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  • testing Clojure in Maven

    - by Ralph
    I am new at Maven and even newer at Clojure. As an exercise to learn the language, I am writing a spider solitaire player program. I also plan on writing a similar program in Scala to compare the implementations (see my post http://stackoverflow.com/questions/2571267/modern-java-alternatives-closed). I have configured a Maven directory structure containing the usual src/main/clojure and src/test/clojure directories. My pom.xml file includes the clojure-maven-plugin. When I run "mvn test", it displays "No tests to run", despite my having test code in the src/test/clojure directory. As I misnaming something? Here is my pom.xml file: <?xml version="1.0" encoding="UTF-8"?> <project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd"> <modelVersion>4.0.0</modelVersion> <groupId>SpiderPlayer</groupId> <artifactId>SpiderPlayer</artifactId> <version>1.0.0-SNAPSHOT</version> <inceptionYear>2010</inceptionYear> <packaging>jar</packaging> <properties> <maven.build.timestamp.format>yyMMdd.HHmm</maven.build.timestamp.format> <main.dir>org/dogdaze/spider_player</main.dir> <main.package>org.dogdaze.spider_player</main.package> <main.class>${main.package}.Main</main.class> </properties> <build> <sourceDirectory>src/main/clojure</sourceDirectory> <testSourceDirectory>src/main/clojure</testSourceDirectory> <plugins> <plugin> <groupId>com.theoryinpractise</groupId> <artifactId>clojure-maven-plugin</artifactId> <version>1.3.1</version> </plugin> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-antrun-plugin</artifactId> <version>1.3</version> <executions> <execution> <goals> <goal>run</goal> </goals> <phase>generate-sources</phase> <configuration> <tasks> <echo file="${project.build.sourceDirectory}/${main.dir}/Version.clj" message="(ns ${main.package})${line.separator}"/> <echo file="${project.build.sourceDirectory}/${main.dir}/Version.clj" append="true" message="(def version &quot;${maven.build.timestamp}&quot;)${line.separator}"/> </tasks> </configuration> </execution> </executions> </plugin> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-assembly-plugin</artifactId> <version>2.1</version> <executions> <execution> <goals> <goal>single</goal> </goals> <phase>package</phase> <configuration> <descriptorRefs> <descriptorRef>jar-with-dependencies</descriptorRef> </descriptorRefs> <archive> <manifest> <mainClass>${main.class}</mainClass> </manifest> </archive> </configuration> </execution> </executions> </plugin> <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-surefire-plugin</artifactId> <configuration> <redirectTestOutputToFile>true</redirectTestOutputToFile> <skipTests>false</skipTests> <skip>false</skip> </configuration> <executions> <execution> <id>surefire-it</id> <phase>integration-test</phase> <goals> <goal>test</goal> </goals> <configuration> <skip>false</skip> </configuration> </execution> </executions> </plugin> </plugins> </build> <dependencies> <dependency> <groupId>commons-cli</groupId> <artifactId>commons-cli</artifactId> <version>1.2</version> <scope>compile</scope> </dependency> </dependencies> </project> Here is my Clojure source file (src/main/clojure/org/dogdaze/spider_player/Deck.clj): ; Copyright 2010 Dogdaze (ns org.dogdaze.spider_player.Deck (:use [clojure.contrib.seq-utils :only (shuffle)])) (def suits [:clubs :diamonds :hearts :spades]) (def ranks [:ace :two :three :four :five :six :seven :eight :nine :ten :jack :queen :king]) (defn suit-seq "Return 4 suits: if number-of-suits == 1: :clubs :clubs :clubs :clubs if number-of-suits == 2: :clubs :diamonds :clubs :diamonds if number-of-suits == 4: :clubs :diamonds :hearts :spades." [number-of-suits] (take 4 (cycle (take number-of-suits suits)))) (defstruct card :rank :suit) (defn unshuffled-deck "Create an unshuffled deck containing all cards from the number of suits specified." [number-of-suits] (for [rank ranks suit (suit-seq number-of-suits)] (struct card rank suit))) (defn deck "Create a shuffled deck containing all cards from the number of suits specified." [number-of-suits] (shuffle (unshuffled-deck number-of-suits))) Here is my test case (src/test/clojure/org/dogdaze/spider_player/TestDeck.clj): ; Copyright 2010 Dogdaze (ns org.dogdaze.spider_player (:use clojure.set clojure.test org.dogdaze.spider_player.Deck)) (deftest test-suit-seq (is (= (suit-seq 1) [:clubs :clubs :clubs :clubs])) (is (= (suit-seq 2) [:clubs :diamonds :clubs :diamonds])) (is (= (suit-seq 4) [:clubs :diamonds :hearts :spades]))) (def one-suit-deck [{:rank :ace, :suit :clubs} {:rank :ace, :suit :clubs} {:rank :ace, :suit :clubs} {:rank :ace, :suit :clubs} {:rank :two, :suit :clubs} {:rank :two, :suit :clubs} {:rank :two, :suit :clubs} {:rank :two, :suit :clubs} {:rank :three, :suit :clubs} {:rank :three, :suit :clubs} {:rank :three, :suit :clubs} {:rank :three, :suit :clubs} {:rank :four, :suit :clubs} {:rank :four, :suit :clubs} {:rank :four, :suit :clubs} {:rank :four, :suit :clubs} {:rank :five, :suit :clubs} {:rank :five, :suit :clubs} {:rank :five, :suit :clubs} {:rank :five, :suit :clubs} {:rank :six, :suit :clubs} {:rank :six, :suit :clubs} {:rank :six, :suit :clubs} {:rank :six, :suit :clubs} {:rank :seven, :suit :clubs} {:rank :seven, :suit :clubs} {:rank :seven, :suit :clubs} {:rank :seven, :suit :clubs} {:rank :eight, :suit :clubs} {:rank :eight, :suit :clubs} {:rank :eight, :suit :clubs} {:rank :eight, :suit :clubs} {:rank :nine, :suit :clubs} {:rank :nine, :suit :clubs} {:rank :nine, :suit :clubs} {:rank :nine, :suit :clubs} {:rank :ten, :suit :clubs} {:rank :ten, :suit :clubs} {:rank :ten, :suit :clubs} {:rank :ten, :suit :clubs} {:rank :jack, :suit :clubs} {:rank :jack, :suit :clubs} {:rank :jack, :suit :clubs} {:rank :jack, :suit :clubs} {:rank :queen, :suit :clubs} {:rank :queen, :suit :clubs} {:rank :queen, :suit :clubs} {:rank :queen, :suit :clubs} {:rank :king, :suit :clubs} {:rank :king, :suit :clubs} {:rank :king, :suit :clubs} {:rank :king, :suit :clubs}]) (def two-suits-deck [{:rank :ace, :suit :clubs} {:rank :ace, :suit :diamonds} {:rank :ace, :suit :clubs} {:rank :ace, :suit :diamonds} {:rank :two, :suit :clubs} {:rank :two, :suit :diamonds} {:rank :two, :suit :clubs} {:rank :two, :suit :diamonds} {:rank :three, :suit :clubs} {:rank :three, :suit :diamonds} {:rank :three, :suit :clubs} {:rank :three, :suit :diamonds} {:rank :four, :suit :clubs} {:rank :four, :suit :diamonds} {:rank :four, :suit :clubs} {:rank :four, :suit :diamonds} {:rank :five, :suit :clubs} {:rank :five, :suit :diamonds} {:rank :five, :suit :clubs} {:rank :five, :suit :diamonds} {:rank :six, :suit :clubs} {:rank :six, :suit :diamonds} {:rank :six, :suit :clubs} {:rank :six, :suit :diamonds} {:rank :seven, :suit :clubs} {:rank :seven, :suit :diamonds} {:rank :seven, :suit :clubs} {:rank :seven, :suit :diamonds} {:rank :eight, :suit :clubs} {:rank :eight, :suit :diamonds} {:rank :eight, :suit :clubs} {:rank :eight, :suit :diamonds} {:rank :nine, :suit :clubs} {:rank :nine, :suit :diamonds} {:rank :nine, :suit :clubs} {:rank :nine, :suit :diamonds} {:rank :ten, :suit :clubs} {:rank :ten, :suit :diamonds} {:rank :ten, :suit :clubs} {:rank :ten, :suit :diamonds} {:rank :jack, :suit :clubs} {:rank :jack, :suit :diamonds} {:rank :jack, :suit :clubs} {:rank :jack, :suit :diamonds} {:rank :queen, :suit :clubs} {:rank :queen, :suit :diamonds} {:rank :queen, :suit :clubs} {:rank :queen, :suit :diamonds} {:rank :king, :suit :clubs} {:rank :king, :suit :diamonds} {:rank :king, :suit :clubs} {:rank :king, :suit :diamonds}]) (def four-suits-deck [{:rank :ace, :suit :clubs} {:rank :ace, :suit :diamonds} {:rank :ace, :suit :hearts} {:rank :ace, :suit :spades} {:rank :two, :suit :clubs} {:rank :two, :suit :diamonds} {:rank :two, :suit :hearts} {:rank :two, :suit :spades} {:rank :three, :suit :clubs} {:rank :three, :suit :diamonds} {:rank :three, :suit :hearts} {:rank :three, :suit :spades} {:rank :four, :suit :clubs} {:rank :four, :suit :diamonds} {:rank :four, :suit :hearts} {:rank :four, :suit :spades} {:rank :five, :suit :clubs} {:rank :five, :suit :diamonds} {:rank :five, :suit :hearts} {:rank :five, :suit :spades} {:rank :six, :suit :clubs} {:rank :six, :suit :diamonds} {:rank :six, :suit :hearts} {:rank :six, :suit :spades} {:rank :seven, :suit :clubs} {:rank :seven, :suit :diamonds} {:rank :seven, :suit :hearts} {:rank :seven, :suit :spades} {:rank :eight, :suit :clubs} {:rank :eight, :suit :diamonds} {:rank :eight, :suit :hearts} {:rank :eight, :suit :spades} {:rank :nine, :suit :clubs} {:rank :nine, :suit :diamonds} {:rank :nine, :suit :hearts} {:rank :nine, :suit :spades} {:rank :ten, :suit :clubs} {:rank :ten, :suit :diamonds} {:rank :ten, :suit :hearts} {:rank :ten, :suit :spades} {:rank :jack, :suit :clubs} {:rank :jack, :suit :diamonds} {:rank :jack, :suit :hearts} {:rank :jack, :suit :spades} {:rank :queen, :suit :clubs} {:rank :queen, :suit :diamonds} {:rank :queen, :suit :hearts} {:rank :queen, :suit :spades} {:rank :king, :suit :clubs} {:rank :king, :suit :diamonds} {:rank :king, :suit :hearts} {:rank :king, :suit :spades}]) (deftest test-unshuffled-deck (is (= (unshuffled-deck 1) one-suit-deck)) (is (= (unshuffled-deck 2) two-suits-deck)) (is (= (unshuffled-deck 4) four-suits-deck))) (deftest test-shuffled-deck (is (= (set (deck 1)) (set one-suit-deck))) (is (= (set (deck 2)) (set two-suits-deck))) (is (= (set (deck 4)) (set four-suits-deck)))) (run-tests) Any idea why the test is not running? BTW, feel free to suggest improvements to the Clojure code. Thanks, Ralph

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  • Number of ways to place kings on chess board

    - by Rakesh
    You have an N x N chessboard and you wish to place N kings on it. Each row and column should contain exactly one king, and no two kings should attack each other (two kings attack each other if they are present in squares which share a corner). The kings in the first K rows of the board have already been placed. You are given the positions of these kings as an array pos[ ]. pos[i] is the column in which the king in the ith row has already been placed. All indices are 0-indexed. In how many ways can the remaining kings be placed? Input: The first line contains the number of test cases T. T test cases follow. Each test case contains N and K on the first line, followed by a line having K integers, denoting the array pos[ ] as described above. Output: Output the number of ways to place kings in the remaining rows satisfying the above conditions. Output all numbers modulo 1000000007. Constraints: 1 <= T <= 20 1 <= N <= 16 0 <= K <= N 0 <= pos_i < N The kings specified in the input will be in different columns and not attack each other. Sample Input: 5 4 1 2 3 0 5 2 1 3 4 4 1 3 0 2 6 1 2 Sample Output: 1 0 2 1 18 Explanation: For the first example, there is a king already placed at row 0 and column 2. The king in the second row must belong to column 0. The king in the third row must belong to column 3, and the last king must beong to column 1. Thus there is only 1 valid placement. For the second example, there is no valid placement. How should i approach this problem

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  • CodeGolf: Brothers

    - by John McClane
    Hi guys, I just finished participating in the 2009 ACM ICPC Programming Conest in the Latinamerican Finals. These questions were for Brazil, Bolivia, Chile, etc. My team and I could only finish two questions out of the eleven (not bad I think for the first try). Here's one we could finish. I'm curious to seeing any variations to the code. The question in full: ps: These questions can also be found on the official ICPC website available to everyone. In the land of ACM ruled a greeat king who became obsessed with order. The kingdom had a rectangular form, and the king divided the territory into a grid of small rectangular counties. Before dying the king distributed the counties among his sons. The king was unaware of the rivalries between his sons: The first heir hated the second but not the rest, the second hated the third but not the rest, and so on...Finally, the last heir hated the first heir, but not the other heirs. As soon as the king died, the strange rivaly among the King's sons sparked off a generalized war in the kingdom. Attacks only took place between pairs of adjacent counties (adjacent counties are those that share one vertical or horizontal border). A county X attacked an adjacent county Y whenever X hated Y. The attacked county was always conquered. All attacks where carried out simultanously and a set of simultanous attacks was called a battle. After a certain number of battles, the surviving sons made a truce and never battled again. For example if the king had three sons, named 0, 1 and 2, the figure below shows what happens in the first battle for a given initial land distribution: INPUT The input contains several test cases. The first line of a test case contains four integers, N, R, C and K. N - The number of heirs (2 <= N <= 100) R and C - The dimensions of the land. (2 <= R,C <= 100) K - Number of battles that are going to take place. (1 <= K <= 100) Heirs are identified by sequential integers starting from zero. Each of the next R lines contains C integers HeirIdentificationNumber (saying what heir owns this land) separated by single spaces. This is to layout the initial land. The last test case is a line separated by four zeroes separated by single spaces. (To exit the program so to speak) Output For each test case your program must print R lines with C integers each, separated by single spaces in the same format as the input, representing the land distribution after all battles. Sample Input: Sample Output: 3 4 4 3 2 2 2 0 0 1 2 0 2 1 0 1 1 0 2 0 2 2 2 0 0 1 2 0 0 2 0 0 0 1 2 2 Another example: Sample Input: Sample Output: 4 2 3 4 1 0 3 1 0 3 2 1 2 2 1 2

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  • Publish a software with copyright and license

    - by King Chan
    I just read some artical about publishing software and I am personally developing some random metero application at the moment. The artical were suggesting the software should have a publisher website. But what I have to put down in the publisher website to keep my copyright? Is it simply really just "Designed/Developed @ 2012 By King Chan" at the bottom of the site and software and is enough? Or do I have to even write a long paragraph of license/agreement said the user who download/use the software cannot copy the icon/functionality etc? (The Apple and Samsung things get me worry about CopyRight now....)

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  • Best tutorial ever! Is there one just like it for XHTML and CSS...?

    - by Joshua C
    I have been learning Ruby on Rails using www.railstutorial.org, and I LOVE it! My only problem? Well, I can build the applications just fine, but my knowledge of designing the skin (CSS) of the application is limited. Is there a really good XHTML and CSS which is very similar to the Ruby on Rails Tutorial by Michael Hartl? If not, perhaps you can point me towards some of the best? Thanks, Joshua Collins P.S. Only if Michael would create a CSS and XHTML tutorial himself... sigh

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  • In MMO game, how to handle user characters, who are offline?

    - by Deele
    In my medieval MMO game, players have their own character, that represents themselves inside game. Like a King. Players could have cities and armies, but King acts as main driving force. Then it comes to player, going offline/vacation/disconnect. How to deal with "offline King", to keep some sort of reality in game, without ruining everything for player. I have never liked unrealistic stuff in games, like appearing/dissapearing from thin air, like in WoW or other MMO RPG's, when it comes to connect/disconnect, like in Matrix movie, when you are disconnected, your "avatar" inside the system just vaninshes. Ok, if player char stays where it was left, other players who are online could kick his ass like offline player char was frozen? I see only one solution - give player char, while offline, some sort of AI, that controls char. Is there any other solutions? May be, some sort of legend/story, could make users only as inner-voice, leaving King just passively controlled by user, or other stuff... Please, help! I hope you understand my question.

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  • C# Alternating threads

    - by Mutoh
    Imagine a situation in which there are one king and n number of minions submissed to him. When the king says "One!", one of the minions says "Two!", but only one of them. That is, only the fastest minion speaks while the others must wait for another call of the king. This is my try: using System; using System.Threading; class Program { static bool leaderGO = false; void Leader() { do { lock(this) { //Console.WriteLine("? {0}", leaderGO); if (leaderGO) Monitor.Wait(this); Console.WriteLine("> One!"); Thread.Sleep(200); leaderGO = true; Monitor.Pulse(this); } } while(true); } void Follower (char chant) { do { lock(this) { //Console.WriteLine("! {0}", leaderGO); if (!leaderGO) Monitor.Wait(this); Console.WriteLine("{0} Two!", chant); leaderGO = false; Monitor.Pulse(this); } } while(true); } static void Main() { Console.WriteLine("Go!\n"); Program m = new Program(); Thread king = new Thread(() => m.Leader()); Thread minion1 = new Thread(() => m.Follower('#')); Thread minion2 = new Thread(() => m.Follower('$')); king.Start(); minion1.Start(); minion2.Start(); Console.ReadKey(); king.Abort(); minion1.Abort(); minion2.Abort(); } } The expected output would be this (# and $ representing the two different minions): > One! # Two! > One! $ Two! > One! $ Two! ... The order in which they'd appear doesn't matter, it'd be random. The problem, however, is that this code, when compiled, produces this instead: > One! # Two! $ Two! > One! # Two! > One! $ Two! # Two! ... That is, more than one minion speaks at the same time. This would cause quite the tumult with even more minions, and a king shoudln't allow a meddling of this kind. What would be a possible solution?

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  • Oracle VM Deep Dives

    - by rickramsey
    "With IT staff now tasked to deliver on-demand services, datacenter virtualization requirements have gone beyond simple consolidation and cost reduction. Simply provisioning and delivering an operating environment falls short. IT organizations must rapidly deliver services, such as infrastructure-as-a-service (IaaS), platform-as-a-service (PaaS), and software-as-a-service (SaaS). Virtualization solutions need to be application-driven and enable:" "Easier deployment and management of business critical applications" "Rapid and automated provisioning of the entire application stack inside the virtual machine" "Integrated management of the complete stack including the VM and the applications running inside the VM." Application Driven Virtualization, an Oracle white paper That was published in August of 2011. The new release of Oracle VM Server delivers significant virtual networking performance improvements, among other things. If you're not sure how virtual networks work or how to use them, these two articles by Greg King and friends might help. Looking Under the Hood at Virtual Networking by Greg King Oracle VM Server for x86 lets you create logical networks out of physical Ethernet ports, bonded ports, VLAN segments, virtual MAC addresses (VNICs), and network channels. You can then assign channels (or "roles") to each logical network so that it handles the type of traffic you want it to. Greg King explains how you go about doing this, and how Oracle VM Server for x86 implements the network infrastructure you configured. He also describes how the VM interacts with paravirtualized guest operating systems, hardware virtualized operating systems, and VLANs. Finally, he provides an example that shows you how it all looks from the VM Manager view, the logical view, and the command line view of Oracle VM Server for x86. Fundamental Concepts of VLAN Networks by Greg King and Don Smerker Oracle VM Server for x86 supports a wide range of options in network design, varying in complexity from a single network to configurations that include network bonds, VLANS, bridges, and multiple networks connecting the Oracle VM servers and guests. You can create separate networks to isolate traffic, or you can configure a single network for multiple roles. Network design depends on many factors, including the number and type of network interfaces, reliability and performance goals, the number of Oracle VM servers and guests, and the anticipated workload. The Oracle VM Manager GUI presents four different ways to create an Oracle VM network: Bonds and ports VLANs Both bond/ports and VLANS A local network This article focuses the second option, designing a complex Oracle VM network infrastructure using only VLANs, and it steps through the concepts needed to create a robust network infrastructure for your Oracle VM servers and guests. More Resources Virtual Networking for Dummies Download Oracle VM Server for x86 Find technical resources for Oracle VM Server for x86 -Rick Follow me on: Blog | Facebook | Twitter | Personal Twitter | YouTube | The Great Peruvian Novel

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  • Issue with user having a gmail account and Google Apps account using same email/username

    - by Joshua
    Greetings! We have a user in our organization that had been using her email address at our domain at her username for gmail.com We recently moved our folks on to Google Apps, and have just moved our email server over to Google (IMAP/SMTP). I'm having all kinds of trouble only with this user's account with her sending and receiving email via the new Google mail server and wondering if it's because of her existing Gmail account. So her email address with us is [email protected], which is her login/user id with us on our Google Apps site. She still has her gmail identity tied to that same [email protected]. She's ok with deleting her old Gmail account...if I do so however will it goof things up for her going forward with us on the Google Apps site? Will she not be able to receive email? Thanks! Joshua

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  • Creating Custom validation rule and register it

    - by FormsEleven
    What is Validation Rule? A validation rule is a piece of code that performs some check ensuring that data meets given constraints.In an enterprise application development environment, often it might require developers to have validation be performed based on some logic at several places across projects. Instead of redundant validation creation, a custom validation rule provides a library with a validation rules that can be registered and used across applications.A custom Validation is encapsulated in a reusable component so that you do not have to write it every time when you need to do input validation. Here is how we can easily implement a custom validation that checks for name of an employee to be "KING" For creating a custom Validation , 1.         Create Generic Application Workspace "CustomValidator" with the project "Model" 2.         Create an BC4J based on emp table. 3.         Create a custom validation rule.In EmpNamerule class, update the validateValue(..) method as follows:  public boolean validateValue(Object value) { EntityImpl emp = (EntityImpl)value; if(emp.getAttribute("Ename").toString().equals("KING")){ return false; } return true; } Create ADF Library: Next step would be to create ADF library. Create ADF library with name lets say testADFLibrary1.jarRegister ADF Library Next step is to register the ADF library , so that its available across the applications. Invoke the menu "Tools -> Preferences"Select the option "Business Components -> Registered Rules" from left paneClick on button "Pick Library". The dialog "Select Library" comes up with  the user library addedAdd new library' that points to the above jarCheck the checkbox "Register" and set the name for the rule Sample UsageHere is how we can easily implement a validation rule that restrict the name of the employee not to be "KING".Create new Application with BC4J based on EMP table.Create new validation under Business rule tab for Ename & select the above custom validation rule.Run the AppModule tester.

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  • google docs + web app

    - by King
    Hi Guys I am trying to create a web app to share docs with all editor features (just like google docs). My main requirements for this app are as follows: 1. Should have all editor features (can be done using open office api, google docs api, Microsoft office web apps api) 2. Should be shared between multiple users and can be edited by multiple users and other sync features (can be done using google docs api, Microsoft office web apps) 3. Can save the document created and edited on my own/ custom server addr. (Which api can support this??? I know open office can support this) Guys can you please suggest me one api which can be used to do all the above. Also please suggest if I am underestimating any API above regarding any functionality that i thing is not supported. Thanks King

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  • TXT File or Database?

    - by Ruth Rettigo
    Hey folks! What should I use in this case (Apache + PHP)? Database or just a TXT file? My priority #1 is speed. Operations Adding new items Reading items Max. 1 000 records Thank you. Database (MySQL) +----------+-----+ | Name | Age | +----------+-----+ | Joshua | 32 | | Thomas | 21 | | James | 34 | | Daniel | 12 | +----------+-----+ TXT file Joshua 32 Thomas 21 James 34 Daniel 12

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  • How do I convert my matrix from OpenGL to Marmalade?

    - by King Snail
    I am using a third party rendering API, Marmalade, on top of OpenGL code and I cannot get my matrices correct. One of the API's authors states this: We're right handed by default, and we treat y as up by convention. Since IwGx's coordinate system has (0,0) as the top left, you typically need a 180 degree rotation around Z in your view matrix. I think the viewer does this by default. In my OpenGL app I have access to the view and projection matrices separately. How can I convert them to fit the criteria used by my third party rendering API? I don't understand what they mean to rotate 180 degrees around Z, is that in the view matrix itself or something in the camera before making the view matrix. Any code would be helpful, thanks.

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  • Node.js MMO - process and/or map division

    - by Gipsy King
    I am in the phase of designing a mmo browser based game (certainly not massive, but all connected players are in the same universe), and I am struggling with finding a good solution to the problem of distributing players across processes. I'm using node.js with socket.io. I have read this helpful article, but I would like some advice since I am also concerned with different processes. Solution 1: Tie a process to a map location (like a map-cell), connect players to the process corresponding to their location. When a player performs an action, transmit it to all other players in this process. When a player moves away, he will eventually have to connect to another process (automatically). Pros: Easier to implement Cons: Must divide map into zones Player reconnection when moving into a different zone is probably annoying If one zone/process is always busy (has players in it), it doesn't really load-balance, unless I split the zone which may not be always viable There shouldn't be any visible borders Solution 1b: Same as 1, but connect processes of bordering cells, so that players on the other side of the border are visible and such. Maybe even let them interact. Solution 2: Spawn processes on demand, unrelated to a location. Have one special process to keep track of all connected player handles, their location, and the process they're connected to. Then when a player performs an action, the process finds all other nearby players (from the special player-process-location tracking node), and instructs their matching processes to relay the action. Pros: Easy load balancing: spawn more processes Avoids player reconnecting / borders between zones Cons: Harder to implement and test Additional steps of finding players, and relaying event/action to another process If the player-location-process tracking process fails, all other fail too I would like to hear if I'm missing something, or completely off track.

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  • Databinding to an Entity Framework in WPF

    - by King Chan
    Is it good to use databinding to Entity Framework's Entity in WPF? I created a singleton entity framework context: To have only one connection and it won't open and close all the time. So I can pass the Entity around to any class, and can modify the Entity and make changes to the database. All ViewModels getting the entity out from the same Context and databinding to the View saves me time from mapping new object, but now I imagine there is problem in not using the newest Context: A ViewModel databinding to a Entity, then someone else updated the data. The ViewModel will still display the old data, because the Context is never being dispose to refresh. I always create new Context and then dispose of it. If I want to pass the Entity around, then there will be conflicts between Context and Entity. What is the suggested way of doing this ?

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  • Should each app have its own database, or should small apps be merged into one?

    - by King
    We have a bunch of small to medium sized apps, each of which has its own database (MSSQL Server). There was a suggestion that we consoldate the 'related' databases into a smaller set amount of larger databases. They don't particularly share a lot of data, they would just be under a similar business group. For example, using a 'Finance' DB to hold the tables and procedures for finance apps. Would it be appropriate to use a different schema for each app? E.g. App1.SomeTable App1.SomeOtherTable AppTwo.SomeTable What are the pros and cons of this approach? What should I watch out for? Thanks

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  • FFmpeg not recording audio during screen capture

    - by King
    I'm using the script below to run FFmpeg on Ubuntu 10.10. I followed these instructions to install FFmpeg & x264. While ffmpeg does capture the screen it does not capture the mic audio. I've checked that the mic works via "System Preferences". Anyone have any ideas on what the problem(s) could be and suggestions on how to resolve this issue? Thanks. ffmpeg -f alsa -ac 2 -i hw:0,0 -f x11grab -r 30 -s $(xwininfo -root | grep 'geometry' | awk '{print $2;}') -i :0.0 -acodec pcm_s16le -vcodec libx264 -vpre lossless_ultrafast -threads 0 -y screen-capture.mkv

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  • Programatically clicking a HTML button by vb.net [closed]

    - by Chauhdry King
    I have to click a HTML button programatically which is on the 3rd page of the website. The button is without id. It has just name type and value. The HTML code of the button is given below <FORM NAME='form1' METHOD='post' action='/dflogin.php'> <INPUT TYPE='hidden' NAME='txtId' value='E712050-15'><INPUT TYPE='hidden' NAME='txtassId' value='1'><INPUT TYPE='hidden' NAME='txtPsw' value='HH29'><INPUT TYPE='hidden' NAME='txtLog' value='0'><h6 align='right'><INPUT TYPE='SUBMIT' NAME='btnSub' value='Next' style='background-color:#009900; color:#fff;'></h6></FORM> I am using the following code to click it Dim i As Integer Dim allButtons As HtmlElementCollection allButtons = WebBrowser1.Document.GetElementsByTagName("input") i = 0 For Each webpageelement As HtmlElement In allButtons i += 1 If i = 5 Then webpageelement.InvokeMember("click") End If Next But I am not able to click it. I am using the vb.net 2008 platform. Can anyone tell me the solution to click it?

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  • View matrix question (rotate by 180 degrees)

    - by King Snail
    I am using a third party rendering API on top of OpenGL code and I cannot get my matrices correct. The API states this: We're right handed by default, and we treat y as up by convention. Since IwGx's coordinate system has (0,0) as the top left, you typically need a 180 degree rotation around Z in your view matrix. I think the viewer does this by default. In my OpenGL app I have access to the view and projection matrices separately. How can I convert them to fit the criteria used by my third party rendering API? I don't understand what they mean to rotate 180 degrees around Z, is that in the view matrix itself or something in the camera before making the view matrix. Any code would be helpful, thanks.

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  • Need suggestion for Mutiple Windows application design

    - by King Chan
    This was previously posted in StackOverflow, I just moved to here... I am using VS2008, MVVM, WPF, Prism to make a mutiple window CRM Application. I am using MidWinow in my MainWindow, I want Any ViewModel would able to make request to MainWindow to create/add/close MidChildWindow, ChildWindow(from WPF Toolkit), Window (the Window type). ViewModel can get the DialogResult from the ChildWindow its excutes. MainWindow have control on all opened window types. Here is my current approach: I made Dictionary of each of the windows type and stores them into MainWindow class. For 1, i.e in a CustomerInformationView, its CustomerInformationViewModel can execute EditCommand and use EventAggregator to tell MainWindow to open a new ChildWindow. CustomerInformationViewModel: CustomerEditView ceView = new CustomerEditView (); CustomerEditViewModel ceViewModel = CustomerEditViewModel (); ceView.DataContext = ceViewModel; ChildWindow cWindow = new ChildWindow(); cWindow.Content = ceView; MainWindow.EvntAggregator.GetEvent<NewWindowEvent>().Publish(new WindowEventArgs(ceViewModel.ViewModeGUID, cWindow )); cWindow.Show(); Notice that all my ViewModel will generates a Guid for help identifies the ChildWindow from MainWindow's dictionary. Since I will only be using 1 View 1 ViewModel for every Window. For 2. In CustomerInformationViewModel I can get DialogResult by OnClosing event from ChildWindow, in CustomerEditViewModel can use Guid to tell MainWindow to close the ChildWindow. Here is little question and problems: Is it good idea to use Guid here? Or should I use HashKey from ChildWindow? My MainWindows contains windows reference collections. So whenever window close, it will get notifies to remove from the collection by OnClosing event. But all the Windows itself doesn't know about its associated Guid, so when I remove it, I have to search for every KeyValuePair to compares... I still kind of feel wrong associate ViewModel's Guid for ChildWindow, it would make more sense if ChildWindow has it own ID then ViewModel associate with it... But most important, is there any better approach on this design? How can I improve this better?

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  • How to detect which edges of a rectange touch when they collide in iOS

    - by Mike King
    I'm creating a basic "game" in iOS 4.1. The premise is simple, there is a green rectangle ("disk") that moves/bounces around the screen, and red rectangle ("bump") that is stationary. The user can move the red "bump" by touching another coordinate on the screen, but that's irrelevant to this question. Each rectangle is a UIImageView (I will replace them with some kind of image/icon once I get the mechanics down). I've gotten as far as detecting when the rectangles collide, and I'm able to reverse the direction of the green "disk" on the Y axis if they do. This works well when the green "disk" approaches the red "bump" from top or bottom, it bounces off in the other direction. But when it approaches from the side, the bounce is incorrect; I need to reverse the X direction instead. Here's the timer I setup: - (void)viewDidLoad { xSpeed = 3; ySpeed = -3; gameTimer = [NSTimer scheduledTimerWithTimeInterval:0.05 target:self selector:@selector(mainGameLoop:) userInfo:nil repeats:YES]; [super viewDidLoad]; } Here's the main game loop: - (void) mainGameLoop:(NSTimer *)theTimer { disk.center = CGPointMake(disk.center.x + xSpeed, disk.center.y + ySpeed); // make sure the disk does not travel off the edges of the screen // magic number values based on size of disk's frame // startAnimating causes the image to "pulse" if (disk.center.x < 55 || disk.center.x > 265) { xSpeed = xSpeed * -1; [disk startAnimating]; } if (disk.center.y < 55 || disk.center.y > 360) { ySpeed = ySpeed * -1; [disk startAnimating]; } // check to see if the disk collides with the bump if (CGRectIntersectsRect(disk.frame, bump.frame)) { NSLog(@"Collision detected..."); if (! [disk isAnimating]) { ySpeed = ySpeed * -1; [disk startAnimating]; } } } So my question is: how can I detect whether I need to flip the X speed or the Y speed? ie: how can I calculate which edge of the bump was collided with?

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  • Algorithmic Forecasting and Pattern Recognition

    - by Ryan King
    Say a user could enter project data into my software. Each project has 2 variables "size" and "work" and they're related but the relationship is not known. Is there a way to programmatically determine the relationship between the variables based on previous data and forecast the amount of work provided if only given the size of the project in the future? For Example, say the user had manually entered the following projects. Project 1 - Size:1, Work: 4 Project 2 - Size:2, Work: 7 Project 3 - Size:3, Work: 10 Project 4 - Size:4, Work: x What should I look into to be able to programmatically determine, that Work = Size*3+1 and therefor be able to say that x=13?

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  • Is HTML5 more secure to develop for than Silverlight?

    - by King Chan
    I'm learning Silverlight, and I know that if I master it, I can apply the same concepts to WPF, which means I can do either web or desktop development pretty easily. But I've read articles and followed the discussion online, and I understand HTML5 is gaining traction for being cross-platform, and a lot of people seem to be moving to HTML5. From my understanding, any HTML5 application would be built with HTML and JavaScript (or Flash). But is it secure? It seems like anyone can easily use their browser's "view source" option and grab your code. Is this something I should be worried about, or is there a way to protect against it?

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  • error: no such partition after 11.10 upgrade to 12.04

    - by Alan King
    -I recently upgraded my 11.10 install to 12.04 LTS and got the above error message upon reboot after a GNU GRUB version ubuntu3 display showing Ubuntu 3.2.0-23-generic pae and other kernels or memory tests to choose from. The upgrade had to be done by CD because the Update Manager did not show the 12.04 upgrade option. After selecting the default install option of upgrading 11.10 to 12.04, I was presented with a screen saying that I had not specified a swap partition. Upon selection the 'back' key, I was taken to a partition page which listed two current partitions (only Ubuntu 11.10 had been installed - no Windoz): an ext4 partition plus a small 1.8GB partition. I double clicked the small partition and selected it as the swap partition even though I wondered at the time why this even came up. I can see the two user folders under home from the file manager screen while runnning 12.04 from the CD but if I try to access either one an error message is displayed saying I do not have permission while I get a loading message in the lower right corner of the window that does not go away. I have two questions: Can I access the user folders prior to recovery via the Terminal? If so, how? How do I fix the GRUB issue?

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  • JavaScript and callback nesting

    - by Jake King
    A lot of JavaScript libraries (notably jQuery) use chaining, which allows the reduction of this: var foo = $(".foo"); foo.stop(); foo.show(); foo.animate({ top: 0 }); to this: $(".foo").stop().show().animate({ top: 0 }); With proper formatting, I think this is quite a nice syntactic capability. However, I often see a pattern which I don't particularly like, but appears to be a necessary evil in non-blocking models. This is the ever-present nesting of callback functions: $(".foo").animate({ top: 0, }, { callback: function () { $.ajax({ url: 'ajax.php', }, { callback: function () { ... } }); } }); And it never ends. Even though I love the ease non-blocking models provide, I hate the odd nesting of function literals it forces upon the programmer. I'm interesting in writing a small JS library as an exercise, and I'd love to find a better way to do this, but I don't know how it could be done without feeling hacky. Are there any projects out there that have resolved this problem before? And if not, what are the alternatives to this ugly, meaningless code structure?

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