Search Results

Search found 21742 results on 870 pages for 'unique values'.

Page 19/870 | < Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >

  • increment values in printf [migrated]

    - by ravi_arya
    #include <stdio.h> int main() { int i=1; printf("%d %d %d\n",i,++i,i++); i=1; printf("%d %d %d\n",++i,i,i++); i=1; printf("%d %d %d\n",i++,++i,i); i=1; printf("%d %d %d\n",i++,i,++i); i=1; printf("%d %d %d\n",++i,i++,i); i=1; printf("%d \n",(++i)*(++i)*(++i)); i=1; printf("%d %d %d\n",++i, ++i, ++i); return 0; } Output (GCC) 3 3 1 3 3 1 2 3 3 2 3 3 3 1 3 36 4 4 4 Output(Visual Studio) 3 3 1 3 3 1 2 3 3 2 3 3 3 1 3 64 4 4 4 Can any one explain this?

    Read the article

  • Using macro to check null values [migrated]

    - by poliron
    My C code contains many functions with pointers to different structs as parameteres which shouldn't be NULL pointers. To make my code more readable, I decided to replace this code: if(arg1==NULL || arg2==NULL || arg3==NULL...) { return SOME_ERROR; } With that macro: NULL_CHECK(arg1,arg2,...) How should I write it, if the number of args is unknown and they can point to different structs?(I work in C99)

    Read the article

  • A really unique case of Load Balancing

    - by Shamshun
    I have an internet connection which has limited up/down bandwidth per IP address. What I want to do is to get multiple IP addresses on a "single" LAN interface, and use a load balancer to distribute traffic through them. I was successful at getting 100 ip addresses on a single interface. my problem is that Linux and Windows use the first ip address of an interface by default, so my bandwidth is not increased. I would appreciate if someone tells me what Load Balancing software has the ability to distribute load between multiple IPs on a single interface. I have tried to do so on both Win7 and Backtrack-LinuxR2

    Read the article

  • A unique identifier for a Domain

    - by jchoover
    I asked a question over on StackOverflow and was directed to ask a related one here to see if I could get any additional input. Basically, I am looking to have my application aware of what domain it's running under, if any at all. (I want to expose certain debugging facilities only in house, and due to our deployment model it isn't possible to have a different build.) Since I am over paranoid, I didn't want to just rely on the domain name to ensure we are in house. As such I noted the DOMAIN_CONTROLLER_INFO (http://msdn.microsoft.com/en-us/library/ms675912(v=vs.85).aspx ) returned from DsGetDcName (http://msdn.microsoft.com/en-us/library/ms675983(v=vs.85).aspx) has a GUID associated with it, however I can find little if any information on it. I am assuming this GUID is generated at the time the first DC in a domain is created, and that it would live on for the life of the domain. Does anyone else have any inner knowledge and would be kind enough to confirm or deny my assumptions?

    Read the article

  • Selecting unique records in XSLT/XPath

    - by Daniel I-S
    I have to select only unique records from an XML document, in the context of an <xsl:for-each> loop. I am limited by Visual Studio to using XSL 1.0. <availList> <item> <schDate>2010-06-24</schDate> <schFrmTime>10:00:00</schFrmTime> <schToTime>13:00:00</schToTime> <variousOtherElements></variousOtherElements> </item> <item> <schDate>2010-06-24</schDate> <schFrmTime>10:00:00</schFrmTime> <schToTime>13:00:00</schToTime> <variousOtherElements></variousOtherElements> </item> <item> <schDate>2010-06-25</schDate> <schFrmTime>10:00:00</schFrmTime> <schToTime>12:00:00</schToTime> <variousOtherElements></variousOtherElements> </item> <item> <schDate>2010-06-26</schDate> <schFrmTime>13:00:00</schFrmTime> <schToTime>14:00:00</schToTime> <variousOtherElements></variousOtherElements> </item> <item> <schDate>2010-06-26</schDate> <schFrmTime>10:00:00</schFrmTime> <schToTime>12:00:00</schToTime> <variousOtherElements></variousOtherElements> </item> </availList> The uniqueness must be based on the value of the three child elements: schDate, schFrmTime and schToTime. If two item elements have the same values for all three child elements, they are duplicates. In the above XML, items one and two are duplicates. The rest are unique. As indicated above, each item contains other elements that we do not wish to include in the comparison. 'Uniqueness' should be a factor of those three elements, and those alone. I have attempted to accomplish this through the following: availList/item[not(schDate = preceding:: schDate and schFrmTime = preceding:: schFrmTime and schToTime = preceding:: schToTime)] The idea behind this is to select records where there is no preceding element with the same schDate, schFrmTime and schToTime. However, its output is missing the last item. This is because my XPath is actually excluding items where all of the child element values are matched within the entire preceding document. No single item matches all of the last item's child elements - but because each element's value is individually present in another item, the last item gets excluded. I could get the correct result by comparing all child values as a concatenated string to the same concatenated values for each preceding item. Does anybody know of a way I could do this?

    Read the article

  • MySQL get list of unique items in a SET

    - by The Disintegrator
    I have a products table with a column of type SET (called especialidad), with these possible values. [0] => NADA [1] => Freestyle / BMX [2] => Street / Dirt [3] => XC / Rural Bike [4] => All Mountain [5] => Freeride / Downhill / Dual / 4x [6] => Ruta / Triathlon / Pista [7] => Comfort / City / Paseo [8] => Kids [9] => Playera / Chopper / Custom [10] => MTB recreacion [11] => Spinning / Fitness Any given product can have one or many of these i/e "Freestyle / BMX,Street / Dirt" Given a subset of the rows, I need to get a list of all the present "especialidad" values. But I need a list to be exploded and unique Article1: "Freestyle / BMX,Street / Dirt" Article2: "Street / Dirt,Kids" Article2: "Kids" Article4: "Street / Dirt,All Mountain" Article5: "Street / Dirt" I need a list like this Freestyle / BMX Street / Dirt" Kids" All Mountain" I tried with group_concat(UNIQUE) but I get a list of the permutations...

    Read the article

  • unique items from an observableArray of object properties

    - by Joe
    I'm trying to extract unique properties from a knockout.js observableArray of objects, to populate a drop menu. Being new to knockout, I'm really struggling with this! I want to iterate over a contacts list, and populate a drop menu with a unique value from each person object within the observableArray. So in my code example below, I wish to populate my drop menu with a list of people 'type' - family, friend etc. Looking on Google, I found a similar function, but it does not return any values, even if I console.log the results? //dummy data more rows in actual code... var people = [ { name: "Contact 1", address: "1, a street, a town, a city, AB12 3CD", tel: "0123456789", email: "[email protected]", type: "family" }, { name: "Contact 2", address: "1, a street, a town, a city, AB12 3CD", tel: "0123456789", email: "[email protected]", type: "friend" } ]; function ContactsViewModel(people) { var self = this; self.contacts = ko.observableArray(people); self.uniqueSelect = ko.dependentObservable(function() { return( ko.utils.arrayGetDistinctValues(self.contacts().type).sort()); }, self); }; ko.applyBindings(new ContactsViewModel()); And HTML template <p>Show me: <select data-bind="options: ContactsViewModel.uniqueSelect"></select></p> Any help appreciated, as a noob I'm lost! Thanks

    Read the article

  • Storing unique values into an array and comparing against a loop - PHP

    - by Aphex22
    I'm writing a PHP report which is designed to be exported purely as a CSV file, using commma delimiters. There are three columns relating to product_id, these three columns are as follows: SKU Parent / Child Parent SKU 12345 parent 12345 12345_1 child 12345 12345_2 child 12345 12345_3 child 12345 12345_4 child 12345 18099 parent 18099 18099_1 child 18099 Here's a link to the full CSV file: http://i.imgur.com/XELufRd.png At the moment the code looks like this: $sql = "select * from product WHERE on_amazon = 'on' AND active = 'on'"; $result = mysql_query($sql) or die ( mysql_error() );?> <? // set headers echo " Type, SKU, Parent / Child, Parent SKU, Product name, Manufacturer name, Gender, Product_description, Product price, Discount price, Quantity, Category, Photo 1, Photo 2, Photo 3, Photo 4, Photo 5, Photo 6, Photo 7, Photo 8, Color id, Color name, Size name <br> "; // load all stock while ($line = mysql_fetch_assoc($result) ) { ?> <?php // Loop through each possible size variation to see whether any of the quantity column has stock > 0 $con_size = array (35,355,36,37,375,38,385,39,395,40,405,41,415,42,425,43,435,44,445,45,455,46,465,47,475,48,485); $arrlength=count($con_size); for($x=0;$x<$arrlength;$x++) { // check if size is available if($line['quantity_c_size_'.$con_size[$x].'_chain'] > 0 ) { ?> <? echo 'Shoes'; ?>, <?=$line['product_id']?>, , , <?=$line['title']?>, <? $brand = $line['jys_brand']; echo ucfirst($brand); ?>, <? $gender = $line['category']; if ($gender == 'Mens') { echo 'H'; } else{ echo 'F'; } ?>, <?=preg_replace('/[^\da-z]/i', ' ', $line['amazon_desc']) ?>, <?=$line['price']?>, <?=$line['price']?>, <?=$line['quantity_c_size_'.$con_size[$x].'_chain']?>, <? $category = $line['style1']; switch ($category) { case "ankle-boots": echo "10013"; break; case "knee-high-boots": echo "10011"; break; case "high-heel-boots": echo "10033"; break; case "low-heel-boots": echo "10014"; break; case "wedge-boots": echo "10014"; break; case "western-boots": echo "10032"; break; case "flat-shoes": echo "10034"; break; case "high-heel-shoes": echo "10039"; break; case "low-heel-shoes": echo "10039"; break; case "wedge-shoes": echo "10035"; break; case "ballerina-shoes": echo "10008"; break; case "boat-shoes": echo "10018"; break; case "loafer-shoes": echo "10037"; break; case "work-shoes": echo "10039"; break; case "flat-sandals": echo "10041"; break; case "low-heel-sandals": echo "10042"; break; case "high-heel-sandals": echo "10042"; break; case "wedge-sandals": echo "10042"; break; case "mule-sandals": echo "10038"; break; case "mary-jane-shoes": echo "10039"; break; case "sports-shoes": echo "10026"; break; case "court-shoes": echo "10035"; break; case "peep-toe-shoes": echo "10035"; break; case "flat-boots": echo "10609"; break; case "mid-calf-boots": echo "10014"; break; case "trainer-shoes": echo "10009"; break; case "wellington-boots": echo "10012"; break; case "lace-up-boots": echo "10609"; break; case "chelsea-and-jodphur-boots": echo "10609"; break; case "desert-and-chukka-boots": echo "10032"; break; case "lace-up-shoes": echo "10034"; break; case "slip-on-shoes": echo "10043"; break; case "gibson-and-derby-shoes": echo "10039"; break; case "oxford-shoes": echo "10039"; break; case "brogue-shoes": echo "10039"; break; case "winter-boots": echo "10021"; break; case "slipper-shoes": echo "10016"; break; case "mid-heel-shoes": echo "10039"; break; case "sandals-and-beach-shoes": echo "10044"; break; case "mid-heel-sandals": echo "10042"; break; case "mid-heel-boots": echo "10014"; break; default: echo ""; } ?>, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_1.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_2.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_3.jpg, http://www.getashoe.co.uk/full/<?=$line['product_id']?>_4.jpg, , , , , <? $colour = preg_replace('/[^\da-z]/i', ' ', $line['colour']); if( preg_match( '/white.*/i', $colour)) { echo '1'; } elseif( preg_match( '/yellow.*/i', $colour)) { echo '4'; } elseif( preg_match( '/orange.*/i', $colour)) { echo '7'; } elseif( preg_match( '/red.*/i', $colour)) { echo '8'; } elseif( preg_match( '/pink.*/i', $colour)) { echo '13'; } elseif( preg_match( '/purple.*/i', $colour)) { echo '15'; } elseif( preg_match( '/blue.*/i', $colour)) { echo '19'; } elseif( preg_match( '/green.*/i', $colour)) { echo '25'; } elseif( preg_match( '/brown.*/i', $colour)) { echo '28'; } elseif( preg_match( '/grey.*/i', $colour)) { echo '35'; } elseif( preg_match( '/black.*/i', $colour)) { echo '38'; } elseif( preg_match( '/gold.*/i', $colour)) { echo '41'; } elseif( preg_match( '/silver.*/i', $colour)) { echo '46'; } elseif( preg_match( '/multi.*/i', $colour)) { echo '594'; } elseif( preg_match( '/beige.*/i', $colour)) { echo '6887'; } elseif( preg_match( '/nude.*/i', $colour)) { echo '6887'; } else { echo '534'; } ?>, <?=$line['colour']?>, <?=$con_size[$x]?> <br> <? // finish checking if size is available } } ?> So at the moment this is simply echoing out the product_ID into the SKU column. The code would need to enter the product_id into an array and check whether it is unique. If the product_id is unique to the array, then the product_id is echoed out unaltered, and parent is echoed out to the 'Parent/Child' column and then the product_id is repeated to the 'Parent SKU' column. However, if the array is checked and the product_id already exists in the array, then the product_id is echoed out to the 'SKU' column with a suffix i.e. _1. Then child is echoed to the 'Parent / Child' column and the original parent product_id echoed to the 'Parent SKU' column. HOWEVER - the same SKU cannot be repeated with the same suffix i.e. 12345_1, 12345_1 - so presumably there would be to be another array for the suffixed SKUs to be checked against. If anybody could help, it would be great. Thanks --- UPDATE ANSWER --- I managed to solved this myself and thought I would share my solution for future reference. /* * Array to collect product_ids and check whether unique. * If unique product_id becomes parent SKU * If not product_id becomes child of previous parent and suffixed with _1, _2 etc... */ if (!in_array($line['product_id'], $SKU)) { $SKU[] = $line['product_id']; $parent = $line['product_id']; $a = 0; ?> <? echo 'Shoes'; ?>, <? echo $parent; ?>, <? echo "Parent"; ?>, <? echo $parent; ?>, <? } else { $child = $line['product_id'] . "_" . $a; ?> <? echo 'Shoes'; ?>, <? echo $child; ?>, <? echo "Child"; ?>, <? echo $child; <? // increment suffix value for child SKU $a++; ?>

    Read the article

  • Combinationally unique MySQL tables

    - by Jack Webb-Heller
    So, here's the problem (it's probably an easy one :P) This is my table structure: CREATE TABLE `users_awards` ( `user_id` int(11) NOT NULL, `award_id` int(11) NOT NULL, `duplicate` int(11) NOT NULL DEFAULT '0', UNIQUE KEY `award_id` (`award_id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 So it's for a user awards system. I don't want my users to be granted the same award multiple times, which is why I have a 'duplicate' field. The query I'm trying is this (with sample data of 3 and 2) : INSERT INTO users_awards (user_id, award_id) VALUES ('3','2') ON DUPLICATE KEY UPDATE duplicate=duplicate+1 So my MySQL is a little rusty, but I set user_id to be a primary key, and award_id to be a UNIQUE key. This (kind of) created the desired effect. When user 1 was given award 2, it entered. If he/she got this twice, only one row would be in the table, and duplicate would be set to 1. And again, 2, etc. When user 2 was given award 1, it entered. If he/she got this twice, duplicate updated, etc. etc. But when user 1 is given award 1 (after user 2 has already been awarded it), user 2 (with award 1)'s duplicate field increases and nothing is added to user 1. Sorry if that's a little n00bish. Really appreciate the help! Jack

    Read the article

  • Finding the unique paths through a Neo4j graph

    - by Larry
    I have a Neo4j graph with 12 inputs and 4 outputs, and am trying to write a query with the Java Traverser that will return the 14 unique paths from an input to an output node. All the queries I have tried return only a subset of the 14 paths. For example, the code below returns 4 paths, but the other 10 all stop 1 node short of the output. RelationshipType relType = RelationshipTypes.EDGE; TraversalDescription td = new TraversalDescriptionImpl() .depthFirst() .relationships(relType, Direction.OUTGOING); for (Node node : inputs){ Traverser tv = td.traverse(node); Iterator<Path> iter = tv.iterator(); // ... print path } I've tried uniqueness and depth settings as well, with no effect. The query below returns all 14 paths using the web interface, but when I use the ExecutionEngine class, I only get 13 paths back. START s=node(*) MATCH (s)-[p:EDGE*]->(c) WHERE s.type! = "INPUT" AND c.type! = "OUTPUT" RETURN p How do I get all the unique paths using the Java API?

    Read the article

  • Trouble recording unique regex output to array in perl

    - by Structure
    The goal of the following code sample is to read the contents of $target and assign all unique regex search results to an array. I have confirmed my regex statement works so I am simplifying that so as not to focus on it. When I execute the script I get a list of all the regex results, however, the results are not unique which leads me to believe that my manipulation of the array or my if (grep{$_ eq $1} @array) { check is causing a problem(s). #!/usr/bin/env perl $target = "string to search"; $inc = 0; $once = 1; while ($target =~ m/(regex)/g) { #While a regex result is returned if ($once) { #If $once is not equal to zero @array[$inc] = $1; #Set the first regex result equal to @array[0] $once = 0; #Set $once equal to zero so this is not executed more than once } else { if (grep{$_ eq $1 } @array ) { #From the second regex result, check to see if the result is already in the array #If so, do nothing } else { @array[$inc] = $1; #If it is not, then assign the regex search result to the next unused position in the array in any position. $inc++; #Increment to next unused array position. } } } print @array; exit 0;

    Read the article

  • Windows Unique Identifier?

    - by user775013
    So there is this software. When installed it somehow (probably reads file or registry entry) recognizes my windows operating system. It's supposed to do some tasks only once per unique computer. If I uninstall the program and re install it, the software remembers that it has been installed and therefore do not do the task. If I use system restore, software also does not do the tasks. If I load image of the system before the install, software also doesn't do the tasks. If I re install a fresh copy of windows, then only the software does the task. IP even does not matter. Everything is the same, except it is a brand new copy of Windows operating system. So I guess that the software reads some kind of unique operating system identifier, then connects to server to create a user profile. So the question is? What could be those files which software uses to check system identifier? So far I have found out that there are entries under registry. WindowsNT/CurrentVersion and Windows/Cryptography but software do not rely on them. Where else should I search? Any software which could help me find out?

    Read the article

  • Generating all unique crossword puzzle grids

    - by heydenberk
    I want to generate all unique crossword puzzle grids of a certain grid size (4x4 is a good size). All possible puzzles, including non-unique puzzles, are represented by a binary string with the length of the grid area (16 in the case of 4x4), so all possible 4x4 puzzles are represented by the binary forms of all numbers in the range 0 to 2^16. Generating these is easy, but I'm curious if anyone has a good solution for how to programmatically eliminate invalid and duplicate cases. For example, all puzzles with a single column or single row are functionally identical, hence eliminating 7 of those 8 cases. Also, according to crossword puzzle conventions, all squares must be contiguous. I've had success removing all duplicate structures, but my solution took several minutes to execute and probably was not ideal. I'm at something of a loss for how to detect contiguity so if anyone has ideas on this it'd be much appreciated. I'd prefer solutions in python but write in whichever language you prefer. If anyone wants, I can post my python code for generating all grids and removing duplicates, slow as it may be.

    Read the article

  • Need help finding a unique value in array

    - by bardockyo
    My code is complete minus one little flaw. It searches the array and prints out which values are unique, however it always counts the first entry as unique even if it is followed by the same value. Can anyone look at my code and tell me which part is messing this up because it is driving me crazy. #include <stdio.h> #define size 7 int main(void) { int array1[size], target, answer, found, x, k, prev, count =1, i; printf("Please input %d integers: ", size); scanf("%d", &target); for(x = 0; x < size; x++) { scanf("%d", &array1[x]); } prev = array1[0]; for (i = 1; i < size; i++) { if (array1[i] == prev) { count++; } else { if (count < 2) printf("%d=%d\n", prev, count); prev = array1[i]; count = 1; } } if (count < 2) { printf("%d=%d\n", prev, count); } return 0; }

    Read the article

  • How to do a "where in values" in LINQ-to-Entities

    - by Ty
    Does anybody know how to apply a "where in values" type condition using LINQ-to-Entities? I've tried the following but it doesn't work: var values = new[] { "String1", "String2" }; // some string values var foo = model.entitySet.Where(e = values.Contains(e.Name)); I believe this works in LINQ-to-SQL though? Any thoughts?

    Read the article

  • casing the object values

    - by deep
    Hai am using telerik wpf grid in grid selection change event am getting the selected row values. the problem is the values are as object. object myData = radGridView.SelectedItem; the object myData contains the row values. but i don know how to get values from the myData object

    Read the article

  • stored values within a custom function

    - by romunov
    My program takes a data.frame and crunches the numbers. At one point, values from j-th column are multiplied by a predefined values that depends on the column name (species name, actually - it's en ecological index). So far, I've been providing these values via a second data.frame by matching column names. What would be an efficient way of integrating fixed variable values within a function? I would like my program to be as portable as possible, without the need for a second data.frame file.

    Read the article

  • replace values in a String from a Hashtable in Java

    - by Adnan
    My string looks like; String values = "I am from UK, and you are from FR"; and my hashtable; Hashtable countries = new Hashtable(); countries.put("United Kingdom", new String("UK")); countries.put("France", new String("FR")); What would be the most effective way to change the values in my string with the values from the hashtable accordingly. These are just 2 values to change, but in my case I will have 100+

    Read the article

  • Allowed Values list in drupal CCK Fields

    - by GaxZE
    Hello, I'm basically looking to simply print out each of the allowed values in a CCK field.. i know the allowed values are stored inside a text field within the table: 'content_node_field'. the values are then stored within 'global_settings' I'm looking to somehow print out each individual allowed value using a PHP loop. however with all values being stored within one text field.. im finding it hard to print out each value individually.

    Read the article

  • passing values from exe to dll c++

    - by jello
    so I have this executable which takes values from a joystick and outputs those values (i have the code). I want to pass those values to a dll, which is read in a program (i have the code for the dll). how can I pass those values from the exe to the dll?

    Read the article

  • Excel 2010 filter arrow not showing text values

    - by DVP
    I have an odd problem on a tracker spreadsheet I use. All the columns have a filter, but when you click on the filter arrow it doesn't show you a breakdown of all the text values for that column. All it shows is the usual 'sort A to Z/Z to A', but the bottom half of the pop-up screen is blank, where normally you have a list of text values that you can further filter by putting a tick next to each. It only displays (Select All) which you can tick, but its pointless as the column has selected all text values and hasn't been further filtered, which is what I need to do.

    Read the article

  • Average Difference and Direction Between Values in Excel with Blanks

    - by 114
    I have a sheet that looks something like this: Sheet 1 1 2 3 4 5 6 7 8 9 10 11 1 6 2 3 5 3 4 2 4 9 4 5 6 4 6 6 7 5 3 3 3 10 8 4 8 8 9 4 11 12 12 6 10 11 8 5 5 4 9 4 7 6 What I would like to be able to do is find the average difference and direction between values in each column. For example, the first 4 rows would look like: Average Difference # + Movements # -Movements 1 2 2 1 0 3 4 (2+5+5)/3 2 1 Blanks represent N/A values due to insufficient information, and differences are calculated successively i.e. col2-col1, col3-col2, col4-col3 If I just take the differences and make a duplicate table with the formula =C2-B2 copied across issues arise whenever there is a blank space between two values or at the beginning of the row. Is there an easy way to fix this or another way to do this that I might be missing?

    Read the article

  • Array Unique in two dimentional array in PHP

    - by Kaiser
    Hi I have an array that looks like this : Array ( [0] => Array ( [x] => 01 [y] => 244 ) [1] => Array ( [x] => 02 [y] => 244 ) [2] => Array ( [x] => 03 [y] => 244 ) [3] => Array ( [x] => 04 [y] => 243 ) [4] => Array ( [x] => 05 [y] => 243 ) [5] => Array ( [x] => 05 [y] => 244 ) [6] => Array ( [x] => 06 [y] => 242 ) [7] => Array ( [x] => 06 [y] => 243 ) [8] => Array ( [x] => 07 [y] => 243 ) [9] => Array ( [x] => 08 [y] => 243 ) [10] => Array ( [x] => 09 [y] => 242 ) [11] => Array ( [x] => 10 [y] => 244 ) [12] => Array ( [x] => 12 [y] => 243 ) [13] => Array ( [x] => 13 [y] => 243 ) [14] => Array ( [x] => 13 [y] => 243 ) [15] => Array ( [x] => 15 [y] => 243 ) ) x represent days and y values of a certain variable. I would like to display an array of unique days x ( last element ) and values y pragmatically. for example day 6 I have two y values but I want to display only the last one ( 243 ). Thanks for help

    Read the article

< Previous Page | 15 16 17 18 19 20 21 22 23 24 25 26  | Next Page >