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  • regular expression breaking on new line

    - by shyam
    I'm trying to use a regular expression as below: preg_match_all('|<table.*</table>|',$html,$matches, PREG_SET_ORDER); But this is not working, and I think the problem is the new line inside the string $html. Could someone tell me a work around?

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  • Regular Expression not disappearing

    - by user2439019
    I have 3 phone fields and any one is required. SO i had a custom validation class to make any one of them is required. And i am calling those class as follows [RegularExpression(@"^\(?([0-9]{3})\)?. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [AtLeastOneRequired("PhoneHome", "PhoneMobile", "PhoneOffice", ErrorMessage = "Please provide either of PhoneHome or PhoneMobile or phoneOffice. ")] public string PhoneHome { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneOffice", ResourceType = typeof(ResContactItems))] public string PhoneOffice { get; set; } [StringLength(11, MinimumLength = 10)] [RegularExpression(@"^\(?([0-9]{3})\)?[-. ]?([0-9]{3})[-. ]?([0-9]{4})$", ErrorMessage = "Entered phone format is not valid. <br/> 10 digits are required.<br/> No spaces between digits. <br/> Numbers only.")] [Display(Name = "Prompt_PhoneMobile", ResourceType = typeof(ResContactItems))] public string PhoneMobile { get; set; } The problem is with only "PhoneHome " field , if i enter incorrect format, it will display error message based ont he regular expression given .But the regular expression message is not disappearing wwhen we enter the correct format too.It will disappear only in f the field is empty.Other two fields are showing properly. Is this due to the custom class i am calling.? Please help me to sort out this issue Thanks, Vidya

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  • .NET regular expression

    - by vert
    How would I write a regular expression (C#) which will check a given string to see if any of its characters are characters OTHER than the following: a-z A-Z Æ æ Å å Ø ø - '

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  • Regular expression to process key value pairs

    - by user677680
    I am attempting to write a regular expression to process a string of key value(s) pairs formatted like so KEY/VALUE KEY/VALUE VALUE KEY/VALUE A key can have multiple values separated by a space. I want to match a keys values together, so the result on the above string would be VALUE VALUE VALUE VALUE I currently have the following as my regex [A-Z0-9]+/([A-Z0-9 ]+)(?:(?!^[A-Z0-9]+/)) but this returns VALUE KEY as the first result.

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  • Regular expression to remove one parameter from query string

    - by Kip
    I'm looking for a regular expression to remove a single parameter from a query string, and I want to do it in a single regular expression if possible. Say I want to remove the foo parameter. Right now I use this: /&?foo\=[^&]+/ That works as long as foo is not the first parameter in the query string. If it is, then my new query string starts with an ampersand. (For example, "foo=123&bar=456" gives a result of "&bar=456".) Right now, I'm just checking after the regex if the query string starts with ampersand, and chopping it off if it does. Example edge cases: Input | Output -------------------------+----------------- foo=123 | (empty string) foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 Edit OK as pointed out in comments there are there are way more edge cases than I originally considered. I got the following regex to work with all of them: /&foo(\=[^&]*)?(?=&|$)|^foo(\=[^&]*)?(&|$)/ This is modified from Mark Byers's answer, which is why I'm accepting that one, but Roger Pate's input helped a lot too. Here is the full suite of test cases I'm using, and a Perl script which tests them. Input | Output -------------------------+------------------- foo | foo&bar=456 | bar=456 bar=456&foo | bar=456 abc=789&foo&bar=456 | abc=789&bar=456 foo= | foo=&bar=456 | bar=456 bar=456&foo= | bar=456 abc=789&foo=&bar=456 | abc=789&bar=456 foo=123 | foo=123&bar=456 | bar=456 bar=456&foo=123 | bar=456 abc=789&foo=123&bar=456 | abc=789&bar=456 xfoo | xfoo xfoo&bar=456 | xfoo&bar=456 bar=456&xfoo | bar=456&xfoo abc=789&xfoo&bar=456 | abc=789&xfoo&bar=456 xfoo= | xfoo= xfoo=&bar=456 | xfoo=&bar=456 bar=456&xfoo= | bar=456&xfoo= abc=789&xfoo=&bar=456 | abc=789&xfoo=&bar=456 xfoo=123 | xfoo=123 xfoo=123&bar=456 | xfoo=123&bar=456 bar=456&xfoo=123 | bar=456&xfoo=123 abc=789&xfoo=123&bar=456 | abc=789&xfoo=123&bar=456 foox | foox foox&bar=456 | foox&bar=456 bar=456&foox | bar=456&foox abc=789&foox&bar=456 | abc=789&foox&bar=456 foox= | foox= foox=&bar=456 | foox=&bar=456 bar=456&foox= | bar=456&foox= abc=789&foox=&bar=456 | abc=789&foox=&bar=456 foox=123 | foox=123 foox=123&bar=456 | foox=123&bar=456 bar=456&foox=123 | bar=456&foox=123 abc=789&foox=123&bar=456 | abc=789&foox=123&bar=456 Test script (Perl) @in = ('foo' , 'foo&bar=456' , 'bar=456&foo' , 'abc=789&foo&bar=456' ,'foo=' , 'foo=&bar=456' , 'bar=456&foo=' , 'abc=789&foo=&bar=456' ,'foo=123' , 'foo=123&bar=456' , 'bar=456&foo=123' , 'abc=789&foo=123&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); @exp = ('' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'' , 'bar=456' , 'bar=456' , 'abc=789&bar=456' ,'xfoo' , 'xfoo&bar=456' , 'bar=456&xfoo' , 'abc=789&xfoo&bar=456' ,'xfoo=' , 'xfoo=&bar=456' , 'bar=456&xfoo=' , 'abc=789&xfoo=&bar=456' ,'xfoo=123', 'xfoo=123&bar=456', 'bar=456&xfoo=123', 'abc=789&xfoo=123&bar=456' ,'foox' , 'foox&bar=456' , 'bar=456&foox' , 'abc=789&foox&bar=456' ,'foox=' , 'foox=&bar=456' , 'bar=456&foox=' , 'abc=789&foox=&bar=456' ,'foox=123', 'foox=123&bar=456', 'bar=456&foox=123', 'abc=789&foox=123&bar=456' ); print "Succ | Input | Output | Expected \n"; print "-----+--------------------------+--------------------------+-------------------------\n"; for($i=0; $i <= $#in; $i++) { $out = $in[$i]; $out =~ s/_PUT_REGEX_HERE_//; $succ = ($out eq $exp[$i] ? 'PASS' : 'FAIL'); #if($succ eq 'FAIL') #{ printf("%s | %- 24s | %- 24s | %- 24s\n", $succ, $in[$i], $out, $exp[$i]); #} }

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  • Looking for good Regex book

    - by Cyberherbalist
    I've been trying to get a good grounding with Regular Expressions, and am looking for a single book to do so. I've been going through Amazon.com's listings on this subject, and I've identified a few possibilities, but am unsure which would be best for a C# developer who can write very simple Regexs, but wants to learn more. On a scale of 0-9 where 0 is knowing how to spell "Regex" but nothing else, and 9 where I could write a book on the subject out of my own head, I would place myself at 2. Which of the following would be your choice: Mastering Regular Expressions by Jeffrey E F Friedl Regular Expressions Cookbook by Jan Goyvaerts and Steven Levithan Sams Teach Yourself Regular Expressions in 10 Minutes by Ben Forta Beginning Regular Expressions (Programmer to Programmer) by Andrew Watt Regular Expression Recipes for Windows Developers: A Problem-Solution Approach by Nathan A. Good Regular Expression Recipes: A Problem-Solution Approach by Nathan A. Good Now, according to Amazon, "Regular Expressions Cookbook" (REC) above is rated the highest according to user ratings, but only based on 20 reviews. The first one, "Mastering Regular Expressions" (MRE) is rated second based on 140 reviews. This alone suggests that MRE might be by far the best one. But is it best for a relative beginner? Would I perhaps be better getting "Beginning Regular Expressions" (BRE) instead, to start with? Please help me resolve my confusion!

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  • Little Regular Expression (against HTML) help

    - by Marcos Placona
    Hi, I have the following HTML <p>Some text <a title="link" href="http://link.com/" target="_blank">my link</a> more text <a title="link" href="http://link.com/" target="_blank">more link</a>.</p> <p>Another paragraph.</p> <p>[code:cf]</p> <p>&lt;cfset ArrFruits = ["Orange", "Apple", "Peach", "Blueberry", </p> <p>"Blackberry", "Strawberry", "Grape", "Mango", </p> <p>"Clementine", "Cherry", "Plum", "Guava", </p> <p>"Cranberry"]&gt;</p> <p>[/code]</p> <p>Another line</p> <p><img src="http://image.jpg" alt="Array" /> </p> <p>More text</p> <p>[code:cf]</p> <p>&lt;table border="1"&gt;</p> <p> &lt;cfoutput&gt;</p> <p> &lt;cfloop array="#GroupsOf(ArrFruits, 5)#" index="arrFruitsIX"&gt;</p> <p>  &lt;tr&gt;</p> <p> &lt;cfloop array="#arrFruitsIX#" index="arrFruit"&gt;</p> <p>     &lt;td&gt;#arrFruit#&lt;/td&gt;</p> <p> &lt;/cfloop&gt;</p> <p>  &lt;/tr&gt;</p> <p> &lt;/cfloop&gt;</p> <p> &lt;/cfoutput&gt;</p> <p>&lt;/table&gt;</p> <p>[/code]</p> <p>With an output that looks like:</p> <p><img src="another_image.jpg" alt="" width="342" height="85" /></p> What I'm trying to do, is write a regular expression that will remove all the or , and whenever it finds a , it will replace it with a line-break. So far, my pattern looks like this: /\<p\>(.*?)(<\/p>)/g And I'm replacing the matches with: $1\n It all looks good, but it's also replacing the contents inside the [code][/code] tags, which in this case should not replace the tags at all, so as a result, i would lkike to get rid of the tags, when the content isn't inside the [code] tags. I can't ever get negation right, I know it will be something along the lines of \<p\>^\[code*\](.*?)(<\/p>) But obviously this doesn't work :-) Could anyone please lend me a hand with this regex? BTW, I know I shouldn't be using regular expressions to parse HTML at all. I'm fully aware of that, but still, for this specific case, I'd like to use regex. Thanks in advance

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  • Python regular expressions matching variables to end of line

    - by None
    When you use variables (is that the correct word?) in python regular expressions like this: "blah (?P\w+)" ("value" would be the variable), how could you make the variable's value be the text after "blah " to the end of the line or to a certain character not paying any attention to the actual content of the variable. For example, this is pseudo-code for what I want: >>> import re >>> p = re.compile("say (?P<value>continue_until_text_after_assignment_is_recognized) endsay") >>> m = p.match("say Hello hi yo endsay") >>> m.group('value') 'Hello hi yo' Note: The title is probably not understandable. That is because I didn't know how to say it. Sorry if I caused any confusion.

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  • How to cut a URL with regular expression

    - by AhmadAssaf
    Hello, i am trying to chop a string that contains several information in java .. the text is something like that : <a href="http://www.hootsuite.com" rel="nofollow">HootSuite</a> i am thinking of using the .split method that need regular expression .. what i want it to split this string into the URL without quotes .. http://...... .com and then the text between the tags .. this case HootSuite .. i will appreciate the help Thank you

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  • Regular expressions in findstr

    - by Johannes Rössel
    I'm doing a little string validation with findstr and its /r flag to allow for regular expressions. In particular I'd like to validate integers. The regex ^[0-9][0-9]*$ worked fine for non-negative numbers but since I now support negative numbers as well I tried ^([1-9][0-9]*|0|-[1-9][0-9]*)$ for either positive or negative integers or zero. The regex works fine theoretically. I tested it in PowerShell and it matches what I want. However, with findstr /r /c:"^([1-9][0-9]*|0|-[1-9][0-9]*)$" it doesn't. While I know that findstr doesn't have the most advanced regex support (even below Notepad++ which is probably quite an achievement), I would have expected such simple expressions to work. Any ideas what I'm doing wrong here?

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  • Mixing regular expression and other conditional expression in a bash if statement

    - by Tassos
    I can't get around this for quite sometime now. As I read along manuals and tutorials I'm getting more confused. I want an if statement with the following logic: if [ -n $drupal_version ] && [[ "$drupal_version" =~ DRUPAL-[6-9]-[1-9][1-9] ]]; then but I can't get it to work properly. When the script is evaluated using the "bash -x ... " script construct, works ok but when is run as a regular script my expression is not evaluated (eventhough the above condition should be met the else part is run). Could you provide any help?

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  • Fuzzy Regular Expressions

    - by Thomas Ahle
    In my work I have with great results used approximate string matching algorithms such as Damerau–Levenshtein distance to make my code less vulnerable to spelling mistakes. Now I have a need to match strings against simple regular expressions such TV Schedule for \d\d (Jan|Feb|Mar|...). This means that the string TV Schedule for 10 Jan should return 0 while T Schedule for 10. Jan should return 2. This could be done by generating all strings in the regex (in this case 100x12) and find the best match, but that doesn't seam practical. Do you have any ideas how to do this effectively?

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  • Using regular expressions to do mass replace in Notepad++

    - by user638820
    I've been trying to replace (and translate) this text, and i don't know what formula I should Use for thousands of places that I need to translate to Spanish. OKay this is what i want to do, i want to use regular expressions on Notepadd++. I give 4 variations, and in bold is what's supposed to go after the name of the place, in lower case and not to be confused with eg. Agency Village because that's its name. Missouri 5,988,927 Adrian City city 1,677 Advance city 1,347 Affton CDP 20,307 Agency Village village 684 Airport Drive village 698 To | [[Adrian City (Misuri)|Adrian City]] || ciudad || 1677 |- | [[Advance (Misuri)|Advance]] || ciudad || 1347 |- | [[Afton (Misuri)|Afton]] || CDP || 20307 |- | [[Agency Village (Misuri)|Agency Village]] || villa || 684 |- | [[Airport Drive (Misuri)|Airport Drive]] || villa || 698

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  • regular expression to read the string between <title> and </title>

    - by user262325
    Hello every one I hope to read the contents between and in a html string. I think it should be in objective-c @"<title([\\s\\S]*)</title>" below are the codes that rewrited for regular expression //source of NSStringCategory.h #import <Foundation/Foundation.h> #import <regex.h> @interface NSStringCategory:NSObject { regex_t preg; } -(id)initWithPattern:(NSString *)pattern options:(int)options; -(void)dealloc; -(BOOL)matchesString:(NSString *)string; -(NSString *)matchedSubstringOfString:(NSString *)string; -(NSArray *)capturedSubstringsOfString:(NSString *)string; +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options; +(NSStringCategory *)regexWithPattern:(NSString *)pattern; +(NSString *)null; +(void)initialize; @end @interface NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options; -(BOOL)matchedByPattern:(NSString *)pattern; -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options; -(NSString *)substringMatchedByPattern:(NSString *)pattern; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options; -(NSArray *)substringsCapturedByPattern:(NSString *)pattern; -(NSString *)escapedPattern; @end and .m file #import "NSStringCategory.h" static NSString *nullstring=nil; @implementation NSStringCategory -(id)initWithPattern:(NSString *)pattern options:(int)options { if(self=[super init]) { int err=regcomp(&preg,[pattern UTF8String],options|REG_EXTENDED); if(err) { char errbuf[256]; regerror(err,&preg,errbuf,sizeof(errbuf)); [NSException raise:@"CSRegexException" format:@"Could not compile regex \"%@\": %s",pattern,errbuf]; } } return self; } -(void)dealloc { regfree(&preg); [super dealloc]; } -(BOOL)matchesString:(NSString *)string { if(regexec(&preg,[string UTF8String],0,NULL,0)==0) return YES; return NO; } -(NSString *)matchedSubstringOfString:(NSString *)string { const char *cstr=[string UTF8String]; regmatch_t match; if(regexec(&preg,cstr,1,&match,0)==0) { return [[[NSString alloc] initWithBytes:cstr+match.rm_so length:match.rm_eo-match.rm_so encoding:NSUTF8StringEncoding] autorelease]; } return nil; } -(NSArray *)capturedSubstringsOfString:(NSString *)string { const char *cstr=[string UTF8String]; int num=preg.re_nsub+1; regmatch_t *matches=calloc(sizeof(regmatch_t),num); if(regexec(&preg,cstr,num,matches,0)==0) { NSMutableArray *array=[NSMutableArray arrayWithCapacity:num]; int i; for(i=0;i<num;i++) { NSString *str; if(matches[i].rm_so==-1&&matches[i].rm_eo==-1) str=nullstring; else str=[[[NSString alloc] initWithBytes:cstr+matches[i].rm_so length:matches[i].rm_eo-matches[i].rm_so encoding:NSUTF8StringEncoding] autorelease]; [array addObject:str]; } free(matches); return [NSArray arrayWithArray:array]; } free(matches); return nil; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern options:(int)options { return [[[NSStringCategory alloc] initWithPattern:pattern options:options] autorelease]; } +(NSStringCategory *)regexWithPattern:(NSString *)pattern { return [[[NSStringCategory alloc] initWithPattern:pattern options:0] autorelease]; } +(NSString *)null { return nullstring; } +(void)initialize { if(!nullstring) nullstring=[[NSString alloc] initWithString:@""]; } @end @implementation NSString (NSStringCategory) -(BOOL)matchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options|REG_NOSUB]; return [re matchesString:self]; } -(BOOL)matchedByPattern:(NSString *)pattern { return [self matchedByPattern:pattern options:0]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re matchedSubstringOfString:self]; } -(NSString *)substringMatchedByPattern:(NSString *)pattern { return [self substringMatchedByPattern:pattern options:0]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern options:(int)options { NSStringCategory *re=[NSStringCategory regexWithPattern:pattern options:options]; return [re capturedSubstringsOfString:self]; } -(NSArray *)substringsCapturedByPattern:(NSString *)pattern { return [self substringsCapturedByPattern:pattern options:0]; } -(NSString *)escapedPattern { int len=[self length]; NSMutableString *escaped=[NSMutableString stringWithCapacity:len]; for(int i=0;i<len;i++) { unichar c=[self characterAtIndex:i]; if(c=='^'||c=='.'||c=='['||c=='$'||c=='('||c==')' ||c=='|'||c=='*'||c=='+'||c=='?'||c=='{'||c=='\\') [escaped appendFormat:@"\\%C",c]; else [escaped appendFormat:@"%C",c]; } return [NSString stringWithString:escaped]; } @end I use the codes below to get the string between "" and "" NSStringCategory *a=[[NSStringCategory alloc] initWithPattern:@"<title([\s\S]*)</title>" options:0];// Unfortunately [a matchedSubstringOfString:response]] always returns nil I do not if the regular expression is wrong or any other reason. Welcome any comment Thanks interdev

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  • Regular expression replace in PL/pgSQL

    - by dreamlax
    If I have the following input (excluding quotes): "The ancestral territorial imperatives of the trumpeter swan" How can I collapse all multiple spaces to a single space so that the input is transformed to: "The ancestral territorial imperatives of the trumpeter swan" This is going to be used in a trigger function on insert/update (which already trims leading/trailing spaces). Currently, it raises an exception if the input contains multiple adjacent spaces, but I would rather it simply transforms it into something valid before inserting. What is the best approach? I can't seem to find a regular-expression replace function for PL/pgSQL. There is a text_replace function, but this will only collapse at most two spaces down to one (meaning three consecutive spaces will collapse to two). Calling this function over and over is not ideal.

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  • Regular expression in C#

    - by user340015
    i have text something like this. @@MMIVLoader@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@MMIVLib@[email protected]@BCM_7400S_LE@Product@Aug 21 2009@ @@HuaweFGDLDrv@[email protected]@7324@PRODUCT@Aug 20 2009@ @@ProtectVer@[email protected] @BCM_SDE5.03@PRODUCT@Aug 4 2009 06:56:19@ @@KernelSw@[email protected]@BCM-7454@PRODUCT@ Dec 19 2007@ @@ReceiverSw@[email protected]@HWBC01ZS@PRODUCT@May 3 2010@ i want the out put in an array like MMIVLoader 4.1.2 MMIVLib 4.1.2 HuaweFGDLDrv 01.00.09 ProtectVer 127.8.1 KernelSw 0.0.1 ReceiverSw E.5.6.001 Can any one suggest me how to do this in c# using regular expression or is there a any sophisticated way to do this thanks in advance

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  • Regular Expressions

    - by Rocky
    Hello Everyone, I am new to Stackoverflow and I have a quick question. Let's assume we are given a large number of HTML files (large as in theoretically infinite). How can I use Regular Expressions to extract the list of Phone Numbers from all those files? Explanation/expression will be really appreciated. The Phone numbers can be any of the following formats: (123) 456 7899 (123).456.7899 (123)-456-7899 123-456-7899 123 456 7899 1234567899 Thanks a lot for all your help and have a good one!

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  • JavaScript String Replace with a tricky regular expression

    - by Juri
    Hi. I'm trying to work out what regular expression I would need to change this string html = '<img style="width: 311px; height: 376px;" alt="test" src="/img/1268749322.jpg" />'; to this html = '<img width="311" height="376" alt="test" src="/img/1268749322.jpg" />'; with the help of Javascript.replace. This is my start: html = html.replace(/ style="width:\?([0-9])px*"/g, "width=\"$1\""); Can anyone help me? THANKS

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  • Regular expression in BASH

    - by Ryan
    Hello everyone, I was hoping someone could answer my quick question as I am going nuts! I have recently started learning regular expressions in my Java programming however am a little confused how to get certain features to work correctly directly in BASH. For example, the following code is not working as I think it should. echo 2222 | grep '2\{2\}' I am expecting it to return: 22 I have tried variations of it including: echo 2222 | grep '2{2}' echo 2222 | grep -P '2\{2\}' echo 2222 | grep -E '2\{2\}' However I am completely out of ideas. I'm sure this is a simple parameter / syntax fix and would love some help! P.S I've done tons of googling and every reference I find does not work in BASH; regex's can run on so many different platforms and engines =/

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  • Evaluating a regular expression range

    - by Dan Atkinson
    Hi there! Is there a nice way to evaluate a regular expression range, say, for a url such as http://example.com/[a-z]/[0-9].htm This would be converted into: http://example.com/a/0.htm http://example.com/a/1.htm http://example.com/a/2.htm ... http://example.com/a/9.htm ... http://example.com/z/0.htm http://example.com/z/1.htm http://example.com/z/2.htm ... http://example.com/z/9.htm I've been scratching my head about this, and there's no pretty way of doing it without going through the alphabet and looping through numbers. Thanks in advance!

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  • A regular expression that will allow a string with only one Capital Letter

    - by Phoenix
    The string should be 6 - 20 characters in length. And it should contain 1 Capital letter. I can do this in code using C# string st = "SomeString" Regex rg = new Regex("[A-Z]"); MatchCollection mc = rg.Matches(st); Console.WriteLine("Total Capital Letters: " + mc.Count); if (mc.Count > 1) { return false; } But what i really want is a Regular expression that will match my string if it only contains one capital. The string can start with a common letter and should have only letters. Thanks In advance. (I did look at some of the other RegEx questions but they did not help).

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  • Java (Android) regular expression to strip out HTML paragraph

    - by jackbot
    I have an Android application which grabs some data from an external XML source. I've stripped out some HTML from one of the XML elements, but it's in the format: <p class="x">Some text...</p> <p>Some more text</p> <p>Some final text</p> I want to extract the middle paragraph text, how can I do this? Would a regular expression be the best way? I don't really want to start including external HTML parsing libraries.

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  • Usability standards when combining AJAX and regular POST-based form saves

    - by mcrider
    I'm working on a project where on certain pages (e.g. settings pages) we combine AJAX and regular fill-out-the-form-then-submit POST based operations. I'm curious if anyone has advice on improving the usability of such a page. One of my ideas is that when the user enters/modifies a value in a non-ajax part of the page, some sort of div would appear (say in a fashion similar to Growl) indicating that the user needs to save by pressing 'Submit' at the bottom of the page (and possibly putting up a modal dialog if the user navigates away from the page before saving, though that might be a bit too intrusive). I'm sure this type of interaction exists, but I can't find any examples.

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  • Regular Expression Help - Brackets within brackets

    - by adbox
    Hello I'm trying to develop a function that can sort through a string that looks like this: Donny went to the {park|store|{beach with friends|beach alone}} so he could get a breath of freash air. What I intend to do is search the text recursively for {} patterns where there is no { or } inside the {}, so only the innermost sandwiched text is selected, where I will then run a php to array the contents and select one at random, repeating process until the whole string has been parsed, showing a complete sentence. I just cannot wrap my head around regular expressions though. Appreciate any help!

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