follows: SELECT SUM(TIME_TO_SEC(TIMEDIFF(T1.col2, T1.col1))* T2.col1 / (3600 *1000)) AS TotalTime FROM Table T1 JOIN Table T2 ON T1.col3 = T2.col3 WHERE T1.col4 = 'i' AND T1.col1 >= '2009-12-25 00:00:00' AND T1.col2 <= '2009-12-26 00:00:00'; The other 3 queries are similar, only the where clause changes slightly. This set of 4 queries is fired 5 times. The first 3 times against the join of table T1 and T2, passing in different values for col4. And the next two times against the join of table T3 and T2 passing in different values for col4. These 5 values are the y-axis values for a particular x-axis point. The data returned by all these queries is the same format. so, we tried doing a UNION ALL on all these queries. No substantial difference. One strange thing, however, after indexing the foreign key on the table T1 [while it contained over a lakh records], the queries were using the index, but they had become slower. At times, the queries would take double the time to return the data.

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• Query Months help

  - by StealthRT

  Hey all i am in need of some helpful tips/advice on how to go about my problem. I have a database that houses a "signup" table. The date for this table is formated as such: 2010-04-03 00:00:00 Now suppose i have 10 records in this database: 2010-04-03 00:00:00 2010-01-01 00:00:00 2010-06-22 00:00:00 2010-02-08 00:00:00 2010-02-05 00:00:00 2010-03-08 00:00:00 2010-09-29 00:00:00 2010-11-16 00:00:00 2010-04-09 00:00:00 2010-05-21 00:00:00 And i wanted to get each months total registers... so following the example above: Jan = 1 Feb = 2 Mar = 1 Apr = 2 May = 1 Jun = 1 Jul = 0 Aug = 0 Sep = 1 Oct = 0 Nov = 1 Dec = 0 Now how can i use a query to do that but not have to use a query like: WHERE left(date, 7) = '2010-01' and keep doing that 12 times? I would like it to be a single query call and just have it place the months visits into a array like so: do until EOF theMonthArray[0] = "total for jan" theMonthArray[1] = "total for feb" theMonthArray[2] = "total for mar" theMonthArray[3] = "total for apr" ...etc loop I just can not think of a way to do that other than the example i posted with the 12 query called-one for each month. This is my query as of right now. Again, this only populates for one month where i am trying to populate all 12 months all at once. SELECT count(idNumber) as numVisits, theAccount, signUpDate, theActive from userinfo WHERE theActive = 'YES' AND idNumber = '0203' AND theAccount = 'SUB' AND left(signUpDate, 7) = '2010-04' GROUP BY idNumber ORDER BY numVisits; The example query above outputs this: numVisits | theAccount | signUpDate | theActive 2 SUB 2010-04-16 00:00:00 YES Which is correct because i have 2 records within the month of April. But again, i am trying to do all 12 months at one time (in a single query) so i do not tax the database server as much when compared to doing 12 different query's... UPDATE I'm looking to do something like along these lines: if NOT rst.EOF if left(rst("signUpDate"), 7) = "2010-01" then theMonthArray[0] = rst("numVisits") end if if left(rst("signUpDate"), 7) = "2010-02" then theMonthArray[1] = rst("numVisits") end if etc etc.... end if Any help would be great! :) David

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• Designing a game database

  - by Ronald

  I'm trying to design a database to record game histories for a game I'm working on. I have 3 different tables: users, gamehistories, and gamescores. Columns for tables: users: uid, displayname, email gamehistories: gid, pubID, start (datetime), end (datetime) gamescores: gid, uid, score I am trying to produce the following result set given a userID (uid): Opponent's displayname, my score, opponent's score, duration Any ideas? Is my design ok? How can I query these tables to get game histories for a given uid?

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• complex sql which runs extremely slow when the query has order by clause

  - by basit.

  I have following complex query which I need to use. When I run it, it takes 30 to 40 seconds. But if I remove the order by clause, it takes 0.0317 sec to return the result, which is really fast compare to 30 sec or 40. select DISTINCT media.* , username from album as album , album_permission as permission , user as user, media as media where ((media.album_id = album.album_id and album.private = 'yes' and album.album_id = permission.album_id and (permission.email = '' or permission.user_id = '') ) or (media.album_id = album.album_id and album.private = 'no' ) or media.album_id = '0' ) and media.user_id = user.user_id and media.media_type = 'video' order by media.id DESC LIMIT 0,20 The id on order by is primary key which is indexed too. So I don't know what is the problem. I also have album and album permission table, just to check if media is public or private, if private then check if user has permission or not. I was thinking maybe that is causing the issue. What if I did this in sub query, would that work better? Also can someone help me write that sub query, if that is the solution? If you can't help write it, just at least tell me. I'm really going crazy with this issue.. SOLUTION MAYBE Yes, I think sub-query would be best solution for this, because the following query runs at 0.0022 seconds. But I'm not sure if validation of an album would be accurate or not, please check. select media.*, username from media as media , user as user where media.user_id = user.user_id and media.media_type = 'video' and media.id in (select media2.id from media as media2 , album as album , album_permission as permission where ((media2.album_id = album.album_id and album.private = 'yes' and album.album_id = permission.album_id and (permission.email = '' or permission.user_id = '')) or (media.album_id = album.album_id and album.private = 'no' ) or media.album_id = '0' ) and media.album_id = media2.album_id ) order by media.id DESC LIMIT 0,20

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• Semantic Maps

  A MediaWiki extension that allows you to insert, edit, view and aggregate coordinate data

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• In SQL Server can I insert multiple nodes into XML from a table?

  - by tpower

  I want to generate some XML in a stored procedure based on data in a table. The following insert allows me to add many nodes but they have to be hard-coded or use variables (sql:variable): SET @MyXml.modify(' insert <myNode> {sql:variable("@MyVariable")} </myNode> into (/root[1]) ') So I could loop through each record in my table, put the values I need into variables and execute the above statement. But is there a way I can do this by just combining with a select statement and avoiding the loop? Edit I have used SELECT FOR XML to do similar stuff before but I always find it hard to read when working with a hierarchy of data from multiple tables. I was hoping there would be something using the modify where the XML generated is more explicit and more controllable.

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• Variables are "lost" somewhere, then reappear... all with no error thrown.

  - by rob - not a robber

  Hi All, I'm probably going to make myself look like a fool with my horrible scripting but here we go. I have a form that I am collecting a bunch of checkbox info from using a binary method. ON/SET=1 !ISSET=0 Anyway, all seems to be going as planned except for the query bit. When I run the script, it runs through and throws no errors, but it's not doing what I think I am telling it to. I've hard coded the values in the query and left them in the script and it DOES update the DB. I've also tried echoing all the needed variables after the script runs and exiting right after so I can audit them... and they're all there. Here's an example. ####FEATURES RECORD UPDATE ### HERE I DECIDE TO RUN THE SCRIPT BASED ON WHETHER AN IMAGE BUTTON WAS USED if (isset($_POST["button_x"])) { ### HERE I AM ASSIGNING 1 OR 0 TO A VAR BASED ON WHTER THE CHECKBOX WAS SET if (isset($_POST["pool"])) $pool=1; if (!isset($_POST["pool"])) $pool=0; if (isset($_POST["darts"])) $darts=1; if (!isset($_POST["darts"])) $darts=0; if (isset($_POST["karaoke"])) $karaoke=1; if (!isset($_POST["karaoke"])) $karaoke=0; if (isset($_POST["trivia"])) $trivia=1; if (!isset($_POST["trivia"])) $trivia=0; if (isset($_POST["wii"])) $wii=1; if (!isset($_POST["wii"])) $wii=0; if (isset($_POST["guitarhero"])) $guitarhero=1; if (!isset($_POST["guitarhero"])) $guitarhero=0; if (isset($_POST["megatouch"])) $megatouch=1; if (!isset($_POST["megatouch"])) $megatouch=0; if (isset($_POST["arcade"])) $arcade=1; if (!isset($_POST["arcade"])) $arcade=0; if (isset($_POST["jukebox"])) $jukebox=1; if (!isset($_POST["jukebox"])) $jukebox=0; if (isset($_POST["dancefloor"])) $dancefloor=1; if (!isset($_POST["dancefloor"])) $dancefloor=0; ### I'VE DONE LOADS OF PERMUTATIONS HERE... HARD SET THE 1/0 VARS AND LEFT THE $estab_id TO BE PICKED UP. SET THE $estab_id AND LEFT THE COLUMN DATA TO BE PICKED UP. ALL NO GOOD. IT _DOES_ WORK IF I HARD SET ALL VARS THOUGH mysql_query("UPDATE thedatabase SET pool_table='$pool', darts='$darts', karoke='$karaoke', trivia='$trivia', wii='$wii', megatouch='$megatouch', guitar_hero='$guitarhero', arcade_games='$arcade', dancefloor='$dancefloor' WHERE establishment_id='22'"); ###WEIRD THING HERE IS IF I ECHO THE VARS AT THIS POINT AND THEN EXIT(); they all show up as intended. header("location:theadminfilething.php"); exit(); THANKS ALL!!!

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• sql pulling a row for next or previous row of a current row

  - by basit.

  id | photo title | created_date XEi43 | my family | 2009 08 04 dDls | friends group | 2009 08 05 32kJ | beautiful place | 2009 08 06 EOIk | working late | 2009 08 07 Say I have the id 32kJ. How would I get the new or previous row?

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• php edit database entery script not working.

  - by Jacksta

  I have two files which show all contats in a database, then edits them. The second script keeps directing the browser back due to this part. I cant work out how to make it work! :) <?php if (!$_POST[id]) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION[valid] != "yes") { header( "Location: pick_modcontact.php"); exit; } This script shows all contacts in a database which is an "address book" this part works fine. please see below. Name:pick_modcontact.php if ($_SESSION[valid] != "yes") { header( "Location: contact_menu.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin", "user") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT id, f_name, l_name FROM $table_name ORDER BY f_name"; $result = @mysql_query($sql, $connection) or die(mysql_error()); $num = @mysql_num_rows($result); if ($num < 1) { $display_block = "<p><em>Sorry No Results!</em></p>"; } else { while ($row = mysql_fetch_array($result)) { $id = $row['id']; $f_name = $row['f_name']; $l_name = $row['l_name']; $option_block .= "<option value\"$id\">$f_name, $l_name</option>"; } $display_block = "<form method=\"POST\" action=\"show_modcontact.php\"> <p><strong>Contact:</strong> <select name=\"id\">$option_block</select> <input type=\"submit\" name=\"submit\" value=\"Select This Contact\"></p> </form>"; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <h1>My Contact Management System</h1> <h2><em>Modify a Contact</em></h2> <p>Select a contact from the list below, to modify the contact's record.</p> <? echo "$display_block"; ?> <br> <p><a href="contact_menu.php">Return to Main Menu</a></p> </body> </html> This script is for modifying the contact: named show_modcontact.php <?php if (!$_POST[id]) { header( "Location: pick_modcontact.php"); exit; } else { session_start(); } if ($_SESSION[valid] != "yes") { header( "Location: pick_modcontact.php"); exit; } $db_name = "testDB"; $table_name = "my_contacts"; $connection = @mysql_connect("localhost", "admin_cantsayno", "cantsayno") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "SELECT f_name, l_name, address1, address2, address3, postcode, prim_tel, sec_tel, email, birthday FROM $table_name WHERE id = '$_POST[id]'"; $result = @mysql_query($sql, $connection) or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $f_name = $row['f_name']; $l_name = $row['l_name']; $address1 = $row['address1']; $address2 = $row['address2']; $address3 = $row['address3']; $country = $row['country']; $prim_tel = $row['prim_tel']; $sec_tel = $row['sec_tel']; $email = $row['email']; $birthday = $row['birthday']; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Modify A Contact</title> </head> <body> <form action="do_modcontact.php" method="post"> <input type="id" value="<? echo "$_POST[id]"; ?>" /> <table cellpadding="5" cellspacing="3"> <tr> <th>Name & Address Information</th> <th> Other Contact / Personal Information</th> </tr> <tr> <td align="top"> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name" ?>" size="35" maxlength="75" /></p> <p><strong>Last Name:</strong><br /> <input type="text" name="l_name" value="<? echo "$l_name" ?>" size="35" maxlength="75" /></p> <p><strong>Address1:</strong><br /> <input type="text" name="f_name" value="<? echo "$address1" ?>" size="35" maxlength="75" /></p> <p><strong>Address2:</strong><br /> <input type="text" name="f_name" value="<? echo "$address2" ?>" size="35" maxlength="75" /></p> <p><strong>Address3:</strong><br /> <input type="text" name="f_name" value="<? echo "$address3" ?>" size="35" maxlength="75" /> </p> <p><strong>Postcode:</strong><br /> <input type="text" name="f_name" value="<? echo "$postcode" ?>" size="35" maxlength="75" /></p> <p><strong>Country:</strong><br /> <input type="text" name="f_name" value="<? echo "$country" ?>" size="35" maxlength="75" /> </p> <p><strong>First Name:</strong><br /> <input type="text" name="f_name" value="<? echo "$f_name" ?>" size="35" maxlength="75" /></p> </td> <td align="top"> <p><strong>Prim Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$prim_tel" ?>" size="35" maxlength="75" /></p> <p><strong>Sec Tel:</strong><br /> <input type="text" name="f_name" value="<? echo "$sec_tel" ?>" size="35" maxlength="75" /></p> <p><strong>Email:</strong><br /> <input type="text" name="f_name" value="<? echo "$email" ?>" size="35" maxlength="75" /> </p> <p><strong>Birthday:</strong><br /> <input type="text" name="f_name" value="<? echo "$birthday" ?>" size="35" maxlength="75" /> </p> </td> </tr> <tr> <td align="center"> <p><input type="submit" name="submit" value="Update Contact" /></p> <br /> <p><a href="contact_menu.php">Retuen To Menu</a></p> </td> </tr> </table> </form> </body> </html>

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• Query design in SQL - ORDER BY SUM() of field in rows which meet a certain condition

  - by Christian Mann

  OK, so I have two tables I'm working with - project and service, simplified thus: project ------- id PK name str service ------- project_id FK for project time_start int (timestamp) time_stop int (timestamp) One-to-Many relationship. Now, I want to return (preferably with one query) a list of an arbitrary number of projects, sorted by the total amount of time spent at them, which is found by SUM(time_stop) - SUM(time_start) WHERE project_id = something. So far, I have SELECT project.name FROM service LEFT JOIN project ON project.id = service.project_id LIMIT 100 but I cannot figure out how what to ORDER BY.

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• Retrieve 2 last posts for each category.

  - by Savageman

  Hello, Lets say I have 2 tables: blog_posts and categories. Each blog post belongs to only ONE category, so there is basically a foreign key between the 2 tables here. I would like to retrieve the 2 lasts posts from each category, is it possible to achieve this in a single request? GROUP BY would group everything and leave me with only one row in each category. But I want 2 of them. It would be easy to perform 1 + N query (N = number of category). First retrieve the categories. And then retrieve 2 posts from each category. I believe it would also be quite easy to perform M queries (M = number of posts I want from each category). First query selects the first post for each category (with a group by). Second query retrieves the second post for each category. etc. I'm just wondering if someone has a better solution for this. I don't really mind doing 1+N queries for that, but for curiosity and general SQL knowledge, it would be appreciated! Thanks in advance to whom can help me with this.

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• using LIKE with logical operators

  - by ryanthegecko

  i can't seem to figure out how to combine LIKE with an OR or AND: DELETE * FROM persons WHERE FirstName = 'Abe' AND LastName LIKE '%coln'; Looks like it should owrk to me but I get error 1064 (syntax0 Is there a correct way to do this?

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• Doctrine CodeIgniter MySQL CRUD errors

  - by 01010011

  Hi, I am using CI + Doctrine + MySQL and I am getting the following CRUD errors: (1) When trying to create a new record in the database with this code: $book_title = 'The Peloponnesian War'; $b = new Book(); $b-title = $book_title; $b-price = 10.50; $b-save(); I get this error: Fatal error: Uncaught exeption 'Doctrine_Connection_Mysql_Exception' with message 'SQLSTATE[42S22]: Column not found: 1054 Unknown column 'title' in 'field list' in ... (2) When trying to fetch a record from the database and display on my view page with this code: $book_title = 'The Peloponnesian War'; $title = $book_title; $search_results = Doctrine::getTable('Book')-findOneByTitle($title); echo $search_results-title; (in view file) I get this error: Fatal error: Uncaught exception 'Doctrine_Connection_Mysql_Exception' with message 'SQLSTATE[45S22]: Column not found: 1054 Unknown column 'b.id' in 'field list" in ... And finally, when I try to update a record as follows: $book_title = 'The Peloponnesian War'; $title = $book_title; $u = Doctrine::getTable('Book')-find($title); $u-title = $title; $u-save(); I get a similar error: Fatal error: Uncaught exception 'Doctrine_Connection_Mysql_Exception' with message 'SQLSTATE[42S22]: Column not found: 1054 Unknown column 'b.id' in 'field list''in ... Here is my Doctrine_Record model: class Book extends Doctrine_Record{ public function setTableDefinition() { $this->hasColumn('book_id'); $this->hasColumn('isbn10','varchar',20); $this->hasColumn('isbn13','varchar',20); $this->hasColumn('title','varchar',100); $this->hasColumn('edition','varchar',20); $this->hasColumn('author_f_name','varchar',20); $this->hasColumn('author_m_name','varchar',20); $this->hasColumn('author_l_name','varchar',20); $this->hasColumn('cond','enum',null, array('values' => array('as new','very good','good','fair','poor'))); $this->hasColumn('price','decimal',8, array('scale' =>2)); $this->hasColumn('genre','varchar',20); } public function setUp() { $this->setTableName('Book'); //$this->actAs('Timestampable'); } Any assistance will be really appreciated. Thanks in advance.

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• PHP & MySQL submit error message problem

  - by peakUC

  When I submit a new name and not a new avatar I get the following avatar error message Please upload a .gif, .jpeg, .jpg or .png image!. I want to be able to send a new name only without having to upload a new avatar each time I submit the form without getting the avatar error message Please upload a .gif, .jpeg, .jpg or .png image! can someone help me fix this problem? Here is the php code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $first_name = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['first_name']))); $user_id = '3'; if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if($_FILES["avatar"]["type"] == "image/gif" || $_FILES["avatar"]["type"] == "image/jpeg" || $_FILES["avatar"]["type"] == "image/jpg" || $_FILES["avatar"]["type"] == "image/png" || $_FILES["avatar"]["type"] == "image/pjpeg") { if (file_exists("../members/" . $user_id . "/images/" . $_FILES["avatar"]["name"])) { echo '<p class="error">' . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))) . ' already exists! '; } else if($_FILES["avatar"]["name"] == TRUE) { move_uploaded_file($_FILES["avatar"]["tmp_name"], "../members/" . $user_id . "/images/" . mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"]))))); $avatar = mysqli_real_escape_string($mysqli, htmlentities(strip_tags(basename($_FILES["avatar"]["name"])))); } } else if($_FILES["avatar"]["type"] != "image/gif" || $_FILES["avatar"]["type"] != "image/jpeg" || $_FILES["avatar"]["type"] != "image/jpg" || $_FILES["avatar"]["type"] != "image/png" || $_FILES["avatar"]["type"] != "image/pjpeg") { echo '<p class="error">Please upload a .gif, .jpeg, .jpg or .png image!</p>'; } } else if($_FILES['avatar']['size'] >= 5242880) { echo '<p class="error">Please upload a smaller pic!</p>'; } else if($_FILES["avatar"]["name"] == NULL) { $avatar = NULL; } if(isset($_FILES["avatar"]["name"]) && $_FILES['avatar']['size'] <= 5242880) { if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, first_name, avatar) VALUES ('$user_id', '$first_name', '$avatar')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET first_name = '$first_name', avatar = '$avatar' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } }

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• Searching 2 fields at the same time

  - by donpal

  I have a table of first and last names firstname lastname --------- --------- Joe Robertson Sally Robert Jim Green Sandra Jordan I'm trying to search this table based on an input that consists of the full name. For example: input: Joe Robert I thought about using SELECT * FROM tablename WHERE firstname LIKE BUT the table stores the first and last name separately, so I'm not sure how to do the search in this case

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• Problem with ColdFusion communicating with MySQL database

  - by Greg

  Hi, I have been working to migrate a non-profit website from a local server (running Windows XP) to a GoDaddy hosting account (running Linux). Most of the pages are written in ColdFusion. Things have gone smoothly, up until this point. There is a flash form within the site (see this page: http://www.preservenet.cornell.edu/employ/submitjob.cfm) which, when completed, takes the visitor to this page: submitjobaction.cfm . I'm not quite sure what to make of this error, since I copied exactly what had been in the old MySQL database, and the .cfm files are exactly as they had been when they worked on the old server. Am I missing something? Below is the code from the database that the error seems to be referring to. When I change "Positionlat" to some default value in the database as it suggests in the error, it says that another field needs a default value, and it's a neverending chain of errors as I try to correct it. This is probably a stupid error that I'm missing, but I've been working at it for days and can't find what I'm missing. I would really appreciate any help. Thanks! -Greg DROP TABLE IF EXISTS employopp; CREATE TABLE employopp ( POSTID int(10) NOT NULL auto_increment, USERID varchar(10) collate latin1_general_ci default NULL, STATUS varchar(10) collate latin1_general_ci NOT NULL default 'ACTIVE', TYPE varchar(50) collate latin1_general_ci default 'professional', JOBTITLE varchar(70) collate latin1_general_ci default NULL, NUMBER varchar(30) collate latin1_general_ci default NULL, SALARY varchar(40) collate latin1_general_ci default NULL, ORGNAME varchar(70) collate latin1_general_ci default NULL, DEPTNAME varchar(70) collate latin1_general_ci default NULL, ORGDETAILS mediumtext character set utf8 collate utf8_unicode_ci, ORGWEBSITE varchar(200) collate latin1_general_ci default NULL, ADDRESS varchar(60) collate latin1_general_ci default 'none given', ADDRESS2 varchar(60) collate latin1_general_ci default NULL, CITY varchar(30) collate latin1_general_ci default NULL, STATE varchar(30) collate latin1_general_ci default NULL, COUNTRY varchar(3) collate latin1_general_ci default 'USA', POSTALCODE varchar(10) collate latin1_general_ci default NULL, EMAIL varchar(75) collate latin1_general_ci default NULL, NOMAIL varchar(5) collate latin1_general_ci default NULL, PHONE varchar(20) collate latin1_general_ci default NULL, FAX varchar(20) collate latin1_general_ci default NULL, WEBSITE varchar(200) collate latin1_general_ci default NULL, POSTDATE varchar(10) collate latin1_general_ci default NULL, POSTUNTIL varchar(20) collate latin1_general_ci default 'select date', POSTUNTILFILLED varchar(20) collate latin1_general_ci NOT NULL default 'until filled', texteHTML mediumtext character set utf8 collate utf8_unicode_ci, HOWTOAPPLY mediumtext character set utf8 collate utf8_unicode_ci, CONFIRSTNM varchar(30) collate latin1_general_ci default NULL, CONLASTNM varchar(60) collate latin1_general_ci default NULL, POSITIONCITY varchar(30) collate latin1_general_ci default NULL, POSITIONSTATE varchar(30) collate latin1_general_ci default NULL, POSITIONCOUNTRY varchar(3) collate latin1_general_ci default 'USA', POSITIONLAT varchar(50) collate latin1_general_ci NOT NULL, POSITIONLNG varchar(50) collate latin1_general_ci NOT NULL, PRIMARY KEY (POSTID) ) ENGINE=MyISAM AUTO_INCREMENT=2007 DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci;

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• using PHP to create multidimensional array from simple JSON array

  - by Michael Robinson

  I have a php query the returns the following JSON format from a table. [{"memberid":"18", "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School", }, It needs the following format: [{"memberid":"18" { "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School",} }, I was told in another question that PHP would work and it looks like "Transversing" might be appropriate, I'm looking to find out what to put in the Php before it returns the JASON. My Array.plist will look like the following: Root: Dictionary V Rows: Array V Item 0: Dictionary Title: String 18 V Children Array V Item 0 Dictionary Title String 30 etc. Thanks in advance.

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• using checkbox yo update MySql table

  - by Martin

  Hi All I have been searching round the internet for days on this matter but I keep coming up against a brick wall. What I have is a table full of checkboxes inside an admin area acting as a monthly "to-do" list. It's essentially a worksheet of 30 or so things to do each month that must be checked off each month and notes added if applicable. I have managed to get the checkboxes to update via mysql and be shown somewhere as a list of ticks. I simply did this my setting the value to 1 and on submission it updates the sql table. I have to cover my bases here and also offer the option to un-tick items if they have been ticked b y mistake. But I cant figure out how this is done. Below is my checking code... any help on this matter would be great. <?php $currentTask = ''; echo "<tr class='tr'>"; while ($seolistRow = mysql_fetch_array($seolistRes)) { $taskValue = $seolistRow["taskValue"]; $worksheetID = $seolistRow["worksheetID"]; $taskName = $seolistRow["taskName"]; $taskInfo = $seolistRow["taskInfo"]; if ($taskValue == 1) { $taskDone = "<input type='checkbox' value='1' class='checkbox' name='checkbox".$worksheetID."' id=checkbox'".$worksheetID."' checked='checked' /><div class='taskinfo'>".$taskInfo."</div>"; } else { $taskDone = "<input type='checkbox' value='0' class='checkbox' name='checkbox".$worksheetID."' id='checkbox".$worksheetID."' />"; } if ($currentTask != $taskName) { echo "</tr>"; echo "<tr class='tr'>"; echo "<td class='task'>".$taskName."</td>"; } echo "<td class='tick'>".$taskDone."</td>"; $currentTask = $taskName; } echo "</tr>"; ?>

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• Do I have to use mysql_real_escape_string if I bind parameters?

  - by Babak

  I have the following code: function dbPublish($status) { global $dbcon, $dbtable; if(isset($_GET['itemId'])) { $sqlQuery = 'UPDATE ' . $dbtable . ' SET active = ? WHERE id = ?'; $stmt = $dbcon->prepare($sqlQuery); $stmt->bind_param('ii', $status, $_GET['itemId']); $stmt->execute(); $stmt->close(); } } Do I need to mysql_real_escape_string in this case or am i okay?

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• How to fix unresolved external symbol due to MySql Connector C++?

  - by Chan

  Hi everyone, I followed this tutorial http://blog.ulf-wendel.de/?p=215#hello. I tried both on Visual C++ 2008 and Visual C++ 2010. Either static or dynamic, the compiler gave me the same exact error messages: error LNK2001: unresolved external symbol _get_driver_instance Has anyone experience this issue before? Update: + Additional Dependencies: mysqlcppconn.lib + Additional Include Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\include + Additional Libraries Directories: C:\Program Files\MySQL\MySQL Connector C++ 1.0.5\lib\opt Thanks, Chan Nguyen

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• Complex Rails queries across multiple tables, unions, and will_paginate. Solved.

  - by uberllama

  Hi folks. I've been working on a complex "user feed" type of functionality for a while now, and after experimenting with various union plugins, hacking named scopes, and brute force, have arrived at a solution I'm happy with. S.O. has been hugely helpful for me, so I thought I'd post it here in hopes that it might help others and also to get feedback -- it's very possible that I worked on this so long that I walked down an unnecessarily complicated road. For the sake of my example, I'll use users, groups, and articles. A user can follow other users to get a feed of their articles. They can also join groups and get a feed of articles that have been added to those groups. What I needed was a combined, pageable feed of distinct articles from a user's contacts and groups. Let's begin. user.rb has_many :articles has_many :contacts has_many :contacted_users, :through => :contacts has_many :memberships has_many :groups, :through => :memberships contact.rb belongs_to :user belongs_to :contacted_user, :class_name => "User", :foreign_key => "contacted_user_id" article.rb belongs_to :user has_many :submissions has_many :groups, :through => :submissions group.rb has_many :memberships has_many :users, :through => :memberships has_many :submissions has_many :articles, :through => :submissions Those are the basic models that define my relationships. Now, I add two named scopes to the Article model so that I can get separate feeds of both contact articles and group articles should I desire. article.rb # Get all articles by user's contacts named_scope :by_contacts, lambda {|user| {:joins => "inner join contacts on articles.user_id = contacts.contacted_user_id", :conditions => ["articles.published = 1 and contacts.user_id = ?", user.id]} } # Get all articles in user's groups. This does an additional query to get the user's group IDs, then uses those in an IN clause named_scope :by_groups, lambda {|user| {:select => "DISTINCT articles.*", :joins => :submissions, :conditions => {:submissions => {:group_id => user.group_ids}}} } Now I have to create a method that will provide a UNION of these two feeds into one. Since I'm using Rails 2.3.5, I have to use the construct_finder_sql method to render a scope into its base sql. In Rails 3.0, I could use the to_sql method. user.rb def feed "(#{Article.by_groups(self).send(:construct_finder_sql,{})}) UNION (#{Article.by_contacts(self).send(:construct_finder_sql,{})})" end And finally, I can now call this method and paginate it from my controller using will_paginate's paginate_by_sql method. HomeController.rb @articles = Article.paginate_by_sql(current_user.feed, :page => 1) And we're done! It may seem simple now, but it was a lot of work getting there. Feedback is always appreciated. In particular, it would be great to get away from some of the raw sql hacking. Cheers.

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• mysql index optimization for a table with multiple indexes that index some of the same columns

  - by Sean

  I have a table that stores some basic data about visitor sessions on third party web sites. This is its structure: id, site_id, unixtime, unixtime_last, ip_address, uid There are four indexes: id, site_id/unixtime, site_id/ip_address, and site_id/uid There are many different types of ways that we query this table, and all of them are specific to the site_id. The index with unixtime is used to display the list of visitors for a given date or time range. The other two are used to find all visits from an IP address or a "uid" (a unique cookie value created for each visitor), as well as determining if this is a new visitor or a returning visitor. Obviously storing site_id inside 3 indexes is inefficient for both write speed and storage, but I see no way around it, since I need to be able to quickly query this data for a given specific site_id. Any ideas on making this more efficient? I don't really understand B-trees besides some very basic stuff, but it's more efficient to have the left-most column of an index be the one with the least variance - correct? Because I considered having the site_id being the second column of the index for both ip_address and uid but I think that would make the index less efficient since the IP and UID are going to vary more than the site ID will, because we only have about 8000 unique sites per database server, but millions of unique visitors across all ~8000 sites on a daily basis. I've also considered removing site_id from the IP and UID indexes completely, since the chances of the same visitor going to multiple sites that share the same database server are quite small, but in cases where this does happen, I fear it could be quite slow to determine if this is a new visitor to this site_id or not. The query would be something like: select id from sessions where uid = 'value' and site_id = 123 limit 1 ... so if this visitor had visited this site before, it would only need to find one row with this site_id before it stopped. This wouldn't be super fast necessarily, but acceptably fast. But say we have a site that gets 500,000 visitors a day, and a particular visitor loves this site and goes there 10 times a day. Now they happen to hit another site on the same database server for the first time. The above query could take quite a long time to search through all of the potentially thousands of rows for this UID, scattered all over the disk, since it wouldn't be finding one for this site ID. Any insight on making this as efficient as possible would be appreciated :) Update - this is a MyISAM table with MySQL 5.0. My concerns are both with performance as well as storage space. This table is both read and write heavy. If I had to choose between performance and storage, my biggest concern is performance - but both are important. We use memcached heavily in all areas of our service, but that's not an excuse to not care about the database design. I want the database to be as efficient as possible.

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