Search Results

Search found 34305 results on 1373 pages for 'self referencing table'.

Page 178/1373 | < Previous Page | 174 175 176 177 178 179 180 181 182 183 184 185  | Next Page >

  • Highlight table view cells when user drags across rows

    - by chronos
    I have a grouped table view that does not need to scroll. I'd like each cell to highlight as the user moves their finger down the screen and call didSelectRowAtIndexPath on release. This behaviour can be seen done by apple in 'settings mail add account'? I can't seem to replicate it myself, all I can get is the default, where the cell deselects as soon as the user moves their finger.

    Read the article

  • hash table with chaining method program freezing

    - by Justin Carrey
    I am implementing hash table in C using linked list chaining method. The program compiles but when inserting a string in hash table, the program freezes and gets stuck. The program is below: struct llist{ char *s; struct llist *next; }; struct llist *a[100]; void hinsert(char *str){ int strint, hashinp; strint = 0; hashinp = 0; while(*str){ strint = strint+(*str); } hashinp = (strint%100); if(a[hashinp] == NULL){ struct llist *node; node = (struct llist *)malloc(sizeof(struct llist)); node->s = str; node->next = NULL; a[hashinp] = node; } else{ struct llist *node, *ptr; node = (struct llist *)malloc(sizeof(struct llist)); node->s = str; node->next = NULL; ptr = a[hashinp]; while(ptr->next != NULL){ ptr = ptr->next; } ptr->next = node; } } void hsearch(char *strsrch){ int strint1, hashinp1; strint1 = 0; hashinp1 = 0; while(*strsrch){ strint1 = strint1+(*strsrch); } hashinp1 = (strint1%100); struct llist *ptr1; ptr1 = a[hashinp1]; while(ptr1 != NULL){ if(ptr1->s == strsrch){ cout << "Element Found\n"; break; } else{ ptr1 = ptr1->next; } } if(ptr1 == NULL){ cout << "Element Not Found\n"; } } hinsert() is to insert elements into hash and hsearch is to search an element in the hash. Hash function is written inside hinsert() itself. In the main(), what i am initializing all the elements in a[] to be NULL like this: for(int i = 0;i < 100; i++){ a[i] = NULL; } Help is very much appreciated. Thanks !

    Read the article

  • Erro while join table in SQL

    - by Color Shadow
    I have two tables that have relationship with UserName field. Based on UserName column, I want to get ID from CarReserve table. Here is my SQL statement: SELECT CarReserve.ID FROM CarReserve INNER JOIN aspnet_Users ON CarReserve.UserName = aspnet_Users.UserName WHERE UserName = @UserName Unfortunately, I am getting this warning: Ambiguous column name "UserName" Can anyone here tell me what is wrong with my statement?

    Read the article

  • Selecting two specific mysql table rows in a single query

    - by Scotta
    Lets say I have a table with 20 entries. They are sorted by date (date is a column name _) in descending order. How would I go about selecting ONLY the newest entry and the 15th oldest entry? I am getting all 15 results by doing the following query SELECT * FROM mytable m WHERE col1 = "zzz" ORDER BY date DESC LIMIT 15;

    Read the article

  • How to find missing alpha values in sets of data within same table in SQL

    - by Jeff
    I have a table of many values where one column has the WO Number, and another column has the Resource ID. I need to be able to find all the WO numbers that do not have a resource value of "RW". Here is an example of the typical information. I need to be able to know that work order 5678 does not have an "RW" Resource ID. WO Number - Resource ID 1234 - IN 1234 - WE 1234 - AS 1234 - RW 5678 - PR 5678 - WE 5678 - IN 5678 - AS

    Read the article

  • SQL updating a column in a table

    - by tecnodude
    Hi, I have the following table in an access database id VisitNo Weight 1 1 100 1 2 95 1 3 96 1 4 94 1 5 93 Now row 2 and 4 are deleted. So i have... id VisitNo Weight 1 1 100 1 3 96 1 5 93 However what i need is... id VisitNo Weight 1 1 100 1 2 96 1 3 93 What is the SQL query i need to accomplish the above? thanks

    Read the article

  • Getting maximum value from table using LINQ

    - by Tena
    I have a table in my database. I want to get the maximum value of a column named NumOfView. I used this code: var advert=(from ad in storedb.Ads where ad.AdScope == "1" select ad.NumOfView).Max(); It works but when there are two or more same maximum values it doesn't work and this message appears: Sequence contains more than one element What should I do now? Your answers will be very helpfull. Thanks

    Read the article

  • Large Data Table with first column fixed

    - by bhavya_w
    I have structure as shown in the fiddle http://jsfiddle.net/5LN7U/. <section class="container"> <section class="field"> <ul> <li> Question 1 </li> <li> question 2 </li> <li> question 3 </li> <li> question 4 </li> <li> question 5 </li> <li> question 6 </li> <li> question 7 </li> </ul> </section> <section class="datawrap"> <section class="datawrapinner"> <ul> <li><b>Answer 1 :</b></li> <li><b>Answer 2 :</b></li> <li><b>Answer 3 :</b></li> <li><b>Answer 4 :</b></li> <li><b>Answer 5 :</b></li> <li><b>Answer 6 :</b></li> <li><b>Answer 7 :</b></li> </ul> </section> </section> </section> Basically its a table structure made using divs. The first column contains a long list of questions and the second column contains answers/multiple answers which can be quite big ( there has to be horizontal scrolling in the second column.) The problem i am facing is when i scroll downwards the second column which has the horizontal scroll bar is also scrolling downward. I want horizontal scrollbar to be fixed there. as in it should be always fixed there no matter how much i scroll vertically. Much Like Google Spreadsheets: where the first column stays fixed and there's horizontal scrolling on rest of the columns with over vertical scrolling for whole of the data. I cannot used position fixed in the second column. P.S : please no lectures on using div's for making a table structure. I have my own reasons. and its kinda urgent. Thanks in advance.

    Read the article

  • why do I need virtual table?

    - by lego69
    I was looking for some information about virtual table, but can't find something easy to understand, can somebody give me good example(not from Wiki, please), with explanations, or link, thanks in advance

    Read the article

  • SQL Server : copy data from one table to another

    - by Gladdy
    I want to update Table2 names with names from Table1 with matching Ids I have around 100 rows in each table. Here is my sample tables. Table1 ID Name Table2 ID Name Sample data Table1 ID |Name -------- 1 |abc 2 |bcd Table2 ID |Name -------- 1 |xyz 2 |OOS Expected result Table2 ID |Name -------- 1 |abc 2 |bcd How can I do this?

    Read the article

  • pyqt QTreeWidget setItemWidget dissapears after drag/drop

    - by mleep
    I'm trying to keep a widget put into a QTreeWidgetItem after a reparent (drag and drop) using QTreeWidget.setItemWidget() But the result, if you compile the following code - is that the widget inside the QTreeWidgetItem disappears. Any idea why? What code would fix this (repopulate the QTreeWidgetItem with the widget I guess?) from PyQt4.QtCore import * from PyQt4.QtGui import * class InlineEditor (QWidget): _MUTE = 'MUTE' def __init__ (self, parent): QWidget.__init__ (self, parent) self.setAutoFillBackground (True) lo = QHBoxLayout() lo.setSpacing(4) self._cbFoo = QComboBox() for x in ["ABC", "DEF", "GHI", "JKL"]: self._cbFoo.addItem(x) self._leBar = QLineEdit('', self) lo.addWidget (self._cbFoo, 3) lo.addSpacing (5) lo.addWidget (QLabel ( 'Bar:')) lo.addWidget (self._leBar, 3) lo.addStretch (5) self.setLayout (lo) class Form (QDialog): def __init__(self,parent=None): QDialog.__init__(self, parent) grid = QGridLayout () tree = QTreeWidget () # Here is the issue? tree.setDragDropMode(QAbstractItemView.InternalMove) tree.setColumnCount(3) for n in range (2): i = QTreeWidgetItem (tree) # create QTreeWidget the sub i i.setText (0, "first" + str (n)) # set the text of the first 0 i.setText (1, "second") for m in range (2): j = QTreeWidgetItem(i) j.setText (0, "child first" + str (m)) #b1 = QCheckBox("push me 0", tree) # this wont work w/ drag by itself either #tree.setItemWidget (tree.topLevelItem(0).child(1), 1, b1) item = InlineEditor(tree) # deal with a combination of multiple controls tree.setItemWidget(tree.topLevelItem(0).child(1), 1, item) grid.addWidget (tree) self.setLayout (grid) app = QApplication ([]) form = Form () form.show () app.exec_ ()

    Read the article

< Previous Page | 174 175 176 177 178 179 180 181 182 183 184 185  | Next Page >