Search Results

Search found 13288 results on 532 pages for 'print expression'.

Page 178/532 | < Previous Page | 174 175 176 177 178 179 180 181 182 183 184 185  | Next Page >

  • How do I find, count, and display unique elements of an array using Perl?

    - by Luke
    I am a novice Perl programmer and would like some help. I have an array list that I am trying to split each element based on the pipe into two scalar elements. From there I would like to spike out only the lines that read ‘PJ RER Apts to Share’ as the first element. Then I want to print out the second element only once while counting each time the element appears. I wrote the piece of code below but can’t figure out where I am going wrong. It might be something small that I am just overlooking. Any help would be greatly appreciated. ## CODE ## my @data = ('PJ RER Apts to Share|PROVIDENCE', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Condo|WEST WARWICK', 'PJ RER Condo|WARWICK'); foreach my $line (@data) { $count = @data; chomp($line); @fields = split(/\|/,$line); if (($fields[0] =~ /PJ RER Apts to Share/g)){ @array2 = $fields[1]; my %seen; my @uniq = grep { ! $seen{$_}++ } @array2; my $count2 = scalar(@uniq); print "$array2[0] ($count2)","\n" } } print "$count","\n"; ## OUTPUT ## PROVIDENCE (1) JOHNSTON (1) JOHNSTON (1) JOHNSTON (1) 6

    Read the article

  • how do I paste text to a line by line text filter like awk, without having stdin echo to the screen?

    - by Barton Chittenden
    I have a text in an email on a windows box that looks something like this: 100 some random text 101 some more random text 102 lots of random text, all different 103 lots of random text, all the same I want to extract the numbers, i.e. the first word on each line. I've got a terminal running bash open on my Linux box... If these were in a text file, I would do this: awk '{print $1}' mytextfile.txt I would like to paste these in, and get my numbers out, without creating a temp file. my naive first attempt looked like this: $ awk '{print $1}' 100 some random text 100 101 some more random text 101 102 lots of random text, all different 103 lots of random text, all the same 102 103 The buffering of stdin and stdout make a hash of this. I wouldn't mind if stdin all printed first, followed by all of stdout; this is what would happen if I were to paste into 'sort' for example, but awk and sed are a different story. a little more thought gave me this: open two terminals. Create a fifo file. Read from the fifo on one terminal, write to it on another. This does in fact work, but I'm lazy. I don't want to open a second terminal. Is there a way in the shell that I can hide the text echoed to the screen when I'm passing it in to a pipe, so that I paste this: 100 some random text 101 some more random text 102 lots of random text, all different 103 lots of random text, all the same but see this? $ awk '{print $1}' 100 101 102 103

    Read the article

  • Problem when reading input in C

    - by gcx
    I've made a Linked List. Its elements keep both previous and next items' address. It gets commands from an input file. It detects the command and uses the following statement as a parameter. (text: add_to_front john - means: add_to_front(john)) Code: http://pastebin.com/KcAm1y3L When I try to give the commands from an input file it gives me same output over and over. However, if I write inputs in main() manually, it works. For ex input file: add_to_front john add_to_back jane add_to_back jane print (unfortunately) the output is: >add_to_front john >add_to_back jane >add_to_back jane >print jane jane jane Although, if I write add_to_front(john); add_to_back(jane); add_to_back(jane); print(); instead of this command check: while (scanf("%s",command)!=EOF) { if (strcmp(command,"add_to_front")==0) { gets(parameter); add_to_front(parameter); } else if (strcmp(command,"add_to_back")==0) { gets(parameter); add_to_back(parameter); } else if (strcmp(command,"remove_from_back")==0) remove_from_back(parameter); ... printf(" HUH?\n"); } } in main() it gives the correct output. I know it's a lot to ask but this thing is bothering me for 2 days. What do you think i'm doing wrong?

    Read the article

  • Spaceship objects

    - by Jam
    I'm trying to make a program which creates a spaceship and I'm using the status() method to display the ship's name and fuel values. However, it doesn't seem to be working. I think I may have messed something up with the status() method. I'm also trying to make it so that I can change the fuel values, but I don't want to create a new method to do so. I think I've taken a horrible wrong turn somewhere in there. Help please! class Ship(object): def __init__(self, name="Enterprise", fuel=0): self.name=name self.fuel=fuel print "The spaceship", name, "has arrived!" def status(): print "Name: ", self.name print "Fuel level: ", self.fuel status=staticmethod(status) def main(): ship1=Ship(raw_input("What would you like to name this ship?")) fuel_level=raw_input("How much fuel does this ship have?") if fuel_level<0: self.fuel=0 else: self.fuel(fuel_level) ship2=Ship(raw_input("What would you like to name this ship?")) fuel_level2=raw_input("How much fuel does this ship have?") if fuel_level2<0: self.fuel=0 else: self.fuel(fuel_level2) ship3=Ship(raw_input("What would you like to name this ship?")) fuel_level3=raw_input("How much fuel does this ship have?") if fuel_level3<0: self.fuel=0 else: self.fuel(fuel_level3) Ship.status() main() raw_input("Press enter to exit.")

    Read the article

  • How to convert a printer driver to a stand-alone console application which can generate a printer fi

    - by Thorbjørn Ravn Andersen
    I have a situation where the only way to generate a certain datafile is to print it manually to FILE: under Windows and save it in a file for further processing. I would really like to have a small stand-alone program which embeds this binary printer driver so I can run it from a batch file and have it generate that binary file for me, as we can then fully automate the "save file in Visio, 'print' it and upload it to the final destination and trigger a remote test". Is this possible with a suitable Windows SDK? I am a Java programmer, so I do not know Visual Studio and the possibilities with MSDN - yet! - but I'd appreciate pointers. EDIT: I have the installation files for that printer driver, both 32 and 64 bit. Older versions may include a 16 bit driver. EDIT: The "print to FILE:" functionality is just what was recommended by the documentation. I have played a little bit with using the LPR-protocol to see what it can do. I'd still prefer the "invoke small binary" approach.

    Read the article

  • Python: query a class's parent-class after multiple derivations ("super()" does not work)

    - by henry
    Hi, I have built a class-system that uses multiple derivations of a baseclass (object-class1-class2-class3): class class1(object): def __init__(self): print "class1.__init__()" object.__init__(self) class class2(class1): def __init__(self): print "class2.__init__()" class1.__init__(self) class class3(class2): def __init__(self): print "class3.__init__()" class2.__init__(self) x = class3() It works as expected and prints: class3.__init__() class2.__init__() class1.__init__() Now I would like to replace the 3 lines object.__init__(self) ... class1.__init__(self) ... class2.__init__(self) with something like this: currentParentClass().__init__() ... currentParentClass().__init__() ... currentParentClass().__init__() So basically, i want to create a class-system where i don't have to type "classXYZ.doSomething()". As mentioned above, I want to get the "current class's parent-class". Replacing the three lines with: super(type(self), self).__init__() does NOT work (it always returns the parent-class of the current instance - class2) and will result in an endless loop printing: class3.__init__() class2.__init__() class2.__init__() class2.__init__() class2.__init__() ... So is there a function that can give me the current class's parent-class? Thank you for your help! Henry -------------------- Edit: @Lennart ok maybe i got you wrong but at the moment i think i didn't describe the problem clearly enough.So this example might explain it better: lets create another child-class class class4(class3): pass now what happens if we derive an instance from class4? y = class4() i think it clearly executes: super(class3, self).__init__() which we can translate to this: class2.__init__(y) this is definitly not the goal(that would be class3.__init__(y)) Now making lots of parent-class-function-calls - i do not want to re-implement all of my functions with different base-class-names in my super()-calls.

    Read the article

  • Perl Parallel::ForkManager wait_all_children() takes excessively long time

    - by zhang18
    I have a script that uses Parallel::ForkManager. However, the wait_all_children() process takes incredibly long time even after all child-processes are completed. The way I know is by printing out some timestamps (see below). Does anyone have any idea what might be causing this (I have 16 CPU cores on my machine)? my $pm = Parallel::ForkManager->new(16) for my $i (1..16) { $pm->start($i) and next; ... do something within the child-process ... print (scalar localtime), " Process $i completed.\n"; $pm->finish(); } print (scalar localtime), " Waiting for some child process to finish.\n"; $pm->wait_all_children(); print (scalar localtime), " All processes finished.\n"; Clearly, I'll get the Waiting for some child process to finish message first, with a timestamp of, say, 7:08:35. Then I'll get a list of Process i completed messages, with the last one at 7:10:30. However, I do not receive the message All Processes finished until 7:16:33(!). Why is that 6-minute delay between 7:10:30 and 7:16:33? Thx!

    Read the article

  • Saving "heavy" figure to PDF in MATLAB - rendering problem

    - by yuk
    I generate a figure in MATLAB with lot amount of points (100000+) and want to save it into a PDF file. With zbuffer or painters renderer I've got very large and slowly opened file (over 4 Mb) - all points are in vector format. Using OpenGL renderer rasterize the figure in PDF, ok for the plot, but not good for text labels. The file size is about 150 Kb. Try this simplified code, for example: x=linspace(1,10,100000); y=sin(x)+randn(size(x)); plot(x,y,'.') set(gcf,'Renderer','zbuffer') print -dpdf -r300 testpdf_zb set(gcf,'Renderer','painters') print -dpdf -r300 testpdf_pa set(gcf,'Renderer','opengl') print -dpdf -r300 testpdf_op The actual figure is much more complex with several axes and different types of plots. Is there a way to rasterize the figure, but keep text labels as vectors? Another problem with OpenGL is that is does not work in terminal mode (-nosplash -nodesktop) under Mac OSX. Looks like OpenGL is not supported. I have to use terminal mode for automation. The MATLAB version I run is 2007b. Mac OSX server 10.4.

    Read the article

  • Using pam_python in a script running with mod_python

    - by markys
    Hi ! I would like to develop a web interface to allow users of a Linux system to do certain tasks related to their account. I decided to write the backend of the site using Python and mod_python on Apache. To authenticate the users, I thought I could use python_pam to query the PAM service. I adapted the example bundled with the module and got this: # out is the output stream used to print debug def auth(username, password, out): def pam_conv(aut, query_list, user_data): out.write("Query list: " + str(query_list) + "\n") # List to store the responses to the different queries resp = [] for item in query_list: query, qtype = item # If PAM asks for an input, give the password if qtype == PAM.PAM_PROMPT_ECHO_ON or qtype == PAM.PAM_PROMPT_ECHO_OFF: resp.append((str(password), 0)) elif qtype == PAM.PAM_PROMPT_ERROR_MSG or qtype == PAM.PAM_PROMPT_TEXT_INFO: resp.append(('', 0)) out.write("Our response: " + str(resp) + "\n") return resp # If username of password is undefined, fail if username is None or password is None: return False service = 'login' pam_ = PAM.pam() pam_.start(service) # Set the username pam_.set_item(PAM.PAM_USER, str(username)) # Set the conversation callback pam_.set_item(PAM.PAM_CONV, pam_conv) try: pam_.authenticate() pam_.acct_mgmt() except PAM.error, resp: out.write("Error: " + str(resp) + "\n") return False except: return False # If we get here, the authentication worked return True My problem is that this function does not behave the same wether I use it in a simple script or through mod_python. To illustrate this, I wrote these simple cases: my_username = "markys" my_good_password = "lalala" my_bad_password = "lololo" def handler(req): req.content_type = "text/plain" req.write("1- " + str(auth(my_username,my_good_password,req) + "\n")) req.write("2- " + str(auth(my_username,my_bad_password,req) + "\n")) return apache.OK if __name__ == "__main__": print "1- " + str(auth(my_username,my_good_password,sys.__stdout__)) print "2- " + str(auth(my_username,my_bad_password,sys.__stdout__)) The result from the script is : Query list: [('Password: ', 1)] Our response: [('lalala', 0)] 1- True Query list: [('Password: ', 1)] Our response: [('lololo', 0)] Error: ('Authentication failure', 7) 2- False but the result from mod_python is : Query list: [('Password: ', 1)] Our response: [('lalala', 0)] Error: ('Authentication failure', 7) 1- False Query list: [('Password: ', 1)] Our response: [('lololo', 0)] Error: ('Authentication failure', 7) 2- False I don't understand why the auth function does not return the same value given the same inputs. Any idea where I got this wrong ? Here is the original script, if that could help you. Thanks a lot !

    Read the article

  • How to parse a custom XML-style error code response from a website

    - by user1870127
    I'm developing a program that queries and prints out open data from the local transit authority, which is returned in the form of an XML response. Normally, when there are buses scheduled to run in the next few hours (and in other typical situations), the XML response generated by the page is handled correctly by the java.net.URLConnection.getInputStream() function, and I am able to print the individual results afterwards. The problem is when the buses are NOT running, or when some other problem with my queries develops after it is sent to the transit authority's web server. When the authority developed their service, they came up with their own unique error response codes, which are also sent as XMLs. For example, one of these error messages might look like this: <Error xmlns:i="http://www.w3.org/2001/XMLSchema-instance"> <Code>3005</Code> <Message>Sorry, no stop estimates found for given values.</Message> </Error> (This code and similar is all that I receive from the transit authority in such situations.) However, it appears that URLConnection.getInputStream() and some of its siblings are unable to interpret this custom code as a "valid" response that I can handle and print out as an error message. Instead, they give me a more generic HTTP/1.1 404 Not Found error. This problem cascades into my program which then prints out a java.io.FileNotFoundException error pointing to the offending input stream. My question is therefore two-fold: 1. Is there a way to retrieve, parse, and print a custom XML-formatted error code sent by a web service using the plugins that are available in Java? 2. If the above is not possible, what other tools should I use or develop to handle such custom codes as described?

    Read the article

  • Return a list of imported Python modules used in a script?

    - by Jono Bacon
    Hi All, I am writing a program that categorizes a list of Python files by which modules they import. As such I need to scan the collection of .py files ad return a list of which modules they import. As an example, if one of the files I import has the following lines: import os import sys, gtk I would like it to return: ["os", "sys", "gtk"] I played with modulefinder and wrote: from modulefinder import ModuleFinder finder = ModuleFinder() finder.run_script('testscript.py') print 'Loaded modules:' for name, mod in finder.modules.iteritems(): print '%s ' % name, but this returns more than just the modules used in the script. As an example in a script which merely has: import os print os.getenv('USERNAME') The modules returned from the ModuleFinder script return: tokenize heapq __future__ copy_reg sre_compile _collections cStringIO _sre functools random cPickle __builtin__ subprocess cmd gc __main__ operator array select _heapq _threading_local abc _bisect posixpath _random os2emxpath tempfile errno pprint binascii token sre_constants re _abcoll collections ntpath threading opcode _struct _warnings math shlex fcntl genericpath stat string warnings UserDict inspect repr struct sys pwd imp getopt readline copy bdb types strop _functools keyword thread StringIO bisect pickle signal traceback difflib marshal linecache itertools dummy_thread posix doctest unittest time sre_parse os pdb dis ...whereas I just want it to return 'os', as that was the module used in the script. Can anyone help me achieve this?

    Read the article

  • Excel VBA - export to UTF-8

    - by Tom
    The macro I created works fine, I just need to sort out the saving business. Now I get a popup asking me where to save it, but I would like it to save it under a default name and path AND encoded in UTF-8. This is my full code I use, the bottom part saves the document I presume. Public Sub ExportToTextFile(FName As String, Sep As String, SelectionOnly As Boolean, AppendData As Boolean) Dim WholeLine As String Dim fnum As Integer Dim RowNdx As Long Dim ColNdx As Integer Dim StartRow As Long Dim EndRow As Long Dim StartCol As Integer Dim EndCol As Integer Dim CellValue As String Dim teller As Integer 'Teller aangemaakt ter controle voor het aantal velden 'teller = 1 Application.ScreenUpdating = False On Error GoTo EndMacro: fnum = FreeFile If SelectionOnly = True Then With Selection StartRow = .Cells(1).Row StartCol = .Cells(26).Column EndRow = .Cells(.Cells.Count).Row EndCol = .Cells(.Cells.Count).Column End With Else With ActiveSheet.UsedRange StartRow = .Cells(1).Row StartCol = .Cells(26).Column EndRow = .Cells(.Cells.Count).Row EndCol = .Cells(26).Column End With End If If AppendData = True Then Open FName For Append Access Write As #fnum Else Open FName For Output Access Write As #fnum End If For RowNdx = StartRow To EndRow WholeLine = "" For ColNdx = StartCol To EndCol If Cells(RowNdx, ColNdx).Value = "" Then CellValue = "" Else CellValue = Cells(RowNdx, ColNdx).Value End If WholeLine = WholeLine & CellValue & Sep Next ColNdx WholeLine = Left(WholeLine, Len(WholeLine) - Len(Sep)) Print #fnum, WholeLine, "" 'Print #fnum, teller, WholeLine, "" 'teller = teller + 1 Next RowNdx EndMacro: On Error GoTo 0 Application.ScreenUpdating = True Close #fnum End Sub Sub Dump4Mini() Dim FileName As Variant Dim Sep As String FileName = Application.GetSaveAsFilename(InitialFileName:=Blank, filefilter:="Text (*.txt),*.txt") If FileName = False Then Exit Sub End If Sep = "|" If Sep = vbNullString Then Exit Sub End If Debug.Print "FileName: " & FileName, "Separator: " & Sep ExportToTextFile FName:=CStr(FileName), Sep:=CStr(Sep), SelectionOnly:=False, AppendData:=False End Sub

    Read the article

  • How to set DocFlavor for printservice in Java for WIndows.

    - by om
    Hello, I have written code to run the printer programatically in Java.I have to set the value of docflavor to print the .txt file.When I set it for INPUT_STREAM.TEXT_PLAIN_UTF_8 and run my program on Linux , it prints the text file.but when i run the same code for windows.It can't print the text file.It only prints the jpeg format file.I am using HP Deskjet F735 printer for this. Following is my code . DocFlavor docflavor = DocFlavor.INPUT_STREAM.TEXT_PLAIN_UTF_8; PrintRequestAttributeSet attr_set = new HashPrintRequestAttributeSet(); attr_set.add(new Copies(2)); PrintService[] service = PrintServiceLookup.lookupPrintServices(docflavor, attr_set); if (service.length==0) { JOptionPane.showMessageDialog(null, "No Printer Selected"); } else if (service.length > 0) { System.out.println("Selected printer is " + service[0].getName()); DocPrintJob pj = service[0].createPrintJob(); { PrintService ps = pj.getPrintService(); FileInputStream fis = null; try { File file = new File("/home/ignu/Desktop/newfile"); fis = new FileInputStream(file); Doc doc = new SimpleDoc(fis, docflavor, null); pj.print(doc, attr_set);

    Read the article

  • Object suddenly missing from HttpServletRequest

    - by Jeune
    I print a list directly in the servlet using the print writer and the list prints. When I try to put in the jsp however the list doesn't print whether I use JSTL or scriptlets. I tried to test in JSTL and scriptlet if the object is null and turns out that it is! Why does this happen and how can I fix this? Servlet code that works for (Artist artist:artists){ resp.getWriter().println(artist.getName()); } Servlet code that puts object in the request public void doGet(HttpServletRequest req, HttpServletResponse resp) throws IOException { ApplicationContext ctx = new ClassPathXmlApplicationContext("com/helloworld/beans/helloworld-context.xml"); ArtistDao artistDao = (ArtistDao) ctx.getBean("artistDao"); List<Artist> artists = null; try { artists = artistDao.getAll(); } catch (SQLException e) { e.printStackTrace(); } req.setAttribute("artists", artists); try { req.getRequestDispatcher("index.jsp").forward(req, resp); } catch (ServletException e) { e.printStackTrace(); } scriptlet code that suddenly finds the object null <% List<Artist> artists = (List<Artist>) request.getAttribute("artists"); if (artists == null) { out.println("artists null"); } else { for (Artist artist: artists){ out.println(artist.getName()); } } %> Even the jstl code seems to agree <c:if test="${artists eq null}"> Artists are null </c:if> <c:forEach var="artist" items="${artists}"> ${artist.name} </c:forEach> For my app I am using weblogic, spring 2.5.6 and ibatis.

    Read the article

  • use proxy in python to fetch a webpage

    - by carmao
    I am trying to write a function in Python to use a public anonymous proxy and fetch a webpage, but I got a rather strange error. The code (I have Python 2.4): import urllib2 def get_source_html_proxy(url, pip, timeout): # timeout in seconds (maximum number of seconds willing for the code to wait in # case there is a proxy that is not working, then it gives up) proxy_handler = urllib2.ProxyHandler({'http': pip}) opener = urllib2.build_opener(proxy_handler) opener.addheaders = [('User-agent', 'Mozilla/5.0')] urllib2.install_opener(opener) req=urllib2.Request(url) sock=urllib2.urlopen(req) timp=0 # a counter that is going to measure the time until the result (webpage) is # returned while 1: data = sock.read(1024) timp=timp+1 if len(data) < 1024: break timpLimita=50000000 * timeout if timp==timpLimita: # 5 millions is about 1 second break if timp==timpLimita: print IPul + ": Connection is working, but the webpage is fetched in more than 50 seconds. This proxy returns the following IP: " + str(data) return str(data) else: print "This proxy " + IPul + "= good proxy. " + "It returns the following IP: " + str(data) return str(data) # Now, I call the function to test it for one single proxy (IP:port) that does not support user and password (a public high anonymity proxy) #(I put a proxy that I know is working - slow, but is working) rez=get_source_html_proxy("http://www.whatismyip.com/automation/n09230945.asp", "93.84.221.248:3128", 50) print rez The error: Traceback (most recent call last): File "./public_html/cgi-bin/teste5.py", line 43, in ? rez=get_source_html_proxy("http://www.whatismyip.com/automation/n09230945.asp", "93.84.221.248:3128", 50) File "./public_html/cgi-bin/teste5.py", line 18, in get_source_html_proxy sock=urllib2.urlopen(req) File "/usr/lib64/python2.4/urllib2.py", line 130, in urlopen return _opener.open(url, data) File "/usr/lib64/python2.4/urllib2.py", line 358, in open response = self._open(req, data) File "/usr/lib64/python2.4/urllib2.py", line 376, in _open '_open', req) File "/usr/lib64/python2.4/urllib2.py", line 337, in _call_chain result = func(*args) File "/usr/lib64/python2.4/urllib2.py", line 573, in lambda r, proxy=url, type=type, meth=self.proxy_open: \ File "/usr/lib64/python2.4/urllib2.py", line 580, in proxy_open if '@' in host: TypeError: iterable argument required I do not know why the character "@" is an issue (I have no such in my code. Should I have?) Thanks in advance for your valuable help.

    Read the article

  • Starting a process in one HTTP call and getting results in another

    - by KillianDS
    Hi, I'm writing a very simple testing framework for my application, the design isn't perfect, but I don't have time to write something more complex. Essentially, I have a client and server-application, on my server I want a small python web server to start the server application with given test sequences on a GET or POST call. Also, the application prints some testdata to stderr which I'd like to catch and return in another HTTP call. At the moment I have this: from subprocess import Popen, PIPE from BaseHTTPServer import BaseHTTPRequestHandler, HTTPServer p = None class MyHandler(BaseHTTPRequestHandler): def do_GET(self): global p if self.path.endswith("start/"): p = Popen(["./bin/Release/simplex264","BBB-360","127.0.0.1"], stderr=PIPE) print 'started' return elif self.path.endswith("getResults/"): self.wfile.write(p.stderr.read()) return self.send_error(404,'File Not Found: %s' % self.path) def main(): try: server = HTTPServer(('localhost', 9876), MyHandler) print 'Started server...' server.serve_forever() except KeyboardInterrupt: print 'Shutting down...' server.socket.close() if __name__ == '__main__': main() Which 'works', except for one part, when I try to open http://localhost:9876/start/, it does not return before the process ended. However, the 'started' appears in my shell immediately (I added this because I thought the Popen call would only return after execution). I do not know the perfect inner workings of Popen and BaseHTTPRequestHandler however and do not really know where it goes wrong. Is there any way to make this work asynchronously?

    Read the article

  • emacs: Inferior-mode python-shell appears "lagged"

    - by Begbie00
    Hi all - I'm a Python(3.1.2)/emacs(23.2) newbie teaching myself tkinter using the pythonware tutorial found here. Relevant code is pasted below the question. Question: when I click the Hello button (which should call the say_hi function) why does the inferior python shell (i.e. the one I kicked off with C-c C-c) wait to execute the say_hi print function until I either a) click the Quit button or b) close the root widget down? When I try the same in IDLE, each click of the Hello button produces an immediate print in the IDLE python shell, even before I click Quit or close the root widget. Is there some quirk in the way emacs runs the Python shell (vs. IDLE) that causes this "lagged" behavior? I've noticed similar emacs lags vs. IDLE as I've worked through Project Euler problems, but this is the clearest example I've seen yet. FYI: I use python.el and have a relatively clean init.el... (setq python-python-command "d:/bin/python31/python") is the only line in my init.el. Thanks, Mike === Begin Code=== from tkinter import * class App: def __init__(self,master): frame = Frame(master) frame.pack() self.button = Button(frame, text="QUIT", fg="red", command=frame.quit) self.button.pack(side=LEFT) self.hi_there = Button(frame, text="Hello", command=self.say_hi) self.hi_there.pack(side=LEFT) def say_hi(self): print("hi there, everyone!") root = Tk() app = App(root) root.mainloop()

    Read the article

  • Return a list of important Python modules in a script?

    - by Jono Bacon
    Hi All, I am writing a program that categorizes a list of Python files by which modules they import. As such I need to scan the collection of .py files ad return a list of which modules they import. As an example, if one of the files I import has the following lines: import os import sys, gtk I would like it to return: ["os", "sys", "gtk"] I played with modulefinder and wrote: from modulefinder import ModuleFinder finder = ModuleFinder() finder.run_script('testscript.py') print 'Loaded modules:' for name, mod in finder.modules.iteritems(): print '%s ' % name, but this returns more than just the modules used in the script. As an example in a script which merely has: import os print os.getenv('USERNAME') The modules returned from the ModuleFinder script return: tokenize heapq __future__ copy_reg sre_compile _collections cStringIO _sre functools random cPickle __builtin__ subprocess cmd gc __main__ operator array select _heapq _threading_local abc _bisect posixpath _random os2emxpath tempfile errno pprint binascii token sre_constants re _abcoll collections ntpath threading opcode _struct _warnings math shlex fcntl genericpath stat string warnings UserDict inspect repr struct sys pwd imp getopt readline copy bdb types strop _functools keyword thread StringIO bisect pickle signal traceback difflib marshal linecache itertools dummy_thread posix doctest unittest time sre_parse os pdb dis ...whereas I just want it to return 'os', as that was the module used in the script. Can anyone help me achieve this?

    Read the article

  • PHP, is_array() generating an "Undefined property: stdClass::$crit " error

    - by Brook Julias
    is_array($src2->crit) is generating an "Undefined property: stdClass::$crit" error. The line throwing the error is: if(is_array($src2->crit) && count($src->crit) > 0){ $src2->crit is initialized here. $src2->crit = array(); $src2->crit[0] = new dataSet(); $src2->crit[0]->tblName = $tbl2; $src2->crit[0]->colName = "ID"; $src2->crit[0]->val = $elm->editID; When testing $src2->crit with this code. print("\$src->crit is a ".$src->crit."<br />"); print_r($src->crit); print("<br />"); This is returned. $src2->crit is a Array Array ( [0] => dataSet Object ( [tblName] => sExam [colName] => ID [val] => 10 ) ) What am I not seeing/understanding correctly? If print("\$src2->crit is a ".$src->crit."<br />") returns that it is an array then why is is_array($src2->$crit) generating an error?

    Read the article

  • Perl : get substring which matches refex error

    - by Michael Mao
    Hi all: I am very new to Perl, so please bear with my simple question: Here is the sample output: Most successful agents in the Emarket climate are (in order of success): 1. agent10896761 ($-8008) 2. flightsandroomsonly ($-10102) 3. agent10479475hv ($-10663) Most successful agents in the Emarket climate are (in order of success): 1. agent10896761 ($-7142) 2. agent10479475hv ($-8982) 3. flightsandroomsonly ($-9124) I am interested only in agent names as well as their corresponding balances, so I am hoping to get the following output: agent10896761 -8008 flightsandroomsonly -10102 agent10479475hv -10663 agent10896761 -7142 agent10479475hv -8982 flightsandroomsonly -9124 For later processes. This is the code I've got so far: #!/usr/bin/perl -w open(MYINPUTFILE, $ARGV[0]); while(<MYINPUTFILE>) { my($line) = $_; chomp($line); # regex match test if($line =~ m/agent10479475/) { if($line =~ m/($-[0-9]+)/) { print "$1\n"; } } if($line =~ m/flightsandroomsonly/) { print "$line\n"; } } The second regex match has nothing wrong, 'cause that is printing out the whole line. However, for the first regex match, I've got some other output such like: $ ./compareResults.pl 3.txt 2. flightsandroomsonly ($-10102) 0479475 0479475 3. flightsandroomsonly ($-9124) 1. flightsandroomsonly ($-8053) 0479475 1. flightsandroomsonly ($-6126) 0479475 If I "escape" the braces like this if($line =~ m/\($-[0-9]+\)/) { print "$1\n"; } Then there is never a match for the first regex... So I stuck with a problem of making that particular regex work. Any hints for this? Many thanks in advance.

    Read the article

  • set a cookie while sending PERL HTTP::Request

    - by dexter
    i have created HTTP::Request which looks like this: #!/usr/bin/perl require HTTP::Request; require LWP::UserAgent; $request = HTTP::Request->new(GET => 'http://www.google.com/'); $ua = LWP::UserAgent->new; $ua->cookie_jar({file => "testcookies.txt",autosave =>1}); $response = $ua->request($request); if($response->is_success){ print "sucess\n"; print $response->code; } else { print "fail\n"; die $response->code; } now, When i send Request: $request = HTTP::Request->new(GET => 'http://www.google.com/'); $ua = LWP::UserAgent->new; $ua->cookie_jar({file => "testcookies.txt",autosave =>1}); i want to set a cookie which might look like.. $request = HTTP::Request->new(GET => 'http://www.google.com/'); $ua = LWP::UserAgent->new; $ua->new CGI::Cookie(-name=>"testCookie",-value=>"cookieValue"); $ua->cookie_jar({file => "testcookies.txt"}); gives error though. AND, want to log the http response codes in the file please help thank you

    Read the article

  • Avoiding a fork()/SIGCHLD race condition

    - by larry
    Please consider the following fork()/SIGCHLD pseudo-code. // main program excerpt for (;;) { if ( is_time_to_make_babies ) { pid = fork(); if (pid == -1) { /* fail */ } else if (pid == 0) { /* child stuff */ print "child started" exit } else { /* parent stuff */ print "parent forked new child ", pid children.add(pid); } } } // SIGCHLD handler sigchld_handler(signo) { while ( (pid = wait(status, WNOHANG)) > 0 ) { print "parent caught SIGCHLD from ", pid children.remove(pid); } } In the above example there's a race-condition. It's possible for "/* child stuff */" to finish before "/* parent stuff */" starts which can result in a child's pid being added to the list of children after it's exited, and never being removed. When the time comes for the app to close down, the parent will wait endlessly for the already-finished child to finish. One solution I can think of to counter this is to have two lists: started_children and finished_children. I'd add to started_children in the same place I'm adding to children now. But in the signal handler, instead of removing from children I'd add to finished_children. When the app closes down, the parent can simply wait until the difference between started_children and finished_children is zero. Another possible solution I can think of is using shared-memory, e.g. share the parent's list of children and let the children .add and .remove themselves? But I don't know too much about this. EDIT: Another possible solution, which was the first thing that came to mind, is to simply add a sleep(1) at the start of /* child stuff */ but that smells funny to me, which is why I left it out. I'm also not even sure it's a 100% fix. So, how would you correct this race-condition? And if there's a well-established recommended pattern for this, please let me know! Thanks.

    Read the article

  • Saving "heavy" image to PDF in MATLAB - rendering problem

    - by yuk
    I generate a figure in MATLAB with lot amount of points (100000+) and want to save it into a PDF file. With zbuffer or painters renderer I've got very large and slowly opened file (over 4 Mb) - all points are in vector format. Using OpenGL renderer rasterize the figure in PDF, ok for the plot, but not good for text labels. The file size is about 150 Kb. Try this simplified code, for example: x=linspace(1,10,100000); y=sin(x)+randn(size(x)); plot(x,y,'.') set(gcf,'Renderer','zbuffer') print -dpdf -r300 testpdf_zb set(gcf,'Renderer','painters') print -dpdf -r300 testpdf_pa set(gcf,'Renderer','opengl') print -dpdf -r300 testpdf_op The actual figure is much more complex with several axes and different types of plots. Is there a way to rasterize the figure, but keep text labels as vectors? Another problem with OpenGL is that is does not work in terminal mode (-nosplash -nodesktop) under Mac OSX. Looks like OpenGL is not supported. I have to use terminal mode for automation. The MATLAB version I run is 2007b. Mac OSX server 10.4.

    Read the article

  • Ruby - calling constructor without arguments & removal of new line characters

    - by Raj
    I am a newbie at Ruby, I have written down a sample program. I dont understand the following: Why constructor without any arguments are not called in Ruby? How do we access the class variable outside the class' definition? Why does it always append newline characters at the end of the string? How do we strip it? Code: class Employee attr_reader :empid attr_writer :empid attr_writer :name def name return @name.upcase end attr_accessor :salary @@employeeCount = 0 def initiaze() @@employeeCount += 1 puts ("Initialize called!") end def getCount return @@employeeCount end end anEmp = Employee.new print ("Enter new employee name: ") anEmp.name = gets() print ("Enter #{anEmp.name}'s employee ID: ") anEmp.empid = gets() print ("Enter salary for #{anEmp.name}: ") anEmp.salary = gets() theEmpName = anEmp.name.split.join("\n") theEmpID = anEmp.empid.split.join("\n") theEmpSalary = anEmp.salary.split.join("\n") anEmp = Employee.new() anEmp = Employee.new() theCount = anEmp.getCount puts ("New employee #{theEmpName} with employee ID #{theEmpID} has been enrolled, welcome to hell! You have been paid as low as $ #{theEmpSalary}") puts ("Total number of employees created = #{theCount}") Output: Enter new employee name: Lionel Messi Enter LIONEL MESSI 's employee ID: 10 Enter salary for LIONEL MESSI : 10000000 New employee LIONEL MESSI with employee ID 10 has been enrolled, welcome to hell! You have been paid as low as $ 10000000 Total number of employees created = 0 Thanks

    Read the article

  • Noob boost::bind member function callback question

    - by shaz
    #include <boost/bind.hpp> #include <iostream> using namespace std; using boost::bind; class A { public: void print(string &s) { cout << s.c_str() << endl; } }; typedef void (*callback)(); class B { public: void set_callback(callback cb) { m_cb = cb; } void do_callback() { m_cb(); } private: callback m_cb; }; void main() { A a; B b; string s("message"); b.set_callback(bind(A::print, &a, s)); b.do_callback(); } So what I'm trying to do is to have the print method of A stream "message" to cout when b's callback is activated. I'm getting an unexpected number of arguments error from msvc10. I'm sure this is super noob basic and I'm sorry in advance.

    Read the article

< Previous Page | 174 175 176 177 178 179 180 181 182 183 184 185  | Next Page >