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  • Creando un File Upload

    - by jaullo
    Para iniciar hablaremos un poco sobre el control File Upload, de esta forma daremos una idea general de que es y como trabaja. El File Upload es un control de asp.net que permite que los usuarios seleccionen un archivo de cualquier ubicación en el equipo y lo suban a un directorio predeterminado a traves de una página asp.net. En principio este control esta limitado para no permitir subir archivos de mas de 4 MB. Sin embargo, desde el webconfig de nuestra aplicacón podremos cambiar ese valor, ya sea para aumentarlo o bien para disminuirlo. Nuestro ejemplo, se enfocará en crear un webcontrol que permita seleccionar un archivo y guardarlo, asi que empecemos. Lo primero será agregar a nuestra página un webcontrol que llamaremos Upload.ascx Posteriormente en nuestro webcontrol, agregamos el siguiente código: <table style="width: 100%">         <tr>             <td colspan="3">             <div align="center">                  <asp:Label ID="Label1" runat="server" Text="File Upload"></asp:Label>              </div>             </td>                    </tr>         <tr>             <td style="width: 456px" rowspan="2">                                                             &nbsp;</td>             <td style="width: 386px">                                <div align="center">                         <asp:FileUpload ID="FileUpload1" runat="server" Height="24px" Width="243px" />                         <span id="Span1" runat="server" />                            </div>                      </td>             <td rowspan="2">                                                             </td>         </tr>         <tr>             <td style="width: 386px">                 <div align="center">                      <asp:ImageButton Id="btnupload" runat="server" OnClick="btnupload_Click"                     ImageUrl="~/Styles/img/upload.png" style="text-align: center" />           </div>                  </td>         </tr>         <tr>             <td colspan="3">                 &nbsp;</td>         </tr>     </table>  De esta forma nuestro control deberá verse algo así   Por último en el code behin de nuestro control agregamos el código a nuestro boton, el cual será el encargado de leer el archivo que se encuentra en el File Upload y guardarlo en la ruta especificada.  Protected Sub btnupload_Click(ByVal sender As Object, ByVal e As System.Web.UI.ImageClickEventArgs) Handles btnupload.Click         If FileUpload1.HasFile Then             Dim fileExt As String             fileExt = System.IO.Path.GetExtension(FileUpload1.FileName)             If (fileExt = ".exe") Then                 Label1.Text = "You can´t upload .exe file!"             Else                 Try                     FileUpload1.SaveAs(decrpath & _                        FileUpload1.FileName)                     Label1.Text = "File name: " & _                       FileUpload1.PostedFile.FileName & "<br>" & _                       "File Size: " & _                       FileUpload1.PostedFile.ContentLength & " kb<br>" & _                       "Content type: " & _                       FileUpload1.PostedFile.ContentType                 Catch ex As Exception                     Label1.Text = "ERROR: " & ex.Message.ToString()                 End Try             End If         Else             Label1.Text = "You have not specified a file!"         End If            End Sub   Como vemos en el código anterior tambien hemos agregado otros elementos los cuales nos dirán el nombre del archivo, el tipo de contenido y el tamaño en kb una vez que el archivo ha sido súbido al servidor. Por último deben tomar en cuenta que decrpath es la ruta en donde será subido el archivo, la cual deben variar a su gusto.

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  • php image upload library

    - by Tchalvak
    I'm looking to NOT reinvent the wheel with an image upload system in php. Is there a good standalone library that allows for: Creating the system for uploading, renaming, and perhaps resizing images. Creating the front-end, html and/or javascript for the form upload parts of image upload. I've found a lot of image gallery systems, but no promising standalone system & ui libraries, ready for insertion into custom php.

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  • How to Implement Complex Form Data?

    - by SoulBeaver
    I'm supposed to implement a relatively complex form that looks like follows, but has at least four more pages requiring the user to fill in all necessary information for the tracks: This data will need to be sent to the server, which is implemented using Dropwizard. I'm looking for best practices on how to upload and send such a complex form with potentially dozens of songs to the server. The simplest available solution I have seen is a simple multipart/form-data request with the following form schema (Source): Client <html> <body> <h1>File Upload with Jersey</h1> <form action="rest/file/upload" method="post" enctype="multipart/form-data"> <p> Select a file : <input type="file" name="file" size="45" /> </p> <input type="submit" value="Upload It" /> </form> </body> </html> Server @POST @Path("/upload") @Consumes(MediaType.MULTIPART_FORM_DATA) public Response uploadTrack(final FormDataMultiPart multiPart) { List<FormDataBodyPart> artists = multiPart.getFields("artist"); StringBuffer output = new StringBuffer(); for (FormDataBodyPart artist : artists) output.append(artist.getValueAs(String.class)); List<FormDataBodyPart> tracks = multiPart.getFields("track"); for (FormDataBodyPart track : tracks) writeToFile(track.getValueAs(InputStream.class), "Foo"); return Response.status(200).entity(output.toString()).build(); } Then I have also read about file uploads via Ajax or Formdata (Mozilla HttpRequest) which allows for Posts in the formats application/x-www-form-urlencoded, multipart/form-data, or text/plain. I don't know which approach, if any, is best. An ideal solution would be to utilize Jackson to convert a json string into my data objects, but I don't get the impression that this is possible with binary data.

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  • Animation file format

    - by Paul
    I'm trying to make a simple 2D animation file format. It'll be very rudimentary: only an XML file containing some parameters (such as frame duration) and metadata, and some images, each representing a frame. I'd like to have the whole animation (frames and XML document) packed in a single file. How do you suggest I do that? What libraries are there that would allow easy access to the files inside the animation file itself? The language I'm using is C++ and the platform is Windows, but I'd rather not use a platform dependent library, if possible.

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  • how to upload & preview multiple images at single input and store in to php mysql [closed]

    - by Nilesh Sonawane
    This is nilesh , i am newcomer in this field , i need the script for when i click the upload button then uploaded images it should preview and store into db like wise i want to upload 10 images at same page using php mysql . #div { border:3px dashed #CCC; width:500px; min-height:100px; height:auto; text-align:center: } Multi-Images Uploader '.$f.''; } } } ? </div> <br> <font color='#3d3d3d' size='small'>By: Ahmed Hussein</font> this script select multiple images and then uplod , but i need to upload at a time only one image which preview and store into database like wise min 10 image user can upload .......

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  • Importing tab delimited file into array in Visual Basic 2013 [migrated]

    - by JaceG
    I am needing to import a tab delimited text file that has 11 columns and an unknown number of rows (always minimum 3 rows). I would like to import this text file as an array and be able to call data from it as needed, throughout my project. And then, to make things more difficult, I need to replace items in the array, and even add more rows to it as the project goes on (all at runtime). Hopefully someone can suggest code corrections or useful methods. I'm hoping to use something like the array style sMyStrings(3,2), which I believe would be the easiest way to control my data. Any help is gladly appreciated, and worthy of a slab of beer. Here's the coding I have so far: Imports System.IO Imports Microsoft.VisualBasic.FileIO Public Class Main Dim strReadLine As String Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load Dim sReader As IO.StreamReader = Nothing Dim sRawString As String = Nothing Dim sMyStrings() As String = Nothing Dim intCount As Integer = -1 Dim intFullLoop As Integer = 0 If IO.File.Exists("C:\MyProject\Hardware.txt") Then ' Make sure the file exists sReader = New IO.StreamReader("C:\MyProject\Hardware.txt") Else MsgBox("File doesn't exist.", MsgBoxStyle.Critical, "Error") End End If Do While sReader.Peek >= 0 ' Make sure you can read beyond the current position sRawString = sReader.ReadLine() ' Read the current line sMyStrings = sRawString.Split(New Char() {Chr(9)}) ' Separate values and store in a string array For Each s As String In sMyStrings ' Loop through the string array intCount = intCount + 1 ' Increment If TextBox1.Text <> "" Then TextBox1.Text = TextBox1.Text & vbCrLf ' Add line feed TextBox1.Text = TextBox1.Text & s ' Add line to debug textbox If intFullLoop > 14 And intCount > -1 And CBool((intCount - 0) / 11 Mod 0) Then cmbSelectHinge.Items.Add(sMyStrings(intCount)) End If Next intCount = -1 intFullLoop = intFullLoop + 1 Loop End Sub

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  • Upload File From URL

    - by Ryan Naddy
    I have been using Windows for a while, and with it there is a feature when you want to upload a photo (for example) to a website, you click on the "Choose File" in Chrome to upload a photo, a "File Explorer" opens, and instead of selecting a file from the hard drive you can paste a URL into the "File Explorer" and press open and it will download the file from the web to your temporary files, and use it to be uploaded. Is there any way I can do that in Ubuntu 12.10? Here is the windows example:Upload from url via File Explorer

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  • Debugger for file I/O development?

    - by datenwolf
    Okay, the question title may be a bit cryptic. But it aptly describes what I'm looking for: I think every experienced coder went through this numerous times: You get a binary file format specification, you implement the reader for it, and… nothing works like expected. So you run your code in the debugger, go execute through the code line by line, every header field is read in seemingly correct, but when it comes to the bulk data, offset and indices no longer match up. What would really help in this situation was a binary file viewer, that shows you the progress of your file pointer, as you step through the code, and ideally would also highlight all memory maps. Then you could see the context of the current I/O operations, most notably those darn "off-by-one" mistakes, which are even more annoying when reading a file. Implementing such a debugger should not be too hard. traces on the process' file descriptors/handles and triggers on the I/O functions, to update the display. Only: I don't know of such a kind of debugger to exist. Do I just lack knowledge about the existance of such a tool, or is there really no such thing?

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  • Large uploaded file won't display in Ubuntu One but is included in file usage

    - by user1488963
    On Ubuntu 10.04, I uploaded a single 711 MB. My total file usage in Ubuntu One went up to 877MB, which is about right, but the file doesn't show in Ubuntu One so I can't download or delete it. Either the file is there and I can't see it for some reason. Or the file is not there and the total file usage figure is wrong. Does anyone know what has happened? I have a free account but am well below my 5GB limit.

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  • Search a string in a file and write the matched lines to another file in Java

    - by Geeta
    For searching a string in a file and writing the lines with matched string to another file it takes 15 - 20 mins for a single zip file of 70MB(compressed state). Is there any ways to minimise it. my source code: getting Zip file entries zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while (entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if (entry.isDirectory()) { continue; } searchString(Thread.currentThread(),entry.getName(), new BufferedInputStream (zipFile.getInputStream(entry)), Out_File, search_string, stats); } zipFile.close(); Searching String public void searchString(Thread CThread, String Source_File, BufferedInputStream in, File outfile, String search, String stats) throws IOException { int count = 0; int countw = 0; int countl = 0; String s; String[] str; BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); System.out.println(CThread.currentThread()); while ((s = br2.readLine()) != null) { str = s.split(search); count = str.length - 1; countw += count; //word count if (s.contains(search)) { countl++; //line count WriteFile(CThread,s, outfile.toString(), search); } } br2.close(); in.close(); } -------------------------------------------------------------------------------- public void WriteFile(Thread CThread,String line, String out, String search) throws IOException { BufferedWriter bufferedWriter = null; System.out.println("writre thread"+CThread.currentThread()); bufferedWriter = new BufferedWriter(new FileWriter(out, true)); bufferedWriter.write(line); bufferedWriter.newLine(); bufferedWriter.flush(); } Please help me. Its really taking 40 mins for 10 files using threads and 15 - 20 mins for a single file of 70MB after being compressed. Any ways to minimise the time.

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  • best way to output a full precision double into a text file

    - by flevine100
    Hi, I need to use an existing text file to store some very precise values. When read back in, the numbers essentially need to be exactly equivalent to the ones that were originally written. Now, a normal person would use a binary file... for a number of reasons, that's not possible in this case. So... do any of you have a good way of encoding a double as a string of characters (aside from increasing the precision). My first thought was to cast the double to a char[] and write out the chars. I don't think that's going to work because some of the characters are not visible, produce sounds, and even terminate strings ('\0'... I'm talkin to you!) Thoughts?

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  • How to get proper alignment when printing to file

    - by user1067334
    I have this Structure the elements of which that I need to write in a text file struct Stage3ADisplay { int nSlot; char *Item; char *Type; int nIndex; unsigned char attributesMD[17]; //the last character is \0 unsigned char contentsMD[17]; //only for regular files - //the last character is \0 }; buffer = malloc(sizeof(Stage3ADisplayVar[nIterator]->nSlot) + sizeof(Stage3ADisplayVar[nIterator]->Item) + sizeof(Stage3ADisplayVar[nIterator]->Type) + sizeof(Stage3ADisplayVar[nIterator]->nIndex) + sizeof(Stage3ADisplayVar[nIterator]->attributesMD) + sizeof(Stage3ADisplayVar[nIterator]->contentsMD) + 1); sprintf (buffer,"%d %s %s %d %x %x",Stage3ADisplayVar[nIterator]->nSlot, Stage3ADisplayVar[nIterator]->Item,Stage3ADisplayVar[nIterator]->Type,Stage3ADisplayVar[nIterator]->nIndex,Stage3ADisplayVar[nIterator]->attributesMD,Stage3ADisplayVar[nIterator]->contentsMD); How do I make sure the rows in the file are properly aligned. Thank you.

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  • C read part of file into cache

    - by Pete Jodo
    I have to do a program (for Linux) where there's an extremely large index file and I have to search and interpret the data from the file. Now the catch is, I'm only allowed to have x-bytes of the file cached at any time (determined by argument) so I have to remove certain data from the cache if it's not what I'm looking for. If my understanding is correct, fopen (r) doesn't put anything in the cache, only when I call getc or fread(specifying size) does it get cached. So my question is, lets say I use fread and read 100 bytes but after checking it, only 20 of the 100 bytes contains the data I need; how would I remove the useless 80 bytes from cache (or overwrite it) in order to read more from the file.

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  • nginx php-fpm uploaded files have nginx ownership after executing move uploaded file

    - by Vangel
    I have a problem with php 5.3.6 using PHP-FPM and file uploads. My Nginx runs as user nginx PHP-FPM uses pools configured for each vhost. For example a user: test group : test runs one pool. When the php file uploads to temp file it is owned by user test. After move_uploaded_file is executed by php script it is owned by nginx :/. The reason for this could be the fact that the original upload file script does an exec('/usr/bin/php do_uploadedfiles.php') which does the actual moving. I do not know if the change in ownership to web server is the correct behaviour. Is there a way in PHP to change the ownership back to the user I want? Maybe make exec "run as"?

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  • split large text file without missing data record

    - by Santosh
    I have a 140 MB text file, which contains detail information of books in library. For each book details there is a standard format data details in text file. I need to parse it and insert the data in Database. Here, parsing text file is not an issue. I am facing problem in parsing this large file. So i decided to split the file in small file around 2 MB each file. But i can't manually split this large file in so many pieces. I got HJsplit tool, which split the file but this also doesn't helped as this split the file but 1 book details half part is in one file and rest part is in second file. so if i split this way then information will be missed. How to split the large so that i cant miss the information ? Is there any tool which help me in this condition.

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  • How are Java ByteBuffer's limit and position variable's updated?

    - by Dummy Derp
    There are two scenarios: writing and reading Writing: Whenever I write something to the ByteBuffer by calling its put(byte[]) method the position variable is incremented as: current position + size of byte[] and limit stays at the max. If, however, I put the data in a view buffer then I will have to, manually, calculate and update the position Before I call the write(ByteBuffer) method of the channel to write something, I will have to flip() the Bytebuffer so that position points to zero and limit points to the last byte that was written to the ByteBuffer. Reading: Whenever I call the read(ByteBuffer) method of a channel to read something, the position variable stays at 0 and the limit variable of the ByteBuffer points to the last byte that was read. So, if the ByteBuffer is smaller than the file being read, the limit variable is pushed to max This means that the ByteBuffer is already flipped and I can proceed to extracting the values from the ByteBuffer. Please, correct me where I am wrong :)

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  • Whats a good structure to save and retrieve locations of images?

    - by Goot
    I got a java-ee application, where I collect informations about movies. Im my backend I provide data like the name, description, genre and a random uuid. I also got lots of related files, which are stored on a file server. Including some screenshots, the dvd or bluRay cover and video trailers. My current approach is: When saving the files to the fileserver, I retrieve the movies random uuid (which is the primary key btw.). I then rename the files screenshot_[UUID]_1, screenshot_[UUID]_2 ... etc. Now, there are lots of other ways to handle this, like saving all filenames in a database or creating a dir structure on the fileserver for every uuid and, e.g., return all images in the "[uuid]/screenshots" folder via REST. I expect about 30k requests a day, so the service has to be pretty performant. Whats the best way to solve this?

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  • Very weird C file-handling anomaly

    - by KáGé
    Hello, I got a very weird issue that I cant figure out in my school project, which is the simulation of a simple filesystem in a human-readable textfile. Unfortunately I don't yet have enough time to translate the comments in my code or make it less gibberish, so if you are bothered by that, you don't have to help, I understand. See the code HERE. Now in drive.h, at line 574 is this part: i = getline(); #ifdef DEBUG printf("Free space in all found at %d.\n\n", i); if(drive.disk != NULL){ printf("Disk OK\n\n"); } #endif //write in data state = seekline(i); Before this it finds place for the allocation database entry in the ALL sector (see the "image files" in the mounts folder, this issue was tested on mount_30.efs-dbf), then gets the line with i = getline() fine (getline is in lglobal.h, line 39), but after that any file manipulation (in this case seekline's fseek, but if I comment that out, then the first fprintf after that) crashes the program straight away. I think the file gets somehow corrupted (though the Disk OK message appears) but can't figure out how. I've tried putting i = getline(); into comment, but it didn't make any difference. I've also tried asking at local programming forums but they didn't really help either. The last few lines of the output before it crashes: Dir written. (drive.h line 562) Seekline entered: 268 (called at drive.h line 564) Getline entered. (called at drive.h line 574) Line got: 268. Free space in all found at 268. (drive.h line 576) Seekline entered: 268 (called at drive.h line 582, note that this exact call was run successfully less than 20 lines back. This one should set the pointer to the beginning of the line it is currently in) After this it crashes. Does anyone has any idea of what causes this and how could I fix it? Thank you.

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  • Zabbix doesn't update value from file neither with log[] nor with vfs.file.regexp[] item

    - by tymik
    I am using Zabbix 2.2. I have a very specific environment, where I have to generate desired data to file via script, then upload that file to ftp from host and download it to Zabbix server from ftp. After file is downloaded, I check it with log[] and vfs.file.regexp[] items. I use these items as below: log[/path/to/file.txt,"C.*\s([0-9]+\.[0-9])$",Windows-1250,,"all",\1] vfs.file.regexp[/path/to/file.txt,"C.*\s([0-9]+\.[0-9])$",Windows-1250,,,\1] The line I am parsing looks like below: C: 8195Mb 5879Mb 2316Mb 28.2 The value I want to extract is 28.2 at the end of file. The problem I am currently trying to solve is that when I update the file (upload from host to ftp, then download from ftp to Zabbix server), the value does not update. I was trying only log[] at start, but I suspect, that log[] treat the file as real log file and doesn't check the same lines (althought, following the documentation, it should with "all" value), so I added vfs.file.regexp[] item too. The log[] has received a value in past, but it doesn't update. The vfs.file.regexp[] hasn't received any value so far. file.txt has got reuploaded and redownloaded several times and situation doesn't change. It seems that log[] reads only new lines in the file, it doesn't check lines already caught if there are any changes. The zabbix_agentd.log file doesn't report any problem with access to file, nor with regexp construction (it did report "unsupported" for log[] key, when I had something set up wrong). I use debug logging level for agent - I haven't found any interesting info about that problem. I have no idea what I might be doing wrong or what I do not know about how Zabbix is performing these checks. I see 2 solutions for that: adding more lines to the file instead of making new one or making new files and check them with logrt[], but those doesn't satisfy my desires. Any help is greatly appreciated. Of course I will provide additional information, if requested - for now I don't know what else might be useful.

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  • OAF Page to Upload Files into Server from local Machine

    - by PRajkumar
    1. Create a New Workspace and Project File > New > General > Workspace Configured for Oracle Applications File Name – PrajkumarFileUploadDemo   Automatically a new OA Project will also be created   Project Name -- FileUploadDemo Default Package -- prajkumar.oracle.apps.fnd.fileuploaddemo   2. Create a New Application Module (AM) Right Click on FileUploadDemo > New > ADF Business Components > Application Module Name -- FileUploadAM Package -- prajkumar.oracle.apps.fnd.fileuploaddemo.server Check Application Module Class: FileUploadAMImpl Generate JavaFile(s)   3. Create a New Page Right click on FileUploadDemo > New > Web Tier > OA Components > Page Name -- FileUploadPG Package -- prajkumar.oracle.apps.fnd.fileuploaddemo.webui   4. Select the FileUploadPG and go to the strcuture pane where a default region has been created   5. Select region1 and set the following properties --     Attribute Property ID PageLayoutRN AM Definition prajkumar.oracle.apps.fnd.fileuploaddemo.server.FileUploadAM Window Title Uploading File into Server from Local Machine Demo Window Title Uploading File into Server from Local Machine Demo     6. Create Stack Layout Region Under Page Layout Region Right click PageLayoutRN > New > Region   Attribute Property ID MainRN AM Definition messageComponentLayout   7. Create a New Item messageFileUpload Bean under MainRN Right click on MainRN > New > messageFileUpload Set Following Properties for New Item --   Attribute Property ID MessageFileUpload Item Style messageFileUpload   8. Create a New Item Submit Button Bean under MainRN Right click on MainRN > New > messageLayout Set Following Properties for messageLayout --   Attribute Property ID ButtonLayout   Right Click on ButtonLayout > New > Item   Attribute Property ID Submit Item Style submitButton Attribute Set /oracle/apps/fnd/attributesets/Buttons/Go   9. Create Controller for page FileUploadPG Right Click on PageLayoutRN > Set New Controller Package Name: prajkumar.oracle.apps.fnd.fileuploaddemo.webui Class Name: FileUploadCO   Write Following Code in FileUploadCO processFormRequest   import oracle.cabo.ui.data.DataObject; import java.io.FileOutputStream; import java.io.InputStream; import oracle.jbo.domain.BlobDomain; import java.io.File; import oracle.apps.fnd.framework.OAException; public void processFormRequest(OAPageContext pageContext, OAWebBean webBean) { super.processFormRequest(pageContext, webBean);    if(pageContext.getParameter("Submit")!=null)  {   upLoadFile(pageContext,webBean);      } }   -- Use Following Code if want to Upload Files in Local Machine -- ----------------------------------------------------------------------------------- public void upLoadFile(OAPageContext pageContext,OAWebBean webBean) { String filePath = "D:\\PRajkumar";  System.out.println("Default File Path---->"+filePath);  String fileUrl = null;  try  {   DataObject fileUploadData =  pageContext.getNamedDataObject("MessageFileUpload"); //FileUploading is my MessageFileUpload Bean Id   if(fileUploadData!=null)   {    String uFileName = (String)fileUploadData.selectValue(null, "UPLOAD_FILE_NAME");  // include this line    String contentType = (String) fileUploadData.selectValue(null, "UPLOAD_FILE_MIME_TYPE");  // For Mime Type    System.out.println("User File Name---->"+uFileName);    FileOutputStream output = null;    InputStream input = null;    BlobDomain uploadedByteStream = (BlobDomain)fileUploadData.selectValue(null, uFileName);    System.out.println("uploadedByteStream---->"+uploadedByteStream);                               File file = new File("D:\\PRajkumar", uFileName);    System.out.println("File output---->"+file);    output = new FileOutputStream(file);    System.out.println("output----->"+output);    input = uploadedByteStream.getInputStream();    System.out.println("input---->"+input);    byte abyte0[] = new byte[0x19000];    int i;         while((i = input.read(abyte0)) > 0)    output.write(abyte0, 0, i);    output.close();    input.close();   }  }  catch(Exception ex)  {   throw new OAException(ex.getMessage(), OAException.ERROR);  }     }   -- Use Following Code if want to Upload File into Server -- ------------------------------------------------------------------------- public void upLoadFile(OAPageContext pageContext,OAWebBean webBean) { String filePath = "/u01/app/apnac03r12/PRajkumar/";  System.out.println("Default File Path---->"+filePath);  String fileUrl = null;  try  {   DataObject fileUploadData =  pageContext.getNamedDataObject("MessageFileUpload");  //FileUploading is my MessageFileUpload Bean Id     if(fileUploadData!=null)   {    String uFileName = (String)fileUploadData.selectValue(null, "UPLOAD_FILE_NAME");   // include this line    String contentType = (String) fileUploadData.selectValue(null, "UPLOAD_FILE_MIME_TYPE");   // For Mime Type    System.out.println("User File Name---->"+uFileName);    FileOutputStream output = null;    InputStream input = null;    BlobDomain uploadedByteStream = (BlobDomain)fileUploadData.selectValue(null, uFileName);    System.out.println("uploadedByteStream---->"+uploadedByteStream);                               File file = new File("/u01/app/apnac03r12/PRajkumar", uFileName);    System.out.println("File output---->"+file);    output = new FileOutputStream(file);    System.out.println("output----->"+output);    input = uploadedByteStream.getInputStream();    System.out.println("input---->"+input);    byte abyte0[] = new byte[0x19000];    int i;         while((i = input.read(abyte0)) > 0)    output.write(abyte0, 0, i);    output.close();    input.close();   }  }  catch(Exception ex)  {   throw new OAException(ex.getMessage(), OAException.ERROR);  }     }   10. Congratulation you have successfully finished. Run Your page and Test Your Work           -- Used Code to Upload files into Server   -- Before Upload files into Server     -- After Upload files into Server       -- Used Code to Upload files into Local Machine   -- Before Upload files into Local Machine       -- After Upload files into Local Machine

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  • Help needed implementing a web based file management system with a file hierarchy system, help neede

    - by molleman
    Hello i am trying to create a web application that will allow users to upload files online, i am using gwt while using hibernate for database communication, i am able to upload file to a server , and store them on the server. but what i want is to associate the files with a user. i want the user to be able to create folders and store a file in sub folders. my logic was to use the composite pattern to store folders and fileLocations with a user but i am am finding it difficult to implement this so i can show the files and folders within a gwt tree. what would be the best way to implement a hierarchy of folders and information of the location of a file so it could be displayed in a gwt tree? what i did have was a User would hold a reference to a root folder and then each sub folder could hold folders or fileLocations. i used the composite pattern to implement the file hierarchy, but when i want to display a the contents of a folder i need a for loop for each list. so i could a folder within a folder within a folder that would need 3 for loops to show the contents of my folders. What is the best way to implement this file management system. so what do you guys think?

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