Search Results

Search found 34274 results on 1371 pages for 'mysql table'.

Page 192/1371 | < Previous Page | 188 189 190 191 192 193 194 195 196 197 198 199  | Next Page >

  • Mysql slowing down my application

    - by user2985991
    my application is taking ages to load because of my database isnt located on my computer.. Anyone have any idea to how improve my performance? public Form1() { Splash splash = new Splash(); splash.Show(); InitializeComponent(); Load(); public void Load() { db.SelectTeam(); db.SelectMatches(); } On db.SelectTeam and SelectMatches I get everything I need from mysql and put into lists... Sorry if it's confusing, but I don't know what to do, and sorry for my bad english EDIT: Here are the querys string query = "SELECT * FROM teams ORDER BY name"; string query = "SELECT * FROM matches ORDER BY date ASC";

    Read the article

  • php, mySQL & AJAX: Unable to use sessions across the scripts in the same domain

    - by Devner
    Hi all, I have the following pages: page1.php, page2.php and page3.php. Code in each of them is as below CODE: page1.php <script type="text/javascript"> $(function(){ $('#imgID').upload({ submit_to_url: "page2.php", file_name: 'myfile1', description : "Image", limit : 1, file_types : "*.jpg", }) }); </script> <body> <form action="page3.php" method="post" enctype="multipart/form-data" name="frm1" id="frm1"> //Some other text fields <input type="submit" name="submit" id="submit" value="Submit" /> </form> </body> page2.php <?php session_start(); $a = $_SESSION['a']; $b = $_SESSION['b']; $c = $_SESSION['c']; $res = mysql_query("SELECT col FROM table WHERE col1 = $a AND col2 = $b AND col3 = $c LIMIT 1"); $num_rows = mysql_num_rows($res); echo $num_rows; //echos 0 when in fact it should have been 1 because the data in the Session exists. //Ok let's proceed further //... Do some stuff... //Store some more values and create new session variables (and assume that page1.php is going to be able to use it) $_SESSION['d'] = 'd'; $_SESSION['e'] = 'e'; $_SESSION['f'] = 'f'; if (move_uploaded_file($_FILES['file']['tmp_name'], $file)) { echo "success"; } else { echo "error ".$_FILES['file']['error']; } ?> page3.php <?php session_start(); if( isset($_POST['submit']) ) { //These sessions are non-existent although the AJAX request //to page2.php may have created them when called via AJAX from within page1.php echo $_SESSION['d'].$_SESSION['e'].$_SESSION['f']; ?> } ?> As the code says it I am posting some info via AJAX call from page1.php to page2.php. page2.php is supposed to be able to use the session values from page1.php i.e. $_SESSION['a'], $_SESSION['b'] and $_SESSION['c'] but it does not. Why? How can I fix this? page2.php is creating some more sessions after some processing is done and a response is sent back to page1.php. The submit button of the form on page1.php is hit and the page gets POST'ed to page3.php. But when the SESSION info that gets created in page2.php is echoed, it's blank signifying that SESSIONS from page2.php are not used. How can I fix this? I looked over a lot of information and have spent about 50 hours trying to do different things with my scripts before arriving at the above conclusions. My app. is custom made using function (not OOPS) and does not use any PHP frameworks & I am not even about to use any as my knowledge of OOP concepts is limited any many frameworks are object oriented. I came across race conditions, but the solutions provided don't help too much. One more solution of using DB to hold sessions and seek and retrieve from DB is the last thing on my mind and I really want to avoid creating table, coding and maintaining code for a task as simple as just keeping sessions across pages in the same domain. So my request is: Is there a way that I can solve the above problem(s) via simple coding in present conditions? Any help is appreciated. Thank you.

    Read the article

  • Copying contents of a MySQL table to a table in another (local) database

    - by Philip Eve
    I have two MySQL databases for my site - one is for a production environment and the other, much smaller, is for a testing/development environment. Both have identical schemas (except when I am testing something I intend to change, of course). A small number of the tables are for internationalisation purposes: TransLanguage - non-English languages TransModule - modules (bundles of phrases for translation, that can be loaded individually by PHP scripts) TransPhrase - individual phrases, in English, for potential translation TranslatedPhrase - translations of phrases that are submitted by volunteers ChosenTranslatedPhrase - screened translations of phrases. The volunteers who do translation are all working on the production site, as they are regular users. I wanted to create a stored procedure that could be used to synchronise the contents of four of these tables - TransLanguage, TransModule, TransPhrase and ChosenTranslatedPhrase - from the production database to the testing database, so as to keep the test environment up-to-date and prevent "unknown phrase" errors from being in the way while testing. My first effort was to create the following procedure in the test database: CREATE PROCEDURE `SynchroniseTranslations` () LANGUAGE SQL NOT DETERMINISTIC MODIFIES SQL DATA SQL SECURITY DEFINER BEGIN DELETE FROM `TransLanguage`; DELETE FROM `TransModule`; INSERT INTO `TransLanguage` SELECT * FROM `PRODUCTION_DB`.`TransLanguage`; INSERT INTO `TransModule` SELECT * FROM `PRODUCTION_DB`.`TransModule`; INSERT INTO `TransPhrase` SELECT * FROM `PRODUCTION_DB`.`TransPhrase`; INSERT INTO `ChosenTranslatedPhrase` SELECT * FROM `PRODUCTION_DB`.`ChosenTranslatedPhrase`; END When I try to run this, I get an error message: "SELECT command denied to user 'username'@'localhost' for table 'TransLanguage'". I also tried to create the procedure to work the other way around (that is, to exist as part of the data dictionary for the production database rather than the test database). If I do it that, way, I get an identical message except it tells me I'm denied the DELETE command rather than SELECT. I have made sure that my user has INSERT, DELETE, SELECT, UPDATE and CREATE ROUTINE privileges on both databases. However, it seems as though MySQL is reluctant to let this user exercise its privileges on both databases at the same time. How come, and is there a way around this?

    Read the article

  • Mysql - help me optimize this query (improved question)

    - by sandeepan-nath
    About the system: - There are tutors who create classes and packs - A tags based search approach is being followed.Tag relations are created when new tutors register and when tutors create packs (this makes tutors and packs searcheable). For details please check the section How tags work in this system? below. Following is the concerned query SELECT SUM(DISTINCT( t.tag LIKE "%Dictatorship%" )) AS key_1_total_matches, SUM(DISTINCT( t.tag LIKE "%democracy%" )) AS key_2_total_matches, COUNT(DISTINCT( od.id_od )) AS tutor_popularity, CASE WHEN ( IF(( wc.id_wc > 0 ), ( wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date > '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'classes_published', CASE WHEN ( IF(( lp.id_lp > 0 ), ( lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ), 0) ) THEN 1 ELSE 0 END AS 'packs_published', td . *, u . * FROM tutor_details AS td JOIN users AS u ON u.id_user = td.id_user LEFT JOIN learning_packs_tag_relations AS lptagrels ON td.id_tutor = lptagrels.id_tutor LEFT JOIN learning_packs AS lp ON lptagrels.id_lp = lp.id_lp LEFT JOIN learning_packs_categories AS lpc ON lpc.id_lp_cat = lp.id_lp_cat LEFT JOIN learning_packs_categories AS lpcp ON lpcp.id_lp_cat = lpc.id_parent LEFT JOIN learning_pack_content AS lpct ON ( lp.id_lp = lpct.id_lp ) LEFT JOIN webclasses_tag_relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN webclasses AS wc ON wtagrels.id_wc = wc.id_wc LEFT JOIN learning_packs_categories AS wcc ON wcc.id_lp_cat = wc.id_wp_cat LEFT JOIN learning_packs_categories AS wccp ON wccp.id_lp_cat = wcc.id_parent LEFT JOIN order_details AS od ON td.id_tutor = od.id_author LEFT JOIN orders AS o ON od.id_order = o.id_order LEFT JOIN tutors_tag_relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor JOIN tags AS t ON ( t.id_tag = ttagrels.id_tag ) OR ( t.id_tag = lptagrels.id_tag ) OR ( t.id_tag = wtagrels.id_tag ) WHERE ( u.country = 'IE' OR u.country IN ( 'INT' ) ) AND CASE WHEN ( ( t.id_tag = lptagrels.id_tag ) AND ( lp.id_lp 0 ) ) THEN lp.id_status = 1 AND lp.published = 1 AND lpcp.status = 1 AND ( lpcp.country_code = 'IE' OR lpcp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( ( t.id_tag = wtagrels.id_tag ) AND ( wc.id_wc 0 ) ) THEN wc.wc_api_status = 1 AND wc.wc_type = 0 AND wc.class_date '2010-06-01 22:00:56' AND wccp.status = 1 AND ( wccp.country_code = 'IE' OR wccp.country_code IN ( 'INT' ) ) ELSE 1 END AND CASE WHEN ( od.id_od 0 ) THEN od.id_author = td.id_tutor AND o.order_status = 'paid' AND CASE WHEN ( od.id_wc 0 ) THEN od.can_attend_class = 1 ELSE 1 END ELSE 1 END GROUP BY td.id_tutor HAVING key_1_total_matches = 1 AND key_2_total_matches = 1 ORDER BY tutor_popularity DESC, u.surname ASC, u.name ASC LIMIT 0, 20 The problem The results returned by the above query are correct (AND logic working as per expectation), but the time taken by the query rises alarmingly for heavier data and for the current data I have it is like 25 seconds as against normal query timings of the order of 0.005 - 0.0002 seconds, which makes it totally unusable. It is possible that some of the delay is being caused because all the possible fields have not yet been indexed. The tag field of tags table is indexed. Is there something faulty with the query? What can be the reason behind 20+ seconds of execution time? How tags work in this system? When a tutor registers, tags are entered and tag relations are created with respect to tutor's details like name, surname etc. When a Tutors create packs, again tags are entered and tag relations are created with respect to pack's details like pack name, description etc. tag relations for tutors stored in tutors_tag_relations and those for packs stored in learning_packs_tag_relations. All individual tags are stored in tags table. The explain query output:- Please see this screenshot - http://www.test.examvillage.com/Explain_query.jpg

    Read the article

  • mySQL to .XSL help

    - by kielie
    hi guys, I have to create a script that takes a mySQL table, and exports it into .XSL format, and then saves that file into a specified folder on the web host. I got it working, but now I can't seem to get it to automatically save the file to the location without prompting the user. It needs to run every day at a specified time, so it can save the previous days leads into a .XSL file on the web host. Here is the code: <?php // DB TABLE Exporter // // How to use: // // Place this file in a safe place, edit the info just below here // browse to the file, enjoy! // CHANGE THIS STUFF FOR WHAT YOU NEED TO DO $dbhost = "-"; $dbuser = "-"; $dbpass = "-"; $dbname = "-"; $dbtable = "-"; // END CHANGING STUFF $cdate = date("Y-m-d"); // get current date // first thing that we are going to do is make some functions for writing out // and excel file. These functions do some hex writing and to be honest I got // them from some where else but hey it works so I am not going to question it // just reuse // This one makes the beginning of the xls file function xlsBOF() { echo pack("ssssss", 0x809, 0x8, 0x0, 0x10, 0x0, 0x0); return; } // This one makes the end of the xls file function xlsEOF() { echo pack("ss", 0x0A, 0x00); return; } // this will write text in the cell you specify function xlsWriteLabel($Row, $Col, $Value ) { $L = strlen($Value); echo pack("ssssss", 0x204, 8 + $L, $Row, $Col, 0x0, $L); echo $Value; return; } // make the connection an DB query $dbc = mysql_connect( $dbhost , $dbuser , $dbpass ) or die( mysql_error() ); mysql_select_db( $dbname ); $q = "SELECT * FROM ".$dbtable." WHERE date ='$cdate'"; $qr = mysql_query( $q ) or die( mysql_error() ); // Ok now we are going to send some headers so that this // thing that we are going make comes out of browser // as an xls file. // header("Pragma: public"); header("Expires: 0"); header("Cache-Control: must-revalidate, post-check=0, pre-check=0"); header("Content-Type: application/force-download"); header("Content-Type: application/octet-stream"); header("Content-Type: application/download"); //this line is important its makes the file name header("Content-Disposition: attachment;filename=export_".$dbtable.".xls "); header("Content-Transfer-Encoding: binary "); // start the file xlsBOF(); // these will be used for keeping things in order. $col = 0; $row = 0; // This tells us that we are on the first row $first = true; while( $qrow = mysql_fetch_assoc( $qr ) ) { // Ok we are on the first row // lets make some headers of sorts if( $first ) { foreach( $qrow as $k => $v ) { // take the key and make label // make it uppper case and replace _ with ' ' xlsWriteLabel( $row, $col, strtoupper( ereg_replace( "_" , " " , $k ) ) ); $col++; } // prepare for the first real data row $col = 0; $row++; $first = false; } // go through the data foreach( $qrow as $k => $v ) { // write it out xlsWriteLabel( $row, $col, $v ); $col++; } // reset col and goto next row $col = 0; $row++; } xlsEOF(); exit(); ?> I tried using, fwrite to accomplish this, but it didn't seem to go very well, I removed the header information too, but nothing worked. Here is the original code, as I found it, any help would be greatly appreciated. :-) Thanx in advance. :-)

    Read the article

  • HELP ME !! I am Not able to update form data to mysql using php and jquery

    - by Jimson Jose
    i tired and was unable to find the answer i am looking for an answer. my problem is that i am unable to update the values enterd in the form. I have attached all the files i'm using MYSQL database to fetch data. what happens is that i'm able to add and delete records from form using jquery and PHP scripts to MYSQL database, but i am not able to update data which was retrived from database. the file structure is as follows index.php is a file with jquery functions where it displays form for adding new data to MYSQL using save.php file and list of all records are view without refrishing page (calling load-list.php to view all records from index.php works fine, and save.php to save data from form) - Delete is an function called from index.php to delete record from mysql database (function calling delete.php works fine) - Update is an function called from index.php to update data using update-form.php by retriving specific record from mysql tabel, (works fine) Problem lies in updating data from update-form.php to update.php (in which update query is wrriten for mysql) i had tried in many ways at last i had figured out that data is not being transfred from update-form.php to update.php there is a small problem in jquery ajax function where it is not transfering data to update.php page. some thing is missing in calling update.php page it is not entering into that page I am new bee in programming i had collected this script from many forums and made this one.So i was limited in solving this problem i cam to know that this is good platform for me and many where we get a help to create new things.. please guide me with your help to complete my effors !!!!! i will be greatfull to all including ths site which gave me an oppurtunity to present my self..... please find the link below to download all files which is of 35kb (virus free assurance) download mysmallform files in ZIPped format, including mysql query thanks a lot in advance, May GOD bless YOU and THIS SITE

    Read the article

  • PHP/MySQL Swap places in database + JavaScript (jQuery)

    - by James Brooks
    I'm currently developing a website which stores bookmarks in a MySQL database using PHP and jQuery. The MySQL for bookmarks looks like this (CSV format): id,userid,link_count,url,title,description,tags,shareid,fav,date "1";"1";"0";"img/test/google.png";"Google";"Best. Search Engine. Ever.";"google, search, engine";"7nbsp";"0";"1267578934" "2";"1";"1";"img/test/james-brooks.png";"jTutorials";"Best. jQuery Tutorials. Ever.";"jquery, jtutorials, tutorials";"8nbsp";"0";"1267578934" "3";"1";"2";"img/test/benokshosting.png";"Benoks Hosting";"Cheap website hosting";"Benoks, Hosting, server, linux, cpanel";"9nbsp;";"0";"1267578934" "4";"1";"3";"img/test/jbrooks.png";"James Brooks";"Personal website FTW!";"james, brooks, jbrooksuk, blog, personal, portfolio";"1nbsp";"0";"1267578934" "6";"1";"4";"img/test/linkbase.png";"LinkBase";"Store and organise your bookmarks and access them from anywhere!";"linkbase, bookmarks, organisation";"3nbsp";"0";"1267578934" "5";"1";"5";"img/test/jtutorials.png";"jTutorials";"jQuery tutorials, videos and examples!";"jquery, jtutorials, tutorials";"2nbsp";"0";"1267578934" I'm using jQuery Sortable to move the bookmarks around (similar to how Google Chrome does). Here is the JavaScript code I use to format the bookmarks and post the data to the PHP page: $(".bookmarks").sortable({scroll: false, update: function(event, ui){ // Update bookmark position in the database when the bookmark is dropped var newItems = $("ul.bookmarks").sortable('toArray'); console.log(newItems); var oldItems = ""; for(var imgI=0;imgI < newItems.length;imgI++) { oldItems += $("ul.bookmarks li#" + imgI + " img").attr("id") + ","; } oldItems = oldItems.slice(0, oldItems.length-1); console.log("New position: " + newItems); console.log("Old position: " + oldItems); // Post the data $.post('inc/updateBookmarks.php', 'update=true&olditems=' + oldItems + "&newitems=" + newItems, function(r) { console.log(r); }); } }); The PHP page then goes about splitting the posted arrays using explode, like so: if(isset($pstUpdate)) { // Get the current and new positions $arrOldItems = $_POST['olditems']; $arrOldItems = explode(",", $arrOldItems); $arrNewItems = $_POST['newitems']; $arrNewItems = explode(",", $arrNewItems); // Get the user id $usrID = $U->user_field('id'); // Update the old place to the new one for($anID=0;$anID<count($arrOldItems);$anID++) { //echo "UPDATE linkz SET link_count='" . $arrNewItems[$anID] . "' WHERE userid='" . $usrID . "' AND link_count='" . $arrOldItems[$anID] . "'\n"; //echo "SELECT id FROM linkz WHERE link_id='".$arrOldItems[$anID]."' AND userid='".$usrID."'"; $curLinkID = mysql_fetch_array(mysql_query("SELECT id FROM linkz WHERE link_count='".$arrOldItems[$anID]."' AND userid='".$usrID."'")) or die(mysql_error()); echo $arrOldItems[$anID] . " => " . $arrNewItems[$anID] . " => " . $curLinkID['id'] . "\n"; //mysql_query("UPDATE linkz SET link_count='" . $arrNewItems[$anID] . "' WHERE userid='" . $usrID . "' AND link_count='" . $curLinkID['id'] . "'") or die(mysql_error()); // Join a string with the new positions $outPos .= $arrNewItems[$anID] . "|"; } echo substr($outPos, 0, strlen($outPost) - 1); } So, each bookmark is given it's own link_count id (which starts from 0 for each user). Every time a bookmark is changed, I need the link_count to be changed as needed. If we take this array output as the starting places: Array ( [0] => 0 [1] => 1 [2] => 2 [3] => 3 [4] => 4 [5] => 5 ) Each index equalling the link_count position, the resulting update would become: Array ( [0] => 1 [1] => 0 [2] => 3 [3] => 4 [4] => 5 [5] => 2 ) I have tried many ways but none are successful. Thanks in advance.

    Read the article

  • Adjust CSS of all cells of a specific table without giving each cell a unique id?

    - by javanix
    Is there any way to modify the CSS properties of one table's cells based on the table's ids, rather than specific child ids? I would like to change one table's appearance (giving each cell a colored border, for instance) one way, and another table another way, but I'd like to avoid specifying an id for each cell. To be clear, I don't need to individually access each cell in the table - I just want to set all of the properties of "child" cells of various tables.

    Read the article

  • Easiest way to choose a percentage of an amount of rows from a MySQL table?

    - by Rob
    I have a script that has a GET variable: $_GET['percentage'] I have a MySQL table of data. Now lets say that there are 100 rows of data in this table. In pseudo-code: SELECT data FROM table Now would it be possible to select $_GET['percentage'] of random data from table? For example (again in pseudo-code): $_GET['percentage'] = 10; SELECT 10% of data from table order by rand() If this IS possible, how could I do it?

    Read the article

  • How to config putty remote port forwarding to connect mysql?

    - by kev
    I installed MySQL to a Windows box. I want to connect it from a Linux box. I run plink to setup a remote port forwarding in Windows box. I try to connect it from Linux box, but it's not working. Windows (192.168.1.101) C:\> plink -v -N -R 3306:localhost:3306 [email protected] -pw ADMIN Also tried putty with this config: Port forwarding: R3306->localhost:3306 Linux (192.168.1.102) $ mysql ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (2) $ nc localhost 3306 J 5.5.283V6L[fnu¦¦!¦$N>-c-R9bbG{mysql_native_password

    Read the article

  • What kind of server do I need to handle 10 million requests and mySQL queries a day?

    - by Calvin
    I'm a new bie of server administration and I'm looking for a powerful hosting service to host my new website. This website is basically a back-end of an mobile online game, and it will: handle up to 10 million of HTTPS request and mySQL queries a day store up to 2000 GB file on the hard disk transfer probably 5000 GB data in and out per month it runs on PHP and mySQL have 10 million records in mySQL database, for each record there are 5-10 fields, around 100 bytes each I really don't know what kind of a server I need to handle these requirements, my question is: what cpu/ram do I need for a dedicated server or vps? what hosting companies are able to offer this kind of dedicated server or VPS? what about cloud computing? I've researched Amazon EC2 but it seems complicated to me. And I've contacted Rackspace but strangely they said Cloudsites is not suitable for my requirements. I wonder if there is other cloud hosting company. any other alternative method? thanks very much!

    Read the article

  • Puppet: how to use data from a MySQL table in Puppet 3.0 templates?

    - by Luke404
    I have some data whose source-of-truth is in a MySQL database, size is expected to max out at the some-thousands-rows range (in a worst-case scenario) and I'd like to use puppet to configure files on some servers with that data (mostly iterating through those rows in a template). I'm currently using Puppet 3.0.x, and I cannot change the fact that MySQL will be the authoritative source for that data. Please note, data comes from external sources and not from puppet or from the managed nodes. What possible approaches are there? Which one would you recommend? Would External Node Classifiers be useful here? My "last resort" would be regularly dumping the table to a YAML file and reading that through Hiera to a Puppet template, or to directly dump the table in one or more pre-formatted text file(s) ready to be copied to the nodes. There is an unanswered question on SF about system users but the fundamental issue is probably similar to mine - he's trying to get data out of MySQL.

    Read the article

  • Un-table a cell range in Excel 2007

    - by Joe
    In Excel 2007, if you highlight a block of cells and then "Format as Table", it doesn't just apply colors and formatting, it somehow marks those cells as being a table. Now I want to get rid of the table, but keep all the cells (i.e. keep the data). So I tried clearing the table style and formatting, but Excel still recognizes those cells as being a table. I can tell because: When I select a cell that was in the table, Excel still displays the "Table Tools / Design" tab I cannot merge cells that were in the table <- this is what's annoying me So, how do I un-table those cells? I want to keep all the cell data and formatting, but have Excel not recognize them as a table.

    Read the article

  • How to recover from failed Mysql schema update, with replication?

    - by OmerGertel
    I have two MySQL servers configured with master-slave replication. Before we deploy a new application version we: 1) STOP SLAVE 2) Take a MySQL dump of the slave. However, if a mistake is done during the deployment of the new schema version (a table is dropped by mistake, for example), having the slave intact doesn't help. Our service is write-intensive, so we can't turn it back up until we have a master working. If we now load the mysql dump back into the master, it will take a long time during which our service remains down. What is the best-practice to recover from such a mistake? How can I setup the system so I can easily promote the slave, turn on our service and only then tend to the broken database? Mainly, I'm worried with re-syncing the slave and the master after changes are done on the slave.

    Read the article

  • How to connect MySQL database of local server in NetBeans 7.0.1 ( windows)?

    - by diEcho
    Hello All, I am using NetBeans IDE 7.0.1 on Windows 7 very first time for my php. Actually in my company there is a local server ( 192.168.1.99) where all projects resides and we access phpmyadmin of that local server, Although I have added my project folders with NetBeans (this was also very hectic) but now I am having problem to connect database of my local server as I can see 192.168.1.99/phpmyadmin through my browser. I have set below value Server Host : localhost, Server port number : 3306, Administrator username : keshav Administrator password : ****** and when i click on connect, a popup error windows appears with below text Unable to connect to the MySQL server: org.netbeans.api.db.explorer.DatabaseException: org.netbeans.api.db.explorer.DatabaseException: java.sql.SQLException: Access denied for user 'keshav'@'localhost' (using password: YES). The server may not be running or your MySQL connection properties may not be set correctly. Do you want to edit your MySQL connection properties? Please help me out. Thanks

    Read the article

  • Why doesn't my PHP install see the MySQL extension?

    - by Evan Padd
    So I just set up PHP (Version 5.2.17), MySQL (5.5.28), and Apace (2.2) on my Windows 7 computer. I want to test a mysql connection, but the mysql extension is apparently not loaded (based on phpinfo()). Here's what I did: Changed the extension dir in the php.ini (extension_dir = ".;c:\php\ext") and uncommented the extension=php_mysql.dll line Copied libmysql.dll to the Apache's bin directory Added C:\php to the system's $PATH Restarted the server, then the computer And it's still not working. What did I miss? EDIT: I'm looking through phpinfo()'s outout and it says: "Server API | Apache 2.0 Handler" and I'm running 2.2. Is that a problem?

    Read the article

  • Can you link to a good MySQL dumper PHP script?

    - by Ivan
    I need to migrate a website to another host. I have only FTP server access and MySQL name+pass (the MySQL server's IP I was provided is 127.0.0.1, and there's neither PhpMyAdmin nor SSHell to use). A web app run there can access the DB using credentials I know and localhost server. So I'd need a PHP script, that will correctly dump all the available databases of the MySQL server so that they can be imported on the new server. Can you recommend a good one?

    Read the article

  • Which FTP Daemon should I use if I want to use MySQL for authentication?

    - by wag2639
    We want to set up a FTP Daemon on our Ubuntu 10.04 server that can use a simple (probably custom) built web interface for a FTP server using MySQL for authentication. It'll be public facing but only intended for use by a few customers or clients. I know vsftpd, ProFTPd, and Pure-FTPd but I'm not sure which is best for this application. Main features we would like: a. Very good MySQL authentication integration b. Able to specify a list folders/files (folder level is sufficient) each user has access to through MySQL Anything else would just be sprinkles on top.

    Read the article

  • Safety concerns on allowing connections to MySQL with no password on localhost?

    - by ÉricO
    In the case of a Linux system, is there any security concern to let MySQL users with standard privileges (that is, not the root users) connect to the database with no password from localhost? I think that enforcing a password even for localhost can add a layer of protection, since, with no password the database access would be compromised if the SSH access is itself compromised. Considering that, would it be less safe to allow no password connection to MySQL than having the same password for SSH and for MySQL? I don't know if that is to be taken into account, but we also use phpMyAdmin to let users administrate their own database. I am asking because I kinda dislike having to put our database passwords unencrypted in the source or configuration files of our applications, where they can easily be leaked unintentionally. Since our servers are configured to run our applications as the Linux user the application belongs to, I was considering allowing no password from localhost as a simple solution. So, would that be a very bad idea or not?

    Read the article

  • Drupal7 doesn't detect MySQL on CentOS, but Wordpress3 does?

    - by jyaworski
    Hey guys. I'm running CentOS 5.5 here with Apache2, PHP5, and MySQL 5. My wordpress install on the same system runs perfectly, but the drupal7 install script only detects SQLite. The mysql module is enabled in php.ini, so that isn't the problem. Do you think it could be something with Drupal 7, or my PHP install? I tested it on localhost (I'm essentially running ArchLinux with Apache) and it installs just fine. I don't see a difference between my local php.ini and my server php.ini. I get this when accessing install.php on the server. SQLite The type of database your Drupal data will be stored in. Your PHP configuration only supports a single database type, so it has been automatically selected. Edit: The mysql PDO module is installed already.

    Read the article

  • BIND unstable with DLZ+MySQL on Ubuntu 9.10, any ideas?

    - by Chris
    My BIND server keeps dropping out and I can't work out why. Here is some info from the syslog that I think pertains to the failure(s): Apr 22 21:12:17 dnsdebug named[6613]: mysql driver unable to return result set for lookup query Apr 22 21:12:17 dnsdebug kernel: [285552.573949] type=1503 audit(1271963537.759:53): operation="open" pid=6618 parent=1 profile="/usr/sbin/named" requested_mask="::rw" denied_mask="::rw" fsuid=107 ouid=0 name="/dev/tty" Apr 22 21:12:17 dnsdebug named[6613]: mysql driver unable to return result set for lookup query Apr 22 21:13:17 dnsdebug named[6613]: last message repeated 7 times Any ideas? Mysql had a segfault sometimes, but that seems to be no longer an issue. It's the 64bit version of ubuntu too. Sometimes it will return records just fine, other times it appears to just randomly go down.

    Read the article

  • I am trying to setup phpMyAdmin to use with a remote MySQL databases on Scientific Linux release 6.2

    - by techsjs2012
    I am trying to setup phpMyAdmin to use with a remote MySQL databases on Scientific Linux release 6.2. If I use the mysql command line to connect to the remote database it works great but if I use mysqladmin I am getting "#2002 Cannot log in to the MySQL server". I have found if I do a: setenforce 0 It will work from myphpadmin to my remote database but once I reboot or set Scientific Linux setenforce back to one it stops working again.. I know setenforce 0 is not the right thing to do but can someone please give me details steps on how to get this working the right way... thanks I am new to Scientific Linux and been having some issues.. thanks

    Read the article

  • OOMK kills mysql and apache when there is still a lot[?] of mem

    - by Flyer
    let me first say that I'm pretty new ti *nix systems and even more to server management. Anyway, I've got a little problem. I got VPS with 1gb mem, system is debian 6. I have few sites running on it, though some load can only be caused by one of them. Recently, OOMK started to kill mysql, causing wp and phpbb giving error that it can't connect to mysql server. Error itself is not good, especially if it happens at night and site becomes unavailable until I wake up and restart mysql. I have probably bad line in my cron which can be cause of it all (again, I'm new to it) */20 * * * * sync; echo 3 > /proc/sys/vm/drop_caches Well, if you need any information, let me know, since I don't really know which information can be useful here. Also, I'd like to know if it's not too bad to have above cron task.

    Read the article

  • Does it make a difference to read from a file instead of from MySQL?

    - by Joe Huang
    My web server currently is quite loaded. And I have a PHP file that is accessed very often remotely. The PHP file basically makes a MySQL query and returns a JSON formatted string. I am thinking to use a Cron job to write the necessary data into a file every 15 mins, so the PHP file doesn't make a MySQL query, instead it reads from the file. Does it make a difference? I mean to alleviate the server loading (CPU/MySQL) a bit?

    Read the article

  • What is the most secure way to set up a mysql user for Wordpress?

    - by Sinthia V
    I am setting up Subdomain based MU on my domain.Everything is hosted by me running on one CentOS/Webmin VPS. Will I be better off setting the MySQL user's domain as localhost, 127.0.0.1 or with a wildcard %.mydomain.com? Which is more secure? Is localhost === 127.0.0.1? If not what is the difference? Also, what is my domain from MySQL's or Wordpress' pov when I am connected by ssh terminal? How about When I connect by Webmin or Usermin? Does MySQL see me as Webmin or my Unix user?

    Read the article

< Previous Page | 188 189 190 191 192 193 194 195 196 197 198 199  | Next Page >