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  • Configuring Request-Reply in JMSAdapter

    - by [email protected]
    Request-Reply is a new feature in 11g JMSAdapter that helps you achieve the following:Allows you to combine Request and Reply in a single step. In the prior releases of the Oracle SOA Suite, you would require to configure two distinct adapters. Performs automatic correlation without you needing to configure BPEL "correlation sets". This would work seamlessly in Mediator and BPMN as well.In order to configure the JMSAdapter Request-Reply, please follow these steps:1) Drag and drop a JMSAdapter onto the "External References" swim lane in your composite editor. 2) Enter default values for the first few screens in the JMS Adapter wizard till you hit the screen where the wizard prompts you to enter the operation name. Select "Request-Reply" as the "Operation Type" and Asynchronous as "Operation Name".3) Select the Request and Reply queues in the following screens of the wizard. The message will be en-queued in the "Request" queue and the reply will be returned in the "Reply" queue. The reason I have used such a selector is that the back-end system that reads from the request queue and generates the response in the response queue actually generates more than one response and hence I must use a filter to exclude the unwanted responses.4) Select the message schema for request as well as response. 5) Add an <invoke> activity in BPEL corresponding to the JMS Adapter partner link. Please note that I am setting an additional header as my third-party application requires this.6) Add a <receive> activity just after the <invoke> and select the "Reply" operation. Please make sure that the "Create Instance" option is unchecked.Your completed BPEL process will something like this:

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  • Linux Email Server Auto-Reply

    - by Robert Smith
    I need to setup a mail server that has the following functionality: if a user sends an email to a specific address on this server, the server must first check if the email has a PDF attachment, do some processing to that PDF file and then reply to the user's initial mail with the new PDF file attached. My question is how would it be possible to achieve this functionality, and what software / mail server do you recommend? I'm thinking that it can be solved the following way: when the server receives a new email it executes an external Python script that checks the attachment, processes the PDF file and then sends it back in the user's mailbox. What mail server would be able to do this, and what configurations does it need?

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  • Linked List is now Patented?

    - by John Isaiah Carmona
    Linked list Ming-Jen Wang Patent number: 7028023 Filing date: Sep 26, 2002 Issue date: Apr 11, 2006 Application number: 10/260,471 A computerized list is provided with auxiliary pointers for traversing the list in different sequences. One or more auxiliary pointers enable a fast, sequential traversal of the list with a minimum of computational time. Such lists may be used in any application where lists may be reordered for various purposes. Does this mean that I need to acquire permission before using a linked list in my codes? What about the codes I write from my previous apps that uses a linked list? What about the framework that implements the linked list?

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  • Invert linear linked list

    - by ArtWorkAD
    Hi, a linear linked list is a set of nodes. This is how a node is defined (to keep it easy we do not distinguish between node an list): class Node{ Object data; Node link; public Node(Object pData, Node pLink){ this.data = pData; this.link = pLink; } public String toString(){ if(this.link != null){ return this.data.toString() + this.link.toString(); }else{ return this.data.toString() ; } } public void inc(){ this.data = new Integer((Integer)this.data + 1); } public void lappend(Node list){ Node child = this.link; while(child != null){ child = child.link; } child.link = list; } public Node copy(){ if(this.link != null){ return new Node(new Integer((Integer)this.data), this.link.copy()); }else{ return new Node(new Integer((Integer)this.data), null); } } public Node invert(){ Node child = this.link; while(child != null){ child = child.link; } child.link = this;.... } } I am able to make a deep copy of the list. Now I want to invert the list so that the first node is the last and the last the first. The inverted list has to be a deep copy. I started developing the invert function but I am not sure. Any Ideas? Update: Maybe there is a recursive way since the linear linked list is a recursive data structure. I would take the first element, iterate through the list until I get to a node that has no child and append the first element, I would repeat this for the second, third....

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  • Sorting a Linked List [closed]

    - by Mohit Sehgal
    I want to sort a linked list. Here Node is class representing a node in a Linked List I have written a code to bubble sort a linked list. Program does not finishes execution. Kindly point out the mistakes. class Node { public: int data; public: Node *next; Node() { data=0;next=0; } Node(int d) { data=d; } void setData(int d) { data=d; } void print() { cout<<data<<endl; } bool operator==(Node n) { return this->data==n.data; } bool operator >(Node d) { if((this->data) > (d.data)) return true; return false; } }; class LList { public: int noOfNodes; Node *start;/*Header Node*/ LList() { start=new Node; noOfNodes=0;start=0; } void addAtFront(Node* n) { n->next=(start); start=n; noOfNodes++; } void addAtLast(Node* n) { Node *cur=(start); n->next=NULL; if(start==NULL) { start=n; noOfNodes++; return; } while(cur->next!=NULL) { cur=cur->next; } cur->next=n; noOfNodes++; } void addAtPos(Node *n,int pos) { if(pos==1) { addAtFront(n);return; } Node *cur=(start); Node *prev=NULL; int curPos=0; n->next=NULL; while(cur!=NULL) { curPos++; if(pos==curPos+1) { prev=cur; } if(pos==curPos) { n->next=cur; prev->next=n; break; } cur=cur->next; } noOfNodes++; } void removeFirst() { Node *del=start; start=start->next; delete del; noOfNodes--; return; } void removeLast() { Node *cur=start,*prev=NULL; while(cur->next!=NULL) { prev=cur; cur=cur->next; } prev->next=NULL; Node *del=cur->next; delete del; noOfNodes--; return; } void removeNodeAt(int pos) { if(pos<1) return; if(pos==1) { removeFirst();return;} int curPos=1; Node* cur=start->next; Node* prev=start; Node* del=NULL; while(curPos<pos&&cur!=NULL) { curPos++; if(curPos==pos) { del=cur; prev->next=cur->next; cur->next=NULL; delete del; noOfNodes--; break; } prev=prev->next; cur=cur->next; } } void removeNode(Node *d) { Node *cur=start; if(*d==*cur) { removeFirst();return; } cur=start->next; Node *prev=start,*del=NULL; while(cur!=NULL) { if(*cur==*d) { del=cur; prev->next=cur->next; delete del; noOfNodes--; break; } prev=prev->next; cur=cur->next; } } int getPosition(Node data) { int pos=0; Node *cur=(start); while(cur!=NULL) { pos++; if(*cur==data) { return pos; } cur=cur->next; } return -1;//not found } Node getNode(int pos) { if(pos<1) return -1;// not a valid position else if(pos>noOfNodes) return -1; // not a valid position Node *cur=(start); int curPos=0; while(cur!=NULL) { if(++curPos==pos) return *cur; cur=cur->next; } } void reverseList()//reverse the list { Node* cur=start->next; Node* d=NULL; Node* prev=start; while(cur!=NULL) { d=cur->next; cur->next=start; start=cur; prev->next=d; cur=d; } } void sortBubble() { Node *i=start,*j=start,*prev=NULL,*temp=NULL,*after=NULL; int count=noOfNodes-1;int icount=0; while(i->next!=NULL) { j=start; after=j->next; icount=0; while(++icount!=count) { if((*j)>(*after)) { temp=after->next; after->next=j; prev->next=j->next; j->next=temp; prev=after; after=j->next; } else{ prev=j; j=after; after=after->next; } } i=i->next; count--; } } void traverse() { Node *cur=(start); int c=0; while(cur!=NULL) { // cout<<"start"<<start; c++; cur->print(); cur=cur->next; } noOfNodes=c; } ~LList() { delete start; } }; int main() { int n; cin>>n; int d; LList list; Node *node; Node *temp=new Node(2123); for(int i=0;i<n;i++) { cin>>d; node=new Node(d); list.addAtLast(node); } list.addAtPos(temp,1); cout<<"traverse\n"; list.traverse(); temp=new Node(12); list.removeNode(temp); cout<<"12 removed"; list.traverse(); list.reverseList(); cout<<"\nreversed\n"; list.traverse(); cout<<"bubble sort\n"; list.sortBubble(); list.traverse(); getch(); delete node; return 0; }

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  • Test if single linked list is circular by traversing it only once

    - by user1589754
    I am a fresher and I was asked this question in a recent interview I gave. The question was --- By traversing each element of linked list just once find if the single linked list is circular at any point. To this I answered that we will store reference of each node while traversing the list in another linked list and for every node in the list being tested we will find if the reference exists in the list I am storing the references. The interviewer said that he needs a more optimized way to solve this problem. Can anyone please tell me what would be a more optimized method to solve this problem.

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  • Easiest way to merge a changed list to the master list

    - by Kiran Chandrashekhar
    I have a two lists of class object : private List<IntVector> UserData = new List<IntVector>(); private List<IntVector> EditData = new List<IntVector>(); UserData is the Master List and EditData is another list which would be used to add, delete, or modify the list. One of the class memeber is CaseNo which would not change for an IntVector. I have made changes in the EditData and would like to merge the changes to the UserData. Any idea how to do it ?

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  • How to configure Exchange Server with AutoReply that sends the reply only once?

    - by Abel
    If you configure Exchange Server 2007 for auto-reply on a public address, and the reply is sent to an address that also has auto-reply or out-of-office-auto-reply, then Exchange Server will receive a new message, same from-address, and will again send an auto-reply. This can go on forever and can potentially lead to a DoS situation. How can I prevent multiple sending of auto-reply to the same address, preferably in a given timeframe (to prevent legitimate multiple mails to be treated incorrectly), using Exchange Server 2007? Our XS hosting provider says it cannot be done, but that strikes me as odd.

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  • Java - How to find count of items in a list in another list

    - by David Buckley
    Say I have two lists: List<String>products = new ArrayList<String>(); products.add("computer"); products.add("phone"); products.add("mouse"); products.add("keyboard"); List<String>cart = new ArrayList<String>(); cart.add("phone"); cart.add("monitor"); I need to find how many items in the cart list exist in the products list. For the lists above, the answer would be 1 (as phone is in products and cart). If the cart list was: List<String>cart = new ArrayList<String>(); cart.add("desk"); cart.add("chair"); The result would be 0. If cart contained computer, mouse, desk, chair, the result would be 2 (for computer and mouse). Is there something in the Apache Commons Collections or the Google Collections API? I've looked through them and see ways to get a bag count, but not from another list, although it's possible I'm missing something. Right now, the only way I can think of is to iterate over the cart items and see if products contains the individual item and keep a count. I can't use containsAll as I need the count (not a boolean), and that would fail if all items in cart didn't exist in the product list (which can happen). I'm using Java 1.6 if that matters.

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  • .net byte[] to List<List<Point>>

    - by user1112111
    Is is possible to convert a byte array back to a List<List<Point>> ? LE: I am saving the List<List<Point>> in a database BLOB field. When I retrieve it, I want to convert it back to a List<List<Point>>. So I have the byte[], but I cannot figure out how to convert it. How should the de/serialization look like ?

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  • Python - List of Lists Slicing Behavior

    - by Dan Dobint
    When I define a list and try to change a single item like this: list_of_lists = [['a', 'a', 'a'], ['a', 'a', 'a'], ['a', 'a', 'a']] list_of_lists[1][1] = 'b' for row in list_of_lists: print row It works as intended. But when I try to use list comprehension to create the list: row = ['a' for range in xrange(3)] list_of_lists = [row for range in xrange(3)] list_of_lists[1][1] = 'b' for row in list_of_lists: print row It results in an entire column of items in the list being changed. Why is this? How can I achieve the desired effect with list comprehension?

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  • Create unordered list tree menu from data stored in an table with the adjacency list model...php

    - by Ronedog
    I need to create a tree menu of "nth" subcategories. I settled on using the adjacency list model for my table structure, because I won't be updating this table very much and this seemed the easiest to implement for my use. I want to style the output using "ul" and "li" tags...I already have a css and jquery solution to do the styling. My problem comes from pulling the data out of the database and using a recursive function via PHP to build the list ... the list is a concatenated string that gets parsed to build the tree. I'm really having a hard time getting the closing "ul" and "li" tags to line up just where they need to be. Is this the best way to do this? Are there other better ways using arrays or something like that to do this? Any examples you can point me to of "best practices" for building a list like this will be appreciated. Thanks.

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  • Comment reply procedure using jquery and php?

    - by Prashant
    I have Commenting system in my app. For a single video entry anyone can post a comment and someone else can post reply to that comment and replies, cannot have thier further reples, similar to StackOverflow is doing (1 Answer, and thier 1 or more replies). I want the similar functionality what SO has, Let's I have the following HTML <div class="comment" id="comment-908"> First comment </div> <div class="reply"> <div id="reply-909> reply 1 </div> <div id="reply-910> reply 2 </div> <div id="reply-911> reply 3 </div> </div> <form id="reply-form"> <textarea id="replycomment" name="replycomment"></textarea> <input type="submit" name="submit-reply" value="add reply" /> </form> Now above HTML is a sample which I have created, When someone will click on "add reply" button then I am using jquery to post there reply. Now I want to know that there will be multiple comment and multiple add reply forms. So who clicks on which button and for which comment someone wants to post a reply, how will i know that? The above HTML is not in correct way, please suggest me the correct HTML flow which I can use and how to work with jquery? now I want to know when soe

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  • Update a list from another list

    - by Langali
    I have a list of users in local store that I need to update from a remote list of users every once in a while. Basically: If a remote user already exists locally, update its fields. If a remote user doesn't already exist locally, add the user. If a local user doesn't appear in the remote list, deactivate or delete. If a local user also appears in the remote list, update its fields. Just a simple case of syncing the local list. Is there a better way to do this in pure Java than the following? I feel gross looking at my own code. public class User { Integer id; String email; boolean active; //Getters and Setters....... public User(Integer id, String email, boolean active) { this.id = id; this.email = email; this.active = active; } @Override public boolean equals(Object other) { boolean result = false; if (other instanceof User) { User that = (User) other; result = (this.getId() == that.getId()); } return result; } } public static void main(String[] args) { //From 3rd party List<User> remoteUsers = getRemoteUsers(); //From Local store List<User> localUsers =getLocalUsers(); for (User remoteUser : remoteUsers) { boolean found = false; for (User localUser : localUsers) { if (remoteUser.equals(localUser)) { found = true; localUser.setActive(remoteUser.isActive()); localUser.setEmail(remoteUser.getEmail()); //update } break; } if (!found) { User user = new User(remoteUser.getId(), remoteUser.getEmail(), remoteUser.isActive()); //Save } } for(User localUser : localUsers ) { boolean found = false; for(User remoteUser : remoteUsers) { if(localUser.equals(remoteUser)) { found = true; localUser.setActive(remoteUser.isActive()); localUser.setEmail(remoteUser.getEmail()); //Update } break; } if(!found) { localUser.setActive(false); // Deactivate } } }

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  • Parallel.For maintain input list order on output list

    - by romeozor
    I'd like some input on keeping the order of a list during heavy-duty operations that I decided to try to do in a parallel manner to see if it boosts performance. (It did!) I came up with a solution, but since this was my first attempt at anything parallel, I'd need someone to slap my hands if I did something very stupid. There's a query that returns a list of card owners, sorted by name, then by date of birth. This needs to be rendered in a table on a web page (ASP.Net WebForms). The original coder decided he would construct the table cell-by-cell (TableCell), add them to rows (TableRow), then each row to the table. So no GridView, allegedly its performance is bad, but the performance was very poor regardless :). The database query returns in no time, the most time is spent on looping through the results and adding table cells etc. I made the following method to maintain the original order of the list: private TableRow[] ComposeRows(List<CardHolder> queryResult) { int queryElementsCount = queryResult.Count(); // array with the query's size var rowArray = new TableRow[queryElementsCount]; Parallel.For(0, queryElementsCount, i => { var row = new TableRow(); var cell = new TableCell(); // various operations, including simple ones such as: cell.Text = queryResult[i].Name; row.Cells.Add(cell); // here I'm adding the current item to it's original index // to maintain order in the output list rowArray[i] = row; }); return rowArray; } So as you can see, because I'm returning a very different type of data (List<CardHolder> -> TableRow[]), I can't just simply omit the ordering from the original query to do it after the operations. Also, I also thought it would be a good idea to Dispose() the objects at the end of each loop, because the query can return a huge list and letting cell and row objects pile up in the heap could impact performance.(?) How badly did I do? Does anyone have a better solution in case mine is flawed?

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  • dpkg: warning: files list file for package 'x' missing

    - by Mark
    I get this warning for several packages every time I install any package or perform apt-get upgrade. Not sure what is causing it; it's a fresh Debian install on my OpenVZ server and I haven't changed any dpkg settings. Here's an example: root@debian:~# apt-get install cowsay Reading package lists... Done Building dependency tree Reading state information... Done Suggested packages: filters The following NEW packages will be installed: cowsay 0 upgraded, 1 newly installed, 0 to remove and 0 not upgraded. Need to get 21.9 kB of archives. After this operation, 91.1 kB of additional disk space will be used. Get:1 http://ftp.us.debian.org/debian/ unstable/main cowsay all 3.03+dfsg1-4 [21.9 kB] Fetched 21.9 kB in 0s (70.2 kB/s) Selecting previously unselected package cowsay. dpkg: warning: files list file for package 'libssh2-1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libkrb5-3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libwrap0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcap2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpam-ck-connector:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libc6:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libtalloc2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libselinux1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libp11-kit0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libavahi-client3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libbz2-1.0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpcre3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgpm2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgnutls26:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libavahi-common3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcroco3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'liblzma5:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpaper1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsensors4:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libbsd0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libavahi-common-data:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libss2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libblkid1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libslang2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libacl1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcomerr2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libkrb5support0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'e2fslibs:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'librtmp0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libidn11:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpcap0.8:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libattr1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libdevmapper1.02.1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'odbcinst1debian2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libexpat1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libltdl7:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libkeyutils1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcups2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsqlite3-0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libck-connector0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'zlib1g:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libnl1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libfontconfig1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libudev0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsepol1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libmagic1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libk5crypto3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libunistring0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgpg-error0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libusb-0.1-4:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpam0g:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libpopt0:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgssapi-krb5-2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgeoip1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libcurl3-gnutls:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libtasn1-3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libuuid1:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgcrypt11:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libgdbm3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libdbus-1-3:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libsysfs2:amd64' missing; assuming package has no files currently installed dpkg: warning: files list file for package 'libfreetype6:amd64' missing; assuming package has no files currently installed (Reading database ... 21908 files and directories currently installed.) Unpacking cowsay (from .../cowsay_3.03+dfsg1-4_all.deb) ... Processing triggers for man-db ... Setting up cowsay (3.03+dfsg1-4) ... root@debian:~# Everything works fine, but these warning messages are pretty annoying. Does anyone know how I can fix this?

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  • Python list comprehension to return edge values of a list

    - by mvid
    If I have a list in python such as: stuff = [1, 2, 3, 4, 5, 6, 7, 8, 9] with length n (in this case 9) and I am interested in creating lists of length n/2 (in this case 4). I want all possible sets of n/2 values in the original list, for example: [1, 2, 3, 4], [2, 3, 4, 5], ..., [9, 1, 2, 3] is there some list comprehension code I could use to iterate through the list and retrieve all of those sublists? I don't care about the order of the values within the lists, I am just trying to find a clever method of generating the lists.

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  • IE6 list issue - First list on page ignores horizontal margins

    - by user307922
    Hi Folks, I am creating a store in Magento and have a weird issue with IE6 and the ordered lists on my page. For some reason, IE6 ignores the horizontal margin on my first list. Not the first element in the list but the whole list. I have multiple list on the page. Here is a link to the offending page: http://byerofma.nexcess.net/products/pangean-furniture.html I have tried everything I can think of. Any ideas? Cheers, Chuck

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  • filtering elements from list of lists in Python?

    - by user248237
    I want to filter elements from a list of lists, and iterate over the elements of each element using a lambda. For example, given the list: a = [[1,2,3],[4,5,6]] suppose that I want to keep only elements where the sum of the list is greater than N. I tried writing: filter(lambda x, y, z: x + y + z >= N, a) but I get the error: <lambda>() takes exactly 3 arguments (1 given) How can I iterate while assigning values of each element to x, y, and z? Something like zip, but for arbitrarily long lists. thanks, p.s. I know I can write this using: filter(lambda x: sum(x)..., a) but that's not the point, imagine that these were not numbers but arbitrary elements and I wanted to assign their values to variable names.

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  • [C++] STL list - how to find a list element by its object fields

    - by Dominic Bou-Samra
    I have a list: list<Unit *> UnitCollection; containing Unit objects, which has an accessor like: bool Unit::isUnit(string uCode) { if(this->unitCode == uCode) return true; else return false; } How do I search my UnitCollection list by uCode and return the corresponding element (preferably it's index). I have looked at the find() method, but i'm not sure you can pass a boolean method in instead of a searched item parameter if that makes sense.

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  • List filtering: list comprehension vs. lambda + filter

    - by Agos
    I happened to find myself having a basic filtering need: I have a list and I have to filter it by an attribute of the items. My code looked like this: list = [i for i in list if i.attribute == value] But then i thought, wouldn't it be better to write it like this? filter(lambda x: x.attribute == value, list) It's more readable, and if needed for performance the lambda could be taken out to gain something. Question is: are there any caveats in using the second way? Any performance difference? Am I missing the Pythonic Way™ entirely and should do it in yet another way (such as using itemgetter instead of the lambda)? Thanks in advance

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  • List.clear() followed by List.add() not working.

    - by Vincent
    I have the following C# Class/Function: class Hand { private List<Card> myCards = new List<Card>(); public void sortBySuitValue() { IEnumerable<Card> query = from s in myCards orderby (int)s.suit, (int)s.value select s; myCards = new List<Card>(); myCards.AddRange(query); } } On a card Game. This works fine, however, I had trouble at first, instead of using myCards = new List(); to 'reset' myCards, I would use myCards.clear(), however, once I called the clear function, I would not be able to call myCards.add() or myCards.addRange(). The count would stay at zero. Is my current approach good? Is using LINQ to sort my cards good/bad?

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