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  • How do I set Perl's @INC for a CGI script?

    - by pistacchio
    I have the follwing, simplest Perl CGI script: use strict; use warnings; use CGI(); use CGI::Carp qw(fatalsToBrowser); use Template; print CGI::header(); foreach(@INC) { print "$_\n"; } When called (http://[..]/cgi-bin/p.cgi) I am given the following error: Can't locate Template.pm in @INC (@INC contains: /usr/lib/perl5/site_perl/5.8.8/i386-linux-thread-multi /usr/lib/perl5/site_perl/5.8.8 /usr/lib/perl5/site_perl /usr/lib/perl5/vendor_perl/5.8.8/i386-linux-thread-multi /usr/lib/perl5/vendor_perl/5.8.8 /usr/lib/perl5/vendor_perl /usr/lib/perl5/5.8.8/i386-linux-thread-multi /usr/lib/perl5/5.8.8 .) at /home/pistacchio/webapps/htdocs/cgi-bin/p.cgi line 8. BEGIN failed--compilation aborted at /home/pistacchio/webapps/htdocs/cgi-bin/p.cgi line 8. I made sure that Template is installed and indeed when running this program from shell it works (loads Template) and outputs: Content-Type: text/html; charset=ISO-8859-1 /home/pistacchio/lib/perl5 /home/pistacchio/lib/perl5/lib/i386-linux-thread-multi /home/pistacchio/lib/perl5/lib /home/pistacchio/lib/perl5/lib/i386-linux-thread-multi /usr/lib/perl5/site_perl/5.8.8/i386-linux-thread-multi /usr/lib/perl5/site_perl/5.8.8 /usr/lib/perl5/site_perl /usr/lib/perl5/vendor_perl/5.8.8/i386-linux-thread-multi /usr/lib/perl5/vendor_perl/5.8.8 /usr/lib/perl5/vendor_perl /usr/lib/perl5/5.8.8/i386-linux-thread-multi /usr/lib/perl5/5.8.8 Template is installed in /home/pistacchio/lib/perl5/lib/i386-linux-thread-multi [pistacchio@web118 i386-linux-thread-multi]$ pwd /home/pistacchio/lib/perl5/lib/i386-linux-thread-multi [pistacchio@web118 i386-linux-thread-multi]$ ls auto perllocal.pod Template Template.pm This directory is correctly listed in env and, as previously posted, in @INC. In @INC it is shown twice, so I even tried to pop it out before calling use Template, but without result. From env: [pistacchio@web118 i386-linux-thread-multi]$ env [..] PERL5LIB=/home/pistacchio/lib/perl5:/home/pistacchio/lib/perl5/lib:/home/pistacchio/lib/perl5/lib/i386-linux-thread-multi [..] Removing use Template gets rid of the problem.

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  • How do I use Perl's LWP to log in to a web application?

    - by maxjackie
    I would like to write a script to login to a web application and then move to other parts of the application: use HTTP::Request::Common qw(POST); use LWP::UserAgent; use Data::Dumper; $ua = LWP::UserAgent->new(keep_alive=>1); my $req = POST "http://example.com:5002/index.php", [ user_name => 'username', user_password => "password", module => 'Users', action => 'Authenticate', return_module => 'Users', return_action => 'Login', ]; my $res = $ua->request($req); print Dumper(\$res); if ( $res->is_success ) { print $res->as_string; } When I try this code I am not able to login to the application. The HTTP status code returned is 302 that is found, but with no data. If I post username/password with all required things then it should return the home page of the application and keep the connection live to move other parts of the application.

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  • sqlite3 'database is locked' won't go away with retries

    - by Azarias
    I have a sqlite3 database that is accessed by a few threads (3-4). I am aware of the general limitations of sqlite3 with regards to concurrency as stated http://www.sqlite.org/faq.html#q6 , but I am convinced that is not the problem. All of the threads both read and write from this database. Whenever I do a write, I have the following construct: try: Cursor.execute(q, params) Connection.commit() except sqlite3.IntegrityError: Notify except sqlite3.OperationalError: print sys.exc_info() print("DATABASE LOCKED; sleeping for 3 seconds and trying again") time.sleep(3) Retry On some runs, I won't even hit this block, but when I do, it never comes out of it (keeps retrying, but I keep getting the 'database is locked' error from exc_info. If I understand the reader/writer lock usage correctly, some amount of waiting should help with the contention. What this sounds like is deadlock, but I do not use any transactions in my code, and every SELECT or INSERT is simply a one off. Some threads, however, keep the same connection when they do their operation (which includes a mix of SELECTS and INSERTS and other modifiers). I would appericiate it if you could shade a light on this, and also ways around fixing it (besides using a different database engine.)

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  • Recursive problem...

    - by Chronos
    Guys, I'm new to java and multithreading..... and I have a following problem: I have two classes running in two different threads. Class A and Class B. Class A has the method "onNewEvent()". Once that method is invoked, it will ask class B to do some work. As soon as B finishes the work it invokes onJobDone() method of the class A. Now... here comes the problem... what I want is to create new job within onJobDone() method and to send it again to B. here is what I do (pseudo code) ... in the sequence of execution A.onNewEvent(){ //create job //ask B to do it B.do() } B.do{ // Do some stuff A.jobDone() } A.onJobDOne(){ B.do() //doItAgain // print message "Thank you for doing it" } The problem is... that message "Thank you for doing it" never gets printed... in fact, when onJobDone() method is invoked, it invokes B.do()... because B.do() is very fast, it invokes onJobDone() immediatly... so execution flow never comes to PRINT MESSAGE part of code... I suppose this is one of the nasty multithreading problems.... any help would be appreciated.

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  • How to populate Range variable from a Sub/Function call?

    - by Ken Ingram
    I am trying to get this sub to work but the operationalRange variable is not being assigned. Despite the fact that the function selectBodyRow(bodyName) works fine. Sub sortRows(bodyName As String, ByRef wksht As Worksheet) Dim operationalRange As Range Set operationalRange = selectBodyRow(bodyName) Debug.Print "Sorting Worksheet: " & wksht.Name If Not operationalRange Is Nothing Then operationalRange.Select Debug.Print "Sorting " & operationalRange.Count & "Rows." ActiveWorkbook.Worksheets(wksht.Name).Sort.SortFields.Clear ActiveWorkbook.Worksheets(wksht.Name).Sort.SortFields.Add Key:=operationalRange, _ SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal ActiveWorkbook.Worksheets(wksht.Name).Sort.SortFields.Add Key:=operationalRange, _ SortOn:=xlSortOnValues, Order:=xlAscending, DataOption:=xlSortNormal With ActiveWorkbook.Worksheets(wksht.Name).Sort .SetRange operationalRange .Header = xlGuess .MatchCase = False .Orientation = xlTopToBottom .SortMethod = xlPinYin .Apply End With Else MsgBox "Body is not being Set" End If End Sub The Sub being called by the above Sub is: Function selectBodyRow(bodyName As String) As Range Dim rangeStart As String, rangeEnd As String Dim selectionStart As Range, selectionEnd As Range Dim result As Range, srchRng As Range, cngrs As Variant If bodyName = "WEST" Then rangeStart = "<-WEST START->" rangeEnd = "<-WEST END->" ElseIf bodyName = "EAST" Then rangeStart = "<-EAST START->" rangeEnd = "<-EAST END->" End If Set srchRng = Range("A:A") srchRng.Select Set selectionStart = srchRng.Find(What:=rangeStart, After:=ActiveCell, LookIn _ :=xlValues, LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:= _ xlNext, MatchCase:=False, SearchFormat:=False) Set selectionEnd = srchRng.Find(What:=rangeEnd, After:=ActiveCell, LookIn _ :=xlValues, LookAt:=xlPart, SearchOrder:=xlByRows, SearchDirection:= _ xlNext, MatchCase:=False, SearchFormat:=False) Set result = Range(selectionStart.Offset(1, 0), selectionEnd.Offset(-1, 0)) result.EntireRow.Select End Function

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  • forms problem in django 1.1

    - by alexarsh
    I have the following form: class ModuleItemForm2(forms.ModelForm): class Meta: model = Module_item fields = ('title', 'media', 'thumb', 'desc', 'default', 'player_option') The model is: class Module_item(models.Model): title = models.CharField(max_length=100) layout = models.CharField(max_length=5, choices=LAYOUTS_CHOICE) media = models.CharField(help_text='Media url', max_length=500, blank=True, null=True) conserv = models.ForeignKey(Conserv, help_text= 'Redirect to Conserv', blank=True, null=True) conserve_section = models.CharField(max_length=100, help_text= 'Section within the redirected Conserv', blank=True, null=True) parent = models.ForeignKey('self', help_text='Upper menu.', blank=True, null=True) module = models.ForeignKey(Module, blank=True, null=True) thumb = models.FileField(upload_to='sms/module_items/thumbs', blank=True, null=True) desc = models.CharField(max_length=500, blank=True, null=True) auto_play = models.IntegerField(help_text='Auto start play (miliseconds)', blank=True, null=True) order = models.IntegerField(help_text='Display order', blank=True, null=True) depth = models.IntegerField(help_text='The layout depth', blank=True, null=True) flow_replace = models.IntegerField(blank=True, null=True) default = models.IntegerField(help_text='The selected sub item (Note: Starting from 0)', blank=True, null=True) player_options = models.CharField(max_length=1000, null=True, blank=True) In my view I build form: module_item_form2 = ModuleItemForm2() print module_item_form2 And I get the following error on the print line: 'NoneType' object has no attribute 'label' It works fine with django 1.0.2. I see the error only in django 1.1. Do you have an idea what am I doing wrong? Regards, Arshavski Alexander.

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  • Flash - Http service bound to a button can be used only once ?

    - by SAKIROGLU Koray
    I have a flex project, in one of the screen of my UI, I create a HTTP service that call a "doGet" J2EE servlet through the GET method; and I bind the service call to a button. The service print log to system.out so I know when it is run. The problem I have is, when I click said button the first time, the servlets do what it is supposed to do, and print the stack to system.out, but if I click another time, nothing happens. Any idea what might be the cause ? Here's the flex code (code and service has been generated by Eclipse flex plugin) <mx:Script> <![CDATA[ protected function button_clickHandler(event:MouseEvent):void { LaunchSimulResult.token = simulation.LaunchSimul(); } ]]> </mx:Script> <mx:Canvas> ... <mx:Button label="Simulation" id="button" click="button_clickHandler(event)"/> .. </mx:Canvas> <mx:CallResponder id="LaunchSimulResult"/> <simulation:Simulation id="simulation" fault="Alert.show(event.fault.faultString + '\n' + event.fault.faultDetail)" showBusyCursor="true"/>

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  • Right way to return proxy model instance from a base model instance in Django ?

    - by sotangochips
    Say I have models: class Animal(models.Model): type = models.CharField(max_length=255) class Dog(Animal): def make_sound(self): print "Woof!" class Meta: proxy = True class Cat(Animal): def make_sound(self): print "Meow!" class Meta: proxy = True Let's say I want to do: animals = Animal.objects.all() for animal in animals: animal.make_sound() I want to get back a series of Woofs and Meows. Clearly, I could just define a make_sound in the original model that forks based on animal_type, but then every time I add a new animal type (imagine they're in different apps), I'd have to go in and edit that make_sound function. I'd rather just define proxy models and have them define the behavior themselves. From what I can tell, there's no way of returning mixed Cat or Dog instances, but I figured maybe I could define a "get_proxy_model" method on the main class that returns a cat or a dog model. Surely you could do this, and pass something like the primary key and then just do Cat.objects.get(pk = passed_in_primary_key). But that'd mean doing an extra query for data you already have which seems redundant. Is there any way to turn an animal into a cat or a dog instance in an efficient way? What's the right way to do what I want to achieve?

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  • How do I make this nested for loop, testing sums of cubes, more efficient?

    - by Brian J. Fink
    I'm trying to iterate through all the combinations of pairs of positive long integers in Java and testing the sum of their cubes to discover if it's a Fibonacci number. I'm currently doing this by using the value of the outer loop variable as the inner loop's upper limit, with the effect being that the outer loop runs a little slower each time. Initially it appeared to run very quickly--I was up to 10 digits within minutes. But now after 2 full days of continuous execution, I'm only somewhere in the middle range of 15 digits. At this rate it may end up taking a whole year just to finish running this program. The code for the program is below: import java.lang.*; import java.math.*; public class FindFib { public static void main(String args[]) { long uLimit=9223372036854775807L; //long maximum value BigDecimal PHI=new BigDecimal(1D+Math.sqrt(5D)/2D); //Golden Ratio for(long a=1;a<=uLimit;a++) //Outer Loop, 1 to maximum for(long b=1;b<=a;b++) //Inner Loop, 1 to current outer { //Cube the numbers and add BigDecimal c=BigDecimal.valueOf(a).pow(3).add(BigDecimal.valueOf(b).pow(3)); System.out.print(c+" "); //Output result //Upper and lower limits of interval for Mobius test: [c*PHI-1/c,c*PHI+1/c] BigDecimal d=c.multiply(PHI).subtract(BigDecimal.ONE.divide(c,BigDecimal.ROUND_HALF_UP)), e=c.multiply(PHI).add(BigDecimal.ONE.divide(c,BigDecimal.ROUND_HALF_UP)); //Mobius test: if integer in interval (floor values unequal) Fibonacci number! if (d.toBigInteger().compareTo(e.toBigInteger())!=0) System.out.println(); //Line feed else System.out.print("\r"); //Carriage return instead } //Display final message System.out.println("\rDone. "); } } Now the use of BigDecimal and BigInteger was delibrate; I need them to get the necessary precision. Is there anything other than my variable types that I could change to gain better efficiency?

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  • How can I change a form's input value with javascript

    - by Biroka
    How can I change a form's input value with javascript depending on witch combobox item is selected. I have a form with some imported values, and there is a field of witch imported value can be changed via a combobox. In my case: print("<input type='hidden' name='issue_array[{$issue["nr"]}][\"supplier\"]' value='{$issue["supplier"]}' />"); I have a combobox, that if I change it's value, should change the value of the input above. This is what I tried: print("<select name='supplier_combo' onchange='setSupplierInputValue(this.value, ${issue['nr']})'>"); and the script: echo "\r\n" . '<SCRIPT TYPE="text/javascript">' . "\r\n"; echo 'function setSupplierInputValue(value, issue_nr)' . "\r\n"; echo '{' . "\r\n"; echo ' issue_array[issue_nr]["supplier"] = value;'; echo '}' . "\r\n"; echo '</SCRIPT>'. "\r\n"; But it doesn't work, please help.

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  • urllib2.Request() with data returns empty url

    - by Mr. Polywhirl
    My main concern is the function: getUrlAndHtml() If I manually build and append the query to the end of the uri, I can get the response.url(), but if I pass a dictionary as the request data, the url does not come back. Is there anyway to guarantee the redirected url? In my example below, if thisWorks = True I get back a url, but the returned url is the request url as opposed to a redirect link. On a sidenote, the encoding for .E2.80.93 does not translate to - for some reason? #!/usr/bin/python import pprint import urllib import urllib2 from bs4 import BeautifulSoup from sys import argv URL = 'http://en.wikipedia.org/w/index.php?' def yesOrNo(boolVal): return 'yes' if boolVal else 'no' def getTitleFromRaw(page): return page.strip().replace(' ', '_') def getUrlAndHtml(title, printable=False): thisWorks = False if thisWorks: query = 'title={:s}&printable={:s}'.format(title, yesOrNo(printable)) opener = urllib2.build_opener() opener.addheaders = [('User-agent', 'Mozilla/5.0')] response = opener.open(URL + query) else: params = {'title':title,'printable':yesOrNo(printable)} data = urllib.urlencode(params) headers = {'User-agent':'Mozilla/5.0'}; request = urllib2.Request(URL, data, headers) response = urllib2.urlopen(request) return response.geturl(), response.read() def getSoup(html, name=None, attrs=None): soup = BeautifulSoup(html) if name is None: return None return soup.find(name, attrs) def setTitle(soup, newTitle): title = soup.find('div', {'id':'toctitle'}) h2 = title.find('h2') h2.contents[0].replaceWith('{:s} for {:s}'.format(h2.getText(), newTitle)) def updateLinks(soup, url): fragment = '#' for a in soup.findAll('a', href=True): a['href'] = a['href'].replace(fragment, url + fragment) def writeToFile(soup, filename='out.html', indentLevel=2): with open(filename, 'wt') as out: pp = pprint.PrettyPrinter(indent=indentLevel, stream=out) pp.pprint(soup) print('Wrote {:s} successfully.'.format(filename)) if __name__ == '__main__': def exitPgrm(): print('usage: {:s} "<PAGE>" <FILE>'.format(argv[0])) exit(0) if len(argv) == 2: help = argv[1] if help == '-h' or help == '--help': exitPgrm() if False:''' if not len(argv) == 3: exitPgrm() ''' page = 'Led Zeppelin' # argv[1] filename = 'test.html' # argv[2] title = getTitleFromRaw(page) url, html = getUrlAndHtml(title) soup = getSoup(html, 'div', {'id':'toc'}) setTitle(soup, page) updateLinks(soup, url) writeToFile(soup, filename)

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  • LuaEdit can't find module when Lua files all in the same folder

    - by joverboard
    I downloaded LuaEdit to use as an IDE and debug tool however I'm having trouble using it for even the simplest things. I've created a solution with 2 files in it, all of which are stored in the same folder. My files are as follows: --startup.lua require("foo") test("Testing", "testing", "one, two, three") --foo.lua foo = {} print("In foo.lua") function test(a,b,c) print(a,b,c) end This works fine when in my C++ compiler when accessed through some embed code, however when I attempt to use the same code in LuaEdit, it crashes on line 3 require("foo") with an error stating: module 'foo' not found: no field package.preload['foo'] no file 'C:\Program Files (x86)\LuaEdit 2010\lua\foo.lua' no file 'C:\Program Files (x86)\LuaEdit 2010\lua\foo\init.lua' no file 'C:\Program Files (x86)\LuaEdit 2010\foo.lua' no file 'C:\Program Files (x86)\LuaEdit 2010\foo\init.lua' no file '.\foo.lua' no file 'C:\Program Files (x86)\LuaEdit 2010\foo.dll' no file 'C:\Program Files (x86)\LuaEdit 2010\loadall.dll' no file '.\battle.dll' I have also tried creating these files prior to adding them to a solution and still get the same error. Is there some setting I'm missing? It would be great to have an IDE/debugger but it's useless to me if it can't run linked functions.

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  • PHP classes totally forgotten something today - sorry

    - by russp
    Hi guys, really sorry about being "totally thick today" but I have forgotten how to do something simple - too much time not in php recently. Want to use the OS phpapi How do I print out the individual rows - see told you I was being thick today // The fields we will be fetching. if (isset($_GET['test']) && $_GET['test'] == 'plaxo') { // plaxo is a PortableContacts end-point so doesn't know about the OpenSocial specific fields $profile_fields = array(); } else { $profile_fields = array( 'aboutMe', 'displayName', 'bodyType', 'currentLocation', 'drinker', 'happiestWhen', 'lookingFor' ); } // The number of friends to fetch. $friend_count = 2; $batch = $osapi->newBatch(); // Fetch the current user. $self_request_params = array( 'userId' => $userId, // Person we are fetching. 'groupId' => '@self', // @self for one person. 'fields' => $profile_fields // Which profile fields to request. ); $batch->add($osapi->people->get($self_request_params), 'self'); // Fetch the friends of the user $friends_request_params = array( 'userId' => $userId, // Person whose friends we are fetching. 'groupId' => '@friends', // @friends for the Friends group. 'fields' => $profile_fields, // Which profile fields to request. 'count' => $friend_count // Max friends to fetch. ); $batch->add($osapi->people->get($friends_request_params), 'friends'); // Get supportedFields Request $batch->add($osapi->people->getSupportedFields(), 'supportedFields'); // Send the batch request. $result = $batch->execute(); Say I wanted to print out "aboutMe", whats the echo? cos echo $result['aboutMe'] doesn't work.

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  • How to count the Chinese word in a file using regex in perl?

    - by Ivan
    I tried following perl code to count the Chinese word of a file, it seems working but not get the right thing. Any help is greatly appreciated. The Error message is Use of uninitialized value $valid in concatenation (.) or string at word_counting.pl line 21, <FILE> line 21. Total things = 125, valid words = which seems to me the problem is the file format. The "total thing" is 125 that is the string number (125 lines). The strangest part is my console displayed all the individual Chinese words correctly without any problem. The utf-8 pragma is installed. #!/usr/bin/perl -w use strict; use utf8; use Encode qw(encode); use Encode::HanExtra; my $input_file = "sample_file.txt"; my ($total, $valid); my %count; open (FILE, "< $input_file") or die "Can't open $input_file: $!"; while (<FILE>) { foreach (split) { #break $_ into words, assign each to $_ in turn $total++; next if /\W|^\d+/; #strange words skip the remainder of the loop $valid++; $count{$_}++; # count each separate word stored in a hash ## next comes here ## } } print "Total things = $total, valid words = $valid\n"; foreach my $word (sort keys %count) { print "$word \t was seen \t $count{$word} \t times.\n"; } ##---Data---- sample_file.txt ??????,???????,????.??????.????:"?????????????,??????,????????.????????,?????????, ???????????.????????,???????????,??????,??????.???:`??,???????????.'?????, ??????????."??????,??????.????.???, ????????????,????,??????,?????????,??????????????. ????????,??????,???????????,????????,????????.????,????,???????, ??????????,??????,????????.??????.

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  • Python unicode search not giving correct answer

    - by user1318912
    I am trying to search hindi words contained one line per file in file-1 and find them in lines in file-2. I have to print the line numbers with the number of words found. This is the code: import codecs hypernyms = codecs.open("hindi_hypernym.txt", "r", "utf-8").readlines() words = codecs.open("hypernyms_en2hi.txt", "r", "utf-8").readlines() count_arr = [] for counter, line in enumerate(hypernyms): count_arr.append(0) for word in words: if line.find(word) >=0: count_arr[counter] +=1 for iterator, count in enumerate(count_arr): if count>0: print iterator, ' ', count This is finding some words, but ignoring some others The input files are: File-1: ???? ??????? File-2: ???????, ????-???? ?????-???, ?????-???, ?????_???, ?????_??? ????_????, ????-????, ???????_???? ????-???? This gives output: 0 1 3 1 Clearly, it is ignoring ??????? and searching for ???? only. I have tried with other inputs as well. It only searches for one word. Any idea how to correct this?

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  • 'C++ object destroyed' in QComboBox descendant editor in delegate

    - by Max
    Hi, all! I have modified combobox to hold colors, using QtColorCombo (http://qt.nokia.com/products/appdev/add-on-products/catalog/4/Widgets/qtcolorcombobox) as howto for the 'more...' button implementation details. It works fine in C++ and in PyQt on linux, but I get 'underlying C++ object was destroyed' when use this control in PyQt on Windows. It seels like the error happens when: ... # in constructor: self.activated.connect(self._emitActivatedColor) ... def _emitActivatedColor(self, index): if self._colorDialogEnabled and index == self.colorCount(): print '!!!!!!!!! QtGui.QColorDialog.getColor()' c = QtGui.QColorDialog.getColor() # <----- :( delegate fires 'closeEditor' print '!!!!!!!!! ' + c.name() if c.isValid(): self._numUserColors += 1 #at the next line currentColor() tries to access C++ layer and fails self.addColor(c, self.currentColor().name()) self.setCurrentIndex(index) ... Maybe console output will help. I've overridden event() in editor and got: ... MouseButtonRelease FocusOut Leave Paint Enter Leave FocusIn !!!!!!!!! QtGui.QColorDialog.getColor() WindowBlocked Paint WindowDeactivate !!!!!!!!! 'CloseEditor' fires! Hide HideToParent FocusOut DeferredDelete !!!!!!!!! #6e6eff ... Can someone explain, why there is such a different behaviour in the different environments, and maybe give a workaround to fix this. Here is minimal example: http://docs.google.com/Doc?docid=0Aa0otNVdbWrrZDdxYnF3NV80Y20yam1nZHM&hl=en

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  • Using $this when not in object context--i am using the latest version of php and mysql

    - by user309381
    This is user.php: include("databse.php");//retrieving successfully first name and lastname from databse file into user.php class user { public $first_name; public $last_name; public static function full_name() { if(isset($this->first_name) && isset($this->last_name)) { return $this->first_name . " " . $this->last_name; } else { return ""; } } } ?> Other php file, index.php: <?php include(databse.php); include(user.php); $record = user::find_by_id(1); $object = new user(); $object->id = $record['id']; $object->username = $record['username']; $object->password = $record['password']; $object->first_name = $record['first_name']; $object->last_name = $record['last_name']; // echo $object->full_name(); echo $object->id;// successfully print the id echo $object->username;//success fully print the username echo->$object->full_name();//**ERROR:Using $this when not in object context** ?>

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  • Most efficient way to write over file after reading

    - by Ryan McClure
    I'm reading in some data from a file, manipulating it, and then overwriting it to the same file. Until now, I've been doing it like so: open (my $inFile, $file) or die "Could not open $file: $!"; $retString .= join ('', <$inFile>); ... close ($inFile); open (my $outFile, $file) or die "Could not open $file: $!"; print $outFile, $retString; close ($inFile); However I realized I can just use the truncate function and open the file for read/write: open (my $inFile, '+<', $file) or die "Could not open $file: $!"; $retString .= join ('', <$inFile>); ... truncate $inFile, 0; print $inFile $retString; close ($inFile); I don't see any examples of this anywhere. It seems to work well, but am I doing it correctly? Is there a better way to do this?

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  • Basic PHP OOPS Query

    - by appu
    Ok. I am starting out OOPS in PHP. Created a couple of classes: customer(parent) and sales(child) class that inherits from parent class. Created another testcustomer.php in which a new sales object is created however the salesprint() function defined in the sales class does not echo out customer's name though it is set to be "Jane" in the class.customer.php(parent). My thinking is that when sales class extends customer class PHP automatically includes all the code from class.customer.php to sales.customer.php and therefore the constructor in parent class set $name to "Jane". Here is the code: class.customer.php <?php class customer{ private $name; private $cust_no; public function __construct($customerid) { $this->name = 'Jane'; $this->cust_no = $customerid; } } ?> class.sales.php <?php require_once('class.customer.php'); class sales extends customer{ public function salesprint($customerid) { echo "Hello $this->name this is a print of your purchased products"; } } ?> testcustomer.php require_once('class.sales.php'); $objsales = new sales(17); $objsales->salesprint(17); ?> The Output I get Hello this is a print of your purchased products. What am i doing wrong ? thanks romesh

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  • Secure Copy File from remote server via scp and os module in Python

    - by user1063572
    I'm pretty new to Python and programming. I'm trying to copy a file between two computers via a python script. However the code os.system("ssh " + hostname + " scp " + filepath + " " + user + "@" + localhost + ":" cwd) won't work. I think it needs a password, as descriped in How do I copy a file to a remote server in python using scp or ssh?. I didn't get any error logs, the file just won't show in my current working directory. However every other command with os.system("ssh " + hostname + "command") or os.popen("ssh " + hostname + "command") does work. - command = e.g. ls When I try ssh hostname scp file user@local:directory in the commandline it works without entering a password. I tried to combine os.popen commands with getpass and pxssh module to establish a ssh connection to the remote server and use it to send commands directly (I only tested it for an easy command): import pxssh import getpass ssh = pxssh.pxssh() ssh.force_password = True hostname = raw_input("Hostname: ") user = raw_input("Username: ") password = getpass.getpass("Password: ") ssh.login(hostname, user, password) test = os.popen("hostname") print test But I'm not able to put commands through to the remote server (print test shows, that hostname = local and not the remote server), however I'm sure, the conection is established. I thought it would be easier to establish a connection than always use "ssh " + hostname in the bash commands. I also tried some of the workarounds in How do I copy a file to a remote server in python using scp or ssh?, but I must admit due to lack of expirience I didn't get them to work. Thanks a lot for helping me.

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  • jQuery replaceWith(data) is not correctly doing his job

    - by Tristan
    Hello, i did a small ajax div refresh, but instead of replacing the values with the new ones, jquery adds the new data before the old ones. What possibily causes that please ? <script type="text/javascript"> $(document).ready(function(){ $('#AJAX').click(function(e){ e.preventDefault(); var hebergeur = $('#hebergeurJQUERY').val(); $.post("/statistiques/maj-bloc-commentaires.php", { hebergeur : hebergeur }, function(data){ // déclenchée seulement si succès $("#TOREPLACE").replaceWith(data).val( ); }); }); }); </script> The HTML : print '<div id="a_remplacer"> <div class="detail_commentaires"> <table class="tableau_detail_commentaires"> <tr> <td class="tab_space">Serveur <strong>'.$row['type'].'</strong></td> <td>Qualite</td> <td style="color:'.$c_vote.'">'.htmlentities($row['vote']).'</td> </tr> </div> </div> The PHP ajax echo : print '<div id="a_remplacer"><div class="detail_commentaires" > <table class="tableau_detail_commentaires"> <tr> <td class="tab_space">Serveur <strong>'.$row['type'].'</strong></td> <td>Qualite</td> <td style="color:'.$c_vote.'">'.htmlentities($row['vote']).'</td> </tr></div></div> Thanks

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  • Create static instances of a class inside said class in Python

    - by Samir Talwar
    Apologies if I've got the terminology wrong here—I can't think what this particular idiom would be called. I've been trying to create a Python 3 class that statically declares instances of itself inside itself—sort of like an enum would work. Here's a simplified version of the code I wrote: class Test: A = Test("A") B = Test("B") def __init__(self, value): self.value = value def __str__(self): return "Test: " + self.value print(str(Test.A)) print(str(Test.B)) Writing this, I got an exception on line 2 (A = Test("A")). I assume line 3 would also error if it had made it that far. Using __class__ instead of Test gives the same error. File "<stdin>", line 1, in <module> File "<stdin>", line 2, in Test NameError: name 'Test' is not defined Is there any way to refer to the current class in a static context in Python? I could declare these particular variables outside the class or in a separate class, but for clarity's sake, I'd rather not if I can help it. To better demonstrate what I'm trying to do, here's the same example in Java: public class Test { private static final Test A = new Test("A"); private static final Test B = new Test("B"); private final String value; public Test(String value) { this.value = value; } public String toString() { return "Test: " + value; } public static void main(String[] args) { System.out.println(A); System.out.println(B); } } This works as you would expect: it prints: Test: A Test: B How can I do the same thing in Python?

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  • Piping EOF problems with stdio and C++/Python

    - by yeus
    I got some problems with EOF and stdio. I have no idea what I am doing wrong. When I see an EOF in my program I clear the stdin and next round I try to read in a new line. The problem is: for some reason the getline function immediatly (from the second run always, the first works just as intended) returns an EOF instead of waiting for a new input from py python process... Any idea? alright Here is the code: #include <string> #include <iostream> #include <iomanip> #include <limits> using namespace std; int main(int argc, char **argv) { for (;;) { string buf; if (getline(cin,buf)) { if (buf=="q") break; /*****///do some stuff with input //my actual filter program cout<<buf; /*****/ } else { if ((cin.rdstate() & istream::eofbit)!=0)cout<<"eofbit"<<endl; if ((cin.rdstate() & istream::failbit)!=0)cout<<"failbit"<<endl; if ((cin.rdstate() & istream::badbit)!=0)cout<<"badbit"<<endl; if ((cin.rdstate() & istream::goodbit)!=0)cout<<"goodbit"<<endl; cin.clear(); cin.ignore(numeric_limits<streamsize>::max()); //break;//I am not using break, because I //want more input when the parent //process puts data into stdin; } } return 0; } and in python: from subprocess import Popen, PIPE import os from time import sleep proc=Popen(os.getcwd()+"/Pipingtest",stdout=PIPE,stdin=PIPE,stderr=PIPE); while(1): sleep(0.5) print proc.communicate("1 1 1") print "running"

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  • LLVM: Passing a pointer to a struct, which holds a pointer to a function, to a JIT function

    - by Rusky
    I have an LLVM (version 2.7) module with a function that takes a pointer to a struct. That struct contains a function pointer to a C++ function. The module function is going to be JIT-compiled, and I need to build that struct in C++ using the LLVM API. I can't seem get the pointer to the function as an LLVM value, let alone pass a pointer to the ConstantStruct that I can't build. I'm not sure if I'm even on the track, but this is what I have so far: void print(char*); vector<Constant*> functions; functions.push_back(ConstantExpr::getIntToPtr( ConstantInt::get(Type::getInt32Ty(context), (int)print), /* function pointer type here, FunctionType::get(...) doesn't seem to work */ )); ConstantStruct* struct = cast<ConstantStruct>(ConstantStruct::get( cast<StructType>(m->getTypeByName("printer")), functions )); Function* main = m->getFunction("main"); vector<GenericValue> args; args[0].PointerVal = /* not sure what goes here */ ee->runFunction(main, args);

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  • why does cx_oracle execute() not like my string now?

    - by Frank Stallone
    I've downloaded cx_oracle some time ago and wrote a script to convert data to XML. I've had to reisntall my OS and grabbed the latest version of cx_Oracle (5.0.3) and all of the sudden my code is broken. The first thing was that cx_Oracle.connect wanted unicode rather string for the username and password, that was very easy to fix. But now it keeps failing on the cursor.execute and tells me my string is not a string even when type() tells me it is a string. Here is a test script I initally used ages ago and worked fine on my old version but does not work on cx_Oracle now. import cx_Oracle ip = 'url.to.oracle' port = 1521 SID = 'mysid' dsn_tns = cx_Oracle.makedsn(ip, port, SID) connection = cx_Oracle.connect(u'name', u'pass', dsn_tns) cursor = connection.cursor() cursor.arraysize = 50 sql = "select isbn, title_code from core_isbn where rownum<=20" print type(sql) cursor.execute(sql) for isbn, title_code in cursor.fetchall(): print "Values from DB:", isbn, title_code cursor.close() connection.close() When I run that I get: Traceback (most recent call last): File "C:\NetBeansProjects\Python\src\db_temp.py", line 48, in cursor.execute(sql) TypeError: expecting None or a string Does anyone know what I may be doing wrong?

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