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  • Use the Django ORM in a standalone script (again)

    - by Rishabh Manocha
    I'm trying to use the Django ORM in some standalone screen scraping scripts. I know this question has been asked before, but I'm unable to figure out a good solution for my particular problem. I have a Django project with defined models. What I would like to do is use these models and the ORM in my scraping script. My directory structure is something like this: project scrape #scraping scripts ... test.py web django_project settings.py ... #Django files I tried doing the following in project/scrape/test.py: print os.path.join(os.path.abspath('..'), 'web', 'django_project') sys.path.append(os.path.join(os.path.abspath('..'), 'web', 'django_project')) print sys.path print "-------" os.environ['DJANGO_SETTINGS_MODULE'] = 'django_project.settings' #print os.environ from django_project.myapp.models import MyModel print MyModel.objects.count() However, I get an ImportError when I try to run test.py: Traceback (most recent call last): File "test.py", line 12, in <module> from django_project.myapp.models import MyModel ImportError: No module named django_project.myapp.models One solution I found around this problem is to create a symbolic link to ../web/govcheck in the scrape folder: :scrape rmanocha$ ln -s ../web/govcheck ./govcheck With this, I can then run test.py just fine. However, this seems like a hack, and more importantly, is not very portable (I will have to create this symbolic link everywhere I run this code). So, I was wondering if anyone has any better solutions for my problem?

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  • Test Ruby-on-Rails controller with RSpec and different route name

    - by jhwist
    I have a Rails model named Xpmodule with a corresponding controller XpmoduleController. class XpmoduleController < ApplicationController def index @xpmodule = Xpmodule.find(params[:module_id]) end def subscribe flash[:notice] = "You are now subscribed to #{params[:subscription][:title]}" redirect_to :action => :index end end The original intent was to name the model Module which for obvious reasons doesn't work. However I still want to have the URLs look like /module/4711/ therefore I added this to my routes.rb: map.connect '/module/:module_id', :controller => 'xpmodule', :action => 'index' map.connect '/module/:module_id/subscribe', :controller => 'xpmodule', :action => 'subscribe' Now I want to test this controller with Rspec: describe XpmoduleController do fixtures :xpmodules context "index" do it "should assign the current xpmodule" do xpm = mock_model(Xpmodule) Xpmodule.should_receive(:find).and_return(xpm) get "index" assigns[:xpmodule].should be_an_instance_of(Xpmodule) end end end for which I get No route matches {:action=>"index", :controller=>"xpmodule"}. Which of course is sort-of right, but I don't want to add this route just for testing purposes. Is there a way to tell Rspec to call a different URL in get?

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  • installing paramiko

    - by fixxxer
    This may sound like a repeated question on SF, but I could not find a clear answer to it, yet.So. I installed Paramiko 1.7 with "setup.py install" command and while running the demo.py program, I got this error: Traceback (most recent call last): File "C:\Documents and Settings\fixavier\Desktop\paramiko-1.7\demos\demo.py", line 33, in <module> import paramiko File "C:\Python26\lib\site-packages\paramiko\__init__.py", line 69, in <module> from transport import randpool, SecurityOptions, Transport File "C:\Python26\lib\site-packages\paramiko\transport.py", line 32, in <module> from paramiko import util File "C:\Python26\lib\site-packages\paramiko\util.py", line 31, in <module> from paramiko.common import * File "C:\Python26\lib\site-packages\paramiko\common.py", line 99, in <module> from Crypto.Util.randpool import PersistentRandomPool, RandomPool ImportError: No module named Crypto.Util.randpool I'm getting this error even after installing PyCrypto 2.1. On running test.py(which comes with the installation), I got the following error - Traceback (most recent call last): File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\test.py", line 18, in <module> from Crypto.Util import test File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\build/lib.win32-2.6\Crypto\Util\test.py", line 17, in <module> import testdata File "C:\Documents and Settings\fixavier\Desktop\pycrypto-2.0.1\pycrypto-2.0.1\test\testdata.py", line 450, in <module> from Crypto.Cipher import AES ImportError: cannot import name AES I don't have the confidence to go ahead and install AES after all this, for all I know I may get another ImportError! Please advice.Is it the way of installation thats problematic?

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  • EF4 Generate Database

    - by shaneseaton
    Hi, I am trying my hardest to find the simplest way to create a basic "model first" entity framework example. However I am struggling with the actually generation of the database, particularly the running of the SQL against the database. Tools Visual Studio 2010 SQL Server 2008 Express Process Create a new class project Add a new Server-Database item (mdf) named "Database1.mdf" to the project Add an empty ADO.net Entity Model Create a simple entity (Person: Id, Name) Generate the Script selecting the Database1 connection created for me by visual studio Right click the script editor and select the "Execute SQL..." option Log in to SQLEXPRESS This is where is falls over saying it cant find a database name "Database1". The "problem" is that the SQL server has not had Database1 attached to it. I am 100% positive that Visual Studio use to attach a database to SQLExpress when it created a new database (Step 2). This appears to not be the case any more (even the beta of VS2010 did it). Can someone confirm this? or tell me how to get this to happen? Is there a way that I can modify the TSQL script to use an un-attached database. ie a file. I know I can use SQL Management Studio or sqlcmd to attach the database, but I would ideally like to avoid the solutions as I would like to see the cleanest method of just using visual studio. Ideal Solutions (in order of most prefered) Get visual studio to attach the newly created database Modify the generated SQL to point to file Thanks in advance.

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  • Problems with zend-tool reporting that providers are not valid

    - by Mario
    I have recently setup XAMPP 1.7.3 and ZendFramework 1.10.4 on a new computer and many of the commands that I normally use now fail. Here are the steps I used to setup and test ZF. First I added the ZF library folder (C:\xampp\php\ZendFramework-1.10.4\library) to the include path in php.ini. Then I added the ZF bin folder (C:\xampp\php\ZendFramework-1.10.4\bin) to my Path system variable. To test that everything is configured correctly I ran the command "zf show version" from the command line. The result is "Zend Framework Version: 1.9.6". Immediately something appears to be wrong. The file that is downloaded is "ZendFramework-1.10.4.zip" and the reported version is 1.9.6. I have re-downloaded the latest version (1.10.4) and removed old copy. Still the incorrect version number problem persisted. Having done some research there is a bug in the ZF knowledgebase that version 1.10.3 reports a wrong version number. So that may explain the version number problem. Moving forward I tried to run some zf-tool commands and certain commands reports that the action or provider is not valid. Example: C:\xampp\htdocs>zf create project test Creating project at C:/xampp/htdocs/test C:\xampp\htdocs>cd test C:\xampp\htdocs\test>zf create controller Test Creating a controller at C:\xampp\htdocs\test/application/controllers/TestController.php ... Updating project profile 'C:\xampp\htdocs\test/.zfproject.xml' C:\xampp\htdocs\test>zf create action test Test Creating an action named test inside controller at C:\xampp\htdocs\test/application/controllers/TestController.php ... Updating project profile 'C:\xampp\htdocs\test/.zfproject.xml' C:\xampp\htdocs\test>zf enable layout An Error Has Occurred Action 'enable' is not a valid action. ... C:\xampp\htdocs\test>zf create form Test An Error Has Occurred Provider 'form' is not a valid provider. ... Can any one provide insight into these errors and how to correct them?

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  • json-framework: EXC_BAD_ACCESS on stringWithObject

    - by Vegar
    UPDATE: I found that the reason for the previous error was an error in the documentation. The method should be named proxyForJson, not jsonProxyObject... But I'm still stuck, though. I now get an EXC_BAD_ACCESS error inside stringWithObject some where. Any clues? UPDATE 2: My proxyForJson implementation is a cut-n-paste from then documentation: - (id)proxyForJson { return [NSDictionary dictionaryWithObjectsAndKeys: Navn, @"Navn", Adresse, @"Adresse", Alder, @"Alder", nil]; } Trying to make json serialization work for my custom objective-c class. As I understand the documentation, json-framework can serialize custom objects, if they implement the jsonProxyObject method. So I have this class: @interface MyObject : NSObject { NSString *Name; NSString *Addresse; NSInteger Age; } @property (nonatomic, retain) NSString *Name; @property (nonatomic, retain) NSString *Addresse; @property (nonatomic, assign) NSInteger Age; - (id)jsonProxyObject; @end And I try to serialize an array with some instances in it: [json stringWithObject:list error:&error]; But all I get is he following error: "JSON serialisation not supported for MyObject" I guess the jsonWriter can't find my jsonProxyObject method for some reason, buy why? Regards.

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  • ASP.NET/C# - Deserialize XML, XSD.exe created multiple classes

    - by Barryman9000
    I'm trying to deserialize some XML (returned from a web service) into an object that I created using XSD.exe. The XSD executable created a .CS file with a different partial class for each parent node in the XML. For Example, the beginning of the XML looks like this (why can't I post xml here? sorry, this is ugly): <disclaimer><notificationDescription>Additional charges will apply.</notificationDescription></disclaimer><quote><masterQuote></masterQuote></quote> And the Class generated by the XSD.exe has a partial class named disclaimer with a get; set; string for notificationDescription. And another partial class for quoteMasterQuote with the corresponding child nodes as public strings. How can I deserialize this XML file into multiple classes? I found this code, but it seems like it'll only work for one object. public static PricingResponse2 DeSerialize(string _xml) { PricingResponse2 _resp = new PricingResponse2(); StringReader _strReader = new StringReader(_xml); XmlSerializer _serializer = new XmlSerializer(_resp.GetType()); XmlReader _xmlReader = new XmlTextReader(_strReader); try { _resp = (PricingResponse2)_serializer.Deserialize(_xmlReader); return _resp; } catch (Exception ex) { string _error = ex.Message; throw; } finally { _xmlReader.Close(); _strReader.Close(); _strReader.Dispose(); } } This is the first time I've tried this, so I'm a little lost.

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  • Why can't c# use inline anonymous lambdas or delegates?

    - by Samuel Meacham
    I hope I worded the title of my question appropriately. In c# I can use lambdas (as delegates), or the older delegate syntax to do this: Func<string> fnHello = () => "hello"; Console.WriteLine(fnHello()); Func<string> fnHello2 = delegate() { return "hello 2"; }; Console.WriteLine(fnHello2()); So why can't I "inline" the lambda or the delegate body, and avoid capturing it in a named variable (making it anonymous)? // Inline anonymous lambda not allowed Console.WriteLine( (() => "hello inline lambda")() ); // Inline anonymous delegate not allowed Console.WriteLine( (delegate() { return "hello inline delegate"; })() ); An example that works in javascript (just for comparison) is: alert( (function(){ return "hello inline anonymous function from javascript"; })() ); Which produces the expected alert box. UPDATE: It seems you can have an inline anonymous lambda in C#, if you cast appropriately, but the amount of ()'s starts to make it unruly. // Inline anonymous lambda with appropriate cast IS allowed Console.WriteLine( ((Func<string>)(() => "hello inline anonymous lambda"))() ); Perhaps the compiler can't infer the sig of the anonymous delegate to know which Console.WriteLine() you're trying to call? Does anyone know why this specific cast is required?

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  • Problem Binding a ObservableCollection to a ListBox in WPF/MVVM

    - by alexqs
    I'm working in some code , using wpf and starting to use mvvm. So far i have no problem, when i have one element and I have to show the values of it in the screen (binding of the specific name of the property). But now, i have to work with a property list , not knowing the names of it. So I created a class, named GClass, that only have two propierties, name and value. I created the ObservableCollection, and fill for now with direct values, and asign the view (lstview) datacontext with the object i have created. But I cant see any result, it always shows a blank listbox. Can someone tell me if see why is happening ? Code of c# VDt = new ObservableCollection<GClass>(); var vhDt = message.SelectSingleElement(typeof (Vh)) as Vehiculo; if(vhDt != null) { VDt.Add(new GClass() {Name = "Numero: ", Value = ""}); VDt.Add(new GClass() {Name = "Marca: ", Value = ""}); VDt.Add(new GClass() {Name = "Conductor: ", Value = ""}); lstview.DataContext = this; _regionManager.RegisterViewWithRegionInIndex(RegionNames.MainRegion, lstview, 0); Code of the view <ListBox Margin="5,5,5,25" ItemsSource="{Binding VDt}"> <ListBox.Template> <ControlTemplate> <ListViewItem Content="{Binding Name}"></ListViewItem> <ListViewItem Content="{Binding Value}"></ListViewItem> </ControlTemplate> </ListBox.Template> </ListBox> I have research here, but i cant see, what I'm doing wrong. I will apreciate if someone help me.

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  • php.ini file creation in server

    - by tibin mathew
    Hi, I am developing a php website. I cant see php.ini file in my server. my host will not provide it. So i'm now going to create a copy of that php.ini file. so i have tried system() i searched in google and i got this link. http://drupal.org/node/290592 Here they are using like this system("cp /usr/local/php5/lib/php.ini /home/YOURUSERNAME/php.ini"); in my server when i looked the phpinfo my php.ini location is /ms/svc/php5/conf/php.ini and when i looked for the current directory of my server using this $dir_path = str_replace( $_SERVER['DOCUMENT_ROOT'], "", dirname(realpath(FILE)) ) . DIRECTORY_SEPARATOR; i got my current directory as /netapp/whnas-swamp/s11/s11/01712/www.sample.com/webdocs/ so my system command will now look lke this system("/ms/svc/php5/conf/php.ini /netapp/whnas-swamp/s11/s11/01712/www.sample.com/webdocs/php.ini"); i have named this page as getthephpini.php and when i b rowse this page i got a blank page but no new php.ini file created in my server. Is any mistake in that code??? Can any one show me the correct way Please help me Thanks

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  • Reversing Django URLs With Extra Options

    - by Justin Voss
    Suppose I have a URLconf like below, and 'foo' and 'bar' are valid values for page_slug. urlpatterns = patterns('', (r'^page/(?P<page_slug>.*)/', 'myapp.views.someview'), ) Then, I could reconstruct the URLs using the below, right? >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/page/foo/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/page/bar/' But what if I change my URLconf to this? urlpatterns = patterns('', (r'^foo-direct/', 'myapp.views.someview', {'page_slug': 'foo'}), (r'^my-bar-page/', 'myapp.views.someview', {'page_slug': 'bar'}), ) I expected this result: >>> from django.core.urlresolvers import reverse >>> reverse('myapp.views.someview', kwargs={'page_slug': 'foo'}) '/foo-direct/' >>> reverse('myapp.views.someview', kwargs={'page_slug': 'bar'}) '/my-bar-page/' However, this throws a NoReverseMatch exception. I suspect I'm trying to do something impossible. Any suggestions on a saner way to accomplish what I want? Named URLs aren't an option, since I don't want other apps that link to these to need to know about the specifics of the URL structure (encapsulation and all that).

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  • Asp.net Webdeployment Project override applicationSettings

    - by citronas
    I got a web deyploment project for a web application project in vs 2008. While building the web deployment project, I want to replace properties in the web.config. My settings are autogenrated by the deisgner. <applicationSettings> <NAMESPACE.Properties.Settings> <setting name="Testenvironment" serializeAs="String"> <value>True</value> </setting> </NAMESPACE.Properties.Settings> </applicationSettings> In the config file which contains the settings for the specific server looks like the following: <?xml version="1.0"?> <applicationSettings> <NAMESPACE.Properties.Settings> <setting name="Testenvironment" serializeAs="String"> <value>False</value> </setting> </NAMESPACE.Properties.Settings> </applicationSettings> Sadly, this does not work. I get an error "The format of a configSource file must be an element containing the name of the section" that highlights the second line (2nd example code). How must the Tag be named in order to make evertything work? Edit: Deleting the "applicationSetting"-Tags does not work either.

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  • java: <identifier> expected with ArrayList

    - by A-moc
    I have a class named Storage. Storage contains an arraylist of special objects called Products. Each product contains information such as name, price, etc. My code is as follows: class Storage{ Product sprite = new Product("sprite",1.25,30); Product pepsi = new Product("pepsi",1.85,45); Product orange = new Product("orange",2.25,36); Product hershey = new Product("hershey",1.50,33); Product brownie = new Product("brownie",2.30,41); Product apple = new Product("apple",2.00,15); Product crackers = new Product("peanut",3.90,68); Product trailmix = new Product("trailmix",1.90,45); Product icecream = new Product("icecream",1.65,28); Product doughnut = new Product("doughnut",2.75,18); Product banana = new Product("banana",1.25,32); Product coffee = new Product("coffee",1.30,40); Product chips = new Product("chips",1.70,35); ArrayList<Product> arl = new ArrayList<Product>(); //add initial elements to arraylist arl.add(sprite); arl.add(pepsi); arl.add(orange); arl.add(hershey); arl.add(brownie); arl.add(apple); arl.add(peanut); arl.add(trailmix); arl.add(icecream); arl.add(doughnut); arl.add(banana); arl.add(coffee); arl.add(chips); } Whenever I compile, I get an error message on lines 141-153 stating <identifier> expected. I know it's an elementary problem, but I can't seem to figure this out. Any help is much appreciated.

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  • Binding DataGridComboBoxColumn to a one to many entity framework relation

    - by Cristian
    I have two tables in the model, one table contains entries related to the other table in a one to many relations, for example: Table User ID Name Table Comments ID UserID Title Text I want to show a datagrid in a WPF window with two columns, one text column with the User name and another column with a combobox showing all the comments made by the user. The datagrid definition is like this: <DataGrid AutoGenerateColumns="False" [layout options...] Name="dataGrid1" ItemsSource="{Binding}"> <DataGrid.Columns> <DataGridTextColumn Header="Name" Binding="{Binding Path=Name}"/> <DataGridComboBoxColumn Header="Comments" SelectedValueBinding="{Binding Path=UserID}" SelectedValuePath="ID" DisplayMemberPath="Title" ItemsSource="{Binding Path=Comments}" /> </DataGrid.Columns> </DataGrid> in the code I assign the DataContext like this: dataGrid1.DataContext = entities.Users; The entity User has a property named Comments that leads to all the comments made by the user. The queries are returning data and the user names are shown but the combobox is not being filled. May be the approach is totally wrong or I'm just missing a very simple point here, I'm opened to learn better methods to do this. Thanks

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  • Mark duplicates in MySql with php (without deleting)

    - by Adam
    So, I'm having some problems with a MySQL query (see other question), and decided to try a different approach. I have a database table with some duplicate rows, which I actually might need for future reference, so I don't want to remove. What I'm looking for is a way to display the data without those duplicates, but without removing them. I can't use a simple select query (as described in the other question). So what I need to do is write a code that does the following: 1. Go through my db Table. 2. Spot duplicates in the "ip" column. 3. Mark the first instance of each duplicate with "0" (in a column named "duplicate") and the rest with "1". This way I can later SELECT only the rows WHERE duplicate=0. NOTE: If your solution is related to the SELECT query, please read this other question first - there's a reason I'm not just using GROUP BY / DISTINCT. Thanks in advance.

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  • Building error in Eclipse with build.xml

    - by Zachary
    I am working on a Java project with Eclipse. This project requires a second project (not mine), named sams in its build-path. The sams is provided with a build.xml file and it should generate some code using Apache CXF when building it. When I use Apache ANT on Eclipse and run the cxf.generated command from its build file I get the following error: Buildfile: C:\Docs\ZacRocha\Desktop\sams\build.xml cxf.generated: [echo] Generating code using Apache CXF wsdl2java... [java] 16-Jun-2010 16:04:08 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] 16-Jun-2010 16:04:08 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] WSDLToJava Error: org.apache.cxf.wsdl11.WSDLRuntimeException: Fail to create wsdl definition from : file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivesoftware.wsdl%7d [java] Caused by : WSDLException: faultCode=PARSER_ERROR: Problem parsing 'file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivesoftware.wsdl%7d'.: java.io.FileNotFoundException: C:\Docs\ZacRocha\Desktop\sams\${archivesoftware.wsdl} (The system cannot find the file specified) [java] 16-Jun-2010 16:04:10 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] 16-Jun-2010 16:04:10 org.apache.cxf.binding.corba.CorbaConduit prepare [java] SEVERE: Could not resolve target object [java] WSDLToJava Error: org.apache.cxf.wsdl11.WSDLRuntimeException: Fail to create wsdl definition from : file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivehardware.wsdl%7d [java] Caused by : WSDLException: faultCode=PARSER_ERROR: Problem parsing 'file:/C:/Docs/ZacRocha/Desktop/sams/$%7barchivehardware.wsdl%7d'.: java.io.FileNotFoundException: C:\Docs\ZacRocha\Desktop\sams\${archivehardware.wsdl} (The system cannot find the file specified) BUILD SUCCESSFUL Total time: 4 seconds I am used to program on Eclipse and I know very little about building with Apache ANT. Can someone tell me where exactly the problem may be? Thanks in advance!

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  • WCF, ASMX Basic HTTP binding and IIS

    - by Brennan Mann
    Hello, I have been doing a lot of work with WCF "self" hosted applications. I recently was requested to write a web service where the calling client was a Linux based program named "WGET". I would like to use WCF instead of a traditional ASMX web service. The web service is returning a standard XML response. I am not sure of the underlining details between the two technologies but I know WCF is the proper route. I created a WCF service to be hosted in IIS ( using basicHttpBinding). 1.) Did classic ASMX web services ( standard HTTP POST/GET) use SOAP to return responses? I created an class from XSD for the web service response. What is really going on behind the scenes? Is there just special XML HTTP headers that know how to handle to response? Is the response not wrapped in SOAP? The traditional ASMX web service worked perfectly with the class I generated using the .Net "XSD" program. 2.) I want to use WCF for this service. Will using basicHttpBinding work? As I have read, that is the correct binding to use for ASMX clients. Does this use SOAP, standard HTTP headers, or something else? 3.) This is a dumb question because I have not done a lot of web service programming. I noticed on the ASMX default landing page there were examples for responses and code to invoke the functionality. When I create the same service using WCF, I had to create a client application to perform these tasks. Is there a way to expose the WCF endpoint like a classic ASMX service or is the WSDL the only route? As always, I really appreciate the feedback. Thanks, Brennan

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  • Problems with ltk (common lisp)

    - by Silvanus
    I installed ltk to Steel Bank Common Lisp with asdf-install, but I can't even start using it V_V. The code below is the simplest example in the documentation, and is copied almost verbatim. asdf:operate 'asdf:load-op :ltk) (defun hello-1() (with-ltk () (let ((b (make-instance 'button :master nil :text "Press Me" :command (lambda () (format t "Hello World!~&"))))) (pack b)))) (hello-1) This is the error message I get from sbcl: ; in: LAMBDA NIL ; (PACK B) ; ; caught STYLE-WARNING: ; undefined function: PACK ; (WITH-LTK NIL ; (LET ((B (MAKE-INSTANCE 'BUTTON :MASTER NIL :TEXT "Press Me" :COMMAND #))) ; (PACK B))) ; ; caught STYLE-WARNING: ; undefined function: WITH-LTK ; ; compilation unit finished ; Undefined functions: ; PACK WITH-LTK ; caught 2 STYLE-WARNING conditions debugger invoked on a SIMPLE-ERROR in thread #: There is no class named BUTTON. Type HELP for debugger help, or (SB-EXT:QUIT) to exit from SBCL. restarts (invokable by number or by possibly-abbreviated name): 0: [ABORT] Exit debugger, returning to top level. (SB-PCL::FIND-CLASS-FROM-CELL BUTTON NIL T)

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  • Problem with non blocking fifo in bash

    - by timdel
    Hi! I'm running a few Team Fortress 2 servers and I want to write a little management script. Basically the TF2 servers are a fg process which provides a server console, so I can start the server, type status and get an answer from it: ***@purple:~/tf2$ ./start_server_testing Auto detecting CPU Using AMD Optimised binary. Server will auto-restart if there is a crash. Console initialized. [bla bla bla] Connection to Steam servers successful. VAC secure mode is activated. status hostname: Team Fortress version : 1.0.6.1/15 3883 secure udp/ip : ***.***.133.31:27600 map : ctf_2fort at: 0 x, 0 y, 0 z players : 0 (2 max) # userid name uniqueid connected ping loss state adr Great, now I want to create a script which sends the command sm_reloadadmins to all my servers. The best way I found to do this is using a fifo named pipe. Now what I want to do is having this pipe readonly and non blocking to the server process, so I can write into the pipe and the server executes it, but still I want to write via console one the server, so if I switch back to the fg process of the server and I type status I want an answer printed. I tried this (assuming serverfifo is mkfifo serverfifo): ./start_server_testing < serverfifo Not working, the server won't start until something is written to the pipe. ./start_server_testing <> serverfifo Thats actually working pretty good, I can see the console output of the server and I can write to the fifo and the server executes the commands, but I can't write via console to the server anymore. Also, if I write 'exit' to the pipe (which should end the server) and I'm running it in a screen the screen window is getting killed for some reason (wtf why?). I only need the server to read the fifo without blocking AND all my keyboard input on the server itself should be send to the server AND all server ouput should be written to the console. Is that possible? If yes, how?

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  • Scapy Installed, when i use it as module Its full of errors ???

    - by Rami Jarrar
    I installed scapy 2.xx (after get some missed modules to make it install),, then i'm trying to use it as module in my python programs,, but i cant it give me alot of errors, I download and installed some missed modules and finally i'm depressed, because this error, after hard work i got this Traceback (most recent call last): File "<pyshell#0>", line 1, in <module> from scapy.all import * File "C:\Python26\scapy\all.py", line 43, in <module> from crypto.cert import * File "C:\Python26\scapy\crypto\cert.py", line 15, in <module> from Crypto.PublicKey import * File "C:\Python26\lib\Crypto\PublicKey\RSA.py", line 34, in <module> from Crypto import Random File "C:\Python26\lib\Crypto\Random\__init__.py", line 29, in <module> import _UserFriendlyRNG File "C:\Python26\lib\Crypto\Random\_UserFriendlyRNG.py", line 36, in <module> from Crypto.Random.Fortuna import FortunaAccumulator File "C:\Python26\lib\Crypto\Random\Fortuna\FortunaAccumulator.py", line 36, in <module> import FortunaGenerator File "C:\Python26\lib\Crypto\Random\Fortuna\FortunaGenerator.py", line 32, in <module> from Crypto.Util import Counter File "C:\Python26\lib\Crypto\Util\Counter.py", line 27, in <module> import _counter ImportError: No module named _counter by do the following code: from scapy.all import * p=sr1(IP(dst=ip_dst)/ICMP()) if p: p.show() so what should i do,, is there a solution for this ???

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  • git branch naming best practices

    - by skiphoppy
    I've been using a local git repository interacting with my group's CVS repository for several months, now. I've made an almost neurotic number of branches, most of which have thankfully merged back into my trunk. But naming is starting to become an issue. If I have a task easily named with a simple label, but I accomplish it in three stages which each include their own branch and merge situation, then I can repeat the branch name each time, but that makes the history a little confusing. If I get more specific in the names, with a separate description for each stage, then the branch names start to get long and unwieldy. I did learn looking through old threads here that I could start naming branches with a / in the name, i.e., topic/task, or something like that. I may start doing that and seeing if it helps keep things better organized. What are some best practices for naming git branches? Edit: Nobody has actually suggested any naming conventions. I do delete branches when I'm done with them. I just happen to have several around due to management constantly adjusting my priorities. :) As an example of why I might need more than one branch on a task, suppose I need to commit the first discrete milestone in the task to the group's CVS repository. At that point, due to my imperfect interaction with CVS, I would perform that commit and then kill that branch. (I've seen too much weirdness interacting with CVS if I try to continue to use the same branch at that point.)

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  • Django 1.4.1 error loading MySQLdb module when attempting 'python manage.py shell'

    - by Paul
    I am trying to set up MySQL, and can't seem to be able to enter the Django manage.py shell interpreter. Getting the output below: rrdhcp-10-32-44-126:django pavelfage$ python manage.py shell Traceback (most recent call last): File "manage.py", line 10, in <module> execute_from_command_line(sys.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 443, in execute_from_command_line utility.execute() File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/__init__.py", line 382, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 196, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 232, in execute output = self.handle(*args, **options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/base.py", line 371, in handle return self.handle_noargs(**options) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/core/management/commands/shell.py", line 45, in handle_noargs from django.db.models.loading import get_models File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 40, in <module> backend = load_backend(connection.settings_dict['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/__init__.py", line 34, in __getattr__ return getattr(connections[DEFAULT_DB_ALIAS], item) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 92, in __getitem__ backend = load_backend(db['ENGINE']) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/utils.py", line 24, in load_backend return import_module('.base', backend_name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/django/db/backends/mysql/base.py", line 16, in <module> raise ImproperlyConfigured("Error loading MySQLdb module: %s" % e) django.core.exceptions.ImproperlyConfigured: Error loading MySQLdb module: No module named _mysql Any suggestions really appreciated.

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  • NSBundle loading a NSViewController

    - by Staros
    Hey all, I'm looking into a project that would upload custom NSBundles that include a NSViewController. In my main program I've got this code to deal with the bundle after it's been loaded... id principalClass = [loadedBundle principalClass]; id instance = [[principalClass alloc] init]; [localLabel setStringValue:[instance name]]; NSView *incomingView = [[instance viewController] view]; [localView addSubview:incomingView]; [localView display]; And the principal classes init method in the bundle looks like this... -(id) init { if(self = [super init]){ name = @"My Plugin"; viewController = [[ViewController alloc] initWithNibName:@"View" bundle:nil]; } return self; } View.nib is a nib located in the bundles project. But whenever I load the bundle I get this error... 2010-05-27 09:11:18.423 PluginLoader[45032:a0f] unable to find nib named: View in bundle path: (null) 2010-05-27 09:11:18.424 PluginLoader[45032:a0f] -[NSViewController loadView] could not load the "View" nib. I know I've got everything wired up because the line [label setStringValue:[instance name]]; sets the label text correctly. Plus, if I take all of the clases in the bundle and load them into my main applications project everything works as expect. Any thoughts on how I can correctly reference "View" in my bundle? Thanks!

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  • GlassFish can't find persistence provider for EntityManager

    - by Xorty
    Hi, I am building Spring MVC project (2.5). It runs on GlassFish v3 server and I am using Hibernate for ORM mapping from Derby database. I am having trouble with deployment - GlassFish says : No Persistence provider for EntityManager named mvcspringPU. Here is how I create EntityManagerFactory : emf = Persistence.createEntityManagerFactory("mvcspringPU"); And here is my configuration file persistence.xml <?xml version="1.0" encoding="UTF-8"?> <persistence version="1.0" xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"> <persistence-unit name="mvcspringPU" transaction-type="JTA"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <jta-data-source>CarsDB</jta-data-source> <properties> <property name="hibernate.hbm2ddl.auto" value="update"/> </properties> </persistence-unit> </persistence> I am building with NetBeans 6.8, so things like build paths should be alright (generated by IDE itself).

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  • Convert text files to excel files using python

    - by Rahim Jaafar
    I am working on INFORMIX 4GL programs. That programs produce output text files.This is an example of the output: Lot No|Purchaser name|Billing|Payment|Deposit|Balance| J1006|JAUHARI BIN HAMIDI|5285.05|4923.25|0.00|361.80| J1007|LEE, CHIA-JUI AKA LEE, ANDREW J. R.|5366.15|5313.70|0.00|52.45| J1008|NAZRIN ANEEZA BINTI NAZARUDDIN|5669.55|5365.30|0.00|304.25| J1009|YAZID LUTFI BIN AHMAD LUTFI|3180.05|3022.30|0.00|157.75| This text files can manually convert to excel files.But, I wanna ask, is there any script that I can use to convert .txt files to .xls files ? Hi all,now I'm already can convert text files to excell file by python using script that was given from user named Rami Helmy.A big thanks for him.But now,That script will produce more than one excell files depends on the number of '|' from the text files.Beside that,That script also can only convert one text files.I a going to convert all text files without state the name of text files.Therefore,I am looking such a way on how to this script going to: output only one excell file convert all .txt files from the directory that was given from user. output excell's file name are automaticly copied from the file name of text files. I am new in python,hopefully someone can help me to solve my problems.Thank You.. done all the task,but there was something that I'm confused.. that output excell files contains an "square" symbol like this: then, how can I ensure that there is no square symbol like that after I convert from text files to excell? thank you...

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