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  • R programming function without ()

    - by Mark Kennedy
    So, I Have the following very simple map.r file. I'm trying to have the user type "click" in interactive mode and then have the function . Since it's a function, the user has to type "click()" how can I make it so that they only have to the word (w/o parentheses), and then have that function do something with the img. So the user types: mydist("image.pnm") click //And then the function click does what it's supposed to mydist <- function(mapfile) { img <- read.pnm(mapfile) plot(img) } click <- function() { //Prompt user to click on img }

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  • Portable Socket programming in C/C++ possible?

    - by questions
    I am thinking of creating a multi-platform portable C++ server-client application. Is it even possible while using only standard libraries? If no, what other libraries are there? Are there any improvements in this direction in C++11x? Like for threads, now we have std::threads. To make it more clear.. I want something like boost::thread, which provides multiplatform portable multithreading, for networking. And why C++ doesn't have libraries(standard) for such basic things like networking?

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  • Make FalseClass behave like TrueClass with meta programming

    - by Edvinas Bartkus
    This is theoretical question: is it possible to change FalseClass behavior to act like TrueClass? It is possible to override to_s, xor, &, | behavior but that is not enough. If you like Test Driven Development, follow my colleague's suggestion: puts "false is new true!" if false puts "never happens" if true Asserts won't work, would it? Is it possible to pass the test successfully?

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  • How to insert into data base using multi threading programming [closed]

    - by user1196650
    I am having a method and that method needs to do the following thing: It has to insert records into a database. No insert is done for the same table again. All inserts are into different tables. I need a multi threading logic which inserts the details into db using different threads. I am using oracle db and driver configuration and remaining stuff are perfect. Please help me with an efficient answer. Can anyone could provide me with a skeleton logic of the program.

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  • Qt Programming:Installer not able to create shortcut in start menu in Windows 7

    - by nav
    Hello all, I am creating an installer to deploy some application .and I am getting following problems All applications shortcut get created in start menu under a common name like: *Start MENU-CMKIT-gcompris -open office -Scratch* A pop up should be launched at the end of installation,which has buttons for each application and it will start respective application when user clicks on button.Its not launching now. Its very critical for me,please help me.I am also ready to pay for this but give me solution for these. please mail me on

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  • definition of wait-free (referring to parallel programming)

    - by tecuhtli
    In Maurice Herlihy paper "Wait-free synchronization" he defines wait-free: "A wait-free implementation of a concurrent data object is one that guarantees that any process can complete any operation in a finite number of steps, regardless the execution speeds on the other processes." www.cs.brown.edu/~mph/Herlihy91/p124-herlihy.pdf Let's take one operation op from the universe. (1) Does the definition mean: "Every process completes a certain operation op in the same finite number n of steps."? (2) Or does it mean: "Every process completes a certain operation op in any finite number of steps. So that a process can complete op in k steps another process in j steps, where k != j."? Just by reading the definition i would understand meaning (2). However this makes no sense to me, since a process executing op in k steps and another time in k + m steps meets the definition, but m steps could be a waiting loop. If meaning (2) is right, can anybody explain to me, why this describes wait-free? In contrast to (2), meaning (1) would guarantee that op is executed in the same number of steps k. So there can't be any additional steps m that are necessary e.g. in a waiting loop. Which meaning is right and why? Thanks a lot, sebastian

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  • bulls and cows game -- programming algorithm(python)

    - by IcyFlame
    This is a simulation of the game Cows and Bulls with three digit numbers I am trying to get the number of cows and bulls between two numbers. One of which is generated by the computer and the other is guessed by the user. I have parsed the two numbers I have so that now I have two lists with three elements each and each element is one of the digits in the number. So: 237 will give the list [2,3,7]. And I make sure that the relative indices are maintained.the general pattern is:(hundreds, tens, units). And these two lists are stored in the two lists: machine and person. ALGORITHM 1 So, I wrote the following code, The most intuitive algorithm: cows and bulls are initialized to 0 before the start of this loop. for x in person: if x in machine: if machine.index(x) == person.index(x): bulls += 1 print x,' in correct place' else: print x,' in wrong place' cows += 1 And I started testing this with different type of numbers guessed by the computer. Quite randomly, I decided on 277. And I guessed 447. Here, I got the first clue that this algorithm may not work. I got 1 cow and 0 bulls. Whereas I should have got 1 bull and 1 cow. This is a table of outputs with the first algorithm: Guess Output Expected Output 447 0 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 0 cows 2 bulls, 0 cows 777 0 bulls, 3 cows 2 bulls, 0 cows So obviously this algorithm was not working when there are repeated digits in the number randomly selected by the computer. I tried to understand why these errors are taking place, But I could not. I have tried a lot but I just could not see any mistake in the algorithm(probably because I wrote it!) ALGORITHM 2 On thinking about this for a few days I tried this: cows and bulls are initialized to 0 before the start of this loop. for x in range(3): for y in range(3): if x == y and machine[x] == person[y]: bulls += 1 if not (x == y) and machine[x] == person[y]: cows += 1 I was more hopeful about this one. But when I tested this, this is what I got: Guess Output Expected Output 447 1 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 2 cows 2 bulls, 0 cows 777 2 bulls, 4 cows 2 bulls, 0 cows The mistake I am making is quite clear here, I understood that the numbers were being counted again and again. i.e.: 277 versus 477 When you count for bulls then the 2 bulls come up and thats alright. But when you count for cows: the 7 in 277 at units place is matched with the 7 in 477 in tens place and thus a cow is generated. the 7 in 277 at tens place is matched with the 7 in 477 in units place and thus a cow is generated.' Here the matching is exactly right as I have written the code as per that. But this is not what I want. And I have no idea whatsoever on what to do after this. Furthermore... I would like to stress that both the algorithms work perfectly, if there are no repeated digits in the number selected by the computer. Please help me with this issue. P.S.: I have been thinking about this for over a week, But I could not post a question earlier as my account was blocked(from asking questions) because I asked a foolish question. And did not delete it even though I got 2 downvotes immediately after posting the question.

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  • C++ Programming in Linux Platform

    - by viswanathan
    I am a software engineer and i work in VC++, C++ in WIndows OS. Are there any major differences when it comes to coding in C++ in Linux environment. Or is it just some adjustments that we have to make when we need to code in C++ in Linux.

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  • Representing a number in a byte array (java programming)

    - by Mark Roberts
    I'm trying to represent the port number 9876 (or 0x2694 in hex) in a two byte array: class foo { public static void main (String args[]) { byte[] sendData = new byte[1]; sendData[0] = 0x26; sendData[1] = 0x94; } } But I get a warning about possible loss of precision: foo.java:5: possible loss of precision found : int required: byte sendData[1] = 0x94; ^ 1 error How can I represent the number 9876 in a two byte array without losing precision?

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  • Java Programming Help

    - by user215049
    hi, im a bit confused on this and i dont know how to solve this question that i have been asked, id be grateful if you could assist me on this question, maybe try to tell me what needs to be done, and how. the question is: Write a method called countChars which takes an InputStream as a parameter, reads the stream and returns the number of characters it contains as an int. Any IOExceptions which might occur in the method should be passed back to the method's caller. Note that the method header should show that it is possible that an exception might occur. i attempted this question with the following code: public class countChars { public int countChars(int InputStream) { return InputStream; } } and i get an error message saying : Main.java:26: cannot find symbol symbol : method countChars(java.io.InputStream) location: class Main s1 = "" + countChars(f1); ^ 1 error

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  • File folder sql programming

    - by eski
    I'm trying to figure out the best way to make a file folder system in sql. I'm making a website that will be using similar system as explorer in windows. You open your c: drive and you see there some folders and files, and you open one folder and you see more files and folders there. So what i'm asking, would i use one table for this and just point to the parent id number or what ? I have this in my head.. You make a Primary folder, it gets the u_id=1. Then i make a file in that folder, it gets u_id=2 and p_id=1 so i know its there right? same with the folders. This would all be in one table but i cant help thinking there is some major flaw in this..

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  • programming help

    - by user208639
    class Person holds personal data Its constructor receives 3 parameters, two Strings representing first and last names and an int representing age public Person(String firstName, String lastName, int age) { its method getName has no parameters and returns a String with format "Lastname, Firstname" its method getAge takes no parameters and returns an int representing the current age its method birthday increases age value by 1 and returns the new age value Create the class Person and paste the whole class into the textbox below public class Person { public Person(String first, String last, int age) { getName = "Lastname, Firstname"; System.out.print(last + first); getAge = age + 1; return getAge; System.out.print(getAge); birthday = age + 1; newAge = birthday; return newAge; } } im getting errors such as "cannot find symbol - variable getName" but when i declare a variable it still not working, i also wanted to ask if i am heading in the right direction or is it all totally wrong? im using a program called BlueJ to work on.

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  • help for hindi programming

    - by yogeshbablu
    #include<wchar.h> #include<iostream> using namespace std; int main(int argc,char* argv[]) { fputws(L"?? ?? ?????? ????",stdout); return 0; } ?? ?? ?????? ??? is displayed when i run it on ubuntu can anybody help me out?

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  • Android programming help

    - by Tuffy G
    I want to start making a program for a local charity on the Android platform. Where can go I for resources and tutorials to learn? I'm very new at this, so would like something simple that can be followed by someone with minimal technical knowledge.

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  • Watch IPL League 2010 Online On YouTube

    - by Suganya
    Having said that IPL League match for the year 2010 starts tomorrow, Many of us would be interested in watching the broadcast live online. The first match between Deccan chargers and Kolkata Knight Riders starts tomorrow at 20.00 IST. IPL T20 lasts for 45 days starting from March 12th 2010 till April 25th 2010. The entire league takes place in India. The opening ceremony takes place on 12th continued by the official game between Deccan Chargers and Kolkata Knight Riders Most of us would not be able to watch the match on Television. So this year IPL joins hand with Google to make it available live on NET. How to Watch IPL Match Live Online Google and IPL has joined their hands to make the match available online for all the viewers around the world. To watch the IPL Match live online log on here How to Watch IPL Match Live On Mobile IPL and GCV(Global Cricket Ventures) are tied to July Systems. You can watch IPL matches live on mobile by accessing the link directly using a GPRS enabled mobile or viewers can simply call from their mobile phone to MiX (Mobile Internet Experience) using the Toll Free number 08 123 123 123. Once you call this Toll Free number a link will be sent to your mobile. You can access that link to view the live cricket on your mobile. Watch IPL League Cricket Match Live Online Watch IPL League Cricket Match Live On Mobile Join us on Facebook to read all our stories right inside your Facebook news feed.

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  • MySQL – Introduction to CONCAT and CONCAT_WS functions

    - by Pinal Dave
    MySQL supports two types of concatenation functions. They are CONCAT and CONCAT_WS CONCAT function just concats all the argument values as such SELECT CONCAT('Television','Mobile','Furniture'); The above code returns the following TelevisionMobileFurniture If you want to concatenate them with a comma, either you need to specify the comma at the end of each value, or pass comma as an argument along with the values SELECT CONCAT('Television,','Mobile,','Furniture'); SELECT CONCAT('Television',',','Mobile',',','Furniture'); Both the above return the following Television,Mobile,Furniture However you can omit the extra work by using CONCAT_WS function. It stands for Concatenate with separator. This is very similar to CONCAT function, but accepts separator as the first argument. SELECT CONCAT_WS(',','Television','Mobile','Furniture'); The result is Television,Mobile,Furniture If you want pipeline as a separator, you can use SELECT CONCAT_WS('|','Television','Mobile','Furniture'); The result is Television|Mobile|Furniture So CONCAT_WS is very flexible in concatenating values along with separate. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: MySQL, PostADay, SQL, SQL Authority, SQL Query, SQL Tips and Tricks, T SQL

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  • IASA South East Florida Chapter &ndash; November 2012 Meeting

    - by Rainer Habermann
    After a short introduction by Rainer Habermann and announcements for the chapter and promoting the upcoming IASA IFC Certification Class in January 2013 at Citrix, the audience was exited to welcome Jesus Rodriquez for the main presentation about “Mobilizing the Enterprise”.       Jesus is a co-founder and CEO of both Tellago Studios and Tellago, two fast growing start-ups with a unique vision around software technology. Jesus spends his days working on the technology and strategic vision of both companies. Under his leadership, Tellago and Tellago Studios have been recognized as an innovator in the areas of enterprise software and solutions achieving important awards like the Inc500, American Business Awards’ American and International Business Awards. A software scientist by background, Jesus is an internationally recognized speaker and author with contributions that include hundreds of articles and sessions at industry conferences. Jesus serves as an advisor to several software companies such as Microsoft and Oracle, and is the only person who holds both the Microsoft MVP and Oracle ACE awards. Jesus introduced the architecture of the Enterprise Mobile Backend as a service, integrating enterprise mobile applications with corporate line of business systems and providing robust backend capabilities represent some of the major challenges in today’s enterprise mobility solutions. The mobile consumer space has seen the emergence of backend as a service technologies as one of the main mechanisms for enabling backend capabilities in mobile applications. This session introduced the concept of mobile backend as a service (MBaaS) as the fundamental enabler of the next generation enterprise mobile applications. The session further explored the fundamental components and services of a mBaaS platform that makes it an ideal option for enabling backend capabilities in enterprise mobile applications. Using real world examples. Jesus demonstrated how mBaaS represents an agile and extremely simple model to integrate mobile applications with corporate systems. Thank you very much to Jesus Rodriquez for an outstanding presentation, Peak 10 Data Centers for hosting our meeting, and to TEK Systems for Snacks. Pictures taken by Ted Harwood.   Rainer Habermann President IASA SE Florida Chapter

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  • What are basic programs like, recursion, Fibonacci, small trick programs?

    - by Mike
    This question may seem daft (I'm a new to 'programming' and should probably stop if this is the type of question I'm required to ask)... What are: "basic programs like, recursion, fibonacci, factorial, string manipulation, small trick programs"? I've recently read Coding Horror - the non programmer and followed the links to Kegel and How to get hired. Then I delved through some similar questions here (hence the block quote) and I realised that as a fully fledged non-programmer I probably wouldn't know if I knew recursion (or any of the others) because I wouldn't know what it looked like, or why it was used, and what the results would look like after it was used. I suppose I'm trying to get a picture of "the basics". What the principles are and why we learn them - where they'll be used and what result/s your looking for. If they'll be used as an interview question during my first interview sometime in 2020 I would like to look less ignorant than those 199 out of 200 who just don't know the how, or the why, of programming. As always...I'll get my coat. Thanks Mike

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  • What does it mean that "Lisp can be written in itself?"

    - by Mason Wheeler
    Paul Graham wrote that "The unusual thing about Lisp-- in fact, the defining quality of Lisp-- is that it can be written in itself." But that doesn't seem the least bit unusual or definitive to me. ISTM that a programming language is defined by two things: Its compiler or interpreter, which defines the syntax and the semantics for the language by fiat, and its standard library, which defines to a large degree the idioms and techniques that skilled users will use when writing code in the language. With a few specific exceptions, (the non-C# members of the .NET family, for example,) most languages' standard libraries are written in that language for two very good reasons: because it will share the same set of syntactical definitions, function calling conventions, and the general "look and feel" of the language, and because the people who are likely to write a standard library for a programming language are its users, and particularly its designer(s). So there's nothing unique there; that's pretty standard. And again, there's nothing unique or unusual about a language's compiler being written in itself. C compilers are written in C. Pascal compilers are written in Pascal. Mono's C# compiler is written in C#. Heck, even some scripting languages have implementations "written in itself". So what does it mean that Lisp is unusual in being written in itself?

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  • NSPredicate as a constraint solver?

    - by Felixyz
    I'm working on a project which includes some slightly more complex dynamic layout of interface elements than what I'm used to. I always feel stupid writing complex code that checks if so-and-so is close to such-and-such and in that case move it x% in some direction, etc. That's just not how programming should be done. Programming should be as declarative as possible! Precisely because what I'm going to do is fairly simple, I thought it would be a good opportunity to try something new, and I thought of using NSPredicate as a simple constraints solver. I've only used NSPredicate for very simple tasks so far, but I know that it capable of much more. Are there any ideas, experiences, examples, warnings, insights that could be useful here? I'll give a very simple example so there will be something concrete to answer. How could I use NSPredicate to solve the following constraints: viewB.xmid = (viewB.leftEdge + viewB.width) / 2 viewB.xmid = max(300, viewA.rightEdge + 20 + viewB.width/2) ("viewB should be horizontally centered on coordinate 300, unless its left edge gets within 20 pixels of viewB's right edge, in which case viewA's left edge should stay fixed at 20 pixels to the right of viewB's right edge and viewA's horizontal center get pushed to the right.") viewA.rightEdge and viewB.width can vary, and those are the 'input variables'. EDIT: Any solution would probably have to use the NSExpression method -(id)expressionValueWithObject:(id)object context:(NSMutableDictionary *)context. This answer is relevant.

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