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  • XML: Multiple roots + text content outside the root. Does anyone do it?

    - by Jeffrey Sweeney
    I have another one of those "is it done in XML" questions (my last one about xml comments hasn't been answered if anyone has a good explanation) I was just wondering if anyone, anywhere would: Use multiple root elements in an XML document Put text content outside of a root element W3C discourages these practices, Javascript's DOMParser doesn't even allow these cases, and I can't think of one sane reason to do either of these things. However, I know how bizarre some implementations of XML have been, so I wouldn't be surprised. Does anyone have any real world examples where this would be done? I will also accept an answer that specifies if other mainstream parsers allow doing either of these.

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  • Is it convenient to use a XML/JSON generated based system? [closed]

    - by Marcelo de Assis
    One of my clients insists that we missed a requisite for the project(a little social network, using PHP + MySql), is that all queries are made from XML / JSON static files (using AJAX) and not directly from the database. Edit: The main reason, stated by client, is a way to economize bandwith. Even the file loading, has to be using AJAX, to avoid server side processing. We will still use a database to store and insert data. These XML / JSON files will be (re) generated whenever any data is changed by CMS or users. As the project was developed without this "technique", we'll have a lot of work ahead, so I would like to avoid that. I'm asking if it's convenient to use a XML generated based system, because I think a database is already "optimized" and secure to deal with a lot of data traffic. Other issue I'm afraid of, is a chance of conflict when a user is trying to read a XML/JSON which is being just generated.

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  • Unit test: How best to provide an XML input?

    - by TheSilverBullet
    I need to write a unit test which validates the serialization of two attributes of an XML(size ~ 30 KB) file. What is the best way to provide an input for this test? Here are the options I have considered: Add the file to the project and use a file reader Pass the contents of the XML as a string Create the XML through a program and pass it Which is my best option and why? If there is another way which you think is better, I would love to hear it.

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  • How can I pass an external instance to the constructor of an object that's being created using the default XNA XML content loader?

    - by Michael
    I'm trying to understand how to use the XNA XML content importer to instantiate non-trivial objects that are more than a collection of basic properties (e.g., a class that inherits from DrawableGameObject or GameObject and requires other things to be passed into its constructor). Is it possible to pass existing external instances (e.g., an instance of the current Game) to the constructor of an object that's being created using the default XNA XML content loader? For example, imagine that I have the following class, inheriting from DrawableGameComponent: public class Character : DrawableGameComponent { public string Name { get; set; } public Character(Game game) : base(game) { } public override void Update(GameTime gameTime) { } public override void Draw(GameTime gameTime) { } } If I had a simple class that did not need other parameters in its constructor (i.e., the Game instance), then I could simply use this XML: <XnaContent> <Asset Type="MyNamespace.Character"> <Name>John Doe</Name> </Asset> </XnaContent> ...and then create an instance of Character using this code: var character = Content.Load<Character>("MyXmlAssetName"); But that won't work because I need to pass the need to pass the Game into the constructor. What's the best way to handle this situation? Is there a way to pass in things like the current Game using the default XNA XML content loader? Do I need to write my own XML loader? (If so, how?) Is there a better object-oriented design that I should be using for my classes? Note: Although I used Game in this example, I'm really just asking how to pass any type of existing instance to my constructors. (For example, I'm using the Farseer Physics Engine, and some of my classes also need a reference to the Farseer World object too.) Thanks in advance.

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  • Why do XML namespace URIs use the http scheme?

    - by svick
    A XML namespace should be a URI, but it can use any URI scheme, including those that are not URLs. Then why do all widely used XML namespaces use the http scheme (e.g. http://www.w3.org/XML/1998/namespace), considering that trying to use the URI as an URL by retrieving that document using the HTTP protocol is not guaranteed to do anything useful (and often doesn't)? I understand the usefulness of DNS domains in namespace names to help guarantee uniqueness. But that doesn't require the http scheme, there could be a separate scheme for that (something like namespace:w3.org/XML/1998/namespace). This would avoid the confusion between URIs and URLs, while maintaining domain-based uniqueness.

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  • How do I use Content.Load() with raw XML files?

    - by xnanewb
    I'm using the Content.Load() mechanism to load core game definitions from XML files. It works fine, though some definitions should be editable/moddable by the players. Since the content pipeline compiles everything into xnb files, that doesn't work for now. I've seen that the inbuild XNA Song content processor does create 2 files. 1 xnb file which contains meta data for the song and 1 wma file which contains the actual data. I've tried to rebuild that mechanism (so that the second file is the actual xml file), but for some reason I can't use the namespace which contains the IntermediateSerializer class to load the xml (obviously the namespace is only available in a content project?). How can I deploy raw, editable xml files and load them with Content.Load()?

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  • Using LINQ to XML, how can I join two sets of data based on ordinal position?

    - by Donald Hughes
    Using LINQ to XML, how can I join two sets of data based on ordinal position? <document> <set1> <value>A</value> <value>B</value> <value>C</value> </set1> <set2> <value>1</value> <value>2</value> <value>3</value> </set2> </document> Based on the above fragment, I would like to join the two sets together such that "A" and "1" are in the same record, "B" and "2" are in the same record, and "C" and "3" are in the same record.

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  • Cannot validate xml doc againest a xsd schema (Cannot find the declaration of element 'replyMessage

    - by Daziplqa
    Hi Guyz, I am using the following code to validate an an XML file against a XSD schema package com.forat.xsd; import java.io.IOException; import java.net.URL; import javax.xml.XMLConstants; import javax.xml.transform.Source; import javax.xml.transform.stream.StreamSource; import javax.xml.validation.Schema; import javax.xml.validation.SchemaFactory; import javax.xml.validation.Validator; import org.xml.sax.ErrorHandler; import org.xml.sax.SAXException; import org.xml.sax.SAXParseException; public class XSDValidate { public void validate(String xmlFile, String xsd_url) { try { SchemaFactory factory = SchemaFactory.newInstance(XMLConstants.W3C_XML_SCHEMA_NS_URI); Schema schema = factory.newSchema(new URL(xsd_url)); Validator validator = schema.newValidator(); ValidationHandler handler = new ValidationHandler(); validator.setErrorHandler(handler); validator.validate(getSource(xmlFile)); if (handler.errorsFound == true) { System.err.println("Validation Error : "+ handler.exception.getMessage()); }else { System.out.println("DONE"); } } catch (SAXException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } private Source getSource(String resource) { return new StreamSource(XSDValidate.class.getClassLoader().getResourceAsStream(resource)); } private class ValidationHandler implements ErrorHandler { private boolean errorsFound = false; private SAXParseException exception; public void error(SAXParseException exception) throws SAXException { this.errorsFound = true; this.exception = exception; } public void fatalError(SAXParseException exception) throws SAXException { this.errorsFound = true; this.exception = exception; } public void warning(SAXParseException exception) throws SAXException { } } /* * Test */ public static void main(String[] args) { new XSDValidate().validate("com/forat/xsd/reply.xml", "https://ics2wstest.ic3.com/commerce/1.x/transactionProcessor/CyberSourceTransaction_1.53.xsd"); // return error } } As appears, It is a standard code that try to validate the following XML file: <?xml version="1.0" encoding="UTF-8"?> <replyMessage xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <merchantReferenceCode>XXXXXXXXXXXXX</merchantReferenceCode> <requestID>XXXXXXXXXXXXX</requestID> <decision>XXXXXXXXXXXXX</decision> <reasonCode>XXXXXXXXXXXXX</reasonCode> <requestToken>XXXXXXXXXXXXX </requestToken> <purchaseTotals> <currency>XXXXXXXXXXXXX</currency> </purchaseTotals> <ccAuthReply> <reasonCode>XXXXXXXXXXXXX</reasonCode> <amount>XXXXXXXXXXXXX</amount> <authorizationCode>XXXXXXXXXXXXX</authorizationCode> <avsCode>XXXXXXXXXXXXX</avsCode> <avsCodeRaw>XXXXXXXXXXXXX</avsCodeRaw> <authorizedDateTime>XXXXXXXXXXXXX</authorizedDateTime> <processorResponse>0XXXXXXXXXXXXX</processorResponse> <authRecord>XXXXXXXXXXXXX </authRecord> </ccAuthReply> </replyMessage> Against the following XSD : https://ics2wstest.ic3.com/commerce/1.x/transactionProcessor/CyberSourceTransaction_1.53.xsd The error is : Validation Error : cvc-elt.1: Cannot find the declaration of element 'replyMessage'. Could you please help me!

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  • How do I return pure XML from asmx web service?

    - by User
    I want an asmx webservice with a method GetPeople() that returns the following XML (NOT a SOAP response): <People> <Person> <FirstName>Sara</FirstName> <LastName>Smith</LastName> </Person> <Person> <FirstName>Bill</FirstName> <LastName>Wilson</LastName> </Person> <People/> How can I do this?

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  • .NET and XML: How can I read nested namespaces (<abc:xyz:name attr="value"/>)?

    - by Entrase
    Suppose there is an element in XML data: <abc:xyz:name attr="value"/> I'm trying to read it with XmlReader. The problem is that I get XmlException that says The ‘:’ character, hexadecimal value 0x3A, cannot be included in a name I have already declared "abc" namespace. I have also tried adding "abc:xyz" and "xyz" namespaces. But this doesn't help at all. I could replace some text before parsing but there may be some more elegant solution. So what should I do? Here is my code: XmlReaderSettings settings = new XmlReaderSettings() NameTable nt = new NameTable(); XmlNamespaceManager nsmgr = new XmlNamespaceManager(nt); nsmgr.AddNamespace("abc", ""); nsmgr.AddNamespace("xyz", ""); XmlParserContext context = new XmlParserContext(null, nsmgr, null, XmlSpace.None); // So this reader can't read <abc:xyz:name attr="value"/> XmlReader reader = XmlReader.Create(path, settings, context);“

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  • Deleting xml file using radio value

    - by ???? ???
    i using php to delete file, but i got table loop like this: <table border="0" width="100%" cellpadding="0" cellspacing="0" id="product-table"> <tr class="bg_tableheader"> <th class="table-header-check"><a id="toggle-all" ></a> </th> <th class="table-header-check"><a href="#"><font color="white">Username</font></a> </th> <th class="table-header-check"><a href="#"><font color="white">First Name</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Last Name</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Email</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Group</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Birthday</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Gender</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Age</font></a></th> <th class="table-header-check"><a href="#"><font color="white">Country</font></a></th> </tr> <?php $files = glob('users/*.xml'); foreach($files as $file){ $xml = new SimpleXMLElement($file, 0, true); echo ' <tr> <td></td> <form action="" method="post"> <td class="alternate-row1"><input type="radio" name="file_name" value="'. basename($file, '.xml') .'" />'. basename($file, '.xml') .'</td> <td>'. $xml->name .'&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp&nbsp</td> <td class="alternate-row1">'. $xml->lastname .'</td> <td>'. $xml->email .'</td> <td class="alternate-row1">'. $xml->level .'</td> <td>'. $xml->birthday .'</td> <td class="alternate-row1">'. $xml->gender .'</td> <td>'. $xml->age .'</td> <td class="alternate-row1">'. $xml->country .'</td> </tr>'; } ?> </table> </div> <?php if(isset($_POST['file_name'])){ unlink('users/'.$_POST['file_name']); } ?> <input type="submit" value="Delete" /> </form> so as you can see i got radio value set has basename (xml file name) but from some reason it not working, any idea why is that? Thanks in advance.

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  • How- XLST Transformation

    - by Yuan Ray
    Just wanted to ask on how to get the author names in the given xml sample below and put an attribut of eq="yes". EQ means Equal Contributors. This is the XML. <ArticleFootnote Type="Misc"> <Para>John Doe and Jane Doe are equal contributors.</Para> </ArticleFootnote> This should be the output in other form of XML. <AuthorGroups> <Authors eq="yes">John Doe</Authors> <Authors eq="yes">Jane Doe</Authors> </AuthorGroups> Assuming that JOhn Doe and Jane Doe are already defined in the list of authors but after the transformation, author tag should have the attribute eq="yes". Please help as I don't know much writing in xlst. Thanks in advance.

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  • Retrieve XML from URL

    - by Pl4za
    I am having some problems retrieving a xml from url with the following code: private static String getAlbumArt(String artistName, String albumName){ try{ XMLParser xml_parser = new XMLParser(); String xml = xml_parser.getXmlFromUrl(getAlbumURL(artistName, albumName)); Document doc = xml_parser.getDomElement(xml); NodeList N = doc.getElementsByTagName("album"); Node node = N.item(0); NodeList N2 = node.getChildNodes(); System.out.println("1------"); for (int i = 0; i < N2.getLength(); i++) { Node detailNode = N2.item(i); if (detailNode.getNodeType() == Node.ELEMENT_NODE) { System.out.println("2------"); if (detailNode.getNodeName().equalsIgnoreCase("image")) { String sizeVal = ((Element) detailNode).getAttribute("size"); String url = detailNode.getTextContent(); if (sizeVal.equalsIgnoreCase("large")) { return url; } } } } } catch (Exception e){ } return null; } The xml function which i call in the above code: public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } getAlbumURL: public static String getAlbumURL(String artist, String album){ return URL_METHOD + METHOD_GETALBUM + AMPERSAND + API_KEY + AMPERSAND + PARAM_ARTIST + artist + AMPERSAND + PARAM_ALBUM + album; } XMLparser: public class XMLParser { // constructor public XMLParser() { } //Get XML from URL public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } //Get dom element public Document getDomElement(String xml){ Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } //Get nod element public final String getElementValue(Node elem ) { Node child; if( elem != null){ if (elem.hasChildNodes()){ for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ if( child.getNodeType() == Node.TEXT_NODE ){ return child.getNodeValue(); } } } } return ""; } //Get element value public String getValue(Element item, String str) { NodeList nlList = item.getElementsByTagName(str).item(0).getChildNodes(); Node nValue = (Node) nlList.item(0); return nValue.getNodeValue(); } } Any ideas ? I seriously don't know what is wrong.. I used this before and it worked.

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  • Web.xml: Are url-pattern tags relative to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • XML Schema - how do you conditionally require address elements? (street, city, state, etc)

    - by Sly
    If an address can be composed of child elements: Street, City, State, PostalCode...how do you allow this XML: <Address> <Street>Somestreet</Street> <PostalCode>zip</PostalCode> </Address> and allow this: <Address> <Street>Somestreet</Street> <City>San Jose</City> <State>CA</State> </Address> but not this: <Address> <Street>Somestreet</Street> <City>San Jose</City> </Address> What schema will do such things!?

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  • How could I do something like this in a XML schema?

    - by chobo2
    Hi I want to mass create some users and I want to set the users timezone automatically. However I am using timezones generated by this Dictionary<string, TimeZoneInfo> storeZoneName = TimeZoneInfo.GetSystemTimeZones().ToDictionary(z => z.DisplayName); So I need the names to be exactly like the ones this list returns. So can I put like a constraint on that xml node that the name has to exactly match one of the names. So I am guessing I will need to write this list somewhere in the file and that's what I am not sure if you can do something like that in a schema.

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  • Web.xml: Are url-pattern tags relitive to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

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  • how to filter data from xml file for displaying only selected as nodes in treeview

    - by michale
    I have an xml file named "books.xml" provided in the link "http://msdn.microsoft.com/en-us/library/windows/desktop/ms762271(v=vs.85).aspx". What my requirement was to disaplay only the <title> from xml information as nodes in tree view. But when i did the following coding its displaying all the values as nodes like "catalog" as rootnode, book as parent node for all then author,title,genre etc as nodes but i want only root node catalogue and title as nodes not even book. Can any body guide me what modification i need to do in the exisitng logic for displaying title as nodes OpenFileDialog dlg = new OpenFileDialog(); dlg.Title = "Open XML document"; dlg.Filter = "XML Files (*.xml)|*.xml"; dlg.FileName = Application.StartupPath + "\\..\\..\\Sample.xml"; if (dlg.ShowDialog() == DialogResult.OK) { try { //Just a good practice -- change the cursor to a //wait cursor while the nodes populate this.Cursor = Cursors.WaitCursor; //First, we'll load the Xml document XmlDocument xDoc = new XmlDocument(); xDoc.Load(dlg.FileName); //Now, clear out the treeview, //and add the first (root) node treeView1.Nodes.Clear(); treeView1.Nodes.Add(new TreeNode(xDoc.DocumentElement.Name)); TreeNode tNode = new TreeNode(); tNode = (TreeNode)treeView1.Nodes[0]; //We make a call to addTreeNode, //where we'll add all of our nodes addTreeNode(xDoc.DocumentElement, tNode); //Expand the treeview to show all nodes treeView1.ExpandAll(); } catch (XmlException xExc) //Exception is thrown is there is an error in the Xml { MessageBox.Show(xExc.Message); } catch (Exception ex) //General exception { MessageBox.Show(ex.Message); } finally { this.Cursor = Cursors.Default; //Change the cursor back } }} //This function is called recursively until all nodes are loaded private void addTreeNode(XmlNode xmlNode, TreeNode treeNode) { XmlNode xNode; TreeNode tNode; XmlNodeList xNodeList; if (xmlNode.HasChildNodes) //The current node has children { xNodeList = xmlNode.ChildNodes; for (int x = 0; x <= xNodeList.Count - 1; x++) //Loop through the child nodes { xNode = xmlNode.ChildNodes[x]; treeNode.Nodes.Add(new TreeNode(xNode.Name)); tNode = treeNode.Nodes[x]; addTreeNode(xNode, tNode); } } else //No children, so add the outer xml (trimming off whitespace) treeNode.Text = xmlNode.OuterXml.Trim(); }

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  • How can I create the XML::Simple data structure using a Perl XML SAX parser?

    - by DVK
    Summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog—due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. I'm looking for an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is; e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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  • XML pass values to timer, AS3

    - by VideoDnd
    My timer has three variables that I can trace to the output window, but don't know how to pass them to the timer. How to I pass the XML values to my timer? Purpose I want to test with an XML document, before I try connecting it to an XML socket. myXML <?xml version="1.0" encoding="utf-8"?> <SESSION> <TIMER TITLE="speed">100</TIMER> <COUNT TITLE="starting position">-77777</COUNT> <FCOUNT TITLE="ramp">1000</FCOUNT> </SESSION> myFlash //myTimer 'instance of mytext on stage' /* fields I want to change with XML */ //CHANGE TO 100 var timer:Timer = new Timer(10); //CHANGE TO -77777 var count:int = 0; //CHANGE TO 1000 var fcount:int = 0; timer.addEventListener(TimerEvent.TIMER, incrementCounter); timer.start(); function incrementCounter(event:TimerEvent) { count++; fcount=int(count*count/1000);//starts out slow... then speeds up mytext.text = formatCount(fcount); } function formatCount(i:int):String { var fraction:int = i % 100; var whole:int = i / 100; return ("0000000" + whole).substr(-7, 7) + "." + (fraction < 10 ? "0" + fraction : fraction); } //LOAD XML var myXML:XML; var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("time.xml")); myLoader.addEventListener(Event.COMPLETE, processXML); //PARSE XML function processXML(e:Event):void { myXML = new XML(e.target.data); trace(myXML.ROGUE.*); trace(myXML); //TEXT var text:TextField = new TextField(); text.text = myXML.TIMER.*; text.textColor = 0xFF0000; addChild(text); } RESOURCES OReilly's ActionScript 3.0 Cookbook, Chapter 12 Strings, Chapter 20 XML

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  • Transform 3d viewport vector to 2d vector

    - by learning_sam
    I am playing around with 3d transformations and came along an issue. I have a 3d vector already within the viewport and need to transform it to a 2d vector. (let's say my screen is 10x10) Does that just straight works like regualar transformation or is something different here? i.e.: I have the vector a = (2, 1, 0) within the viewport and want the 2d vector. Does that works like this and if yes how do I handle the "0" within the 3rd component?

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  • Parsing XML with the PHP XMLReader

    - by coffeecoder
    Hi Guys, I am writing program that reads in some XML from the $_POST variable and then parses using the PHP XMLReader and the data extracted input into a database. I am using the XMLReader as the XML supplied will more than likely be too big to place into memory. However I am having some issues, my XML and basic code as are follows: '<?xml version="1.0"?> <data_root> <data> <info>value</info> </data> <action>value</action> </data_root>' $request = $_REQUEST['xml']; $reader = new XMLReader(); $reader->XML($request); while($reader->read()){ //processing code } $reader->close() My problem is that the code will work perfectly if the XML being passed does not have the <?xml version="1.0"?> line, but if i include it, and it will be included when the application goes into a live production environment, the $reader->read() code for the while loop does not work and the XML is not parsed within the while loop. Has anyone seen similar behaviour before or knows why this could be happening? Thanks in advance.

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  • Will JSON replace XML as a data format?

    - by 13ren
    When I first saw XML, I thought it was basically a representation of trees. Then I thought: the important thing isn't that it's a particularly good representation of trees, but that it is one that everyone agrees on. Just like ASCII. And once established, it's hard to displace due to network effects. The new alternative would have to be much better (maybe 10 times better) to displace it. Of course, ASCII has been (mostly) replaced by Unicode, for internationalization. According to google trends, XML has a x43 lead, but is declining - while JSON grows. Will JSON replace XML as a data format? (edited) for which tasks? for which programmers/industries? NOTES: S-expressions (from lisp) are another representation of trees, but which has not gained mainstream adoption. There are many, many other proposals, such as YAML and Protocol Buffers (for binary formats). I can see JSON dominating the space of communicating with client-side AJAX (AJAJ?), and this possibly could back-spread into other systems transitively. XML, being based on SGML, is better than JSON as a document format. I'm interested in XML as a data format. XML has an established ecosystem that JSON lacks, especially ways of defining formats (XML Schema) and transforming them (XSLT). XML also has many other standards, esp for web services - but their weight and complexity can arguably count against XML, and make people want a fresh start (similar to "web services" beginning as a fresh start over CORBA).

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