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  • Update MySQL table using data from a text file through Java

    - by Karthi Karthi
    I have a text file with four lines, each line contains comma separated values like below file My file is: Raj,[email protected],123455 kumar,[email protected],23453 shilpa,[email protected],765468 suraj,[email protected],876567 and I have a MySQL table which contains four fields firstname lastname email phno ---------- ---------- --------- -------- Raj babu [email protected] 2343245 kumar selva [email protected] 23453 shilpa murali [email protected] 765468 suraj abd [email protected] 876567 Now I want to update my table using the data in the above text file through Java. I have tried using bufferedReader to read from the file and used split method using comma as delimiter and stored it in array. But it is not working. Any help appreciated. This is what I have tried so far void readingFile() { try { File f1 = new File("TestFile.txt"); FileReader fr = new FileReader(f1); BufferedReader br = new BufferedReader(fr); String strln = null; strln = br.readLine(); while((strln=br.readLine())!=null) { // System.out.println(strln); arr = strln.split(","); strfirstname = arr[0]; strlastname = arr[1]; stremail = arr[2]; strphno = arr[3]; System.out.println(strfirstname + " " + strlastname + " " + stremail +" "+ strphno); } // for(String i : arr) // { // } br.close(); fr.close(); } catch(IOException e) { System.out.println("Cannot read from File." + e); } try { st = conn.createStatement(); String query = "update sampledb set email = stremail,phno =strphno where firstname = strfirstname "; st.executeUpdate(query); st.close(); System.out.println("sampledb Table successfully updated."); } catch(Exception e3) { System.out.println("Unable to Update sampledb table. " + e3); } } and the output i got is: Ganesh Pandiyan [email protected] 9591982389 Dass Jeyan [email protected] 9689523645 Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1 Gowtham Selvan [email protected] 9894189423 at TemporaryPackages.FileReadAndUpdateTable.readingFile(FileReadAndUpdateTable.java:35) at TemporaryPackages.FileReadAndUpdateTable.main(FileReadAndUpdateTable.java:72) Java Result: 1 @varadaraj: This is the code of yours.... String stremail,strphno,strfirstname,strlastname; // String[] arr; Connection conn; Statement st; void readingFile() { try { BufferedReader bReader= new BufferedReader(new FileReader("TestFile.txt")); String fileValues; while ((fileValues = bReader.readLine()) != null) { String[] values=fileValues .split(","); strfirstname = values[0]; // strlastname = values[1]; stremail = values[1]; strphno = values[2]; System.out.println(strfirstname + " " + strlastname + " " + stremail +" "+ strphno); } bReader.close(); } catch (IOException e) { System.out.println("File Read Error"); } // for(String i : arr) // { // } try { st = conn.createStatement(); String query = "update sampledb set email = stremail,phno =strphno where firstname = strfirstname "; st.executeUpdate(query); st.close(); System.out.println("sampledb Table successfully updated."); } catch(Exception e3) { System.out.println("Unable to Update sampledb table. " + e3); } }

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  • dynamically drawing polylines on googlemaps using php/mysql

    - by arc
    Hi. I am new to the googlemaps API. I have written a small app for my mobile phone that periodically updates its location to an SQL databse. I would like to display this information on a googlemap in my browser. Ideally i'd like to then poll the database periodically and if any new co-ords have arrived, add them to the line. Best way of describing it is this; http://tiny.cc/HEIa0 In a quest to get to there, i've started on the documents on google and been modifying them to try and acheive what I want. It doesn't work - and i don't know enough to know why. I would love some advice as to why, and any pointers towards my ultimate goal would be very much welcomed. Google Maps AJAX + MySQL/PHP Example <script type="text/javascript"> //<![CDATA[ function load() { if (GBrowserIsCompatible()) { var map = new GMap2(document.getElementById("map")); map.addControl(new GSmallMapControl()); map.addControl(new GMapTypeControl()); map.setCenter(new GLatLng(47.614495, -122.341861), 13); GDownloadUrl("phpsqlajax_genxml.php", function(data) { var xml = GXml.parse(data); var line = []; var markers = xml.documentElement.getElementsByTagName("points"); for (var i = 0; i < points.length; i++) { var point = points.item(i); var lat = point.getAttribute("lat"); var lng = point.getAttribute("lng"); var latlng = new GLatLng(lat, lng); line.push(latlng); if (point.firstChild) { var station = point.firstChild.nodeValue; var marker = createMarker(latlng, station); map.addOverlay(marker); } } var polyline = new GPolyline(line, "#ff0000", 3, 1); map.addOverlay(polyline); }); } //]]> My php file is generating the following XML; <?xml version="1.0" encoding="UTF-8" ?> <points> <point lng="-122.340141" lat="47.608940"/> <point lng="-122.344391" lat="47.613590"/> <point lng="-122.356445" lat="47.624561"/> <point lng="-122.337654" lat="47.606365"/> <point lng="-122.345673" lat="47.612823"/> <point lng="-122.340363" lat="47.605961"/> <point lng="-122.345467" lat="47.613976"/> <point lng="-122.326584" lat="47.617214"/> <point lng="-122.342834" lat="47.610126"/> </points> I have successfully worked through this; http://code.google.com/apis/maps/articles/phpsqlajax.html before attempting to customise the code. Any pointers? Where am I go wrong?

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  • mySQL to XLS using PHP?

    - by kielie
    Hi guys, how can I create a .XLS document from a mySQL table using PHP? I have tried just about everything, with no success. Basically, I need to take form data, and input it into a database, which I have done, and then I need to retrieve that table data and parse it into a microsoft excel file, which needs to be saved automatically onto the web server. <?php // DB TABLE Exporter // // How to use: // // Place this file in a safe place, edit the info just below here // browse to the file, enjoy! // CHANGE THIS STUFF FOR WHAT YOU NEED TO DO $dbhost = "-"; $dbuser = "-"; $dbpass = "-"; $dbname = "-"; $dbtable = "-"; // END CHANGING STUFF $cdate = date("Y-m-d"); // get current date // first thing that we are going to do is make some functions for writing out // and excel file. These functions do some hex writing and to be honest I got // them from some where else but hey it works so I am not going to question it // just reuse // This one makes the beginning of the xls file function xlsBOF() { echo pack("ssssss", 0x809, 0x8, 0x0, 0x10, 0x0, 0x0); return; } // This one makes the end of the xls file function xlsEOF() { echo pack("ss", 0x0A, 0x00); return; } // this will write text in the cell you specify function xlsWriteLabel($Row, $Col, $Value ) { $L = strlen($Value); echo pack("ssssss", 0x204, 8 + $L, $Row, $Col, 0x0, $L); echo $Value; return; } // make the connection an DB query $dbc = mysql_connect( $dbhost , $dbuser , $dbpass ) or die( mysql_error() ); mysql_select_db( $dbname ); $q = "SELECT * FROM ".$dbtable." WHERE date ='$cdate'"; $qr = mysql_query( $q ) or die( mysql_error() ); // start the file xlsBOF(); // these will be used for keeping things in order. $col = 0; $row = 0; // This tells us that we are on the first row $first = true; while( $qrow = mysql_fetch_assoc( $qr ) ) { // Ok we are on the first row // lets make some headers of sorts if( $first ) { foreach( $qrow as $k => $v ) { // take the key and make label // make it uppper case and replace _ with ' ' xlsWriteLabel( $row, $col, strtoupper( ereg_replace( "_" , " " , $k ) ) ); $col++; } // prepare for the first real data row $col = 0; $row++; $first = false; } // go through the data foreach( $qrow as $k => $v ) { // write it out xlsWriteLabel( $row, $col, $v ); $col++; } // reset col and goto next row $col = 0; $row++; } xlsEOF(); exit(); ?> I just can't seem to figure out how to integrate fwrite into all that to write the generated data into a .xls file, how would I go about doing that? I need to get this working quite urgently, so any help would be greatly appreciated. Thanx guys.

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  • MySQL syntax: can't create table

    - by peng
    mysql> create table balance_sheet( -> Cash_and_cash_equivalents VARCHAR(20), -> Trading_financial_assets VARCHAR(20), -> Note_receivable VARCHAR(20), -> Account_receivable VARCHAR(20), -> Advance_money VARCHAR(20), -> Interest_receivable VARCHAR(20), -> Dividend_receivable VARCHAR(20), -> Other_notes_receivable VARCHAR(20), -> Due_from_related_parties VARCHAR(20), -> Inventory VARCHAR(20), -> Consumptive_biological_assets VARCHAR(20), -> Non_current_asset(expire_in_a_year) VARCHAR(20), -> Other_current_assets VARCHAR(20), -> Total_current_assets VARCHAR(20), -> Available_for_sale_financial_assets VARCHAR(20), -> Held_to_maturity_investment VARCHAR(20), -> Long_term_account_receivable VARCHAR(20), -> Long_term_equity_investment VARCHAR(20), -> Investment_real_eastate VARCHAR(20), -> Fixed_assets VARCHAR(20), -> Construction_in_progress VARCHAR(20), -> Project_material VARCHAR(20), -> Liquidation_of_fixed_assets VARCHAR(20), -> Capitalized_biological_assets VARCHAR(20), -> Oil_and_gas_assets VARCHAR(20), -> Intangible_assets VARCHAR(20), -> R&d_expense VARCHAR(20), -> Goodwill VARCHAR(20), -> Deferred_assets VARCHAR(20), -> Deferred_income_tax_assets VARCHAR(20), -> Other_non_current_assets VARCHAR(20), -> Total_non_current_assets VARCHAR(20), -> Total_assets VARCHAR(20), -> Short_term_borrowing VARCHAR(20), -> Transaction_financial_liabilities VARCHAR(20), -> Notes_payable VARCHAR(20), -> Account_payable VARCHAR(20), -> Item_received_in_advance VARCHAR(20), -> Employee_pay_payable VARCHAR(20), -> Tax_payable VARCHAR(20), -> Interest_payable VARCHAR(20), -> Dividend_payable VARCHAR(20), -> Other_account_payable VARCHAR(20), -> Due_to_related_parties VARCHAR(20), -> Non_current_liabilities_due_within_one_year VARCHAR(20), -> Other_current_liabilities VARCHAR(20), -> Total_current_liabilities VARCHAR(20), -> Long_term_loan VARCHAR(20), -> Bonds_payable VARCHAR(20), -> Long_term_payable VARCHAR(20), -> Specific_payable VARCHAR(20), -> Estimated_liabilities VARCHAR(20), -> Deferred_income_tax_liabilities VARCHAR(20), -> Other_non_current_liabilities VARCHAR(20), -> Total_non_current_liabilities VARCHAR(20), -> Total_liabilities VARCHAR(20), -> Paid_in_capital VARCHAR(20), -> Contributed_surplus VARCHAR(20), -> Treasury_stock VARCHAR(20), -> Earned_surplus VARCHAR(20), -> Retained_earnings VARCHAR(20), -> Translation_reserve VARCHAR(20), -> Nonrecurring_items VARCHAR(20), -> Total_equity(non) VARCHAR(20), -> Minority_interests VARCHAR(20), -> Total_equity VARCHAR(20), -> Total_liabilities_&_shareholder's_equity VARCHAR(20)); '> '> when i press enter,there is the output of ' ,no other reaction ,what's wrong?

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  • mySQL to .XSL help

    - by kielie
    hi guys, I have to create a script that takes a mySQL table, and exports it into .XSL format, and then saves that file into a specified folder on the web host. I got it working, but now I can't seem to get it to automatically save the file to the location without prompting the user. It needs to run every day at a specified time, so it can save the previous days leads into a .XSL file on the web host. Here is the code: <?php // DB TABLE Exporter // // How to use: // // Place this file in a safe place, edit the info just below here // browse to the file, enjoy! // CHANGE THIS STUFF FOR WHAT YOU NEED TO DO $dbhost = "-"; $dbuser = "-"; $dbpass = "-"; $dbname = "-"; $dbtable = "-"; // END CHANGING STUFF $cdate = date("Y-m-d"); // get current date // first thing that we are going to do is make some functions for writing out // and excel file. These functions do some hex writing and to be honest I got // them from some where else but hey it works so I am not going to question it // just reuse // This one makes the beginning of the xls file function xlsBOF() { echo pack("ssssss", 0x809, 0x8, 0x0, 0x10, 0x0, 0x0); return; } // This one makes the end of the xls file function xlsEOF() { echo pack("ss", 0x0A, 0x00); return; } // this will write text in the cell you specify function xlsWriteLabel($Row, $Col, $Value ) { $L = strlen($Value); echo pack("ssssss", 0x204, 8 + $L, $Row, $Col, 0x0, $L); echo $Value; return; } // make the connection an DB query $dbc = mysql_connect( $dbhost , $dbuser , $dbpass ) or die( mysql_error() ); mysql_select_db( $dbname ); $q = "SELECT * FROM ".$dbtable." WHERE date ='$cdate'"; $qr = mysql_query( $q ) or die( mysql_error() ); // Ok now we are going to send some headers so that this // thing that we are going make comes out of browser // as an xls file. // header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: application/force-download"); header("Content-Type: application/octet-stream"); header("Content-Type: application/download"); //this line is important its makes the file name header("Content-Disposition: attachment;filename=export_".$dbtable.".xls "); header("Content-Transfer-Encoding: binary "); // start the file xlsBOF(); // these will be used for keeping things in order. $col = 0; $row = 0; // This tells us that we are on the first row $first = true; while( $qrow = mysql_fetch_assoc( $qr ) ) { // Ok we are on the first row // lets make some headers of sorts if( $first ) { foreach( $qrow as $k => $v ) { // take the key and make label // make it uppper case and replace _ with ' ' xlsWriteLabel( $row, $col, strtoupper( ereg_replace( "_" , " " , $k ) ) ); $col++; } // prepare for the first real data row $col = 0; $row++; $first = false; } // go through the data foreach( $qrow as $k => $v ) { // write it out xlsWriteLabel( $row, $col, $v ); $col++; } // reset col and goto next row $col = 0; $row++; } xlsEOF(); exit(); ?> I tried using, fwrite to accomplish this, but it didn't seem to go very well, I removed the header information too, but nothing worked. Here is the original code, as I found it, any help would be greatly appreciated. :-) Thanx in advance. :-)

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  • Another Call to a member function get_segment() on a non-object question

    - by hogofwar
    I get the above error when calling this code: <? class Test1 extends Core { function home(){ ?> This is the INDEX of test1 <? } function test2(){ echo $this->uri->get_segment(1); //this is where the error comes from ?> This is the test2 of test1 testing URI <? } } ?> I get the error where commentated. This class extends this class: <?php class Core { public function start() { require("funk/funks/libraries/uri.php"); $this->uri = new uri(); require("funk/core/loader.php"); $this->load = new loader(); if($this->uri->get_segment(1) != "" and file_exists("funk/pages/".$this->uri->get_segment(1).".php")){ include("funk/pages/". $this->uri->get_segment(1).".php"); $var = $this->uri->get_segment(2); if ($var != ""){ $home= $this->uri->get_segment(1); $Index= new $home(); $Index->$var(); }else{ $home= $this->uri->get_segment(1); $Index = new $home(); $Index->home(); } }elseif($this->uri->get_segment(1) and ! file_exists("funk/pages/".$this->uri->get_segment(1).".php")){ echo "404 Error"; }else{ include("funk/pages/index.php"); $Index = new Index(); $Index->home(); //$this->Index->index(); echo "<!--This page was created with FunkyPHP!-->"; } } } ?> And here is the contents of uri.php: <?php class uri { private $server_path_info = ''; private $segment = array(); private $segments = 0; public function __construct() { $segment_temp = array(); $this->server_path_info = preg_replace("/\?/", "", $_SERVER["PATH_INFO"]); $segment_temp = explode("/", $this->server_path_info); foreach ($segment_temp as $key => $seg) { if (!preg_match("/([a-zA-Z0-9\.\_\-]+)/", $seg) || empty($seg)) unset($segment_temp[$key]); } foreach ($segment_temp as $k => $value) { $this->segment[] = $value; } unset($segment_temp); $this->segments = count($this->segment); } public function segment_exists($id = 0) { $id = (int)$id; if (isset($this->segment[$id])) return true; else return false; } public function get_segment($id = 0) { $id--; $id = (int)$id; if ($this->segment_exists($id) === true) return $this->segment[$id]; else return false; } } ?> i have asked a similar question to this before but the answer does not apply here. I have rewritten my code 3 times to KILL and Delimb this godforsaken error! but nooooooo....

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  • having trouble in mysql if statement

    - by user225269
    I just want to simplify what I am doing before, having multiple php files for all data to be listed. Here is my html form: <table border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="post" action="list.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="3">List Students</td> </tr> <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option>Year</option> <option>Address</option> </select></td></td> </tr> <tr> <td width="10"><input align="right" type="submit" name="Submit" value="Submit" > </td> </tr> </form> </table> And here's the form action: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $gyear= $_POST['general']; if ("YEAR"==$_POST['general']) { $result = mysql_query("SELECT * FROM student WHERE YEAR='{$_POST["specific"]}'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> <th>LASTNAME</th> <th>FIRSTNAME</th> </tr>"; while($row = mysql_fetch_array($result)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "<td>" . $row['LASTNAME'] . "</td>"; echo "<td>" . $row['FIRSTNAME'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?> Please help, how do I equate the YEAR(column in mysql database) and the option box(general). if ("YEAR"==$_POST['general']) please correct me if I'm wrong.

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  • change password code error.....

    - by shimaTun
    I've created a code to change a password. Now it seem contain an error.before i fill the form. the page display the error message: Parse error: parse error, unexpected $end in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 222 this the code: <?php # userChangePass.php //this page allows logged in user to change their password. $page_title='Change Your Password'; //if no first_name variable exists, redirect the user if(!isset($_SESSION['nameuser'])){ header("Location: http://" .$_SERVER['HTTP_HOST']. dirname($_SERVER['PHP_SELF'])."/index.php"); ob_end_clean(); exit(); }else{ if(isset($_POST['submit'])) {//handle form. require_once('connectioncomplaint.php'); //connec to the database //check for a new password and match againts the confirmed password. if(eregi ("^[[:alnum:]]{4,20}$", stripslashes(trim($_POST['password1'])))){ if($_POST['password1'] == $_POST['password2']){ $p =escape_data($_POST['password1']); }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Your password did not match the confirmed password!</font></p>'; } }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Please Enter a valid password!</font></p>'; } if($p){ //if everything OK. //make the query $query="UPDATE access SET password=PASSWORD('$p') WHERE userid={$_SESSION['userid']}"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; //include('templates/footer.inc');//include the HTML footer. exit(); }else{//if it did not run ok $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } mysql_close();//close the database connection. }else{//failed the validation test. echo '<p><font color="red" size="+1"> Please try again.</font></p>'; } }//end of the main Submit conditional. ?> And code for form: <h1>Change Your Password</h1> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <fieldset> <p><b>New Password:</b><input type="password" name="password1" size="20" maxlength="20" /> <small>Use only letters and numbers.Must be between 4 and 20 characters long.</small></p> <p><b>Confirm New Password:</b><input type="password" name="password2" size="20" maxlength="20" /></p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Change My Password" /></div> </form><!--End Form-->

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  • Listing issue, GROUP mysql

    - by SethCodes
    Here is a mock-up example of Mysql table: | ID | Country | City | ________________________________ | 1 | Sweden | Stockholm | | 2 | Sweden | Stockholm | | 3 | Sweden | Lund | | 4 | Sweden | Lund | | 5 | Germany | Berlin | | 6 | Germany | Berlin | | 7 | Germany | Hamburg | | 8 | Germany | Hamburg | Notice how both rows Country and city have repeated values inside them. Using GROUP BY country, city in my PDO query, the values will not repeat while in loop. Here is PDO for this: $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : The above code will result in an output like this (some editing in-between). GROUP BY works but the country repeats: Sweden - Stockholm Sweden - Lund Germany - Berlin Germany - Hamburg Using bootstrap collapse and above code, I separate the country from the city with a simple drop down collopase. Here is code: <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> It then looks something like this (once collapse is initiated): Sweden > Stockholm Sweden > Lund Germany >Berlin Germany >Hamburg Here is where I face the problem. The above lists the values Sweden and Germany 2 times. I want Sweden and Germany to only list one time, and the cities listed below, so the desired look is to be this: Sweden // Lists one time > Stockholm > Lund Germany // Lists one time >Berlin >Hamburg I have tried using DISTINCT, GROUP_CONTACT and other methods, yet none get my desired output (above). Suggestions? Below is my current full code in action: <? $query = "SELECT id, city, country FROM table GROUP BY country, city"; $stmt = $db->query($query); while($row = $stmt->fetch(PDO::FETCH_ASSOC)) : ?> <li> <a data-toggle="collapse" data-target="#<?= $row['id']; ?>" href="search.php?country=<?= $row['country']; ?>"> <?= $row['country']; ?> </a> <div id ="<?= $row['id']; ?>" class="collapse in"> //collapse div here <a href="search.php?city=<?= $row['city']; ?>"> <?= $row['city']; ?><br></a> </div> //end </li> <? endwhile ?>

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  • PHP & MySQL pagination display problem.

    - by TaG
    I asked a similar question like this yesterday but after waiting for ever I figured out part of the problem but now I'm stuck again I'm trying to display ... when the search results are to long because my pagination links will keep on displaying and will not stop until every link is displayed on the page. For example I'm trying to achieve the following in the example below. Can some one help me fix my code so I can update my site. Thanks This is what I want to be able to do. First Previous 1 2 ... 5 6 7 8 9 10 11 12 13 ... 199 200 Next Last Here is my pagination code that displays the links. $display = 20; if (isset($_GET['p']) && is_numeric($_GET['p'])) { $pages = $_GET['p']; } else { $q = "SELECT COUNT(id) FROM comments WHERE user_id=3"; $r = mysqli_query ($mysqli, $q) or trigger_error("Query: $q\n<br />MySQL Error: " . mysqli_error($mysqli)); $row = mysqli_fetch_array ($r, MYSQLI_NUM); $records = $row[0]; if ($records > $display) { $pages = ceil ($records/$display); } else { $pages = 1; } } if (isset($_GET['s']) && is_numeric($_GET['s'])) { $start = $_GET['s']; } else { $start = 0; } //content goes here if ($pages > 1) { echo '<br /><p>'; $current_page = ($start/$display) + 1; if ($current_page != 1) { echo '<a href="index.php">First</a>'; } if ($current_page != 1) { echo '<a href="index.php?s=' . ($start - $display) . '&p=' . $pages . '">Previous</a> '; } for ($i = 1; $i <= $pages; $i++) { if ($i != $current_page) { echo '<a href="index.php?s=' . (($display * ($i - 1))) . '&p=' . $pages . '">' . $i . '</a> '; } else { echo '<span>' . $i . '</span> '; } } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($start + $display) . '&p=' . $pages . '">Next</a>'; } if ($current_page != $pages) { echo '<a href="index.php?s=' . ($pages - 1) . '&p=' . $pages . '">Last</a>'; } echo '</p>'; }

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  • mysql_affected_rows() always returns 1 even though no row was updated.

    - by happyhardik
    What I am trying to do is: (programmatically) Update status where id is something, if no rows where updated, give error: we cannot find the record with id something, otherwise give message success. Here I am using mysql_affected_rows() to know if a row was updated or not, but it always return 1, so the user gets a success message, even though there was no row updated. Can anyone tell me what could it be?

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  • Duplicate DNS Zones (Error 4515 in Event Log )

    - by Campo
    I am getting these two error in the DNS Event log (errors at end of question). I have confirmed I do have duplicate zones. I am wondering which ones to delete. The DomainDNSZone contains all of our DNS records but it does not have the _msdcs zone.... that is in the ForestDNSZone with the duplicates that are not in use. here is a picture of that 3 Questions. I understand the advantages of having DNS in the ForestDNSZone. so... Why is DNS using the DomainDNSZone and is that acceptable considering _msdcs... is in the ForestDNSZone? If so, should I just delete the DC=1.168.192.in-addr.arpa and DC=supernova.local from the ForestDNSZone? Or should I try to get those to be the ones in use? What are those steps? I understand how to delete. That is simple but if i must move zones some info would be appreaciated there. Just to confirm. from my understanding. I can delete the two duplicates in the ForestDNSZone and leave the _msdcs.supernova.local as thats required there. This will resolve the erros I see. Just fyi when I look in those folders from the ForestDNSZone they have just 2 and 1 entries respectively. So obviously not in use compared to the others. I am pretty sure I understand the steps to complete this. But if you would like to provide that info, bonus points! Event Type: Warning Event Source: DNS Event Category: None Event ID: 4515 Date: 1/4/2011 Time: 2:14:18 PM User: N/A Computer: STANLEY Description: The zone 1.168.192.in-addr.arpa was previously loaded from the directory partition DomainDnsZones.supernova.local but another copy of the zone has been found in directory partition ForestDnsZones.supernova.local. The DNS Server will ignore this new copy of the zone. Please resolve this conflict as soon as possible. If an administrator has moved this zone from one directory partition to another this may be a harmless transient condition. In this case, no action is necessary. The deletion of the original copy of the zone should soon replicate to this server. If there are two copies of this zone in two different directory partitions but this is not a transient caused by a zone move operation then one of these copies should be deleted as soon as possible to resolve this conflict. To change the replication scope of an application directory partition containing DNS zones and for more details on storing DNS zones in the application directory partitions, please see Help and Support. For more information, see Help and Support Center at http://go.microsoft.com/fwlink/events.asp. Data: 0000: 89 25 00 00 %.. AND Event Type: Warning Event Source: DNS Event Category: None Event ID: 4515 Date: 1/4/2011 Time: 2:14:18 PM User: N/A Computer: STANLEY Description: The zone supernova.local was previously loaded from the directory partition DomainDnsZones.supernova.local but another copy of the zone has been found in directory partition ForestDnsZones.supernova.local. The DNS Server will ignore this new copy of the zone. Please resolve this conflict as soon as possible. If an administrator has moved this zone from one directory partition to another this may be a harmless transient condition. In this case, no action is necessary. The deletion of the original copy of the zone should soon replicate to this server. If there are two copies of this zone in two different directory partitions but this is not a transient caused by a zone move operation then one of these copies should be deleted as soon as possible to resolve this conflict. To change the replication scope of an application directory partition containing DNS zones and for more details on storing DNS zones in the application directory partitions, please see Help and Support. For more information, see Help and Support Center at http://go.microsoft.com/fwlink/events.asp. Data: 0000: 89 25 00 00 %..

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  • A couple PHP/MySQL questions...

    - by Jeff
    I am a college student taking a course in php and mysql progamming and my first question is about the "$variable" variables in the following code: <?php ob_start(); ?> <?php session_start(); if ($_SESSION['auth'] != "true") { header("Location: login.php"); exit; } $uid = $_SESSION['user']; $connection = mysql_connect("localhost", "username", "password"); mysql_select_db("username", $connection); $result = mysql_query ( "SELECT * FROM users where user_id = '$uid'", $connection); $num = mysql_numrows($result); $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"firstname"); $f2=mysql_result($result,$i,"lastname"); ?> <html><body> <p> <td><center><font size = "18" face="Arial"><?php echo "Name: $f1 "; echo $f2; ?> </font></center></td> </p> </body></html> <?php $i++; } ?> <?php $result1 = mysql_query ( "SELECT * FROM phone where user_id = '$uid'", $connection); $num1 = mysql_numrows($result1); $j=0; while ($j < $num1) { $f3=mysql_result($result1,$j,"type"); $f4=mysql_result($result1,$j,"number"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f5: "; echo "($f3) "; echo "$f4 <br />"; ?> </font></center></td> </p> </body></html> <?php $j++; } ?> <?php $result2 = mysql_query ( "SELECT * FROM address where user_id = '$uid'", $connection); $num2 = mysql_numrows($result2); $h=0; while ($h < $num2) { $f6=mysql_result($result2,$h,"type"); $f7=mysql_result($result2,$h,"address"); $f8=mysql_result($result2,$h,"city"); $f9=mysql_result($result2,$h,"state"); $f10=mysql_result($result2,$h,"zip"); ?> <html><body> <p> <br> <td><center><font size = "12" face="Arial"><?php echo "$f10 Address: $f6, $f7, $f8 $f9"; ?></font></center></td> </p> </body></html> <?php $h++; } ?> <?php include 'navbar.php'; ob_end_flush(); ?> I just don't really understand the $variables at all. Are they user-generated or are they entities in the database? And how does the code know which $result is which? My second question is that, if this was someone else in my class's code and I wanted to modify it to make it my own and substitute my own variables, how would I go about doing that? Do the $variables need to be changed if they are not user-defined and if so, how? I apologize if these are dumb questions, but I am a beginner at this programming language. Thanks in advance for your help. -Jeff

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  • Show last 4 table entries mysql php

    - by user272899
    I have a movie database Kind of like a blog and I want to display the last 4 created entries. I have a column in my table for timestamp called 'dateadded'. Using this code how would I only display the 4 most recent entries to table <?php //connect to database mysql_connect($mysql_hostname,$mysql_user,$mysql_password); @mysql_select_db($mysql_database) or die("<b>Unable to connect to specified database</b>"); //query databae $query = "SELECT * FROM movielist"; $result=mysql_query($query) or die('Error, insert query failed'); $row=0; $numrows=mysql_num_rows($result); while($row<$numrows) { $id=mysql_result($result,$row,"id"); $imgurl=mysql_result($result,$row,"imgurl"); $imdburl=mysql_result($result,$row,"imdburl"); ?> <div class="moviebox rounded"><a href="http://<?php echo $domain; ?>/viewmovie?movieid=<?php echo $id; ?>" rel="facebox"> <img src="<?php echo $imgurl; ?>" /> <form method="get" action=""> <input type="text" name="link" class="link" style="display:none" value="http://us.imdb.com/Title?<?php echo $imdburl; ?>"/> </form> </a></div> <?php $row++; } ?>

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  • MySql too many connections

    - by MichaelMcCabe
    I hate to bring up a question which is widely asked on the web, but I cant seem to solve it. I started a project a while back and after a month of testing, I hit a "Too many connections" error. I looked into it, and "Solved" it by increasing the max_connections. This then worked. Since then more and more people started to use it, and it hit again. When I am the only user on the site, i type "show processlist" and it comes up with about 50 connections which are still open (saying "Sleep" in the command). Now, I dont know enough to speculate why these are open, but in my code I tripple checked and every connection I open, I close. ie. public int getSiteIdFromName(String name, String company)throws DataAccessException,java.sql.SQLException{ Connection conn = this.getSession().connection(); Statement smt = conn.createStatement(); ResultSet rs=null; String query="SELECT id FROM site WHERE name='"+name+"' and company_id='"+company+"'"; rs=smt.executeQuery(query); rs.next(); int id=rs.getInt("id"); rs.close(); smt.close(); conn.close(); return id; } Every time I do something else on the site, another load of connections are opened and not closed. Is there something wrong with my code? and if not, what could be the problem?

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  • Problem with WHERE columnName = Data in MySQL query in C#

    - by Ryan Sullivan
    I have a C# webservice on a Windows Server that I am interfacing with on a linux server with PHP. The PHP grabs information from the database and then the page offers a "more information" button which then calls the webservice and passes in the name field of the record as a parameter. So i am using a WHERE statement in my query so I only pull the extra fields for that record. I am getting the error: System.Data.SqlClient.SqlException:Invalid column name '42' Where 42 is the value from the name field from the database. my query is string selectStr = "SELECT name, castNotes, triviaNotes FROM tableName WHERE name =\"" + show + "\""; I do not know if it is a problem with my query or something is wrong with the database, but here is the rest of my code for reference. NOTE: this all works perfectly when I grab all of the records, but I only want to grab the record that I ask my webservice for. public class ktvService : System.Web.Services.WebService { [WebMethod] public string moreInfo(string show) { string connectionStr = "MyConnectionString"; string selectStr = "SELECT name, castNotes, triviaNotes FROM tableName WHERE name =\"" + show + "\""; SqlConnection conn = new SqlConnection(connectionStr); SqlDataAdapter da = new SqlDataAdapter(selectStr, conn); DataSet ds = new DataSet(); da.Fill(ds, "tableName"); DataTable dt = ds.Tables["tableName"]; DataRow theShow = dt.Rows[0]; string response = "Name: " + theShow["name"].ToString() + "Cast: " + theShow["castNotes"].ToString() + " Trivia: " + theShow["triviaNotes"].ToString(); return response; } }

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  • MySQL: Complex Join Statement involving two tables and a third correlation table

    - by Stephen
    I have two tables that were built for two disparate systems. I have records in one table (called "leads") that represent customers, and records in another table (called "manager") that are the exact same customers but "manager" uses different fields (For example, "leads" contains an email address, and "manager" contains two fields for two different emails--either of which might be the email from "leads"). So, I've created a correlation table that contains the lead_id and manager_id. currently this correlation table is empty. I'm trying to query the "leads" table to give me records that match either "manager" email field with the single "leads" email field, while at the same time ignoring fields that have already been added to the "correlated" table. (this way I can see how many leads that match have not yet been correlated.) Here's my current, invalid SQL attempt: SELECT leads.id, manager.id FROM leads, manager LEFT OUTER JOIN correlation ON correlation.lead_id = leads.id WHERE correlation.id IS NULL AND leads.project != "someproject" AND (manager.orig_email = leads.email OR manager.dest_email = leads.email) AND leads.created BETWEEN '1999-01-01 00:00:00' AND '2010-05-10 23:59:59' ORDER BY leads.created ASC; I get the error: Unknown column 'leads.id' in 'on clause' Before you wonder: there are records in the "leads" table where leads.project != "someproject" and leads.created falls between those dates. I've included those additional parameters for completeness.

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  • Difficulty creating a paging function with MySQL and ColdFusion

    - by Mel
    I'm trying to create pagination for search results using MySQL and ColdFusion. My intention is to only retrieve the queries that can be displayed on a single page, thus making the process efficient. I tried using two queries in my function, but I could not return two variables to the cfinvoke. The following code does not paginate, but it displays the result search results using a CFC: <!---DEFINE DEFAULT STATE---> <cfparam name="variables.searchResponse" default=""> <cfparam name="URL.titleName" default=""> <cfparam name="URL.genreID" default=""> <cfparam name="URL.platformID" default=""> <!---TitleName can only be blank if one or both genre and platform are selected---> <cfif StructKeyExists(URL, "searchQuery") AND (Len(Trim(URL.titleName)) LTE 2 AND Len(URL.genreID) IS 0 AND Len(URL.platformID) IS 0)> <cfset variables.searchResponse = "invalidString"> <cfelseif StructKeyExists(URL, "searchQuery")> <cfinvoke component="gz.cfcomp.test" method="searchGames" returnvariable="resultData" argumentcollection="#URL#"> <cfset variables.searchResponse = "hasResult"> </cfif> <cfif searchResponse EQ "hasResult" AND resultData.RecordCount EQ 0> <cfset variables.searchResponse = "noResult"> </cfif> Using this logic, I can display what I need to display on the page: <cfif searchResponse EQ "invalidString"> <cfoutput>Invalid search</cfoutput> </cfif> <cfif searchResponse EQ "noResult"> <cfoutput>No results found</cfoutput> </cfif> <cfif searchResponse EQ "hasResult"> <cfoutput>Display Results</cfoutput> </cfif> If I were executing the queries on the same page, it would be easy to follow the many tutorials out there. But the queries are executing in a function. Displaying the data is easy, but paginating it has become a nightmare for me. Here is my function: <cffunction name="searchGames" access="public" output="false"> <cfargument name="titleName" required="no" type="string"> <cfargument name="genreID" required="no" type="string"> <cfargument name="platformID" required="no" type="string"> <!--- DEFINE LOCAL VARIABLES---> <cfset var resultData = ""> <!---GET DATA---> <cfquery name="resultData" datasource="myDSN"> SELECT * <!---JOINS FOR GENRE/PLATFORM GO HERE---> WHERE <!---CONDITIONS GO HERE---> </cfquery> <!---RETURN VARIABLE---> <cfreturn resultData> </cffunction> To paginate, I thought about modifying my function to the following (a new query using a count statement): <!--- DEFINE LOCAL VARIABLES---> <cfset var resultCount = ""> <!---GET DATA---> <cfquery name="resultCount" datasource="myDSN"> SELECT COUNT(gameID) AS rowsFound FROM GAMES <!---JOINS FOR GENRE/PLATFORM GO HERE---> WHERE <!---CONDITIONS GO HERE---> </cfquery> <!---RETURN VARIABLE---> <cfreturn resultCount> Then I figured if there is a result to return, I would execute a nested query and create the pagination variables: <cfif resultCount.rowsFound GTE 0> <cfparam name="pageNumber" default="1"> <cfset var recordsPerPage = 5> <cfset var numberOfPages = Int(resultCount.RecordCount / recordsPerPage)> <cfset var recordsToSkip = pageNumber * recordsPerPage - recordsPerPage> <!---DEFINE LOCAL VARIABLE---> <cfset var resultData = ""> <cfquery name="resultData" datasource="myDSN"> <!---GET DATA AND SEND IT BACK USING LIMIT WITH #recordsToSkip# and #RecordsPerPage#---> </cfquery> <!---RETURN VARIABLE---> <cfreturn resultData> </cffunction> I figured I would return two variables: resultCount and resultData. I would use #resultCount# to build my pagination, and #resultData# to display the output. The problem is I can't return two variables in the same cfinvoke tag. Any ideas of how to approach the the right way? I'm totally lost as to the logic I need to follow.

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • Search Form using PHP/mySQL and Fancybox iFrame

    - by Cocoonfxmedia
    I am struggling to get a search form in PHP to work with a fancybox iFrame. The search form queries a MySQL database and I want the results to show in the iFrame. However for some reason i can not get this to work. I have pasted the complete code below. Appreciate any support with this? Java Script: <script type="text/javascript"> $(document).ready(function() { $("#tip5").fancybox({ 'scrolling' : 'no', 'titleShow' : false, 'onClosed' : function() { $("#login_error").hide(); } }); }); </script> HTML/PHP <form method="post" action="test2.php?go" id="topF"> <input type="text" name="name"> <input type="submit" name="submit" id="tip5" href="#results" value="Search" class="buttonSubmit"> </form> <div id="results"> <?php if(isset($_POST['submit'])){ if(isset($_GET['go'])){ if(preg_match("/[A-Z | a-z]+/", $_POST['name'])){ $name=$_POST['name']; //-query the database table $sql="SELECT id, COMPANY, TOWN, COUNTY, ServiceStandards,Active FROM main WHERE Active='Y' AND COMPANY LIKE '%" . $name . "%' OR TOWN LIKE '%" . $name . "%'AND Active='Y' OR ServiceStandards LIKE '%" . $name . "%' AND Active='Y' OR COUNTY LIKE '%" . $name . "%'AND Active='Y'"; $result5=mysql_query($sql); $numrows=mysql_num_rows($result5); echo "<p>" .$numrows . " results found for " . stripslashes($name) . "</p>"; //-create while loop and loop through result set while($numrow=mysql_fetch_array($result5)){ $Company =$numrow['COMPANY']; $Town=$numrow['TOWN']; $County=$numrow['COUNTY']; $ID=$numrow['id']; $Service=$numrow['ServiceStandards']; //-display the result of the array echo "<ul>\n"; echo "<li>" . "<a href=\"test2.php?id=$ID\">" .$Company . "</a></li>\n"; echo "</ul>"; } } else{ echo "<p>Please enter a search query</p>"; } } } if(isset($_GET['by'])){ $letter=$_GET['by']; $sql="SELECT *,COMPANY,COMPANY+0 FROM main WHERE Active='Y' AND COMPANY LIKE '" . $letter . "%' ORDER BY COMPANY"; $result5=mysql_query($sql); $result6=mysql_query($sql); $rows=mysql_num_rows($result6); echo "<p>" .$numrows . " results found for " . $letter . "</p>"; while($rows=mysql_fetch_array($result6)){ $Company =$rows['COMPANY']; $Town=$rows['TOWN']; $County=$rows['COUNTY']; $Post=$rows['POSTCODE']; $ID=$rows['id']; //-display the result of the array echo "<ul>\n"; echo "<li>" . "<a href=\"test2.php?id=$ID\">" .$Company . "</a> <br/>" .$Town . ", " .$County. ", " .$Post."</li>\n"; echo "</ul>"; } } if(isset($_GET['id'])){ $contactid=$_GET['id']; $sql="SELECT * FROM main WHERE Active='Y' AND id=" . $contactid; $result7=mysql_query($sql); while($row=mysql_fetch_array($result7)){ $Company =$row['COMPANY']; $Town=$row['TOWN']; $County=$row['COUNTY']; $Email=$row['Email']; $Web=$row['Web']; //-display the result of the array echo 'Company Name: '. $row['COMPANY'] . '<br />'; echo 'Town: '. $row['TOWN'] . '<br/>'; echo 'Postcode: '. $row['POSTCODE'] . '<br/>'; echo 'Telephone: '. $row['TELEPHONE'] . '<br/>'; echo 'Email: '. $row['Email'] . '<br/>'; echo 'Web: ' . "<a href=".$Web.">" .$Web . "</a> <br/>\n"; echo ' '. '<br/>'; echo 'Service: '. $row['ServiceStandards'] . '</br>'; } } ?> </div>

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • MySQL Casting in C#

    - by user798080
    Okay, so I'm attempting to print out the contents of a table in a comma-separated file. using (OdbcCommand com = new OdbcCommand("SELECT * FROM pie_data WHERE Pie_ID = ?", con)) { com.Parameters.AddWithValue("", Request.Form["pie_id"]); com.ExecuteNonQuery(); using (OdbcDataReader reader = com.ExecuteReader()) { string finalstring = ""; while (reader.Read()) { finalstring = reader.GetString(9) + ","; for (int i = 0; i <= 8; i = i + 1) { finalstring = finalstring + reader.GetString(i) + ","; } } } Response.Write(finalstring); noredirect = 1; } My table layout is: CREATE TABLE `rent_data` ( `Pies` INT(10) UNSIGNED NOT NULL, `Name` VARCHAR(85) NOT NULL, `Email` VARCHAR(85) NOT NULL, `Pie_Rent` DATE NOT NULL, `Rent_To` DATE NOT NULL, `Returned_Date` DATE NULL DEFAULT NULL, `Place` VARCHAR(100) NOT NULL, `Purpose` MEDIUMTEXT NOT NULL, `Comments` MEDIUMTEXT NULL, `Pie_ID` SMALLINT(5) UNSIGNED ZEROFILL NOT NULL, INDEX `Pie_ID` (`Equipment_ID`) ) The error I'm getting is this: Exception Details: System.InvalidCastException: Unable to cast object of type 'System.Int64' to type 'System.String'. On the line: finalstring = finalstring + reader.GetString(i) + ",";

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  • Mysql Query is not working, why?

    - by Furkan Kadioglu
    Im using this example: www.jtable.org Now i download to jtable php version. And i edited script. Jtable simple version is working but my edition is doesnt working. I can do list, but i cant do add a row; this codes having problem. But php doesnt giving any error. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } if you doesnt understand, please ask me question. Where is the problem?

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  • Form Submitting Incorrect Information to MySQL Database

    - by ThatMacLad
    I've created a form that submits data to a MySQL database but the Date, Time, Year and Month fields constantly revert to the exact same date (1st January 1970) despite the fact that when I submit the information to the database the form displays the current date, time etc to me. I've already set it so that the time and date fields automatically display the current time and date. Could someone please help me with this. Form: <html> <head> <title>Blog | New Post</title> <link rel="stylesheet" href="css/newposts.css" type="text/css" /> </head> <body> <div class="new-form"> <div class="header"> <a href="edit.php"><img src="images/edit-home-button.png"></a> </div> <div class="form-bg"> <?php if (isset($_POST['submit'])) { $month = htmlspecialchars(strip_tags($_POST['month'])); $date = htmlspecialchars(strip_tags($_POST['date'])); $year = htmlspecialchars(strip_tags($_POST['year'])); $time = htmlspecialchars(strip_tags($_POST['time'])); $title = htmlspecialchars(strip_tags($_POST['title'])); $entry = $_POST['entry']; $timestamp = strtotime($month . " " . $date . " " . $year . " " . $time); $entry = nl2br($entry); if (!get_magic_quotes_gpc()) { $title = addslashes($title); $entry = addslashes($entry); } mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "INSERT INTO php_blog (timestamp,title,entry) VALUES ('$timestamp','$title','$entry')"; $result = mysql_query($sql) or print("Can't insert into table php_blog.<br />" . $sql . "<br />" . mysql_error()); if ($result != false) { print "<p class=\"success\">Your entry has successfully been entered into the blog. </p>"; } mysql_close(); } ?> <?php $current_month = date("F"); $current_date = date("d"); $current_year = date("Y"); $current_time = date("H:i"); ?> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_month; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_date; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_year; ?>" /> <input type="text" name="time" id="time" size="5"value="<?php echo $current_time; ?>" /> <input class="field2" type="text" id="title" value="Title Goes Here." name="title" size="40" /> <textarea class="textarea" cols="80" rows="20" name="entry" id="entry" class="field2"></textarea> <input class="field" type="submit" name="submit" id="submit" value="Submit"> </form> </div> </div> </div> <div class="bottom"></div> </body> </html>

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  • PHP/MySQL Problem

    - by Scott
    Why does this only print the sites specific content under the first site, and doesn't do it for the other 2? <?php echo 'NPSIN Data will be here soon!'; // connect to DB $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = 'root'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to DB'); $dbname = 'npsin'; mysql_select_db($dbname); // get number of sites $query = 'select count(*) from sites'; $result = mysql_query($query) or die ('Query failed: ' . mysql_error()); $resultArray = mysql_fetch_array($result); $numSites = $resultArray[0]; echo "<br><br>"; // get all sites $query = 'select site_name from sites'; $result = mysql_query($query); // get site content $query2 = 'select content_name, site_id from content'; $result2 = mysql_query($query2); // get site files // print info $count = 1; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "Site $count: "; echo "$row[0]"; echo "<br>"; $contentCount = 1; while ($row2 = mysql_fetch_array($result2, MYSQL_NUM)) { $id = $row2[1]; if ($id == ($count - 1)) { echo "Content $contentCount: "; echo "$row2[0]"; echo "<br>"; } $contentCount++; } $count++; } ?>

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