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  • Word 2007 COM - Can't directly access a page when word is set to invisible

    - by Robbie
    I'm using Word 2007 via COM from PHP 5.2 Apache 2.0 on a windows machine. The goal is to programmatically render jpeg thumbnails from each page in a Word document. The following code works correctly if you set $word-Visible to 1: try { $word = new COM('word.application'); $word->Visible = 0; $word->Documents->Open("C:\\test.doc"); echo "Number of pages: " . $word->ActiveDocument->ActiveWindow->ActivePane->Pages->Count() . "</br>"; $i = 1; foreach ($word->ActiveDocument->ActiveWindow->ActivePane->Pages as $page) { echo "Page number: $i </br>"; $i++; } //get the EMF image of the page $data = $word->ActiveDocument->ActiveWindow->ActivePane->Pages->Item(3)->EnhMetaFileBits; $word->ActiveDocument->Close(); $word->Quit(); } catch (Exception $e) { echo "Exception: " .$e->getMessage(); } The test document I'm using contains 35 pages. The code will display the correct number of pages but the for each loop only loops over 1 page. I can only directly access page 1 and 2 in the Pages-Item() collection. If I try to access another page I get the exception: "The requested member of the collection does not exist." If I set the $word-Visible property to 1 I do get all the pages in the foreach loop and I can access any page directly. Everything is working as expected if Word is set to be visible. Even stranger is the fact that if I set Word to be invisible and I don't have the foreach loop I can only access page 1 instead of page 1 and 2 if I do the for each loop. Any pointers on how I can access all the pages in the document and keeping word invisible?

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  • django: grouping in an order_by query?

    - by AP257
    Hi all, I want to allocate rankings to users, based on a points field. Easy enough you'd think with an order_by query. But how do I deal with the situation where two users have the same number of points and need to share the same ranking? Should I use annotate to find users with the same number of points? My current code, and a pseudocode description of what I'd like to do, are below. top_users = User.objects.filter(problem_user=False).order_by('-points_total') # Wrong - in pseudocode, this should be # Get the highest points_total, find all the users with that points_total, # if there is more than one user, set status to 'Joint first prize', # otherwise set status to 'First prize' top_users[0].status = "First prize" if (top_users[1]): top_users[1].status = "Second prize" if (top_users[2]): top_users[2].status = "Third prize" if (top_users[3]): top_users[3:].status = "Highly commended" The code above doesn't deal with the situation where two users have the same number of points and need to share second prize. I guess I need to create a query that looks for unique values of points_total, and does some kind of nested ranking? It also doesn't cope with the fact that sometimes there are fewer than 4 users - does anyone know how I can do (in pseudocode) 'if top_users[1] is not null...' in Python?

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  • Converting a PHP associative array to a JSON associative array

    - by Extrakun
    I am converting a look-up table in PHP which looks like this to JavaScript using json_encode: AbilitiesLookup Object ( [abilities:private] => Array ( [1] => Ability_MeleeAttack Object ( [abilityid:protected] => [range:protected] => 1 [name:protected] => MeleeAttack [ability_identifier:protected] => MeleeAttack [aoe_row:protected] => 1 [aoe_col:protected] => 1 [aoe_shape:protected] => [cooldown:protected] => 0 [focusCost:protected] => 0 [possibleFactions:protected] => 2 [abilityDesc:protected] => Basic Attack ) .....snipped... And in JSON, it is: {"1":{"name":"MeleeAttack","fof":"2","range":"1","aoe":[null,"1","1"],"fp":"0","image":"dummy.jpg"},.... The problem is I get a JS object, not an array, and the identifier is a number. I see 2 ways around this problem - either find a way to access the JSON using a number (which I do not know how) or make it such that json_encode (or some other custom encoding functions) can give a JavaScript associative array. (Yes, I am rather lacking in my JavaScript department). Note: The JSON output doesn't match the array - this is because I do a manual json encoding for each element in the subscript, before pushing it onto an array (with the index as the key), then using json_encode on it. To be clear, the number are not sequential because it's an associative array (which is why the JSON output is not an array).

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  • Oracle Data Provider and casting

    - by mrjoltcola
    I use Oracle's specific data provider, not the Microsoft provider that is being discontinued. The thing I've found about ODP.NET is how picky it is with data types. Where JDBC and other ADO providers just convert and make things work, ODP.NET will throw an invalid cast exception unless you get it exactly right. Consider this code: String strSQL = "SELECT DOCUMENT_SEQ.NEXTVAL FROM DUAL"; OracleCommand cmd = new OracleCommand(strSQL, conn); reader = cmd.ExecuteReader(); if (reader != null && reader.Read()) { Int64 id = reader.GetInt64(0); return id; } Due to ODP.NET's pickiness on conversion, this doesn't work. My usual options are: 1) Retrieve into a Decimal and return it with a cast to an Int64 (I don't like this because Decimal is just overkill, and at least once I remember reading it was deprecated...) Decimal id = reader.GetDecimal(0); return (Int64)id; 2) Or cast in the SQL statement to make sure it fits into Int64, like NUMBER(18) String strSQL = "SELECT CAST(DOCUMENT_SEQ.NEXTVAL AS NUMBER(18)) FROM DUAL"; I do (2), because I feel its just not clean pulling a number into a .NET Decimal when my domain types are Int32 or Int64. Other providers I've used are nice (smart) enough to do the conversion on the fly. Any suggestions from the ODP.NET gurus?

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  • GRAPH PROBLEM: find an algorithm to determine the shortest path from one point to another in a recta

    - by newba
    I'm getting such an headache trying to elaborate an appropriate algorithm to go from a START position to a EXIT position in a maze. For what is worth, the maze is rectangular, maxsize 500x500 and, in theory, is resolvable by DFS with some branch and bound techniques ... 10 3 4 7 6 3 3 1 2 2 1 0 2 2 2 4 2 2 5 2 2 1 3 0 2 2 2 2 1 3 3 4 2 3 4 4 3 1 1 3 1 2 2 4 2 2 1 Output: 5 1 4 2 Explanation: Our agent looses energy every time he gives a step and he can only move UP, DOWN, LEFT and RIGHT. Also, if the agent arrives with a remaining energy of zero or less, he dies, so we print something like "Impossible". So, in the input 10 is the initial agent's energy, 3 4 is the START position (i.e. column 3, line 4) and we have a maze 7x6. Think this as a kind of labyrinth, in which I want to find the exit that gives the agent a better remaining energy (shortest path). In case there are paths which lead to the same remaining energy, we choose the one which has the small number of steps, of course. I need to know if a DFS to a maze 500x500 in the worst case is feasible with these limitations and how to do it, storing the remaining energy in each step and the number of steps taken so far. The output means the agent arrived with remaining energy= 5 to the exit pos 1 4 in 2 steps. If we look carefully, in this maze it's also possible to exit at pos 3 1 (column 3, row 1) with the same energy but with 3 steps, so we choose the better one. With these in mind, can someone help me some code or pseudo-code? I have troubles working this around with a 2D array and how to store the remaining energy, the path (or number of steps taken)....

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  • Average performance of binary search algorithm?

    - by Passionate Learner
    http://en.wikipedia.org/wiki/Binary_search_algorithm#Average_performance BinarySearch(int A[], int value, int low, int high) { int mid; if (high < low) return -1; mid = (low + high) / 2; if (A[mid] > value) return BinarySearch(A, value, low, mid-1); else if (A[mid] < value) return BinarySearch(A, value, mid+1, high); else return mid; } If the integer I'm trying to find is always in the array, can anyone help me write a program that can calculate the average performance of binary search algorithm? I know I can do this by actually running the program and counting the number of calls, but what I'm trying to do here is to do it without calling the function. I'm not asking for a time complexity, I'm trying to calculate the average number of calls. For example, the average number of calls to find a integer in A[2], it would be 1.67 (5/3).

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  • XSLT Global count of grouped items

    - by Chris
    Hi there, I have a set of items which i am grouping using the muenchian method using keys. This is working great however when i try to do things with the first x number of items it is doing it on the x number of items in each group rather than across the whole set of results. How would i get the individual position of each item accross the whole collection? <xsl:key name="pictures-by-productid" match="/dsQueryResponse/Rows/Row" use="@ProductId" /> <xsl:template match="/"> <div style="border:1px solid red; float:left;"> <xsl:apply-templates select="/" mode="sub"> </xsl:apply-templates> </div> </xsl:template> and the second template <xsl:template match="/" mode="sub"> <xsl:for-each select="/dsQueryResponse/Rows/Row[count(. | key('pictures-by-productid', @ProductId)[1]) = 1]"> <xsl:for-each select="key('pictures-by-productid', @ProductId)"> <xsl:sort select="@PictureType" /> <div style="float:left; margin:2px;"> <img src="{@ThumbNailUrl}" width="58" /> <br /> Download <xsl:number value="position()" format="1. " /> <xsl:value-of select="." /> </div> </xsl:for-each> </xsl:for-each> </xsl:template> Thanks Chris

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  • Porting an IBXpress Interbase 6 app to the current Firebird platform, on Delphi 7?

    - by robsoft
    Just wondering if there are any gotchas to be wary of here. We have a legacy D7 app that we developed several years ago for a client, which uses IBXpress to talk to the open source Interbase 6 build. We're having a number of issues with that platform these days (very slow to connect/start-up on new hardware being the chief one) and the client has okayed spending some time/money moving the database over to Firebird. We really DON'T want to embark upon moving it to D2010 (or D2007 which would be my preference right now) as we figure that we might have to move the database layer from IBXpress to something else to best suit Firebird anyway. And at the end of the day, the client is only looking to lessen the database pain, not overhaul/upgrade/rewrite the app. Given the ancestry of Firebird, is it a fairly painless, well-understood path from IBXpress Interbase 6 to (whatever) with Firebird? We have quite a number of sprocs, triggers (and even datatypes) etc in the existing IB database already (and the client has a number of paying customers all using this platform) so we felt that going to Firebird was more likely to be a smoother move than moving to SQL Express (or another flavour of DB entirely). Note that we're not looking for 'embedded' DB advocacy - in many of our client's customers' installations, the software is used in a multi-user client-server way so keeping that kind of approach is important.

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  • How to change one Button background in a gridview? -- Android

    - by Tstop Studios
    I have a GridView with 16 ImageView buttons. My program makes a random number and when the user clicks a button in the gridview, i want it to take the random number (0-15) and set the background of the tile with the same position as the random number (0-15) to a different image. How can I just change one of the buttons background? Here's my code so far: public class ButtonHider extends Activity { Random random = new Random(); int pos; @Override protected void onCreate(Bundle savedInstanceState) { // TODO Auto-generated method stub super.onCreate(savedInstanceState); setContentView(R.layout.button_hider); pos = random.nextInt(15); GridView gridview = (GridView) findViewById(R.id.gvBH); gridview.setAdapter(new ImageAdapter(this)); gridview.setOnItemClickListener(new OnItemClickListener() { public void onItemClick(AdapterView<?> parent, View v, int position, long id) { pos = random.nextInt(16); if (position == pos) { Toast.makeText(ButtonHider.this, "Found Me!", Toast.LENGTH_SHORT).show(); } else { Toast.makeText(ButtonHider.this, "Try Again!!", Toast.LENGTH_SHORT).show(); } } }); } public class ImageAdapter extends BaseAdapter { private Context mContext; public ImageAdapter(Context c) { mContext = c; } public int getCount() { return 16; } public Object getItem(int position) { return null; } public long getItemId(int position) { return 0; } // create a new ImageView for each item referenced by the Adapter public View getView(int position, View convertView, ViewGroup parent) { ImageView imageView; if (convertView == null) { // if it's not recycled, initialize some // attributes imageView = new ImageView(mContext); imageView.setLayoutParams(new GridView.LayoutParams(100, 100)); imageView.setScaleType(ImageView.ScaleType.CENTER_CROP); imageView.setPadding(15, 15, 15, 15); } else { imageView = (ImageView) convertView; } imageView.setImageResource(R.drawable.bh_b); return imageView; } } }

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  • Can I build this XPath query dynamically in XSLT?

    - by Martin Doms
    I have a document that looks something like <root> <element> <subelement1 /> <subelement2 /> </element> <element> <subelement2 /> <subelement1 /> </element> </root> In my XSLT sheet in the context of /element[2]/[someNode] I want to get a number that represents the distance of /element[1]/[someNode] (ie, the number of preceding siblings of /element1/[someNode]). For example, in the context of /element[2]/subelement1 I'd like to have some way to get the number 2, the distance from /element[1] to /element[1]/subelement2. I only ever need the distance of the given node name from the first instance of . Intuitively I thought I could construct this like <xsl:variable name="nodename" select="name()" /> <xsl:value-of select="/element[1]/$nodename/preceding-sibling::*" /> but unfortunately this sheet doesn't compile. Is what I'm trying to achieve possible in XSLT?

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  • Advice welcomed on creating my own Swing component

    - by Toto
    Recently I asked which was the best Swing component to bind to a BigDecimal variable (with some particular editing properties). It turns out that none of the standard Swing components suit me completely, nor did the third-party Swing component libraries I've found out there. So I’ve decided to create my own Swing component. Component description: I want to extend JTextField or JFormattedTextField, so my new component can be easily bound to a BigDecimal variable. The component will have customizable scale and length properties. Behavior: When the component is drawn, it shows only the decimal point and space for scale digits to its right. When the component receives focus the caret should be positioned left to the decimal point. As the user types numbers (any other character is ignored) they appear to the left of the caret, only length – scale numbers are accepted, any other number typed is ignored as the integer portion is full. Any time the user types the decimal point the caret moves to the right side of the decimal point. The following numbers typed are shown in the decimal part, only scale numbers are considered any other number typed is ignored as the decimal portion is full. Additionally, thousand separators should appear as the user types numbers left to the decimal point. Invoking a getValue() method on the component should yield the BigDecimal representing the number just entered. I’ve never created my own Swing component; I’ve barely used the standard ones. So I would appreciate any good tutorial/info/tip on creating the component described. This is the only thing I've got so far. Thanks in advance.

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  • PHP - Database schema: version control, branching, migrations.

    - by Billiam
    I'm trying to come up with (or find) a reusable system for database schema versioning in php projects. There are a number of Rails-style migration projects available for php. http://code.google.com/p/mysql-php-migrations/ is a good example. It uses timestamps for migration files, which helps with conflicts between branches. General problem with this kind of system: When development branch A is checked out, and you want to check out branch B instead, B may have new migration files. This is fine, migrating to newer content is straight forward. If branch A has newer migration files, you would need to migrate downwards to the nearest shared patch. If branch A and B have significantly different code bases, you may have to migrate down even further. This may mean: Check out B, determine shared patch number, check out A, migrate downwards to this patch. This must be done from A since the actual applied patches are not available in B. Then, checkout branch B, and migrate to newest B patch. Reverse process again when going from B to A. Proposed system: When migrating upwards, instead of just storing the patch version, serialize the whole patch in database for later use, though I'd probably only need the down() method. When changing branches, compare patches that have been run to patches that are available in the destination branch. Determine nearest shared patch (or oldest difference, maybe) between db table of run patches and patches in destination branch by ID or hash. Could also look for new or missing patches that are buried under a number of shared patches between the two branches. Automatically merge down to the nearest shared patch, using the db table stored down() methods, and then merge up to the branche's latest patch. My question is: Is this system too crazy and/or fraught with consequences to bother developing? My experience with database schema versioning is limited to PHP autopatch, which is an up()-only system requiring filenames with sequential IDs.

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  • Readability and IF-block brackets: best practice

    - by MasterPeter
    I am preparing a short tutorial for level 1 uni students learning JavaScript basics. The task is to validate a phone number. The number must not contain non-digits and must be 14 digits long or less. The following code excerpt is what I came up with and I would like to make it as readable as possible. if ( //set of rules for invalid phone number phoneNumber.length == 0 //empty || phoneNumber.length > 14 //too long || /\D/.test(phoneNumber) //contains non-digits ) { setMessageText(invalid); } else { setMessageText(valid); } A simple question I can not quite answer myself and would like to hear your opinions on: How to position the surrounding (outermost) brackets? It's hard to see the difference between a normal and a curly bracket. Do you usually put the last ) on the same line as the last condition? Do you keep the first opening ( on a line by itself? Do you wrap each individual sub-condition in brackets too? Do you align horizontally the first ( with the last ), or do you place the last ) in the same column as the if? Do you keep ) { on a separate line or you place the last ) on the same line with the last sub-condition and then place the opening { on a new line? Or do you just put the ) { on the same line as the last sub-condition? Community wiki. EDIT Please only post opinions regarding the usage and placement of brackets. The code needs not be re-factored. This is for people who have only been introduced to JavaScript a couple of weeks ago. I am not asking for opinions how to write the code so it's shorter or performs better. I would only like to know how do you place brackets around IF-conditions.

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  • How CPU finds ISR and distinguishes between devices

    - by ripunjay-tripathi-gmail-com
    I should first share all what I know - and that is complete chaos. There are several different questions on the topic, so please don't get irritated :). 1) To find an ISR, CPU is provided with a interrupt number. In x86 machines (286/386 and above) there is a IVT with ISRs in it; each entry of 4 bytes in size. So we need to multiply interrupt number by 4 to find the ISR. So first bunch of questions is - I am completely confused in mechanism of CPU receiving the interrupt. To raise an interrupt, firstly device shall probe for IRQ - then what ? The interrupt number travels "on IRQ" towards CPU? I also read something like device putting ISR address on data bus ; whats that then ? What is the concept of devices overriding the ISR. Can somebody tell me few example devices where CPU polls for interrupts? And where does it finds ISR for them ? 2) If two devices share an IRQ (which is very much possible), how does CPU differs amongst them ? What if both devices raise an interrupt of same priority simultaneously. I got to know there will be masking of same type and low priority interrupts - but how this communication happens between CPU and device controller? I studied the role of PIC and APIC for this problem, but could not understand. Thanks for reading. Thank you very much for answering.

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  • event flow in action script 3

    - by Shay
    i try to dispatch a custom event from some component on the stage and i register other component to listen to it but the other component doesn't get the event here is my code what do i miss public class Main extends MovieClip //main document class { var compSource:Game; var compMenu:Menu; public function Main() { compSource = new Game; compMenu = new Menu(); var mc:MovieClip = new MovieClip(); addChild(mc); mc.addChild(compSource); // the source of the event - event dispatch when clicked btn mc.addChild(compMenu); //in init of that Movie clip it add listener to the compSource events } } public class Game extends MovieClip { public function Game() { btn.addEventListener(MouseEvent.CLICK, onFinishGame); } private function onFinishGame(e:MouseEvent):void { var score:Number = Math.random() * 100 + 1; dispatchEvent(new ScoreChanged(score)); } } public class Menu extends MovieClip { //TextField score public function Menu() { addEventListener(Event.ADDED_TO_STAGE, init); } private function init(e:Event):void { removeEventListener(Event.ADDED_TO_STAGE, init); //on init add listener to event ScoreChanged addEventListener(ScoreChanged.SCORE_GAIN, updateScore); } public function updateScore(e:ScoreChanged):void { //it never gets here! tScore.text = String(e._score); } } public class ScoreChanged extends Event { public static const SCORE_GAIN:String = "SCORE_GAIN"; public var _score:Number; public function ScoreChanged( score:Number ) { trace("new score"); super( SCORE_GAIN, true); _score = score; } } I don't want to write in Main compSource.addEventListener(ScoreChanged.SCORE_GAIN, compMenu.updateScore); cause i dont want the the compSource will need to know about compMenu its compMenu responsibility to know to what events it needs to listen.... any suggestions? Thanks!

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  • How to get position of parent element - XSL

    - by joe
    What I wish I could do in xsl is the following, but unfortunatly parent/position() is not valid. XSL <xsl:template match="li"> <bullet> <xsl:apply-templates/> </bullet> <!-- todo: if this is the last bullet AND there are no more "p" tags, output footer --> <xsl:if test="count(ancestor::div/*) = parent/position()"> <footer/> </xsl:if> </xsl:template> XML <html> <div> <p>There is an x number of me</p> <p>There is an x number of me</p> <p>There is an x number of me</p> <ul> <li>list item</li> <li>list item</li> <li>list item</li> <li>list item</li> <li>list item</li> </ul> </div> </html> Anyone have any ideas how to figure out this problem from WITHIN my template match for li? Thanks!

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  • average case running time of linear search algorithm

    - by Brahadeesh
    Hi all. I am trying to derive the average case running time for deterministic linear search algorithm. The algorithm searches an element x in an unsorted array A in the order A[1], A[2], A[3]...A[n]. It stops when it finds the element x or proceeds until it reaches the end of the array. I searched on wikipedia and the answer given was (n+1)/(k+1) where k is the number of times x is present in the array. I approached in another way and am getting a different answer. Can anyone please give me the correct proof and also let me know whats wrong with my method? E(T)= 1*P(1) + 2*P(2) + 3*P(3) ....+ n*P(n) where P(i) is the probability that the algorithm runs for 'i' time (i.e. compares 'i' elements). P(i)= (n-i)C(k-1) * (n-k)! / n! Here, (n-i)C(k-1) is (n-i) Choose (k-1). As the algorithm has reached the ith step, the rest of k-1 x's must be in the last n-i elements. Hence (n-i)C(k-i). (n-k)! is the total number of ways of arranging the rest non x numbers, and n! is the total number of ways of arranging the n elements in the array. I am not getting (n+1)/(k+1) on simplifying.

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  • Convert query with system objects from SQL 2000 to 2005/2008

    - by Dan
    I have some SQL I need to get working on SQL 2005/2008. The SQL is from SQL 2000 and uses some system objects to make it work. master.dbo.spt_provider_types master.dbo.syscharsets systypes syscolumns sysobjects I know SQL 2005 does no longer use system tables and I can get the same information from views, but I am looking for a solution that will work for both SQL 2000 and 2005/2008. Any ideas? select top 100 percent TABLE_CATALOG = db_name(), TABLE_SCHEMA = user_name(o.uid), TABLE_NAME = o.name, COLUMN_NAME = c.name, ORDINAL_POSITION = convert(int, ( select count(*) from syscolumns sc where sc.id = c.id AND sc.number = c.number AND sc.colid <= c.colid )), IS_COMPUTED = convert(bit, c.iscomputed) from syscolumns c left join syscomments m on c.cdefault = m.id and m.colid = 1, sysobjects o, master.dbo.spt_provider_types d, systypes t, master.dbo.syscharsets a_cha /* charset/1001, not sortorder.*/ where o.name = @table_name and permissions(o.id, c.name) <> 0 and (o.type in ('U','V','S') OR (o.type in ('TF', 'IF') and c.number = 0)) and o.id = c.id and t.xtype = d.ss_dtype and c.length = case when d.fixlen > 0 then d.fixlen else c.length end and c.xusertype = t.xusertype and a_cha.type = 1001 /* type is charset */ and a_cha.id = isnull(convert(tinyint, CollationPropertyFromID(c.collationid, 'sqlcharset')), convert(tinyint, ServerProperty('sqlcharset'))) -- make sure there's one and only one row selected for each column order by 2, 3, c.colorder ) tbl where IS_COMPUTED = 0

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  • Random String Generator creates same string on multiple calls

    - by rockinthesixstring
    Hi there. I've build a random string generator but I'm having a problem whereby if I call the function multiple times say in a Page_Load method, the function returns the same string twice. here's the code ''' <summary>' ''' Generates a Random String' ''' </summary>' ''' <param name="n">number of characters the method should generate</param>' ''' <param name="UseSpecial">should the method include special characters? IE: # ,$, !, etc.</param>' ''' <param name="SpecialOnly">should the method include only the special characters and excludes alpha numeric</param>' ''' <returns>a random string n characters long</returns>' Public Function GenerateRandom(ByVal n As Integer, Optional ByVal UseSpecial As Boolean = True, Optional ByVal SpecialOnly As Boolean = False) As String Dim chars As String() ' a character array to use when generating a random string' Dim ichars As Integer = 74 'number of characters to use out of the chars string' Dim schars As Integer = 0 ' number of characters to skip out of the characters string' chars = { _ "A", "B", "C", "D", "E", "F", _ "G", "H", "I", "J", "K", "L", _ "M", "N", "O", "P", "Q", "R", _ "S", "T", "U", "V", "W", "X", _ "Y", "Z", "0", "1", "2", "3", _ "4", "5", "6", "7", "8", "9", _ "a", "b", "c", "d", "e", "f", _ "g", "h", "i", "j", "k", "l", _ "m", "n", "o", "p", "q", "r", _ "s", "t", "u", "v", "w", "x", _ "y", "z", "!", "@", "#", "$", _ "%", "^", "&", "*", "(", ")", _ "-", "+"} If Not UseSpecial Then ichars = 62 ' only use the alpha numeric characters out of "char"' If SpecialOnly Then schars = 62 : ichars = 74 ' skip the alpha numeric characters out of "char"' Dim rnd As New Random() Dim random As String = String.Empty Dim i As Integer = 0 While i < n random += chars(rnd.[Next](schars, ichars)) System.Math.Max(System.Threading.Interlocked.Increment(i), i - 1) End While rnd = Nothing Return random End Function but if I call something like this Dim str1 As String = GenerateRandom(5) Dim str2 As String = GenerateRandom(5) the response will be something like this g*3Jq g*3Jq and the second time I call it, it will be 3QM0$ 3QM0$ What am I missing? I'd like every random string to be generated as unique.

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  • How is it that json serialization is so much faster than yaml serialization in python?

    - by guidoism
    I have code that relies heavily on yaml for cross-language serialization and while working on speeding some stuff up I noticed that yaml was insanely slow compared to other serialization methods (e.g., pickle, json). So what really blows my mind is that json is so much faster that yaml when the output is nearly identical. >>> import yaml, cjson; d={'foo': {'bar': 1}} >>> yaml.dump(d, Dumper=yaml.SafeDumper) 'foo: {bar: 1}\n' >>> cjson.encode(d) '{"foo": {"bar": 1}}' >>> import yaml, cjson; >>> timeit("yaml.dump(d, Dumper=yaml.SafeDumper)", setup="import yaml; d={'foo': {'bar': 1}}", number=10000) 44.506911039352417 >>> timeit("yaml.dump(d, Dumper=yaml.CSafeDumper)", setup="import yaml; d={'foo': {'bar': 1}}", number=10000) 16.852826118469238 >>> timeit("cjson.encode(d)", setup="import cjson; d={'foo': {'bar': 1}}", number=10000) 0.073784112930297852 PyYaml's CSafeDumper and cjson are both written in C so it's not like this is a C vs Python speed issue. I've even added some random data to it to see if cjson is doing any caching, but it's still way faster than PyYaml. I realize that yaml is a superset of json, but how could the yaml serializer be 2 orders of magnitude slower with such simple input?

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  • Date difference in Javascript (ignoring time of day)

    - by Alan
    I'm writing an equipment rental application where clients are charged a fee for renting equipment based on the duration (in days) of the rental. So, basically, (daily fee * number of days) = total charge. For instant feedback on the client side, I'm trying to use Javascript to figure out the difference in two calendar dates. I've searched around, but nothing I've found is quite what I'm looking for. Most solutions I've seen are of the form: function dateDiff1(startDate, endDate) { return ((endDate.getTime() - startDate.getTime()) / 1000*60*60*24); } My problem is that equipment can be checked out and returned at any time of day during those two dates with no additional charge. The above code is calculating the number of 24 hour periods between the two dates, when I'm really interested in the number of calendar days. For example, if someone checked out equipment at 6am on July 6th and returned it at 10pm on July 7th, the above code would calculate that more than one 24 hour period had passed, and would return 2. The desired result is 1, since only one calendar date has elapsed (i.e. the 6th to the 7th). The closest solution I've found is this function: function dateDiff2(startDate, endDate) { return endDate.getDate() - startDate.getDate(); } which does exactly what I want, as long as the two dates are within the same month. However, since getDate() only returns the day of month (i.e. 1-31), it doesn't work when the dates span multiple months (e.g. July 31 to August 1 is 1 day, but the above calcuates 1 - 31, or -29). On the backend, in PHP, I'm using gregoriantojd(), which seems to work just fine (see this post for an example). I just can't find an equivalent solution in Javascript. Anyone have any ideas?

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  • QTableWidget::itemAt() returns seemingly random items

    - by Jordan Milne
    I've just started using Qt, so please bear with me. When I use QTableWidget-getItemAt(), it returns a different item from if I used currentItemChanged and clicked the same item. I believe it's necessary to use itemAt() since I need to get the first column of whatever row was clicked. Some example code is below: MainWindow::MainWindow(QWidget *parent) : QMainWindow(parent), ui(new Ui::MainWindow) { ui->setupUi(this); QList<QString> rowContents; rowContents << "Foo" << "Bar" << "Baz" << "Qux" << "Quux" << "Corge" << "Grault" << "Garply" << "Waldo" << "Fred"; for(int i =0; i < 10; ++i) { ui->tableTest->insertRow(i); ui->tableTest->setItem(i, 0, new QTableWidgetItem(rowContents[i])); ui->tableTest->setItem(i, 1, new QTableWidgetItem(QString::number(i))); } } //... void MainWindow::on_tableTest_currentItemChanged(QTableWidgetItem* current, QTableWidgetItem* previous) { ui->lblColumn->setText(QString::number(current->column())); ui->lblRow->setText(QString::number(current->row())); ui->lblCurrentItem->setText(current->text()); ui->lblCurrentCell->setText(ui->tableTest->itemAt(current->column(), current->row())->text()); } For the item at 1x9, lblCurrentItem displays "9" (as it should,) whereas lblCurrentCell displays "Quux". Am I doing something wrong?

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  • Implementing Operator Overloading with Logarithms in C++

    - by Jacob Relkin
    Hello my friends, I'm having some issues with implementing a logarithm class with operator overloading in C++. My first goal is how I would implement the changeBase method, I've been having a tough time wrapping my head around it. My secoond goal is to be able to perform an operation where the left operand is a double and the right operand is a logarithm object. Here's a snippet of my log class: // coefficient: double // base: unsigned int // number: double class _log { double coefficient, number; unsigned int base; public: _log() { base = rand(); coefficient = rand(); number = rand(); } _log operator+ ( const double b ) const; _log operator* ( const double b ) const; _log operator- ( const double b ) const; _log operator/ ( const double b ) const; _log operator<< ( const _log &b ); double getValue() const; bool changeBase( unsigned int base ); }; You guys are awesome, thank you for your time.

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  • compareTo and nested Enums

    - by echox
    Hi, in "A Programmers Guide to Java SCJP Certification" I found an example which I can't follow. This the given enum: enum Scale3 { GOOD(Grade.C), BETTER(Grade.B), BEST(Grade.A); enum Grade {A, B, C} private Grade grade; Scale3(Grade grade) { this.grade = grade; } public Grade getGrade() { return grade; } } This is the given expression: Scale3.GOOD.getGrade().compareTo(Scale3.Grade.A) > 0; I don't understand why this expression will be true? The return value will be 2. compareTo() will return a value 0 if the given object is "less" than the object. Scale3.Grade.A is the "biggest" element of Grades, its ordinal number is 0. Scale3.GOOD is the "biggest" element of Scale3, its ordinal number is also 0. The constructor of Scale3 is called with Scale3.Grade.C, which ordinal number is 2. So the given expression is equal to the following code: Scale3.Grade.C.compareTo(Scale3.Grade.A) > 0; A is "bigger" than C, so shouldn't be the result < 0?

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  • Package caption Error: Continued 'figure' after 'table'

    - by Eduardo
    Hello I am having a problem with the numbering of figures using Latex, I am getting this error message: Package caption Error: Continued 'figure' after 'table' This is my code: \begin{table} \centering \subfloat[Tabla1\label{tab:Tabla1}]{ \small \begin{tabular}{ | c | c | c | c | c |} \hline \multicolumn{5}{|c|}{\textbf{Tabla 1}} \\ \hline ... ... \end{tabular} } \qquad \subfloat[Tabla2\label{tab:Tabla2}]{ \small \begin{tabular}{ | c | c | c | c | c |} \hline \multicolumn{5}{|c|}{\textbf{Tabla 2}} \\ \hline ... ... \end{tabular} } \caption{These are tables} \label{tab:Tables} \end{table} \begin{figure} \centering \subfloat[][Figure 1]{\label{fig:fig1}\includegraphics[width = 14cm]{fig1}} \qquad \subfloat[][Figure 2]{\label{fig:fig2}\includegraphics[width = 14cm]{fig2}} \end{figure} \begin{figure}[t] \ContinuedFloat \subfloat[][Figure 2]{\label{fig:fig3}\includegraphics[width = 14cm]{fig3}} \caption{Those are figures} \label{fig:Figures} \end{figure} \newpage What I want to do, it is to have this configuration: Table Table Figure 1 Figure 2 Figure 3 Since Figure 1 and Figure 2 are too big to fit vertically I want the Figure 3 to be alone in another page that's why I have the \ContinuedFloat. Externally looks fine but the problem is the numbering, I am getting for the Figures the number 5.2, that is the same number that a Figure I have before (The correct number should be 5.3). However if I try to reference the figures: \ref{fig:fig1}, \ref{fig:fig2} y \ref{fig:fig2} I get: 5.3a, 5.3b y 5.2c The two first right the last one wrong. I have been stuck with this for hours any ideas?. Thans a lot in advance

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