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  • Can I take the voice data (f.e. in mp3 format) from speech recognition? [closed]

    - by Ersin Gulbahar
    Possible Duplicate: Android: Voice Recording and saving audio I mean ; I use voice recognition classes on android and I succeed voice recognition. But I want to real voice data not words instead of it. For example I said 'teacher' and android get you said teacher.Oh ok its good but I want to my voice which include 'teacher'.Where is it ? Can I take it and save another location? I use this class to speech to text : package net.viralpatel.android.speechtotextdemo; import java.util.ArrayList; import android.app.Activity; import android.content.ActivityNotFoundException; import android.content.Intent; import android.os.Bundle; import android.speech.RecognizerIntent; import android.view.Menu; import android.view.View; import android.widget.ImageButton; import android.widget.TextView; import android.widget.Toast; public class MainActivity extends Activity { protected static final int RESULT_SPEECH = 1; private ImageButton btnSpeak; private TextView txtText; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); txtText = (TextView) findViewById(R.id.txtText); btnSpeak = (ImageButton) findViewById(R.id.btnSpeak); btnSpeak.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Intent intent = new Intent( RecognizerIntent.ACTION_RECOGNIZE_SPEECH); intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, "en-US"); try { startActivityForResult(intent, RESULT_SPEECH); txtText.setText(""); } catch (ActivityNotFoundException a) { Toast t = Toast.makeText(getApplicationContext(), "Ops! Your device doesn't support Speech to Text", Toast.LENGTH_SHORT); t.show(); } } }); } @Override public boolean onCreateOptionsMenu(Menu menu) { getMenuInflater().inflate(R.menu.activity_main, menu); return true; } @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); switch (requestCode) { case RESULT_SPEECH: { if (resultCode == RESULT_OK && null != data) { ArrayList<String> text = data .getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS); txtText.setText(text.get(0)); } break; } } } } Thanks.

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  • Adapter Methods in Android?

    - by Praveen Chandrasekaran
    i have go through the three methods in Adapters classes. getView() newView() bindView() what are the difference between those methods? please share some tutorial, sample code or logics to understand this. Thanks. i have to create a listview with the progressive icons. which adapter you suggest me to do that?

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  • how to send image to remote server using web services in android

    - by Aswan
    get image from sdcard and store that image to remote server. i am getting the image from sdcard and i converterd that image to bytearray by using bitmap .but what's the problem if i oberver byte array it is showing some different values it is not matching with .net image byte array conversion. can u pl help if you have any solution it is very urgent to me following is the code i am using can u pl suggest me FileInputStream fin = new FileInputStream(new File("/sdcard/pictures/1.jpg")); BufferedInputStream bis = new BufferedInputStream(fin,3000); byte[] data = new byte[bis.available()]; bis.read(data, 0, data.length); byte[] data1=new byte[data.length]; for (int i = 0; i < data.length; i++) { System.out.print(data[i]); data1[i]=data[i]; } System.out.println("5..................."+data1); Bitmap bitmap = BitmapFactory.decodeByteArray(data1,0,data1.length); System.out.println("6..................."+data1.length); Log.v("hgfjohfjghjdfhgj",""+bitmap); if(bitmap!=null) image.setImageBitmap(bitmap); else Log.e("Bitmap "," Not Created");

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  • How to check if EditText has a value in Android / Java

    - by Allen Gingrich
    This should be simple, but I have tried if statements checking for null values and also ones checking the .length of it: EditText marketValLow = (EditText) findViewById(R.id.marketValLow); EditText marketValHigh = (EditText) findViewById(R.id.marketValHigh); if (marketValLow.getText().length() != 0 && marketValHigh.getText().length() != 0) { Intent intent = new Intent(); intent.setClass(v.getContext(), CurrentlyOwe.class); startActivity(intent); } else { Toast.makeText(CurrentMarketValue.this, "You need to enter a high AND low.", Toast.LENGTH_SHORT); } But it doesn't detect nothing was entered. Any ideas? Thanks!

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  • Streaming audio not working in Android

    - by user320293
    Hi, I'm sure that this question has been asked before but I've been unable to find a solid answer. I'm trying to load a streaming audio from a server. Its a audio/aac file http://3363.live.streamtheworld.com:80/CHUMFMAACCMP3 The code that I'm using is private void playAudio(String str) { try { final String path = str; if (path == null || path.length() == 0) { Toast.makeText(RadioPlayer.this, "File URL/path is empty", Toast.LENGTH_LONG).show(); } else { // If the path has not changed, just start the media player MediaPlayer mp = new MediaPlayer(); mp.setAudioStreamType(AudioManager.STREAM_MUSIC); try{ mp.setDataSource(getDataSource(path)); mp.prepareAsync(); mp.start(); }catch(IOException e){ Log.i("ONCREATE IOEXCEPTION", e.getMessage()); }catch(Exception e){ Log.i("ONCREATE EXCEPTION", e.getMessage()); } } } catch (Exception e) { Log.e("RPLAYER EXCEPTION", "error: " + e.getMessage(), e); } } private String getDataSource(String path) throws IOException { if (!URLUtil.isNetworkUrl(path)) { return path; } else { URL url = new URL(path); URLConnection cn = url.openConnection(); cn.connect(); InputStream stream = cn.getInputStream(); if (stream == null) throw new RuntimeException("stream is null"); File temp = File.createTempFile("mediaplayertmp", ".dat"); temp.deleteOnExit(); String tempPath = temp.getAbsolutePath(); FileOutputStream out = new FileOutputStream(temp); byte buf[] = new byte[128]; do { int numread = stream.read(buf); if (numread <= 0) break; out.write(buf, 0, numread); } while (true); try { stream.close(); } catch (IOException ex) { Log.e("RPLAYER IOEXCEPTION", "error: " + ex.getMessage(), ex); } return tempPath; } } Is this the correct implementation? I'm not sure where I'm going wrong. Can someone please please help me on this.

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  • Android game logic problem

    - by semajhan
    I'm currently creating a game and have a problem which I think I know why it is occurring but not entirely sure and even if I knew, don't know how to solve. I have a 2D array 10 x 10 and have a "player" class that takes up a tile. Now, I have created 2 instances of the player and move them around via swiping. Around the edges I have put "walls" that the player cannot walk through and everything works fine, until I remove a wall. Once I remove a wall and move the character/player to the edge of the screen, the player cannot go any further. The problem occurs here, where the second instance of the player is not at the edge of the screen but say 2 tiles from the first instance of "player" who is at the edge. If I try moving them further into the direction of the edge, I understand that the first instance of player wouldn't move or do anything but the second instance of player should still move, but it won't. This is the code that executed when the user swipes: if (player.getArrayX() - 1 != player2.getArrayX()) { player.moveLeft(); } else if (player.getArrayX() - 1 == player2.getArrayX() && player.getArrayY() != player2.getArrayY()) { player.moveLeft(); } if (player2.getArrayX() - 1 != player.getArrayX()) { player2.moveLeft(); } else if (player2.getArrayX() - 1 == player.getArrayX() && player2.getArrayY() != player.getArrayY()) { player2.moveLeft(); } In the player class I have: public void moveLeft() { if (alive) { switch (levelMaster.getLevel1(getArrayX() - 1, getArrayY())) { case 0: break; case 1: subX(); // basically moves player left setArrayX(getArrayX() - 1); // shifts x coord of player 1 within tilemap Log.d("semajhan", "x: " + getArrayX()); break; case 9: subX(); setArrayX(getArrayX() - 1); setAlive(false); break; } } } Any help on the matter or further insight would be greatly appreciated, thanks.

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  • Android -- Object Creation/Memory Allocation vs. Performance

    - by borg17of20
    Hello all, This is probably an easy one. I have about 20 TextViews/ImageViews in my current project that I access like this: ((TextView)multiLayout.findViewById(R.id.GameBoard_Multi_Answer1_Text)).setText(""); //or ((ImageView)multiLayout.findViewById(R.id.GameBoard_Multi_Answer1_Right)).setVisibility(View.INVISIBLE); My question is this, am I better off, from a performance standpoint, just assigning these object variables? Further, am I losing some performance to the constant "search" process that goes on as a part of the findViewById(...) method? (i.e. Does findsViewById(...) use some sort of hashtable/hashmap for look-ups or does it implement an iterative search over the view hierarchy?) At present, my program never uses more than 2.5MB of RAM, so will assigning 20 or so more object variables drastically affect this? I don't think so, but I figured I'd ask. Thanks.

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  • Connecting GPS coordinates taken from a database in Android using Overlay

    - by LordSnoutimus
    I am currently building an application that allows users to track where their phone has been on a Google Map. At the moment, when the onLocationChanged() method is called, the application stores the current GPS longitude and latitude in a database and calls the animateTo() method to the current position. Using SDK 1.5, how would I go about connecting these points with a coloured line drawn on the MapView using an Overlay?.

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  • android, find the nearest location without going through all the locations

    - by Marwan
    I am building a taxi dispatching app first: I need the passenger app to show the nearest taxis, now I know how to do that in code but in my way I have to go through all the taxis locations(in database on server) and calculate the distance from the passenger location and get the lowest ones - I don't want to do this because there will be a lot of taxis and going through all of them and making some math is kind of pain on the server- is there a way to get the nearest ones without going through all of them? second: what the best database to use - first, should it be sql or non-sql - I need a very robust database, because there will be a lot of updates (I mean the passengers locations added then deleted when arriving to destination && the taxis location changes frequently) finally: I will use RubyOnRails to do the server side and json as data transfer format, do you have a recommendation to me on something better? Thanks

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  • Android: Get the screen resolution / pixels as integer values

    - by poeschlorn
    Hi guys, this is a really simple question on which I've found no answer :/ How can I quickly access the screen resolution (width, height) as integer values? I've tried this one, but it always shows zero on my emulator: DisplayMetrics dm = new DisplayMetrics(); int width = dm.widthPixels / 2; In my case I want to dynamically create a table with tableRows, each containing two cols. This cols all shall fill half of the screen in width. Can someone give me a hint?

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  • draw is being constantly called in my android map overlay

    - by Itsik
    I'm trying to draw a route onto my MapView. I've extended Overlay and implemented the draw() method. The route is displayed properly, although while debugging, I added a breakpoint on draw(), and noticed it is being called constantly. I only want it to be re-drawn if someone moves the map or zooms (the draw take into account these changes when drawing the route) What can cause this ?

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  • android internal phone storage

    - by John
    how can you retrieve yours phone internal storage from an app? I found memoryinfo, but it seems that returns information on how much memory your currently running tasks. I am trying to get my app to retrieve how much internal phone storage is available.

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  • android disabled view are focusable

    - by Arutha
    When I disabled views such as radiobutton or buttons with the setEnabled method, the views are still focusable but with view such as EditText they are'nt... I need to call setFocusable(false) if i want that all my views don't receive focus when they are disabled ?

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  • Android Repetitive Task

    - by Steve
    In an Activity, I need to call a web service every 30 seconds or so, and use the data to update the UI. Is there a recommended approach on how to schedule a repetitive task? Thanks

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  • Writing Resources from filesystem in Android

    - by Markus
    Hi, as I need to get a specific Frame from a Website I want to display in an WebView, I decided to grab the .html from the net and save it under file:///data/data//files/file.html. Stroed there I can edit it using regex or String methods. Now two questions: Is there a way to bind this file to an resource. e.g. to /res/raw/file.html and get it updated dynamically as i edit it? Or can i write the File directly to the resources? Is this whole stuff I do there any good or performant at all? I mean maybe there is a better way to get the .html code between two tags from a Webpage and display it via WebView. Kind regards Markus

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  • Custom Attributes in Android

    - by Arun
    I'm trying to create a custom attribute called Tag for all editable elements. I added the following to attrs.xml <declare-styleable name="Spinner"> <attr name="tag" format="string" /> </declare-styleable> <declare-styleable name="EditText"> <attr name="tag" format="string" /> </declare-styleable> I get an error saying "Attribute tag has already been defined" for the EditText. Is it not possible to create a custom attribute of the same name on different elements?

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  • Playing Ogg Sound in Android

    - by baba tenor
    In my application, I am trying to play a sound file in ogg format, stored in raw folder in res directory of my application. When I press the button that calls below function, it just freezes with the button pressed and does not respond. In the end, I have to terminate the application from Eclipse. Nothing about an error or exception in Logcat. In debugging mode, it enters create function and never comes back. What am I doing wrong? private void playbeep() { mPlayer = MediaPlayer.create(this, R.raw.beep); mPlayer.start(); mPlayer.release(); }

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  • Make a String text Bold in Java Android

    - by meskh
    I want to make Habit Number: bold , I tried the HTML tag but it didn't work. I did some research but couldn't find any. Hope someone is able to help me. Thanks! String habitnumber = "Habit Number: " + String.valueOf(habitcounter); String Title = habit.getTitle(); String description = habit.getDescription(); //Set text for the row tv.setText(habitnumber+ "\n" + Title + " \n" + description + "\n --------------------");

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  • Android Layouts Scrolling in Landscaped Mode

    - by y ramesh rao
    I have a strange issue in which on rotating the Screen to Landscaped mode the Views present inside Remain at the same place But I cannot scroll them inside the screen. How can I make them Scroll so that every thing that move out should be displayed properly to the user. Should there be any more attribute to be set for allowing such kind of behavior.

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  • Problems with Twitter on Android App

    - by Dayner Alvarez Rodriguez
    I'm trying to show one public twitter profile in one WebView of my app, is not necessary to login twitter, in the MotoDev Simulator this works fine, but in the physical device don't work, this: "403 fobiden limite exceed rate" error appears, this is the simple code line that I'm using: webView.loadUrl("https://mobile.twitter.com/#!/asambleaecuador"); and works fine into de MotoDev simulator AVD ....can somebody helpme please!!! Thanks

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  • Android - BitmapFactory.decodeByteArray - OutOfMemoryError (OOM)

    - by Bob Keathley
    I have read 100s of article about the OOM problem. Most are in regard to large bitmaps. I am doing a mapping application where we download 256x256 weather overlay tiles. Most are totally transparent and very small. I just got a crash on a bitmap stream that was 442 Bytes long while calling BitmapFactory.decodeByteArray(....). The Exception states: java.lang.OutOfMemoryError: bitmap size exceeds VM budget(Heap Size=9415KB, Allocated=5192KB, Bitmap Size=23671KB) The code is: protected Bitmap retrieveImageData() throws IOException { URL url = new URL(imageUrl); InputStream in = null; OutputStream out = null; HttpURLConnection connection = (HttpURLConnection) url.openConnection(); // determine the image size and allocate a buffer int fileSize = connection.getContentLength(); if (fileSize < 0) { return null; } byte[] imageData = new byte[fileSize]; // download the file //Log.d(LOG_TAG, "fetching image " + imageUrl + " (" + fileSize + ")"); BufferedInputStream istream = new BufferedInputStream(connection.getInputStream()); int bytesRead = 0; int offset = 0; while (bytesRead != -1 && offset < fileSize) { bytesRead = istream.read(imageData, offset, fileSize - offset); offset += bytesRead; } // clean up istream.close(); connection.disconnect(); Bitmap bitmap = null; try { bitmap = BitmapFactory.decodeByteArray(imageData, 0, bytesRead); } catch (OutOfMemoryError e) { Log.e("Map", "Tile Loader (241) Out Of Memory Error " + e.getLocalizedMessage()); System.gc(); } return bitmap; } Here is what I see in the debugger: bytesRead = 442 So the Bitmap data is 442 Bytes. Why would it be trying to create a 23671KB Bitmap and running out of memory?

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