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  • C# NotifyIcon behaviour on Windows 7 with MouseClick, MouseDoubleClick events

    - by binball
    Hi, I have strange behaviour with my app after run it on Windows 7. It's connected with NotifyIcon while app is minimized. What should happens: 1) Click once on icon with mouse left button then Balloon with some text should appears 2) Double click on icon will show again app window On Windows 7 MouseDoubleClick is also fired but window is not showing. I don't know why. The same code works good on Windows XP. private void notifyIcon_MouseClick(object sender, MouseEventArgs e) { if (e.Button == MouseButtons.Left) { this.NotifyIconShowBalloonWithData(); } } private void notifyIcon_MouseDoubleClick(object sender, MouseEventArgs e) { this.Show(); WindowState = FormWindowState.Normal; notifyIcon.Visible = false; } What did I wrong? :) Thanks in advance for your answer.

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  • How do I make these layers not overlap?

    - by Doug
    http://dougymak.com/jquery/test.html# I have three problems that I need help with. 1 ) When you click "More" on top right, it open a div #search and the background is being overlapped by the brown element below. I tried using z-index, but it didn't work. 2 ) I'm trying to make the div #search align directly beneath the "More", but upon setting the width of #search, it aligns to the left side. 3 ) When I hover over the navigation on the left, the popup is being overlapped by the text in the middle. I want the popup to be on top of the text.

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  • Random directions, with no repeat.. (Bad Description)

    - by Neurofluxation
    Hey there, So I'm knocking together a random pattern generation thing. My code so far: int permutes = 100; int y = 31; int x = 63; while (permutes > 0) { int rndTurn = random(1, 4); if (rndTurn == 1) { y = y - 1; } //go up if (rndTurn == 2) { y = y + 1; } //go down if (rndTurn == 3) { x = x - 1; } //go right if (rndTurn == 4) { x = x + 1; } //go left setP(x, y, 1); delay(250); } My question is, how would I go about getting the code to not go back on itself? e.g. The code says "Go Left" but the next loop through it says "Go Right", how can I stop this? NOTE: setP turns a specific pixel on. Cheers peoples!

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  • adding DATE_SUB to query to return range of values in mysql

    - by ian
    Here is my original query: $query = mysql_query("SELECT s.*, UNIX_TIMESTAMP(`date`) AS `date`, f.userid as favoritehash FROM songs s LEFT JOIN favorites f ON f.favorite = s.id AND f.userid = '$userhash' ORDER BY s.date DESC"); This returns all the songs in my DB and then joins data from my favorites table so I can display wich items a return visitors has clicked as favorites or not. Visitors are recognized by a unique has storred in a cookie and in the favorites table. I need to alter this query so that I can get just the last months worth of songs. Below is my attempt at adding DATE_SUB to my query: $query = mysql_query("SELECT s.*, UNIX_TIMESTAMP(`date`) AS `date`, f.userid as favoritehash FROM songs s WHERE `date` >= DATE_SUB( NOW( ) , INTERVAL 1 MONTH ) LEFT JOIN favorites f ON f.favorite = s.id AND f.userid = '$userhash' ORDER BY s.date DESC"); Suggestions?

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  • Advanced SQL query with lots of joins

    - by lund.mikkel
    Hey fellow programmers Okay, first let me say that this is a hard one. I know the presentation may be a little long. But I how you'll bare with me and help me through anyway :D So I'm developing on an advanced search for bicycles. I've got a lot of tables I need to join to find all, let's say, red and brown bikes. One bike may come in more then one color! I've made this query for now: SELECT DISTINCT p.products_id, #simple product id products_name, #product name products_attributes_id, #color id pov.products_options_values_name #color name FROM products p LEFT JOIN products_description pd ON p.products_id = pd.products_id INNER JOIN products_attributes pa ON pa.products_id = p.products_id LEFT JOIN products_options_values pov ON pov.products_options_values_id = pa.options_values_id LEFT JOIN products_options_search pos ON pov.products_options_values_id = pos.products_options_values_id WHERE pos.products_options_search_id = 4 #code for red OR pos.products_options_search_id = 5 #code for brown My first concern is the many joins. The Products table mainly holds product id and it's image and the Products Description table holds more descriptive info such as name (and product ID of course). I then have the Products Options Values table which holds all the colors and their IDs. Products Options Search is containing the color IDs along with a color group ID (products_options_search_id). Red has the color group code 4 (brown is 5). The products and colors have a many-to-many relationship managed inside Products Attributes. So my question is first of all: Is it okay to make so many joins? Is i hurting the performance? Second: If a bike comes in both red and brown, it'll show up twice even though I use SELECT DISTINCT. Think this is because of the INNER JOIN. Is this possible to avoid and do I have to remove the doubles in my PHP code? Third: Bikes can be double colored (i.e. black and blue). This means that there are two rows for that bike. One where it says the color is black and one where is says its blue. (See second question). But if I replace the OR in the WHERE clause it removes both rows, because none of them fulfill the conditions - only the product. What is the workaround for that? I really hope you will and can help me. I'm a little desperate right now :D Regards Mikkel Lund

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  • How do I overlay an icon/image onto another image on form submission?

    - by marcamillion
    So I am trying to add an icon to an image, once someone has 'tagged' a portion of the image - i.e. they have submitted the form. How do I do that in jQuery? Just to be clear...imagine you are on flickr and you see an image. You want to add an annotation, you click on the image where you want, and it shows you a form field. You enter the information you want to, then after you have done so, there is a small image left on top of the picture that shows where you have left a comment. Any ideas?

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  • jQuery appendTo (switching back and forth)

    - by Starboy
    So what I'm trying to accomplish is a simple appendTo a certain element. The issue I'm having is after execute is run, it appends to the location but then proceed to go back to the ul it resides in. <script type="text/javascript"> function execute() { $('#desCopy').appendTo('#description') $('#imgPlace').appendTo('#IMGbox') } </script> <div id="content" style="background:#000; width:989px;"> <div style="float:left; left:18px; margin:0; width:337px; position:relative; padding:15px 0 0 0; color:#FFF;"> <div id="description"> </div> </div> <div id="IMGbox" style="float:left; position:relative; display:block; background:#F00; width:652px; height:258px; background:#0FF; overflow:hidden;"> </div> <div style="float:right; background:#CCC; height:25px; width:652px;"> <ul> <li><a href="" onclick="execute()">Slide 1</a> <ul style=""> <li><span id="desCopy">Test description, Test description</span></li> <li><img src="images/test.jpg" id="imgPlace"></li> </ul> </li> </ul> </div> </div>

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  • How do I get the next token in a Cstring if I want to use it as an int? (c++)

    - by Van
    My objective is to take directions from a user and eventually a text file to move a robot. The catch is that I must use Cstrings(such as char word[];) rather than the std::string and tokenize them for use. the code looks like this: void Navigator::manualDrive() { char uinput[1]; char delim[] = " "; char *token; cout << "Enter your directions below: \n"; cin.ignore(); cin.getline (uinput, 256); token=strtok(uinput, delim); if(token == "forward") { int inches; inches=token+1; travel(inches); } } I've never used Cstrings I've never tokenized anything before, and I don't know how to write this. Our T.A.'s expect us to google and find all the answers because they are aware we've never been taught these methods. Everyone in my lab is having much more trouble than usual. I don't know the code to write but I know what I want my program to do. I want it to execute like this: 1) Ask for directions. 2) cin.getline the users input 3) tokenize the inputed string 4) if the first word token == "forward" move to the next token and find out how many inches to move forward then move forward 5) else if the first token == "turn" move to the next token. if the next token == "left" move to the next token and find out how many degrees to turn left I will have to do this for forward x, backward x, turn left x, turn right x, and stop(where x is in inches or degrees). I already wrote functions that tell the robot how to move forward an inch and turn in degrees. I just need to know how to convert the inputted strings to all lowercase letters and move from token to token and convert or extract the numbers from the string to use them as integers. If all is not clear you can read my lab write up at this link: http://www.cs.utk.edu/~cs102/robot_labs/Lab9.html If anything is unclear please let me know, and I will clarify as best I can.

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  • WPF TreeView PreviewMouseDown on TreeViewItem

    - by imekon
    If I handle the PreviewMouseDown event on TreeViewItem, I get events for everything I click on that TreeViewItem include the little +/- box to the left (Windows XP). How can I distinguish that? I tried the following: // We've had a single click on a tree view item // Unfortunately this is the WHOLE tree item, including the +/- // symbol to the left. The tree doesn't do a selection, so we // have to filter this out... MouseDevice device = e.Device as MouseDevice; // This is bad. The whole point of WPF is for the code // not to know what the UI has - yet here we are testing for // it as a workaround. Sigh... // This is broken - if you click on the +/- on a item, it shouldn't // go on to be processed by OnTreeSingleClick... ho hum! if (device.DirectlyOver.GetType() != typeof(Path)) { OnTreeSingleClick(sender); } What I'm after is just single click on the tree view item excluding the extra bits it seems to include.

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  • Query joining in sql server 2005

    - by Domnic
    I have two queries like: SELECT PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO ACCOUNT, COUNT(PC_CHEQUE_NO) CHQS, SUM(CONVERT(FLOAT, PC_AMOUNT)) CHQ_AMT FROM GLAS_PDC_CHEQUES WHERE PC_COMP_CODE = '1' AND PC_DISCD IS NULL GROUP BY PC_SL_LDGR_CODE, PC_SL_ACNO ,PC_COMP_CODE ORDER BY PC_SL_ACNO -------------------------------------------------- SELECT COAD_PTY_FULL_NAME,PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO, PC_DEPT_NO, PC_DOC_TYPE, PC_CHEQUE_NO, PC_BANK_AC_NO FROM GLAS_PTY_ADDRESS,GLAS_SBLGR_MASTERS,GLAS_PDC_CHEQUES WHERE COAD_COMP_CODE = '1' AND SLMA_COMP_CODE = COAD_COMP_CODE AND SLMA_ADDR_ID = COAD_ADDR_ID AND SLMA_LDGRCTL_CODE = PC_SL_LDGR_CODE AND PC_COMP_CODE=SLMA_COMP_CODE AND SLMA_ACNO = PC_SL_ACNO AND SLMA_LDGRCTL_YEAR = DBO.GLAS_VALIDATIONS_GET_OPEN_YEAR(PC_COMP_CODE) If I execute first query alone I get 5 records... If I join the above two query like: SELECT PC_COMP_CODE, PC_SL_LDGR_CODE, PC_SL_ACNO ACCOUNT, COUNT(PC_CHEQUE_NO) CHQS, SUM(CONVERT(FLOAT, PC_AMOUNT)) CHQ_AMT, COAD_PTY_FULL_NAME FROM GLAS_PDC_CHEQUES LEFT OUTER JOIN GLAS_SBLGR_MASTERS ON( SLMA_COMP_CODE=PC_COMP_CODE AND SLMA_LDGRCTL_CODE = PC_SL_LDGR_CODE AND SLMA_ACNO = PC_SL_ACNO ) LEFT OUTER JOIN GLAS_PTY_ADDRESS ON( SLMA_COMP_CODE = COAD_COMP_CODE AND SLMA_ADDR_ID = COAD_ADDR_ID) WHERE PC_COMP_CODE = '1' AND PC_DISCD IS NULL AND SLMA_LDGRCTL_YEAR = DBO.GLAS_VALIDATIONS_GET_OPEN_YEAR(PC_COMP_CODE) GROUP BY PC_SL_LDGR_CODE, PC_SL_ACNO ,PC_COMP_CODE,COAD_PTY_FULL_NAME ORDER BY PC_SL_ACNO then I just get 2 records.... I need that 5 records to display after join..... How can I do it?

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  • X11: How do I REALLY grab the mouse pointer?

    - by Drew Hall
    I've implemented a horizontal splitter widget in Xlib. I'm trying to grab the mouse when the user clicks & drags on the splitter bar (so that the user can dynamically move the split & thus resize the windows on either side of the splitter bar). I've used XGrabPointer() after receiving a left click, in hopes that all future mouse motion (dragging) will be diverted to the splitter window until the left button is released. Unfortuntately, it doesn't seem to work like that. If the user drags too quickly and the mouse pointer enters one of the windows on either side of the split, the MotionEvent messages are diverted to that (child) window rather than the splitter window. What have I done wrong? My XGrabPointer() call is as follows: ::XGrabPointer(mDisplay, window, True, ButtonPressMask | ButtonReleaseMask | PointerMotionMask | FocusChangeMask | EnterWindowMask | LeaveWindowMask, GrabModeAsync, GrabModeAsync, RootWindow(mDisplay, DefaultScreen(mDisplay)), None, CurrentTime);

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  • Implementing rounded corners on slide down navigation menu

    - by Nick
    I am working on the slide down menu you can see here. I have rounded corners on both ul#navigation and ul.subnavigation. When the submenu slides down it is possible to see the border at the bottom of ul.subnavigation overlap with the content of ul#navigation, when I would like it to slide down smoothly, without the 'flicker'. I am aware that this issue is caused by the rounded corners. I need ul.subnavigation to cover the rounded corners at the bottom of ul#navigation when the menu drops down, without seeing the double border-bottom issue. I hope this is clear! Code is below. Thanks, Nick HTML <ul id="navigation"> <li class="dropdown"><a href="#">menu</a> <ul class="sub_navigation"> <li><a href="#">home</a></li> <li><a href="#">help</a></li> <li><a href="#">disable tips</a></li> </ul> </li> </ul> JQUERY $('.dropdown').hover(function() { $(this).find('.sub_navigation').slideToggle(); });? CSS ul#navigation, ul.sub_navigation { margin:0; padding:0; list-style-type:none; min-width:100px; background-color: white; font-size:15px; font-family: Trebuchet MS; text-align: center; -khtml-border-radius: 0 0 5px 5px; -moz-border-radius: 0 0 5px 5px; -webkit-border-radius: 0 0 5px 5px; border-radius: 0 0 5px 5px; border:1px black solid; border-top:none; } ul.sub_navigation { margin-left:-1px; position: absolute; top:28px; } ul#navigation { float:left; position:absolute; top:0; } ul#navigation li { float:left; min-width:100px; } ul.sub_navigation { position:absolute; display:none; } ul.sub_navigation li { clear:both; } a, a:active, a:visited { display:block; padding:7px; }

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  • WindowStartupLocation.CenterScreen is opening my window on the wrong display

    - by chaiguy
    According to the documentation, CenterScreen should open the window in the center of the screen that contains the mouse cursor, however this is not happening. I have a dual monitor setup, with my secondary monitor appearing to the left of my primary monitor (the one with the task bar). When the user clicks a link in my interface on the primary (right-most) monitor, and I open a new window with WindowStartupLocation set to CenterScreen, the window appears in the center of the screen of the left monitor. This is not where the mouse is and I am lost as to why it is picking that display. Has anyone experienced this before or have any ideas for a workaround? If I can't get the proper behavior using WindowStartupLocation, I will just manually move the window to the proper display (I still have to figure that out though).

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  • How can give third child div within one parent div

    - by Mubeen
    I have one Parent div. Top of the Parent div contains two child divs. How can i give third child div below the first child div <div class=parent1> <div class=child1>some text</div> /*this is in top left of the parent div */ <div class=child2>some text</div> /*this is in top right of the parent div */ <div class=child3>some text</div> /*how can i write css for this div come as left bottom*/

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  • How to Control Screen Layouts in LightSwitch

    - by ChrisD
    Visual Studio LightSwitch has a bunch of screen templates that you can use to quickly generate screens. They give you good starting points that you can customize further. When you add a new screen to your project you see a set of screen templates that you can choose from. These templates lay out all the related data you choose to put on a screen automatically for you. And don’t under estimate them; they do a great job of laying out controls in a smart way. For instance, a tab control will be used when you select more than one related set of data to display on a screen. However, you’re not limited to taking the layout as is. In fact, the screen designer is pretty flexible and allows you to create stacks of controls in a variety of configurations. You just need to visualize your screen as a series of containers that you can lay out in rows and columns. You then place controls or stacks of controls into these areas to align the screen exactly how you want. If you’re new in Visual Studio LightSwitch, you can see this tutorial. OK, Let’s start with a simple example. I have already designed my data entities for a simple order tracking system similar to the Northwind database. I also have added a Search Data  Screen to search my Products already. Now I will add a new Details Screen for my Products and make it the default screen via the “Add New Screen” dialog: The screen designer picks a simple layout for me based on the single entity I chose, in this case Product. Hit F5 to run the application, select a Product on the search screen to open the Product Details Screen. Notice that it’s pretty simple because my entity is simple. Click the “Customize” button in the top right of the screen so we can start tweaking it. The left side of the screen shows the containership of controls and data bindings (called the content tree) and the right side shows the live preview with data. Notice that we have a simple layout of two rows but only one row is populated (with a vertical stack of controls in this case). The bottom row is empty. You can envision the screen like this: Each container will display a group of data that you select. For instance in the above screen, the top row is set to a vertical stack control and the group of data to display is coming from Product. So when laying out screens you need to think in terms of containers of controls bound to groups of data. To change the data to which a container is bound, select the data item next to the container: You can select the “New Group” item in order to create more containers (or controls) within the current container. For instance to totally control the layout, select the Product in the top row and hit the delete key. This will delete the vertical stack and therefore all the controls on the screen. The content tree will still have two rows, but the rows are now both empty. If you want a layout of four containers (two rows and two columns) then select “New Group” for the data item and then change the vertical stack control to “Two Columns” for both of the rows as shown here: You can keep going on and on by selecting new groups and choosing between rows or columns. Here’s a layout with 8 containers, 4 rows and 2 columns: And here is a layout with 7 content areas; one row across the top of the screen and three rows with two columns below that: When you select Choose Content and select a data item like Product it will populate all the controls within the container (row or column in a vertical stack) however you have complete control on what to display within each group. You can delete fields you don’t want to display and/or change their controls. You can also change the size of controls and how they display by changing the settings in the properties window. If you are in the Screen Designer (and not the customization mode like we are here) you can also drag-drop data items from the left-hand side of the screen to the content tree. Note, however, that not all areas of the tree will allow you to drop a data item if there is a binding already set to a different set of data. For instance you can’t drop a Customer ID into the same group as a Product if they originate from different entities. To get around this, all you need to do is create a new group and content area as shown above. Let’s take a more complex example that deals with more than just product. I want to design a complex screen that displays Products and their Category, as well as all the OrderDetails for which that product is selected. This time I will create a new screen and select List and Details, select the Products screen data, and include the related OrderDetails. However I’m going to totally change the layout so that a Product grid is at the top left and below that is the selected Product detail. Below that will be the Category text fields and image in two columns below. On the right side I want the OrderDetails grid to take up the whole right side of the screen. All this can be done in customization mode while you’re debugging the application. To do this, I first deleted all the content items in the tree and then re-created the content tree as shown in the image below. I also set the image to be larger and the description textbox to be 5 rows using the property window below the live preview. I added the green lines to indicate the containers and show how it maps to the content tree (click to enlarge): I hope this demystifies the screen designer a little bit. Remember that screen templates are excellent starting points – you can take them as-is or customize them further. It takes a little fooling around with customizing screens to get them to do exactly what you want but there are a ton of possibilities once you get the hang of it. Stay tuned for more information on how to create your own screen templates that show up in the “Add New Screen” dialog. Enjoy! The tutorial that might be interested: Adding Custom Control In LightSwitch

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  • Optimize MySQL query (ngrams, COUNT(), GROUP BY, ORDER BY)

    - by Gerardo
    I have a database with thousands of companies and their locations. I have implemented n-grams to optimize search. I am making one query to retrieve all the companies that match with the search query and another one to get a list with their locations and the number of companies in each location. The query I am trying to optimize is the latter. Maybe the problem is this: Every company ('anunciante') has a field ('estado') to make logical deletes. So, if 'estado' equals 1, the company should be retrieved. When I run the EXPLAIN command, it shows that it goes through almost 40k rows, when the actual result (the reality matching companies) are 80. How can I optimize this? This is my query (XXX represent the n-grams for the search query): SELECT provincias.provincia AS provincia, provincias.id, COUNT(*) AS cantidad FROM anunciantes JOIN anunciante_invertido AS a_i0 ON anunciantes.id = a_i0.id_anunciante JOIN indice_invertido AS indice0 ON a_i0.id_invertido = indice0.id LEFT OUTER JOIN domicilios ON anunciantes.id = domicilios.id_anunciante LEFT OUTER JOIN localidades ON domicilios.id_localidad = localidades.id LEFT OUTER JOIN provincias ON provincias.id = localidades.id_provincia WHERE anunciantes.estado = 1 AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') AND indice0.id IN (SELECT invertido_ngrama.id_palabra FROM invertido_ngrama JOIN ngrama ON ngrama.id = invertido_ngrama.id_ngrama WHERE ngrama.ngrama = 'XXX') GROUP BY provincias.id ORDER BY cantidad DESC And this is the query explained (hope it can be read in this format): id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY anunciantes ref PRIMARY,estado estado 1 const 36669 Using index; Using temporary; Using filesort 1 PRIMARY domicilios ref id_anunciante id_anunciante 4 db84771_viaempresas.anunciantes.id 1 1 PRIMARY localidades eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.domicilios.id_localidad 1 1 PRIMARY provincias eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.localidades.id_provincia 1 1 PRIMARY a_i0 ref PRIMARY,id_anunciante,id_invertido PRIMARY 4 db84771_viaempresas.anunciantes.id 1 Using where; Using index 1 PRIMARY indice0 eq_ref PRIMARY PRIMARY 4 db84771_viaempresas.a_i0.id_invertido 1 Using index 6 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 6 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 5 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 5 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 4 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 4 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 3 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 3 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index 2 DEPENDENT SUBQUERY ngrama const PRIMARY,ngrama ngrama 5 const 1 Using index 2 DEPENDENT SUBQUERY invertido_ngrama eq_ref PRIMARY,id_palabra,id_ngrama PRIMARY 8 func,const 1 Using index

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  • Thinking of an Inner Join as a Cross Join and then satisfying some condition(s)?

    - by Jian Lin
    It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then satisfying some condition(s)? Because the equi-join can be obvious, but the non-equi-join can be a bit confusing. But if we always use the Cross Join, and then filter out the ones satisfying the condition, then we get the resulting table. In other words, we can always analyze it by using the first record on the left table, and then go through every single records on the right, and then repeat that for 2nd record on the left, and for the 3rd, 4th, ... etc. So in our mind, we can analyze it using this way, and it is like O(n^2), although what happens in the DBMS maybe that it is a lot faster (when an index is present). Is there another good way to think of it besides this method?

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  • XSL file handling through javascript

    - by Zaid Iqbal
    i want to handle my xsl file through my javascript code. I made my XSL file but i want to dynamically change my XSL file at run time.As in add more attributes in header or data. My javascript code as follow` <script> function loadXMLDoc(dname) { if (window.XMLHttpRequest) { xhttp=new XMLHttpRequest(); } else { xhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xhttp.open("GET",dname,false); xhttp.send(""); return xhttp.responseXML; } function displayResult() { xml=loadXMLDoc("cdcatalog.xml"); xsl=loadXMLDoc("cdcatalog.xsl"); // code for IE if (window.ActiveXObject) { ex=xml.transformNode(xsl); document.getElementById("example").innerHTML=ex; } // code for Mozilla, Firefox, Opera, etc. else if (document.implementation && document.implementation.createDocument) { xsltProcessor=new XSLTProcessor(); xsltProcessor.importStylesheet(xsl); resultDocument = xsltProcessor.transformToFragment(xml,document); document.getElementById("example").appendChild(resultDocument); } } </script> My XSL file code: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/"> <html> <body> <h2>My CD Collection</h2> <table border="1"> <tr bgcolor="#9acd32"> <th align="left">Title</th> <th align="left">Artist</th> <th align="left">Country</th> </tr> <xsl:for-each select="catalog/cd"> <tr> <td><xsl:value-of select="title" /></td> <td><xsl:value-of select="artist" /></td> <td><xsl:value-of select="country" /></td> </tr> </xsl:for-each> </table> </body> </html> </xsl:template> </xsl:stylesheet> `

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  • Positioning a tooltip relative to another div in JQuery

    - by James P
    Here's my tooltips markup and CSS: <div class="tooltip">Click here to like it</div> .tooltip { position: absolute; display: none; background: url('images/tooltip.gif') no-repeat; width: 100%; height: 40px; font-size: 0.8em; line-height: 40px; padding: 0px 0px 0px 8px; } Now, I have a div on my page called #button_container. I would like to place this .tooltip div 150px to the right of that div via JQuery. I understand I need to set this tooltips top and left attributes, but not sure how. Idealy the tooltips top attribute should be the same as #button_container (although #button_container isn't positioned absolutely) and 150 less than #button_container's left attribute. I don't really know where to get started on this so any help would be very much appreciated. Thanks.

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  • hibernate createSQL how to cache it?

    - by cometta
    If i use Criteria statement, i able to use cache easily. but when i using custom CREATESQL, like below, how do i cache it? Query query = getHibernateTemplate().getSessionFactory().getCurrentSession().createSQLQuery( " select company_keysupplier.ddiv as ddiv, company_division.name as DIVISION, company_keysupplier.ddep as ddep,company_department.name as DEPARTMENT"+ " from company_keysupplier "+ " left join company_division on "+ " (company_keysupplier.ddiv= company_division.division_code and company_keysupplier.survey_num=company_division.survey_num) "+ " left join company_department on "+ " (company_keysupplier.ddep= company_department.department_code and company_keysupplier.survey_num=company_department.survey_num) "+ " where company_keysupplier.sdiv = :sdiv and company_keysupplier.sdep = :sdep and company_keysupplier.survey_num= :surveyNum " + " order by company_division.name, company_keysupplier.ddep " ) .addScalar("ddiv") .addScalar("ddep") .addScalar("DIVISION") .addScalar("DEPARTMENT") .setResultTransformer(Transformers.aliasToBean(IssKeysupplier.class)); query.setString("sdiv", sdiv); query.setString("sdep", sdepartment); query.setBigInteger("surveyNum", survey_num); //i tried query.setCachable(true) fail...... List result= (List<IssKeysupplier>)query.list(); return result;

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  • Binary Tree operator overloading and recursion

    - by furious.snail
    I was wondering how to overload the == operator for a binary tree to compare if two trees have identical data at same nodes. So far this is what I have: bool TreeType::operator==(const TreeType& otherTree) const { if((root == NULL) && (otherTree.root == NULL)) return true; //two null trees are equal else if((root != NULL) && (otherTree.root != NULL)) { return((root-info == otherTree.root-info) && //this part doesn't actually do anything recursively... //(root-left == otherTree.root-left) && //(root-right == otherTree.root-right)) } else return false; //one tree is null the other is not } I have a similar function that takes two TreeNode pointers as parameters but I've been stuck on how to convert it to this function.

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  • It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then sa

    - by Jian Lin
    It seems like the safest way to think of an Inner Join is to think of it as a Cross Join and then satisfying some condition(s)? Because the equi-join can be obvious, but the non-equi-join can be a bit confusing. But if we always use the Cross Join, and then filter out the ones satisfying the condition, then we get the resulting table. In other words, we can always analyze it by using the first record on the left table, and then go through every single records on the right, and then repeat that for 2nd record on the left, and for the 3rd, 4th, ... etc. So in our mind, we can analyze it using this way, and it is like O(n^2), although what happens in the DBMS maybe that it is a lot faster (when an index is present). Is there another good way to think of it besides this method?

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  • how to drag a 'div' element to the google maps ,that be changed to a 'marker'..use jquery

    - by zjm1126
    this is my code : <!DOCTYPE html PUBLIC "-//WAPFORUM//DTD XHTML Mobile 1.0//EN" "http://www.wapforum.org/DTD/xhtml-mobile10.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" > <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <meta name="viewport" content="width=device-width,minimum-scale=1.0,maximum-scale=1.0,user-scalable=no"> </head> <body onload="initialize()" onunload="GUnload()"> <style type="text/css"> </style> <div id="map_canvas" style="width: 500px; height: 300px;float:left;"></div> <div id=b style="width: 50px; height: 50px;background:red;float:left;margin-left:300px;"></div> <script src="jquery-1.4.2.js" type="text/javascript"></script> <script src="jquery-ui-1.8rc3.custom.min.js" type="text/javascript"></script> <script src="http://ditu.google.cn/maps?file=api&amp;v=2&amp;key=ABQIAAAA-7cuV3vqp7w6zUNiN_F4uBRi_j0U6kJrkFvY4-OX2XYmEAa76BSNz0ifabgugotzJgrxyodPDmheRA&sensor=false"type="text/javascript"></script> <script type="text/javascript"> //********** function initialize() { if (GBrowserIsCompatible()) { // function createMarker(point, number) { var marker = new GMarker(point); var message = ["?","?","?","??","??"]; marker.value = number; GEvent.addListener(marker, "click", function() { var myHtml = "<b>#" + number + "</b><br/>" + message[number -1]; map.openInfoWindowHtml(point, myHtml); }); return marker; } // var map = new GMap2(document.getElementById("map_canvas")); map.setCenter(new GLatLng(39.9493, 116.3975), 13); // Add 5 markers to the map at random locations var bounds = map.getBounds(); var southWest = bounds.getSouthWest(); var northEast = bounds.getNorthEast(); var lngSpan = northEast.lng() - southWest.lng(); var latSpan = northEast.lat() - southWest.lat(); for (var i = 0; i < 5; i++) { var point = new GLatLng(southWest.lat() + latSpan * Math.random(), southWest.lng() + lngSpan * Math.random()); map.addOverlay(createMarker(point, i + 1)); } } } //************* $("#b").draggable(); </script> </body> </html>

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