Search Results

Search found 28793 results on 1152 pages for 'line endings'.

Page 197/1152 | < Previous Page | 193 194 195 196 197 198 199 200 201 202 203 204  | Next Page >

  • troubles with generated constructor in linq2sql

    - by zerkms
    After adding one more table to linq2sql .dbml schema i got Value cannot be null. Parameter name: mapping Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.ArgumentNullException: Value cannot be null. Parameter name: mapping and it refers to autogenerated file: Line 45: #endregion Line 46: Line 47: public db() : Line 48: base(global::data.Properties.Settings.Default.nanocrmConnectionString, mappingSource) Line 49: { Any ideas why this hapenned and how to solve this?

    Read the article

  • why can't I comment lines in visual mode

    - by Haiyuan Zhang
    I want to comment several lines in my .vimrc, the usual way I do it is :x,ys/^/"/ and x stands for the start line number and y stands for the line number of the last line. I read some post which said in visual mode this task can be done by the following step: 1 Select your lines with VISUAL BLOCK 2 press I to insert before all highlighted lines. 3 type your comment charact , in this case should be " 4 then ESC I fllowed the above steps and met met problems in step 2 . the thing is when I select the lines in Visual mode and press I , vim ( I use version7.2) go back to insert mode and the cursor back to the start of the first line. so if you continue to do the step 3 and step 4, you end up in just inserting " at the start the first line , far from what I want to achieve. so could you point out what's wrong with the recipe ? thanks in advance

    Read the article

  • Browser back button creating problem

    - by user175084
    I have a dynamically generated gridview on page with sorting provided in the code behind also. Now i move from page A to page B using a link, this also works fine. But when i press the browser back button and come back to my page A and again try to sort... page A throws an exception... is there a way to program this back button like we program a button normally.. Thanks ` Cannot find column machinename. Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.IndexOutOfRangeException: Cannot find column machinename. Source Error: Line 519: Line 520: //Sort the data. Line 521: dt.DefaultView.Sort = e.SortExpression + " " + GetSortDirection(e.SortExpression); Line 522: GridView1.DataSource = Session["TaskTable"]; Line 523: GridView1.DataBind();`

    Read the article

  • gae error when i login.

    - by zjm1126
    i am using http://code.google.com/p/gaema/source/browse/#hg/demos/webapp, and this is my traceback: Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 510, in __call__ handler.get(*groups) File "D:\gaema\demos\webapp\main.py", line 31, in get google_auth.get_authenticated_user(self._on_auth) File "D:\gaema\demos\webapp\gaema\auth.py", line 641, in get_authenticated_user OpenIdMixin.get_authenticated_user(self, callback) File "D:\gaema\demos\webapp\gaema\auth.py", line 83, in get_authenticated_user url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) File "D:\Python25\lib\urllib.py", line 1250, in urlencode v = quote_plus(str(v)) UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) how to do this thanks ??????????????? ???????? ??????????? ?????????????? ???????

    Read the article

  • Why would a error get thrown inside my try-catch?

    - by George Johnston
    I'm pushing a copy of our application over to a new dev server (IIS7) and the application is blowing up on a line inside of a try-catch block. It doesn't happen locally, it actually obey's the rules of a try-catch block, go figure. Any idea why this would be happening? Shouldn't it just be failing silently? Is there something environmental I need to enable/disable? Exception Details: System.NullReferenceException: Object reference not set to an instance of an object. Line 229: Try Line 230: Here >> : _MemoryStream.Seek(6 * StartOffset, 0) Line 232: _MemoryStream.Read(_Buffer, 0, 6) Line 233: Catch ex As IOException End Try Although it doesn't matter for answering this question, I thought I would mention that it's third party code for the Geo IP lookup.

    Read the article

  • Should I call release on these cocoa objective-c variables?

    - by Andrew Arrow
    In the code below I'm making a new NSString with alloc and initializing it with the contents of some file. Because I'm calling alloc I know it's my responsibility to call release on the string when I'm done. But what about the variables "lines" and "line"? Since the method "componentsSeparatedByString" does not start with the word "new" or "create" can I assume "lines" will be autoreleased? Same question for "line" since "objectAtIndex" also does not start with "new" or "create". NSString* buffer = [[NSString alloc] initWithData:[fileManager contentsAtPath:@"/foo"] encoding:NSUTF8StringEncoding]; NSArray* lines = [buffer componentsSeparatedByString:@"\n"]; NSString* line = [lines objectAtIndex:5]; // do something with line [buffer release]; So is the code above okay? Or should I be calling "release" on lines and line too? Thanks.

    Read the article

  • How can I stop my application?

    - by Roman
    I have the main thread from which I start a window using invokeLater. I run my application from command line. So, when application is running I see the window and my command line is "blocked" by the application. I can stop the application either by closing the window (as a result the command line is unblocked) or by typing Ctrl-C in the command line (as a result the window disappear). I wanted to be able to stop the application by clicking on a button in the window of the application. I used setVisible(false) for that. But in this way I can achieve the goal only partially. My window really disappear but the command line is still blocked. So, the software is still running. Well, I assume it's because some other threads are still running. But how can I easily close all these threads (like I do by closing the window of the application manually).

    Read the article

  • Strange exception while using linq2sql

    - by zerkms
    Description: An unhandled exception occurred during the execution of the current web request. Please review the stack trace for more information about the error and where it originated in the code. Exception Details: System.ArgumentNullException: Value cannot be null. Parameter name: mapping Source Error: Line 45: #endregion Line 46: Line 47: public db() : Line 48: base(global::data.Properties.Settings.Default.nanocrmConnectionString, mappingSource) Line 49: { this is what i get if i implement such class: partial class db { static db _db = new db(); public static db GetInstance() { return _db; } } db is a linq2sql datacontext why this hapenned and how to solve this?

    Read the article

  • Alter table add multiple columns ms sql

    - by phenevo
    Is anyone can tell me where is mistake in this query ALTER TABLE Countries ADD ( HasPhotoInReadyStorage bit, HasPhotoInWorkStorage bit, HasPhotoInMaterialStorage bit, HasText bit); ALTER TABLE Regions ADD ( HasPhotoInReadyStorage bit, HasPhotoInWorkStorage bit, HasPhotoInMaterialStorage bit HasText bit); ALTER TABLE Provinces ADD ( HasPhotoInReadyStorage bit, HasPhotoInWorkStorage bit, HasPhotoInMaterialStorage bit HasText bit); ALTER TABLE Cities ADD ( HasPhotoInReadyStorage bit, HasPhotoInWorkStorage bit, HasPhotoInMaterialStorage bit HasText bit); Alter table Hotels Add { HasPhotoInReadyStorage bit, HasPhotoInWorkStorage bit, HasPhotoInMaterialStorage bit, HasHotelPhotoInReadyStorage bit, HasHotelPhotoInWorkStorage bit, HasHotelPhotoInMaterialStorage bit, HasReporterData bit, HasMovieInReadyStorage bit, HasMovieInWorkStorage bit, HasMovieInMaterialStorage bit }; I get errors: Msg 102, Level 15, State 1, Line 2 Incorrect syntax near '('. Msg 102, Level 15, State 1, Line 9 Incorrect syntax near '('. Msg 102, Level 15, State 1, Line 15 Incorrect syntax near '('. Msg 102, Level 15, State 1, Line 22 Incorrect syntax near '('. Msg 102, Level 15, State 1, Line 29 Incorrect syntax near '{'.

    Read the article

  • Django + WebKit = Broken pipe

    - by Saosin
    I'm running the Django 1.2 development server and I get these Broken Pipe error messages whenever I load a page from it with Chrome or Safari. My co-worker is getting the error as well when he loads a page from his dev server. We don't have these errors when using Opera or Firefox. Traceback (most recent call last): File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 281, in run self.finish_response() File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 321, in finish_response self.write(data) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/site-packages/django/core/servers/basehttp.py", line 417, in write self._write(data) File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 300, in write self.flush() File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/socket.py", line 286, in flush self._sock.sendall(buffer) error: [Errno 32] Broken pipe Can anyone help me out? I'm going crazy over this!

    Read the article

  • Javascript substrings multiline replace by RegExp

    - by Radek Šimko
    Hi, I'm having some troubles with matching a regular expression in multi-line string. <script> var str="Welcome to Google!\n"; str = str + "We are proud to announce that Microsoft has \n"; str = str + "one of the worst Web Developers sites in the world."; document.write(str.replace(/.*(microsoft).*/gmi, "$1")); </script> http://jsbin.com/osoli3/3/edit As you may see on the link above, the output of the code looks like this: Welcome to Google! Microsoft one of the worst Web Developers sites in the world. Which means, that the replace() method goes line by line and if there's no match in that line, it returns just the whole line... Even if it has the "m" (multiline) modifier...

    Read the article

  • Should one use PHP to print all of a page's HTML?

    - by Mala
    Hi So I've always developed PHP pages like this: <?php goes at the top, ?> goes at the bottom, and all the HTML gets either print()ed or echo()ed out. Is that slower than having non-dynamic html outputted outside of <?php ?> tags? I can't seem to find any info about this. Thanks! --Mala UPDATE: the consesus seems to be on doing it my old way being hard to read. This is not the case if you break your strings up line by line as in: print("\n". "first line goes here\n". "second line goes here\n". "third line"); etc. It actually makes it a lot easier to read than having html outside of php structures, as this way everything is properly indented. That being said, it involves a lot of string concatenation.

    Read the article

  • MPI4Py Scatter sendbuf Argument Type?

    - by Noel
    I'm having trouble with the Scatter function in the MPI4Py Python module. My assumption is that I should be able to pass it a single list for the sendbuffer. However, I'm getting a consistent error message when I do that, or indeed add the other two arguments, recvbuf and root: File "code/step3.py", line 682, in subbox_grid i = mpi_communicator.Scatter(station_range, station_data) File "Comm.pyx", line 427, in mpi4py.MPI.Comm.Scatter (src/ mpi4py_MPI.c:44993) File "message.pxi", line 321, in mpi4py.MPI._p_msg_cco.for_scatter (src/mpi4py_MPI.c:14497) File "message.pxi", line 232, in mpi4py.MPI._p_msg_cco.for_cco_send (src/mpi4py_MPI.c:13630) File "message.pxi", line 36, in mpi4py.MPI.message_simple (src/ mpi4py_MPI.c:11904) ValueError: message: expecting 2 or 3 items Here is the relevant code snipped, starting a few lines above 682 mentioned above. for station in stations #snip--do some stuff with station station_data = [] station_range = range(1,len(station)) mpi_communicator = MPI.COMM_WORLD i = mpi_communicator.Scatter(station_range, nsm) #snip--do some stuff with station[i] nsm = combine(avg, wt, dnew, nf1, nl1, wti[i], wtm, station[i].id) station_data = mpi_communicator.Gather(station_range, nsm) I've tried a number of combinations initializing station_range, but I must not be understanding the Scatter argument types properly. Does a Python/MPI guru have a clarification this?

    Read the article

  • PEP8: conflict between W292 and W391

    - by seler
    As far as I know in unix it's a good practice to always have blank line at the end of file - or to put it in other words: every line should end with \n. While checking my python code with PEP8 I noticed that it also states that there should be \n at end of file: W292 no newline at end of file JCR: The last line should have a newline. What's strange, it conflicts with W391: W391 blank line at end of file JCR: Trailing blank lines are superfluous. Okay: spam(1) W391: spam(1)\n How it should be? Should I have blank line at the end of file or not?

    Read the article

  • Dynamically created image doesn't show when <img>'s src is refreshed to point to it

    - by Obay
    Hello, I have a javascript function generateGraph() { ... jQuery.get('chart.php?month='+month+'&year='+year); document.getElementById('graph').src = 'charts/'+month+'_'+year+'.png'; ... } which is called onChange. It basically creates, if not exists, or refreshes if already exists, a PNG image (using the first line above) and supposedly displays the generated image (using the second line above). The first line works, but the second one doesn't. Meaning, the image is generated, but the second line can't display the image, unless the page is reloaded, or if the image being referred to already existed before the page was loaded (meaning the 1st line just "refreshed" the image) Any ideas as to why this is and how to fix it? Thanks much for your help in advance!

    Read the article

  • how to change string values in dictionary to int values

    - by tom smith
    I have a dictionary such as: {'Sun': {'Satellites': 'Mercury,Venus,Earth,Mars,Jupiter,Saturn,Uranus,Neptune,Ceres,Pluto,Haumea,Makemake,Eris', 'Orbital Radius': '0', 'Object': 'Sun', 'RootObject': 'Sun', 'Radius': '20890260'}, 'Earth': {'Period': '365.256363004', 'Satellites': 'Moon', 'Orbital Radius': '77098290', 'Radius': '63710.41000.0', 'Object': 'Earth'}, 'Moon': {'Period': '27.321582', 'Orbital Radius': '18128500', 'Radius': '1737000.10', 'Object': 'Moon'}} I am wondering how to change just the number values to ints instead of strings. def read_next_object(file): obj = {} for line in file: if not line.strip(): continue line = line.strip() key, val = line.split(": ") if key in obj and key == "Object": yield obj obj = {} obj[key] = val yield obj planets = {} with open( "smallsolar.txt", 'r') as f: for obj in read_next_object(f): planets[obj["Object"]] = obj print(planets)

    Read the article

  • Parsing names with pyparsing

    - by johnthexiii
    I have a file of names and ages, john 25 bob 30 john bob 35 Here is what I have so far from pyparsing import * data = ''' john 25 bob 30 john bob 35 ''' name = Word(alphas + Optional(' ') + alphas) rowData = Group(name + Suppress(White(" ")) + Word(nums)) table = ZeroOrMore(rowData) print table.parseString(data) the output I am expecting is [['john', 25], ['bob', 30], ['john bob', 35]] Here is the stacktrace Traceback (most recent call last): File "C:\Users\mccauley\Desktop\client.py", line 11, in <module> eventType = Word(alphas + Optional(' ') + alphas) File "C:\Python27\lib\site-packages\pyparsing.py", line 1657, in __init__ self.name = _ustr(self) File "C:\Python27\lib\site-packages\pyparsing.py", line 122, in _ustr return str(obj) File "C:\Python27\lib\site-packages\pyparsing.py", line 1743, in __str__ self.strRepr = "W:(%s)" % charsAsStr(self.initCharsOrig) File "C:\Python27\lib\site-packages\pyparsing.py", line 1735, in charsAsStr if len(s)>4: TypeError: object of type 'And' has no len()

    Read the article

  • Converting the value from string to integer in a nested dictionary

    - by tom smith
    I want to change the numbers in my dictionary to int values for use later in my program. So far I have import time import math x = 400 y = 300 def read_next_object(file): obj = {} for line in file: if not line.strip(): continue line = line.strip() key, val = line.split(": ") if key in obj and key == "Object": yield obj obj = {} obj[key] = val yield obj planets = {} with open( "smallsolar.txt", 'r') as f: for obj in read_next_object(f): planets[obj["Object"]] = obj print(planets) scale=250/int(max([planets[x]["Orbital Radius"] for x in planets if "Orbital Radius" in planets[x]])) print(scale) and the output is {'Sun': {'Object': 'Sun', 'Satellites': 'Mercury,Venus,Earth,Mars,Jupiter,Saturn,Uranus,Neptune,Ceres,Pluto,Haumea,Makemake,Eris', 'Orbital Radius': '0', 'RootObject': 'Sun', 'Radius': '20890260'}, 'Moon': {'Object': 'Moon', 'Orbital Radius': '18128500', 'Period': '27.321582', 'Radius': '1737000.10'}, 'Earth': {'Object': 'Earth', 'Satellites': 'Moon', 'Orbital Radius': '77098290', 'Period': '365.256363004', 'Radius': '6371000.0'}} 3.2426140709476178e-06 I want to be able to convert the numbers in the dict to ints for further use. Any help in greatly appreciated.

    Read the article

  • More XML Problems - Undeclared Entity 'nbsp'

    - by Gogster
    I'm getting the error: Line 49: xml = r.ReadToEnd(); Line 50: Line 51: System.Xml.Linq.XDocument xmlDoc = System.Xml.Linq.XDocument.Parse(xml); Line 52: Line 53: var query = from p in xmlDoc.Descendants("member") On my XML. When I run the code to generate the XML in an empty page, it runs without error, if I call the code within my webpage it throws this error. The only 'nbsp' on the page is a doctype declaration at the top of the XSLT: <!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]> I'm at a loss as to where this error is coming from and I am looking for suggestions please! Thanks.

    Read the article

  • Twisted chainDeferred not working as expected

    - by Martin Gergov
    I have a problem figuring out a somewhat simple twisted python code. From what I have red in the docs, the code here should work without Unhandled Error. I get this: HELLO! HANDLED! HANDLED 2! Unhandled error in Deferred: Unhandled Error Traceback (most recent call last): File "package_tester.py", line 31, in <module> a().callback(2) File "/usr/local/lib/python2.7/dist-packages/twisted/internet/defer.py", line 368, in callback self._startRunCallbacks(result) File "/usr/local/lib/python2.7/dist-packages/twisted/internet/defer.py", line 464, in _startRunCallbacks self._runCallbacks() --- <exception caught here> --- File "/usr/local/lib/python2.7/dist-packages/twisted/internet/defer.py", line 551, in _runCallbacks current.result = callback(current.result, *args, **kw) File "package_tester.py", line 5, in c raise Exception() exceptions.Exception: Isn't the failure from the chained deferred passed to end() errback ?

    Read the article

  • Google App Engine python - Self is not defined

    - by sdasdas
    I have a request that maps to this class ChatMsg It takes in 3 get variables, username, roomname, and msg. But it fails on this last line here. class ChatMsg(webapp.RequestHandler): # this is line 239 def get(self): username = urllib.unquote(self.request.get('username')) roomname = urllib.unquote(self.request.get('roomname')) # this is line 242 When it tries to assign roomname, it tells me: <type 'exceptions.NameError'>: name 'self' is not defined Traceback (most recent call last): File "/base/data/home/apps/chatboxes/1.341998073649951735/chatroom.py", line 239, in <module> class ChatMsg(webapp.RequestHandler): File "/base/data/home/apps/chatboxes/1.341998073649951735/chatroom.py", line 242, in ChatMsg roomname = urllib.unquote(self.request.get('roomname')) what the hell is going on to make self not defined

    Read the article

  • Can not access android /data folder?

    - by fonter
    try { Runtime rt = Runtime.getRuntime(); Process pcs = rt.exec("ls -l /data"); BufferedReader br = new BufferedReader(new InputStreamReader(pcs .getInputStream())); String line = null; while ((line = br.readLine()) != null) { Log.e("line","line="+line); } br.close(); pcs.waitFor(); int ret = pcs.exitValue(); Log.e("ret","ret="+ret); } catch (Exception e) { Log.e("Exception", "Exception", e); } only print "ret=0",How to print the correct path?

    Read the article

  • Google app engine error when I login.

    - by zjm1126
    i am using http://code.google.com/p/gaema/source/browse/#hg/demos/webapp, and this is my traceback: Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 510, in __call__ handler.get(*groups) File "D:\gaema\demos\webapp\main.py", line 31, in get google_auth.get_authenticated_user(self._on_auth) File "D:\gaema\demos\webapp\gaema\auth.py", line 641, in get_authenticated_user OpenIdMixin.get_authenticated_user(self, callback) File "D:\gaema\demos\webapp\gaema\auth.py", line 83, in get_authenticated_user url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) File "D:\Python25\lib\urllib.py", line 1250, in urlencode v = quote_plus(str(v)) UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128) how to do this thanks updated i change the code from args = dict((k, v[-1]) for k, v in self.request.arguments.iteritems()) args["openid.mode"] = u"check_authentication" url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) to args = dict((k, v[-1].encode('utf-8')) for k, v in self.request.arguments.iteritems()) args["openid.mode"] = u"check_authentication" url = self._OPENID_ENDPOINT + "?" + urllib.urlencode(args) but also error.

    Read the article

  • Access VBA remove CR & LF only from the beginning of a text string by searching for them

    - by uZI
    Hi there I need to remove line breaks from the beginning of a memo type records. I dont want to use the replace function as it would remove all line breaks from the record which is not desired. Its only the line breaks at the beginning of the field that I am interested in removing. Furthermore, the my records do not always begin with a line break so I cant really use text positioning, the solution would be to look for line break at the beginning instead of always expecting it at the beginning. click here for a sample of what my data looks like any help will be greatly appreciated

    Read the article

  • asp.net Configuration Error on host

    - by zey
    I uploaded my asp.net site to hosting site , and my site browse correctly . But when I go to login url , it's show me the error Configuration Error Description: An error occurred during the processing of a configuration file required to service this request. Please review the specific error details below and modify your configuration file appropriately. Parser Error Message: It is an error to use a section registered as allowDefinition='MachineToApplication' beyond application level. This error can be caused by a virtual directory not being configured as an application in IIS. Source Error: Line 23: </assemblies> Line 24: </compilation> Line 25: <authentication mode="Forms"> Line 26: <forms loginUrl="~/Account/Login.aspx" timeout="2880" /> Line 27: </authentication> How can I fix it ?

    Read the article

< Previous Page | 193 194 195 196 197 198 199 200 201 202 203 204  | Next Page >