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  • How do I override the OK/Cancel button of new list item form in SharePoint?

    - by jlech
    I have a custom list in SharePoint, and I want to override the OK/Cancel buttons that are in the New Item form (The form displayed when you click "New" in the default view of the list). I want the saving logic to remain intact, but I just want to change the default page it redirects to, ideally, to a whole separate page on the site that's not a view of the list. Is there any way I can achieve this? Thanks in advance!

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  • How can I implement a 'select all' check-box on my CRM 4 custom form?

    - by Gryphoenix
    I am working on a custom CRM form with numerous checkboxes, organized by sections. I would like to implement a 'select all' feature to the form and am trying to understand how to format the JavaScript. My research thus far has pointed me to the possibility of using a FOR statement to iterate through all of the elements in the section I want to process, setting their values accordingly, but am unsure of which document.getElements ... method to utilize.

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  • How to add a button on outlook toolbar to a custom form?

    - by eqbridges
    Hi I have an Outlook form that I'd like to provide ready access to by adding a button or link to it on the outlook toolbar. How can I customize the toolbar to do this? Essentially, a single click of the button on the toolbar should bring up the custom form. This should work in Outlook 2003 and 2007 (preferably). If it only works in 2007 that would be acceptable. Thanks!

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  • Javascript to change image form submit button src not working.

    - by james
    I'm trying to change the src of an image form submit button using an onclick, but it doesn't seem to be working correctly. Am I missing something? <input class="submit_image" id="my_form_button" onclick="$('my_form_button').src='/images/buttons/submitting.gif'" src="/images/buttons/submit.gif" type="image" /> I've also tried using the same JS on the form tag using onsubmit with no luck.

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  • Is any tool can help create/fix a table into normal form?

    - by WuYi
    Hi,I know the importance of being normal in database design. But many people always lives with broken windows. Is any tool can help create/fix a table to normal form? I mean to force developer create table in normal form, or help to check if the table being normal base on existed data within the table. Thanks……

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  • How do I add a custom table to a form in another module in Drupal?

    - by Kareed
    I am trying to make a module to add a table to a form in another module. I found I can add the new data in a module_form_alter hook but how to I get it to run through a theme hook? The module I am trying to modify has a theme hook for the page I want to modify. I don't want to change the original form I just want to add a table with new data below it. Thanks

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  • Parallelism in .NET – Part 3, Imperative Data Parallelism: Early Termination

    - by Reed
    Although simple data parallelism allows us to easily parallelize many of our iteration statements, there are cases that it does not handle well.  In my previous discussion, I focused on data parallelism with no shared state, and where every element is being processed exactly the same. Unfortunately, there are many common cases where this does not happen.  If we are dealing with a loop that requires early termination, extra care is required when parallelizing. Often, while processing in a loop, once a certain condition is met, it is no longer necessary to continue processing.  This may be a matter of finding a specific element within the collection, or reaching some error case.  The important distinction here is that, it is often impossible to know until runtime, what set of elements needs to be processed. In my initial discussion of data parallelism, I mentioned that this technique is a candidate when you can decompose the problem based on the data involved, and you wish to apply a single operation concurrently on all of the elements of a collection.  This covers many of the potential cases, but sometimes, after processing some of the elements, we need to stop processing. As an example, lets go back to our previous Parallel.ForEach example with contacting a customer.  However, this time, we’ll change the requirements slightly.  In this case, we’ll add an extra condition – if the store is unable to email the customer, we will exit gracefully.  The thinking here, of course, is that if the store is currently unable to email, the next time this operation runs, it will handle the same situation, so we can just skip our processing entirely.  The original, serial case, with this extra condition, might look something like the following: foreach(var customer in customers) { // Run some process that takes some time... DateTime lastContact = theStore.GetLastContact(customer); TimeSpan timeSinceContact = DateTime.Now - lastContact; // If it's been more than two weeks, send an email, and update... if (timeSinceContact.Days > 14) { // Exit gracefully if we fail to email, since this // entire process can be repeated later without issue. if (theStore.EmailCustomer(customer) == false) break; customer.LastEmailContact = DateTime.Now; } } .csharpcode, .csharpcode pre { font-size: small; color: black; font-family: consolas, "Courier New", courier, monospace; background-color: #ffffff; /*white-space: pre;*/ } .csharpcode pre { margin: 0em; } .csharpcode .rem { color: #008000; } .csharpcode .kwrd { color: #0000ff; } .csharpcode .str { color: #006080; } .csharpcode .op { color: #0000c0; } .csharpcode .preproc { color: #cc6633; } .csharpcode .asp { background-color: #ffff00; } .csharpcode .html { color: #800000; } .csharpcode .attr { color: #ff0000; } .csharpcode .alt { background-color: #f4f4f4; width: 100%; margin: 0em; } .csharpcode .lnum { color: #606060; } Here, we’re processing our loop, but at any point, if we fail to send our email successfully, we just abandon this process, and assume that it will get handled correctly the next time our routine is run.  If we try to parallelize this using Parallel.ForEach, as we did previously, we’ll run into an error almost immediately: the break statement we’re using is only valid when enclosed within an iteration statement, such as foreach.  When we switch to Parallel.ForEach, we’re no longer within an iteration statement – we’re a delegate running in a method. This needs to be handled slightly differently when parallelized.  Instead of using the break statement, we need to utilize a new class in the Task Parallel Library: ParallelLoopState.  The ParallelLoopState class is intended to allow concurrently running loop bodies a way to interact with each other, and provides us with a way to break out of a loop.  In order to use this, we will use a different overload of Parallel.ForEach which takes an IEnumerable<T> and an Action<T, ParallelLoopState> instead of an Action<T>.  Using this, we can parallelize the above operation by doing: Parallel.ForEach(customers, (customer, parallelLoopState) => { // Run some process that takes some time... DateTime lastContact = theStore.GetLastContact(customer); TimeSpan timeSinceContact = DateTime.Now - lastContact; // If it's been more than two weeks, send an email, and update... if (timeSinceContact.Days > 14) { // Exit gracefully if we fail to email, since this // entire process can be repeated later without issue. if (theStore.EmailCustomer(customer) == false) parallelLoopState.Break(); else customer.LastEmailContact = DateTime.Now; } }); There are a couple of important points here.  First, we didn’t actually instantiate the ParallelLoopState instance.  It was provided directly to us via the Parallel class.  All we needed to do was change our lambda expression to reflect that we want to use the loop state, and the Parallel class creates an instance for our use.  We also needed to change our logic slightly when we call Break().  Since Break() doesn’t stop the program flow within our block, we needed to add an else case to only set the property in customer when we succeeded.  This same technique can be used to break out of a Parallel.For loop. That being said, there is a huge difference between using ParallelLoopState to cause early termination and to use break in a standard iteration statement.  When dealing with a loop serially, break will immediately terminate the processing within the closest enclosing loop statement.  Calling ParallelLoopState.Break(), however, has a very different behavior. The issue is that, now, we’re no longer processing one element at a time.  If we break in one of our threads, there are other threads that will likely still be executing.  This leads to an important observation about termination of parallel code: Early termination in parallel routines is not immediate.  Code will continue to run after you request a termination. This may seem problematic at first, but it is something you just need to keep in mind while designing your routine.  ParallelLoopState.Break() should be thought of as a request.  We are telling the runtime that no elements that were in the collection past the element we’re currently processing need to be processed, and leaving it up to the runtime to decide how to handle this as gracefully as possible.  Although this may seem problematic at first, it is a good thing.  If the runtime tried to immediately stop processing, many of our elements would be partially processed.  It would be like putting a return statement in a random location throughout our loop body – which could have horrific consequences to our code’s maintainability. In order to understand and effectively write parallel routines, we, as developers, need a subtle, but profound shift in our thinking.  We can no longer think in terms of sequential processes, but rather need to think in terms of requests to the system that may be handled differently than we’d first expect.  This is more natural to developers who have dealt with asynchronous models previously, but is an important distinction when moving to concurrent programming models. As an example, I’ll discuss the Break() method.  ParallelLoopState.Break() functions in a way that may be unexpected at first.  When you call Break() from a loop body, the runtime will continue to process all elements of the collection that were found prior to the element that was being processed when the Break() method was called.  This is done to keep the behavior of the Break() method as close to the behavior of the break statement as possible. We can see the behavior in this simple code: var collection = Enumerable.Range(0, 20); var pResult = Parallel.ForEach(collection, (element, state) => { if (element > 10) { Console.WriteLine("Breaking on {0}", element); state.Break(); } Console.WriteLine(element); }); If we run this, we get a result that may seem unexpected at first: 0 2 1 5 6 3 4 10 Breaking on 11 11 Breaking on 12 12 9 Breaking on 13 13 7 8 Breaking on 15 15 What is occurring here is that we loop until we find the first element where the element is greater than 10.  In this case, this was found, the first time, when one of our threads reached element 11.  It requested that the loop stop by calling Break() at this point.  However, the loop continued processing until all of the elements less than 11 were completed, then terminated.  This means that it will guarantee that elements 9, 7, and 8 are completed before it stops processing.  You can see our other threads that were running each tried to break as well, but since Break() was called on the element with a value of 11, it decides which elements (0-10) must be processed. If this behavior is not desirable, there is another option.  Instead of calling ParallelLoopState.Break(), you can call ParallelLoopState.Stop().  The Stop() method requests that the runtime terminate as soon as possible , without guaranteeing that any other elements are processed.  Stop() will not stop the processing within an element, so elements already being processed will continue to be processed.  It will prevent new elements, even ones found earlier in the collection, from being processed.  Also, when Stop() is called, the ParallelLoopState’s IsStopped property will return true.  This lets longer running processes poll for this value, and return after performing any necessary cleanup. The basic rule of thumb for choosing between Break() and Stop() is the following. Use ParallelLoopState.Stop() when possible, since it terminates more quickly.  This is particularly useful in situations where you are searching for an element or a condition in the collection.  Once you’ve found it, you do not need to do any other processing, so Stop() is more appropriate. Use ParallelLoopState.Break() if you need to more closely match the behavior of the C# break statement. Both methods behave differently than our C# break statement.  Unfortunately, when parallelizing a routine, more thought and care needs to be put into every aspect of your routine than you may otherwise expect.  This is due to my second observation: Parallelizing a routine will almost always change its behavior. This sounds crazy at first, but it’s a concept that’s so simple its easy to forget.  We’re purposely telling the system to process more than one thing at the same time, which means that the sequence in which things get processed is no longer deterministic.  It is easy to change the behavior of your routine in very subtle ways by introducing parallelism.  Often, the changes are not avoidable, even if they don’t have any adverse side effects.  This leads to my final observation for this post: Parallelization is something that should be handled with care and forethought, added by design, and not just introduced casually.

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  • Why is my program getting slower and slower ?

    - by RedWolf
    I'm using the program to send data from database to the Excel file . It works fine at the beginning and then becomes more and more slowly,finally it run out of the memory and the following error ocurrs: "java.lang.OutOfMemoryError: Java heap space...". The problem can be resolved by adding the jvm heap sapce.But the question is that it spends too much time to run out the program. After several minutes,it finished a loop with 4 seconds which can be finished with 0.5 seconds at the beginning . I can't found a solution to make it always run in a certain speed. Is it my code problem? Any clues on this? Here is the code: public void addAnswerRow(List<FinalUsers> finalUsersList,WritableWorkbook book){ if (finalUsersList.size() >0 ) { try { WritableSheet sheet = book.createSheet("Answer", 0); int colCount = 0; sheet.addCell(new Label(colCount++,0,"Number")); sheet.addCell(new Label(colCount++,0,"SchoolNumber")); sheet.addCell(new Label(colCount++,0,"District")); sheet.addCell(new Label(colCount++,0,"SchoolName")); sheet.setColumnView(1, 15); sheet.setColumnView(3, 25); List<Elements> elementsList = this.elementsManager.getObjectElementsByEduTypeAndQuestionnaireType(finalUsersList.get(0).getEducationType().getId(), this.getQuestionnaireByFinalUsersType(finalUsersList.get(0).getFinalUsersType().getId())); Collections.sort(elementsList, new Comparator<Elements>(){ public int compare(Elements o1, Elements o2) { for(int i=0; i< ( o1.getItemNO().length()>o2.getItemNO().length()? o2.getItemNO().length(): o1.getItemNO().length());i++){ if (CommonFun.isNumberic(o1.getItemNO().substring(0, o1.getItemNO().length()>3? 4: o1.getItemNO().length()-1)) && !CommonFun.isNumberic(o2.getItemNO().substring(0, o2.getItemNO().length()>3? 4: o2.getItemNO().length()-1))){ return 1; } if (!CommonFun.isNumberic(o1.getItemNO().substring(0, o1.getItemNO().length()>3? 4: o1.getItemNO().length()-1)) && CommonFun.isNumberic(o2.getItemNO().substring(0,o2.getItemNO().length()>3? 4:o2.getItemNO().length()-1))){ return -1; } if ( o1.getItemNO().charAt(i)!=o2.getItemNO().charAt(i) ){ return o1.getItemNO().charAt(i)-o2.getItemNO().charAt(i); } } return o1.getItemNO().length()> o2.getItemNO().length()? 1:-1; }}); for (Elements elements : elementsList){ sheet.addCell(new Label(colCount++,0,this.getTitlePre(finalUsersList.get(0).getFinalUsersType().getId(), finalUsersList.get(0).getEducationType().getId())+elements.getItemNO()+elements.getItem().getStem())); } int sheetRowCount =1; int sheetColCount =0; for(FinalUsers finalUsers : finalUsersList){ sheetColCount =0; sheet.addCell(new Label(sheetColCount++,sheetRowCount,String.valueOf(sheetRowCount))); sheet.addCell(new Label(sheetColCount++,sheetRowCount,finalUsers.getSchool().getSchoolNumber())); sheet.addCell(new Label(sheetColCount++,sheetRowCount,finalUsers.getSchool().getDistrict().getDistrictNumber().toString().trim())); sheet.addCell(new Label(sheetColCount++,sheetRowCount,finalUsers.getSchool().getName())); List<AnswerLog> answerLogList = this.answerLogManager.getAnswerLogByFinalUsers(finalUsers.getId()); Map<String,String> answerMap = new HashMap<String,String>(); for(AnswerLog answerLog :answerLogList ){ if (answerLog.getOptionsId() != null) { answerMap.put(answerLog.getElement().getItemNO(), this.getOptionsAnswer(answerLog.getOptionsId())); }else if (answerLog.getBlanks()!= null){ answerMap.put(answerLog.getElement().getItemNO(), answerLog.getBlanks()); }else{ answerMap.put(answerLog.getElement().getItemNO(), answerLog.getSubjectiveItemContent()); } } for (Elements elements : elementsList){ sheet.addCell(new Label(sheetColCount++,sheetRowCount,null==answerMap.get(elements.getItemNO())?"0":answerMap.get(elements.getItemNO()))); } sheetRowCount++; } book.write(); book.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (RowsExceededException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (WriteException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }

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  • CSS - Why am I not able to set height and width of <a href> elements?

    - by Kenny Bones
    Hi, I'm trying to create css buttons by using the following html markup: <a href="access.php" class="css_button_red">Forgot password</a> But it ends up being not bigger than the text in the middle. Even though I've set the class's height and width. You can preview the problem here btw, www.matkalenderen.no Notice the first button, that's a form button and it's using it's own class. At first I tried to use the same class on the css button as well and the same problem appeared, so I tried to separate them into their own classes. In case there was some kind of crash. But it didn't matter anyway. What am I missing here?

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  • Are the old httpHandlers and httpModules elements needed in IIS7?

    - by James Newton-King
    I'd like to clean up the web.config and remove unneeded XML. A default ASP.NET 3.5 web application has the follow elements in the web.config: <httpHandlers> <remove verb="*" path="*.asmx"/> <add verb="*" path="*.asmx" validate="false" type="System.Web.Script.Services.ScriptHandlerFactory, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add verb="*" path="*_AppService.axd" validate="false" type="System.Web.Script.Services.ScriptHandlerFactory, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add verb="GET,HEAD" path="ScriptResource.axd" type="System.Web.Handlers.ScriptResourceHandler, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" validate="false"/> </httpHandlers> <httpModules> <add name="ScriptModule" type="System.Web.Handlers.ScriptModule, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> <add name="UrlRoutingModule" type="System.Web.Routing.UrlRoutingModule, System.Web.Routing, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35" /> </httpModules> When running under IIS7, which has modules and handlers being registered under the system.webServer element, is the configuration above still needed?

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  • How to use XPath to filter elements by TextContent? get parent by axis?

    - by Michael Mao
    Hi all: I've found a similar question on SO, however, that seems not exactly what I wanna achieve: Say, this is a sample XML file: <root> <item> <id isInStock="true">10001</id> <category>Loose Balloon</category> </item> <item> <id isInStock="true">10001</id> <category>Bouquet Balloon</category> </item> <item> <id isInStock="true">10001</id> <category>Loose Balloon</category> </item> </root> If I wanna get a "filtered" subset of the item elements from this XML, how could I use an XPath expression to directly address that? XPathExpression expr = xpath.compile("/root/item/category/text()"); I now know this would evaluate to be the collection of all the TextContent from the categories, however, that means I have to use a collection to store the values, then iterate, then go back to grab other related info such as the item id again. Another question is : how could I refer to the parent node properly? Say, this xpath expression would get me the collection of all the id nodes, right? But what I want is the collection of item nodes: XPathExpression expr = xpath.compile("/root/item/id[@isInStock='true']"); I know I should use the "parent" axis to refer to that, but I just cannot make it right... Is there a better way of doing this sort of thing? Learning the w3cschools tutorials now... Sorry I am new to XPath in Java, and thanks a lot in advance.

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  • How do I keep child elements together with parent jQuery sortable.

    - by unknowndomain
    I have a list of items like this... <ol> <li> <span></span> <img src="image.png" /> <p>Image Caption</p> </li> </ol> And I want to be able to sort the LI's but not the sub elements, they should just move with their parent. I am using the jQuery to do that... $('ol li').sortable({ 'cursor': 'move' }); And its working but not moving the whole lot just the element you clicked i.e. the <p>, <img> or <span> I can't figure out how to solve this so I looked about and found an option called 'items': '> li' which was recommended but upon using this nothing drags any more but using firebug + jquery plugin I can see there is a sortable on the <li> still. Not sure what to do, example here: http://clareshilland.unknowndomain.co.uk/ Press ctrl+l to login. Enter the login details: Username: clarePassword: demo Select 'edit' from under then 'image' portion of the menu. The sortables should be those polaroids. Thanks in advance, another one I've been banging my head on the table with.

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  • jquery how to create a new div, assign some attributes, and create an id from some other elements at

    - by Ronedog
    How can I accomplish this...what I've tried below is not working and I'm unsure how to make it work. What I'm trying to do is create a div and assign it some attributes, then append this div to all the < li elements that are the on the last node of my unordered list. And lastly, but most important I want to retrieve the value of the attribute called "p_node" from the < li that is being appended to and insert it in as part of the ID of the newely created div Here's my current jquery code: $('<div />,{id:"'+ $("#nav li:not(:has(li))").attr("p_node").val() +'_p_cont_div", class:"property_position"}').appendTo("#nav li:not(:has(li))"); Here's the HTML before the div creation: <ul> <li p_node="98" class="page_name">Category A</li> </ul> <ul> <li p_node="99" class="page_name">Category B</li> </ul> Here's what I want it to look like after the new div creation: <ul> <li p_node="98" class="page_name">Category A</li> <div id="98_p_cont_div" class="property_position"></div> </ul> <ul> <li p_node="99" class="page_name">Category B</li> <div id="99_p_cont_div" class="property_position"></div> </ul> Thanks for your help.

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  • Is there a tag in XHTML that you can put anywhere in the body - even inside TABLE elements?

    - by Iain Fraser
    I would like to be able to place an empty tag anywhere in my document as a marker that can be addressed by jQuery. However, it is important that the XHTML still validates. To give you a bit of background as to what I'm doing: I've compared the current and previous versions of a particular document and I'm placing markers in the html where the differences are. I'm then intending to use jQuery to highlight the parent block-level elements when highlightchanges=true is in the URL's query string. At the moment I'm using <span> tags but it occurred to me that this sort of thing wouldn't validate: <table> <tr> <td>Old row</td> </tr> <span class="diff"></span><tr> <td>Just added</td> </tr> </table> So is there a tag I can use anywhere? Meta tag maybe? Thanks for your help! Iain

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  • How do I find, count, and display unique elements of an array using Perl?

    - by Luke
    I am a novice Perl programmer and would like some help. I have an array list that I am trying to split each element based on the pipe into two scalar elements. From there I would like to spike out only the lines that read ‘PJ RER Apts to Share’ as the first element. Then I want to print out the second element only once while counting each time the element appears. I wrote the piece of code below but can’t figure out where I am going wrong. It might be something small that I am just overlooking. Any help would be greatly appreciated. ## CODE ## my @data = ('PJ RER Apts to Share|PROVIDENCE', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Condo|WEST WARWICK', 'PJ RER Condo|WARWICK'); foreach my $line (@data) { $count = @data; chomp($line); @fields = split(/\|/,$line); if (($fields[0] =~ /PJ RER Apts to Share/g)){ @array2 = $fields[1]; my %seen; my @uniq = grep { ! $seen{$_}++ } @array2; my $count2 = scalar(@uniq); print "$array2[0] ($count2)","\n" } } print "$count","\n"; ## OUTPUT ## PROVIDENCE (1) JOHNSTON (1) JOHNSTON (1) JOHNSTON (1) 6

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  • What is the correct syntax for XSD to restrict attrributes values in the elements list?

    - by Leonard
    What is the correct syntax for XSD schema to define the following restriction: In the list of elements we have to specify that attribute can contain value of "c" unlimited number of times, but value of "b" - the zero or only one time. For example, the correct xml looks like this: <root> <elem atr="c">111</elem> <elem atr="c">222</elem> <elem atr="b">333</elem> <elem atr="c">444</elem> <elem atr="c">555</elem> </root> And incorrect one is: <root> <elem atr="c">111</elem> <elem atr="c">222</elem> <elem atr="b">333</elem> <elem atr="c">444</elem> <elem atr="b">555</elem> </root>

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