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  • Error handling in controllers with MVC

    - by twrn
    Does it make sense to do error handling and logging inside actions methods or handle the OnException method inside the controllers. One way means writing try/catches in all the action methods even when there is nothing to be done to recover from the error. Handling this at the controller level would allow logging and redirection to an error handler page without writing try/catches inside all the action methods. Which method makes the most sense? Here is example code of try/catches in an action method. [HttpPost] public ActionResult Delete(int id) { using (new Tracer("Project Controller")) { try { Logger.Write("Deleting project"); projService.DeleteProject(id); TempData["message"] = "Project Deleted successfully"; } catch (System.Exception ex) { HandleException(ex, "Project could not be deleted."); } return RedirectToAction("List"); } }

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  • Add params before submit form ROR

    - by Jorge Najera T
    It's possible to add some parameters before submit an form? My problem is that I need to send the ticket id to my payment controller. A possibility is to send it through an hidden input field, but there's any other secure way to achieve this? Any help will be appreciated. Thanks. The process of buying a ticket 0) Select the event 1) User select the kind of ticket he wants to buy. 2) User add his personal information 3) Finally the Checkout (payment controller)

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  • How to send exceptions to exceptionController?

    - by ivar
    <bean class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver"> <property name="mappedHandlers"> <set> <ref bean="exceptionController" /> </set> </property> <property name="defaultErrorView" value="tiles/content/error" /> </bean> I'm trying to send exceptions to a controller so I can create a redirect. If I comment out the mappedHandlers part then the error tile is displayed but it is only a tile. The rest of the tiles load normally. I need to make a redirect in the controller so I can show an error page not just an error tile. I can't find enough information or an example how the exception invokes some method in exceptionController.

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  • Where do I put constants file for Codeigniter (PHP)?

    - by wag2639
    I have a list of constants (I'm using them as an enum), some are define statements, and some are just global variables. Where am I suppose to put them in the MVC framework so I can use them for both my model and my controller that needs to reference it? I'd rather not stick it into config/constants.php since they shouldn't be called except for by this model and the controllers that use it. Edit 1: Clarification To be more specific, I have my message_model model and it has a bunch of constants that I need that are stored in message_model_constants.php. Where should I put message_model_constants.php and is there a way to have it automatically included by the controller that loads message_model when message_model is not (and I don't want it to be) auto-loaded. Edit 2: I really don't want to have the constants auto-loaded except for when I use the model

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  • Can someone explain Kohana 3's routing system?

    - by alex
    In bootstrap.php, where you set routes, I'm having a hard time getting them to work. I read some documentation a while ago that I can't seem to find again that explains them. Here is one of my examples Route::set('products', 'products/(type)', array('type' => '.+')) ->defaults(array( 'controller' => 'articles', 'action' => 'view_product', 'page' => 'shock-absorbers', )); I thought that would mean a request like products/something would load up the articles controller, and the action_view_product method. But I can't get it to work. Can someone please explain to me exactly how they work, and what all the method parameters are?

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  • ASP.Net MVC - Models and User Controls

    - by cdotlister
    Hi guys, I have a View with a Master Page. The user control makes use of a Model: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<BudgieMoneySite.Models.SiteUserLoginModel>" %> This user control is shown on all screens (Part of the Master Page). If the user is logged in, it shows a certain text, and if the user isn't logged in, it offers a login box. That is working OK. Now, I am adding my first functional screen. So I created a new view... and, well, i generated the basic view code for me when I selected the controller method, and said 'Create View'. My Controller has this code: public ActionResult Transactions() { List<AccountTransactionDetails> trans = GetTransactions(); return View(trans); } private List<AccountTransactionDetails> GetTransactions() { List<AccountTransactionDto> trans = Services.TransactionServices.GetTransactions(); List<AccountTransactionDetails> reply = new List<AccountTransactionDetails>(); foreach(var t in trans) { AccountTransactionDetails a = new AccountTransactionDetails(); foreach (var line in a.Transactions) { AccountTransactionLine l = new AccountTransactionLine(); l.Amount = line.Amount; l.SubCategory = line.SubCategory; l.SubCategoryId = line.SubCategoryId; a.Transactions.Add(l); } reply.Add(a); } return reply; } So, my view was generated with this: <%@ Page Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<System.Collections.Generic.List<BudgieMoneySite.Models.AccountTransactionDetails>>" %> Found <%=Model.Count() % Transactions. All I want to show for now is the number of records I will be displaying. When I run it, I get an error: "The model item passed into the dictionary is of type 'System.Collections.Generic.List`1[BudgieMoneySite.Models.AccountTransactionDetails]', but this dictionary requires a model item of type 'BudgieMoneySite.Models.SiteUserLoginModel'." It looks like the user control is being rendered first, and as the Model from the controller is my List<, it's breaking! What am I doing wrong?

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  • Best Design Pattern to Implement while Mapping Actions in MVC

    - by FidEliO
    What could be the best practices of writing the following case: We have a controller which based on what paths users take, take different actions. For example: if user chooses the path /path1/hello it will say hello. If a user chooses /path1/bye?name="Philipp" it will invoke sayGoodBye() and etc. I have written a switch statement inside the controller which is simple, however IMO not efficient. What are the best way to implement this, considering that paths are generally String. private void takeAction() { switch (path[1]) { case "hello": //sayHello(); break; case "bye": //sayBye(); break; case "case3": //Blah(); break; ... } }

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  • MVC: Structuring Feed Output

    - by Brian Wigginton
    The framework I'm using on my project follows the MVC Pattern. I"M building JSON feeds and need to structure them in a different way then what the system gives me by default from the ORM. Where should I be handling the task of mangling and shaping my data that I'll serve up, in the model, view or controller? Right now I'm doing it in my controller, then passing that data to the view. I can see this fitting better under the Model or the View but not sure which one.

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  • What is the best way to log errors in Zend Framework in my project at this stage?

    - by Pasta
    We built an app in Zend Framework and have not worked a lot in setting up error reporting and logging. Is there any way we could get some level or error reporting without too much change in the code? Is there a ErrorHandler plugin available? The basic requirement is to log errors that happens within the controller, missing controllers, malformed URLs, etc. I also want to be able to log errors within my controllers. Will using error controller here, help me identify and log errors within my controllers? How best to do this with minimal changes?

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  • What would be the best approach for this?

    - by chobo
    I have a site which has an area that requires authentication. Right now I use the roles attribute on all the controllers in that area, and I run a query to retrieve that users ID, and all their settings. It seems like a code or design smell to me that I am retrieving the userid and settings each time a controller in that area loads up? I'm not sure if I should be using sessions, or if ASP.Net MVC 2.0 provides some unique way to handle this. Another concern is security. Overall, I don't really know which way to turn. Design wise I would like the userId and settings retrieved only once when the user logs into the area. Right now I grab the userId each time a controller loads up, and then if required, I query the database for their settings each time as well.

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  • How to call javascript function when url variable is sent

    - by mattlarkin
    Hello, heres basically what I need to get done. I have a jsp page which allows me to add/modify/delete an item. The items are stored in a database which I have controller classes to access(dont worry bout that part) When an item gets selected and deleted the id of the item gets sent to the controller to be processed. The item will not always be deleted if their is a foreign key constraint so I send either a delete=true or delete=false through url back to the jsp page. I would like to have it so a javascript function gets called displaying an alert saying the item was deleted or the item was not deleted. can someone please tell me the best way to do this? thank you

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  • TableView problem with Tab Bar!?!?!

    - by Daniel Granger
    I created a tableView which worked fine in a single view app but as soon as I changed the view controller for a Tab Bar Controller and tapped the tab for the view with the table view in I suddenly get this! What has gone wrong? [Session started at 2010-03-28 15:30:15 +0100.] 2010-03-28 15:30:17.763 LogbookTable[13473:207] *** -[UIViewController tableView:numberOfRowsInSection:]: unrecognized selector sent to instance 0x3b14d10 2010-03-28 15:30:17.765 LogbookTable[13473:207] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[UIViewController tableView:numberOfRowsInSection:]: unrecognized selector sent to instance 0x3b14d10' 2010-03-28 15:30:17.766 LogbookTable[13473:207] Stack: ( 29303899, 2465178889, 29685819, 29255286, 29107906, 4372518, 4379894, 4378891, 3095430, 3035941, 3077376, 3065931, 55820976, 55820399, 55818438, 55817530, 2739877, 2763572, 2745983, 2773089, 37399897, 29088640, 29084744, 2739733, 2777007, 10496, 10350 )

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  • Are these REST HTTP response codes right, and what about the Content-Type?

    - by talentedmrjones
    I'm writing a controller helper that sets the proper response headers for my REST controller action. It's pasted below and should be simplified enough for those who aren't familiar with Zend Framework to understand what I'm doing. My question is: Are these codes correct for their respective responses, and in the case of "access denied" do I use a 401 or 403? Also, in case of responding with an error, I understand I should be placing a message in the response body, but should I set the "Content-Type" to "text/plain"? <?php class App_Controller_Helper_RestResponse extends Zend_Controller_Action_Helper_Abstract { public function denied() { // 403 or 401? } public function notFound() { // 404 } public function created() { // 201 } public function deleted() { // 204 } public function redirect() { // 301 // new url } public function malformed() { // 400 } public function gone() { // 410 } }

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  • Process AJAX response with long runing tasks

    - by mpz
    I have long time task in controller action. I use delayed job for it. (Also in heroku it is good practice for perfomance - dyno must work for small time in each request) But my client need result of it work and users can wait on that task. It is more clear: no any addition models or records in it, simple view and js... I think about such way: On client run AJAX with very long timeout (5 min for example) Client make request to server as usual On controller in action1 def start_work (with delay work setup) i need NO any response to client After work performs (delay job finished) i need run new action2 with response to client Client recieve response after about 1-5 min It is possible?

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  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

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  • MVC Pages that require the user to be logged in

    - by keithjgrant
    I'm working on a little MVC framework and I'm wondering what the "best way" is to structure things so secure pages/controllers always ensure the user is logged in (and thus automatically redirects to a login page--or elsewhere--if not). Obviously, there are a lot of ways to do it, but I'm wondering what solution(s) are the most common or are considered the best practice. Some ideas I had: Explicitly call user->isLoggedIn() at the beginning of your controller action method? (Seems far too easy to forget and leave an important page unsecure on accident) Make your controller extend a secureController that always checks for login in the constructor? Do this check in the model when secure information is requested? (Seems like redundant calls would be made) Something else entirely? Note: I'm working in PHP, though the question is not language-dependent.

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  • Html.ActionLink in a button

    - by Pomster
    I Am trying to connect to a method in my controller, with a button. I can connect though this link: @Html.ActionLink("Print", "Print", new { id = Model.SalesContractId}) But i Don't want a link, i want my button on my dialog to do it. I have tried the following: $('#btnDialogPrint').click(function () { location.href = '<%= Url.Action("Print", "Print", new { id = Model.SalesContractId}) %>'; }); But it just redirect me to a page that say bad request. namespace Contract.Controllers { public class ContractController : Controller { CompassEntities db = new CompassEntities(); public ActionResult Print(int id) { return View(""); // This can be removed and Print code may be added } Don't worry about the code inside i will get to that once i get inside this method. Could i maybe attach a link here? <input type="button" value="Print" id="btnDialogPrint" />

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  • How do I use a named_scope to filter records in my model

    - by kibyegon
    I have a model "Product" with a "description" field. Now I want to have a link in the index page that when clicked will show all products where the description is blank (empty). In the model I have defined a named_scope like this named_scope :no_description, :conditions => { :description => "" } I have checked that the named_scope works by calling Product.no_description.count on the console. As far as I know, the controller is then supposed to handle the filter request from the link on the "index" action but be able to distinguish it from the default which is view all products. def index @products = Product.all ... My problem is getting the controller handle the different request, what route to setup for the link on the view and the actual link on the view. Hope I explained my problem.

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  • will_paginate route only works on page > 1

    - by Avishai
    I have the following routes defined: map.resources :categories, :has_many => :downloads map.resources :downloads, :member => {:go => :get}, :collection => {:tag => :get} map.connect '/downlods/page/:page', :controller => 'downloads', :action => 'index' map.connect '/categories/:category_id/downloads/page/:page', :controller => 'downloads', :action => 'index' For some reason, the first page that the will_paginate helper is called on causes links with ?page=2 to be rendered, while subsequent pages have links with /downloads/page/2. Do you know what might be causing this?

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  • Spring noHandlerFound

    - by Justin
    I am trying to set up my Spring MVC testing environment. But I always get this noHandlerFound error: Aug 21, 2014 4:43:25 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/restful/firstPage] in DispatcherServlet with name 'spring' Aug 21, 2014 4:47:21 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/restful/firstPage2] in DispatcherServlet with name 'spring' Aug 21, 2014 5:10:27 PM org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping found for HTTP request with URI [/restful/index.html] in DispatcherServlet with name 'spring' I already searched for solution, but none can fix my problem. My spring mvc version: 3.1.3.RELEASE This is my web.xml: <servlet> <servlet-name>spring</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> this is my spring-servlet.xml: <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/jsp/" p:suffix=".jsp" /> this is my applicationContext.xml: <context:annotation-config /> <context:component-scan base-package="test.spring" /> <mvc:annotation-driven /> <mvc:resources mapping="/index.html" location="/index.html" /> <mvc:view-controller path="/firstPage" /> This is my Controller: package test.spring; .... @Controller @RequestMapping("/") public class FirstController { @RequestMapping(value = "firstPage2", method = RequestMethod.GET) public String showFirstPage(Map<String,Object> model){ return "firstPage"; } } My server is tomcat 7, there is no error and warning when it is deployed. I also tried this with no luck: <mvc:default-servlet-handler/> Before I start Spring MVC, I can access index.html

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  • Ajax response seems to be getting lost

    - by Ringo Blancke
    I'm using the ddslick jquery dropdown plugin in conjunction with my Rails app. In view1, I have $('#challenges_dropdown').ddslick({ <snipped> onSelected: function (data) { $.ajax({ url: "/load_data", type: "GET", data: {"id": data.selectedData.value} }); } }); I.e., I make a call to my controller to load_data. The controller receives this correctly and then at the end, makes a call to render a separate view render "data" This view contains a script snippet that needs to run in order to update some elements of my original view. For some reason, this script snippet is just not running. I'm very confused. When I use a regular link with data-remote="true", then the whole process works perfectly. However, when I make an AJAX call, it fails. What's going on?? Thanks! Ringo

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  • Rails show view of one model with form for adding one child - nested attributes vs seperate controll

    - by SWR
    I have a basic two tiered model structure: Articles - Comments with one Article having many comments. What is the best way to add a "Add a comment" form to the bottom of the Articles show page? nested_attributes is overkill as I don't want to be able to edit all of the comments on the page, just to add one more. Is the best way even with Rails 2.3 still to make a separate controller and embed a form_for pointing to the other controller into the Articles show view? If so, how do I get validation errors to return to the article display page? I don't want to make a separate comment page/view... thanks

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  • Need help... how to add md5 to password field in php?

    - by jones
    Hi mates, i looking some help and nice attention here.. i bought some php script many years ago and now no suport anymore... i just want to add md5 to password field.. here my form: <?php $SQL = "SELECT * from USERS WHERE USERNAME = '$_SESSION[username]'"; $result = @mysql_query( $SQL ); $row = @mysql_fetch_array( $result ); include 'menu.php'; ?> <FORM METHOD="post" ACTION="?page=query_client"> <INPUT TYPE="hidden" NAME="controller" VALUE="USERS~update~account_details&up=1~<?php echo $row[ID]; ?>"> <TABLE CLASS="basictable"> <TR> <TD CLASS="tdmenu" WIDTH="40%">Username</TD> <TD CLASS="tdmenu" WIDTH="60%"> <b><?php echo $row[USERNAME]; ?></b> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Password *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="PASSWORD" NAME="PASSWORD" SIZE="40" VALUE="<?php echo $row[PASSWORD]; ?>"> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Email Address *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="EMAIL" SIZE="40" VALUE="<?php echo $row[EMAIL]; ?>"> </TD> </TR> <TR> <TD CLASS="tdmenu" WIDTH="40%">Full Name *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="FULLNAME" SIZE="40" VALUE="<?php echo $row[FULLNAME]; ?>"> </TD> <TR> <TD CLASS="tdmenu" WIDTH="40%">Address *</TD> <TD CLASS="tdmenu" WIDTH="60%"> <INPUT TYPE="text" NAME="ADDRESS1" SIZE="40" VALUE="<?php echo $row[ADDRESS1]; ?>"> </TD> </TR> <BR> <TABLE CLASS="basictable"> <TR> <TD CLASS="tdhead2" > <DIV ALIGN="CENTER"><B> <INPUT TYPE="submit" NAME="Submit" VALUE="Submit"> </B></DIV> </TD> </TR> </TABLE> </FORM> and the it self as query_client.php inside look like: <?PHP @session_start(); $controller = $_POST['controller']; $pieces = explode("~", $controller); $table = $pieces[0]; $qt = $pieces[1]; $return = $pieces[2]; $id = $pieces[3]; $hack = $pieces[4]; if ($qt == insert) $qt = 'INSERT INTO'; if ($qt == update) { $qt = 'UPDATE'; $end = "WHERE ID = '$id'"; } $pre = array_keys( $_POST ); mysql_query ("CREATE TABLE IF NOT EXISTS `$table` (`ID` INT NOT NULL AUTO_INCREMENT , PRIMARY KEY ( `id` ) )"); $count = count($pre); $count = $count - 2; $sql = "$qt $table SET"; for ($i=0; $i < $count; $i++) { $x=$i+1; $y = $_POST[$pre[$x]]; $d = $y; mysql_query ("ALTER TABLE `$table` ADD `$pre[$x]` TEXT NOT NULL"); $sql .= " `$pre[$x]` = '$d',"; } $sql .= " ID = '$id' $end"; $query = mysql_query($sql) or die("$sql_error" . mysql_error()); if (empty($hack)) { } else { $pieces = explode("/", $hack); $h0 = $pieces[0]; $h1 = $pieces[1]; $h2 = $pieces[2]; $h3 = $pieces[3]; $h4 = $pieces[4]; $h5 = $pieces[5]; mysql_query ("ALTER TABLE `$table` $h0 $h1 $h2 $h3 $h4 $h5"); $query = mysql_query($sql) or die("$sql_error" . mysql_error()); } if (isset($_GET[inc])) include "$_GET[inc].php"; ?> so please help me how to add md5 in PASSWORD field? thanks in advance..

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  • Add Page Parameter in Zend Framework Doesn't Work

    - by deerawan
    Hello guys, I've been trying to figure this out these days. I got a problem when I want to add 'page' parameter in my URL for my pagination. This is my router -addRoute('budi',new Zend_Controller_Router_Route(':lang/budi',array('controller' = 'budi', 'action' = 'index', 'page' = 1), array('lang'=$s, 'page' = '\d+'))) -addRoute('budi1',new Zend_Controller_Router_Route(':lang/budi/page/:page',array('controller' = 'budi', 'action' = 'index', 'page' = 1), array('lang'=$s, 'page' = '\d+'))) Then I access my URL http://localhost/learningsystem/en/budi but when I hover on my pagination links, the page parameter doesn't appear. The URL is still http://localhost/learningsystem/en/budi but if I enter same URL with index in the end like this one http://localhost/learningsystem/en/budi/index or like this one http://localhost/learningsystem/en/budi/page/1 the page parameter appears perfectly when I click the page 2 link http://localhost/learningsystem/en/budi/index/page/2 Actually, I don't want include 'index' or 'page' at first in my URL. Anyway, I use default pagination.phtml template from Zend. Anyone please help me to solve this problem? Thank you very much

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