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• MS Access MSChart.Graph.8 not printing

  - by Tanj

  Software: Microsoft Access 2007 SP2 Database File Version: Access 2000 I have an access program that I inherited from a previous employee. It uses forms for reports and since I don't have much experience in access I have continued to do this. I have created a copy of the program for another project and modified it to suit. I am having trouble getting more then one chart to print. All the charts display in form view, they all have the same properties (excepting data, position, etc.) For some reason they are not printing. They don't even show up in the print preview. I am thinking it must be something with the graphs themselves as they sometimes lose all information. I have to open the graphs in edit mode and change the data source from column to row and back again so that it gets redrawn. (Refresh doesn't fix it) So right now I don't even have a clue as to where to look so ideas are welcome. Edit #1 It seems to be a problem with linking to an unbound form. Subform Field Linker: Can't build a link between unbound forms. The query for the main form is SELECT tTest.ixTest, tMotorTypes.ixMotorType, tMotorTypes.asMotorType, tMotorTypes.fDeprecated, tTestType.asTest, tTest.asSerialNum, tTest.asOrderNum, tTest.asFrameNum, tTest.asRotorNum, tTest.asOperator, tTest.iStation, tTest.dtTestDate, tTest.ixTestType FROM tMotorTypes INNER JOIN (tTestType INNER JOIN tTest ON tTestType.ixTestType=tTest.ixTestType) ON tMotorTypes.ixMotorType=tTest.ixMotorType; The query for the chart is: SELECT qGraphRSTTemperatures.Frequency, qGraphRSTTemperatures.[Drive End], qGraphRSTTemperatures.[Non Drive End], qGraphRSTTemperatures.[Air In], qGraphRSTTemperatures.Core FROM qGraphRSTTemperatures ORDER BY qGraphRSTTemperatures.ixTemperature; Query qGraphRSTTemperatures: SELECT tElectricalData.dblFrequency AS Frequency, tTemperatures.dblDrvEnd AS [Drive End], tTemperatures.dblNonDrvEnd AS [Non Drive End], tTemperatures.dblAirIn AS [Air In], tTemperatures.dblCore AS Core, tSubTest.ixTest, tTemperatures.ixTemperature FROM (tSubTest INNER JOIN tElectricalData ON tSubTest.ixSubTest = tElectricalData.ixSubTest) LEFT JOIN tTemperatures ON tElectricalData.ixElectrical = tTemperatures.ixElectrical WHERE (((tSubTest.ixSubTestType)=5)) ORDER BY tSubTest.ixTest, tTemperatures.ixTemperature; So how come, in the form view it shows the graph with the correct data when linked thus: Child field: ixTest Master field: ixTest but won't print the graph. The graph will print if I remove the links, but then I have all the data from chart query as it is not limited by ixTest. edit #2 It seems to be a data retrieval/rendering issue in printing. Is there anything in printing that changes the context of records with respect to parent/child relationships?

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• Calling class member through uninitialized class pointer

  - by Adil

  I have following code snippet: class ABC{ public: int a; void print(){cout<<"hello"<<endl;} }; int main(){ ABC *ptr = NULL: ptr->print(); return 0; } It runs successfully. Can someone explain it?

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• Matplotlib: plotting discrete values

  - by Arkapravo

  I am trying to plot the following ! from numpy import * from pylab import * import random for x in range(1,500): y = random.randint(1,25000) print(x,y) plot(x,y) show() However, I keep getting a blank graph (?). Just to make sure that the program logic is correct I added the code print(x,y), just the confirm that (x,y) pairs are being generated. (x,y) pairs are being generated, but there is no plot, I keep getting a blank graph. Any help ?

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• Python beginner confused by a complex line of code

  - by Protean

  I understand the gist of the code, that it forms permutations; however, I was wondering if someone could explain exactly what is going on in the return statement. def perm(l): sz = len(l) print (l) if sz <= 1: print ('sz <= 1') return [l] return [p[:i]+[l[0]]+p[i:] for i in range(sz) for p in perm(l[1:])]

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• Calling class method through NULL class pointer

  - by Adil

  I have following code snippet: class ABC{ public: int a; void print(){cout<<"hello"<<endl;} }; int main(){ ABC *ptr = NULL: ptr->print(); return 0; } It runs successfully. Can someone explain it?

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• Equivalent of python eval in Haskell

  - by TheMachineCharmer

  There is function in python called eval that takes string input and evaluates it. >>> x = 1 >>> print eval('x+1') 2 >>> print eval('12 + 32') 44 >>> What is Haskell equivalent of eval function?

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• Hot python input loop

  - by Josh K

  I'd like to have something similar to the following pseudo code: while input is not None and timer < 5: input = getChar() timer = time.time() - start if timer >= 5: print "took too long" else: print input Anyway to do this without threading? I would like an input method that returns whatever has been entered since the last time it was called, or None (null) if nothing was entered.

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• how to use drawItems() in PyQt?

  - by DSblizzard

  I have these two code fragments in program: class TGraphicsView(QGraphicsView): def __init__(self, parent = None): print("__init__") QGraphicsView.__init__(self, parent) def drawItems(self, Painter, ItemCount, Items, StyleOptions): print("drawItems") Brush = QBrush(Qt.red, Qt.SolidPattern) Painter.setBrush(Brush) Painter.drawEllipse(0, 0, 100, 100) ... Mw.gvNavigation = TGraphicsView(Mw) # Mw - main window Mw.gvNavigation.setGeometry(0, 0, Size1, Size1) Mw.gvNavigation.setScene(Mw.Scene) Mw.gvNavigation.setSceneRect(0, 0, Size2, Size2) Mw.gvNavigation.show() _init_ works, Mw.gvNavigation is displayed and there are Mw.Scene items in it, but drawItems() isn't called. Please explain, what I'm doing wrong.

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• How do I get user input to refer to a variable in Python?

  - by somefreakingguy

  I would like to get user input to refer to some list in my code. I think it's called namespace? So, what would I have to do to this code for me to print whatever the user inputs, supposing they input 'list1' or 'list2'? list1 = ['cat', 'dog', 'juice'] list2 = ['skunk', 'bats', 'pogo stick'] x = raw_input('which list would you like me to print?') I plan to have many such lists, so a series of if...then statements seems unruly.

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• Passing javascript variable to python

  - by William S.

  Hi, for example: #!/usr/bin/python print "This is python." print "<script type="text/javascript"> var pass_to_python = new Number(7) </script>" the_number = pass_to_python??? How do i get the pass_to_python in python? Thanks.

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• Generate a list of file names based on month and year arithmetic

  - by MacUsers

  How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here? Update: I think, I better upload the entire script for better understanding. #!/usr/bin/env python import os, sys from time import strftime from calendar import month_abbr vGroup = {} vo = "group_lhcb" SI00_fig = float(2.478) months = tuple(month_abbr) print "\n%-12s\t%10s\t%8s\t%10s" % ('VOs','CPU-time','CPU-time','kSI2K-hrs') print "%-12s\t%10s\t%8s\t%10s" % ('','(in Sec)','(in Hrs)','(*2.478)') print "=" * 58 for inFile in os.listdir('.'): if inFile.isdigit(): readFile = open(inFile, 'r') lines = readFile.readlines() readFile.close() month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) for line in lines[2:]: if line.find(vo)==0: g, i = line.split() s = vGroup.get(g, 0) vGroup[g] = s + int(i) sumHrs = ((vGroup[g]/60)/60) sumSi2k = sumHrs*SI00_fig print "%-12s\t%10s\t%8s\t%10.2f" % (mnYear,vGroup[g],sumHrs,sumSi2k) del vGroup[g] When I run the script, I get this: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ================================================== Jan, 2011 211201372 58667 145376.83 Dec, 2010 5064337 1406 3484.07 Feb, 2011 17506049 4862 12048.04 Sep, 2010 210874275 58576 145151.33 As I said in the original post, I like the result to be in this order instead: Sep, 2010 210874275 58576 145151.33 Dec, 2010 5064337 1406 3484.07 Jan, 2011 211201372 58667 145376.83 Feb, 2011 17506049 4862 12048.04 The files in the source directory reads like this: [root@serv07 usage]# ls -l total 3632 -rw-r--r-- 1 root root 1144972 Feb 9 19:23 01 -rw-r--r-- 1 root root 556630 Feb 13 09:11 02 -rw-r--r-- 1 root root 443782 Feb 11 17:23 02.bak -rw-r--r-- 1 root root 1144556 Feb 14 09:30 09 -rw-r--r-- 1 root root 370822 Feb 9 19:24 12 Did I give a better picture now? Sorry for not being very clear in the first place. Cheers!! Update @Mark Ransom This is the result from Mark's suggestion: [root@serv07 usage]# ./test.py VOs CPU-time CPU-time kSI2K-hrs (in Sec) (in Hrs) (*2.478) ========================================================== Dec, 2010 5064337 1406 3484.07 Sep, 2010 210874275 58576 145151.33 Feb, 2011 17506049 4862 12048.04 Jan, 2011 211201372 58667 145376.83 As I said before, I'm looking for the result to b printed in this order: Sep, 2010 - Dec, 2010 - Jan, 2011 - Feb, 2011 Cheers!!

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• identifier token keyword antlr parser

  - by batman_for

  How to handle the case where the token 'for' is used in two different situations in the language to parse? Such as statement and as a "parameter" as the following example: echo for print example for i in {0..10..2} do echo "Welcome $i times" done Output: for print example Welcome 0 times Welcome 2 times Welcome 4 times Welcome 6 times Welcome 8 times Welcome 10 times Thanks.

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• FQL or Facebook API: Get only my events created

  - by user347466

  Guys.. i have this query: select eid from event where creator = 100000956216009 Return this error: error: 604 Your statement is not indexable. The WHERE clause must contain an indexable column. Such columns are marked with * in the tables linked from http://wiki.developers.facebook.com/index.php/FQL_Tables How i can get all My Created events? TIA I need to print my events created on my fb account and print it on my External Site.

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• Python, Unicode, and the Windows console

  - by James Sulak

  When I try to print a Unicode string in a windows console, I get a "UnicodeEncodeError: 'charmap' codec can't encode character ...." error. I assume this is because the Windows console does not accept Unicode-only characters. What's the best way around this? Is there any way I can make Python automatically print a "?" instead of failing in this situation? Edit: I'm using Python 2.5.

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• the error "invalid literal for int() with base 10:" keeps coming up

  - by ratce003

  I'm trying to write a very simple program, I want to print out the sum of all the multiples of 3 and 5 below 100, but, an error keeps accuring, saying "invalid literal for int() with base 10:" my program is as follows: sum = "" sum_int = int(sum) for i in range(1, 101): if i % 5 == 0: sum += i elif i % 3 == 0: sum += i else: sum += "" print sum Any help would be much appreciated.

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• Using a regex to match IP addresses in Python

  - by MHibbin

  I'm trying to make a test for checking whether a sys.argv input matches the regex for an IP address... As a simple test, I have the following... import re pat = re.compile("\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}") test = pat.match(hostIP) if test: print "Acceptable ip address" else: print "Unacceptable ip address" However when I pass random values into it, it returns "Acceptable ip address" in most cases, except when I have an "address" that is basically equivalent to \d+ Any thoughts welcome. Cheers Matt

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• Select stats from different days

  - by Michael

  What is the most efficient way to do this? Right now I am doing it this way.. then print $counttoday; print $countyesterday; I know there has to be a better way to do this. Let me know, thanks!

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• Advanced Regex: Smart auto detect and replace URLs with anchor tags

  - by Robert Koritnik

  I've written a regular expression that automatically detects URLs in free text that users enter. This is not such a simple task as it may seem at first. Jeff Atwood writes about it in his post. His regular expression works, but needs extra code after detection is done. I've managed to write a regular expression that does everything in a single go. This is how it looks like (I've broken it down into separate lines to make it more understandable what it does): 1 (?<outer>\()? 2 (?<scheme>http(?<secure>s)?://)? 3 (?<url> 4 (?(scheme) 5 (?:www\.)? 6 | 7 www\. 8 ) 9 [a-z0-9] 10 (?(outer) 11 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\)) 12 | 13 [-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+ 14 ) 15 ) 16 (?<ending>(?(outer)\))) As you may see, I'm using named capture groups (used later in Regex.Replace()) and I've also included some local characters (cšžcd), that allow our localised URLs to be parsed as well. You can easily omit them if you'd like. Anyway. Here's what it does (referring to line numbers): 1 - detects if URL starts with open braces (is contained inside braces) and stores it in "outer" named capture group 2 - checks if it starts with URL scheme also detecting whether scheme is SSL or not 3 - start parsing URL itself (will store it in "url" named capture group) 4-8 - if statement that says: if "sheme" was present then www. part is optional, otherwise mandatory for a string to be a link (so this regular expression detects all strings that start with either http or www) 9 - first character after http:// or www. should be either a letter or a number (this can be extended if you'd like to cover even more links, but I've decided not to because I can't think of a link that would start with some obscure character) 10-14 - if statement that says: if "outer" (braces) was present capture everything up to the last closing braces otherwise capture all 15 - closes the named capture group for URL 16 - if open braces were present, capture closing braces as well and store it in "ending" named capture group First and last line used to have \s* in them as well, so user could also write open braces and put a space inside before pasting link. Anyway. My code that does link replacement with actual anchor HTML elements looks exactly like this: value = Regex.Replace( value, @"(?<outer>\()?(?<scheme>http(?<secure>s)?://)?(?<url>(?(scheme)(?:www\.)?|www\.)[a-z0-9](?(outer)[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+(?=\))|[-a-z0-9/+&@#/%?=~_()|!:,.;cšžcd]+))(?<ending>(?(outer)\)))", "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}", RegexOptions.Compiled | RegexOptions.CultureInvariant | RegexOptions.IgnoreCase); As you can see I'm using named capture groups to replace link with an Anchor tag: "${outer}<a href=\"http${secure}://${url}\">http${secure}://${url}</a>${ending}" I could as well omit the http(s) part in anchor display to make links look friendlier, but for now I decided not to. Question I would like my links to be replaced with shortenings as well. So when user copies a very long link (for instance if they would copy a link from google maps that usually generates long links) I would like to shorten the visible part of the anchor tag. Link would work, but visible part of an anchor tag would be shortened to some number of characters. I could as well append ellipsis at the end of at all possible (and make things even more perfect). Does Regex.Replace() method support replacement notations so that I can still use a single call? Something similar as string.Format() method does when you'd like to format values in string format (decimals, dates etc...).

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• Python begineer confused by a piece of code

  - by Protean

  I understand the gist of the code, that it forms permutations; however, I was wondering if someone could explain exactly what is going on in the return statement. def perm(l): sz = len(l) print (l) if sz <= 1: print ('sz <= 1') return [l] return [p[:i]+[l[0]]+p[i:] for i in range(sz) for p in perm(l[1:])]

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• Python File Search Line And Return Specific Number of Lines after Match

  - by Simos Anderson

  I have a text file that has lines representing some data sets. The file itself is fairly long but it contains certain sections of the following format: Series_Name INFO Number of teams : n1 | Team | # | wins | | TeamName1 | x | y | . . . | TeamNamen1 | numn | numn | Some Irrelevant lines Series_Name2 INFO Number of teams : n1 | Team | # | wins | | TeamName1 | num1 | num2 | . where each section has a header that begins with the Series_Name. Each Series_Name is different. The line with the header also includes the number of teams in that series, n1. Following the header line is a set of lines that represents a table of data. For each series there are n1+1 rows in the table, where each row shows an individual team name and associated stats. I have been trying to implement a function that will allow the user to search for a Team name and then print out the line in the table associated with that team. However, certain team names show up under multiple series. To resolve this, I am currently trying to write my code so that the user can search for the header line with series name first and then print out just the following n1+1 lines that represent the data associated with the series. Here's what I have come up with so far: import re print fname = raw_input("Enter filename: ") seriesname = raw_input("Enter series: ") def findcounter(fname, seriesname): logfile = open(fname, "r") pat = 'INFO Number of teams :' for line in logfile: if seriesname in line: if pat in line: s=line pattern = re.compile(r"""(?P<name>.*?) #starting name \s*INFO #whitespace and success \s*Number\s*of\s*teams #whitespace and strings \s*\:\s*(?P<n1>.*)""",re.VERBOSE) match = pattern.match(s) name = match.group("name") n1 = int(match.group("n1")) print name + " has " + str(n1) + " teams" lcount = 0 for line in logfile: if line.startswith(name): if pat in line: while lcount <= n1: s.append(line) lcount += 1 return result The first part of my code works; it matches the header line that the person searches for, parses the line, and then prints out how many teams are in that series. Since the header line basically tells me how many lines are in the table, I thought that I could use that information to construct a loop that would continue printing each line until a set counter reached n1. But I've tried running it, and I realize that the way I've set it up so far isn't correct. So here's my question: How do you return a number of lines after a matched line when given the number of desired lines that follow the match? I'm new to programming, and I apologize if this question seems silly. I have been working on this quite diligently with no luck and would appreciate any help.

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• Printing Reporting Services in a page throught Javascript

  - by Gabriel Guimarães

  I Have a PerformancePoint Server 2007 Dashboard in a Sharepoint 2007 page. In my Sharepoint page, there's 2 Filters who get passed to the Report, and I need to print this report in the page (in another button, not the SSRS one). So what I need is a javascript method that calls the SSRS print button, which is on a named DIV, inside a WebPartZone that only have one WebPart, a PerformancePoint Dashboard Item (don't know the exact name of the webpart).

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• Unicode troubles

  - by user343803

  Hello, i have just known Python for few days. Unicode seems to be a problem with Python. i have a text file stores a text string like this '\u0110\xe8n \u0111\u1ecf n\xfat giao th\xf4ng Ng\xe3 t\u01b0 L\xe1ng H\u1ea1' i can read the file and print the string out but it displays incorrectly. How can i print it out to screen correctly as follow: "Ðèn d? nút giao thông Ngã tu Láng H?" Thanks in advance

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• How to loop on a JSON object?

  - by Damiano

  Hello, I have this JSON object: {"time":"123456789", "raw":"chat_history", "data":{ "msg":[ {"time":1111111111, "user":"user1", "text":"text from user1"}, {"time":2222222222, "user":"user2", "text":"text from user2"}, {"time":3333333333, "user":"user3", "text":"text from user3"}, {"time":4444444444, "user":"user4", "text":"text from user4"} ] }} I have to create a FOR to loop the elements of data.msg and print it: I would print these results with the FOR: 11111111111 - user1 - text from users1 22222222222 - user2 - text from users2 33333333333 - user3 - text from users3 44444444444 - user4 - text from users4 Could you help me? Thank you very much

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• Long string insertion with sed

  - by Luis Varca

  I am trying to use this expression to insert the contents of one text file into another after a give string. This is a simple bash script: TEXT=`cat file1.txt` sed -i "/teststring/a \ $TEXT" file2.txt This returns an error, "sed: -e expression #1, char 37: unknown command: `M'" The issue is in the fact that the contents of file1.txt are actually a private certificate so it's a large amount of text and unusual characters which seems to be causing an issue. If I replace $TEXT with a simple ASCII value it works but when it reads the large content of file1.txt it fails with that error. Is there some way to carry out this action? Is my syntax off with sed or my quote placement wrong?

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• Simaltaneous connections with PHP and SOAP?

  - by Dov

  I'm new to using SOAP and understanding the utmost basics of it. I create a client resource/connection, I then run some queries in a loop and I'm done. The issue I am having is when I increase the iterations of the loop, ie: from 100 to 1000, it seems to run out of memory and drops an internal server error. How could I possibly run either a) multiple simaltaneous connections or b) create a connection, 100 iterations, close connection, create connection.. etc. "a)" looks to be the better option but I have no clue as to how to get it up and running whilst keeping memory (I assume opening and closing connections) at a minimum. Thanks in advance! index.php <?php // set loops to 0 $loops = 0; // connection credentials and settings $location = 'https://theconsole.com/'; $wsdl = $location.'?wsdl'; $username = 'user'; $password = 'pass'; // include the console and client classes include "class_console.php"; include "class_client.php"; // create a client resource / connection $client = new Client($location, $wsdl, $username, $password); while ($loops <= 100) { $dostuff; } ?> class_console.php <?php class Console { // the connection resource private $connection = NULL; /** * When this object is instantiated a connection will be made to the console */ public function __construct($location, $wsdl, $username, $password, $proxyHost = NULL, $proxyPort = NULL) { if(is_null($proxyHost) || is_null($proxyPort)) $connection = new SoapClient($wsdl, array('login' => $username, 'password' => $password)); else $connection = new SoapClient($wsdl, array('login' => $username, 'password' => $password, 'proxy_host' => $proxyHost, 'proxy_port' => $proxyPort)); $connection->__setLocation($location); $this->connection = $connection; return $this->connection; } /** * Will print any type of data to screen, where supported by print_r * * @param $var - The data to print to screen * @return $this->connection - The connection resource **/ public function screen($var) { print '<pre>'; print_r($var); print '</pre>'; return $this->connection; } /** * Returns a server / connection resource * * @return $this->connection - The connection resource */ public function srv() { return $this->connection; } } ?>

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