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  • How to match multiple field in mySQL

    - by Mint
    Im trying to match forum_id with several different forum_id's, something like forum_id = 5,7,12,43,63,78 I currently have this code: SELECT topic_title, topic_id, forum_id FROM $MYSQL_TOPIC WHERE topic_title LIKE '%%%s%%' AND forum_id = 5 LIMIT 50 (using mysql_real_escape_string and sprintf) I tried: forum_id = 5 OR 7 forum_id = 5|7 forum_id = 5 AND 7 forum_id = 5 & 7 But none of them will match them all and therefore search though them all.

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  • PHP, MySQL, jQuery, AJAX: json data returns correct response but frontend returns error

    - by Devner
    Hi all, I have a user registration form. I am doing server side validation on the fly via AJAX. The quick summary of my problem is that upon validating 2 fields, I get error for the second field validation. If I comment first field, then the 2nd field does not show any error. It has this weird behavior. More details below: The HTML, JS and Php code are below: HTML FORM: <form id="SignupForm" action=""> <fieldset> <legend>Free Signup</legend> <label for="username">Username</label> <input name="username" type="text" id="username" /><span id="status_username"></span><br /> <label for="email">Email</label> <input name="email" type="text" id="email" /><span id="status_email"></span><br /> <label for="confirm_email">Confirm Email</label> <input name="confirm_email" type="text" id="confirm_email" /><span id="status_confirm_email"></span><br /> </fieldset> <p> <input id="sbt" type="button" value="Submit form" /> </p> </form> JS: <script type="text/javascript"> $(document).ready(function() { $("#email").blur(function() { var email = $("#email").val(); var msgbox2 = $("#status_email"); if(email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: "email="+ email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } }); } return false; }); $("#confirm_email").blur(function() { var confirm_email = $("#confirm_email").val(); var email = $("#email").val(); var msgbox3 = $("#status_confirm_email"); if(confirm_email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: 'confirm_email='+ confirm_email + '&email=' + email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } , error: function (data) { alert('Some error'); } }); } return false; }); }); </script> PHP code: <?php //check_ajax2.php if(isset($_POST['email'])) { $email = $_POST['email']; $res = mysql_query("SELECT uid FROM members WHERE email = '$email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { $success = 'y'; $msg_email = 'Email available'; } else { $success = 'n'; $msg_email = 'Email is already in use.</font>'; } print json_encode(array('success' => $success, 'msg_email' => $msg_email)); } if(isset($_POST['confirm_email'])) { $confirm_email = $_POST['confirm_email']; $email = ( isset($_POST['email']) && trim($_POST['email']) != '' ? $_POST['email'] : '' ); $res = mysql_query("SELECT uid FROM members WHERE email = '$confirm_email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { if( isset($email) && isset($confirm_email) && $email == $confirm_email ) { $success = 'y'; $msg_confirm_email = 'Email available and match'; } else { $success = 'n'; $msg_confirm_email = 'Email and Confirm Email do NOT match.'; } } else { $success = 'n'; $msg_confirm_email = 'Email already exists.'; } print json_encode(array('success' => $success, 'msg_confirm_email' => $msg_confirm_email)); } ?> THE PROBLEM: As long as I am validating the $_POST['email'] as well as $_POST['confirm_email'] in the check_ajax2.php file, the validation for confirm_email field always returns an error. With my limited knowledge of Firebug, however, I did find out that the following were the responses when I entered email and confirm_email in the fields: RESPONSE 1: {"success":"y","msg_email":"Email available"} RESPONSE 2: {"success":"y","msg_email":"Email available"}{"success":"n","msg_confirm_email":"Email and Confirm Email do NOT match."} Although the RESPONSE 2 shows that we are receiving the correct message via msg_confirm_email, in the front end, the alert 'Some error' is popping up (I have enabled the alert for debugging). I have spent 48 hours trying to change every part of the code wherever possible, but with only little success. What is weird about this is that if I comment the validation for $_POST['email'] field completely, then the validation for $_POST['confirm_email'] field is displaying correctly without any errors. If I enable it back, it is validating email field correctly, but when it reaches the point of validating confirm_email field, it is again showing me the error. I have also tried renaming success variable in check_ajax2.php page to other different names for both $_POST['email'] and $_POST['confirm_email'] but no success. I will be adding more fields in the form and validating within the check_ajax2.php page. So I am not planning on using different ajax pages for validating each of those fields (and I don't think it's smart to do it that way). I am not a jquery or AJAX guru, so all help in resolving this issue is highly appreciated. Thank you in advance.

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  • Modify MySQL INSERT statement to omit the insertion of certain rows

    - by dave
    I'm trying to expand a little on a statement that I received help with last week. As you can see, I'm setting up a temporary table and inserting rows of student data from a recently administered test for a few dozen schools. When the rows are inserted, they are sorted by the score (totpct_stu, high to low) and the row_number is added, with 1 representing the highest score, etc. I've learned that there were some problems at school #9999 in SMITH's class (every student made a perfect score and they were the only students in the district to do so). So, I do not want to import SMITH's class. As you can see, I DELETED SMITH's class, but this messed up the row numbering for the remainder of student at the school (e.g., high score row_number is now 20, not 1). How can I modify the INSERT statement so as to not insert this class? Thanks! DROP TEMPORARY TABLE IF EXISTS avgpct ; CREATE TEMPORARY TABLE avgpct_1 ( sch_code VARCHAR(3), schabbrev VARCHAR(75), teachername VARCHAR(75), totpct_stu DECIMAL(5,1), row_number SMALLINT, dummy VARCHAR(75) ); -- ---------------------------------------- INSERT INTO avgpct SELECT sch_code , schabbrev , teachername , totpct_stu , @num := IF( @GROUP = schabbrev, @num + 1, 1 ) AS row_number , @GROUP := schabbrev AS dummy FROM sci_rpt WHERE grade = '05' AND totpct_stu >= 1 -- has a valid score ORDER BY sch_code, totpct_stu DESC ; -- --------------------------------------- -- select * from avgpct ; -- --------------------------------------- DELETE FROM avgpct_1 WHERE sch_code = '9999' AND teachername = 'SMITH' ;

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  • checkbox, php and update mysql!

    - by Ronnie Chester Lynwood
    Hello now I got this form. i get values with "while": mysql_query("select * from mp3 where aktif = '0'"); <form name="form" method="post" action=""> <input type="text" size="10" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <textarea name="sarkisozu"><?=$haciosman['sarkisozu']?></textarea> <input type="text" name="a3" value="<?=$haciosman['ekleyen']?"> <input type="checkbox" name="onay[]" /> <input type="submit" name="0" id="0" value="Onayla" /> <form> and updating values with: <? if (isset($_POST['onay'])) { $cikti = mysql_query("update mp3 set aktif = '1', baslik = '$_POST[baslik]' where id = '$_POST[id]'"); if ($cikti) { echo "islem tamam"; exit; } } ?> but this code only updating only one value. how can i let it update multiple values?

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  • MYSQL join - reference external field from nested select?

    - by PHP thinker
    Is it allowed to reference external field from nested select? E.g. SELECT FROM ext1 LEFT JOIN (SELECT * FROM int2 WHERE int2.id = ext1.some_id ) as x ON 1=1 in this case, this is referencing ext1.some_id in nested select. I am getting errors in this case that field ext1.some_id is unknow. Is it possible? Is there some other way?

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  • PHP mySQL - select unique value that not being used from dirrefent table

    - by apis17
    Updates : Please see below i have table: data +-----------------------+--------------+-----------+ | State | d_country | d_postcode| +-----------------------+--------------+-----------+ | State1 | Country1 | 1111 | | State2 | Country2 | 2222 | | State3 | Country3 | 3333 | | State4 | Country4 | 4444 | +-----------------------+--------------+-----------+ And another table: user +-----------------------+--------------+-----------+ | Name | u_country | u_postcode| +-----------------------+--------------+-----------+ | Name1 | Country3 | 3333 | | Name2 | Country5 | 5555 | | Name3 | | 6666 | | Name4 | Country6 | 6666 | | Name5 | Country6 | 6666 | +-----------------------+--------------+-----------+ What SQL should i use to: Determine the number (count) of country that are not listed on table data. For example u_postcode is not listed in d_postcode is 5555 and 6666. It will return 2. List down name and what country not available in table data yet. Updates I want to use grouping to filter postcode and make Name3 and Name4 as different rows. For example: +-----------------------+--------------+-----------+ | Name | u_country | u_postcode| +-----------------------+--------------+-----------+ | Name2 | Country5 | 5555 | | Name3 | | 6666 | | Name4 | Country6 | 6666 | +-----------------------+--------------+-----------+ Any possible idea?

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  • Tricky MySQL Query for messaging system in Rails - Please Help

    - by ole_berlin
    Hi, I'm writing a facebook style messaging system for a Rails App and I'm having trouble selecting the Messages for the inbox (with will_paginate). The messages are organized in threads, in the inbox the most recent message of a thread will appear with a link to it's thread. The thread is organized via a parent_id 1-n relationship with itself. So far I'm using something like this: class Message < ActiveRecord::Base belongs_to :sender, :class_name => 'User', :foreign_key => "sender_id" belongs_to :recipient, :class_name => 'User', :foreign_key => "recipient_id" has_many :children, :class_name => "Message", :foreign_key => "parent_id" belongs_to :thread, :class_name => "Message", :foreign_key => "parent_id" end class MessagesController < ApplicationController def inbox @messages = current_user.received_messages.paginate :page => params[:page], :per_page => 10, :order => "created_at DESC" end end That gives me all the messages, but for one thread the thread itself and the most recent message will appear (and not only the most recent message). I can also not use the GROUP BY clause, because for the thread itself (the parent so to say) the parent_id = nil of course. Anyone got an idea on how to solve this in an elegant way? I already thought about adding the parent_id to the parent itself and then group by parent_id, but I'm not sure if that works. Thanks

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  • What does this MySQL statement do?

    - by user198729
    INSERT IGNORE INTO `PREFIX_tab_lang` (`id_tab`, `id_lang`, `name`) (SELECT `id_tab`, id_lang, (SELECT tl.`name` FROM `PREFIX_tab_lang` tl WHERE tl.`id_lang` = (SELECT c.`value` FROM `PREFIX_configuration` c WHERE c.`name` = 'PS_LANG_DEFAULT' LIMIT 1) AND tl.`id_tab`=`PREFIX_tab`.`id_tab`) FROM `PREFIX_lang` CROSS JOIN `PREFIX_tab`); It's from an opensource project,and no documentation available. Especially,what does cross-join mean? I've only used join/left join .

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  • Specific query in Mysql

    - by Radhe
    I have two tables reports and holidays. reports: (username varchar(30),activity varchar(30),hours int(3),report_date date) holidays: (holiday_name varchar(30), holiday_date date) select * from reports gives +----------+-----------+---------+------------+ | username | activity | hours | date | +----------+-----------+---------+------------+ | prasoon | testing | 3 | 2009-01-01 | | prasoon | coding | 4 | 2009-01-03 | | prasoon | designing| 2 | 2009-01-04 | | prasoon | coding | 4 | 2009-01-06 | +----------+-----------+---------+------------+ select * from holidays gives +--------------+---------------+ | holiday_name | holiday_date | +--------------+---------------+ | Diwali | 2009-01-02 | | Holi | 2009-01-05 | +--------------+---------------+ Is there any way by which I can output the following? +-------------+-----------+---------+-------------------+ | date | activity | hours | holiday_name | +-------------+-----------+---------+-------------------+ | 2009-01-01 | testing | 3 | | | 2009-01-02 | | | Diwali | | 2009-01-03 | coding | 4 | | | 2009-01-04 | designing| 2 | | | 2009-01-05 | | | Holi | | 2009-01-06 | coding | 4 | | +-------------+-----------+---------+-------------------+

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  • MySQL Select statement Where table1.id != table2.id

    - by Michael
    I have a table of data which has posts, then I have a separate table of data which has deleted posts. What happens when a post is deleted is that it's ID get's added to the deleted table rather than removing the post entry. What is a clean efficient way of selecting all the posts from the posts table without selecting the ones that have their ID in the deleted table

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  • mysql - joining three tables with HAVING

    - by Qiao
    I have table: id name type where "type" is 1 or 2 I need to join this table with two other. Rows with "type = 1" should be joined with first table, and =2 with second. Something like SELECT * FROM tbl INNER JOIN tbl_1 ON tbl.name = tbl_1.name HAVING tbl.type = 1 INNER JOIN tbl_2 ON tbl.name = tbl_2.name HAVING tbl.type = 2 But it does not working. How it can be implemented?

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  • Import CSV to mysql

    - by 404error
    I have created a database and table. I have also created all the fields i will be needing. I have created 46 fields including 1 that is my ID for the row. The CSV doesn't contain the id field, nor does it contain the headers for the columns. I am new to all of this but have been trying to figure this out. I'm not on here being lazy asking for the answer, but looking for direction. I'm trying to figure out how to import the CSV but have it start importing data starting at the 2nd field, since I'm hoping the auto_increment will fill in the ID field, which is the first field i created. I tried these instructions with now luck. Can anyone offer some insight? your cvs file's column name must match your table column name browse your required .csv file select CSV using LOAD DATA options Check box 'ON' for Replace table data with file in Fields terminated by box type , in Fields enclosed by box " in Fields escaped by box \ in Lines terminated by box auto in Column names box type column name seperated by , like column1,column2,column3 10 check box ON for Use LOCAL keyword.

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  • Data truncation when retrieving data from MySQL database with prepared statements

    - by KSiimson
    I have a script that retrieves multiple products using prepared statements. Like putting loops into loops, I have prepared statements in prepared statements - so there is a prepared statement for retrieving all products, a prepared statement to retrieve all images for that product, a prepared statement to get all attributes for that products, and so on. This does not work with one MySQLi instance, so I use multiple MySQLi objects that are opened and closed when needed. It usually works fine, but sometimes, especially when displaying multiple products, some data is truncated. For example - MicoLoans becomes MicoLoa. There was an actual spelling mistake here - now when I changed MicoLoans to MicroLoans, the same page displayed MicroLoa... So the same number of characters was truncated from the end. It is sort of consistent where it appears - for example there can be descriptions for 8 products, and description of 1 product is heavily truncated. When I add 9th product, the short description is still truncated for that same product as before. Any ideas?

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  • PHP MySQL INSERT fails due to unique constraint

    - by sjw
    On insert I am catching the unique constraint mysql_errno() 1062. This works fine but I want to find the existing row to re-instate or modify it. Is there are method to obtain the row id on insert fail? I tried mysql_insert_id() but realised that would only return the row I'm inserting (or failed to insert) therefore, I get 0. Is there no option but to issue another mysql_query and simply perform a select on the duplicate value? I just want to make sure there is no better, quicker, more economical way to do this.

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  • change column widths in mysql query

    - by addi
    <?php // Connection Database $search = $_POST ['Search']; mysql_connect("xxxxxx", "xxxxxxxxx", "xxxxxx") or die ("Error Connecting to Database"); mysql_select_db("xxxxxx") or die('Error'); $data = mysql_query("SELECT* FROM course WHERE MATCH (CourseName, CourseDescription, CourseLeader) AGAINST ('". $search ."')") or die (mysql_error()); Print "<table border cellpadding=3>"; while($info = mysql_fetch_array( $data )) { Print "<tr>"; Print "<th>Course Name:</th> <td>".$info['CourseName'] . "</td> "; Print "<th>Course Description:</th><td>".$info['CourseDescription'] . "</td> "; Print "<th>Course Leader:</th><td>".$info['CourseLeader'] . " </td></tr>"; } Print "</table>"; ?> In my php code I print the columns CourseName, CourseDescription, CourseLeader after a search, as a resultset. CourseDescription has a lot of text, how do I print it all? is there a way to change the column widths?

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  • MYSQL get the name from another table that is associated with the first table

    - by Juan Gonzales
    I can't figure out why this statement is not working SELECT myChurches.id AS id, myChurches.church_name AS church_name FROM myChurches INNER JOIN church_staff ON church_staff.church_id=myChurches.id WHERE church_staff.mem_id='$logOptions_id' ORDER BY myChurches.church_name ASC Basically I need to find the person's that are staff members of a church from one table and want to get the 'name' of that church FROM the 'myChurches' table. Hopefully that makes sense. Thanks in advance

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  • Php, mysql selection

    - by cosy
    I have this table ATTRIBUTE id name um 12 capacity MB;GB;TB And this table2 : id id_attribute id_product name value um 1 12 40 hdd maxtor 30 GB 2 12 41 hdd maxtor 40 GB 3 12 42 hdd y 1 TB How can i select from table2 in this order : 30GB 40GB 1TB? Thanks a lot!

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  • select query from mysql_num_rows

    - by Andi Nugroho
    i want create multiple search where statement $where_search is a multiple condition from post form. but stil error when iam using this code ".where_search." in where condition with mysql_num_rows for paging $tampil2 = mysql_query("SELECT * FROM bb where ".$where_search." and kd_kelompok='2' and kd_komoditi='11' and nm_sebutan IS NOT NULL " ); this is the complete code. $where_search = "kd_pok='2' and kd_komoditi='11' "; if (isset($_POST['lakpus'])) { if (empty($_POST['lakpus'])) { } else { if (empty($where_search)) { $where_search .= "lakpus = '$lakpus' "; } else { $where_search .= "AND lakpus = '$lakpus' "; } } } if (isset($_POST['kd_por'])) { $kd_por = $_POST['kd_por'] ; if (empty($_POST['kd_por'])) { } else { if (empty($where_search)) { $where_search .= "kd_por = '$kd_por' "; } else { $where_search .= "AND tab1.kd_por = '$kd_por' "; } } } $max=15; $tampil2 = mysql_query("SELECT * FROM bb where ".$where_search." and kd_kelompok='2' and kd_komoditi='11' and nm_sebutan IS NOT NULL " ); $jml = mysql_num_rows($tampil2); $jmlhal = ceil($jml/$max);

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  • Validating Login / Changing User settings / Php Mysql

    - by Marcelo
    Hi everyone, my questions are about login, and changing already saved data. (Q1) 'Till now I've only saved input in the tables of the database (registration steps), now I need to check if the input (login steps), are the same of my table in database, in fact I have 3 types of users, then I'll have to check 3 kind of tables. Then if the input data matches with one of those 3 tables I will redirect the user to his specific area. I'm thinking about saved the submitted data $login=$_REQUEST['login']; and $password=$_REQUEST['password']; and compare with the login column in the database. Then if the login matches, I'll compare the password submitted with the one in the row, not in the column. But I don't know how to do this search and comparison,neither what to use. Then if both matches I'll redirect the user. Else I'll send an login error message. (this I know how to do) (Q2) What if need to change an already saved user ? For example to change an email address. My changing user's data web page is exactly the same like the registration user web page. Can I load the already saved options and values of registration (table user for example). Then the user will change whatever he thinks it's necessary, and then when he submits the new information, they would not create a new row in my table, but just be overwritten the old information? How can I do this? Sorry for any mistake in English, and Thanks for the attention.

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  • mysql select from multiple table

    - by Loon Yew
    I have 3 tables with values like below tbl_product recID pID price colour 1 BDPLA-0001 1.23 White 2 BDPLA-0002 2.23 Black 3 BDPLA-0003 2.28 Blue tbl_product_size recID pID size stock 1 1 2.0cm 10 2 1 3.0cm 20 3 2 2.5cm 30 4 3 3.6cm 40 5 3 3.8cm 50 tbl_order_details recID pID quantity size 201 BDPLA-0001 5 2.0cm 202 BDPLA-0002 10 2.5cm tbl_product.recID = tbl_product_size.pID tbl_product.pID = tbl_order_details.pID how can i combine the tables and produce result like this pID size stock quantity price BDPLA-0001 2.0cm 10 5 1.23 BDPLA-0001 3.0cm 20 null 1.23 BDPLA-0002 2.5cm 30 10 2.23 BDPLA-0003 3.6cm 40 null 2.28 BDPLA-0003 3.8cm 50 null 2.28

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  • Retrieve part of a MySQL column with PHP

    - by Gerardo Marset
    For instance, if I have the following table: +----+---+----------+ | id | a | position | +----+---+----------+ | 0 | 0 | 0 | | 1 | 0 | 1 | | 2 | 1 | 4 | | 3 | 1 | 9 | | 4 | 1 | 6 | | 5 | 1 | 1 | +----+---+----------+ and I want to get an array that contains the first 100 values from position where a is 1 in ascending order, what would I do? Im guessing something like this: $col = mysql_fetch_array( mysql_query(' SELECT `position` FROM `table` WHERE `a`="1" ORDER BY `position` ASC LIMIT 100 ')); I'd expect to get the following array: +-------+-------+ | index | value | +-------+-------+ | 0 | 1 | | 1 | 4 | | 2 | 6 | | 3 | 9 | +-------+-------+ but it doesn't work. ¿What should I do to make it work? Thanks

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  • mysql display each day in a month

    - by Jason
    during a month, display the infor each date, order by date, but this infor is empty in some day. how can i still display each day as a row? Product date ----------------- 20 2008-01-01 10 2008-01-02 20 2008-01-03 10 2008-01-05 09 2008-01-08 30 2008-01-09 result: Product date ----------------- 20 2008-01-01 10 2008-01-02 20 2008-01-03 0 2008-01-04 10 2008-01-05 0 2008-01-06 0 2008-01-07 09 2008-01-08 30 2008-01-09

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