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  • Filter any mailing list in GMail using the "list:" meta-data

    - by Binary255
    Hi, If I ask GMail to create a filter for a mailing list it creates a rule containing list:mailing-list-identifier, in the case of the NAnt mailing list it wrote: Has the words: list: "nant-users.lists.sourceforge.net" Is there a way to filter any mailing list? I would like to filter conversations from any mailing list containing answers to things I've previously asked (or answered to). Part of that filter is identifying "anything which is part of a mailing list" and I'm wondering if there is a better way than adding another label to all mailing list posts (which is cumbersome).

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  • Linked List is now Patented?

    - by John Isaiah Carmona
    Linked list Ming-Jen Wang Patent number: 7028023 Filing date: Sep 26, 2002 Issue date: Apr 11, 2006 Application number: 10/260,471 A computerized list is provided with auxiliary pointers for traversing the list in different sequences. One or more auxiliary pointers enable a fast, sequential traversal of the list with a minimum of computational time. Such lists may be used in any application where lists may be reordered for various purposes. Does this mean that I need to acquire permission before using a linked list in my codes? What about the codes I write from my previous apps that uses a linked list? What about the framework that implements the linked list?

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  • Active - like-minded Java mailing lists

    - by Lewis Robbins
    I need to find an active Java mailing list, I have looked onto the GNU Java mailing list, to my surprise there had been not too much activity this month, it also focused on any GNU related Java - I'd really help me progress my Java ability, if I had an active, likeminded Java mailing list. Questions' that are not suited to Stackoverflow, or provide little benefit to any user that see's the question: discussing a new API change; best practices; open source discussion; trivia type questions on Java ArrayList boxining-unboxing; Community atmosphere. I also read Jon Skeets blog post about his previous Java/C# mailing lists examples - I did not catch any names, though I did they would be of benefit to me, if I had access to any of them.

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  • Invert linear linked list

    - by ArtWorkAD
    Hi, a linear linked list is a set of nodes. This is how a node is defined (to keep it easy we do not distinguish between node an list): class Node{ Object data; Node link; public Node(Object pData, Node pLink){ this.data = pData; this.link = pLink; } public String toString(){ if(this.link != null){ return this.data.toString() + this.link.toString(); }else{ return this.data.toString() ; } } public void inc(){ this.data = new Integer((Integer)this.data + 1); } public void lappend(Node list){ Node child = this.link; while(child != null){ child = child.link; } child.link = list; } public Node copy(){ if(this.link != null){ return new Node(new Integer((Integer)this.data), this.link.copy()); }else{ return new Node(new Integer((Integer)this.data), null); } } public Node invert(){ Node child = this.link; while(child != null){ child = child.link; } child.link = this;.... } } I am able to make a deep copy of the list. Now I want to invert the list so that the first node is the last and the last the first. The inverted list has to be a deep copy. I started developing the invert function but I am not sure. Any Ideas? Update: Maybe there is a recursive way since the linear linked list is a recursive data structure. I would take the first element, iterate through the list until I get to a node that has no child and append the first element, I would repeat this for the second, third....

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  • What's the best way to read mailing lists in 2011?

    - by Avdi
    I used to use Emacs/GNUS for reading mailing lists, but that feels very 1990. Plus, it doesn't sync my scoring across PCs. GMail is wonderful, but it kind of sucks for mailing lists. The essential "mute" feature doesn't even work unless the mail is in the Inbox. I'd read my mailing lists on the Google Groups site, but not all of them are Google Groups. Basically, I'm looking for the "Google Reader" of mailing lists. Any suggestions?

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  • Sorting a Linked List [closed]

    - by Mohit Sehgal
    I want to sort a linked list. Here Node is class representing a node in a Linked List I have written a code to bubble sort a linked list. Program does not finishes execution. Kindly point out the mistakes. class Node { public: int data; public: Node *next; Node() { data=0;next=0; } Node(int d) { data=d; } void setData(int d) { data=d; } void print() { cout<<data<<endl; } bool operator==(Node n) { return this->data==n.data; } bool operator >(Node d) { if((this->data) > (d.data)) return true; return false; } }; class LList { public: int noOfNodes; Node *start;/*Header Node*/ LList() { start=new Node; noOfNodes=0;start=0; } void addAtFront(Node* n) { n->next=(start); start=n; noOfNodes++; } void addAtLast(Node* n) { Node *cur=(start); n->next=NULL; if(start==NULL) { start=n; noOfNodes++; return; } while(cur->next!=NULL) { cur=cur->next; } cur->next=n; noOfNodes++; } void addAtPos(Node *n,int pos) { if(pos==1) { addAtFront(n);return; } Node *cur=(start); Node *prev=NULL; int curPos=0; n->next=NULL; while(cur!=NULL) { curPos++; if(pos==curPos+1) { prev=cur; } if(pos==curPos) { n->next=cur; prev->next=n; break; } cur=cur->next; } noOfNodes++; } void removeFirst() { Node *del=start; start=start->next; delete del; noOfNodes--; return; } void removeLast() { Node *cur=start,*prev=NULL; while(cur->next!=NULL) { prev=cur; cur=cur->next; } prev->next=NULL; Node *del=cur->next; delete del; noOfNodes--; return; } void removeNodeAt(int pos) { if(pos<1) return; if(pos==1) { removeFirst();return;} int curPos=1; Node* cur=start->next; Node* prev=start; Node* del=NULL; while(curPos<pos&&cur!=NULL) { curPos++; if(curPos==pos) { del=cur; prev->next=cur->next; cur->next=NULL; delete del; noOfNodes--; break; } prev=prev->next; cur=cur->next; } } void removeNode(Node *d) { Node *cur=start; if(*d==*cur) { removeFirst();return; } cur=start->next; Node *prev=start,*del=NULL; while(cur!=NULL) { if(*cur==*d) { del=cur; prev->next=cur->next; delete del; noOfNodes--; break; } prev=prev->next; cur=cur->next; } } int getPosition(Node data) { int pos=0; Node *cur=(start); while(cur!=NULL) { pos++; if(*cur==data) { return pos; } cur=cur->next; } return -1;//not found } Node getNode(int pos) { if(pos<1) return -1;// not a valid position else if(pos>noOfNodes) return -1; // not a valid position Node *cur=(start); int curPos=0; while(cur!=NULL) { if(++curPos==pos) return *cur; cur=cur->next; } } void reverseList()//reverse the list { Node* cur=start->next; Node* d=NULL; Node* prev=start; while(cur!=NULL) { d=cur->next; cur->next=start; start=cur; prev->next=d; cur=d; } } void sortBubble() { Node *i=start,*j=start,*prev=NULL,*temp=NULL,*after=NULL; int count=noOfNodes-1;int icount=0; while(i->next!=NULL) { j=start; after=j->next; icount=0; while(++icount!=count) { if((*j)>(*after)) { temp=after->next; after->next=j; prev->next=j->next; j->next=temp; prev=after; after=j->next; } else{ prev=j; j=after; after=after->next; } } i=i->next; count--; } } void traverse() { Node *cur=(start); int c=0; while(cur!=NULL) { // cout<<"start"<<start; c++; cur->print(); cur=cur->next; } noOfNodes=c; } ~LList() { delete start; } }; int main() { int n; cin>>n; int d; LList list; Node *node; Node *temp=new Node(2123); for(int i=0;i<n;i++) { cin>>d; node=new Node(d); list.addAtLast(node); } list.addAtPos(temp,1); cout<<"traverse\n"; list.traverse(); temp=new Node(12); list.removeNode(temp); cout<<"12 removed"; list.traverse(); list.reverseList(); cout<<"\nreversed\n"; list.traverse(); cout<<"bubble sort\n"; list.sortBubble(); list.traverse(); getch(); delete node; return 0; }

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  • Test if single linked list is circular by traversing it only once

    - by user1589754
    I am a fresher and I was asked this question in a recent interview I gave. The question was --- By traversing each element of linked list just once find if the single linked list is circular at any point. To this I answered that we will store reference of each node while traversing the list in another linked list and for every node in the list being tested we will find if the reference exists in the list I am storing the references. The interviewer said that he needs a more optimized way to solve this problem. Can anyone please tell me what would be a more optimized method to solve this problem.

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  • Easiest way to merge a changed list to the master list

    - by Kiran Chandrashekhar
    I have a two lists of class object : private List<IntVector> UserData = new List<IntVector>(); private List<IntVector> EditData = new List<IntVector>(); UserData is the Master List and EditData is another list which would be used to add, delete, or modify the list. One of the class memeber is CaseNo which would not change for an IntVector. I have made changes in the EditData and would like to merge the changes to the UserData. Any idea how to do it ?

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  • Java - How to find count of items in a list in another list

    - by David Buckley
    Say I have two lists: List<String>products = new ArrayList<String>(); products.add("computer"); products.add("phone"); products.add("mouse"); products.add("keyboard"); List<String>cart = new ArrayList<String>(); cart.add("phone"); cart.add("monitor"); I need to find how many items in the cart list exist in the products list. For the lists above, the answer would be 1 (as phone is in products and cart). If the cart list was: List<String>cart = new ArrayList<String>(); cart.add("desk"); cart.add("chair"); The result would be 0. If cart contained computer, mouse, desk, chair, the result would be 2 (for computer and mouse). Is there something in the Apache Commons Collections or the Google Collections API? I've looked through them and see ways to get a bag count, but not from another list, although it's possible I'm missing something. Right now, the only way I can think of is to iterate over the cart items and see if products contains the individual item and keep a count. I can't use containsAll as I need the count (not a boolean), and that would fail if all items in cart didn't exist in the product list (which can happen). I'm using Java 1.6 if that matters.

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  • .net byte[] to List<List<Point>>

    - by user1112111
    Is is possible to convert a byte array back to a List<List<Point>> ? LE: I am saving the List<List<Point>> in a database BLOB field. When I retrieve it, I want to convert it back to a List<List<Point>>. So I have the byte[], but I cannot figure out how to convert it. How should the de/serialization look like ?

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  • Python - List of Lists Slicing Behavior

    - by Dan Dobint
    When I define a list and try to change a single item like this: list_of_lists = [['a', 'a', 'a'], ['a', 'a', 'a'], ['a', 'a', 'a']] list_of_lists[1][1] = 'b' for row in list_of_lists: print row It works as intended. But when I try to use list comprehension to create the list: row = ['a' for range in xrange(3)] list_of_lists = [row for range in xrange(3)] list_of_lists[1][1] = 'b' for row in list_of_lists: print row It results in an entire column of items in the list being changed. Why is this? How can I achieve the desired effect with list comprehension?

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  • Do you know a good html mailing list management software with admin levels?

    - by SirG
    I'm basically looking for a program/app/script (can be commercial) which I can ideally install on a windows server (we can run asp, asp.net php mssql) we have different groups of people who send newsletters to web members, I want to bring it all into one app which I can monitor and control. Ideally it would be able to create html newsletters, (with some templates) track emails and click throughs. Manage email lists subscribe/unsubscribes. And importantly have different levels of admin, so a newsletter creator could log in and create and send off an email, it goes into a queue where a communications editor can have an overview of all newsletters and approve the sending of the emails or edit them before they are sent off. before I start coding something up myself I thought I'd ask if anyone has any advice! Cheers!

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  • Create unordered list tree menu from data stored in an table with the adjacency list model...php

    - by Ronedog
    I need to create a tree menu of "nth" subcategories. I settled on using the adjacency list model for my table structure, because I won't be updating this table very much and this seemed the easiest to implement for my use. I want to style the output using "ul" and "li" tags...I already have a css and jquery solution to do the styling. My problem comes from pulling the data out of the database and using a recursive function via PHP to build the list ... the list is a concatenated string that gets parsed to build the tree. I'm really having a hard time getting the closing "ul" and "li" tags to line up just where they need to be. Is this the best way to do this? Are there other better ways using arrays or something like that to do this? Any examples you can point me to of "best practices" for building a list like this will be appreciated. Thanks.

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  • Update a list from another list

    - by Langali
    I have a list of users in local store that I need to update from a remote list of users every once in a while. Basically: If a remote user already exists locally, update its fields. If a remote user doesn't already exist locally, add the user. If a local user doesn't appear in the remote list, deactivate or delete. If a local user also appears in the remote list, update its fields. Just a simple case of syncing the local list. Is there a better way to do this in pure Java than the following? I feel gross looking at my own code. public class User { Integer id; String email; boolean active; //Getters and Setters....... public User(Integer id, String email, boolean active) { this.id = id; this.email = email; this.active = active; } @Override public boolean equals(Object other) { boolean result = false; if (other instanceof User) { User that = (User) other; result = (this.getId() == that.getId()); } return result; } } public static void main(String[] args) { //From 3rd party List<User> remoteUsers = getRemoteUsers(); //From Local store List<User> localUsers =getLocalUsers(); for (User remoteUser : remoteUsers) { boolean found = false; for (User localUser : localUsers) { if (remoteUser.equals(localUser)) { found = true; localUser.setActive(remoteUser.isActive()); localUser.setEmail(remoteUser.getEmail()); //update } break; } if (!found) { User user = new User(remoteUser.getId(), remoteUser.getEmail(), remoteUser.isActive()); //Save } } for(User localUser : localUsers ) { boolean found = false; for(User remoteUser : remoteUsers) { if(localUser.equals(remoteUser)) { found = true; localUser.setActive(remoteUser.isActive()); localUser.setEmail(remoteUser.getEmail()); //Update } break; } if(!found) { localUser.setActive(false); // Deactivate } } }

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  • Parallel.For maintain input list order on output list

    - by romeozor
    I'd like some input on keeping the order of a list during heavy-duty operations that I decided to try to do in a parallel manner to see if it boosts performance. (It did!) I came up with a solution, but since this was my first attempt at anything parallel, I'd need someone to slap my hands if I did something very stupid. There's a query that returns a list of card owners, sorted by name, then by date of birth. This needs to be rendered in a table on a web page (ASP.Net WebForms). The original coder decided he would construct the table cell-by-cell (TableCell), add them to rows (TableRow), then each row to the table. So no GridView, allegedly its performance is bad, but the performance was very poor regardless :). The database query returns in no time, the most time is spent on looping through the results and adding table cells etc. I made the following method to maintain the original order of the list: private TableRow[] ComposeRows(List<CardHolder> queryResult) { int queryElementsCount = queryResult.Count(); // array with the query's size var rowArray = new TableRow[queryElementsCount]; Parallel.For(0, queryElementsCount, i => { var row = new TableRow(); var cell = new TableCell(); // various operations, including simple ones such as: cell.Text = queryResult[i].Name; row.Cells.Add(cell); // here I'm adding the current item to it's original index // to maintain order in the output list rowArray[i] = row; }); return rowArray; } So as you can see, because I'm returning a very different type of data (List<CardHolder> -> TableRow[]), I can't just simply omit the ordering from the original query to do it after the operations. Also, I also thought it would be a good idea to Dispose() the objects at the end of each loop, because the query can return a huge list and letting cell and row objects pile up in the heap could impact performance.(?) How badly did I do? Does anyone have a better solution in case mine is flawed?

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  • dpkg: warning: files list file for package 'x' missing

    - by Mark
    I get this warning for several packages every time I install any package or perform apt-get upgrade. Not sure what is causing it; it's a fresh Debian install on my OpenVZ server and I haven't changed any dpkg settings. Here's an example: root@debian:~# apt-get install cowsay Reading package lists... Done Building dependency tree Reading state information... Done Suggested packages: filters The following NEW packages will be installed: cowsay 0 upgraded, 1 newly installed, 0 to remove and 0 not upgraded. Need to get 21.9 kB of archives. After this operation, 91.1 kB of additional disk space will be used. Get:1 http://ftp.us.debian.org/debian/ unstable/main cowsay all 3.03+dfsg1-4 [21.9 kB] Fetched 21.9 kB in 0s (70.2 kB/s) Selecting previously unselected package cowsay. dpkg: warning: files list file for package 'libssh2-1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libkrb5-3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libwrap0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcap2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpam-ck-connector:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libc6:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libtalloc2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libselinux1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libp11-kit0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libavahi-client3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libbz2-1.0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpcre3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgpm2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgnutls26:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libavahi-common3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcroco3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'liblzma5:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpaper1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsensors4:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libbsd0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libavahi-common-data:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libss2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libblkid1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libslang2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libacl1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcomerr2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libkrb5support0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'e2fslibs:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'librtmp0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libidn11:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpcap0.8:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libattr1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libdevmapper1.02.1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'odbcinst1debian2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libexpat1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libltdl7:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libkeyutils1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcups2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsqlite3-0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libck-connector0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'zlib1g:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libnl1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libfontconfig1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libudev0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsepol1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libmagic1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libk5crypto3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libunistring0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgpg-error0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libusb-0.1-4:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpam0g:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpopt0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgssapi-krb5-2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgeoip1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcurl3-gnutls:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libtasn1-3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libuuid1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgcrypt11:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgdbm3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libdbus-1-3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsysfs2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libfreetype6:amd64' missing; assuming package has no files currently installed (Reading database ... 21908 files and directories currently installed.) Unpacking cowsay (from .../cowsay_3.03+dfsg1-4_all.deb) ... Processing triggers for man-db ... Setting up cowsay (3.03+dfsg1-4) ... root@debian:~# Everything works fine, but these warning messages are pretty annoying. Does anyone know how I can fix this?

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  • Python list comprehension to return edge values of a list

    - by mvid
    If I have a list in python such as: stuff = [1, 2, 3, 4, 5, 6, 7, 8, 9] with length n (in this case 9) and I am interested in creating lists of length n/2 (in this case 4). I want all possible sets of n/2 values in the original list, for example: [1, 2, 3, 4], [2, 3, 4, 5], ..., [9, 1, 2, 3] is there some list comprehension code I could use to iterate through the list and retrieve all of those sublists? I don't care about the order of the values within the lists, I am just trying to find a clever method of generating the lists.

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  • IE6 list issue - First list on page ignores horizontal margins

    - by user307922
    Hi Folks, I am creating a store in Magento and have a weird issue with IE6 and the ordered lists on my page. For some reason, IE6 ignores the horizontal margin on my first list. Not the first element in the list but the whole list. I have multiple list on the page. Here is a link to the offending page: http://byerofma.nexcess.net/products/pangean-furniture.html I have tried everything I can think of. Any ideas? Cheers, Chuck

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  • Best MAILING LIST solution for a CONFERENCE and its 400 participants

    - by Ole Morten Amundsen
    Dear community, what would you recommend for mailling lists? The conference is non-profit, named Smidig2010 (=Agile2010 in norwegian), will have about 400-500 participants 16.-17.november. At the time of writing this, we have not opened for registration, but would like people to be able to participate, ask questions, get informed and get inspired. We've used a forum before, but forums don't seem to be a good fit for this. I would like to set up a mailinglist, It'll have to be KISS, for the users: enter your email (a input box at our site smidig2010.no) get a confirmation mail, click a link. start posting, reading through archives, answering others etc. I like the look and feel of googlegroups, but I don't like the signup/account creation overhead imposed on the user. I've heard you may combine googlegroups with mailman and stuff, but, yeah, I can't believe our own incompetence on this subject! Btw, we are mostly developers and the conference app is being written in ruby on rails. Being non-profit, we prefer free, but we take everything into consideration. Any suggestions?

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  • filtering elements from list of lists in Python?

    - by user248237
    I want to filter elements from a list of lists, and iterate over the elements of each element using a lambda. For example, given the list: a = [[1,2,3],[4,5,6]] suppose that I want to keep only elements where the sum of the list is greater than N. I tried writing: filter(lambda x, y, z: x + y + z >= N, a) but I get the error: <lambda>() takes exactly 3 arguments (1 given) How can I iterate while assigning values of each element to x, y, and z? Something like zip, but for arbitrarily long lists. thanks, p.s. I know I can write this using: filter(lambda x: sum(x)..., a) but that's not the point, imagine that these were not numbers but arbitrary elements and I wanted to assign their values to variable names.

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