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  • linked list sort function only loops once

    - by Tristan Pearce
    i have a singly linked list that i am trying to sort from least to greatest by price. here is what i have so far struct part { char* name; float price; int quantity; struct part *next; }; typedef struct part partType; partType *sort_price(partType **item) { partType *temp1 = *item; partType *temp2 = (*item)->next; if ( *item == NULL || (*item)->next == NULL ) return *item; else { while ( temp2 != NULL && temp2->next != NULL ){ if (temp2->price > temp2->next->price){ temp1->next = temp2->next; temp2->next = temp2->next->next; temp1->next->next = temp2; } temp1 = temp2; temp2 = temp2->next; } } return *item; } the list is already populated but when i call the sort function it only swaps the first two nodes that satisfy the condition in the if statement. I dont understand why it doesnt do the check again after the two temp pointers are incremented.

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  • Need to sort 3 arrays by one key array

    - by jeff6461
    I am trying to get 3 arrays sorted by one key array in objective c for the iphone, here is a example to help out... Array 1 Array 2 Array 3 Array 4 1 15 21 7 3 12 8 9 6 7 8 0 2 3 4 8 When sorted i want this to look like Array 1 Array 2 Array 3 Array 4 1 15 21 7 2 3 4 8 3 12 8 9 6 7 8 0 So array 2,3,4 are moving with Array 1 when sorted. Currently i am using a bubble sort to do this but it lags so bad that it crashes by app. The code i am using to do this is int flag = 0; int i = 0; int temp = 0; do { flag=1; for(i = 0; i < distancenumber; i++) { if(distance[i] > distance[i+1]) { temp = distance[i]; distance[i]=distance[i + 1]; distance[i + 1]=temp; temp = FlowerarrayNumber[i]; FlowerarrayNumber[i] = FlowerarrayNumber[i+1]; FlowerarrayNumber[i + 1] = temp; temp = BeearrayNumber[i]; BeearrayNumber[i] = BeearrayNumber[i + 1]; BeearrayNumber[i + 1] = temp; flag=0; } } }while (flag==0); where distance number is the amount of elements in all of the arrays, distance is array 1 or my key array. and the other 2 are getting sorted. If anyone can help me get a merge sort(or something faster, it is running on a iPhone so it needs to be quick and light) to do this that would be great i cannot figure out how the recursion works in this method and so having a hard time to get the code to work. Any help would be greatly appreciated

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  • bidirectional buble sort

    - by davit-datuashvili
    Here is the code I'm using for shacker sort (or bidirectional buble sort). Something is wrong; the error is java.lang.ArrayIndexOutOfBoundsException. Can anybody help me? public class bidirectional{ public static void main(String[]args){ int x[]=new int[]{12,9,4,99,120,1,3,10}; int j; int n=x.length; int st=-1; while (st<n){ st++; n--; for (j=st;j<n;j++) { if (x[j]>x[j+1]) { int t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } for (j=n;--j>=st;) { if (x[j]>x[j+1]) { int t=x[j]; x[j]=x[j+1]; x[j+1]=t; } } } for (int k=0;k<x.length;k++) { System.out.println(x[k]); } } }

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  • Sorting a Singly Linked List With Pointers

    - by Mark Simson
    I am trying to sort a singly linked list using bubble sort by manipulating ONLY the pointers, no keys. The following gets stuck in the for loop and loops infinitely. I don't understand why this is. Can anybody explain to me why the end of the list is not being found? Node* sort_list(Node* head) { Node * temp; Node * curr; for(bool didSwap = true; didSwap; ) { didSwap = false; for(curr = head; curr->next != NULL; curr = curr->next) { if(curr->key > curr->next->key) { temp = curr; curr = curr->next; curr->next = temp; didSwap = true; } cout << curr->next->key << endl; } } return head; } If I change the code so that the keys (data) are swapped, then the function works properly but for some reason I am not able make it work by manipulating only pointers.

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  • Sort multidimension array in php by more than two fields

    - by Ankita Agrawal
    I want to sort array by two fields. I mean to say I have an array like :- Array ( [0] => Array ( [name] => abc [url] => http://127.0.0.1/abc/img1.png [count] => 69 [img] => accessoire-sets_1.jpg ) [1] => Array ( [name] => abc2 [url] => http://127.0.0.1/abc/img12.png [count] => 73 [img] => ) [2] => Array ( [name] => abc45 [url] => http://127.0.0.1/abc/img122.png [count] => 15 [img] => tomahawk-kopen_1.png ) [3] => Array ( [name] => zyz [url] => http://127.0.0.1/abc/img22.png [count] => 168 [img] => ) [4] => Array ( [name] => lmn [url] => http://127.0.0.1/abc/img1222.png [count] => 10 [img] => ) [5] => Array ( [name] => qqq [url] => http://127.0.0.1/abc/img1222.png [count] => 70 [img] => ) [6] => Array ( [name] => dsa [url] => http://127.0.0.1/abc/img1112.png [count] => 43 [img] => ) [7] => Array ( [name] => wer [url] => http://127.0.0.1/abc/img172.png [count] => 228 [img] => ) [8] => Array ( [name] => hhh [url] => http://127.0.0.1/abc/img126.png [count] => 36 [img] => ) [9] => Array ( [name] => rrrt [url] => http://127.0.0.1/abc/img12.png [count] => 51 [img] => ) [10] => Array ( [name] => yyy [url] => http://127.0.0.1/abc/img12.png [count] => 22 [img] => ) [11] => Array ( [name] => cxz [url] => http://127.0.0.1/abc/img12.png [count] => 41 [img] => ) [12] => Array ( [name] => tre [url] => http://127.0.0.1/abc/img12.png [count] => 32 [img] => ) [13] => Array ( [name] => fds [url] => http://127.0.0.1/abc/img12.png [count] => 10 [img] => ) ) array WITHOUT images (field "img" )should always be placed underneath array WITH images. After this there will be sorted on the amount of products (field count) in the array. Means I have to show sort array first on the basis of img then count. I am using usort( $childLinkCats, 'sortempty' );` function sortempty( $a, $b ) { return empty( $a['img'] ); } it will show array with image value above the one who contains null value. and to sort through count Im using usort($childLinkCats, "_sortByCount"); function _sortByCount($a, $b) { return strnatcmp($a['count'], $b['count']); } It will short by count But I am facing problem that only 1 working is working at a time, but I have to use both, please help me.

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  • Android List View Drag and Drop sort

    - by miannelle
    I have a list of records in a listview that I want the user to be able to re-sort using a drag and drop method. I have seen this implemented in other apps, but I have not found a tutorial for it. It must be something that others need as well. Can anyone point me to some code for doing this?

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  • How to read a PS file in reverse order?

    - by Raja Reddy
    I have a PS file to be read in reverse order and process accordingly. Do we have a way to mention to read the file in reverse order in FD in COBOL module? OR do we have something to achieve the same using SORT? Note: Reading the records into a buffer (array) and using it in reverse order would be the first idea that comes to mind but that way doesnt work for file with millions of records. Your suggestions will be appreciated.

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  • Fastest gap sequence for shell sort ?

    - by Tony
    According to Marcin Ciura's Optimal (best known) sequence of increments for shell sort algorithm. The best sequence for shellsort is 1, 4, 10, 23, 57, 132, 301, 701... But how can I generate such a sequence ? In Marcin Ciura's paper he said : Both Knuth’s and Hibbard’s sequences are relatively bad, because they are defined by simple linear recurrences but most algorithm books I searched , they all tend to use Knuth’s sequence : k = 3k + 1 ; because it's easy to generate , what's your way of generating shellsort sequence ?

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  • How to sort a boxplot by the median values in pandas

    - by Chris
    I've got a dataframe outcome2 that I generate a grouped boxplot with in the following manner: In [11]: outcome2.boxplot(column='Hospital 30-Day Death (Mortality) Rates from Heart Attack',by='State') plt.ylabel('30 Day Death Rate') plt.title('30 Day Death Rate by State') Out [11]: What I'd like to do is sort the plot by the median for each state, instead of alphabetically. Not sure how to go about doing so.

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  • combine two arrays and sort

    - by Jun
    Given two arrays like the following: a = array([1,2,4,5,6,8,9]) b = array([3,4,7,10]) I would like the output to be: c = array([1,2,3,4,5,6,7,8,9,10]) or: c = array([1,2,3,4,4,5,6,7,8,9,10]) I'm aware that I can do the following: c = sort(unique(concatenate((a,b))) I'm just wondering if there is a faster way to do it as the arrays I'm dealing with have millions of elements. Any idea is welcomed. Thanks

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  • DRUPAL: order exposed filter items, be carefully it is not that simple (I cannot user "Sort")

    - by Patrick
    hi, DRUPAL question. I'm using Views, with an exposed filter (Taxonomy). I've downloaded the "better exposed filter" module to display it as checkbox list. a Now, how can I order the tags in the filter list ? "Views Sort" is not the solution because I only can order articles but not the filter items!! I want to add an option (checkbox) for the customer to order the tags alphabetically or leave them in the default order. thanks

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  • UITableView reloadData to sort the table cells

    - by harekam_taj
    Hey Guys, I have a uitableview and I am populating the tableview with data from the internet. I added some sort features to the table but when I do the sorting and get new results from the web server and reload the table. The table doesn't refresh, the old results stay on the table and if I press on a particular cell I see the new result just for that cell. Can someone please help me? Thanks

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  • Silverlight DataGrid's sort by column doesn't update programmatically changed cells

    - by David Seiler
    For my first Silverlight app, I've written a program that sends user-supplied search strings to the Flickr REST API and displays the results in a DataGrid. Said grid is defined like so: <data:DataGrid x:Name="PhotoGrid" AutoGenerateColumns="False"> <data:DataGrid.Columns> <data:DataGridTextColumn Header="Photo Title" Binding="{Binding Title}" CanUserSort="True" CanUserReorder="True" CanUserResize="True" IsReadOnly="True" /> <data:DataGridTemplateColumn Header="Photo" SortMemberPath="ImageUrl"> <data:DataGridTemplateColumn.CellTemplate> <DataTemplate> <StackPanel Orientation="Horizontal" VerticalAlignment="Center"> <TextBlock Text="Click here to show image" MouseLeftButtonUp="ShowPhoto"/> <Image Visibility="Collapsed" MouseLeftButtonUp="HidePhoto"/> </StackPanel> </DataTemplate> </data:DataGridTemplateColumn.CellTemplate> </data:DataGridTemplateColumn> </data:DataGrid.Columns> </data:DataGrid> It's a simple two-column table. The first column contains the title of the photo, while the second contains the text 'Click here to show image'. Clicks there call ShowPhoto(), which updates the Image element's Source property with a BitmapImage derived from the URI of the Flickr photo, and sets the image's visibility to Visible. Clicking on the image thus revealed hides it again. All of this was easy to implement and works perfectly. But whenever I click on one of the column headers to sort by that column, the cells that I've updated in this way do not change. The rest of the DataGrid is resorted and updated appropriately, but those cells remain behind, detached from the rest of their row. This is very strange, and not at all what I want. What am I doing wrong? Should I be freshening the DataGrid somehow in response to the sort event, and if so how? Or if I'm not supposed to be messing with the contents of the grid directly, what's the right way to get the behavior I want?

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  • How to build, sort and print a tree of a sort?

    - by Tuplanolla
    This is more of an algorithmic dilemma than a language-specific problem, but since I'm currently using Ruby I'll tag this as such. I've already spent over 20 hours on this and I would've never believed it if someone told me writing a LaTeX parser was a walk in the park in comparison. I have a loop to read hierarchies (that are prefixed with \m) from different files art.tex: \m{Art} graphical.tex: \m{Art}{Graphical} me.tex: \m{About}{Me} music.tex: \m{Art}{Music} notes.tex: \m{Art}{Music}{Sheet Music} site.tex: \m{About}{Site} something.tex: \m{Something} whatever.tex: \m{Something}{That}{Does Not}{Matter} and I need to sort them alphabetically and print them out as a tree About Me (me.tex) Site (site.tex) Art (art.tex) Graphical (graphical.tex) Music (music.tex) Sheet Music (notes.tex) Something (something.tex) That Does Not Matter (whatever.tex) in (X)HTML <ul> <li>About</li> <ul> <li><a href="me.tex">Me</a></li> <li><a href="site.tex">Site</a></li> </ul> <li><a href="art.tex">Art</a></li> <ul> <li><a href="graphical.tex">Graphical</a></li> <li><a href="music.tex">Music</a></li> <ul> <li><a href="notes.tex">Sheet Music</a></li> </ul> </ul> <li><a href="something.tex">Something</a></li> <ul> <li>That</li> <ul> <li>Doesn't</li> <ul> <li><a href="whatever.tex">Matter</a></li> </ul> </ul> </ul> </ul> using Ruby without Rails, which means that at least Array.sort and Dir.glob are available. All of my attempts were formed like this (as this part should work just fine). def fss_brace_array(ss_input)#a concise version of another function; converts {1}{2}...{n} into an array [1, 2, ..., n] or returns an empty array ss_output = ss_input[1].scan(%r{\{(.*?)\}}) rescue ss_output = [] ensure return ss_output end #define tree s_handle = File.join(:content.to_s, "*") Dir.glob("#{s_handle}.tex").each do |s_handle| File.open(s_handle, "r") do |f_handle| while s_line = f_handle.gets if s_all = s_line.match(%r{\\m\{(\{.*?\})+\}}) s_all = s_all.to_a #do something with tree, fss_brace_array(s_all) and s_handle break end end end end #do something else with tree

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  • tableSorter limitation (sort) one page at a time?

    - by Abu Hamzah
    i see that in tableSorter you can sort one page at a time which concerns me. Only 1 page of results can be sorted at a time?, which is pretty limiting. If you have a query result that spans multiple pages, how you will handle this? If anyone knows better, feel free to correct me if iam incorrect Thanks.

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  • How to sort my paws?

    - by Ivo Flipse
    In my previous question I got an excellent answer that helped me detect where a paw hit a pressure plate, but now I'm struggling to link these results to their corresponding paws: I manually annotated the paws (RF=right front, RH= right hind, LF=left front, LH=left hind). As you can see there's clearly a pattern repeating pattern and it comes back in aknist every measurement. Here's a link to a presentation of 6 trials that were manually annotated. My initial thought was to use heuristics to do the sorting, like: There's a ~60-40% ratio in weight bearing between the front and hind paws; The hind paws are generally smaller in surface; The paws are (often) spatially divided in left and right. However, I’m a bit skeptical about my heuristics, as they would fail on me as soon as I encounter a variation I hadn’t thought off. They also won’t be able to cope with measurements from lame dogs, whom probably have rules of their own. Furthermore, the annotation suggested by Joe sometimes get's messed up and doesn't take into account what the paw actually looks like. Based on the answers I received on my question about peak detection within the paw, I’m hoping there are more advanced solutions to sort the paws. Especially because the pressure distribution and the progression thereof are different for each separate paw, almost like a fingerprint. I hope there's a method that can use this to cluster my paws, rather than just sorting them in order of occurrence. So I'm looking for a better way to sort the results with their corresponding paw. For anyone up to the challenge, I have pickled a dictionary with all the sliced arrays that contain the pressure data of each paw (bundled by measurement) and the slice that describes their location (location on the plate and in time). To clarfiy: walk_sliced_data is a dictionary that contains ['ser_3', 'ser_2', 'sel_1', 'sel_2', 'ser_1', 'sel_3'], which are the names of the measurements. Each measurement contains another dictionary, [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10] (example from 'sel_1') which represent the impacts that were extracted. Also note that 'false' impacts, such as where the paw is partially measured (in space or time) can be ignored. They are only useful because they can help recognizing a pattern, but won't be analyzed. And for anyone interested, I’m keeping a blog with all the updates regarding the project!

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  • How can I sort timestamps in perl ?

    - by ablimit
    I have several thousand objects with string property in the format of "yyyy-MM-ddTHH:mm:ssZ". I want to sort these objects ordered by time. Is there any useful packages or scripts for this ? (currently I'm just comparing individual numeric values and it seems it's not very efficient and neat)

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  • best way to find similar items in python

    - by user230911
    I have 1M numbers:N[], and 1 single number n, now I want to find in those 1M numbers that are similar to that single number, say an area of [n-10, n+10]. what's the best way in python to do this? Do I have to sort the 1M number and do an iteration? Thanks

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