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  • XML to XHTML - Best Method?

    - by Ian
    Not wishing to be subjective but I have a need to get data from an XML source and convert it to (X)HTML. From my understanding I can do this with PHP (or other server-side scripts), Javascript, or XSLT. My feeling is that it would be more appropriate to use XSLT as it is dealing with an XML source and this is the purpose for which XSLT exists. I also see it having the advantage that it will still work if the user doesn't have Javascript enabled and wont be restricted to a server which runs PHP (or other server-side script). Am I right in my assumptions? Also could the same be same for an RSS feed? Thanks

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  • With XSLT, how can I use this if-test with an array, when search element is returned by a template call inside the for loop?

    - by codesforcoffee
    I think this simple example might ask the question a lot more clearly. I have an input file with multiple products. There are 10 types of product (2 product IDs is fine enough for this example), but the input will have 200 products, and I only want to output the info for the first product of each type. (Output info for the lowest priced one, so the first one will be the lowest price because I sort by Price first.) So I want to read in each product, but only output the product's info if I haven't already output a product with that same ID. I couldn't figure out how to get the processID template to return a value that I need to do my if-check on, that uses parameters from inside the for-each Product loop -then properly close the if tag in the right place so it won't output the open Product tag unless it passes the if test. I know the following code does not work, but it illustrates the idea and gives me a place to start: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output method="xml" encoding="UTF-8" indent="yes" cdata-section-elements="prod_name adv_notes"/> <xsl:template match="/"> <List> <xsl:for-each select="ProductGroup"> <xsl:sort select="ActiveProducts/Product/Rate"/> <xsl:variable name="IDarray"> <xsl:for-each select="ActiveProducts/Product"> <xsl:variable name="CurrentID"> <xsl:call-template name="processID"> <xsl:with-param name="ProductCode" select="ProductCode" /> </xsl:call-template> </xsl:variable> <xsl:if test="not(contains($IDarray, $CurrentID))"> <child elem="{@elem}"> <xsl:select value-of="$CurrentID" /> </child> <Product> <xsl:attribute name="ID"> <xsl:select value-of="$CurrentID" /> </xsl:attribute> <prod_name> <xsl:value-of select="../ProductName"/> </prod_name> <rate> <xsl:value-of select="../Rate"/> </rate> </Product> </xsl:if> </xsl:for-each> </xsl:variable> </xsl:for-each> </List> </xsl:template> <xsl:template name="processID"> <xsl:param name="ProductCode"/> <xsl:choose> <xsl:when test="starts-with($ProductCode, '515')">5</xsl:when> <xsl:when test="starts-with($ProductCode, '205')">2</xsl:when> </xsl:choose> </xsl:template> Thanks so much in advance, I know some of the awesome programmers here can help! :) -Holly An input would look like this: <ProductGroup> <ActiveProducts> <Product> <ProductCode> 5155 </ProductCode> <ProductName> House </ProductName> <Rate> 3.99 </Rate> </Product> <Product> <ProductCode> 5158 </ProductCode> <ProductName> House </ProductName> <Rate> 4.99 </Rate> </Product> </ActiveProducts> </ProductGroup> <ProductGroup> <ActiveProducts> <Product> <ProductCode> 2058 </ProductCode> <ProductName> House </ProductName> <Rate> 2.99 </Rate> </Product> <Product> <ProductCode> 2055 </ProductCode> <ProductName> House </ProductName> <Rate> 7.99 </Rate> </Product> </ActiveProducts> </ProductGroup> 200 of those with different attributes. I have the translation working, just needed to add that array and if statement somehow. Output would be this for only that simple input file:

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  • Unable to load huge XML document (incorrectly suppose it's due to the XSLT processing)

    - by krisvandenbergh
    I'm trying to match certain elements using XSLT. My input document is very large and the source XML fails to load after processing the following code (consider especially the first line). <xsl:template match="XMI/XMI.content/Model_Management.Model/Foundation.Core.Namespace.ownedElement/Model_Management.Package/Foundation.Core.Namespace.ownedElement"> <rdf:RDF> <rdf:Description rdf:about=""> <xsl:for-each select="Foundation.Core.Class"> <xsl:for-each select="Foundation.Core.ModelElement.name"> <owl:Class rdf:ID="@Foundation.Core.ModelElement.name" /> </xsl:for-each> </xsl:for-each> </rdf:Description> </rdf:RDF> </xsl:template> Apparently the XSLT fails to load after "Model_Management.Model". The PHP code is as follows: if ($xml->loadXML($source_xml) == false) { die('Failed to load source XML: ' . $http_file); } It then fails to perform loadXML and immediately dies. I think there are two options now. 1) I should set a maximum executing time. Frankly, I don't know how that I do this for the built-in PHP 5 XSLT processor. 2) Think about another way to match. What would be the best way to deal with this? The input document can be found at http://krisvandenbergh.be/uml_pricing.xml Any help would be appreciated! Thanks.

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  • Could not find function: resolve-uri

    - by Nisarg Mehta
    When i am trying to transform xml it gives me erro that Could not find function: resolve-uri where resolve-uri is a xpath function . below is my xslt line which will use resolve uri function . <xsl:variable name="filename" select="resolve-uri(concat($dir,'/',$xmlFileName,'_',position(),'.xml'))" /> Can anybody please help me.Is it because of xslt version difference ? Thanks in Advance.

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  • XSL Transform SVG to VML

    - by kzh
    I don't know anything about VML except that Internet Explorer and other Microsoft products use it and that it is a vector graphics format. Can one use XSLT to transform an SVG document to VML? Or are they too different from one another to make this possible? I know that there exist XSLT documents to transform SVG to XAML.

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  • Programatically upload XML file to SSRS server

    - by xt_20
    Hi all, How do I programatically upload an XSLT file to an SSRS server database? I would like exactly the same functionality as the 'Upload File', preferably using the 'rs' command. I have tried rs.CreateResource, but it doesn't seem to work for XML/XSLT files (though it works for Excel and image files) I understand that manipulating the SSRS db is not supported. Thanks

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  • Ant XML Custom Result Formatter

    - by Iso
    Hi, Can anyone point me the tutorial for step by step creating my onw XML custom result formatter. I read that we can create our own result formatter by specifying the XSLT in styledir. I want to know what should specify in XSLT, like the xml tag for testsuite name, testcase name and the result. Thanks in advance

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  • Sharepoint - connectable receiving, XSLT editable web part?

    - by Corey O.
    You can use the "Data View" webpart to take data from a database call, then you can edit the XSLT manually to make it look and do whatever you want, within the scope of that data and XSLT capabilities. Is there a web part that allows me to do the same thing, but with data that is received by a connected webpart source rather than a database set? For example: I'd like to be able to pull in a Data View webpart that queries a bunch of data and makes it available all over the page. Then, I would like to hide that Data View. Once it is hidden, I'd like to be able to take another customizable webpart and pull a field (or multiple fields if possible) from the Data View webpart via a webpart connection. This would allow me to display various fields in creative formats without having to call the same query multiple times on the same page by different webparts. Is there an in house webpart that will allow me to do this?

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  • xml declaration not being omitted from page

    - by Mark Schultheiss
    I have an XSLT transform I am using to process an XML file, inserting it into the body of my aspx page. Reference the following for background information: background on xml/xslt I have the following in my xml file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:myCustomStrings="urn:customStrings"> <xsl:output method="xml" version="2.0" media-type="text/html" omit-xml-declaration="yes" indent="yes" />...unrelated stuff left out here Here is the output that is relevent: <div id="example" /> <?xml version="1.0" encoding="utf-8"?><div xmlns:myCustomStrings="urn:customStrings"><div id="imFormBody" class="imFormBody"> My question relates to the output, specifically to the <?xml version="1.0" encoding="utf-8"?> which is getting included in the output anyway. Is the issue related to the custom method I have used? If so, I don't really see the need to include the xml part as the namespace is in the div tag. Is there a way to ensure that this extra stuff gets left out as I asked it to?

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  • Access external xml using xslt document function return 401

    - by Ciprian Grosu
    On MOSS2007, I have a webpart that display the content of a xml feed. I use a xslt with parameters for transforamtions. There is a situation when I receive a 401 Authorisation exception. I realize that this happen when a document() function from my xslt try to open an external xml. If I try to open this xml in browser all work ok. I provided my admin credentials to the web part and to the XmlSecureResolver. Same problem. The webpart is on server1 and the xml feed and external xml required by xslt is on server2. What can be ? protected override void RenderContents(HtmlTextWriter writer) { base.RenderContents(writer); if (string.IsNullOrEmpty(this.xmlUrl) || this.xmlResponseStream == null) return; try { XslCompiledTransform transform = new XslCompiledTransform(); if (UseXslt) { XmlTextReader stylesheet = null; try { SPSite site = new SPSite(xsltlUrl); SPWeb web = site.OpenWeb(); SPFile file = web.GetFile(xsltlUrl); if (file != null) { stylesheet = new XmlTextReader(file.OpenBinaryStream()); } } catch(Exception ex) { stylesheet = new XmlTextReader(xsltlUrl); } if (stylesheet != null) { transform.Load(stylesheet, new XsltSettings(true, true), GetAResolver()); } using (XmlReader reader = new XmlTextReader(this.xmlResponseStream)) { string theParams = xsltProperties; XsltArgumentList xslAgrs = GetXsltArgumentList(xsltProperties); XmlTextWriter results = new XmlTextWriter(writer.InnerWriter); if (UseProperties) { transform.Transform(reader, xslAgrs, results, GetASecureResolver()); } else { transform.Transform(reader, results); } reader.Close(); } } else { string feedAsString = null; using (StreamReader rssReader = new StreamReader(this.xmlResponseStream)) { feedAsString = rssReader.ReadToEnd(); writer.InnerWriter.Write(SPHttpUtility.HtmlEncode(feedAsString)); } } } catch (Exception ex) { writer.Write(ex.Message); if (this.xmlResponseStream != null) { this.xmlResponseStream.Close(); this.xmlResponseStream.Dispose(); } } } private static XmlSecureResolver GetASecureResolver() { // Create a secure resolver XmlSecureResolver resolver = new XmlSecureResolver(new XmlUrlResolver(), "http://externalservername.com/thesite/"); string proxyUserName = RssFeedUtility.GetConfigFileReader().ProxyUserName; string proxyUserPwd = RssFeedUtility.GetConfigFileReader().ProxyUserPassword; string proxyUserDomain = RssFeedUtility.GetConfigFileReader().ProxyUserDomain; resolver.Credentials = new NetworkCredential(proxyUserName, proxyUserPwd, proxyUserDomain); return resolver; }

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  • XML: Check if anything exists between two nodes

    - by sebastian
    Hi there, I need to find out if anything exists between two nodes. My XML looks like this: <event value1="1" value2="2" value3="3" <info="some info here"/> Line 1.</lb> Line 2.</lb></lb> Line 3.</lb> Line 4.</lb> </event> My goal is to convert the </lb> nodes to </br> HTML tags using XSLT. There is one additional requirement to fulfill though. In case there is one </lb> directly following another </lb> I want to output only one </br>. My XSLT looks like this: <xsl:template match="lb"> <xsl:if test="not(preceding-sibling::lb[1])"> <br/> </xsl:if> </xsl:template> The problem with the XSLT above is that it works correctly for line 1 only as the text between both nodes is ignored. Maybe someone here can help.

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  • TRICKEY ONE PLEASE SOLVE

    - by jack
    Create a DTD to record the sellers of merchandise to the Second-hand shop. Each seller has the child elements sellerID (in the format KSXXXXXXX), name, address, phone and sighted_identification. ? the name element has child elements of title and firstname and surname ? the address element has child elements address_line, suburb, state and postcode ? the sighted_identification can be any of the following – passport – drivers licence – birth certificate – Medicare card. –1. Create a DTD to record the sellers of merchandise to the Second-hand shop. Each seller has the child elements sellerID (in the format KSXXXXXXX), name, address, phone and sighted_identification. ? the name element has child elements of title and firstname and surname ? the address element has child elements address_line, suburb, state and postcode ? the sighted_identification can be any of the following – passport – drivers licence – birth certificate – Medicare card. Create an XML document for five sellers including at least two with multiple sighted identifications. 3. Create an XSLT style sheet to logically display all of the seller’s details. Note 1: it may help you to create lists for both sellers and for sighted_identification. Note 2: The shops database stores the sighted identification of sellers as p, dl, bc and mc rather than by their full name, so creating an entity for each type is required. Note 3: Your XSLT should order the sellers by sellerID – for this reason don’t have them ordered correctly in the XML file – rather sort the sellerID within the XSLT. OUTPUT SHOULD BE SOMETHING LIKE THIS SELLER ID : NAME: ADDRESS : PHONE : IDENTIFICATION : IDENTIFICATION : IDENTIFICATION :

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  • Looping and recursion based on parameter passed

    - by contactkx
    I have an XML organized like below- <section name="Parent 1 Text here" ID="1" > <section name="Child 1 Text here" ID="11"> </section> <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 1 Text here" ID="22"> </section> <section name="Child 2 Text here" ID="23"> <section name="GrandChild Text here" ID="232" > </section> </section> </section> I have to produce the below output XML - <section name="Parent 1 Text here" ID="1" > <section name="Child 2 Text here" ID="12"> <section name="GrandChild Text here" ID="121" > </section> </section> </section> <section name="Parent 2 Text here" ID="2" > <section name="Child 2 Text here" ID="23"> </section> </section> I have to achive above using XSLT 1.0 transformation. I was planning to pass a comma separated string as a parameter with value= "1,12,121,2,23" My question- How to loop the comma separated parameter in XSLT 1.0 ? Is there a simpler way to achieve the above. Please remember I have to do this in XSLT 1.0 Your help is appreciated.

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  • get another sequence elements'value in one sequence.

    - by lxusharp
    I have an XML file as below, and I want to transform it with xslt. I want to achieve is: when do the for-each of "s1" elements, I want to get the corresponding "r1"'s "value" attbute value. the xslt I wrote as below, but it does not work, can anyone give a help? thanks. <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl"> <xsl:output method="html" indent="yes"/> <xsl:template mode="getr1" match="summary" > <xsl:param name="index"/> <xsl:value-of select="r1[$index][@value]"/> </xsl:template> <xsl:template match="/"> <html> <body> <ul> <xsl:for-each select="root/s1"> <xsl:variable name="i" select="position()"/> <li> <xsl:value-of select ="@name"/> : <!--<xsl:apply-templates mode="getr1" select="/root/summary"> <xsl:with-param name="index" select="$i" /> </xsl:apply-templates>--> <!--I want to get the corresponding r1's value according to the index --> <!-- but above code is not work.--> </li> </xsl:for-each> </ul> </body> </html> </xsl:template> </xsl:stylesheet>

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  • Producing a static HTML site from XML content

    - by Skilldrick
    I have a long document in XML from which I need to produce static HTML pages (for distribution via CD). I know (to varying degrees) JavaScript, PHP and Python. The current options I've considered are listed here: I'm not ruling out JavaScript, so one option would be to use ajax to dynamically load the XML content into HTML pages. Learn some basic XSLT and produce HTML to the correct spec this way. Produce the site with PHP (for example) and then generate a static site. Write a script (in Python for example) to convert the XML into HTML. This is similar to the XSLT option but without having to learn XSLT. Useful information: The XML will likely change at some point, so I'd like to be able to easily regenerate the site. I'll have to produce some kind of menu for jumping around the document (so I'll need to produce some kind of index of the content). I'd like to know if anyone has any better ideas that I haven't thought of. If not, I'd like you to tell me which of my options seems the most sensible. I think I know what I'm going to do, but I'd like a second opinion. Thanks.

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  • xsl:template match doesn't find matches

    - by dmo
    I'm trying to convert some Xaml to HTML using the .NET XslCompiledTransform and am running into difficulties getting the xslt to match Xaml tags. For instance with this Xaml input: <FlowDocument PagePadding="5,0,5,0" AllowDrop="True" NumberSubstitution.CultureSource="User" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"> <Paragraph>a</Paragraph> </FlowDocument> And this xslt: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:apply-templates /> </body> </html> </xsl:template> <xsl:template match="FlowDocument"> <xsl:apply-templates /> </xsl:template> <xsl:template match="Paragraph" > <p> <xsl:apply-templates /> </p> </xsl:template> I get this output: <html> <body> a </body> </html> Rather than the expected: <html> <body> <p>a</p> </body> </html> Could this be a problem with the namespace? This is my first attempt at an xsl transform, so I'm at a loss.

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  • Please help me understand why my XSL Transform is not transforming

    - by Damovisa
    I'm trying to transform one XML format to another using XSL. Try as I might, I can't seem to get a result. I've hacked away at this for a while now and I've had no success. I'm not even getting any exceptions. I'm going to post the entire code and hopefully someone can help me work out what I've done wrong. I'm aware there are likely to be problems in the xsl I have in terms of selects and matches, but I'm not fussed about that at the moment. The output I'm getting is the input XML without any XML tags. The transformation is simply not occurring. Here's my XML Document: <?xml version="1.0"?> <Transactions> <Account> <PersonalAccount> <AccountNumber>066645621</AccountNumber> <AccountName>A Smith</AccountName> <CurrentBalance>-200125.96</CurrentBalance> <AvailableBalance>0</AvailableBalance> <AccountType>LOAN</AccountType> </PersonalAccount> </Account> <StartDate>2010-03-01T00:00:00</StartDate> <EndDate>2010-03-23T00:00:00</EndDate> <Items> <Transaction> <ErrorNumber>-1</ErrorNumber> <Amount>12000</Amount> <Reference>Transaction 1</Reference> <CreatedDate>0001-01-01T00:00:00</CreatedDate> <EffectiveDate>2010-03-15T00:00:00</EffectiveDate> <IsCredit>true</IsCredit> <Balance>-324000</Balance> </Transaction> <Transaction> <ErrorNumber>-1</ErrorNumber> <Amount>11000</Amount> <Reference>Transaction 2</Reference> <CreatedDate>0001-01-01T00:00:00</CreatedDate> <EffectiveDate>2010-03-14T00:00:00</EffectiveDate> <IsCredit>true</IsCredit> <Balance>-324000</Balance> </Transaction> </Items> </Transactions> Here's my XSLT: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" /> <xsl:param name="currentdate"></xsl:param> <xsl:template match="Transactions"> <xsl:element name="OFX"> <xsl:element name="SIGNONMSGSRSV1"> <xsl:element name="SONRS"> <xsl:element name="STATUS"> <xsl:element name="CODE">0</xsl:element> <xsl:element name="SEVERITY">INFO</xsl:element> </xsl:element> <xsl:element name="DTSERVER"><xsl:value-of select="$currentdate" /></xsl:element> <xsl:element name="LANGUAGE">ENG</xsl:element> </xsl:element> </xsl:element> <xsl:element name="BANKMSGSRSV1"> <xsl:element name="STMTTRNRS"> <xsl:element name="TRNUID">1</xsl:element> <xsl:element name="STATUS"> <xsl:element name="CODE">0</xsl:element> <xsl:element name="SEVERITY">INFO</xsl:element> </xsl:element> <xsl:element name="STMTRS"> <xsl:element name="CURDEF">AUD</xsl:element> <xsl:element name="BANKACCTFROM"> <xsl:element name="BANKID">RAMS</xsl:element> <xsl:element name="ACCTID"><xsl:value-of select="Account/PersonalAccount/AccountNumber" /></xsl:element> <xsl:element name="ACCTTYPE"><xsl:value-of select="Account/PersonalAccount/AccountType" /></xsl:element> </xsl:element> <xsl:element name="BANKTRANLIST"> <xsl:element name="DTSTART"><xsl:value-of select="StartDate" /></xsl:element> <xsl:element name="DTEND"><xsl:value-of select="EndDate" /></xsl:element> <xsl:for-each select="Items/Transaction"> <xsl:element name="STMTTRN"> <xsl:element name="TRNTYPE"><xsl:choose><xsl:when test="IsCredit">CREDIT</xsl:when><xsl:otherwise>DEBIT</xsl:otherwise></xsl:choose></xsl:element> <xsl:element name="DTPOSTED"><xsl:value-of select="EffectiveDate" /></xsl:element> <xsl:element name="DTUSER"><xsl:value-of select="CreatedDate" /></xsl:element> <xsl:element name="TRNAMT"><xsl:value-of select="Amount" /></xsl:element> <xsl:element name="FITID" /> <xsl:element name="NAME"><xsl:value-of select="Reference" /></xsl:element> <xsl:element name="MEMO"><xsl:value-of select="Reference" /></xsl:element> </xsl:element> </xsl:for-each> </xsl:element> <xsl:element name="LEDGERBAL"> <xsl:element name="BALAMT"><xsl:value-of select="Account/PersonalAccount/CurrentBalance" /></xsl:element> <xsl:element name="DTASOF"><xsl:value-of select="EndDate" /></xsl:element> </xsl:element> </xsl:element> </xsl:element> </xsl:element> </xsl:element> </xsl:template> </xsl:stylesheet> Here's my method to transform my XML: public string TransformToXml(XmlElement xmlElement, Dictionary<string, object> parameters) { string strReturn = ""; // Load the XSLT Document XslCompiledTransform xslt = new XslCompiledTransform(); xslt.Load(xsltFileName); // arguments XsltArgumentList args = new XsltArgumentList(); if (parameters != null && parameters.Count > 0) { foreach (string key in parameters.Keys) { args.AddParam(key, "", parameters[key]); } } //Create a memory stream to write to Stream objStream = new MemoryStream(); // Apply the transform xslt.Transform(xmlElement, args, objStream); objStream.Seek(0, SeekOrigin.Begin); // Read the contents of the stream StreamReader objSR = new StreamReader(objStream); strReturn = objSR.ReadToEnd(); return strReturn; } The contents of strReturn is an XML tag (<?xml version="1.0" encoding="utf-8"?>) followed by a raw dump of the contents of the original XML document, stripped of XML tags. What am I doing wrong here?

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  • Fix for php 5.3.9 libxsl security "bug" fix

    - by Question Mark
    just this morning i updated my debian server to php 5.3.9 , change log (last item in list) has a fix for this bug and now when running any hosted site using XSL transforms i get: Warning: XSLTProcessor::transformToXml(): Can't set libxslt security properties, not doing transformation for security reasons I'm not using any <sax:output> tags in my xslt at all. Does anybody have any information on this, current chatter about it is thin, so i'm i little lost. Using the suggestion about switching ini settings on and off either side of -transformToXml(): ini_set("xsl.security_prefs", XSL_SECPREFS_NONE) or $xsl->setSecurityPreferences(XSL_SECPREFS_NONE) brings me back to the same error Many thanks. Progress: - Upgrading libxml and recompiling libxslt against the new version was a good suggestion, though has not fixed the issue. - Compiling the latest php5.3 snapshot does not fix the issue. Solution: I'm unsure what actually solved this, very sorry for anyone else having the same problem. firstly i upgraded libxml, then applied a few patches, then went into php source for the xsl parser and added some debugging and a few tweaks, after a few compiles getting the configure args right the error went away and wasn't reproducible. I would definitely recommend upgrading libxml as Petr suggested below and then grabbing the latest snapshot from php.net.

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  • screen scraper templates for various websites

    - by intuited
    I'm looking specifically for a convenient way to locally archive posts from this and other similar sites. I'd like to separate the question itself from the answers, or maybe crop the question and store it, keeping the page title. Obviously I don't need to store the menu or the various other site interface chrome. The best way to do this would seem to be to associate an XSLT template with a match on the URL and use that template to pull the various relevant informations and format them. My two-part question: Is there a tool specifically built for this task? I.E. something that takes a URL and checks it against a map of path-matching expressions to templates, and outputs the result of applying the template to that resource? xmlto seems to be most of the way there, and could probably just be called from a script that does the pattern-matching, but something already integrated would be more convenient. Is such a URL_pattern-to-XSLT_template map publicly available somewhere? Question 2.5: Is it legal to do this with sites like this one that have public licenses on their content?

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  • Short hand for number of tags having lengthier [and almost same] Xpath

    - by infant programmer
    For example : this is an xslt <xsl:template match="/root/sub-root/parent/child/grand_child/dummy1/dummy2/dummy3/dummy4/node_1 |/root/sub-root/parent/child/grand_child/dummy1/dummy2/dummy3/dummy4/node_2 |/root/sub-root/parent/child/grand_child/dummy1/dummy2/dummy3/dummy4/node_3 . . |/root/sub-root/parent/child/grand_child/dummy1/dummy2/dummy3/dummy4/node_N"/> In the above code can I use the XPath /root/sub-root/parent/child/grand_child/dummy1/dummy2/dummy3/dummy4 only once [use the braces or whatever] and reduce the bulkiness of the code? As you can see, all the nodes are siblings of each-other, so except their name their Xpath is same. Is there any short-hand property ? Does XSLT 1.0 (or Xpath1.0) allows it?

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  • How to get a non-XML output using JDOM XSLTransformer?

    - by Neil McF
    Hello, I have an XML file which I'd like to parse into a non-XML (text) file based on a XLST file. The code in both seem correct, and it works when testing manually, but I'm having a problem doing this programatically. I'm using JDOM's XSLTransformer class to apply the XSLT to the XML and it returns it in the format of a JDOM Document. The problem here is that I can't seem to access anything in the Document as it is not a proper XML file and I get a "java.lang.IllegalStateException: Root element not set" error. Is there a better way within Java to obtain a non-XML file as a result of XSLT?

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  • fastest in-memory cache for XslCompiledTransform

    - by rudnev
    I have a set of xslt stylesheet files. I need to produce the fastest performance of XslConpiledTransform, so i want to make in-memory representation of these stylesheets. I can load them to in-memory collection as IXpathNavigable on application start, and then load each IXPAthNavigable into singleton XslCompiledTransform on each request. But this works only for styleshhets without xsl:import or xsl:include. (Xsl:import is only for files). also i can load into cache many instances of XSLCompiledTransform for each template. Is it reasonable? Are there other ways? What is the best? what are another tips for improving performance MS Xslt processor?

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