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  • need help speeding up tag cloud filter for IE

    - by rod
    Hi All, Any ideas on how to speed this up in IE (performs decent in Firefox, but almost unusable in IE). Basically, it's a tag cloud with a filter text box to filter the cloud. <html> <head> <script type="text/javascript" src="jquery-1.3.2.min.js"></script> <script type="text/javascript"> $(document).ready(function(){ $('#tagFilter').keyup(function(e) { if (e.keyCode==8) { $('#cloudDiv > span').show(); } $('#cloudDiv > span').not('span:contains(' + $(this).val() + ')').hide(); }); }); </script> </head> <body> <input type="text" id="tagFilter" /> <div id="cloudDiv" style="height: 200px; width: 400px; overflow: auto;"> <script type="text/javascript"> for (i=0;i<=1300;i++) { document.write('<span><a href="#">Test ' + i + '</a>&nbsp;</span>'); } </script> </div> </body> </html> thanks, rodchar

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  • Passing list of items from Controller/Model to a variable in javascript - autocomplete

    - by newbie_developer
    I've a method in a NamesModel which fetches all the names and returns a list of names: public static List<NamesModel> GetAllNames() { List<NamesModel> names = new List<NamesModel>(); // // code to fetch records // return names; } In my controller: public ActionResult Index() { NamesModel model = new NamesModel(); model.GetAllNames(); return View(model); } In the view, I've got a textbox: @Html.TextBox("search-name") Now in my javascript, I want to fetch all names into a variable either from a model (from method) or from controller, for example: <script type="text/javascript"> $(function () { var names = ........... $(document).ready(function () { $('#search-name').autocomplete({ source: names }); }); }); </script> If I use hardcoding then it works but I want to use the names stored in the db. Is it possible? hardcoding example: var names = ["abc", "xyz"];

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  • C# WPF Unable to control Textboxes

    - by Bo0m3r
    I'm a beginner in coding into C#. While I'm launching a process I can't controls my textboxes. I found some answers on this forum but the explaination is a bit to difficult for me to implement it for my problem. I created a small program that will run a batch file to make a backup. While the backup is running I can't modify my textboxes, disabling buttons etc... I already saw that this is normal but I don't know how to implement the solutions. My last attempt was with Dispatcher.invoke as you can see below. public partial class MainWindow : Window { public MainWindow() { InitializeComponent(); tb_Status.Text = "Ready"; } public void status() { Dispatcher.Invoke(DispatcherPriority.Send, new Action( () => { tb_Status.Text = "The backup is running!"; } ) ); } public void process() { try { Process p = new Process(); p.StartInfo.WindowStyle = ProcessWindowStyle.Minimized; p.StartInfo.CreateNoWindow = true; p.StartInfo.UseShellExecute = false; p.StartInfo.RedirectStandardOutput = true; p.StartInfo.FileName = "Robocopy.bat"; p.Start(); string output = p.StandardOutput.ReadToEnd(); p.WaitForExit(); tb_Output.Text = File.ReadAllText("Backup\\log.txt"); } catch (Exception ex) { tb_Status.Text = ex.Message.ToString(); } } private void Bt_Start_Click(object sender, EventArgs e) { status(); Directory.CreateDirectory("Backup"); process(); tb_Status.Text = "The backup finished"; File.Delete("Backup\\log.txt"); } } } Any help is appreciated!

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  • Issue creating side-by-side slideshows with jQuery

    - by JShweky
    I'm trying to create a site with 2 slideshows. I've tweaked and re-tweaked the JS and Jquery numerous times. Sometimes one slideshow works perfectly and the other cycles between one picture, other times both work but are out of sync, or the fadeIn doesn't seem to be applied to the second slideshow, or in some variations one slideshow stays frozen on the initial image and just remains static. Anyway, I created a JS Fiddle (link at bottom) and apparently my code is at least free of typos. JS is below, the rest is on the JS Fiddle. Any help would be greatly appreciated. $(document).ready(function () { $(".slider #1").fadeIn(1000); $(".slider #1").delay(2000).fadeOut(1000); var sc = $(".slider img").size(); var count = 2; setInterval(function () { $(".slider #" + count).fadeIn(1000); $(".slider #" + count).delay(2000).fadeOut(1000); if (count === sc) { count = 1; } else { count++; } }, 3500); $(".sliderTwo #7").fadeIn(1000); $(".sliderTwo #7").delay(2000).fadeOut(1000); var sc2 = 12; var count2 = 7; setInterval(function () { $(".sliderTwo #" + count2).fadeIn(1000); $(".sliderTwo #" + count2).delay(2000).fadeOut(1000); if (count2 === sc2) { count2 = 7; } else { count2++; } }, 3500); }); http://jsfiddle.net/gg4PL/

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  • How to make jquery pop up box responsive

    - by user2375896
    i have jquery pop up responsive , it works but when i change the size of the page , it stays on the right side . <link rel="stylesheet" type="text/css" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.1/themes/base/jquery-ui.css"> <style type="text/css"> .ui-widget-header { background: white; border: 0px; color:black; } #ui-dialog-title-dialog { background-color: black; } .ui-widget-overlay { background: none repeat-x scroll 0 0 black; opacity: 0.7; }</style> and function side is here : <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.1/jquery-ui.min.js"></script> <script type="text/javascript"> $(document).ready(function () { var $dialog = $('<div stye="float:left;" width:auto;"></div>') .html('<p>Lütfen kisi veya kisileri hedef alan haberler yazmayiniz.</p><p>Gerçegi yansitmayan haberler paylasmayiniz. </p><ul><li>Eklediginiz haberler Admin tarafindan onaylandiktan sonra yayinlanacaktir.</li><li>Boyabat.net sitesini kullandiginiz için tesekkür ederiz...</li></ul><table style="margin-right:auto; margin-left:auto;"></table>') .dialog({ autoOpen: true, resizable: true, draggable: true, width: 'auto', // overcomes width:'auto' and maxWidth bug height: 300, maxWidth: 600, modal: true, title: 'Haber Ekleme Kurallari' }); }); </script it works fine but when i run my responsive template and changeit is size to iphone , it is not appera in the screen. I juust need a solution on that . An help appriciate..Thanks

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  • navigation li to create <span></span> around text via jquery

    - by MikesEpitaphSays
    I've been trying all day and reading a few things, but for some reason my code isn't working right What i'm trying to achieve is this: When i create an un ordered list in my index page - I want my jquery to automatically add around the text in the anchor. So i want it to look like this <li><a href="index.htm"><span>Home</span></a></li> while I am only adding: <li><a href="index.htm">Home</a></li> I want to do this because i have a LOT of list items and instead of writing when i'm adding pages it makes the most sense to save some time in the long run and create a loop that will handle that anytime i add one. This is What i have so far (sorry if it looks ugly): $('document').ready(function () { var begSpan = "<span>"; var endSpan = "</span>"; $('p').each(function () { $(this) prepend(begSpan); }).append(endSpan); }); How can i get that to auto create span tags for me

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  • jQuery: serializing array returns empty string

    - by John Smith
    I did not forget to add name attributes as is a common problem and yet my serialized form is returning an empty string. What am I doing wrong? HTML/javascript: <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script> <script> $( document ).ready( function() { $('#word_form').submit(function(e) { e.preventDefault(); console.log($(this).serialize()); //returns an empty string }); }); </script> </head> <body> <div id="wrapper"> <form name="word_form" id="word_form" method="POST"> <input type="image" name="thumbsUp" id="thumb1" value="1" src="http://upload.wikimedia.org/wikipedia/commons/8/87/Symbol_thumbs_up.svg" style="width:50px;height:50px;"> <input type="image" name="thumbsDown" id="thumb2" value="2" src="http://upload.wikimedia.org/wikipedia/commons/8/84/Symbol_thumbs_down.svg" style="width:50px;height:50px;"> </form> </div> </body> Thanks!

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  • Modifying html of dom element that was created after page loaded

    - by Ben321
    I have two separate AJAX calls. One that gets a list of items from a txt file and creates an HTML table out of them and one that talks to a database to find how much each item costs and then lists this in the corresponding table cell for each item (I know this may sound like a strange approach, but it's a good option in our case...). The issue is that the price is not getting written to the table since the table is created (or to be precise, the rows of the table are created) after the page loads. I'm not sure how to fix this. $(document).ready(function() { makeItemTable(); listPrices(); ... }); function makeItemTable() { $.ajax({ url: 'products.php', type: 'GET' }) .done(function(response) { $('.price-table > tbody').html(response); }) } function listPrices() { .ajax({ url: 'prices.php', type: 'GET' }) .done(function(response) { priceData = $.parseJSON(response); $('.price-table tr').each(function() { var item = $(this).find('td:nth-child(1)').text(); if (priceData[item]) { var price = priceData[item]; $(this).find('td:nth-child(2)').text(price); } }) }

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  • How to use scrollTop in jQuery when scrolling within a div?

    - by sharataka
    I am trying to get the scrollTop using jQuery to work when the content I am trying to scroll to is located in within a div. The current implementation doesn't do anything javascript <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5.1/jquery.min.js"></script> <script> $(document).ready(function (){ //$(this).animate(function(){ $('html, body').animate({ scrollTop: $("#test4").offset().top }, 2000); //}); }); </script> html <div class="row"> <div class = "span12"> <div class = "row"> <div class = "span2"> <div style="height:480px;font:12px Georgia, Garamond, Serif;overflow:auto;"> <div id = "test1">Test1</div> <div id = "test2">Test2</div> <div id = "test3">Test3</div> <div id = "test4">Test4</div> </div> </div> <div class = "row"> <div class = "span8"> Other content on the page </div> </div> </div> </div> </div>

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  • div on other div

    - by Gisinior
    i have: <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.6.1/jquery.min.js"></script> <style type="text/css"> #ONE { background-color: #888; width: 500px; height: 500px; } #TWO { background-color: blue; width: 50px; height: 50px; } #THREE { background-color: yellow; width: 200px; height: 200px; display: none; } #four { background-color: red; width: 200px; height: 200px; } </style> <script type="text/javascript"> $(document).ready( function() { $("#TWO").click( function() { $("#THREE").toggle(); }); }); </script> <div id="ONE"><div id="TWO"></div><div id="four"></div><div id="THREE"></div></div> default click for blue div how can i it make? best with transparent :)

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  • jquery .siblings do not work

    - by Mango
    Hi i want when the one #box is open the others #box close. Html: <div id="main"> <div id="link">click</div><!--/*div*/--> <div id="box">content1</div><!--/*div*/--> </div><!--/*div*/--> <div id="main"> <div id="link">click2</div><!--/*div*/--> <div id="box">content2</div><!--/*div*/--> </div><!--/*div*/--> <div id="main"> <div id="link">click3</div><!--/*div*/--> <div id="box">content3</div><!--/*div*/--> </div><!--/*div*/--> Jquery: <script type="text/javascript"> $(document).ready(function(){ $('#main #box').css('display', 'none') $('#main #link').click(function() { $(this).next('#main #box').slideToggle('slow') .siblings('#main #box:visible').css('display', 'none'); }); }); </script> Thanks!

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  • Calling a function from a ajax response content

    - by pistolshrimp
    Hi guys. I have a function when the page is ready. <script> $(function(){ function do_ajax(){ do some stuff } });.... This works great on that page. Then I make a .post call and load the response into a div. The response has a <script>$(selector).click(function(){ do_ajax(); });</script> with the result. I get an error "do_ajax() is undefined". How can I call do_ajax() from an event from the ajax content? Another one. I am using jquery ui datepicker. So, when the page is loaded, I invoke the $(".datepicker").datepicker(); This works great on that page. Then I make a .post call and load the response into a div. The response has a couple of .datepicker fields. The problem is that the newly loaded datepicker fields don't get the calendar unless I return <script>$(".datepicker").datepicker();</script> with the result. Is that how you guys do it or is there another way? Thanks!

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  • jQuery: Is it possible to assign a DOM element to a variable for later use?

    - by Braxo
    I'm working on a project that is using jQuery, which I'm much more familiar with Mootools. I'll start with my code first. var customNamespace = { status: 'closed', popup: $('#popup'), showPopup: function() { // ... } } $(document).ready(function(){ console.log($('#popup')); console.log(customNamespace.popup); console.log($(customNamespace.popup)); $('#popup').fadeIn('slow'); (customNamespace.popup).fadeIn('slow'); $(customNamespace.popup).fadeIn('slow'); }); My goal is to not have jQuery traverse the DOM everytime I want to do something with the #popup div, so I wanted to save it to a variable to use it throughout my script. When the page loads, the console prints out the object 3 times as I would expect, so I assumed that for each method, the fadeIn would just work. But it doesn't, only $('#popup').fadeIn('slow'); Actually fades in the div. Even if I remove my namespace hash, and just save the object to a global variable, and do a var globalVariable = $('#popup'); . . . globalVariable.fadeIn('slow'); Also does not work as I thought it would. Can jQuery do what I am trying to do?

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  • how to filter selected objects then hide objects not selected.

    - by ussteele
    following up from yesterday... This portion of the code does work. $(document).ready(function(){ $('#listMenu a').click(function (selected) { var getPage = $(this).attr('id'); var getName = $(this).attr('name'); //console.log(getPage); //console.log(getName); $(function() { $("#" + getName ).show(); var getColor = $('#' + getName ).css('background-color'); $('#header' ).css('background', getColor); $('#slideshow' ).css('background', getColor); $('span').css('background', getColor); $('#menuContainer').css('background', getColor); }); $('li.listMenu ul').hide(); }); }); I am able to get what I wanted selected; based on vars getPage and getName, now I need to hide what is not selected. I have tried this: $(function() { var notSelected = $('div').filter(selected).attr('id', 'name'); $(this).hide(); console.log(notSelected); }); placed just above: $('li.listMenu ul').hide(); but it's not correct, remember I am really a newbie. what I see on screen is the new selected items on top of what should be hidden. again any help is appreciated. -sjs

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  • Simple Jquery function won't work

    - by stijn26
    I have following jQuery code $(document).ready(function() { for(var i=1;i<4;i++) { var img= ".img"+i; var p= ".p"+i; $(img).on("click", function(){ $(p).hide(); }); } }); Applied on the following html: <div> <article> <h1>Over mezelf <img src='images/plus.png' class='img1'/></h1> <p class='p1'>Test</p> </article> <article> <h1>Contact <img src='images/plus.png' class='img2'/></h1> <p class='p2'>Test</p> </article> <article> <h1>Website <img src='images/plus.png' class='img3'/></h1> <p class='p3'>Test</p> </article> </div> When I click on the images, the last <p> disappears, it doesn't work on the other ones.

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  • Problem with jQuery array

    - by user236106
    <html> <head> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js" type="text/javascript"></script> <script type="text/jscript"> $('document').ready(function (){ var clickNo=0; $('div#pics>img').hide() $('div#pics>input').click(function(event){ $('div#pics>img')[0].show('slow'); }) }); </script> </head> <body> <div id="pics"> <input type="button" value="next" /> <--a bunch of img tags .I had to resort to this comment because the system won't let me include the img tag in the code--> </div> </body> </html> I can't understand why the line $('div#pics>img')[0].show('slow'); is not working.

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  • mcsCustomscrollbar append new content not working

    - by Dariel Pratama
    i have this script in my website. $(document).ready(function(){ var comment = $('textarea[name=comment_text]').val(); var vid = $('input[name=video_id]').val(); $('#add_comment').on('click', function(){ $.post('<?php echo site_url('comment/addcomments'); ?>', $('#comment-form').serialize(), function(data){ data = JSON.parse(data); if(data.userdata){ var date = new Date(data.userdata.comment_create_time * 1000); var picture = data.userdata.user_image.length > 0 ? 'fileupload/'+data.userdata.user_image:'images/no_pic.gif'; var newComment = '<div class="row">\ <div class="col-md-4">\ <img src="<?php echo base_url(); ?>'+picture+'" class="profile-pic margin-top-15" />\ </div>\ <div class="col-md-8 no-pade">\ <p id="comment-user" class="margin-top-15">'+data.userdata.user_firstname+' '+data.userdata.user_lastname+'</p>\ <p id="comment-time">'+date.getTime()+'</p>\ </div>\ <div class="clearfix"></div>\ <div class="col-md-12 margin-top-15" id="comment-text">'+data.userdata.comment_text +'</div>\ <div class="col-md-12">\ <div class="hr-grey margin-top-15"></div>\ </div>\ </div>'; $('#comment-scroll').append($(newComment)); $('#comment').modal('hide'); } }); }); }); what i expect when a comment added to the DB and the PHP page give JSON response, the new comment will be added to the last line of $('#comment-scroll'). #comment-scroll is also have custom scroll bar by mcsCustomscrollbar. the above script also hiding the modal dialog when comment saved and it's working fine which is mean data.userdata is not empty, but why the append() isnt?

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  • Submitting form with Ajax

    - by Sidetracking
    So I'm completely lost on how to submit a form with Ajax. I'm fairly new to Javascript and hopefully I'm not in over my head. When I click submit on my form, nothing happens on my page, not in my SQL database where the info should be stored (double checked process form too). Here's the code if anyone's willing to help Javascript: $(document).ready(function() { $('#form').submit(function() { $.ajax({ url: "../process.php", type: "post", data: $(this).serialize() }); }); } HTML: <form name="contact" method="post" action="" id="form"> <span id="input"> <input type="text" name="first" maxlength="50" size="30" title="First Name" class="textbox"> <input type="text" name="last" maxlength="80" size="30" title="Last Name" class="textbox"> <input type="text" name="email" maxlength="80" size="30" title="Email" class="textbox"> <textarea name="request" maxlength="1000" cols="25" rows="6" title="Request"></textarea> </span> <input type="submit" value="Submit" class="submit"> </form>

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  • Dropdown menu not showing when using position: absolute;

    - by Xiy
    I've just turned my website into a responsive layout and along the way I've somehow managed to make my dropdown menus not work. When hovering over 'Drop-downs' they don't display unless I'm using position: relative. They worked before using position: absolute - but it seems they only work with position relative now. When using relative it uses the width which messes up the navigation bar. Using relative: http://d.pr/i/tp5R Using absolute: http://d.pr/i/j7r1 CSS for my sub-menu div.left_first_header ul.sub-menu { width: 125px; top: 14px; z-index: 2; height: 100%; position: absolute; -webkit-border-radius: 0px 0px 4px 4px; -moz-border-radius: 0px 0px 4px 4px; background: url(images/drop_down_bg.jpg); padding-left: 15px; padding-right: 15px; background-repeat: repeat; } jQuery for the drop down functionality jQuery(document).ready(function ($) { jQuery("ul.dropdown li").hover(function() { $('ul:first',this).css('visibility', 'visible'); }, function() { jQuery(this).removeClass("hover"); jQuery('ul:first',this).css('visibility', 'hidden'); }); }); My website http://wpvault.com/kahlam/ Considering it's 4am I've probably made a really stupid simple mistake. I apologise if I've missed anything.

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  • Get real height of div plus css generated content (if possible)

    - by qp2wd
    I'm trying to use javascript to give three divs a negative top position equal to their height. I've got it working, sort of (thanks to help from here!) but instead of calculating the height of each div and calculating the top position accordingly, each div is being assigned a negative top position of -367px: <script type="text/javascript"> $(document).ready(function() { //Get height of footer popup var pHeight = $('footer ul li > ul').outerHeight(); //Calculate new top position based on footer popup height var nHeight = pHeight + "px"; $('footer ul li > ul').css({ //Change top position to equal height of footer popup 'top' : "-" + nHeight }); }); </script> I've tried this using .height, .outerheight, and even .getheight which someone mentioned on the Jquery documentation for .height. I also tried using an each statement, though it didn't seem to work; I may have written it incorrectly. In addition (if possible), I'd like the negative position to take into account the height of a content being generated using the css :after psuedo-property, though I can always manually add that in to the calculation if javascript has no way to access that. EDIT: Added a test page link. It's the bottom divs I'm trying to target with JS, but if anyone has an idea regarding how to fix the problem with the top divs I'd be much obliged as well. http://www.qualityprinters2.com/test/float-tab-test.html

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  • Issue in alternate Row color using each() method of JQuery

    - by user1323981
    I have a table as under <table > <tr> <th scope="col">EmpId</th><th scope="col">EmpName</th> </tr> <tr> <td>1</td><td>ABC</td> </tr> <tr> <td>2</td><td>DEF</td> </tr> </table> I want to set the alternate row color of only the "td" elements of the table and not "th" by using only each() function. I have tried with <style type="text/css"> tr.even { background-color: green; } tr.odd { background-color: yellow; } </style> $(document).ready(function () { $('table > tbody').each(function () { $('tr:odd', this).addClass('odd').removeClass('even'); $('tr:even', this).addClass('even').removeClass('odd'); }); }); Though this works but it accepts also "th" element. How to avoid that? Please help Thanks

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  • using buttons to open webviews

    - by A-P
    hey guys im trying to make the buttons on my project to open a different webview url. Im new to ios programming, but im used to andriod programming. Is this possible? Ive a,ready created another webview view that sits in the supporting files folderHere is my code below Viewcontroller.m #import "ViewController.h" @implementation ViewController - (void)didReceiveMemoryWarning { [super didReceiveMemoryWarning]; // Release any cached data, images, etc that aren't in use. } #pragma mark - View lifecycle - (void)viewDidLoad { NSString *urlString = @"http://www.athletic-profile.com/Application"; //Create a URL object. NSURL *url = [NSURL URLWithString:urlString]; //URL Requst Object NSURLRequest *webRequest = [NSURLRequest requestWithURL:url]; //Load the request in the UIWebView. [webView loadRequest:webRequest]; [super viewDidLoad]; // Do any additional setup after loading the view, typically from a nib. } - (void)viewDidUnload { [super viewDidUnload]; // Release any retained subviews of the main view. // e.g. self.myOutlet = nil; } - (void)viewWillAppear:(BOOL)animated { [super viewWillAppear:animated]; } - (void)viewDidAppear:(BOOL)animated { [super viewDidAppear:animated]; } - (void)viewWillDisappear:(BOOL)animated { [super viewWillDisappear:animated]; } - (void)viewDidDisappear:(BOOL)animated { [super viewDidDisappear:animated]; } - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { // Return YES for supported orientations return (interfaceOrientation != UIInterfaceOrientationPortraitUpsideDown); } @synthesize webView; @end

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  • Issue with jQuery .submit()

    - by d.lanza38
    I'm having an issue submitting a form with the jquery .submit(); I don't have any elements on my page with a name of name="submit" or name="Submit", same goes for id's. My bit of jQuery code is as follows: $(document).ready(function () { $(document).on('click', "#appSubmit",function(e){ e.preventDefault(); var value = $("#time").val(); if(value == "--"){ $( "#err-time" ).dialog( "open" ); }else{ alert("1"); var dummy = $("#appSubmit").val(); alert(dummy); $("#appSubmit").submit(); alert("2"); } }); }); All of the alerts work properly, even the alert(dummy); prints out the correct value. The alert("2"); prints out, so it isn't even breaking on the $("#appSubmit").submit(); My submit button is <input type="submit" name="appSubmit" id="appSubmit" value="Apply"> Any thoughts would be appreciated, thanks.

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  • Drupal 7 - I can't pass post data in module function

    - by user2603290
    I can't pass post data in my custom module. filenames: mymodule.info mymodule.mod .info name = My Module description = My custom module. package = DEV version = 1.0 core = 7.x .module <?php function mymodule_menu() { $items = array(); $items['getcountries'] = array( 'title' => 'Get Countries', 'page callback' => 'getcountries', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); $items['getstates'] = array( 'title' => 'Get States', 'page callback' => 'getstates', 'access arguments' => array('access content'), 'type' => MENU_CALLBACK, ); return $items; } function getcountries() { $result = db_query("select distinct(country) from region"); $jsonarray = Array(); foreach ($result as $record) { $jsonarray[] = array( 'item' => $record->country, 'value' => $record->country ); } $json = json_encode($jsonarray); echo $json; } function getstates() { echo $_POST["test"]; } Ajax call $(document).ready(function(){ $.ajax({ url: '/getstates', type: 'POST', data: '{"test":"1"}', success : function () { alert('ok'); }, error : function (jqXHR, textStatus, errorThrown) { alert('error'); } }); }); The first item "getcountries" is working fine however the second one is not. I can browse to http://mysite.com/getstates ok but when I call this function using ajax it is not passing the value of "test" which is "1" to $_POST["test"]. I am new to Drupal so I am positive that I miss something here. I thought I need a new set of eyes.

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  • EDIT: I need to generate a string of 7 chars that is based on the id of the row.

    - by Totty
    EDIT: I need to generate a string of 7 chars that is based on the id of the row. So knowing the id of the image and a secret key, i should get the generated string. the string must contain chars from "a" to "z" and numbers from 0 to 9. I have a dir that contains photos like this dir/p3/i2/s21/thumb.jpg the generated string is p3i2s21, then is used to calculate the path of the image. EDIT: currently im using the id of the image: id = 55 then i modify and i get path = 000000055 then path = "000/000/055" then path = "000/000/055/thumb.jpg" ready to use! now i want something more clever because is easy to track down all the images from a server, because ids are sequencial: 1, 2, 3, 4, 5, 6... so i must think of creating from 55 a string that is 7 char length and will not overlap with other numbers. I can even transform the 55 to 0000055 and from this convert to a 7 char length string using a secret string. then when i got the secret string and the id i want to get back that 7 char length string. Is this possible? i was thinking about hases but they only uses 0-9 and a-e and are more chars.. :s

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