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• South migration error: NoMigrations exception for django.contrib.auth

  - by danpalmer

  I have been using South on my project for a while, but I recently did a huge amount of development and changed development machine and I think something messed up in the process. The project works fine, but I can't apply migrations. Whenever I try to apply a migration I get the following traceback: danpalmer:pest Dan$ python manage.py migrate frontend Traceback (most recent call last): File "manage.py", line 11, in <module> execute_manager(settings) File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 362, in execute_manager utility.execute() File "/Library/Python/2.6/site-packages/django/core/management/__init__.py", line 303, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 195, in run_from_argv self.execute(*args, **options.__dict__) File "/Library/Python/2.6/site-packages/django/core/management/base.py", line 222, in execute output = self.handle(*args, **options) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/management/commands/migrate.py", line 102, in handle delete_ghosts = delete_ghosts, File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/__init__.py", line 182, in migrate_app applied = check_migration_histories(applied, delete_ghosts) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/__init__.py", line 85, in check_migration_histories m = h.get_migration() File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/models.py", line 34, in get_migration return self.get_migrations().migration(self.migration) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/models.py", line 31, in get_migrations return Migrations(self.app_name) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 60, in __call__ self.instances[app_label] = super(MigrationsMetaclass, self).__call__(app_label_to_app_module(app_label), **kwds) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 88, in __init__ self.set_application(application, force_creation, verbose_creation) File "/Library/Python/2.6/site-packages/South-0.7-py2.6.egg/south/migration/base.py", line 159, in set_application raise exceptions.NoMigrations(application) south.exceptions.NoMigrations: Application '<module 'django.contrib.auth' from '/Library/Python/2.6/site-packages/django/contrib/auth/__init__.pyc'>' has no migrations. I am not that experienced with South and I haven't met this error before. The only helpful mention I can find online about this error is for pre-0.7 I think and I am on South 0.7. I ran 'easy_install -U South' just to make sure. Thanks for any help that you can provide. I really appreciate it.

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• Django App for Image heavy Magazine Publishing?

  - by stapler

  I'm about to begin work on a Django project for an image heavy non-profit "community arts" magazine. The magazine is published monthly with about 6-8 articles that include with 4-10 images. I've been looking around for other projects that people have started specifically for publishing in Django... Are there any publishing specific Django apps you'd recommend? At the moment the only thing I can find is django-newsroom which looks interesting. Currently I'm just Image Kit / Photologue to attach galleries to an Article Model... but I'd love to figure out a way to more fully integrate images into the article content. Thanks in advance

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• Django CMS error when running project

  - by 47

  I'd set up a site a while back using Django-CMS and it was working fine. However, after upgrading to the latest version of both Django and Django-CMS, it doesn't work anymore...when I try to run the development server, I get this message: "Signal recerivers must accept keyword arguments (**kwargs)." AssertionError: Signal receivers must accept keyword arguments (**kwargs). What could be the problem here? I've tried running the sample app that comes with the CMS and it works just fine.

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• Why can't I use __getattr__ with Django models?

  - by Joshmaker

  I've seen examples online of people using __getattr__ with Django models, but whenever I try I get errors. (Django 1.2.3) I don't have any problems when I am using __getattr__ on normal objects. For example: class Post(object): def __getattr__(self, name): return 42 Works just fine... >>> from blog.models import Post >>> p = Post() >>> p.random 42 Now when I try it with a Django model: from django.db import models class Post(models.Model): def __getattr__(self, name): return 42 And test it on on the interpreter: >>> from blog.models import Post >>> p = Post() ERROR: An unexpected error occurred while tokenizing input The following traceback may be corrupted or invalid The error message is: ('EOF in multi-line statement', (6, 0)) --------------------------------------------------------------------------- TypeError Traceback (most recent call last) /Users/josh/project/ in () /Users/josh/project/lib/python2.6/site-packages/django/db/models/base.pyc in init(self, *args, **kwargs) 338 if kwargs: 339 raise TypeError("'%s' is an invalid keyword argument for this function" % kwargs.keys()[0]) -- 340 signals.post_init.send(sender=self.class, instance=self) 341 342 def repr(self): /Users/josh/project/lib/python2.6/site-packages/django/dispatch/dispatcher.pyc in send(self, sender, **named) 160 161 for receiver in self._live_receivers(_make_id(sender)): -- 162 response = receiver(signal=self, sender=sender, **named) 163 responses.append((receiver, response)) 164 return responses /Users/josh/project/python2.6/site-packages/photologue/models.pyc in add_methods(sender, instance, signal, *args, **kwargs) 728 """ 729 if hasattr(instance, 'add_accessor_methods'): -- 730 instance.add_accessor_methods() 731 732 # connect the add_accessor_methods function to the post_init signal TypeError: 'int' object is not callable Can someone explain what is going on? EDIT: I may have been too abstract in the examples, here is some code that is closer to what I actually would use on the website: class Post(models.Model): title = models.CharField(max_length=255) slug = models.SlugField() date_published = models.DateTimeField() content = RichTextField('Content', blank=True, null=True) # Etc... Class CuratedPost(models.Model): post = models.ForeignKey('Post') position = models.PositiveSmallIntegerField() def __getattr__(self, name): ''' If the user tries to access a property of the CuratedPost, return the property of the Post instead... ''' return self.post.name # Etc... While I could create a property for each attribute of the Post class, that would lead to a lot of code duplication. Further more, that would mean anytime I add or edit a attribute of the Post class I would have to remember to make the same change to the CuratedPost class, which seems like a recipe for code rot.

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• Syncing data between devel/live databases in Django

  - by T. Stone

  With Django's new multi-db functionality in the development version, I've been trying to work on creating a management command that let's me synchronize the data from the live site down to a developer machine for extended testing. (Having actual data, particularly user-entered data, allows me to test a broader range of inputs.) Right now I've got a "mostly" working command. It can sync "simple" model data but the problem I'm having is that it ignores ManyToMany fields which I don't see any reason for it do so. Anyone have any ideas of either how to fix that or a better want to handle this? Should I be exporting that first query to a fixture first and then re-importing it? from django.core.management.base import LabelCommand from django.db.utils import IntegrityError from django.db import models from django.conf import settings LIVE_DATABASE_KEY = 'live' class Command(LabelCommand): help = ("Synchronizes the data between the local machine and the live server") args = "APP_NAME" label = 'application name' requires_model_validation = False can_import_settings = True def handle_label(self, label, **options): # Make sure we're running the command on a developer machine and that we've got the right settings db_settings = getattr(settings, 'DATABASES', {}) if not LIVE_DATABASE_KEY in db_settings: print 'Could not find "%s" in database settings.' % LIVE_DATABASE_KEY return if db_settings.get('default') == db_settings.get(LIVE_DATABASE_KEY): print 'Data cannot synchronize with self. This command must be run on a non-production server.' return # Fetch all models for the given app try: app = models.get_app(label) app_models = models.get_models(app) except: print "The app '%s' could not be found or models could not be loaded for it." % label for model in app_models: print 'Syncing %s.%s ...' % (model._meta.app_label, model._meta.object_name) # Query each model from the live site qs = model.objects.all().using(LIVE_DATABASE_KEY) # ...and save it to the local database for record in qs: try: record.save(using='default') except IntegrityError: # Skip as the record probably already exists pass

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• Django internationalization for admin pages - translate model name and attributes

  - by geekQ

  Django's internationalization is very nice (gettext based, LocaleMiddleware), but what is the proper way to translate the model name and the attributes for admin pages? I did not find anything about this in the documentation: http://docs.djangoproject.com/en/dev/topics/i18n/internationalization/ http://www.djangobook.com/en/2.0/chapter19/ I would like to have "???????? ????? ??? ?????????" instead of "???????? order ??? ?????????". Note, the 'order' is not translated. First, I defined a model, activated USE_I18N = True in settings.py, run django-admin makemessages -l ru. No entries are created by default for model names and attributes. Grepping in the Django source code I found: $ ack "Select %s to change" contrib/admin/views/main.py 70: self.title = (self.is_popup and ugettext('Select %s') % force_unicode(self.opts.verbose_name) or ugettext('Select %s to change') % force_unicode(self.opts.verbose_name)) So the verbose_name meta property seems to play some role here. Tried to use it: class Order(models.Model): subject = models.CharField(max_length=150) description = models.TextField() class Meta: verbose_name = _('order') Now the updated po file contains msgid 'order' that can be translated. So I put the translation in. Unfortunately running the admin pages show the same mix of "???????? order ??? ?????????". I'm currently using Django 1.1.1. Could somebody point me to the relevant documentation? Because google can not. ;-) In the mean time I'll dig deeper into the django source code...

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• django forms- register user script

  - by itsandy

  Hi all, I want to make something like http://www.djangosnippets.org/accounts/register/ using django..the register form. I am new to django. i have made a simple view form using django forms but unable o understand how to connect my form to a database. Im using postgresql. is there an easy way to use some snippet or script to achieve this. Please Help

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• Django admin interface upload failing on request data read error

  - by Jake

  Hi All, This is an updated version of an old question I asked. I've now done a lot more testing, plus the old question got hijacked. I'm getting a request data read error when trying to upload files to the Django admin interface. Files under about 150k work, but bigger files always fail and almost always at around 192k (that's 3 chunks) completed, sometimes at around 160k. The Exception I get is below. File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 405, in read return self._file.read(num_bytes) IOError: request data read error I've tried Chrome and Firefox on Windows and Firefox on Mac - Same results. I can upload to other sites so I don't think it's my connection. I'm running python 2.4, django 1.1, mod_wsgi, on CentOS (a media temple DV server) Locally it's fine (Django development server) Everything I've found on this issue says it's a mod_python issue and that changing to mod_wsgi will fix it, but I am running mod_wsgi. Can anyone help?

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• Using Models and Forms outside of Django?

  - by RadiantHex

  Is it possible to run a view file using Django Model and Form outside of the Django environment?

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• Django 1.2 Equivalent of QuerySet.query.as_sql()

  - by Zach

  In Django 1.1 I was able to produce the SQL used by a QuerySet with this notation: QuerySet.query.as_sql() In Django 1.2, this raises as AttributeError. Anyone know the Django 1.2 equivalent of that method? Thanks

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• Writing good tests for Django applications

  - by Ludwik Trammer

  I've never written any tests in my life, but I'd like to start writing tests for my Django projects. I've read some articles about tests and decided to try to write some tests for an extremely simple Django app or a start. The app has two views (a list view, and a detail view) and a model with four fields: class News(models.Model): title = models.CharField(max_length=250) content = models.TextField() pub_date = models.DateTimeField(default=datetime.datetime.now) slug = models.SlugField(unique=True) I would like to show you my tests.py file and ask: Does it make sense? Am I even testing for the right things? Are there best practices I'm not following, and you could point me to? my tests.py (it contains 11 tests): # -*- coding: utf-8 -*- from django.test import TestCase from django.test.client import Client from django.core.urlresolvers import reverse import datetime from someproject.myapp.models import News class viewTest(TestCase): def setUp(self): self.test_title = u'Test title: bareksc' self.test_content = u'This is a content 156' self.test_slug = u'test-title-bareksc' self.test_pub_date = datetime.datetime.today() self.test_item = News.objects.create( title=self.test_title, content=self.test_content, slug=self.test_slug, pub_date=self.test_pub_date, ) client = Client() self.response_detail = client.get(self.test_item.get_absolute_url()) self.response_index = client.get(reverse('the-list-view')) def test_detail_status_code(self): """ HTTP status code for the detail view """ self.failUnlessEqual(self.response_detail.status_code, 200) def test_list_status_code(self): """ HTTP status code for the list view """ self.failUnlessEqual(self.response_index.status_code, 200) def test_list_numer_of_items(self): self.failUnlessEqual(len(self.response_index.context['object_list']), 1) def test_detail_title(self): self.failUnlessEqual(self.response_detail.context['object'].title, self.test_title) def test_list_title(self): self.failUnlessEqual(self.response_index.context['object_list'][0].title, self.test_title) def test_detail_content(self): self.failUnlessEqual(self.response_detail.context['object'].content, self.test_content) def test_list_content(self): self.failUnlessEqual(self.response_index.context['object_list'][0].content, self.test_content) def test_detail_slug(self): self.failUnlessEqual(self.response_detail.context['object'].slug, self.test_slug) def test_list_slug(self): self.failUnlessEqual(self.response_index.context['object_list'][0].slug, self.test_slug) def test_detail_template(self): self.assertContains(self.response_detail, self.test_title) self.assertContains(self.response_detail, self.test_content) def test_list_template(self): self.assertContains(self.response_index, self.test_title)

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• AddThis Social SignIn and Django

  - by piokuc

  I am developing a Django website. I've been using django-registration for user registration so far but I would really like to allow users to login to my site using their Facebook, Twitter, Google, etc accounts. I am using addthis sharing buttons. I just noticed they introduced a social sign in solution. The idea seems great, you integrate your authentication system with their service once, and your users can login via all of the popular social networking sites. Has anybody integrated addthis social signin plugin with a django website? How can you use it along side django-registration? Are there any similar, alternative solutions?

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• Django admin output extra HTML in ModelSite

  - by VoteyDisciple

  Ultimately, I want to add an <iframe> to the display of a particular model on Django's admin page. Django is already rendering the form for this model correctly, but I want to add this <iframe> in addition to Django's form. The src attribute needs to involve the primary key for the currently-displayed record. I've learned how to properly override the change_form.html template through Django's documentation, and I can add markup to the right block, but I can't figure out how to access the primary key value. (No amount of determined Googling has helped at all.) Alternatively, is there a direct way to specify that I want to produce extra output in my ModelSite definition?

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• Problem with anchor tags in Django after using lighttpd + fastcgi

  - by Drew A

  I just started using lighttpd and fastcgi for my django site, but I've noticed my anchor links are no longer working. I used the anchor links for sorting links on the page, for example I use an anchor to sort links by the number of points (or votes) they have received. For example: the code in the html template: ... {% load sorting_tags %} ... {% ifequal sort_order "points" %} {% trans "total points" %} {% trans "or" %} {% anchor "date" "date posted" %} {% order_by_votes links request.direction %} {% else %} {% anchor "points" "total points" %} {% trans "or" %} {% trans "date posted" %} ... The anchor link on "www.mysite.com/my_app/" for total points will be directed to "my_app/?sort=points" But the correct URL should be "www.mysite.com/my_app/?sort=points" All my other links work, the problem is specific to anchor links. The {% anchor %} tag is taken from django-sorting, the code can be found at http://github.com/directeur/django-sorting Specifically in django-sorting/templatetags/sorting_tags.py Thanks in advance.

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• csrf error in django

  - by niklasfi

  Hello, I want to realize a login for my site. I basically copied and pasted the following bits from the Django Book together. However I still get an error (CSRF verification failed. Request aborted.), when submitting my registration form. Can somebody tell my what raised this error and how to fix it? Here is my code: views.py: # Create your views here. from django import forms from django.contrib.auth.forms import UserCreationForm from django.http import HttpResponseRedirect from django.shortcuts import render_to_response def register(request): if request.method == 'POST': form = UserCreationForm(request.POST) if form.is_valid(): new_user = form.save() return HttpResponseRedirect("/books/") else: form = UserCreationForm() return render_to_response("registration/register.html", { 'form': form, }) register.html: <html> <body> {% block title %}Create an account{% endblock %} {% block content %} <h1>Create an account</h1> <form action="" method="post">{% csrf_token %} {{ form.as_p }} <input type="submit" value="Create the account"> </form> {% endblock %} </body> </html>

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• Django URL Conf Returns Incorrect "Current URL"

  - by natnit

  I have a django app that is mostly done, and the URLs work perfectly when I run it with the manage.py runserver command. However, I've recently tried to get it running via lighttpd, and many links have stopped working. For example: http://mysite.com/races/32 should work, but instead throws this error message. Page not found (404) Request Method: GET Request URL: http://mysite.com/races/32 Using the URLconf defined in racetrack.urls, Django tried these URL patterns, in this order: ^admin/ ^create/$ ^races/$ ^races/(?P<race_id>\d+)/$ ^races/(?P<race_id>\d+)/manage/$ ^races/(?P<text>\w+)/$ ^user/(?P<kol_id>\d+)/$ ^$ ^login/$ ^logout/$ The current URL, 32, didn't match any of these. The request URL is accurate, but the last line (which displays the current URL) is giving 32 instead of races/32 as expected. Here is my urlconf: from django.conf.urls.defaults import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('racetrack.races.views', (r'^admin/', include(admin.site.urls)), (r'^create/$', 'create'), (r'^races/$', 'index'), (r'^races/(?P<race_id>\d+)/$', 'detail'), (r'^races/(?P<race_id>\d+)/manage/$', 'manage'), (r'^races/(?P<text>\w+)/$', 'index'), (r'^user/(?P<kol_id>\d+)/$', 'user'), # temporary for index page replace with welcome page (r'^$', 'index'), ) urlpatterns += patterns('django.contrib.auth.views', (r'^login/$', 'login', {'template_name': 'races/login.html'}), (r'^logout/$', 'logout', {'next_page': '/'}), ) Thank you.

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• Doing a count over a filter query efficiently in django

  - by apple_pie

  Hello, Django newbie here, I need to do a count over a certain filter in a django model. If I do it like so: my_model.objects.filter(...).count() I'm guessing it does the SQL query that retrieves all the rows and only afterwards does the count. To my knowledge it's much more efficient to do the count without retrieving those rows like so "SELECT COUNT(*) FROM ...". Is there a way to do so in django?

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• customizing Django look and feel in Python

  - by user248237

  I am learning Django and got it to work with wsgi. I'm following the tutorial here: http://docs.djangoproject.com/en/1.1/intro/tutorial01/ My question is: how can I customize the look and feel of Django? Is there a repository of templates that "look good", kind of like there are for Wordpress, that I can start from? I find the tutorial counterintuitive in that it goes immediately toward customizing the admin page of Django, rather than the main pages visible to users of the site. Is there an example of a "typical" Django site, with a decent template, that I can look at and built on/modify? The polls application is again not very representative since it's so specialized. any references on this would be greatly appreciated. thanks.

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• how to extract all permissions that a domain user have on the network

  - by Alexandre Jobin

  I would like to know all the permissions a windows domain user have in my network. Is there a way, with a script file or a tool, that can extract this kind of information by checking all the servers and computers in my network? I'm on a Microsoft network with Windows Server 2008 R2, Windows XP, Windows 7. The report should include these kind of informations: report all permissions that the domain user have (read, write, etc...) if the domain user is in a domain group, tell me the permissions that this group have in my network so the report could be something like this: Permissions for USER_A in the DOMAIN.COM the user is part of theses domain groups: GROUP_A GROUP_B SERVER_A W:\wwwRoot (R/W inherited from GROUP_A) W:\sharedFolder (R) SERVER_B c:\projects (R/W) c:\projects\project_a (R/W) c:\projects\project_b (R/W) c:\dumpfolder (R/W inherited from GROUP_B) COMPUTER_A LOCAL\Administrator c:\ (R/W)

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• All my files uploaded have unusable permissions

  - by cosmicbdog

  I've just moved to a new server and have come across some strange permissions issues. Every file I upload has permissions of 600, owned by the user account and is also in the same group. With this permission, the server is unable to make changes to these files. The folder I'm uploading to (via regular ftp) has permissions of 755. Why are any new files I upload here given this permission of 600? And how do I change it so that files added are given permissions so they can be modified by the webserver?

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• What linux permissions are need for www?

  - by Xeoncross

  I know that 777 is full read/write/execute permission for owner/group/other. So this doesn't seem to be needed as it leaves random users full permissions. What permissions are need to be used on /var/www so that... Source control like git or svn Normal users in a group like "websites" or added to "www-data" Servers like apache or lighthttpd And PHP/Perl/Ruby can all read, create, and run files there? If I'm correct, Ruby and PHP scripts are not "executed" directly - but passed to an interpreter. So there is no need for execute permission on files in /var/www. Therefore, it seems like the correct permission would be chmod -R 1660 which would make all files shareable by these four entities all files non-executable by mistake block everyone else from the directory entirely set the permission mode to "sticky" for all future files Is this correct? Update: I just realized that files and directories might need different permissions - I was talking about files above so i'm not sure what the directory permissions would need to be.

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• Windows Shares / NTFS permissions on folder redirection in Active Directory

  - by Shawn Gradwell

  A client has folder redirection in AD setup on each user's Home Folder set to the Z:\ drive as \server\share\username. A Group Policy redirects the user's Documents to the user's Home Folder with the option 'Grant the user to exclusive rights to Documents' selected. The share on the server has permissions for the relevant user security group with 'Full Control', but each user's folder only have NTFS permissions only for 'CREATOR OWNER' and 'Domain Admins'. Why can the different users access other user's folders? I thought the most restrictive permissions applied effectively between the share and the NTFS permissions. Also, this setup has been like this for years, and this client recently updated all client computers to Windows 7. What is the best way to setup this redirection now? I assume only in Group Policy, also Basic Redirection - to create a folder for each user under the root path?

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• NTFS permissions weird inheriance (second take!)

  - by Wil

  A complete re write of my previous question, in a different context. Basically, the issue is that when I create a new user within a new group, the new user has various permissions over various folders. I have deleted the group "users" from this user object, and it is simply a member of the group "test". I have created a folder called c:\foo, when I go to effective permissions under the security tab, I can see that the user "lockdown" has various permissions. As far as I can see, there is nothing that should allow lockdown access. The moment I remove users from this list, it behaves as I would expect, which makes me believe that for some strange reason, the users group behaves like the everyone group and is controlled by the system. That being said, I cannot understand this as under the list, it is not there - and further to this, with the same permissions as the first picture, guest does not have access. This has stumped me and any help is appreciated! (Tested in Windows 2003 and 2008) edit - Should also say that if I go to Effective Permission for the group the user is in, there are no boxes checked, so it is somehow just the user that is getting the permissions from somewhere.

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• Improved ACL editor for Windows file permissions

  - by Myrddin Emrys

  I have recently been doing a lot of updates to our network drive permissions... such as consolidating direct user permissions into group permissions. The built-in ACL editor (Advanced Security Settings dialog) is adequate, but its limitations are frustrating, particularly that it cannot be resized and you cannot look at the list of existing entries at the same time as you are adding a new entry. Is there an improved ACL editor that can be downloaded to supplement the default one?

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• SQL Server NETWORK SERVICE account permissions

  - by RemotecUk

  My SQL Server Windows service is set to use the NETWORK SERVICE account. The server is installed to C:\Program Files\Microsoft SQL Server\MSSQL10_50.MSSQLSERVER\MSSQL. However looking at the permissions on that folder, NETWORK SERVICE does not have any permissions. The groups which are allowed access to that folder are... CREATOR OWNER - who is this? SYSTEM - sounds fine - so that Windows can access the folder I presume? SQLServerMSSQLUser$Computer_Name$MSSQLSERVER - this is the interesting one - what is this? Administrators Users If NETWORK SERVICE is a user with minimal permissions on the system and looks to the O/S as someone connecting from a network how does it have permissions to access any files in the SQL Server install folder? Thanks.

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