Search Results

Search found 31657 results on 1267 pages for 'php 5 3'.

Page 173/1267 | < Previous Page | 169 170 171 172 173 174 175 176 177 178 179 180  | Next Page >

• PHP Exceptions in Classes

  - by mike condiff

  I'm writing a web application (PHP) for my friend and have decided to use my limited OOP training from Java. My question is what is the best way to note in my class/application that specific critical things failed without actually breaking my page. Currently my problem is I have an Object "SummerCamper" which takes a camper_id as it's argument to load all of the necessary data into the object from the database. Say someone specifies a camper_id in the querystring that does not exist, I pass it to my objects constructor and the load fails. Currently I don't see a way for me to just return false from the constructor. I have read I could possibly do this with Exceptions, throwing an exception if no records are found in the database or if some sort of validation fails on input of the camper_id from the application etc. However, I have not really found a great way to alert my program that the Object Load has failed. I tried returning false from within the CATCH but the Object still persists in my php page. I do understand I could put a variable $is_valid = false if the load fails and then check the Object using a get method but I think there may be better ways. What is the best way of achieving the essential termination of an object if a load fails? Should I load data into the object from outside the constructor? Is there some osrt of design pattern that I should look into? Any help would be appreciated.

  Read the article

• php error reporting - having trouble matching local & web server settings

  - by Andrew Heath

  I'm trying to add a custom error handler to my site, but in doing so have discovered that my webhost's PHP error reporting settings and those of my localhost (default XAMPP) vary considerably. While I thought I was programming to E_STRICT like a good little boy, adding the error handler to my webhost revealed craploads of Runtime Notices. Example: Runtime notice strtotime() [function.strtotime]: It is not safe to rely on the system's timezone settings. Please use the date.timezone setting, the TZ environment variable or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'America/Chicago' for 'CST/-6.0/no DST' instead In /home/... Clearly this isn't a red-alert, showstopping error. But what bothers me is that it doesn't show up on my localhost. I'd certainly like to improve my code by addressing these sorts of issues if I could see them! I've looked through both php.ini files, and my webhost's setting is error_reporting = E_ALL & ~E_NOTICE whereas mine was error_reporting = E_STRICT, which I had thought was better. However, changing mine to match and rebooting the server doesn't seem to have accomplished anything. Could someone please point me in the right direction?

  Read the article

• problem with insert into mysql DB using PHP

  - by user504363

  Hi all I have strange problem that I have a PHP page used to insert data into Mysql DB. the problem is that when I execute the code, nothing added to db and no errors is appeared although I set display errors codes error_reporting(E_ALL); ini_set('display_errors', TRUE); ini_set('display_startup_errors', TRUE); any idea about this problem ! here is my used code for inserting function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { if (PHP_VERSION < 6) { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; } $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? doubleval($theValue) : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } include("Connections/mzk_mdc.php"); $ext = 1; $website = "mzk"; $mzk_sql=sprintf("INSERT INTO downloads (image, `by`, `rapid_title`, title, `description`, category, div_id, topic_url, down_times, ext, `website`) VALUES (%s, %s, %s, %s, %s, %s, %s, %s, %s, %s, %s)", GetSQLValueString($topic_thumb_image, "text"), GetSQLValueString($topic_by, "text"), GetSQLValueString($topic_des, "text"), GetSQLValueString($topic_title, "text"), GetSQLValueString($forum_content, "text"), GetSQLValueString($topic_category, "text"),GetSQLValueString($topic_div, "text"),GetSQLValueString($forum_link, "text") ,GetSQLValueString($topic_down_times, "int"),GetSQLValueString($ext, "int"), GetSQLValueString($website, "text")); mysql_select_db($database_mdc, $mdc); $mzk_result = mysql_query($mzk_sql, $mdc) or die("can not do more"); mysql_close($mdc);

  Read the article

• PHP post request to retrieve JSON

  - by Brian

  I'm trying to write some simple php code that will make a post request and then retrieve a JSON result from the server. It seemed simple to me, but the below code simply doesn't open a connection. $port = 2057; $path = "/validate/"; $request = "value1=somevalue&value2=somevalue&value3=somevalue"; $http_request = "POST $path HTTP/1.0\r\n"; $http_request .= "Host: $server\r\n"; $http_request .= "Content-Type: application/x-www-form-urlencoded;\r\n"; $http_request .= "Content-Length: " . strlen($request) . "\r\n"; $http_request .= "\r\n"; $http_request .= $request; $response = ''; if( false == ( $fs = @fsockopen($server, $port) ) ) { die ('Could not open socket'); } fwrite($fs, $http_request); while ( !feof($fs) ) { $response .= fgets($fs, 1160); } fclose($fs); In addition I've tried a more simple approach with: $handle = fopen('http://localhost:2057/validate/?'.$request, "r"); or $response = file_get_contents('http://localhost:2057/validate/' . $request); but both of these approaches just time out. I'm trying to connect to a development server I'm running in Visual Studio, so I'm not sure if that has anything to do with the timeout/connection issues. Open to any suggestions here as long as they are built in PHP.

  Read the article

• PHP Ampersand in String

  - by John

  Hello. I'm having a bit of a problem. I am trying to create an IRC bot, which has an ampersand in its password. However, I'm having trouble putting the ampersand in a string. For example... <?php $var = "g&abc123"; echo $var; ?> I believe this should print g&abc123. However it's printing g. I have tried this as well: <?php $arr = array("key" => "g&abc123"); print_r($arr); ?> This prints it correctly with the g&abc123, however when I say echo $arr['key']; it prints g again. Any help would be appreciated. I'm running PHP5.3.1. EDIT: Also, I just noticed that if I use g&abc123&abc123 it prints g&abc123. Any suggestions?

  Read the article

• searching for multiple columns mysql and php

  - by addi

  i'm trying to search for multiple columns using this code: <?php // Connection Database $search = $_POST ['Search']; mysql_connect("xxxxxx", "xxxxxx", "xxxxx") or die ("Error Connecting to Database"); mysql_select_db("xxxxx") or die('Error'); $data = mysql_query("SELECT CourseName, CourseDescription, CourseLeader FROM course MATCH (CourseName, CourseDescription, CourseLeader) AGAINST ('". $search ."') or die('Error'); Print "<table border cellpadding=3>"; while($info = mysql_fetch_array( $data )) { Print "<tr>"; Print "<th>Course Name:</th> <td>".$info['CourseName'] . "</td> "; Print "<th>Course Description:</th><td>".$info['CourseDescription'] . "</td> "; Print "<th>Course Leader:</th><td>".$info['CourseLeader'] . " </td></tr>"; } Print "</table>"; ?> i'm getting the following error: Parse error: syntax error, unexpected T_STRING in /home/a7105766/public_html/website/scripts/coursesearchdb.php on line 30 what am I doing wrong?? cheers

  Read the article

• Using $this when not in object context--i am using the latest version of php and mysql

  - by user309381

  This is user.php: include("databse.php");//retrieving successfully first name and lastname from databse file into user.php class user { public $first_name; public $last_name; public static function full_name() { if(isset($this->first_name) && isset($this->last_name)) { return $this->first_name . " " . $this->last_name; } else { return ""; } } } ?> Other php file, index.php: <?php include(databse.php); include(user.php); $record = user::find_by_id(1); $object = new user(); $object->id = $record['id']; $object->username = $record['username']; $object->password = $record['password']; $object->first_name = $record['first_name']; $object->last_name = $record['last_name']; // echo $object->full_name(); echo $object->id;// successfully print the id echo $object->username;//success fully print the username echo->$object->full_name();//**ERROR:Using $this when not in object context** ?>

  Read the article

• File streaming in PHP - How to replicate this C#.net code in PHP?

  - by openid_kenja

  I'm writing an interface to a web service where we need to upload configuration files. The documentation only provides a sample in C#.net which I am not familiar with. I'm trying to implement this in PHP. Can someone familiar with both languages point me in the right direction? I can figure out all the basics, but I'm trying to figure out suitable PHP replacements for the FileStream, ReadBytes, and UploadDataFile functions. I believe that the RecService object contains the URL for the web service. Thanks for your help! private void UploadFiles() { clientAlias = “<yourClientAlias>”; string filePath = “<pathToYourDataFiles>”; string[] fileList = {"Config.txt", "ProductDetails.txt", "BrandNames.txt", "CategoryNames.txt", "ProductsSoldOut.txt", "Sales.txt"}; RecommendClient RecService = new RecommendClient(); for (int i = 0; i < fileList.Length; i++) { bool lastFile = (i == fileList.Length - 1); //start generator after last file try { string fileName = filePath + fileList[i]; if (!File.Exists(fileName)) continue; // file not found } // set up a file stream and binary reader for the selected file and convert to byte array FileStream fStream = new FileStream(fileName, FileMode.Open, FileAccess.Read); BinaryReader br = new BinaryReader(fStream); byte[] data = br.ReadBytes((int)numBytes); br.Close(); // pass byte array to the web service string result = RecService.UploadDataFile(clientAlias, fileList[i], data, lastFile); fStream.Close(); fStream.Dispose(); } catch (Exception ex) { // log an error message } } }

  Read the article

• Access values of a group of select boxes in php from post

  - by 2Real

  Hi, I'm new to PHP, and I can't figure this out. I'm trying to figure out how to access the data of a group of select boxes I have defined in my HTML code. I tried grouping them as a class, but that doesn't seem to work... maybe I was doing it wrong. This is the following HTML code. <form action="" method="post"> <select class="foo"> <option> 1.....100</option> </select> <select class="foo"> <option> 1.... 500></option> </select> <input type="submit" value="Submit" name="submit"/> </form> I essentially want to group all my select boxes and access all the values in my PHP code. Thanks

  Read the article

• PHP/Javascript: Need help removing line break from code

  - by Josh K

  I am trying to get names from a .txt file. I am using file('filename.txt') but if i use a php for loop to try and trim the names, it comes out on multiple lines: This is the actual line that prints the javascript (NOTE: I am going to be putting these names into a select box, if you can fix the problem at hand the rest of the code should work so unless you a big problem with it you don't need to comment) <?php for($i=1; $i < 27; $i++){ echo "selbox.options[selbox.options.length] = new Option('".lines[$i]."','".$lines[$i]."');\n"; } ?> Heres how it comes out on the browser: selbox.options[selbox.options.length] = new Option('Djamal ABDOUN ','First1 Last1 '); selbox.options[selbox.options.length] = new Option('Chadli AMRI ','First2 Last2 '); I need those to be on one line so i dont get a unterminated string literal js error Any ideas on what i can do here? EDIT: Oh i should probably mention, the $lines var is initiated like this: $lines = file('filename.txt'); and inside that file i have formatted like this First1 Last1 First2 Last2 First3 Last3 etc. and i hit delete after each Last name until the next first name is touching, then hit enter to put it on a new line (Editor is notepad++)

  Read the article

• php Warning: strtotime() Error

  - by Kavithanbabu

  I have changed my joomla and wordpress files from old server to new server. In the front end and admin side its working without any errors. But in the Database (phpmyadmin) Section it shows some warning messages like this.. Warning: strtotime() [function.strtotime]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'Asia/Calcutta' for 'IST/5.0/no DST' instead in /usr/share/phpmyadmin/libraries/db_info.inc.php on line 88 Warning: strftime() [function.strftime]: It is not safe to rely on the system's timezone settings. You are *required* to use the date.timezone setting or the date_default_timezone_set() function. In case you used any of those methods and you are still getting this warning, you most likely misspelled the timezone identifier. We selected 'Asia/Calcutta' for 'IST/5.0/no DST' instead in /usr/share/phpmyadmin/libraries/common.lib.php on line 1483 Can you please suggest, how to hide these warning messages?? Thanks in advance.

  Read the article

• Adding an Array inside an array in a PHP function

  - by bateman_ap

  I have created a function in PHP that calls a webservice and parses through the result, assinging values to variables and returning them all as an Array. This all works perfectly, however I have come across a need to have an "array within my array" I am assigning values as below: $productName = $product->Name; $productID = $product->ID; $productArray = array( 'productName' => "$productName", 'productID' => "$productID" ); return $productArray; However I now have a piece of data that comes back with multiple results so I need to have a additional array to store these, I am getting the values from the returned XML using a foreach loop, however I want to be able to add them to the array with a name so I can reference them in the returned data, this is where I have a problem... $bestForLists = $product->BestFors; foreach( $bestForLists as $bestForList ) { $productBestFors = $bestForList->BestFor; foreach( $productBestFors as $productBestFor ) { $productBestForName = $productBestFor->Name; $productBestForID = $productBestFor->ID; } } I tried creating an array for these using the below code: $bestForArray[] = (array( "productBestForID" => "$productBestForID", "productBestForName" => "$productBestForName" )); And then at the end merging these together: $productArray= array_merge($productArray,$bestForArray); If I print out the returned value I get: Array ( [productName] => Test Product [productID] => 14128 [0] => Array ( [productBestForID] => 56647 [productBestForName] => Lighting ) [1] => Array ( [productBestForID] => 56648 [productBestForName] => Sound ) ) I would like to give the internal Array a name so I can reference it in my code, or is there a better way of doing this, at the moment I am using the following in my PHP page to get values: $productName = $functionReturnedValues['productName']; I would like to use the following to access the array I could then loop through: $bestForArray = $functionReturnedValues['bestForArray']; Hope someone can help

  Read the article

• JSON parse data in javascript from php

  - by Stefania

  I'm trying to retrieve data in a javascript file from a php file using json. $items = array(); while($r = mysql_fetch_array($result)) { $rows = array( "id_locale" => $r['id_locale'], "latitudine" => $r['lat'], "longitudine" => $r['lng'] ); array_push($items, array("item" => $rows)); } ECHO json_encode($items); and in the javascript file I try to recover the data using an ajax call: $.ajax({ type:"POST", url:"Locali.php", success:function(data){ alert("1"); //var obj = jQuery.parseJSON(idata); var json = JSON.parse(data); alert("2"); for (var i=0; i<json.length; i++) { point = new google.maps.LatLng(json[i].item.latitudine,json[i].item.longitudine); alert(point); } } }) The first alert is printed, the latter does not, it gives me error: Unexpected token <.... but I do not understand what it is. Anyone have any idea where am I wrong? I also tried to recover the data with jquery but with no positive results.

  Read the article

• php oop and mysql

  - by gloris

  I need to get data, to check and send to db. Programming with PHP OOP. Could you tell me if my class structure is good and how dislpay all data?. Thanks <?php class Database{ private $DBhost = 'localhost'; private $DBuser = 'root'; private $DBpass = 'root'; private $DBname = 'blog'; public function connect(){ //Connect to mysql db } public function select($rows){ //select data from db } public function insert($rows){ //Insert data to db } public function delete($rows){ //Delete data from db } } class CheckData{ public $number1; public $number2; public function __construct(){ $this->number1 = $_POST['number1']; $this->number2 = $_POST['number2']; } function ISempty(){ if(!empty($this->$number1)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number1); } else{ echo "Empty1"; } if(!empty($this->$number2)){ echo "Not Empty"; $data = new Database(); $data->insert($this->$number2); } else{ echo "Empty2"; } } } class DisplayData{ //How print all data? function DisplayNumber(){ $data = new Database(); $data->select(); } } $check = new CheckData(); $check->ISempty(); $display = new DisplayData() $display->DisplayNumber(); ?>

  Read the article

• PHP date returning wrong time

  - by gargantaun

  The following script is returning the wrong time after I call date_default_timezone_set("UTC") <?PHP $timestamp = time(); echo "<p>Timestamp: $timestamp</p>"; // This returns the correct time echo "<p>". date("Y-m-d H:i:s", $timestamp) ."</p>"; echo "<p>Now I call 'date_default_timezone_set(\"UTC\")' and echo out the same timestamp.</p>"; echo "Set timezone = " . date_default_timezone_set("UTC"); // This returns a time 5 hours in the past echo "<p>". date("Y-m-d H:i:s", $timestamp) ."</p>"; ?> The timezone on the server is BST. So what should happen is that the second call to 'date' should return a time 1 hour behind the first call. It's actually returning a time 5 hours behind the first one. I should note that the server was originally set up with the EDT timezone (UTC -4). That was changed to BST (UTC +1) and the server was restarted. I can't figure out if this is a PHP problem or a problem with the server.

  Read the article

• I need an IDE for typo3 core development in php

  - by Flugan

  Php in itself is difficult for IDEs because of the dynamic nature of the language. My current development environment is mostly netbeans against a local svn copy of the codebase setup in a local development webserver. The code is full text indexed by vistas search engine for almost instant searches. I do a lot of development directly against the main development server using a combination of tools. Putty to interact with the server and deploy by updating an svn checkout on the development server. Tortoise SVN locally to have a fairly rich SVN experience. Netbeans obviously have SVN integration. Most of the changes on the remote server is commited using the putty session. WinSCP to interact with the development server with norton commander like interface as well as the good putty integration. Finally my text editor for remote editing is notepad++ out of habit and because of some nice features and good price. What I'm really missing is good php editing. Because of the way typo3 works almost all objects are instanciated through make instance abstraction that either returns the base class or the customized class if the framework has been extended. I'm not looking for a magic editing package and would like to find an editor which can use annotations to specify the type of commonly used variables.

  Read the article

• php cURL. preg_match , extract text from xhtml

  - by Michael

  I'm trying to extract the price from the bellow html page/link using php cURL and preg_match . Basically I'm expecting for this code to output 4,550 but for some reasons I get Notice: Undefined offset: 1 in C:\wamp\www\test.php on line 22 I think that the pattern is correct because if I put the html itself in a variable and escape the "" it works ! . Also if I output (echo $result;) it displays the html properly grabbed from foxtons website so I just can't figure it out why the whole thing doesn't work . I need to make this work and also I would appreciate if you would tell me why is that notice generated and why my current script doesn't work. $url = "http://www.foxtons.co.uk/search?bedrooms_from=0&property_id=727717"; $ch = curl_init($url); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch,CURLOPT_RETURNTRANSFER, 1); $result = curl_exec($ch); curl_exec($ch); curl_close($ch); $result2 = str_replace('"', '\"', $result); $tagname1= ");<\/script "; $tagname2= "<\/noscript per month<\/a"; $pattern = "/$tagname1(.*?)$tagname2/"; preg_match($pattern, $result, $matches); $prices = $matches[1]; print_r($prices); ?

  Read the article

• How to inject php code from database into php script ?

  - by luxquarta

  I want to store php code inside my database and then use it into my script. class A { public function getName() { return "lux"; } } // instantiates a new A $a = new A(); Inside my database there is data like "hello {$a->getName()}, how are you ?" In my php code I load the data into a variable $string $string = load_data_from_db(); echo $string; // echoes hello {$a->getName()}, how are you ? So now $string contains "hello {$a-getName()}, how are you ?" {$a-getName()} still being un-interpretated Question: I can't find how to write the rest of the code so that {$a-getName()} gets interpretated "into hello lux, how are you". Can someone help ? $new_string = ?????? echo $new_string; //echoes hello lux, how are you ? Is there a solution with eval() ? (please no debate about evil eval ;)) Or any other solution ?

  Read the article

• Get Mail with PHP and IMAP in Gmail just loading

  - by Oscar Godson

  I'm not sure why. Ive tried a bunch of different code. Wrote it myself, and copied other people's tutorials but every bit of code it's loading forever and eventually stops due to script processing times on the server. Does anyone know why? Oh, and IMAP is turned on, i get IMAP / Exchange on my iPhone from this same account fine. And IMAP is turned on in my version of PHP (checked with phpinfo they all say enabled.) <?php /* connect to gmail */ $hostname = '{imap.gmail.com:993/imap/ssl}INBOX'; $username = '[email protected]'; $password = 'xxxxxx'; /* try to connect */ $inbox = imap_open($hostname,$username,$password) or die('Cannot connect to Gmail: ' . imap_last_error()); /* grab emails */ $emails = imap_search($inbox,'ALL'); /* if emails are returned, cycle through each... */ if($emails) { /* begin output var */ $output = ''; /* put the newest emails on top */ rsort($emails); /* for every email... */ foreach($emails as $email_number) { /* get information specific to this email */ $overview = imap_fetch_overview($inbox,$email_number,0); $message = imap_fetchbody($inbox,$email_number,2); /* output the email header information */ $output.= '<div class="toggler '.($overview[0]->seen ? 'read' : 'unread').'">'; $output.= '<span class="subject">'.$overview[0]->subject.'</span> '; $output.= '<span class="from">'.$overview[0]->from.'</span>'; $output.= '<span class="date">on '.$overview[0]->date.'</span>'; $output.= '</div>'; /* output the email body */ $output.= '<div class="body">'.$message.'</div>'; } echo $output; } /* close the connection */ imap_close($inbox); ?

  Read the article

• Possible to Dynamic Form Generation Using PHP global variables

  - by J M 4

  I am currently a fairly new programmer but am trying to build a registration page for a medical insurance idea we have which captures individual information and subsequent pieces of information about that individual's sub parts. In this case, it is a fight promoter enrolling his 15+ boxers for fight testing services. Right now, I have the site fully laid out to accept 7 fighters worth of information. This is collected during the manager's enrollment. However, each fighter's information is passed and stored in session super globals such as: $_SESSION['F1Firstname']; and $_SESSION['F3SSN3'];. The issue I am running into is this, I want to create a drop down menu selector for the manager to add information for up to 20-30 fighters. Right now I use PHP to state: if ($_SESSION['Num_Fighters'] 6) ... then display the table form fields to collect consumer data. If I have to build hidden elements for 30 fighters AND provide javascript/php validation (yes I am doing both) then I fear the file size for the document will be unnecessarily large for the maanger who only wants to enroll 2 fighters. Can anybody help?

  Read the article

• php while selecting a node should be highlighted.

  - by shaibi

  I need to highlight the node value when I select it.how can I wrirte code for that in php my code is function generate_menu($parent) { $has_childs = false; global $menu_array; foreach($menu_array as $key = $value) { //print_r($value); if ($value['parentid'] == $parent) { if ($has_childs === false) { $has_childs = true; $menu .= '<ul>'; } $clor = 'black'; if(($_GET['id']>0) &&($key == $_GET['id'])) { $clor = '#990000'; } $chld = generate_menu($key); $cls = ($chld != '')? 'folder' : 'file'; $menu .= '<li><span class="'.$cls.'" color='.$clor.'>&nbsp;' . $value['humanid'].'-'.$value['title'] . ' <a href="index.php?id='.$key.'"><img src="images/edit.png" alt=" Edit" title="Edit"/></a></span>'; $menu .= $chld; $menu .= '</li>'; } } if ($has_childs === true) $menu .= '</ul>'; return $menu ; } ?

  Read the article

• PHP and MySQL echoing out a Table

  - by user1631702

  Okay, so I've done this before, and it worked. I am trying to echo out specific rows on my database in a table. Here is my code: <?php $connect = mysql_connect("localhost", "xxx", "xxx") or die ("Hey loser, check your server connection."); mysql_select_db("xxx"); $quey1="select * from `Ad Requests`"; $result=mysql_query($quey1) or die(mysql_error()); ?> <table border=1 style="background-color:#F0F8FF;" > <caption><EM>Student Record</EM></caption> <tr> <th>Student ID</th> <th>Student Name</th> <th>Class</th> </tr> <?php while($row=mysql_fetch_array($result)){ echo "</td><td>"; echo $row['id']; echo "</td><td>"; echo $row['twitter']; echo "</td><td>"; echo $row['why']; echo "</td></tr>"; } echo "</table>"; ?> It gives me no errors, but It just shows a blank table with none of these rows. My Question: How come this wont show any rows in the table, what am I doing wrong?

  Read the article

• PHP DELETE immediately after select

  - by teehoo

  I have a PHP server script that SELECTs some data from a MySQL database. As soon as I have the result from mysql_query and mysql_fetch_assoc stored in my own local variables, I want to delete the row I just selected. The problem with this approach is that it seems that PHP has done pass-by-reference to my local variables instead of pass-by-value, and my local variables become undefined after the delete command. Is there anyway to get around this? Here is my code: $query="SELECT id, peerID, name FROM names WHERE peer = $userID AND docID = '$docID' AND seqNo = $nid"; $result = mysql_query($query); if (!$result) self::logError("FAIL:1 getUsersNamesUpdate() query: ".$query."\n"); if (mysql_num_rows($result) == 0) return array(); $row = mysql_fetch_assoc($result); $result = array(); $result["id"] = $row["id"]; $result["peerID"] = $row["peerID"]; $result["name"] = $row["name"]; $query="DELETE FROM names WHERE id = $result[id];"; $result = mysql_query($query); if (!$result) self::logError("FAIL:2 getUsersNamesUpdate() query: ".$query."\n"); return $result;

  Read the article

• PHP - uninitialized array offset

  - by kimmothy16

  Hey everyone, I am using PHP to create a form with an array of fields. Basically you can add an unlimited number of 'people' to the form and each person has a first name, last name, and phone number. The form requires that you add a phone number for the first person only. If you leave the phone number field blank on any others, the handler file is supposed to be programmed to use the phone number from the first person. So, my fields are: person[] - a hidden field with a value that is this person's primary key. fname[] - an input field lname[] - an input field phone[] - an input field my form handler looks like this: $people = $_POST['person'] $counter = 0; foreach($people as $person): if(phone[$counter] == '') { // use $phone[0]'s phone number } else { // use $phone[$counter] number } $counter = $counter + 1; endforeach; PHP doesn't like this though, it is throwing me an Notice: Uninitialized string offset error. I debugged it by running the is_array function on people, fname, lname, and phone and it returns true to being an array. I can also manually echo out $phone[2], etc. and get the correct value. I've also ran is_int on the $counter variable and it returned true, so I'm unsure why this isn't working as intended? Any help would be great!

  Read the article

• php - create columns from mysql list

  - by user271619

  I have a long list generated from a simple mysql select query. Currently (shown in the code below) I am simply creating list of table rows with each record. So, nothing complicated. However, I want to divide it into more than one column, depending on the number of returned results. I've been wrapping my brain around how to count this in the php, and I'm not getting the results I need. <table> <? $query = mysql_query("SELECT * FROM `sometable`"); while($rows = mysql_fetch_array($query)){ ?> <tr> <td><?php echo $rows['someRecord']; ?></td> </tr> <? } ?> </table> Obviously there's one column generated. So if the records returned reach 10, then I want to create a new column. In other words, if the returned results are 12, I have 2 columns. If I have 22 results, I'll have 3 columns, and so on.

  Read the article

< Previous Page | 169 170 171 172 173 174 175 176 177 178 179 180  | Next Page >