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  • Grouping timestamps by interval between timestamps, then calculating from group MySQL

    - by Emile
    To put this question into context, I'm trying to calculate "time in app" based on an event log. Assume the following table: user_id event_time 2 2012-05-09 07:03:38 3 2012-05-09 07:03:42 4 2012-05-09 07:03:43 2 2012-05-09 07:03:44 2 2012-05-09 07:03:45 4 2012-05-09 07:03:52 2 2012-05-09 07:06:30 I'd like to get the difference between the highest and lowest event_time from a set of timestamps that are within 2 minutes of eachother (and grouped by user). If a timestamp is outside of a 2 minute interval from the set, it should be considered a part of another set. Desired output: user_id seconds_interval 2 7 (because 07:03:45 - 07:03:38 is 7 seconds) 3 0 (because 07:03:42) 4 9 (because 07:03:52 - 2012-05-09 07:03:43) 2 0 (because 07:06:30 is outside 2 min interval of 1st user_id=2 set) This is what I've tried, although I can't group on seconds_interval (even if I could, I'm not sure this is the right direction): SELECT (max(tr.event_time)-min(tr.event_time)) as seconds_interval FROM some_table tr INNER JOIN TrackingRaw tr2 ON (tr.event_time BETWEEN tr2.event_time - INTERVAL 2 MINUTE AND tr2.event_time + INTERVAL 2 MINUTE) GROUP BY seconds_interval

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  • Partition of tables in MySQL

    - by Joel
    Hello, I have read that in a case where a table has many columns, but most of the time only one of them is used (say a title column in a forum post), a way to increase performance would be a partition to two tables, where one will contain only the title and the other one will contain the other columns (such as the forum post body). However, in case I use select ForumTitle from Forum; won't that be good enough to prevent the load of all columns (such as the forum post's body) to the memory, and eliminate the need of partition? Thanks, Joel

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  • mySQL Left Join on multiple tables with conditions

    - by Jarrod
    Hi, I have a problem. I have 4 tables: Invoice_Payment, Invoice, Client, and Calendar Basically, I have the below query, which works well, except, months with no date_due don't return. I.E only months with a date_due will be returned. I think I have to use a left join and join the calendar table with something like: LEFT JOIN Calendar ON Invoice_Payments.date_paid = Calendar.date_field. But I'm having no luck SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Any help appreciated.

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  • getting a date array from a mysql database?

    - by user296516
    Hi guys, I have a database with date field is this format "2010.06.11. | 10:26 13" What is need is a php array that would hold all the different dates, .i.e. array[0] = "2010.06.09." array[1] = "2010.06.10." array[2] = "2010.06.11." Currently I am doing it by selecting the whole table, then looping through the result and adding the date substr to an array if it is not already there. But maybe there is a faster way? Thanks.

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  • Return order of MySQL SHOW COLUMNS

    - by rich
    Hey guys. Simple one this, but one I can't seem to find any information on so here goes. I need to find the columns in a specific table, which is no problem.... SHOW COLUMNS FROM tablename LIKE '%ColumnPrefix%'; But I need to know what order they will be returned, preferable by choosing to order the results ascending alphabetically. I have had no luck with using ORDER BY Field. Any ideas? Cheers!

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  • Php fetch rows from multiple MySQL tables

    - by Jon McIntosh
    Right now I am fetching all of the rows from one of my tables: query = "SELECT * FROM thread WHERE threadid = 2 ORDER BY threadid DESC"; $result = mysql_query($query); $num_rows = mysql_num_rows($result); if((!is_bool($result) || $result) && $num_rows) { while($row = mysql_fetch_array($result)) { $thread = $row['title']; $threadID = $row['threadid']; $poster = $row['postusername']; } What I want to do is go to another table on my database: "post_display", and get the row 'text' where the threadid = 2.

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  • What is an index in MySQL?

    - by Eric
    http://i.imgur.com/JdsUK.jpg I created a table like the picture above. What are the "Indexes"? primary key? unique? It works well without setting indexes.. What do they do? why do I need them? Also, I set all String fields to TEXT because I didn't know how many characters I need. Is this a good idea? I don't see any difference. Thanks!

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  • data in mysql show after barcode split and matches character

    - by klox
    i need some code for the next step..this my first step: <script> $("#mod").change(function() { var barcode; barCode=$("#mod").val(); var data=barCode.split(" "); $("#mod").val(data[0]); $("#seri").val(data[1]); var str=data[0]; var matches=str.matches(/EE|[EJU]).*(D)/i); }); </script> after matches..i want the result can connect to data base then show data from table inside <div id="value">...how to do that?

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  • MYSQL Inner Join two table over two keys

    - by bertsisterwanda
    I am doing a query to return all users shopping carts, stored in the sb_carts table. The product information stored in sb_carts is referenced over two keys product_sku and school_id. It needs to reference both to return a unique product with unique stock levels etc. When I execute the following query it returns one row, I am expecting 3 rows. I have tried breaking the inner join into two separate joins but this still returns only 1 result. joining only on one key has the desired result, but may be retuning the wrong product. A left join returns 3 rows but some data is missing product specific Here is a simplified example of what I am doing SELECT sb_carts.product_sku FROM sb_carts INNER JOIN sb_products ON sb_products.sku = sb_carts.product_sku AND sb_products.school_id = sb_carts.school_id WHERE sb_carts.order_id = 0 AND sb_carts.user_id = 2 GROUP BY sb_carts.cart_id

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  • MySQL Dynamicly determine the tabel to use with inner join

    - by user366990
    He guys, I'm stuck with a problem and I hope someone can help me out. I have a date. For example 2009-10-1. This date is used to check in which season I am working. This could be summer or winter. If whe are in the summer the table to use for my inner join whould be 'summer09_rooms'. If winter 'winter09_rooms'. So I basicly whant to do a CASE WHEN in my INNER JOIN. How to accomplish this. The query would look like this: SELECT name, arrival_date, departure_date FROM holliday a INNER JOIN ( CASE when arrival_date BETWEEN 2009-10-1 AND 2009-4-1 THEN summer09_rooms b ELSE winter09_rooms b END ) ON a.dossier=b.dossier Of course this query isn't working but now I hope you'l see what I want to accomplish. Kind regards, Digital Human

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  • Data Modeling Help - Do I add another table, change existing table's usage, or something else?

    - by StackOverflowNewbie
    Assume I have the following tables and relationships: Person - Id (PK) - Name A Person can have 0 or more pets: Pet - Id (PK) - PersonId (FK) - Name A person can have 0 or more attributes (e.g. age, height, weight): PersonAttribute _ Id (PK) - PersonId (FK) - Name - Value PROBLEM: I need to represent pet attributes, too. As it turns out, these pet attributes are, in most cases, identical to the attributes of a person (e.g. a pet can have an age, height, and weight too). How do I represent pet attributes? Do I create a PetAttribute table? PetAttribute Id (PK) PetId (FK) Name Value Do I change PersonAttribute to GenericAttribute and have 2 foreign keys in it - one connecting to Person, the other connecting to Pet? GenericAttribute Id (PK) PersonId (FK) PetId (FK) Name Value NOTE: if PersonId is set, then PetId is not set. If PetId is set, PersonId is not set. Do something else?

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  • Can this MySQL subquery be optimised?

    - by Dan
    I have two tables, news and news_views. Every time an article is viewed, the news id, IP address and date is recorded in news_views. I'm using a query with a subquery to fetch the most viewed titles from news, by getting the total count of views in the last 24 hours for each one. It works fine except that it takes between 5-10 seconds to run, presumably because there's hundreds of thousands of rows in news_views and it has to go through the entire table before it can finish. The query is as follows, is there any way at all it can be improved? SELECT n.title , nv.views FROM news n LEFT JOIN ( SELECT news_id , count( DISTINCT ip ) AS views FROM news_views WHERE datetime >= SUBDATE(now(), INTERVAL 24 HOUR) GROUP BY news_id ) AS nv ON nv.news_id = n.id ORDER BY views DESC LIMIT 15

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  • MySQL Insert not working with Date column

    - by Ian McCullough
    Hello All, I am having an issue with a simple insert query into a table. I have this PHP Code $T_MEMBER = "INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('$memberID','$last','$first','$birthdate')"; mysql_query($T_MEMBER) or die(mysql_error()); Here are a few examples of what the query looks like if i echo it: INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('2007','Hayes','Karin','1958-30-10') INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('2020','Long','Peggy','1968-29-5') INSERT INTO T_MEMBER (MEMBER_IDENTIFIER,LAST_NAME,FIRST_NAME,BIRTH_DATE) VALUES ('2021','Torres','Diane','1968-30-8') BIRTH_DATE is a date type column. The problem is, after i do any of these queries, the date shows up as 000-00-00!!!! I have been wracking my brain and i cannot seem to find the issue. Thanks, Ian

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  • Change color of a table cell using javascript using dropdown menu

    - by Mike Burzycki
    I'd like to use some javascript code to change the background color of a single cell within a table. I have some code below which allows me to change the page background color. This is similar in concept to what I would like to do, but I would really like to be able to change just one cell...not the whole page. I have thought about making the rest of the cell borders and background colors white, leaving the cell I want to manipulate transparent, but I think this probably a brute force method that will cause me trouble down the road. Does anyone have any advice to do this with javascript? The page background color changing code is here: <form name="bgcolorForm">Try it now: <select onChange="if(this.selectedIndex!=0) document.bgColor=this.options[this.selectedIndex].value"> <option value="choose">set background color <option value="FFFFCC">light yellow <option value="CCFFFF">light blue <option value="CCFFCC">light green <option value="CCCCCC">gray <option value="FFFFFF">white </select></form> Thanks for the help, Mike

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  • HTML input type="submit" doubles row height in table

    - by FelixM
    I have a HTML table where some rows have a button like this: <td > <form action="..." method="GET"> <input type="submit" value="..."/> </form> </td> The rows with the input have about twice the height of other rows that have otherwise similar data. When I remove the just the input, the row height goes back to normal. I have the same behavior in Firefox and IE. Is there any way I can have normal row height AND the button?

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  • Retrieve part of a MySQL column with PHP

    - by Gerardo Marset
    For instance, if I have the following table: +----+---+----------+ | id | a | position | +----+---+----------+ | 0 | 0 | 0 | | 1 | 0 | 1 | | 2 | 1 | 4 | | 3 | 1 | 9 | | 4 | 1 | 6 | | 5 | 1 | 1 | +----+---+----------+ and I want to get an array that contains the first 100 values from position where a is 1 in ascending order, what would I do? Im guessing something like this: $col = mysql_fetch_array( mysql_query(' SELECT `position` FROM `table` WHERE `a`="1" ORDER BY `position` ASC LIMIT 100 ')); I'd expect to get the following array: +-------+-------+ | index | value | +-------+-------+ | 0 | 1 | | 1 | 4 | | 2 | 6 | | 3 | 9 | +-------+-------+ but it doesn't work. ¿What should I do to make it work? Thanks

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  • PHP Moving mySQL Tree Node

    - by TK
    I am having trouble trying to move sub nodes or parent nodes up or down... not that good at math. CREATE TABLE IF NOT EXISTS `pages` ( page-id mediumint(8) unsigned NOT NULL AUTO_INCREMENT, page-left mediumint(8) unsigned NOT NULL, page-right smallint(8) unsigned NOT NULL, page-title text NOT NULL, page-content text NOT NULL, page-time int(11) unsigned NOT NULL, page-slug text NOT NULL, page-template text NOT NULL, page-parent mediumint(8) unsigned NOT NULL, page-type text NOT NULL, PRIMARY KEY (page-id) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 ; INSERT INTO pages (page-id, page-left, page-right, page-title, page-content, page-time, page-slug, page-template, page-parent, page-type) VALUES (17, 1, 6, '1', '', 0, 'PARENT', '', 0, ''), (18, 2, 5, '2', '', 0, 'SUB', '', 17, ''), (19, 3, 4, '3', '', 0, 'SUB-SUB', '', 18, ''), (20, 7, 8, '5', '', 0, 'TEST', '', 0, ''); As example how would I move TEST up above PARENT and say move SUB down below SUB-SUB by playing with the page-left/page-right IDs? Code is not required just help with the SQL concept or math for it, would help me understand how to move it better...

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  • Fact table with multiple facts

    - by Jeff Meatball Yang
    I have a dimension (SiteItem) has two important facts: perUserClicks perBrowserClicks however, within this dimension, I have groups of dimensions based on an attribute column (let's call the groups AboveFoldItems, LeftNavItems, OnTheFlyItems, etc.) each have more facts that are specific to that group: AboveFoldItems: eyeTime, loadTime LeftNavItems: mouseOverTime OnTheFlyItems: doesn't have any extra, but may in the future Is the following fact table schema ok? DateKey SessionKey SiteItemKey perUserClicks perBrowserClicks eyeTime loadTime mouseOverTime It seems a little wasteful since only some columns pertain to some dimension keys (the irrelevant facts are left NULL). But... this seems like it would be a common problem, so there should be a common solution for this, right?

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  • Loading Fact Table + Lookup / UnionAll for SK lookups.

    - by Nev_Rahd
    I got to populate FactTable with 12 lookups to dimension table to get SK's, of which 6 are to different Dim Tables and rest 6 are lookup to same DimTable (type II) doing lookup to same natural key. Ex: PrimeObjectID = lookup to DimObject.ObjectID = get ObjectSK and got other columns which does same OtherObjectID1 = lookup to DimObject.ObjectID = get ObjectSK OtherObjectID2 = lookup to DimObject.ObjectID = get ObjectSK OtherObjectID3 = lookup to DimObject.ObjectID = get ObjectSK OtherObjectID4 = lookup to DimObject.ObjectID = get ObjectSK OtherObjectID5 = lookup to DimObject.ObjectID = get ObjectSK for such multiple lookup how should go in my SSIS package. for now am using lookup / unionall foreach lookup. Is there a better way to this.

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  • Using javascript on an HTML table?

    - by Michael McKay
    Hi, few questions, just wondering if anyone can help? I have a table with 1 long row (1000 pixels) and one single column, how do i go about creating a method whereby when the mouse cursor is on the leftmost side of the cell, a variable, lets say X is set to 0, the further right the mouse cursor moves in the cell, the value of X increases. I know that sounds like a strange question but im working on a project where this type of functionality is desired. Is there a javascript method to create this feature? Thanks for any help.

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  • get value from MySQL database with PHP

    - by Hristo
    $from = $_POST['from']; $to = $_POST['to']; $message = $_POST['message']; $query = "SELECT * FROM Users WHERE `user_name` = '$from' LIMIT 1"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $fromID = $row['user_id']; } I'm trying to have $formID be the user_id for a user in my database. Each row in the Users table is like: user_id | user_name | user_type 1 | Hristo | Agent So I want $from = 1 but the above code isn't working. Any ideas why?

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  • Sample/Example needed for a table/field setup

    - by acctman
    Can someone explain the statement below to me with a working sample/example. thanks in advance. You can not create duplicate fields, but simply add a single extra field, "coupleId", which would have a unique id for each couple; and two rows (one for each person) per couple; then JOIN the table against itself with a constraint like a.coupleId = b.coupleId AND a.id < b.id so that you can condense the data into a single result row for a given couple.

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  • Problem with auto increment primary key (MySQL).

    - by mathon12
    I have 2 tables each using other's primary key as a foreign key. The primary keys for both are set to auto_increment. The problem is, when I try to create and entry into one of the tables, I have no idea what the primary key of the entry is and can't figure out what to put in the other table as a foreign key. What should I do? Do I drop auto_increment altogether and cook up a unique identifier for each entry so I can use it to address the created entries? I'm using PHP, if that's relevant. Thanks.

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  • List hits per hour from a MySQL table

    - by Axel
    I am trying to work out the hits per hour from a database. Data basically is stored as follows (with other columns) : Table Name: Hits ============================ VisitorIP TIMESTAMP ---------------------------- 15.215.65.65 123456789 I want to display total hits per hour (within the last 6 hours ) including the hours that has no hits. Example of the output: // Assuming now : 21:00 21:00 - 0 hits 20:00 - 1 hits 19:00 - 4 hits 18:00 - 0 hits 17:00 - 2 hits 16:00 - 3 hits i would love to get the data as array, Please note that the stored date is in UNIX time stamp format. and there may be some hours without any hits! Thanks

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  • Nested mysql select statements

    - by Jimmy Kamau
    I have a query as below: $sult = mysql_query("select * from stories where `categ` = 'businessnews' and `stryid`='".mysql_query("SELECT * FROM comments WHERE `comto`='".mysql_query("select * from stories where `categ` ='businessnews'")." ORDER BY COUNT(comto) DESC")."' LIMIT 3") or die(mysql_error()); while($ow=mysql_fetch_array($sult)){ The code above should return the top 3 'stories' with the most comments {count(comto)}. The comments are stored in a different table from the stories. The code above does not return any values and doesn't show any errors. Could someone please help?

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