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• ValueProvider.GetValue Extension Method

  - by griegs

  I have a model like this; public class QuickQuote { [Required] public Enumerations.AUSTRALIA_STATES state { get; set; } [Required] public Enumerations.FAMILY_TYPE familyType { get; set; } As you can see the two proerties are enumerations. Now I want to employ my own model binder for reasons that I won't bother getting into at the moment. So I have; public class QuickQuoteBinder : DefaultModelBinder { public object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext) { quickQuote = new QuickQuote(); try { quickQuote.state = (Enumerations.AUSTRALIA_STATES) Enum.Parse(typeof(Enumerations.AUSTRALIA_STATES), bindingContext.ValueProvider.GetValue(bindingContext.ModelName + ".state").AttemptedValue); } catch { ModelState modelState = new ModelState(); ModelError err = new ModelError("Required"); modelState.Errors.Add(err); bindingContext.ModelState.Add(bindingContext.ModelName + ".state", modelState); } The problem is that for each property, and there are heaps, I need to do the whole try catch block. What I thought I might do is create an extension method which would do the whole block for me and all i'd need to pass in is the model property and the enumeration. So I could do something like; quickQuote.state = bindingContext.ValueProvider.GetModelValue("state", ...) etc. Is this possible?

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• No flow definition found. Spring web flow

  - by user184794

  Hi, I am new to Spring webflow and now I am trying the example in Spring recipes book and I know this is a basic question. I am getting the error as follows, org.springframework.webflow.definition.registry.NoSuchFlowDefinitionException: No flow definition '${flowExecutionUrl}&_eventId=next' found at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinitionHolder(FlowDefinitionRegistryImpl.java:126) at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinition(FlowDefinitionRegistryImpl.java:61) at org.springframework.webflow.executor.FlowExecutorImpl.launchExecution(FlowExecutorImpl.java:138) at org.springframework.webflow.mvc.servlet.FlowHandlerAdapter.handle(FlowHandlerAdapter.java:193).... Shown below is my configurations, <bean name="flowController" class="org.springframework.webflow.mvc.servlet.FlowController"> <property name="flowExecutor" ref="flowExecutor"></property> </bean> <webflow:flow-executor id="flowExecutor" /> <webflow:flow-registry id="flowRegistry" > <webflow:flow-location path="/WEB-INF/flows/welcome/welcome.xml"></webflow:flow-location> </webflow:flow-registry> /WEB-INF/flows/welcome/welcome.xml, <view-state id="welcome"> <transition on="next" to="introduction" /> <transition on="skip" to="menu" /> </view-state> <view-state id="introduction"> <on-render> <evaluate expression="libraryService.getHolidays()" result="requestScope.holidays" /> </on-render> <transition on="next" to="menu" /> </view-state> <view-state id="menu"></view-state> In welcome.jsp, <a href="${flowExecutionUrl}&_eventId=next">Next</a> <a href="${flowExecutionUrl}&_eventId=skip">Skip</a> Please let me know what is going wrong. I am using 2.0.9 Release. Thanks in advance, SD

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• Using repaint() method.

  - by owca

  I'm still struggling to create this game : http://stackoverflow.com/questions/2844190/choosing-design-method-for-ladder-like-word-game .I've got it almost working but there is a problem though. When I'm inserting a word and it's correct, the whole window should reload, and JButtons containing letters should be repainted with different style. But somehow repaint() method for the game panel (in Main method) doesn't affect it at all. What am I doing wrong ? Here's my code: Main: import java.util.Scanner; import javax.swing.*; import java.awt.*; public class Main { public static void main(String[] args){ final JFrame f = new JFrame("Ladder Game"); Scanner sc = new Scanner(System.in); System.out.println("Creating game data..."); System.out.println("Height: "); //setting height of the grid while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); /* * I'm creating Grid[]game. Each row of game contains Grid of Element[]line. * Each row of line contains Elements, which are single letters in the game. */ Grid[]game = new Grid[height]; for(int L = 0; L < height; L++){ Grid row = null; int i = L+1; String s; do { System.out.println("Length "+i+", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()]; Element single = null; String[] temp = null; String[] temp2 = new String[s.length()]; temp = s.split(""); for( int j = temp2.length; j>0; j--){ temp2[j-1] = temp[j]; } for (int k = 0 ; k < temp2.length ; k++) { if( k == 0 ){ single = new Element(temp2[k], 2); } else{ single = new Element(temp2[k], 1); } line[k] = single; } row = new Grid(line); game[L] = row; } //############################################ //THE GAME STARTS HERE //############################################ //create new game panel with box layout JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.Y_AXIS)); panel.setBackground(Color.ORANGE); panel.setBorder(BorderFactory.createEmptyBorder(10, 10, 10, 10)); //for each row of the game array add panel containing letters Single panel //is drawn with Grid's paint() method and then returned here to be added for(int i = 0; i < game.length; i++){ panel.add(game[i].paint()); } f.setContentPane(panel); f.pack(); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); boolean end = false; boolean word = false; String text; /* * Game continues until solved() returns true. First check if given word matches the length, * and then the value of any row. If yes - change state of each letter from EMPTY * to OTHER_LETTER. Then repaint the window. */ while( !end ){ while( !word ){ text = JOptionPane.showInputDialog("Input word: "); for(int i = 1; i< game.length; i++){ if(game[i].equalLength(text)){ if(game[i].equalValue(text)){ game[i].changeState(3); f.repaint(); //simple debug - I'm checking if letter, and //state values for each Element are proper for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].letter()); } System.out.println(); for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].getState()); } System.out.println(); //set word to true and ask for another word word = true; } } } } word = false; //check if the game has ended for(int i = 0; i < game.length; i++){ if(game[i].solved()){ end = true; } else { end = false; } } } } } Element: import javax.swing.*; import java.awt.*; public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){ } //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public JButton paint(){ JButton button = null; if( state == EMPTY ){ button = new JButton(" "); button.setBackground(Color.WHITE); } else if ( state == FIRST_LETTER ){ button = new JButton(letter); button.setBackground(Color.red); } else { button = new JButton(letter); button.setBackground(Color.yellow); } return button; } public void changeState(int s){ state = s; } public void setLetter(String s){ letter = s; } public String letter(){ return letter; } public int getState(){ return state; } } Grid: import javax.swing.*; import java.awt.*; public class Grid extends JPanel{ public Element[]e; private Grid[]g; public Grid(){} public Grid( Element[]elements ){ e = new Element[elements.length]; for(int i=0; i< e.length; i++){ e[i] = elements[i]; } } public Grid(Grid[]grid){ g = new Grid[grid.length]; for(int i=0; i<g.length; i++){ g[i] = grid[i]; } Dimension d = new Dimension(600, 600); setMinimumSize(d); setPreferredSize(new Dimension(d)); setMaximumSize(d); } //for Each element in line - change state to i public void changeState(int i){ for(int j=0; j< e.length; j++){ e[j].changeState(3); } } //create panel which will be single row of the game. Add elements to the panel. // return JPanel to be added to grid. public JPanel paint(){ JPanel panel = new JPanel(); panel.setLayout(new GridLayout(1, e.length)); panel.setBorder(BorderFactory.createEmptyBorder(2, 2, 2, 2)); for(int j = 0; j < e.length; j++){ panel.add(e[j].paint()); } return panel; } //check if the length of given string is equal to length of row public boolean equalLength(String s){ int len = s.length(); boolean equal = false; for(int j = 0; j < e.length; j++){ if(e.length == len){ equal = true; } } return equal; } //check if the value of given string is equal to values of elements in row public boolean equalValue(String s){ int len = s.length(); boolean equal = false; String[] temp = null; String[] temp2 = new String[len]; temp = s.split(""); for( int j = len; j>0; j--){ temp2[j-1] = temp[j]; } for(int j = 0; j < e.length; j++){ if( e[j].letter().equals(temp2[j]) ){ equal = true; } else { equal = false; } } if(equal){ for(int i = 0; i < e.length; i++){ e[i].changeState(3); } } return equal; } //check if the game has finished public boolean solved(){ boolean solved = false; for(int j = 0; j < e.length; j++){ if(e[j].getState() == 3){ solved = true; } else { solved = false; } } return solved; } }

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• Static variables and long running thread on IIS 7.5

  - by Dmitry

  Hello people. Help me solve next problem. I have ASP .NET MVC2 application. I run it on IIS 7.5. In one page user clicks button and handler for this button sends request to server (jquery.ajax). At server action in controller starts new thread (it makes long time import): var thread = new Thread(RefreshCitiesInDatabase); thread.Start(); State of import is available in static variable. New thread changes value of variable in the begin of work. User can check state of import too with the help of this variable, which is used in view. And user sees import's state. When I start this function few minutes everything is okey. On page I see right state of import, quantity of imported records is changed, I see changes in logs. But after few minutes begin troubles. When I refresh page with import state sometimes I see that import is okey but sometimes I see page with default values about import (like application is just started), but after that again I can see page with normal import's state. I tried to attach Visual Studio to IIS process and debug application. But when request comes to controller sometimes static variables have right values and sometimes they have default values (static int has 0, static string has "" etc.). Tell me what I do wrong. May be I must start additional thread in other way? Thanks in advance, Dmitry

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• Flex AS3: ComboBox set visible to false doesn't hide

  - by jolierouge

  I have a combobox in a view that receives information about application state changes, and then is supposed to show or hide it's children based on the whole application state. It receives state change messages, it traces the correct values, it does what it's supposed to do, however, it just doesn't seem to work. Essentially, all it needs to do is hide a combobox during one state, and show it again during another state. Here is the code: public function updateState(event:* = null):void { trace("Project Panel Updating State"); switch(ApplicationData.getSelf().currentState) { case 'login': this.visible = false; break; case 'grid': this.visible = true; listProjects.includeInLayout = false; listProjects.visible = false; trace("ListProjects: " + listProjects.visible); listLang.visible = true; break; default: break; } } Here is the MXML: <mx:HBox> <mx:Button id="btnLoad" x="422" y="84" label="Load" enabled="true" click="loadProject();"/> <mx:ComboBox id="listProjects" x="652" y="85" editable="true" change="listChange()" color="#050CA8" fontFamily="Arial" /> <mx:Label x="480" y="86" text="Language:" id="label3" fontFamily="Arial" /> <mx:ComboBox id="listLang" x="537" y="84" editable="true" dataProvider="{langList}" color="#050CA8" fontFamily="Arial" width="107" change="listLangChange(event)"/> <mx:CheckBox x="830" y="84" label="Languages in English" id="langCheckbox" click='toggleLang()'/> </mx:HBox>

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• Kernighan & Ritchie word count example program in a functional language

  - by Frank

  I have been reading a little bit about functional programming on the web lately and I think I got a basic idea about the concepts behind it. I'm curious how everyday programming problems which involve some kind of state are solved in a pure functional programing language. For example: how would the word count program from the book 'The C programming Language' be implemented in a pure functional language? Any contributions are welcome as long as the solution is in a pure functional style. Here's the word count C code from the book: #include <stdio.h> #define IN 1 /* inside a word */ #define OUT 0 /* outside a word */ /* count lines, words, and characters in input */ main() { int c, nl, nw, nc, state; state = OUT; nl = nw = nc = 0; while ((c = getchar()) != EOF) { ++nc; if (c == '\n') ++nl; if (c == ' ' || c == '\n' || c = '\t') state = OUT; else if (state == OUT) { state = IN; ++nw; } } printf("%d %d %d\n", nl, nw, nc); }

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• Problem in setting backgound color to my TreeCellRenderer

  - by Sunil Kumar Sahoo

  Hi I have cretaed my own renderer. I want the back ground should be blue. I have set background color as blue also. But I donot know what is tha problem that the background color of my renderer always seems to be white. I have post the code. please help where I am wrong so that the background color becomes white. class CheckTreeCellRenderer extends JPanel implements TreeCellRenderer { private CheckTreeSelectionModel selectionModel; private MyRenderer delegate; private TristateCheckBox checkBox = new TristateCheckBox("", null, true); public static final State NOT_SELECTED = new State(); public static final State SELECTED = new State(); public static final State DONT_CARE = new State(); public CheckTreeCellRenderer(MyRenderer delegate, CheckTreeSelectionModel selectionModel) { this.delegate = delegate; this.selectionModel = selectionModel; setLayout(new BorderLayout()); setOpaque(true); setBackground(new Color(207, 219, 234)); checkBox.setState(Boolean.TRUE); checkBox.setOpaque(true); checkBox.setBackground(new Color(207, 219, 234)); } public Component getTreeCellRendererComponent(JTree tree, Object value, boolean selected, boolean expanded, boolean leaf, int row, boolean hasFocus) { Component renderer = delegate.getTreeCellRendererComponent(tree, value, selected, expanded, leaf, row, hasFocus); TreePath path = tree.getPathForRow(row); if (path != null) { if (selectionModel.isPathSelected(path, true)) { checkBox.setState(Boolean.TRUE); } else { checkBox.setState(selectionModel.isPartiallySelected(path) ? null : Boolean.FALSE); } } renderer.setBackground(new Color(207, 219, 234)); tree.setOpaque(true); tree.setBackground(new Color(207, 219, 234)); this.setOpaque(true); this.setBackground(new Color(207, 219, 234)); add(checkBox, BorderLayout.WEST); add(renderer, BorderLayout.CENTER); return this; } }

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• Is it possible to create a python iterator over pre-defined mutable data?

  - by Wilduck

  I might be doing this wrong, if I am, let me know, but I'm curious if the following is possible: I have a class that holds a number of dictionaries, each of which pairs names to a different set of objects of a given class. For example: items = {"ball" : ItemInstance1, "sword" : ItemInstance2} people = {"Jerry" : PersonInstance1, "Bob" : PersonInstance2, "Jill" : PersonInstance3} My class would then hold the current items and people that are availible, and these would be subject to change as the state changes: Class State: def __init__(self, items, people): self.items = items self.people = people I would like to define a iter() and next() method such that it iterates through all of the values in its attributes. My first question is whether or not this is possible. If it is, will it be able to support a situation as follows: I define items and people as above then: state = State(items, people) for names, thing in state: print name + " is " + thing.color items[cheese] = ItemInstance3 for names, thing in state: print name + " weighs " + thing.weight While I feel like this would be usefull in the code I have, I don't know if it's either possible or the right approach. Everything I've read about user defined iterators has suggested that each instance of them is one use only.

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• Horizontal histogram won't accept input after the first input

  - by vincentbelkin

  So I'm making a program which is supposed to print a horizontal histogram of the lengths of words in its input. I don't know if most of it is OK since the main problem is it won't accept any input after the first one. Oh I also put comments on the parts I'm having some trouble with, like how to print "-" multiple times in order to represent histogram. I've tried making other versions of the code but I couldn't check if I'm close to getting it because again it won't accept another input after the first input. /*Write a program to print a histogram of the lengths of words in its input. It is easy to draw the histogram with the bars horizontal*/ #include <stdio.h> #define MAX 30 #define IN 1 #define OUT 0 int main() { int a,c,i,k,state,word[MAX]; a=0; k=0; state=OUT; for(i=0;i<MAX;i++) word[i]=0; while((c=getchar())!=EOF) { if(c==' '||c=='\t'||c=='\n') state=OUT; else state=IN; while(state==IN) a++; if(state==OUT) { word[i]=a; i++; } /*This part is hard for me, I don't know how to print X multiple times!*/ if((c==getchar())&&c==EOF) { for(i=0;i<MAX;i++) { for(i=0;i<=word[i];i++) putchar('-'); putchar('\n'); } } } }

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• Conditional execution of EventTriggers in Silverlight 3

  - by Jason

  I'm currently working on the UI of a Silverlight application and need to be able to change the visual state of a control to one of two possible states based on it's current state when handling the same event trigger. For example: I have a control that sits partially in a clipping path, when I click the visible part of the control I want to change the state to "visible" and if I click it again when it is in its "visible" state I want to change to the "hidden" state. Example XAML: <i:Interaction.Triggers> <i:EventTrigger EventName="MouseLeftButtonUp"> <ic:GoToStateAction StateName="Visible"/> <ic:GoToStateAction StateName="Hidden"/> </i:EventTrigger> </i:Interaction.Triggers> Where "i" is "System.Windows.Interactivity;assembly=System.Windows.Interactivity" and "ic" is "Microsoft.Expression.Interactivity.Core;assembly=Microsoft.Expression.Interactions". I'm currently working in Expression Blend 3 and would prefer to have a XAML only solution but am not opposed to coding this if it is completely necessary. I have tried recording a change in the target state name in Blend but this did not work. Any thoughts on this?

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• How to filter what is shown in the for-each loop in XSL

  - by Denoteone

  I thought it would be as easy as tell the for-each to only select top_coach_sales_vw that has "Site" equal to "PB" but when I run the script it does not loop through any of the data in the XML. I am escaping the single quotes because it is part of a php echo. <xsl:for-each select="NewDataSet/top_coach_sales_vw[Site==\'PB\']"> <td><xsl:value-of select="name"/></td> <td><xsl:value-of select="Site"/></td> <td><xsl:value-of select="Status"/></td> </xsl:for-each> XML: <NewDataSet> <top_coach_sales_vw> <name>Mike</name> <Site>PB</Site> <State>Ready</State> </top_coach_sales_vw> <top_coach_sales_vw> <name>Bill</name> <Site>EL</Site> <State>Talking</State> </top_coach_sales_vw> <top_coach_sales_vw> <name>Ted</name> <Site>PB</Site> <State>Ready</State> </top_coach_sales_vw> </NewDataSet>

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• Synth LaF JLabel DISABLED color

  - by mmoris

  Hi all, Using the Synth LaF, I am unable to set a JLabel's FOREGROUND color for the DISABLED state. has anybody succeeded in doing this? Here is my label's style definition in my LaF.xml file. <style id="whiteLabelStyle"> <opaque value="false"/> <font name="Bitstream Vera Sans" size="16" /> <state> <color type="FOREGROUND" value="WHITE"/> </state> <state value="DISABLED"> <color type="FOREGROUND" value="BLACK"/> </state> </style> <bind style="whiteLabelStyle" type="name" key="WhiteOrbitLabel"/> Please not that all the other styles defined in my LaF.xml file are rendered properly in my application including my label's WHITE normal state color (it just never goes to black when I do lbl.setEnabled(false) Also, going through the Synth code, I have found the following comment in SynthStyle.getColor if ((context.getComponentState() & SynthConstants.DISABLED) != 0) { //This component is disabled, so return the disabled color. //In some cases this means ignoring the color specified by the //developer on the component. In other cases it means using a //specified disabledTextColor, such as on JTextComponents. //For example, JLabel doesn't specify a disabled color that the //developer can set, yet it should have a disabled color to the //text when the label is disabled. This code allows for that. if (c instanceof JTextComponent) { JTextComponent txt = (JTextComponent)c; Color disabledColor = txt.getDisabledTextColor(); if (disabledColor == null || disabledColor instanceof UIResource) { return getColorForState(context, type); } } else if (c instanceof JLabel && (type == ColorType.FOREGROUND || type == ColorType.TEXT_FOREGROUND)){ return getColorForState(context, type); } But I could not figure out how to set a disabled color for a JLabel Thanks for your help!

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• Java: Tracking a user login session - Session EJBs vs HTTPSession

  - by bguiz

  If I want to keep track of a conversational state with each client using my web application, which is the better alternative - a Session Bean or a HTTP Session - to use? Using HTTP Session: //request is a variable of the class javax.servlet.http.HttpServletRequest //UserState is a POJO HttpSession session = request.getSession(true); UserState state = (UserState)(session.getAttribute("UserState")); if (state == null) { //create default value .. } String uid = state.getUID(); //now do things with the user id Using Session EJB: In the implementation of ServletContextListener registered as a Web Application Listener in WEB-INF/web.xml: //UserState NOT a POJO this this time, it is //the interface of the UserStateBean Stateful Session EJB @EJB private UserState userStateBean; public void contextInitialized(ServletContextEvent sce) { ServletContext servletContext = sce.getServletContext(); servletContext.setAttribute("UserState", userStateBean); ... In a JSP: public void jspInit() { UserState state = (UserState)(getServletContext().getAttribute("UserState")); ... } Elsewhere in the body of the same JSP: String uid = state.getUID(); //now do things with the user id It seems to me that the they are almost the same, with the main difference being that the UserState instance is being transported in the HttpRequest.HttpSession in the former, and in a ServletContext in the case of the latter. Which of the two methods is more robust, and why?

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• How to "wrap" implementation in C#

  - by igor

  Hello, I have these classes in C# (.NET Framework 3.5) described below: public class Base { public int State {get; set;} public virtual int Method1(){} public virtual string Method2(){} ... public virtual void Method10(){} } public class B: Base { // some implementation } public class Proxy: Base { private B _b; public class Proxy(B b) { _b = b; } public override int Method1() { if (State == Running) return _b.Method1(); else return base.Method1(); } public override string Method2() { if (State == Running) return _b.Method2(); else return base.Method2(); } public override void Method10() { if (State == Running) _b.Method10(); else base.Method10(); } } I want to get something this: public Base GetStateDependentImplementation() { if (State == Running) // may be some other rule return _b; else return base; // compile error } and my Proxy's implementation will be: public class Proxy: Base { ... public override int Method1() { return GetStateDependentImplementation().Method1(); } public override string Method2() { return GetStateDependentImplementation().Method2(); } ... } Of course, I can do this (aggregation of base implementation): public RepeaterOfBase: Base // no any overrides, just inheritance { } public class Proxy: Base { private B _b; private RepeaterOfBase _Base; public class Proxy(B b, RepeaterOfBase aBase) { _b = b; _base = aBase; } } ... public Base GetStateDependentImplementation() { if (State == Running) return _b; else return _Base; } ... But instance of Base class is very huge and I have to avoid to have other additional copy in memory. So I have to simplify my code have to "wrap" implementation have to avoid a code duplication have to avoid aggregation of any additional instance of Base class (duplication) Is it possible to reach these goals?

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• database table design

  - by e.b.white

  I design the tables as below for the system which looks like a package delivering system For example, after user received the package, postman should record in system, and the state(history table) is "delivered",and operator is this postman, the current state(state table) is of course "delivered" history table: +---------------+--------------------------+ | Field | Desc | +---------------+--------------------------+ | id | PRIMARY KEY | +---------------+--------------------------+ | package_id | package_tacking_id | +---------------+--------------------------+ | state | package_state | +---------------+--------------------------+ | operators | operators | +---------------+--------------------------+ | create_time| create_time | +---------------+--------------------------+ state table: +---------------+--------------------------+ | Field | Desc | +---------------+--------------------------+ | id | PRIMARY KEY | +---------------+--------------------------+ | package_id | package_tacking_id | +---------------+--------------------------+ | state | latest_package_state | +---------------+--------------------------+ Above is just the basic information to record, some other information( like invoice, destination,...) should be recored as well. But there are different service types like s1 and s2, for s1 it is not needed to record invoice but s1 need, and maybe s1 need some other information to record (like the tel of end user). After all, at delivering way stations there are additional information to record, and for different service type the information type is different. My question is: 1. For different service type, shall I need to declare different tables(option A) or just one big table which can record all information for all types(option B)? 2. If option A, since the basic information above is MUST, how can prevent from declaring there duplicate fields in different tables?

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• What's the *right* way to handle a POST in FP?

  - by Malvolio

  I'm just getting started with FP and I'm using Scala, which may not be the best way, since I can always fall back to an imperative style if the going gets tough. I'd just rather not. I've got a very specific question that points to a broader lacuna in my understanding of FP. When a web application is processing a GET request, the user wants information that already exists on the web-site. The application only has to process and format the data in some way. The FB way is clear. When a web application is processing a POST request, the user wants change the information held on the site. True, the information is not typically held in application variables, it's in a database or a flat-file, but still, I get the feeling I'm not grokking FP properly. Is there a pattern for handling updates to static data in an FP language? My vague picture of this is that the application is handed the request and the then-current site state. The application does its thing and returns the new site-state. If the current site-state hasn't changed since the application started, the new state becomes the current state and the reply is sent back to the browser (this is my dim image of Clojure's style); if the current state has been changed (by another thread, well, something else happens ...

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• naming a function that exhibits "set if not equal" behavior

  - by Chris Sears

  This might be an odd question, but I'm looking for a word to use in a function name. I'm normally good at coming up with succinct, meaningful function names, but this one has me stumped so I thought I'd appeal for help. The function will take some desired state as an argument and compare it to the current state. If no change is needed, the function will exit normally without doing anything. Otherwise, the function will take some action to achieve the desired state. For example, if wanted to make sure the front door was closed, i might say: my_house.<something>_front_door('closed') What word or term should use in place of the something? I'd like it to be short, readable, and minimize the astonishment factor. A couple clarifying points... I would want someone calling the function to intuitively know they didn't need to wrap the function an 'if' that checks the current state. For example, this would be bad: if my_house.front_door_is_open(): my_house.<something>_front_door('closed') Also, they should know that the function won't throw an exception if the desired state matches the current state. So this should never happen: try: my_house.<something>_front_door('closed') except DoorWasAlreadyClosedException: pass Here are some options I've considered: my_house.set_front_door('closed') my_house.setne_front_door('closed') # ne=not equal, from the setne x86 instruction my_house.ensure_front_door('closed') my_house.configure_front_door('closed') my_house.update_front_door('closed') my_house.make_front_door('closed') my_house.remediate_front_door('closed') And I'm open to other forms, but most I've thought of don't improve readability. Such as... my_house.ensure_front_door_is('closed') my_house.conditionally_update_front_door('closed') my_house.change_front_door_if_needed('closed') Thanks for any input!

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• Flash Builder 4 "includeIn" property causing design view error

  - by Chris

  I am creating a custom TextInput component that will define an "error" state. I have extended the TextInput class to change the state to "error" if the errorString property's length is greater than 0. In the skin class, I have defined an "error" state, and added some logic to detect the size and position of the error icon. However, if I have this code at the same time I use the "includeIn" property in the bitmap image tag, I get a design view error. If I either A) Only include that code with no "includeIn" property set, it works or B) dont include the code to set the icon size and position and only use the "includeIn" property, it works. Any ideas what could be causing the design view problem when I use both the "includeIn" property and the icon size/position code at the same time? TextInput Class: package classes { import spark.components.TextInput; public class TextInput extends spark.components.TextInput { [SkinState("error")]; public function TextInput() { super(); } override public function set errorString( value:String ):void { super.errorString = value; invalidateSkinState(); } override protected function getCurrentSkinState():String { if (errorString.length>0) { return "error"; } return super.getCurrentSkinState(); } } } TextInput Skin File: override protected function updateDisplayList(unscaledWidth:Number, unscaledHeight:Number):void { //THIS IS THE CODE THAT SEEMS TO BE CAUSING THE PROBLEM if(getStyle("iconSize") == "large") { errorIcon.right = -12; errorIcon.source = new errorIconLg(); } else { errorIcon.right = -5; errorIcon.source = new errorIconSm(); } super.updateDisplayList(unscaledWidth, unscaledHeight); } </fx:Script> <s:states> <s:State name="normal"/> <s:State name="disabled"/> <s:State name="error"/> </s:states> //If I remove the problem code above or if I take out the includeIn //property here, it works <s:BitmapImage id="errorIcon" verticalCenter="0" includeIn="error" /> </s:SparkSkin>

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• jquery-ui drag and drop - how to dropped items?

  - by user246114

  Hi, I'm trying to use jquery-ui. I am using one of the drag and drop examples which is pretty much exactly what I need, except instead of moving items between the two lists, I'd like the items to be cloned: http://jqueryui.com/demos/sortable/#connect-lists $(function() { $("#sortable1, #sortable2").sortable({ connectWith: '.connectedSortable' }).disableSelection(); }); <ul id="sortable1" class="connectedSortable"> <li class="ui-state-default">Item 1</li> <li class="ui-state-default">Item 2</li> <li class="ui-state-default">Item 3</li> </ul> <ul id="sortable2" class="connectedSortable"> <li class="ui-state-default">Item 1</li> <li class="ui-state-default">Item 2</li> <li class="ui-state-default">Item 3</li> </ul> so moving an item from the first list to the second list results in list 1 have 2 items, and list 2 having 4 items. I just want it to make clones of the items on the drop. So in the above example, list 1 would still have 3 items, but list 2 would have 4 items, Thank you

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• How To Run XP Mode in VirtualBox on Windows 7 (sort of)

  - by Matthew Guay

  A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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• How To Run XP Mode in VirtualBox on Windows 7 (sort of)

  - by Matthew Guay

  A few weeks ago we showed you how to run XP Mode on a Windows 7 computer without Hardware Virtualization using VMware. Some of you have been asking if it can be done in Virtual Box as well. The answer is “Yes!” and here we’ll show you how. Editor Update: Apparently there isn’t a way to activate XP Mode through VirtualBox using this method. You will however, be able to run it for 30 days. We have a new updated article on how to Install XP Mode with VirtualBox Using the VMLite Plugin.   Earlier we showed you how to run XP mode on windows 7 machines without hardware virtualization capability. Since then, a lot of you have been asking to a write up a tutorial about doing the same thing using VirtualBox.  This makes it another great way to run XP Mode if your computer does not have hardware virtualization.  Here we’ll see how to import the XP Mode from Windows 7 Professional, Enterprise, or Ultimate into VirtualBox so you can run XP in it for free. Note: You need to have Windows 7 Professional or above to use XP Mode in this manner. In our tests we were able to get it to run on Home Premium as well, but you’ll be breaking Windows 7 licensing agreements. Getting Started First, download and install XP Mode (link below).  There is no need to download Virtual PC if your computer cannot run it, so just download the XP Mode from the link on the left. Install XP mode; just follow the default prompts as usual. Now, download and install VirtualBox 3.1.2 or higher(link below).  Install as normal, and simply follow the default prompts. VirtualBox may notify you that your network connection will be reset during the installation.  Press Yes to continue. During the install, you may see several popups asking you if you wish to install device drivers for USB and Network interfaces.  Simply click install, as these are needed for VirtualBox to run correctly. Setup only took a couple minutes, and doesn’t require a reboot. Setup XP Mode in VirtualBox: First we need to copy the default XP Mode so VirtualBox will not affect the original copy.  Browse to C:\Program Files\Windows XP Mode, and copy the file “Windows XP Mode base.vhd”.  Paste it in another folder of your choice, such as your Documents folder. Once you’ve copied the file, right-click on it and click Properties. Uncheck the “Read-only” box in this dialog, and then click Ok. Now, in VirtualBox, click New to create a new virtual machine. Enter the name of your virtual machine, and make sure the operating system selected is Windows XP. Choose how much memory you want to allow the virtual machine to use.  VirtualBox’ default is 192 Mb ram, but for better performance you can select 256 or 512Mb. Now, select the hard drive for the virtual machine.  Select “Use existing hard disk”, then click the folder button to choose the XP Mode virtual drive. In this window, click Add, and then browse to find the copy of XP Mode you previously made. Make sure the correct virtual drive is selected, then press Select. After selecting the VHD your screen should look like the following then click Next. Verify the settings you made are correct. If not, you can go back and make any changes. When everything looks correct click Finish. Setup XP Mode Now, in VirtualBox, click start to run XP Mode. The Windows XP in this virtual drive is not fully setup yet, so you will have to go through the setup process.   If you didn’t uncheck the “Read-only” box in the VHD properties before, you may see the following error.  If you see it, go back and check the file to makes sure it is not read-only. When you click in the virtual machine, it will capture your mouse by default.  Simply press the right Ctrl key to release your mouse so you can go back to using Windows 7.  This will only be the case during the setup process; after the Guest Additions are installed, the mouse will seamlessly move between operating systems. Now, accept the license agreement in XP.   Choose your correct locale and keyboard settings. Enter a name for your virtual XP, and an administrative password. Check the date, time, and time zone settings, and adjust them if they are incorrect.  The time and date are usually correct, but the time zone often has to be corrected. XP will now automatically finish setting up your virtual machine, and then will automatically reboot. After rebooting, select your automatic update settings. You may see a prompt to check for drivers; simply press cancel, as all the drivers we need will be installed later with the Guest Additions. Your last settings will be finalized, and finally you will see your XP desktop in VirtualBox. Please note that XP Mode may not remain activated after importing it into VirtualBox. When you activate it, use the key that is located at C:\Program Files\Windows XP Mode\key.txt.  Note: During our tests we weren’t able to get the activation to go through. We are looking into the issue and will have a revised article showing the correct way to get XP Mode in VirutalBox working correctly soon.    Now we have one final thing to install – the VirtualBox Guest Additions.  In the VirtualBox window, click “Devices” and then select “Install Guest Additions”. This should automatically launch in XP; if it doesn’t, click Start, then My Computer, and finally double-click on the CD drive which should say VirtualBox Guest Additions. Simply install with the normal presets. You can select to install an experimental 3D graphics driver if you wish to try to run games in XP in VirtualBox; however, do note that this is not fully supported and is currently a test feature. You may see a prompt informing you that the drivers have not passed Logo testing; simply press “Continue Anyway” to proceed with the installation.   When installation has completed, you will be required to reboot your virtual machine. Now, you can move your mouse directly from Windows XP to Windows 7 without pressing Ctrl. Integrating with Windows 7 Once your virtual machine is rebooted, you can integrate it with your Windows 7 desktop.  In the VirtualBox window, click Machine and then select “Seamless Mode”.   In Seamless mode you’ll have the XP Start menu and taskbar sit on top of your Windows 7 Start and Taskbar. Here we see XP running on Virtual Box in Seamless Mode. We have the old XP WordPad sitting next to the new Windows 7 version of WordPad. Another view of everything running seamlessly together on the same Windows 7 desktop. Hover the pointer over the XP taskbar to pull up the Virtual Box menu items. You can exit out of Seamless Mode from the VirtualBox menu or using “Ctrl+L”. Then you go back to having it run separately on your desktop again. Conclusion Running XP Mode in a Virtual Machine is a great way to experience the feature on computers without Hardware Virtualization capabilities. If you prefer VMware Player, then you’ll want to check out our articles on how to run XP Mode on Windows 7 machines without Hardware Virtualization, and how to create an XP Mode for Windows 7 Home Premium and Vista. Download VirtualBox Download XP Mode Similar Articles Productive Geek Tips Install XP Mode with VirtualBox Using the VMLite PluginUsing Windows 7 or Vista Compatibility ModeMake Safari Stop Crashing Every 20 Seconds on Windows VistaForce Windows 7 / Vista to Boot Into Safe Mode Without Using the F8 KeyHow To Run Chrome OS in VirtualBox TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 PCmover Professional Enable Check Box Selection in Windows 7 OnlineOCR – Free OCR Service Betting on the Blind Side, a Vanity Fair article 30 Minimal Logo Designs that Say More with Less LEGO Digital Designer – Free Create a Personal Website Quickly using Flavors.me

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• Run Windows in Ubuntu with VMware Player

  - by Matthew Guay

  Are you an enthusiast who loves their Ubuntu Linux experience but still needs to use Windows programs?  Here’s how you can get the full Windows experience on Ubuntu with the free VMware Player. Linux has become increasingly consumer friendly, but still, the wide majority of commercial software is only available for Windows and Macs.  Dual-booting between Windows and Linux has been a popular option for years, but this is a frustrating solution since you have to reboot into the other operating system each time you want to run a specific application.  With virtualization, you’ll never have to make this tradeoff.  VMware Player makes it quick and easy to install any edition of Windows in a virtual machine.  With VMware’s great integration tools, you can copy and paste between your Linux and Windows programs and even run native Windows applications side-by-side with Linux ones. Getting Started Download the latest version of VMware Player for Linux, and select either the 32-bit or 64-bit version, depending on your system.  VMware Player is a free download, but requires registration.  Sign in with your VMware account, or create a new one if you don’t already have one. VMware Player is fairly easy to install on Linux, but you will need to start out the installation from the terminal.  First, enter the following to make sure the installer is marked as executable, substituting version/build_number for the version number on the end of the file you downloaded. chmod +x ./VMware-Player-version/build_number.bundle Then, enter the following to start the install, again substituting your version number: gksudo bash ./VMware-Player-version/build_number.bundle You may have to enter your administrator password to start the installation, and then the VMware Player graphical installer will open.  Choose whether you want to check for product updates and submit usage data to VMware, and then proceed with the install as normal. VMware Player installed in only a few minutes in our tests, and was immediately ready to run, no reboot required.  You can now launch it from your Ubuntu menu: click Applications \ System Tools \ VMware Player. You’ll need to accept the license agreement the first time you run it. Welcome to VMware Player!  Now you can create new virtual machines and run pre-built ones on your Ubuntu desktop. Install Windows in VMware Player on Ubuntu Now that you’ve got VMware setup, it’s time to put it to work.  Click the Create a New Virtual Machine as above to start making a Windows virtual machine. In the dialog that opens, select your installer disk or ISO image file that you want to install Windows from.  In this example, we’re select a Windows 7 ISO.  VMware will automatically detect the operating system on the disk or image.  Click Next to continue. Enter your Windows product key, select the edition of Windows to install, and enter your name and password. You can leave the product key field blank and enter it later.  VMware will ask if you want to continue without a product key, so just click Yes to continue. Now enter a name for your virtual machine and select where you want to save it.  Note: This will take up at least 15Gb of space on your hard drive during the install, so make sure to save it on a drive with sufficient storage space. You can choose how large you want your virtual hard drive to be; the default is 40Gb, but you can choose a different size if you wish.  The entire amount will not be used up on your hard drive initially, but the virtual drive will increase in size up to your maximum as you add files.  Additionally, you can choose if you want the virtual disk stored as a single file or as multiple files.  You will see the best performance by keeping the virtual disk as one file, but the virtual machine will be more portable if it is broken into smaller files, so choose the option that will work best for your needs. Finally, review your settings, and if everything looks good, click Finish to create the virtual machine. VMware will take over now, and install Windows without any further input using its Easy Install.  This is one of VMware’s best features, and is the main reason we find it the easiest desktop virtualization solution to use.   Installing VMware Tools VMware Player doesn’t include the VMware Tools by default; instead, it automatically downloads them for the operating system you’re installing.  Once you’ve downloaded them, it will use those tools anytime you install that OS.  If this is your first Windows virtual machine to install, you may be prompted to download and install them while Windows is installing.  Click Download and Install so your Easy Install will finish successfully. VMware will then download and install the tools.  You may need to enter your administrative password to complete the install. Other than this, you can leave your Windows install unattended; VMware will get everything installed and running on its own. Our test setup took about 30 minutes, and when it was done we were greeted with the Windows desktop ready to use, complete with drivers and the VMware tools.  The only thing missing was the Aero glass feature.  VMware Player is supposed to support the Aero glass effects in virtual machines, and although this works every time when we use VMware Player on Windows, we could not get it to work in Linux.  Other than that, Windows is fully ready to use.  You can copy and paste text, images, or files between Ubuntu and Windows, or simply drag-and-drop files between the two. Unity Mode Using Windows in a window is awkward, and makes your Windows programs feel out of place and hard to use.  This is where Unity mode comes in.  Click Virtual Machine in VMware’s menu, and select Enter Unity. Your Windows desktop will now disappear, and you’ll see a new Windows menu underneath your Ubuntu menu.  This works the same as your Windows Start Menu, and you can open your Windows applications and files directly from it. By default, programs from Windows will have a colored border and a VMware badge in the corner.  You can turn this off from the VMware settings pane.  Click Virtual Machine in VMware’s menu and select Virtual Machine Settings.  Select Unity under the Options tab, and uncheck the Show borders and Show badges boxes if you don’t want them. Unity makes your Windows programs feel at home in Ubuntu.  Here we have Word 2010 and IE8 open beside the Ubuntu Help application.  Notice that the Windows applications show up in the taskbar on the bottom just like the Linux programs.  If you’re using the Compiz graphics effects in Ubuntu, your Windows programs will use them too, including the popular wobbly windows effect. You can switch back to running Windows inside VMware Player’s window by clicking the Exit Unity button in the VMware window. Now, whenever you want to run Windows applications in Linux, you can quickly launch it from VMware Player. Conclusion VMware Player is a great way to run Windows on your Linux computer.  It makes it extremely easy to get Windows installed and running, lets you run your Windows programs seamlessly alongside your Linux ones.  VMware products work great in our experience, and VMware Player on Linux was no exception. If you’re a Windows user and you’d like to run Ubuntu on Windows, check out our article on how to Run Ubuntu in Windows with VMware Player. Link Download VMware Player 3 (Registration required) Download Windows 7 Enterprise 90-day trial Similar Articles Productive Geek Tips Enable Copy and Paste from Ubuntu VMware GuestInstall VMware Tools on Ubuntu Edgy EftRestart the Ubuntu Gnome User Interface QuicklyHow to Add a Program to the Ubuntu Startup List (After Login)How To Run Ubuntu in Windows 7 with VMware Player TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server Snagit 10 Get a free copy of WinUtilities Pro 2010 World Cup Schedule Boot Snooze – Reboot and then Standby or Hibernate Customize Everything Related to Dates, Times, Currency and Measurement in Windows 7 Google Earth replacement Icon (Icons we like) Build Great Charts in Excel with Chart Advisor

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• The Importance of a Security Assessment - by Michael Terra, Oracle

  - by Darin Pendergraft

  Today's Blog was written by Michael Terra, who was the Subject Matter Expert for the recently announced Oracle Online Security Assessment. You can take the Online Assessment here: Take the Online Assessment Over the past decade, IT Security has become a recognized and respected Business discipline.  Several factors have contributed to IT Security becoming a core business and organizational enabler including, but not limited to, increased external threats and increased regulatory pressure. Security is also viewed as a key enabler for strategic corporate activities such as mergers and acquisitions.Now, the challenge for senior security professionals is to develop an ongoing dialogue within their organizations about the importance of information security and how it can impact their organization's strategic objectives/mission. The importance of conducting regular “Security Assessments” across the IT and physical infrastructure has become increasingly important. Security standards and frameworks, such as the international standard ISO 27001, are increasingly being adopted by organizations and their business partners as proof of their security posture and “Security Assessments” are a great way to ensure a continued alignment to these frameworks.Oracle offers a number of different security assessment covering a broad range of technologies. Some of these are short engagements conducted for free with our strategic customers and partners. Others are longer term paid engagements delivered by Oracle Consulting Services or one of our partners. The goal of a security assessment, (also known as a security audit or security review), is to ensure that necessary security controls are integrated into the design and implementation of a project, application or technology.  A properly completed security assessment should provide documentation outlining any security gaps that exist in an infrastructure and the associated risks for those gaps. With that knowledge, an organization can choose to either mitigate, transfer, avoid or accept the risk. One example of an Oracle offering is a Security Readiness Assessment:The Oracle Security Readiness Assessment is a practical security architecture review focused on aligning an organization’s enterprise security architecture to their business principals and strategic objectives. The service will establish a multi-phase security architecture roadmap focused on supporting new and existing business initiatives.Offering OverviewThe Security Readiness Assessment will: Define an organization’s current security posture and provide a roadmap to a desired future state architecture by mapping  security solutions to business goals Incorporate commonly accepted security architecture concepts to streamline an organization’s security vision from strategy to implementation Define the people, process and technology implications of the desired future state architecture The objective is to deliver cohesive, best practice security architectures spanning multiple domains that are unique and specific to the context of your organization. Offering DetailsThe Oracle Security Readiness Assessment is a multi-stage process with a dedicated Oracle Security team supporting your organization.  During the course of this free engagement, the team will focus on the following: Review your current business operating model and supporting IT security structures and processes Partner with your organization to establish a future state security architecture leveraging Oracle’s reference architectures, capability maps, and best practices Provide guidance and recommendations on governance practices for the rollout and adoption of your future state security architecture Create an initial business case for the adoption of the future state security architecture If you are interested in finding out more, ask your Sales Consultant or Account Manager for details.

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• Cost justification for buying a 32GB superfast Alienware M18x with a price tag of around £5K ($10K)

  - by tonyrogerson

  When considering buying a laptop that’s going to cost me around £5,000 I really need to justify the purchase from a business perspective; my Lenovo W700 has served me very well for the last 2 years, it’s an extremely good machine and as solid as a rock (and as heavy), alas though it is limited to the 8GB. As SQL Server 2012 approaches and with my interest in working in the Business Intelligence space over the next year or two it is clear I need a powerful machine that I can run a full infrastructure though virtualised. My requirements For High Availability / Disaster Recovery research and demonstration Machine for a domain controller Four machines in a shared disk cluster (SQL Server Clustering active – active etc.) Five  machines in a file share cluster (SQL Server Availability Groups) For Business Intelligence research and demonstration Not entirely sure how many machine I want to run here, but it would be to cover the entire BI stack in an enterprise setting, sharepoint, sql server etc. For Big Data Research I have a fondness for the NoSQL approach to scalability and dealing with large volumes so I need a number of machines to research VoltDB, Hadoop etc. As you can see the requirements for a SQL Server consultant to service their clients well is considerable; will 8GB suffice, alas no, it will no longer do. I’m a very strong believer that in order to do your job well you must expense it, short cuts only cost you time, waiting 5 minutes instead of an hour for something to run not only saves me time but my clients time, I can do things quicker and more importantly I can demonstrate concepts. My W700 with the 8GB of RAM and SSD’s cost me around £3.5K two years ago, to be honest I’ve not got the full use I wanted out of it but the machine has had the power when I’ve needed it, it’s served me and my clients well. Alienware now do a model (the M18x) with 32GB of RAM; yes 32GB in a laptop! Dual drives so I can whack a couple of really good SSD’s in there, a quad core with hyper threading i7 and a decent speed. I can reduce the cost of the memory by getting it from Crucial, so instead of £1.5K for 32GB it will be around £900, I can also cost save on the SSD as well. The beauty about the M18x is that it is USB3.0, SATA 3 and also really importantly has eSATA, running VM’s will never be easier, I can have a removeable SSD with my VM’s on it and can plug it into my home machine or laptop – an ideal world! The initial outlay of £5K is peanuts compared to the benefits I’ll give my clients, I will be able to present real enterprise concepts, I’ll also be able to give training on those real enterprise concepts and with real, albeit virtualised machines.

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• Unable to suspend with FGLRX enabled

  - by schmmd

  I am unable to suspend in a fully updated (as of yesterday, 29 March 2011) Ubuntu 10.10 installation (kernel 2.6.35-28). Following is a list of some of my hardware: Motherboard: Gigabyte GA-X58A-UD3R Video: Radeon HD-567X-YNF3 Initially, when I went to either Suspend or Hibernate the machine would almost go into suspend, but it would never power down. Instead it would bounce back to the login screen. This was due to a problem with the USB3 ports being unable to suspend (noticed this in /var/log/kern.log). Disabling the USB3 ports in the BIOS fixed this issue. Now Suspend and Hibernate power down the machine. It successfully awakens from Hibernate. However, it will not return from suspend. The mouse and keyboard are not powered and the monitor has no signal. These devices are still not powered after a restart. I must power-cycle the machine. The pm-suspend log ends after it states that it entered suspend (i.e. there is no information any resume code running). I discovered that acpitool -s suspends the machine and resumes successfully exactly once. The second time the machine will not resume. I am not sure how these two tools handle suspend differently. UPDATE: the problem was introduced somewhere between 2.6.35-22 and 2.6.35-28. I have both kernels install presently. Suspend works fine with 2.6.35-22 but not with 2.6.38-28.

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