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  • Link redirects to "show" action instead of the indicated in routes.rb

    - by Brian Roisentul
    I'm working with Ruby on rails 2.3.4 and I'd like to have a link that executes an action when clicked. The relevant part of the routes.rb file looks like this: map.search_filter_relevance "/anuncios/buscar", :controller => 'announcements', :action => 'search_filter_relevance' My view(it's the model's index page) looks like this: <%= link_to 'M&Aacute;S RELEVANTES', search_filter_relevance_path %> And my controller looks like this: def search_filter_relevance raise params.inspect unless params[:announcements].nil? or params[:announcements].empty? @announcements = params[:announcements].order_by_featured end end The problem is that when I click the link I get an error due to some null value in the Show action! I'm not accessing that action at all...why is executing it?

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  • Make user object available to all Controllers in Zend?

    - by Sled
    Hey guys, I'm using Zend_Auth to identify a user in my application. This creates a session with the userobject. My question is how do I make this object available to every Controller and action, so I don't have to pull it out of the session every time I need data from this object? I'm guessing this should be done in bootstrap.php or index.php but I don't really know how to makte it available to every controller.. so any code examples would be appreciated! Thanks!

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  • Testing methods called on yielded object

    - by Todd R
    I have the following controller test case: def test_showplain Cleaner.expect(:parse).with(@somecontent) Cleaner.any_instance.stubs(:plainversion).returns(@returnvalue) post :showplain, {:content => @somecontent} end This works fine, except that I want the "stubs(:plainversion)" to be an "expects(:plainversion)". Here's the controller code: def showplain Cleaner.parse(params[:content]) do | cleaner | @output = cleaner.plainversion end end And the Cleaner is simply: class Cleaner ### other code and methods ### def self.parse(@content) cleaner = Cleaner.new(@content) yield cleaner cleaner.close end def plainversion ### operate on @content and return ### end end Again, I can't figure out how to reliably test the "cleaner" that is made available from the "parse" method. Any suggestions?

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  • jquery $.ajax not working in firefox against rails (406 response) (works in chrome & IE)

    - by phil swenson
    I have a rails backend and am testing the following jquery code against it: var content = $("#notification_content").val(); var data = new Object(); data.content = content; $.ajax({ url: "/notifications/detect_type.json", type:"POST", data: data, success: function(result ){updateTypeDropDown(result)}}); This code works fine in Chrome and IE. However in Firefox (using Firebug), I see this: http://localhost:3000/notifications/detect_type.json 406 Not Acceptable here is a chrome request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:05:59) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson denver co 80209", "controller"="notifications"} User Columns (2.0ms) SHOW FIELDS FROM users User Load (37.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 58ms (View: 1, DB: 40) | 406 Not Acceptable [http://localhost/notifications/detect_type.json] here is a firefox request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:06:41) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson 80209", "controller"="notifications"} User Columns (2.1ms) SHOW FIELDS FROM users User Load (30.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 100ms (View: 1, DB: 33) | 200 OK [http://localhost/notifications/detect_type.json] I'm stumped. Ideas?

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  • Devise role based routing

    - by teknull
    I have an app with multiple users. Each user as a theoretical role (user, client, etc). I've designed a view/controller for each user type. I want to be able to login each type of user do a different root url and lock them to it. Originally I was going to add a column to Users in Devise called role and so I can differentiate the users. The problem I'm having is how to say in routes.rb if current_user.role == "client" root :to = 'controller#index' Once they are logged in to the page I also want to keep them from being able to visit any of my other paths ie: domain.com/calls domain.com/units I've been looking into cancan to run alongside Devise but I'm not sure if this is the answer.

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  • Where to put a recursive function when following MVC?

    - by Glibly
    Hello, I have a recursive function being used to generate a menu on my site. The function is calling a database for each level of children in the menu, and generating html for them. I've currently put this function in a Model part of the code, however, I feel that generating html in the model goes against the MVC. I didn't put it in a Controller because I didn't want to have database calls or HTML generation there. I didn't put it in a View because I didn't want database calls there either. Is the 'correct' way of tackling this problem to have a Controller call a recursive function in a Model that returns a 2d array representing the menu. Then pass the array to a view which has it's own recursive function for generating html from the array?

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  • How to record when user follows external links without slowing user down

    - by taw
    I want to track when user clicks external links for analytics purposes. The simplest solution is to replace all external links with links to special record-and-redirect controller, but that would slow the user unnecessarily. The second idea would be to override click event and within in $.post a message to record controller, then let the main event handler happen, which will usually be either click (open link in same tab) or middle click (open in new tab) - good either way, and the user won't have to wait for wait for my server to record it, it's fire-and-forget. (I don't care if users without Javascript don't get tracked) Is that a reasonable way to go? Or what else would be the best way to track all external link clicks?

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  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

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  • Rendering Views as String with Spring MVC and Apache Tiles

    - by lynxforest
    I am trying to reuse some of my tiles in a controller which is returning a json response to the client. I would like to return a json response similar to the following format: { 'success': <true or false>, 'response': <the contents of an apache tile> } In my controller I would like to perform logic similar to this pseudocode: boolean valid = validator.validate(modelObj) String response = "" if(valid){ response = successView.render() // im looking for a way to actually accomplish // this, where the successView is the apache tiles view. // I would also need to pass a model map to the view somehow. }else{ response = errorView.render() } writeJsonResponse(httpResponse, /* a Map whose json representation looks like the one I described above. */)

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  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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  • Teacher confused about MVC?

    - by Gideon
    I have an assignment to create a game in java using MVC as a pattern. The thing is that stuff I read about MVC aren't really what the teacher is telling me. What I read is that the Model are the information objects, they are manipulated by the controllers. So in a game the controller mutates the placement of the objects and check if there is any collision etc. What my teacher told me is that I should put everything that is universal to the platform in the models and the controllers should only tell the model which input is given. That means the game loop will be in a model class, but also collision checks etc. So what I get from his story is that the View is the screen, the Controller is the unput handeler, and the Model is the rest. Can someone point me in the right direction?

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  • back button wont work.. Iphone

    - by lotuseater
    Hi, I have 2 page controls in my app, one for category and when i click details button of that category other page control comes. I have pushed the first view controller and used present modal view controller. Now a need to go back to the home page from the category page control but the view did load and view will appear wont work. That is where i have added my navigation bar programmatically. is there any way i can call them? i am new to iphone programming. Please help me if you can.... Thankyou

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  • Joomla forwarding code to the View...is this the correct way to do it?

    - by jax
    Here are some sample methods from my Controller class. Now when the user clicks the New button $task=add is sent to the Controller and the add() method is called. As you can see it does not really do anything, it just creates a url and forwards it off to the correct view. Is this the correct way of doing things in the MVC pattern? /** * New button was pressed */ function add() { $link = JRoute::_('index.php?option=com_myapp&c=apps&view=editapp&cid[]=', false); $this->setRedirect($link); } /** * Edit button was pressed - just use the first selection for editing */ function edit() { $cid = JRequest::getVar( 'cid', array(0), '', 'array' ); $id = $cid[0]; $link = JRoute::_("index.php?option=com_myapp&c=apps&view=editapp&cid[]=$id", false); $this->setRedirect($link); }

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  • Decorators vs. classes in python web development.

    - by Tristan
    I've noticed three main ways Python web frameworks deal request handing: decorators, controller classes with methods for individual requests, and request classes with methods for GET/POST. I'm curious about the virtues of these three approaches. Are there major advantages or disadvantages to any of these approaches? To fix ideas, here are three examples. Bottle uses decorators: @route('/') def index(): return 'Hello World!' Pylons uses controller classes: class HelloController(BaseController): def index(self): return 'Hello World' Tornado uses request handler classes with methods for types: class MainHandler(tornado.web.RequestHandler): def get(self): self.write("Hello, world") Which style is the best practice?

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  • How do I (or should I?) access the service layer from a SiteMesh template (views/layouts/main.gsp) in Grails?

    - by knorv
    I need to create a toplist in the page footer on a site that I'm building. The footer is created in the default SiteMesh layout template (views/layouts/main.gsp). In order to create the toplist access to the database is needed, so I've encapsulated all logic needed for the toplist creation in a service class (services/FooService). Please note that while services are usually accessed from the controller layer, in this case the default layout template (views/layouts/main.gsp) is not generated from a controller. Can the layout view (views/layouts/main.gsp) access a service class? How? Is this the correct design decision? If not, what is a better encapsulation and how do I interact with said encapsulation from the layout view (views/layouts/main.gsp)?

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  • How to add :format options to a named route in Rails?

    - by Alfred Nerstu
    I've got a named route called profile and I would like to be able to access it as json. But when I look at my rake routes output I see that the (.:format) is missing. How do I add it to a named route? user GET /users/:id(.:format) {:action=>"show", :controller=>"users"} profile /:username {:action=>"show", :controller=>"users"} Thanks in advance!

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  • What are the differences between MVP, Presentation Model, MVVM and MVC?

    - by Nicholas
    I have a pretty good idea how each of these patterns work some of the minor differences between them, but are they really all that different from each other? It seems to me that the Presenter, Presentation Model, ViewModel and Controller are essentially the same concept. Why couldn't I classify all of these concepts as controllers? I feel like it might simplify the entire idea a great deal. Can anyone give a clear description of their differences? I want to clarify that I do understand how the patterns work, and have implemented most of them in one technology or another. What I am really looking for is someone's experience with one of these patterns, and why they would not consider their ViewModel a controller for instance.

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  • Subprocess with variables & Command from different class

    - by Pastelinux
    source: http://pastebin.com/utL7Ebeq My thinking is that if i run from controller class "main" it will allow me to take the "data" from Class "model", def "filename". It doesn't seem to work. As you can see below what i mean class Controller: def __init__(self): self.model = Model() self.view = View() def main(self): data = self.model.filename() self.view.tcpdump(data) class View: def tcpdump(self, command): subprocess.call(command.split(), shell=False) When i run my code i get this error: subprocess.call(command.split(), shell=False) AttributeError: 'NoneType' object has no attribute 'split' My guess means that its not picking up command (look at source for reference) or that its not getting command with variables. But i know the error when variables are not being picked up so i don't think it is that. My question is, from what i have thus far, how do i from "class view" grab "command" for my subprocesses to run. Thanks~ John Riselvato

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  • iPhone - Landscape Only App

    - by Robert
    Hello all! I am trying to make an app that will only be viewed in Landscape. I have looked up some tutorials (albeit older ones) and have done the following: -set up the info.plist to include a key for uiinterfaceorientation -in the main view controller I have set the frame to be 480 x 320 Now, the first screen loads up ok. Everything is where it should be and whatnot. However, if I click a button that is set to present a modal view controller nothing happens. Everything is linked and coded correctly but nothing happens when I press the button. Am I doing something wrong with trying to force landscape? At it's basic, this question is a how do you effectively make an app that will only be in landscape mode? Thanks for any help.

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  • Are @property's necessary for Interface Builder?

    - by Rits
    In my UIViewController subclass, I have 3 UIView's with each a @property as an IBOutlet. I do not use these properties at all in my code. The views get instantiated as soon as the view controller is created and they are deallocated when the view controller is deallocated. I was thinking; can't I just remove the @property's? I did, and I could still connect my instance variables (with IBOutlet) in Interface Builder. So my question now is; is there any use for properties in combination with Interface Builder, or is it OK to leave them out? Is it required for some memory management or something? Or are they really just for use in your own code? And if I do leave them out, do I still need to release them in dealloc?

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  • Conditional value for ActiveRecord create method only

    - by Steve Wright
    I have a form where I have an administrator creating new users. The form uses the User model I created (login, password, first_name, etc...). For the last field on the form, I want to have a checkbox that doesn't need to be stored as part of the User record, but it is needed for the controller. This will control whether or not the newly created user will receive a welcome email or not. def create @user = User.new(params[:user]) if @user.save if @user.send_welcome_email UserMailer.welcome_email(@user).deliver end redirect_to(admin_users_url, :notice => "User #{@user.name} was successfully created.") else render :action => "new" end end In my view (haml) I am trying to access it like this: %p Send Welcome Email? = f.check_box :send_welcome_email I tried to make this an attr_accessible: :send_welcome_email but the controller does not recognize it. I get an undefined method 'send_welcome_email' for #&lt;User:0x00000100d080a8&gt; I would like it to look like this: What is the best way to get this working:

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  • iPhone screen rotates at random !

    - by Baldoph
    I use a tabBar Controller as root controller. It has 4 tabs and each of its ViewControllers has - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)toInterfaceOrientation { return YES; } as long as the tabBarController itself. But when I rotate the device (real or simulator), the screen turns at random! If it doesn't turn when I open the application it would have the same behavior until I quit the app. I tried to add the 4 viewControllers one by one in IB to see if one was problematic, but I obtained the same issue. It only always works when there is no tabs at all! Please tell me if you have any ideas. Thanks!

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  • How to get the action from the HttpServlet request to dispatch to multiple pages

    - by JFB
    I am using the Page Controller pattern. How could I use the same controller for two different pages by detecting the request action and then dispatching according to the result? Here is my code: account.jsp <form name="input" action="<%=request.getContextPath() %>/edit" method="get"> <input type="submit" value="Modifier" /> </form> Account Servlet public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { System.out.println("received HTTP GET"); String action = request.getParameter("action"); if (action == null) { // the account page dispatch(request, response, "/account"); } else if (action == "/edit") { // the popup edit page dispatch(request, response, "/edit"); } protected void dispatch(HttpServletRequest request, HttpServletResponse response, String page) throws javax.servlet.ServletException, java.io.IOException { RequestDispatcher dispatcher = getServletContext() .getRequestDispatcher(page); dispatcher.forward(request, response); } }

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  • Passing ViewData to PartialView returned from using Html.Action

    - by RWGodfrey
    I want to embed a partial view in an ASP.NET MVC page by returning it from an action method. In my base view, I would have: <%= Html.Action("MyPartialViewAction") %> My controller would have an action method like: [ChildActionOnly] public ActionResult MyPartialViewAction() { return PartialView("MyPartialView"); } I expected the returned partial view (MyPartialView) to have access to the ViewData that was set in the base page's controller action but that doesn't appear to be the case. If I insert the partial view by using the following in my base view it works: <% Html.RenderPartial("MyPartialView") %> I don't want to do that though because I want my "MyPartialViewAction" to execute logic to determine WHICH partial view to return.

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  • Does anybody have practice in programming PCMEF - architectures?

    - by Erkki
    PCMEF is an architecture style presented in the book Practical Software Engineering by Maciaszek and Liong. The layers are: P: Presentation C: Controller M: Mediator E: Entity F: Foundation. It is some kind of enchancement compared with MVC - architecture. I recommend it to interactice, data and communicating - oriented purposes. I have programmed it using Visual Prolog. Foundation in my applications is the data model (domains) for the application. PCMEF is like a simulated computer: Presentation is the display, Controller the user interface and event handling, Mediator the internal logic and data highway. Entity is the database or external interfaces and F defines the knowledge. This is a really nice small architecture. Does any other have experiance of it?

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