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  • Using one data source across multiple views in Kendo UI SPA

    - by user3731783
    I am trying to build a Kendo UI SPA. I have two views. View 1 (appListView) shows Application Details in a grid and view 2 (activityView) will have a dropdown for application names and a grid that shows the activity for selected application As I am loading all the application details on the loading of view 1, I would like to re-use those details to populate the dropdown on view 2. Please see my code below. Everything works fine but when I go to View 2 it makes a call to the service again to get application details. I would like to use the existing data if it is already loaded and if the uses comes to view 2 directly then it should get application data also. I am not sure what I am missing in the code. View Markup: <script id="appListView" type="text/x-kendo-template"> <h3 data-bind="html: displayName"></h3> <div data-role="grid" data-editable="{'mode':'popup'}" data-bind="source: items" data-columns="[ {'field': 'Name'}, {'field': 'ContactEmail','title':'Contact Email'} ]"> </div> </script> <script id="" type="text\x-kendo-template"> <div> Activity for Application&nbsp;&nbsp; <input name="AppName" data-role="dropdownlist" data-source="appsModel.items" data-text-field="Name" data-value-field="Id" data-option-label="Choose an application name" style="width:250px;" /> </div> <div id="Activities" data-role="grid" data-bind="source: items" data-auto-bind="false" data-columns="[ {'field': 'Domain','title':'Domain'}, {'field': 'ActivityType','title':'Activity Type'} ]"> </div> </script> js with DataSource and View Model: //data sources var applications = new kendo.data.DataSource({ schema: { model: { id: "Id" } }, serverFiltering : true, transport: { read: { url: '/api/App', dataType: 'json', type:'GET' } } }); var activities = new kendo.data.DataSource({ schema: { model: { id: "Id" } }, transport: { read: { url: '/api/Activity', dataType: 'json', type: 'GET' }, parameterMap: function (data, type) { if (type == "read") { return 'appId=' + $("#AppName").val() ; } } } }); //Models var appsModel = kendo.observable({ items: applications, displayName: 'My Applications' }); var activityModel = kendo.observable({ items: activities, onAppChange: function(t){ $("#Activities").data("kendoGrid").dataSource.read(); }, dispayName: 'Application Activities' }); //views var layout = new kendo.Layout("layout-template"); var appListView = new kendo.View("appListView", { model: appsModel }); var activityView = new kendo.View("activityView", { model: activityModel }); Thank you for taking time to read this long question.

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  • zend_application showing blank page

    - by daniel
    Hi, I'm using Zend_Application to bootstrap my app. class Bootstrap extends Zend_Application_Bootstrap_Bootstrap { public static $frontController = null; public static $registry = null; protected function _initEnvironment() { ini_set('display_errors', true); //date_default_timezone_set('Europe/London'); } protected function _initRegistry() { self::$registry = new Zend_Registry(array(), ArrayObject::ARRAY_AS_PROPS); Zend_Registry::setInstance(self::$registry); } protected function _initConfiguration() { $config = new Zend_Config_Ini( BASE_PATH . '/data/server/settings.ini', APPLICATION_ENV ); self::$registry->configuration = $config; } protected function _initLogging() { $config = self::$registry->configuration; $logger = new Zend_Log(new Zend_Log_Writer_Stream($config->logging->file)); Zend_Registry::set('logger', $logger); } protected function _initFrontController() { self::$frontController = Zend_Controller_Front::getInstance(); self::$frontController->throwExceptions(true); self::$frontController->returnResponse(true); self::$frontController->setControllerDirectory( APPLICATION_PATH .'/controllers' ); self::$frontController->setParam('registry', self::$registry); return self::$frontController; } protected function _initView() { $config = self::$registry->configuration; $view = new Zend_View; $viewRenderer = new Zend_Controller_Action_Helper_ViewRenderer($view); Zend_Controller_Action_HelperBroker::addHelper($viewRenderer); Zend_Layout::startMvc( array( 'layoutPath' => APPLICATION_PATH . "/layouts/scripts", 'layout' => "layout" ) ); return $view; } protected function _initDatabase() { $config = self::$registry->configuration; $params = array('host' => $config->database->hostname, 'username' => $config->database->username, 'password' => $config->database->password, 'dbname' => $config->database->database); $db = Zend_Db::factory($config->database->type, $params); Zend_Registry::set('db', $db); } protected function _initPlaceholders() { $view = $this->getResource('View'); $view->doctype('XHTML1_STRICT'); $view->headTitle('Greplin') ->setSeparator(' / '); $view->headLink()->prependStylesheet('/src/css/header.css'); $view->headScript()->prependFile('/js/site.js'); return $view; } } When I run the app I get a blank page. Filenames / paths are intact. If I add die() to the bottom of my layout.phtml, I get the page. Something is resetting the headers and sending a blank page. My error reporting is on and I get unrelated errors. What could this be?! Thanks!

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  • Deleting Multiple rows from a TableView

    - by Sid
    hi Frnz, i want to delete multiple rows from a table view based on users selection.obviously i cant use didSelectRowAtIndexPath method coz it will be called for every row selected. i want to allow user to select multiple rows for deletion and then delete them in one go...Is it possible if yes then how to go about it.Also i am using a single view based project and i want the header of table view changed to "Delete" on the same view when the user want to delete the rows from the view. Thx

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  • with "viewDidLoad" my viewController take much time to appear!

    - by dingua
    hi, when i load my viewController i used "viewDidLoad"method to init my view ,but this take much time to make the view appeared .So i had the idea to use "viewDidAppear" method to accelerate the appearance of my view but the load of the informations about my view are now loaded to the memory every time that i push my view (which is normal) or i pop to it(and there is my problem) Have you an idea?

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  • Sub-viewController doesn't get autorotation notifications, bug?

    - by Shizam
    If I have a view (and its controller) and I override the willAnimateRotationToInterfaceOrientation method so I can respond to autorotation events everything works fine and dandy. Now if I create another viewController and add its view to the first viewController's view via: [firstViewController.view addSubview:secondViewController.view] The secondViewController's willAnimateRotationToInterfaceOrientation method isn't called. What gives? Thanks, Sam

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  • A question is related to state maintainance

    - by user217572
    my question is like that My 5 th view is Acontroller and it has 1 UIButton.when i click on this UIButton my Bcontroller's view opens.this operation wrks perfectly. but i'm actually doing state maintainanace.when i reach to 5 th view of Acontroller.after that i press home button and then when i again click on application as per my state maintainance code 5 th view of Acontroller opens .but when i click on it's UIButton Bcontroller's view not open.why A code of UIButton is as below [self.navigationController pushViewController:bcontroller animated:YES]; bcontroller is nothing but object of Bcontroller

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  • what's the right way to cause a subview to redraw when the device orientation changes?

    - by RobertL
    I have a view controller with a view and one subview. When the device orientation changes the view auto-redraws but the subview doesn't. If I explicitly do [subview setNeedsDisplay] it redraws but I don't have a logical place to put that call in my code. And, since I don't have to explicitly tell the view to redraw, it seems counter-intuitive to tell the subview to redraw. Is there a way to make the subview auto-redraw when the view redraws?

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  • invoke a method on the click of backbutton

    - by praseed
    hi friends... Does anyone know how can i invoke a method on the click of the backbarButton of a viewcontroller... wat i have are two table view controllers..one list view and another detail view.... the detail view is pushed in to the navigation controller when an item is clicked in the list view. when the Back bar button is clicked i want to invoke a function... Pls any help will be appreciated..

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  • Stack Info button above UIView in Utility App

    - by bgw
    I've started creating a iPhone Utility app (main view and flip view). I want to draw some graphics in the Main view, so I dragged a UIView object onto it. This works, but I find that if I resize the UIView to fill the Main view, it covers the Info button that invokes the Flip view. Is there any way to get the Info button to appear on top of the UIView? In IB? In code?

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  • How to change the default "double click" action of a web service in a class library (VS2010)?

    - by JL
    I have a web service defined as follows, residing in a class library: [WebService(Namespace = "http://comp.com/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line. // [System.Web.Script.Services.ScriptService] public class SendingItems_new : System.Web.Services.WebService When I double click it, instead of going to code view, it shows the design view. I NEVER use design view, so how can I get it to open up code view instead, its very annoying having to flick from design view each time. Thank you

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  • Getting Started With Sinatra

    - by Liam McLennan
    Sinatra is a Ruby DSL for building web applications. It is distinguished from its peers by its minimalism. Here is hello world in Sinatra: require 'rubygems' require 'sinatra' get '/hi' do "Hello World!" end A haml view is rendered by: def '/' haml :name_of_your_view end Haml is also new to me. It is a ruby-based view engine that uses significant white space to avoid having to close tags. A hello world web page in haml might look like: %html %head %title Hello World %body %div Hello World You see how the structure is communicated using indentation instead of opening and closing tags. It makes views more concise and easier to read. Based on my syntax highlighter for Gherkin I have started to build a sinatra web application that publishes syntax highlighted gherkin feature files. I have found that there is a need to have features online so that customers can access them, and so that they can be linked to project management tools like Jira, Mingle, trac etc. The first thing I want my application to be able to do is display a list of the features that it knows about. This will happen when a user requests the root of the application. Here is my sinatra handler: get '/' do feature_service = Finding::FeatureService.new(Finding::FeatureFileFinder.new, Finding::FeatureReader.new) @features = feature_service.features(settings.feature_path, settings.feature_extensions) haml :index end The handler and the view are in the same scope so the @features variable will be available in the view. This is the same way that rails passes data between actions and views. The view to render the result is: %h2 Features %ul - @features.each do |feature| %li %a{:href => "/feature/#{feature.name}"}= feature.name Clearly this is not a complete web page. I am using a layout to provide the basic html page structure. This view renders an <li> for each feature, with a link to /feature/#{feature.name}. Here is what the page looks like: When the user clicks on one of the links I want to display the contents of that feature file. The required handler is: get '/feature/:feature' do @feature_name = params[:feature] feature_service = Finding::FeatureService.new(Finding::FeatureFileFinder.new, Finding::FeatureReader.new) # TODO replace with feature_service.feature(name) @feature = feature_service.features(settings.feature_path, settings.feature_extensions).find do |feature| feature.name == @feature_name end haml :feature end and the view: %h2= @feature.name %pre{:class => "brush: gherkin"}= @feature.description %div= partial :_back_to_index %script{:type => "text/javascript", :src => "/scripts/shCore.js"} %script{:type => "text/javascript", :src => "/scripts/shBrushGherkin.js"} %script{:type => "text/javascript" } SyntaxHighlighter.all(); Now when I click on the Search link I get a nicely formatted feature file: If you would like see the full source it is available on bitbucket.

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  • Configuring JPA Primary key sequence generators

    - by pachunoori.vinay.kumar(at)oracle.com
    This article describes the JPA feature of generating and assigning the unique sequence numbers to JPA entity .This article provides information on jpa sequence generator annotations and its usage. UseCase Description Adding a new Employee to the organization using Employee form should assign unique employee Id. Following description provides the detailed steps to implement the generation of unique employee numbers using JPA generators feature Steps to configure JPA Generators 1.Generate Employee Entity using "Entities from Table Wizard". View image2.Create a Database Connection and select the table "Employee" for which entity will be generated and Finish the wizards with default selections. View image 3.Select the offline database sources-Schema-create a Sequence object or you can copy to offline db from online database connection. View image 4.Open the persistence.xml in application navigator and select the Entity "Employee" in structure view and select the tab "Generators" in flat editor. 5.In the Sequence Generator section,enter name of sequence "InvSeq" and select the sequence from drop down list created in step3. View image 6.Expand the Employees in structure view and select EmployeeId and select the "Primary Key Generation" tab.7.In the Generated value section,select the "Use Generated value" check box ,select the strategy as "Sequence" and select the Generator as "InvSeq" defined step 4. View image   Following annotations gets added for the JPA generator configured in JDeveloper for an entity To use a specific named sequence object (whether it is generated by schema generation or already exists in the database) you must define a sequence generator using a @SequenceGenerator annotation. Provide a unique label as the name for the sequence generator and refer the name in the @GeneratedValue annotation along with generation strategy  For  example,see the below Employee Entity sample code configured for sequence generation. EMPLOYEE_ID is the primary key and is configured for auto generation of sequence numbers. EMPLOYEE_SEQ is the sequence object exist in database.This sequence is configured for generating the sequence numbers and assign the value as primary key to Employee_id column in Employee table. @SequenceGenerator(name="InvSeq", sequenceName = "EMPLOYEE_SEQ")   @Entity public class Employee implements Serializable {    @Id    @Column(name="EMPLOYEE_ID", nullable = false)    @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="InvSeq")   private Long employeeId; }   @SequenceGenerator @GeneratedValue @SequenceGenerator - will define the sequence generator based on a  database sequence object Usage: @SequenceGenerator(name="SequenceGenerator", sequenceName = "EMPLOYEE_SEQ") @GeneratedValue - Will define the generation strategy and refers the sequence generator  Usage:     @GeneratedValue(strategy = GenerationType.SEQUENCE, generator="name of the Sequence generator defined in @SequenceGenerator")

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  • Configurable Objects - Introduction

    - by Anthony Shorten
    One of the interesting facilities in the framework is Configurable Object functionality (it is also known as Task Optimization and also known as Cool Tools). The idea is that any implementation can create their own views of the base product objects and services and implement functionality against those new views. For example, in Oracle Utilities Customer Care and Billing, there is a Person object. That object is used to store and manage information about individuals as well as companies. In the base product you would use the Person Maintenance screen and fill in some of the screen when you wanted to register or maintain and individual as well and fill out other parts of the screen when you wanted to register or maintain a company. This can be somewhat confusing to some customers. Using Configurable Objects this can be simplified. A business object can be created that is a view of the any object. For example, you could create a Human business object which would cover the aspects of the Person object pertaining to an individual and a Company business object to cover the aspects unique to a company. Even the tag names (i.e. Field Names) in the object can be changed to be more what the implementation is familiar with. The object can also restructure the object. For example, a common identifier for an individual in the USA is the Social Security number, this value is a Person Identifier (as this varies in each country). In the new Human object you can remap the Person Identifier as a Social Security number. To define a Business Object you use a schema editor built into the browser user interface and use a mapping language to setup the business objects. An example of the language is shown below in an extract of the schema for the Human business object. As you can see there are mapping as well as formatting and other tags. This information can be built manually or using a wizard which generates the base structure for you to alter. This is all stored as meta data when saved. Once a Business object is built it can be used as basis for code, other business objects (we support inheritance), called by a screen (called a UI Map) or even as a Web Service. This is just a start with Configurable Objects as you can also create views of base services called Business Services, Service Scripts used for non-object or complex object processing (as well as other things), UI Maps used for screens and Data Areas to reuse definitions across multiple objects. Configurable Objects are powerful and I only really touched on them here. Over the next few months I hope to add lots more entries about them.

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  • Strengthening code with possibly useless exception handling

    - by rdurand
    Is it a good practice to implement useless exception handling, just in case another part of the code is not coded correctly? Basic example A simple one, so I don't loose everybody :). Let's say I'm writing an app that will display a person's information (name, address, etc.), the data being extracted from a database. Let's say I'm the one coding the UI part, and someone else is writing the DB query code. Now imagine that the specifications of your app say that if the person's information is incomplete (let's say, the name is missing in the database), the person coding the query should handle this by returning "NA" for the missing field. What if the query is poorly coded and doesn't handle this case? What if the guy who wrote the query handles you an incomplete result, and when you try to display the informations, everything crashes, because your code isn't prepared to display empty stuff? This example is very basic. I believe most of you will say "it's not your problem, you're not responsible for this crash". But, it's still your part of the code which is crashing. Another example Let's say now I'm the one writing the query. The specifications don't say the same as above, but that the guy writing the "insert" query should make sure all the fields are complete when adding a person to the database to avoid inserting incomplete information. Should I protect my "select" query to make sure I give the UI guy complete informations? The questions What if the specifications don't explicitly say "this guy is the one in charge of handling this situation"? What if a third person implements another query (similar to the first one, but on another DB) and uses your UI code to display it, but doesn't handle this case in his code? Should I do what's necessary to prevent a possible crash, even if I'm not the one supposed to handle the bad case? I'm not looking for an answer like "(s)he's the one responsible for the crash", as I'm not solving a conflict here, I'd like to know, should I protect my code against situations it's not my responsibility to handle? Here, a simple "if empty do something" would suffice. In general, this question tackles redundant exception handling. I'm asking it because when I work alone on a project, I may code 2-3 times a similar exception handling in successive functions, "just in case" I did something wrong and let a bad case come through.

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  • Creating predefinied camera views - How do I move the camera to make sense while using Controller?

    - by Deukalion
    I'm trying to understand 3D but the one thing I can't seem to understand is the Camera. Right now I'm rendering four 3D Cubes with textures and I set the Project Matrix: public BasicCamera3D(float fieldOfView, float aspectRatio, float clipStart, float clipEnd, Vector3 cameraPosition, Vector3 cameraLookAt) { projection_fieldOfView = MathHelper.ToRadians(fieldOfView); projection_aspectRatio = aspectRatio; projection_clipstart = clipStart; projection_clipend = clipEnd; matrix_projection = Matrix.CreatePerspectiveFieldOfView(projection_fieldOfView, aspectRatio, clipStart, clipEnd); view_cameraposition = cameraPosition; view_cameralookat = cameraLookAt; matrix_view = Matrix.CreateLookAt(cameraPosition, cameraLookAt, Vector3.Up); } BasicCamera3D gameCamera = new BasicCamera3D(45f, GraphicsDevice.Viewport.AspectRatio, 1.0f, 1000f, new Vector3(0, 0, 8), new Vector3(0, 0, 0)); This creates a sort of "Top-Down" camera, with 8 (still don't get the unit type here - it's not pixels I guess?) But, if I try to position the camera at the side to make "Side-View" or "Reverse Side View" camera, the camera is rotating to much until it's turned around it a couple of times. I render the boxes at: new Vector3(-1, 0, 0) new Vector3(0, 0, 0) new Vector3(1, 0, 0) new Vector3(1, 0, 1) and with the Top-Down camera it shows good, but I don't get how I can make the camera show the side or 45 degrees from top (Like 3rd person action games) because the logic doesn't make sense. Also, since every object you render needs a new BasicEffect with a new projection/view/world - can you still use the "same" camera always so you don't have to create a new View/Matrix and such for each object. It's seems weird. If someone could help me get the camera to navigate around my objects "naturally" so I can be able to set a few predtermined views to choose from it would be really helpful. Are there some sort of algorithm to calculate the view for this and perhaps not simply one value? Examples: Top-Down-View: I have an object at 0, 0, 0 when I turn the right stick on the Xbox 360 Controller it should rotate around that object kind of, not flip and turn upside down, disappear and then magically appear as a tiny dot somewhere I have no clue where it is like it feels like it does now. Side-View: I have an object at 0, 0, 0 when I rotate to sides or up and down, the camera should be able to show a little more of the periphery to each side (depending on which you look at), and the same while moving up or down.

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  • Simplifying C++11 optimal parameter passing when a copy is needed

    - by Mr.C64
    It seems to me that in C++11 lots of attention was made to simplify returning values from functions and methods, i.e.: with move semantics it's possible to simply return heavy-to-copy but cheap-to-move values (while in C++98/03 the general guideline was to use output parameters via non-const references or pointers), e.g.: // C++11 style vector<string> MakeAVeryBigStringList(); // C++98/03 style void MakeAVeryBigStringList(vector<string>& result); On the other side, it seems to me that more work should be done on input parameter passing, in particular when a copy of an input parameter is needed, e.g. in constructors and setters. My understanding is that the best technique in this case is to use templates and std::forward<>, e.g. (following the pattern of this answer on C++11 optimal parameter passing): class Person { std::string m_name; public: template <class T, class = typename std::enable_if < std::is_constructible<std::string, T>::value >::type> explicit Person(T&& name) : m_name(std::forward<T>(name)) { } ... }; A similar code could be written for setters. Frankly, this code seems boilerplate and complex, and doesn't scale up well when there are more parameters (e.g. if a surname attribute is added to the above class). Would it be possible to add a new feature to C++11 to simplify code like this (just like lambdas simplify C++98/03 code with functors in several cases)? I was thinking of a syntax with some special character, like @ (since introducing a &&& in addition to && would be too much typing :) e.g.: class Person { std::string m_name; public: /* Simplified syntax to produce boilerplate code like this: template <class T, class = typename std::enable_if < std::is_constructible<std::string, T>::value >::type> */ explicit Person(std::string@ name) : m_name(name) // implicit std::forward as well { } ... }; This would be very convenient also for more complex cases involving more parameters, e.g. Person(std::string@ name, std::string@ surname) : m_name(name), m_surname(surname) { } Would it be possible to add a simplified convenient syntax like this in C++? What would be the downsides of such a syntax?

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  • Error about 'invalid JSON' with couchDB view but the json's fine...

    - by Chris Huang-Leaver
    I am trying to setup the following view on CouchDB { "_id":"_design/id", "_rev":"1-9be2e55e05ac368da3047841f301203d", "language":"javascript", "views":{ "by_id":{ "map" : "function(doc) { emit(doc.id, doc)}" },"from_user_id":{ "map" : "function(doc) { if (doc.from_user_id) {emit(doc.from_user_id, doc)}}"}, "from_user":{ "map" : "function(doc) { if (doc.from_user) {emit(doc.from_user, doc)}}"}, "to_user_id":{ "map" : "function(doc) {if (doc.to_user_id){ emit(doc.to_user_id, doc)}}"}, "to_user":{ "map" : "function(doc) {if (doc.to_user){ emit(doc.to_user, doc)}}" }, "max_id":{ "map" : "function(doc) { if (doc.id) {emit(doc._id, eval(doc.id))}}", "reduce" :"function(key,value) { a = value[0]; for (i=1; i <value.length; ++i){a = Math.max(a,value[i])} return a}" } } } when I try to 'PUT' this using curl: curl -X PUT -d keys.json $CDB/_design/id {"error":"bad_request","reason":"invalid UTF-8 JSON"} I know it's not invalid JSON, because I tested it using the 'json' library built into Python 2.6, it loads fine. JS screw ups give me the error 'must evaluate to a function' What else might be wrong with it?

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  • How to display the image in the web view using html code?

    - by Madan Mohan
    Hi Guys, I am getting the data form Parser, In that I am getting a set of urls. Using these urls can I make image url by appending any data values getting from the parser. http://musicbrainz.org/ws/1/artist/f27ec8db-af05-4f36-916e-3d57f91ecf5e?type=xml&inc=url-rels+artist-rels using these url i get data and set of urls.They are not providing image url or thumbnail. So, Is it possible to get or form an image url from parser (http://musicbrainz.org/ws/1/artist/f27ec8db-af05-4f36-916e-3d57f91ecf5e?type=xml&inc=url-rels+artist-rels) and display in the web view. Please help me from this problem. Thank You, Madan Mohan.

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  • How to add a pulldown button in a view's toolbar?

    - by madgnome
    I need to add a pulldown button to a view's toolbar in an Eclipse plugin. Actually buttons in the toolbar are added like that : <extension point="org.eclipse.ui.viewActions"> <viewContribution id="..." targetId="$MyViewId$"> <action id="..." toolbarPath="action1" class="Class extending Action and implementing IViewActionDelegate"> </action> </viewContribution> </extension>

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  • How can I set a highlighted image on a table view cell?

    - by nevan
    I've followed the code in Apple's AdvancedTableViewCells and built a table view with a background image for cells. Now I want to change it so that instead of the blue highlight colour, it shows a darker version of my image. What are the steps I need to follow to do this? I'm using a UITableViewCell subclass with a custom NIB. My background image is implemented as the cell.backgroundView. The steps I've take so far are: Change the selectionStyle of the cell to "None" Set the Highlight colour on my UILabel subviews to a light colour Create a darker version of my background as a separate image Override setSelected: animated: I'm wondering about the next steps.

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  • How can a user view profile info of other users?

    - by Arvind Singh
    I have stored profile info using this code ProfileBase userprofile = HttpContext.Current.Profile; userprofile.SetPropertyValue("FirstName", TextBoxFirstName.Text); userprofile.SetPropertyValue("LastName", TextBoxLastName.Text); userprofile.SetPropertyValue("AboutMe", TextBoxAboutMe.Text); userprofile.SetPropertyValue("ContactNo", TextBoxContactNo.Text); and in web.config <profile enabled="true" defaultProvider="AspNetSqlProfileProvider"> <properties> <add name="FirstName" type="String" /> <add name="LastName" type="String" /> <add name="AboutMe" type="String" /> <add name="ContactNo" type="String" /> </properties> </profile> The profile info is stored and every user is able to view his own profile info using something like this TextBoxFirstName.Text = HttpContext.Current.Profile.GetPropertyValue("FirstName").ToString(); How to fetch profile info of other user say a user types the username of other user in a text box and clicks a button?

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  • How set panel Default Button that is inside a details view in asp.net?

    - by Avinash
    <asp:panel ID="Panel1" runat="server"> <asp:DetailsView ID="DetailsView1" .... <asp:templatefield ShowHeader="False"> <insertitemtemplate> <asp:Button ID="btnAdd" runat="server" CausesValidation="True" CommandName="Insert" Text="Insert"></asp:Button> ... <asp:DetailsView> </asp:panel> and i write the code for setting the panels default button in details view's DataBound event Button btnAdd = new Button(); btnAdd = DetailsView1.Rows[indexNumber].FindControl("btnAdd") as Button; Panel1.DefaultButton = btnAdd.UniqueID; but I get the error : The DefaultButton of 'Panel1' must be the ID of a control of type IButtonControl.

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  • How can I get a view of favorite user documents by user in Couchdb map/reduce?

    - by Jeremy Raymond
    My Couchdb database as a main document type that looks something like: { "_id" : "doc1", "type" : "main_doc", "title" : "the first doc" ... } There is another type of document that stores user information. I want users to be able to tag documents as favorites. Different users can save the same or different documents as favorites. My idea was to introduce a favorite document to track this something like: { "_id" : "fav1", "type" : "favorite", "user_id" : "user1", "doc_id" : "doc1" } It's easy enough to create a view with user_id as the key to get a list of their favorite doc IDs. E.g: function(doc) { if (doc.type == "favorite") { emit(doc.user_id, doc.doc_id); } } However I want to list of favorites to display the user_id, doc_id and title from the document. So output something like: { "key" : "user1", "value" : ["doc1", "the first doc"] }

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