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  • Getting Junk characters while trying to print the file contents using Java

    - by user1523797
    I am reading a file's contents and trying to print the contents using java. But it prints junk characters along with the file content. Code: import java.io.*; public class ReadFile { public String readFile(String filePath){ StringBuilder contents = new StringBuilder(); File file = new File(filePath); try{ String lines = null; FileReader fileReader1 = new FileReader(file); BufferedReader buffer = new BufferedReader(fileReader1); while((lines = buffer.readLine())!=null){ contents.append(lines); } buffer.close(); } catch(FileNotFoundException ex){ System.out.println("File not found."); }catch(IOException ex){ System.out.println("Exception ocurred."); } return contents.toString(); } public static void main(String[] args){ ReadFile rf = new ReadFile(); String lines = rf.readFile("C:\\Data\\FaultDn.txt"); System.out.println("Original file contents: " + lines); } } The file contents are: partner.cisco.com:org-root/mac-pool-QA_MAC_Pool_5-Sep-2012_12:00 The output is: ![Alt Output](C:\Users\safarhee\Desktop\Output.jpg) Can you please point me to what I am missing in this code?

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  • is there a Java GUI for dummies ?

    - by MHero
    Hello, first I want to apologize about my english, it may be not clear enough. Well, I'm new to Java programming, and I search over this web about use of Swing, AWT, 2D, etc. but I didn't get the answer I was looking for. I want to know about a book or method to learn Java GUI programming (not even sure this is a propper term). Previous answers guide me to Filthy Rich Clients by Romain Guy and also to The Swing Tutorial in Sun Web Page. and No offense, but...the first one seems too complex and the second one a bit disorganize. so I ask about a more "for dummies" method. Thanks EDIT: Thanks everyboy, you're very kind and serious. I want to clear some things that I didn't state for being my first question. I dont' want to use autogenerated code(Don't want to say why only focus on my question for consistency) Also I've read Deitel & Deitel and it's a good beginners book but it seems to me that doesn't cover layout(and other details) Finally, I tried to read netbeans generated code but it's a mess find method by method and function by function the way that the IDE does it I hope this edition helps to solve my question

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  • java - find out the type of class which implements of other classes

    - by Johnzzz
    i have a kind of specific problem, let's say, that i have public interface A { } //------------------------------ public class B implements A{ static int countx = 0; } //---------------------------------- public class C implements A{ static int county = 0; } //---------------------------------- public class Arc { public A from; public A to; //======================================== and now I have an object a (which is an instance of Arc) and I want to find out whether it is an instance of B or C and get to the atributes countX or countY (stg like a.from.countX) any ideas? :)

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  • Read large amount of data from file in Java

    - by Crozin
    Hello I've got text file that contains 1 000 002 numbers in following formation: 123 456 1 2 3 4 5 6 .... 999999 100000 Now I need to read that data and allocate it to int variables (the very first two numbers) and all the rest (1 000 000 numbers) to an array int[]. It's not a hard task, but - it's horrible slow. My first attempt was java.util.Scanner: Scanner stdin = new Scanner(new File("./path")); int n = stdin.nextInt(); int t = stdin.nextInt(); int array[] = new array[n]; for (int i = 0; i < n; i++) { array[i] = stdin.nextInt(); } It works as excepted but it takes about 7500 ms to execute. I need to fetch that data in up to several hundred of milliseconds. Then I tried java.io.BufferedReader: Using BufferedReader.readLine() and String.split() I got the same results in about 1700 ms, but it's still too many. How can I read that amount of data in less that 1 second? The final result should be equal to: int n = 123; int t = 456; int array[] = { 1, 2, 3, 4, ..., 999999, 100000 };

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  • Execute external program from Java

    - by Saurabh Lalwani
    Hi, I am trying to execute a program from the Java code. Here is my code: public static void main(String argv[]) { try { String line; Process p = Runtime.getRuntime().exec( "/bin/bash -c ls > OutputFileNames.txt"); BufferedReader input = new BufferedReader( new InputStreamReader(p.getInputStream())); while ((line = input.readLine()) != null) { System.out.println(line); } input.close(); } catch (Exception err) { err.printStackTrace(); } } My OS is Mac OS X 10.6. If I remove the "> OutputFileNames.txt" from the getRuntime().exec() method, all the file names are printed on the console just fine. But I need it to be printed to a file. Also, if I change the command to: Process p = Runtime.getRuntime().exec( "cmd \c dir > OutputFileNames.txt"); and run it on Windows, it runs and prints the results in the file perfectly fine too. I have read the other posts for executing another application from Java but none seemed to relate to my problem. I would really appreciate any help I can get. Thanks,

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  • Java JRE vs GCJ

    - by Martijn Courteaux
    Hi, I have this results from a speed test I wrote in Java: Java real 0m20.626s user 0m20.257s sys 0m0.244s GCJ real 3m10.567s user 3m5.168s sys 0m0.676s So, what is the but of GCJ then? With this results I'm sure I'm not going to compile it with GCJ! I tested this on Linux, are the results in Windows maybe better than that? This was the code from the application: public static void main(String[] args) { String str = ""; System.out.println("Start!!!"); for (long i = 0; i < 5000000L; i++) { Math.sqrt((double) i); Math.pow((double) i, 2.56); long j = i * 745L; String string = new String(String.valueOf(i)); string = string.concat(" kaka pipi"); // "Kaka pipi" is a kind of childly call in Dutch. string = new String(string.toUpperCase()); if (i % 300 == 0) { str = ""; } else { str += Long.toHexString(i); } } System.out.println("Stop!!!"); }

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  • Referencing java resource files for cold fusion

    - by Chimeara
    I am using a .Jar file containing a .properties file in my CF code, however it seems unable to find the .properties file when run from CF. My java code is: String key =""; String value =""; try { File file = new File("src/test.properties"); FileInputStream fileInput = new FileInputStream(file); Properties properties = new Properties(); properties.load(fileInput); fileInput.close(); Enumeration enuKeys = properties.keys(); while (enuKeys.hasMoreElements()) { key = (String) enuKeys.nextElement(); value = properties.getProperty(key); //System.out.println(key + ": " + value); } } catch (FileNotFoundException e) { e.printStackTrace(); key ="error"; } catch (IOException e) { e.printStackTrace(); key ="error"; } return(key + ": " + value); I have my test.properties file in the project src folder, and make sure it is selected when compiling, when run from eclipse it gives the expected key and value, however when run from CF I get the caught errors. My CF code is simply: propTest = CreateObject("java","package.class"); testResults = propTest.main2(); Is there a special way to reference the .properties file so CF can access it, or do I need to include the file outside the .jar somewhere?

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  • Java if/else behaving strangely

    - by Alex
    I'm a real newbie to java, so please excuse me if this is a hopelessly straightforward problem. I have the following from my java game server: // Get input from the client DataInputStream in = new DataInputStream (server.getInputStream()); PrintStream out = new PrintStream(server.getOutputStream()); disconnect=false; while((line = in.readLine().trim()) != null && !line.equals(".") && !line.equals("") && !disconnect) { System.out.println("Received "+line); if(line.equals("h")){ out.println("h"+EOF); // Client handshake System.out.println("Matched 1"); }else if (line.equals("<policy-file-request/>")) { out.println("..."+EOF); // Policy file System.out.println(server.getInetAddress()+": Policy Request"); disconnect=true; System.out.println("Matched 2"); }else if(line.substring(0,3).equals("GET")||line.substring(0,4).equals("POST")){ out.println("HTTP/1.0 200 OK\nServer: VirtuaRoom v0.9\nContent-Type: text/html\n\n..."); // HTML status page disconnect=true; System.out.println("Matched 3"); } else { System.out.println(server.getInetAddress()+": Unknown command, client disconnected."); disconnect=true; System.out.println("Matched else"); } } server.close(); First of all, the client sends an "h" packet, and expects the same back (handshake). However, I want it to disconnect the client when an unrecognised packet is received. For some reason, it responds fine to the handshake and HTML status request, but the else clause is never executed when there's an unknown packet. Thanks

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  • Why aren't Java's generics implicitly polymorphic?

    - by froadie
    I'm a bit confused about how Java generics handle inheritance / polymorphism. Assume the following hierarchy - Animal (Parent) Dog - Cat (Children) So suppose I have a method doSomething(List<Animal> animals). By all the rules of inheritance and polymorphism, I would assume that a List<Dog> is a List<Animal> and a List<Cat> is a List<Animal> - and so either one could be passed to this method. Not so. If I want to achieve this behavior, I have to explicitly tell the method to accept a list of any subset of Animal by saying doSomething(List<? extends Animal> animals). I understand that this is Java's behavior. My question is why? Why is polymorphism generally implicit, but when it comes to generics it must be specified?

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  • How to send java.util.logging to log4j?

    - by matt b
    I have an existing application which does all of its logging against log4j. We use a number of other libraries that either also use log4j, or log against Commons Logging, which ends up using log4j under the covers in our environment. One of our dependencies even logs against slf4j, which also works fine since it eventually delegates to log4j as well. Now, I'd like to add ehcache to this application for some caching needs. Previous versions of ehcache used commons-logging, which would have worked perfectly in this scenario, but as of version 1.6-beta1 they have removed the dependency on commons-logging and replaced it with java.util.logging instead. Not really being familiar with the built-in JDK logging available with java.util.logging, is there an easy way to have any log messages sent to JUL logged against log4j, so I can use my existing configuration and set up for any logging coming from ehcache? Looking at the javadocs for JUL, it looks like I could set up a bunch of environment variables to change which LogManager implementation is used, and perhaps use that to wrap log4j Loggers in the JUL Logger class. Is this the correct approach? Kind of ironic that a library's use of built-in JDK logging would cause such a headache when (most of) the rest of the world is using 3rd party libraries instead.

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  • Why Is Java Missing Access Specifiers?

    - by Tom Tresansky
    Does anyone understand why Java is missing: An access specifier which allows access by the class and all subclasses, but NOT by other classes in the same package? (Protected-minus) An access specifier which allows access by the class, all classes in the same package, AND all classes in any sub-package? (Default-plus) An access specifier which adds classes in sub-packages to the entities currently allowed access by protected? (Protected-plus) I wish I had more choices than protected and default. In particular, I'm interested in the Protected-plus option. Say I want to use a Builder/Factory patterned class to produce an object with many links to other objects. The constructors on the objects are all default, because I want to force you to use the factory class to produce instances, in order to make sure the linking is done correctly. I want to group the factories in a sub-package to keep them all together and distinct from the objects they are instantiating---this just seems like a cleaner package structure to me. No can do, currently. I have to put the builders in the same package as the objects they are constructing, in order to gain the access to defaults. But separating project.area.objects from project.area.objects.builders would be so nice. So why is Java lacking these options? And, is there anyway to fake it?

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  • need help with some basic java.

    - by Racket
    Hi, I'm doing the first chapter exercises on my Java book and I have been stuck for a problem for a while now. I'll print the question, prompt/read a double value representing a monetary amount. Then determine the fewest number of each bill and coin needed to represent that amount, starting with the highest (assume that a ten dollar bill is the maximum size needed). For example, if the value entered is 47,63 (forty-seven dollars and sixty-three cents), and the program should print the equivalent amount as: 4 ten dollar bills 1 five dollar bills 2 one dollar bills 2 quarters 1 dimes 0 nickels 3 pennies" etc. I'm doing an example exactly as they said in order to get an idea, as you will see in the code. Nevertheless, I managed to print 4 dollars, and I can't figure out how to get "1 five dollar", only 7 dollars (see code). Please, don't do the whole code for me. I just need some advice in regards to what I said. Thank you. import java.util.Scanner; public class PP29 { public static void main (String[] args) { Scanner sc = new Scanner (System.in); int amount; double value; double test1; double quarter; System.out.println("Enter \"double\" value: "); value = sc.nextDouble(); amount = (int) value / 10; // 47,63 / 10 = 4. int amount2 = (int) value % 10; // 47 - 40 = 7 quarter = value * 100; // 47,63 * 100 = 4736 int sum = (int) quarter % 100; // 4763 / 100 => 4763-4700 = 63. System.out.println(amount); System.out.println(amount2); } }

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  • how to do sorting using java

    - by karthikacyr
    hi friends, I have text file with list of alphabets and numbers. I want to do sorting w.r.t this number using java. My text file looks like this: a---12347 g---65784 r---675 I read the text file and i split it now. But i dont know how to perform sorting . I am new to java. Please give me a idea. My output want to be g---65784 a---12347 r---675 Plese help me. Thanks in advance. My coding is String str = ""; BufferedReader br = new BufferedReader(new FileReader("counts.txt")); while ((str = br.readLine()) != null) { String[] get = str.split("----"); When i search the internet all suggest in the type of arrays. I tried. But no use.How to inlude the get[1] into array. int arr[]=new int[50] arr[i]=get[1]; for(int i=0;i<50000;i++){ for(int j=i+1;j<60000;j++){ if(arr[i]arr[j]){ System.out.println(arr[i]); } }

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  • Java Socket Closes After Connection?

    - by Matthew
    Why does this port/socket close once a connection has been made by a client? package app; import java.io.*; import java.net.*; public class socketServer { public static void main(String[] args) { int port = 3333; boolean socketBindedToPort = false; try { ServerSocket ServerSocketPort = new ServerSocket(port); System.out.println("SocketServer Set Up on Port: " + port); socketBindedToPort = true; if(socketBindedToPort == true) { Socket clientSocket = null; try { clientSocket = ServerSocketPort.accept();//This method blocks until a socket connection has been made to this port. System.out.println("Waiting for client connection on port:" + port); /** THE CLIENT HAS MADE A CONNECTION **/ System.out.println("CLIENT IS CONENCTED"); } catch (IOException e) { System.out.println("Accept failed: " + port); System.exit(-1); } } else { System.out.println("Socket did not bind to the port:" + port); } } catch(IOException e) { System.out.println("Could not listen on port: " + port); System.exit(-1); } } }

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  • Drag and Drop and identify locations with java

    - by out_sider
    I'm trying to do something quite simple, but I'm having a hard time finding good examples on the net to what I want specifically. I'd like to somehing very similer to what it's here: Dao It's a simple game called DAO and I just need to have a background image with 16 squares (4x4) and drag and drop the images (pieces) on each square to the others. I'm developing the interface using swing and I simply want to know a good place to find tutorials for such implementations or a simple suggestion on how to do it. Thanks in advance

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  • Avoiding instanceof in Java

    - by Mark Lutton
    Having a chain of "instanceof" operations is considered a "code smell". The standard answer is "use polymorphism". How would I do it in this case? There are a number of subclasses of a base class; none of them are under my control. An analogous situation would be with the Java classes Integer, Double, BigDecimal etc. if (obj instanceof Integer) {NumberStuff.handle((Integer)obj);} else if (obj instanceof BigDecimal) {BigDecimalStuff.handle((BigDecimal)obj);} else if (obj instanceof Double) {DoubleStuff.handle((Double)obj);} I do have control over NumberStuff and so on. I don't want to use many lines of code where a few lines would do. (Sometimes I make a HashMap mapping Integer.class to an instance of IntegerStuff, BigDecimal.class to an instance of BigDecimalStuff etc. But today I want something simpler.) I'd like something as simple as this: public static handle(Integer num) { ... } public static handle(BigDecimal num) { ... } But Java just doesn't work that way. I'd like to use static methods when formatting. The things I'm formatting are composite, where a Thing1 can contain an array Thing2s and a Thing2 can contain an array of Thing1s. I had a problem when I implemented my formatters like this: class Thing1Formatter { private static Thing2Formatter thing2Formatter = new Thing2Formatter(); public format(Thing thing) { thing2Formatter.format(thing.innerThing2); } } class Thing2Formatter { private static Thing1Formatter thing1Formatter = new Thing1Formatter(); public format(Thing2 thing) { thing1Formatter.format(thing.innerThing1); } } Yes, I know the HashMap and a bit more code can fix that too. But the "instanceof" seems so readable and maintainable by comparison. Is there anything simple but not smelly?

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  • Dont understand the concept of extends in URL.openConnection() in JAVA

    - by user1722361
    Hi I am trying to learn JAVA deeply and so I am digging into the JDK source code in the following lines: URL url = new URL("http://www.google.com"); URLConnection tmpConn = url.openConnection(); I attached the source code and set the breakpoint at the second line and stepped into the code. I can see the code flow is: URL.openConnection() - sun.net.www.protocol.http.Handler.openConnection() I have two questions about this First In URL.openConnection() the code is: public URLConnection openConnection() throws java.io.IOException { return handler.openConnection(this); } handler is an object of URLStreamHandler, define as blow transient URLStreamHandler handler; But URLStreamHandler is a abstract class and method openConnection() is not implement in it so when handler calls this method, it should go to find a subclass who implement this method, right? But there are a lot classes who implement this methods in sun.net.www.protocol (like http.Hanlder, ftp.Handler ) How should the code know which "openConnection" method it should call? In this example, this handler.openConnection() will go into http.Handler and it is correct. (if I set the url as ftp://www.google.com, it will go into ftp.Handler) I cannot understand the mechanism. second. I have attached the source code so I can step into the JDK and see the variables but for many classes like sun.net.www.protocol.http.Handler, there are not source code in src.zip. I googled this class and there is source code online I can get but why they did not put it (and many other classes) in the src.zip? Where can I find a comprehensive version of source code? Thanks!

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  • Java Daemon Threading with JNI

    - by gwin003
    I have a Java applet that creates a new non-daemon thread like so: Thread childThread = new Thread(new MyRunnable(_this)); childThread.setDaemon(false); childThread.start(); Then my MyRunnable object calls a native method that is implemented in C++: @Override public void run() { while (true) { if (!ran) { System.out.println("isDaemon: " + Thread.currentThread().isDaemon()); _applet.invokePrintManager(_applet.fFormType, _applet.fFormName, _applet.fPrintImmediately, _applet.fDataSet); ran = true; } } } This C++ method calls into a C# DLL that shows a form. My problem is, whenever the user navigates away from the page with a Java applet on it, JVM (and my C# form) is killed. I need the form and JVM to remain open until it is closed by the user. I tried setting my thread to be a non-daemon thread, which is working because System.out.println("isDaemon: " + Thread.currentThread().isDaemon() prints isDaemon: false. Is there something related to the way that the C# form is created (is there another thread I'm not accounting for) or something I am overlooking?? My thread is not a daemon thread, but the JVM is being killed anyways.

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  • Java: Incompatible Types

    - by user2922081
    import java.text.*; import java.util.*; public class Proj3 { public static void main(String[]args){ // DecimalFormat df = new DecimalFormat("#0.00”); Scanner s = new Scanner(System.in); int TotalHours = 0; int TotalGrade = 0; System.out.print("How many courses did you take? "); int Courses = Integer.parseInt(s.nextLine()); System.out.println(""); int CourseNumber = Courses - (Courses - 1); while (Courses > 0){ System.out.print("Course (" + CourseNumber +"): How many hours? "); int Hours = Integer.parseInt(s.nextLine()); TotalHours = TotalHours + Hours; System.out.print("Course (" + CourseNumber +"): Letter grade? "); char Grade = s.nextLine().charAt(0); if (Grade == 'A'){ TotalGrade = TotalGrade + (4 * Hours); } if (Grade == 'B'){ TotalGrade = TotalGrade + (3 * Hours); } if (Grade == 'C'){ TotalGrade = TotalGrade + (2 * Hours); } if (Grade == 'D'){ TotalGrade = TotalGrade + (1 * Hours); } Courses = Courses - 1; CourseNumber = CourseNumber + 1; } Double GPA = TotalGrade / TotalHours; System.out.println(df.format(GPA)); } } This is for an assignment and I don't know how to fix my problem. The Double GPA = TotalGrade / ToutalHours; line is coming up with the Incompatible Types error. Also I'm supposed to include the DecimalFormat df = new DecimalFormat("#0.00”);line at the beginning of the main but its not working. Anything is very helpful. Thanks

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  • How to start networking on a wired interface before logon in Ubuntu Desktop Edition

    - by Burly
    Problem Ubuntu 9.10 Desktop Edition (and possibly previous versions as well, I haven't tested them) has no network connections after boot until at least 1 user logs in. This means any services that require networking (e.g. openssh-server) are not available until someone logs in locally either via gdm, kdm, or a TTY. Background Ubuntu 9.10 Desktop Edition uses the NetworkManager service to take commands from the nm-applet in Gnome (or it's equivalent in KDE). As I understand it, while NetworkManager is running at boot, it is not issued any commands to connect until you login for the first time because nm-applet isn't running until you login and your Gnome session starts (or similar for KDE). I'm not sure what prompts NetworkManager to connect to the network when you login via a TTY. There are several relevant variables involved in starting up the network connections including: Wired vs Wireless (and the resulting drivers, SSID, passwords, and priorities) Static vs DHCP Multiple interfaces Constraints Support Ubuntu 9.10 Karmic Koala (bonus points for additional supported versions) Support wired eth0 interface Receive an IP address via DHCP Receive DNS information via DHCP (obviously the DHCP server must provide this information) Enable networking at the proper time (e.g. some time after file systems are loaded but before network services like ssh start) Switching distros or versions (e.g. to Server Edition) is not an acceptable solution Switching to a Static IP configuration is not an acceptable solution Question How to start networking on a wired interface before logon in Ubuntu Desktop Edition? What I have tried Per this guide, adding the following entry into /etc/network/interfaces so that NetworkManager won't manage the eth0 interface: auth eth0 iface inet dhcp After reboot eth0 is down. Issuing ifconfig eth0 up brings the interface up but it receives no IP address. Issuing dhclient eth0 instead Does bring up the interface and it Does receive an IP address. Completely removing the NetworkManager package in addition to the settings above. I'm a bit confused with the whole UpStart/SysVinit mangling that's going in Ubuntu currently (I'm more familiar with the CentOS world). However, directly issuing sudo /etc/init.d/networking start Or sudo start networking does not bring up the eth0 interface at all, much less get an IP address. See-Also How to force NetworkManager to make a connection before login? References Ubuntu Desktop Edition Ubuntu Networking Configuration Using Command Line Automatic Network Configuration Via Command-Line Start network connection before login

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  • Ethernet interface number changed, and old one does not exist, but does not leave IP address

    - by Sagar
    I have a virtual machine with Mandriva 2007.0 (yes, old - unfortunately we do not have a choice here). Anyway, the problem: Before reboot: active network interface = eth0. No other interfaces present, and network manager confirms this. Static IP address set to 172.31.2.22. No issues, everything working properly, routing et al. -------Reboot--------- After reboot: active network interface = eth1, with a DHCP address. Network manager shows eth0 as disconnected, and not connectable. When I try to set eth1 up with the static IP address (same one), it says "In Use". I then tried ifconfig eth0 172.31.2.29 just to free it up from the eth0 interface so I could use it with eth1 (since this is connected). Result: ifconfig eth0 172.31.2.29 SIOCSIFADDR: No such device eth0: unknown interface: No such device Nothing else changed. Any ideas what could be happening, or at least how I can get my IP address back?

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  • Juniper router dropping pings to external interface

    - by Alexander Garden
    My organization has a Juniper SSG20-WLAN that routes our traffic to the outside world. We've been having intermittent problems with our internet connection so I wrote up a Python script to ping the internal interface of the router, the external interface, a couple of our internal servers, the ISP router our router talks to, their upstream provider, and Google and Yahoo for good measure. It does that about every minute. What I have found is that when our internet goes out, our Juniper router ceases responding to pings on the external interface. Everything past that is, of course, unreachable. The internal interface and our internal servers continue to echo back without interruption. None of the counters indicate dropped packets of any type. They all look normal. The logs complain about VIP servers being unavailable but otherwise nothing indicative of network issues. My questions are these: Does this exonerate our ISP? Or, contrawise, might a problem with the connection be causing the external interface to go down? Is there somewhere else in the SSG20, beside the system log and counters, that might help me track down info on the problem? UPDATE: Turned out that one of the switches between my monitoring box and the router was a router itself, and occasionally diverting from the gateway to itself. Kudos to those who made suggestions along those lines. Not really sure which answer to mark as accepted, as it was really stuff in the comments that turned out to be right. Thanks for the suggestions.

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  • Second ip address on same interface CentOS 6.3

    - by user16081
    I tried to add a second LAN addresses in CentOS 6.3 on a brand new install and it's not working. I installed a new copy of CentOS 5.7 and tried the same and it worked right away. Now I'm just trying to setup the alias on the same subnet and it's not working. what am i doing wrong, is this not possible on CentOS 6.3? second ip address on the same interface but on a different subnet CentOS 5.7 it works: DEVICE=eth0 BOOTPROTO=static BROADCAST=192.168.0.255 HWADDR=00:0C:29:01:6F:89 IPADDR=192.168.0.167 NETMASK=255.255.255.0 NETWORK=192.168.0.0 ONBOOT=yes DEVICE=eth0:0 BOOTPROTO=static BROADCAST=192.168.0.255 HWADDR=00:0C:29:01:6F:89 IPADDR=192.168.0.166 NETMASK=255.255.255.0 NETWORK=192.168.0.0 ONBOOT=yes On CentOS 6.3: does not work DEVICE=eth0 BOOTPROTO=static BROADCAST=192.168.0.255 HWADDR=00:0C:29:1E:DE:86 IPADDR=192.168.0.242 NETMASK=255.255.255.0 NETWORK=192.168.0.0 GATEWAY=192.168.0.1 ONBOOT=yes DNS1=205.134.232.138 DNS2=4.4.4.4 DEVICE=eth0:0 BOOTPROTO=static BROADCAST=192.168.0.255 HWADDR=00:0C:29:1E:DE:86 IPADDR=192.168.0.240 NETMASK=255.255.255.0 NETWORK=192.168.0.0 ONBOOT=yes # /etc/init.d/network restart Shutting down interface eth0: Device state: 3 (disconnected) [ OK ] Shutting down loopback interface: [ OK ] Bringing up loopback interface: [ OK Bringing up interface eth0: Active connection state: activated Active connection path: /org/freedesktop/NetworkManager/ActiveConnection/3 [ OK ] # ping 192.168.0.240 PING 192.168.0.240 (192.168.0.240) 56(84) bytes of data. From 192.168.0.242 icmp_seq=2 Destination Host Unreachable Appreciate any advice, thanks Update: Perhaps this is relevant? On CentOS 5.7: # dmesg |grep eth eth0: registered as PCnet/PCI II 79C970A eth0: link up eth0: link up On 6.3: # dmesg | grep eth e1000 0000:02:00.0: eth0: (PCI:66MHz:32-bit) 00:0c:29:1e:de:86 e1000 0000:02:00.0: eth0: Intel(R) PRO/1000 Network Connection e1000: eth0 NIC Link is Up 1000 Mbps Full Duplex, Flow Control: None 8021q: adding VLAN 0 to HW filter on device eth0 eth0: no IPv6 routers present

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