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  • Help with grasping (INNER?) JOIN

    - by Greenie
    I'm having trouble building a query. I can do what I want in 3 different queries. SELECT id FROM table1 WHERE url LIKE '%/$downloadfile' put that in $url_id SELECT item_id FROM table2 WHERE rel_id = '$url_id'" put that in $item_id SELECT rel_id FROM table2 WHERE rel_id = '$item_id' AND field_id = '42'" put that in $user_id But from reading examples on joins and inner joins I think there's a more elegant way. I cant wrap my brain around writing a better query (but would like to) I can describe how it should go: table1 fields: id, url table2 fields item_id, rel_id, field_id I know the last part of table1.url (LIKE '%/$filename') with that I select table1.id. table1.id is equal to one entry in table2.rel_id. So get that and select the table2.item_id. In table2 there is another entry which has the same table2.item_id and it will have a table2.field_id = '42' And finally the value I need is the table2.rel_id where the table2.field_id was 42. I will fetch that value and put it in $user_id Can this be done with one query using joins/inner joins?

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  • SQL Server indexed view matching of views with joins not working

    - by usr
    Does anyone have experience of when SQL Servr 2008 R2 is able to automatically match indexed view (also known as materialized views) that contain joins to a query? for example the view select dbo.Orders.Date, dbo.OrderDetails.ProductID from dbo.OrderDetails join dbo.Orders on dbo.OrderDetails.OrderID = dbo.Orders.ID cannot be automatically matched to the same exact query. When I select directly from this view ith (noexpand) I actually get a much faster query plan that does a scan on the clustered index of the indexed view. Can I get SQL Server to do this matching automatically? I have quite a few queries and views... I am on enterprise edition of SQL Server 2008 R2.

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  • Is it valid to have more than one question mark in a URL?

    - by Bungle
    I came across the following URL today: http://www.sfgate.com/cgi-bin/blogs/inmarin/detail??blogid=122&entry_id=64497 Notice the doubled question mark at the beginning of the query string: ??blogid=122&entry_id=64497 My browser didn't seem to have any trouble with it, and running a quick bookmarklet: javascript:alert(document.location.search); just gave me the query string shown above. Is this a valid URL? The reason I'm being so pedantic (assuming that I am) is because I need to parse URLs like this for query parameters, and supporting doubled question marks would require some changes to my code. Obviously if they're in the wild, I'll need to support them; I'm mainly curious if it's my fault for not adhering to URL standards exactly, or if it's in fact a non-standard URL.

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  • Mysql 'On Duplicate Key INSERT .... SELECT...'

    - by calumbrodie
    Hi, I'm looking for a way to do the following in mysql. INSERT INTO category (cat_id,sku,description,color) VALUES ('$cat_id','$sku','$description','$color') ON DUPLICATE KEY UPDATE description=$description" this works fine... but I want something further to happen if there is a duplicate key. I want to copy a row from the 'product' table to the 'categorized_products'... AND INSERT categorized_products (a,b,c) SELECT a,b,c FROM products WHERE products.cat = '$cat_id' is there a way to do the INSERT...SELECT as part of the first query or do I need to evaluate the above with mysql_affected_rows ( 1 is updated and == 1 is inserted) and then run my second query. Obviously the above will work but means another query and more LOC. Thanks!

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  • how to order a group result with Linq?

    - by Aaron
    How can I order the results from "group ... by... into..." statement in linq? For instance: var queryResult = from records in container.tableWhatever where records.Time >= DateTime.Today group records by tableWhatever.tableHeader.UserId into userRecords select new { UserID = userRecords.Key, Records = userRecords }; The query returns records in table "contain.tableWhatever" grouped by "UserId". I want the returned results within each group ordered by time decending. How can I do that? More specific, assume the above query return only one group like the following: {UserID = 1, Records= {name1 5/3/2010_7:10pm; name2 5/3/2010_8:10pm; name3 5/3/2010_9:10pm} } After insert the orderby statement in the above query, the returned results should be like this: {UserID = 1, Records= {name3 5/3/2010_9:10pm; name2 5/3/2010_8:10pm; name1 5/3/2010_7:10pm} } Thanks for help!

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  • $where in mongodb web shell not working

    - by Bravo
    i have the below set of test documents which i inserted in to the mongodb and when i use to query the db using the $where get the below exception Error: database error: $where query, but no script engine Any idea why the $where clause not working test data : db.things.save({ "_id" : 1, "domainName" : "test11.com", "hosting" : "hostgator.com" }) db.things.save({ "_id" : 2, "domainName" : "test2.com", "hosting" : "aws.amazon.com"}) db.things.save({ "_id" : 3, "domainName" : "test3.com", "hosting" : "aws.amazon.com" }) db.things.save({ "_id" : 4, "domainName" : "test4.com", "hosting" : "hostgator.com" }) db.things.save({ "_id" : 5, "domainName" : "test5.com", "hosting" : "aws.amazon.com" }) db.things.save({ "_id" : 6, "domainName" : "test6.com", "hosting" : "cloud.google.com" }) db.things.save({ "_id" : 7, "domainName" : "test7.com", "hosting" : "aws.amazon.com" }) db.things.save({ "_id" : 8, "domainName" : "test8.com", "hosting" : "hostgator.com" }) db.things.save({ "_id" : 9, "domainName" : "test9.com", "hosting" : "cloud.google.com" }) db.things.save({ "_id" : 10, "domainName" : "test10.com", "hosting" : "godaddy.com" }) query used : db.things.find( { $where: "this.domainName == 'test11.com'" } );

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  • Intime and OutTime for the Modified date

    - by Jash
    Question is already posted on June 4, but still am not get the Proper answer Again Table Structure: T_Person – Table 1 CARDNO 168 471 488 247 519 518 331 240 518 386 441 331 T_Cardevent – Table 2 CARDEVENTDATE CARDEVENTTIME 20090225 163932 20090225 164630 20090225 165027 20090225 165137 20090225 165147 20090225 165715 20090225 165749 20090303 162059 20090303 162723 20090303 155029 20090303 155707 20090303 162824 Query SELECT CARDNO, CARDEVENTDATE, (1000000 * CAST (CARDEVENTDATE AS BIGINT) + CAST (CARDEVENTTIME AS BIGINT) - 30001) / 1000000 AS CardEvenDateAdjusted, CARDEVENTTIME FROM T_CARDEVENT WHERE (CARDEVENTDATE > 20090601) GROUP BY CARDNO, CARDEVENTDATE, CARDEVENTTIME, (1000000 * CAST(CARDEVENTDATE AS BIGINT) + CAST(CARDEVENTTIME AS BIGINT) - 30001) / 1000000 ORDER BY CARDNO, CARDEVENDATEADJUSTED From this above query date is displaying correctly according to that time 03:00:01 to 03:00:00 How can I get min (time) and Max (time) for the adjusted date? I need the sql query for the above condition. Help me? Urgent Please

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  • how so select similarities in MySQL?

    - by mysqllearner
    Currently, I am doing a search function. Lets say in my database, I have this data: Keyword1 Keyword2 Keyword3 Keysomething Key and the user entered: "Key" as the keyword to search. This is my current query: Q1: SELECT * FROM data WHERE (data_string LIKE '$key%' OR data_string LIKE '%$key%' OR data_string LIKE '%$key') Basically, I have 2 questions: How do I sort by (order by) similarity. From above example, I should have "Key" as my first result. My current result is: Keyword1, Keyword2, Keyword3, Keysomething and Key My SQL query only search by the "data_string" column, what if I want to seach others column? Do I need to do something like this: Q2: SELECT * FROM data WHERE (data_string LIKE '$key%' OR data_string LIKE '%$key%' OR data_string LIKE '%$key') OR (data_other LIKE '$key%' OR data_other LIKE '%$key%' OR data_other LIKE '%$key') ... Is there any better/faster query than Q2?

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  • mysql ON DUPLICATE KEY UPDATE

    - by julio
    Hi-- I'm stuck on a mySQL query using ON DUPLICATE KEY UPDATE. I'm getting the error: mySQL Error: 1062 - Duplicate entry 'hr2461809-3' for key 'fname' The table looks like this: id int(10) NOT NULL default '0', picid int(10) unsigned NOT NULL default '0', fname varchar(255) NOT NULL default '', type varchar(5) NOT NULL default '.jpg', path varchar(255) NOT NULL default '', PRIMARY KEY (id), UNIQUE KEY fname (fname), KEY picid (propid) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; And the query that's breaking is this: INSERT INTO images SET picid=732, fname='hr2461809-3', path='pictures/' ON DUPLICATE KEY UPDATE picid=732, fname='hr2461809-3', path='pictures/' I'm using a very similar query elsewhere in the app with no issues. I'm not sure why this one breaks. I expected that when the UNIQUE KEY on fname gets violated, that it would simply update the row where the violation occurred? Thanks for any help

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  • group by with 3 diffrent

    - by NN
    I have 2 table and I wanna a query with 3 column result in on of them 2 column with view count and title name and in the other 1 column with type_ and i wanna to grouping type_ with max(view count) and show the them title but i didn't have any idea about grouping expression. i think we can solve in by using sub query but i don't know which column use in group by. 2 table join with this expression class pk=resource key i exam this query: SELECT t.title,j.type_ FROM tags asset t,journal article j where type_ in (select type_ from journal article,tags asset where class pk=resource key group by type_) but the answer was wrong

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  • How to retrieve Google Appengine Objects by id (Long value) ?

    - by David
    Hi, i have declared an entity the following way: public class MyEntity { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Long id; @Persistent private String text; //getters and setters } Now I want to retrieve the objects using the id. I tried to manage it from the Google Appengine Data Viewer with "SELECT * FROM MyEntity Where id = 382005" or via a query in a servlet. I get no results returned. But i know for sure that the object with the id exists (i made a jsp which queries all objects in the db and displays them in the db). So what is wrong in my query? Am I querying the wrong field? The Google Appengine Data Viewer names the field "ID/name" and it has the value "id=382005". Do I have to query with this names? I've tried but it didn't work out :(

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  • Get result from mysql orderd by IN clause

    - by SchlaWiener
    I have the following query SELECT * FROM invoice WHERE invoice_id IN (13, 15, 9, 27) My result is: invoice_id | invoice_number | ... ------------------------------------ 9 | 201006003 | 13 | 201006020 | 15 | 201006022 | 27 | 201006035 | which is the result set I want except that is ordered by the invoice_id (which is an autoincrement value). Now I want the result in the order I specified in my query (13, 15, ...). Is there a way to achive that? The background is that I have a DataTable bound to a DataGridView. The user can filter and sort the result but if he want's to print the result I don't use the DataTable for printing because it only contains the most important columns and instead I pull the whole records from the database and pass it to my printing control. I also tried to extend the existing DataTable with the missing results but that seems to slower than using the IN (...) query.

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  • advanced search with mysql

    - by Arsenal
    I'm creating a search function for my website where the user can put in anything he likes in a textfield. It get's matched against anything (name, title, job, car brand, ... you name it) I initially wrote the query with an INNER JOIN on every table that needed to be searched. SELECT column1, column2, ... FROM person INNER JOIN person_car ON ... INNER JOIN car ... This ended up in a query with 6 or 8 INNER JOINs, and a whole lot WHERE ... LIKE '%searchvalue%' Now this query seems to cause a time'out in MySql, and I even got a warning from my hosting provider that the queries just taking up too many resources. Now obviously I'm doing this very wrong, but I was wondering how the correct approach to these kind of search functions is. Thanks!

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  • Group by clause return latest row information

    - by I Like PHP
    below is my table structure table_movie_info i_movie_id |movie_actor_id |movie_actress_id |movie_director_id | movie_producer_id 48 | 5 | 9 | 66 | 21 48 | 6 | 15 | 88 | 22 48 | 7 | 12 | 77 | 23 one more table is table_movie movie_id | movie_year | movie_genre_id |movie_rating 1 | 2009 | 6 | 8 2 | 2001 | 5 | 7.5 48 | 2007 | 3 | 6.8 now i need total movie information using both table,i write below query SELECT * FROM table_movie_info LEFT JOIN table_movie ON movie_id = i_movie_id WHERE i_movie_id=48 GROUP BY i_movie_id above query return only one row , but i need such type of information movie_id=48, actors_id list=5,6,7 acttress_id list=9,15,12 etc.. please tell me the optimized query which h return complete information i need. thanks for helping me always.

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  • Querying Same Lookup Table With Multiple Columns

    - by dmaruca
    I'm a bit confused on this. I have a data table structured like this: Table: Data DataID Val 1 Value 1 2 Value 2 3 Value 3 4 Value 4 Then I have another table structured like this: Table: Table1 Col1 Col2 1 2 3 4 4 3 2 1 Both columns from Table1 point to the data in the data table. How can I get this data to show in a query? For example, a query to return this: Query: Query1 Column1 Column2 Value 1 Value 2 Value 3 Value 4 Value 4 Value 3 Value 2 Value 1 I'm familiar enough with SQL to do a join with one column, but lost beyond that. Any help is appreciated. Sample sql or a link to something to read. Thanks! PS: This is in sqlite

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  • MySQL AND alternative for eatch table in a join

    - by Scott
    I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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  • MySQL AND alternative for each table in a join

    - by Scott
    I have a simple join in a query however I need to have a condition on both of the tables "confirmed='yes'" but if one of the tables doesn't have any that match the query returns with no rows. Database: .----------parties----------. | id - party_id - confirmed | |---------------------------| | 1 1 yes | | 1 2 no | | 1 3 no | +---------------------------+ .-----------events----------. | id - event_id - confirmed | |---------------------------| | 1 1 no | +---------------------------+ Query: SELECT p.party_id, e.event_id FROM parties p LEFT JOIN events e ON p.id=e.id WHERE p.id = '1' AND p.party_id IN (1,2,3) AND e.event_id IN (1) AND p.confirmed='yes' AND e.confirmed='yes' It returns nothing but I want it to return party_id 1 with a empty event_id. I hope this make sense and I not missing anything, Thanks for your help!

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  • Mongo: Finding from multiple queries

    - by waxical
    New to Mongo here. I'm using the PHP lib and trying to work out how I can find in a collection from multiple queries. I could do this by repeating the query with a different query, but I wondered if it can be done in one. I.e. $idsToLookFor = array(2124,4241,5553); $query = $db->thisCollection->find(array('id' => $idsToLookFor)); That's what I'd like to do. However it doesn't work. What I'm trying to do is find a set of results for all the id's at one time. Possible or just do a findOne on each with a foreach/for?

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  • SharePoint 2010 search crawl not working

    - by J. Hammond
    I have the following set up: 1 x Windows server 2008 R2 running SQL 1 x Windows server 2008 R2 running SharePoint 2010. I have an issue with the search service application, the crawl appears to run for a never ending amount of time with 0 successes and 0 failures. Checking the Search Application Topology, I find that "Query Component 0" is "Not Responding". I have tried the following: I have ensured that the index directory has the right permissions applied to it and the search service account is in the right groups to consume those permissions. I have re-created the search service application. I have restarted the search service manually. I have trawled the net as much as possible to find a solution but as of yet have not come across something that has resolved this issue. Any input will be very much appreciated

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  • How do the environments of a standard Terminal command-line and a bash script differ?

    - by fred.bear
    I know there is something different about the environment of the Terminal command-line and the environment in a bash script, but I don't know what that difference is... Here is the example which finally led me to ask this quesiton; it may flush out some of the differences. I am trying to strip leading '0's from a number, with this command. var="000123"; var="${var##+(0)}" ; echo $var When I run this command from the Terminal's command-line, I get: 123 However, when I run it from within a script, it doesn't work; I get: 000123 I'm using Ubuntu 10.04, and tried all the following with the sam results: GNOME Terminal 2.30.2 Konsole 2.4.5 #!/bin/bash #!/bin/sh What is causing this difference? Even if some upgrade will make it work in scripts... I am trying to find out the what and why, so in future, I'll know what to look out for .

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  • Disabling shutdown command for all users, even root - consequences?

    - by Rich
    I would like to disable the shutdown command for all users, even root, on an Ubuntu Server installation. The reason I want to do this is to ensure that I don't get into the habit of shutting down the machine in this way, as I SSH into a lot of production machines at the same time as this one, and I don't want to accidentally shutdown one of the other machines by typing the command into the wrong window. The server I want do disable shutdown on only runs inside VirtualBox on my Windows desktop, and I only use it for local testing so it is not a problem if I can't shut it down from the command line. I have already mitigated the problem a bit by ensuring I have a different password on the VirtualBox image, but obviously if I am within the sudo 'window' on one of the production machines, I could still accidentally shut it down. My questions are: How do I disable the shutdown command? If I do disable the shutdown command, are there any consequences that I should be made aware of? Most specifically, will it disable support for ACPI shutdown that is the equivalent of pressing the power button on a physical machine? Could it affect other generic applications? For information, I just use this VirtualBox image for trying out shell scripts, running Tomcat and Java, and that kind of thing.

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  • How do I switch the Command key and Control key on a MacBook Pro (12.04)?

    - by kalaracey
    I have scoured the web, and I can't seem to get Xmodmap / anything to work properly. I want to swap BOTH my Command keys with my Control key - in essence, inverting what they do currently. How would I do that? I tried xmodmap -e "keycode 133 = Control_L" and corresponding commands for keycodes 134 (right command) and 37 (control left). I even tried these commands, plus xmodmap -pke > ~/.Xmodmap and xmodmap ~/.Xmodmap in .xinitrc. My end goal is I want HUD / Dash to come up when I click control and command to functional control, i.e., control-v is a commond shortcut to paste, i would click command-v

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  • How do I switch the Command key and Control key on a MacBook Pro?

    - by kalaracey
    I have scoured the web, and I can't seem to get Xmodmap / anything to work properly. I want to swap BOTH my Command keys with my Control key - in essence, inverting what they do currently. How would I do that? I tried xmodmap -e "keycode 133 = Control_L" and corresponding commands for keycodes 134 (right command) and 37 (control left). I even tried these commands, plus xmodmap -pke > ~/.Xmodmap and xmodmap ~/.Xmodmap in .xinitrc. My end goal is I want HUD / Dash to come up when I click control and command to functional control, i.e., control-v is a commond shortcut to paste, i would click command-v

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  • 550 operation not permitted using FTP

    - by monkey_boys
    I'm using FTP to manage some files on a site I run but keep seeing this (truncated) error log: Command: DELE calendarpermission.php Response: 550 calendarpermission.php: Operation not permitted [...] Command: DELE button_down.gif Response: 550 button_down.gif: Operation not permitted Command: CWD /domains/example.com/public_html/admincp Response: 250 CWD command successful Command: PWD Response: 257 "/domains/example.com/public_html/admincp" is the current directory Command: RMD control_examples Response: 550 control_examples: Operation not permitted Command: CWD /domains/example.com/public_html Response: 250 CWD command successful Command: PWD Response: 257 "/domains/example.com/public_html" is the current directory Command: RMD admincp Response: 550 admincp: Operation not permitted Status: Retrieving directory listing... Command: PASV Response: 227 Entering Passive Mode (122,155,5,50,138,244). Command: MLSD Response: 150 Opening ASCII mode data connection for MLSD Response: 226 Transfer complete Status: Directory listing successful Status: Set permissions of '/domains/example.com/public_html/admincp' to '777' Command: SITE CHMOD 777 admincp Response: 550 CHMOD 777 admincp: Operation not permitted What do I do to solve this?

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  • Why does the sudo command not work in chroot?

    - by katarina
    I just installed a 32-bit chroot to run on my 64-bit system. In the chroot environment, the sudo command doesn't work, it says sudo: command not found Also, when I try the su root command, my password doesn't work (su: authentication failure). What password do they want? I'm quite new to Ubuntu, so actually I don't really know what I'm doing. I am just trying to follow instructions. I solved this particular problem simply by starting the chroot by the command: katarina@ubuntu:~$ schroot -c oneiric_i386 -u root instead of the one I used the first time: katarina@ubuntu:~$ schroot -a I still have some other problems, but I guess that's not for this question.

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