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  • Nested sql queries in rails when :has_and_belongst_to_many

    - by Godisemo
    Hello, In my application I the next task that has not already been done by a user. I have Three models, A Book that has many Tasks and then I have a User that has has and belongs to many tasks. The table tasks_users table contains all completed tasks so I need to write a complex query to find the next task to perform. I have came up with two solutions in pure SQL that works, but I cant translate them to rails, thats what I need help with SELECT * FROM `tasks` WHERE `tasks`.`book_id` = @book_id AND `tasks`.`id` NOT IN ( SELECT `tasks_users`.`task_id` FROM `tasks_users` WHERE `tasks_users`.`user_id` = @user_id) ORDER BY `task`.`date` ASC LIMIT 1; and equally without nested select SELECT * FROM tasks LEFT JOIN tasks_users ON tasks_users.tasks_id = task.id AND tasks_users.user_id = @user_id WHERE tasks_users.task_id IS NULL AND tasks.book_id = @book_id LIMIT 1; This is what I Have done in rails with the MetaWhere plugin book.tasks.joins(:users.outer).where(:users => {:id => nil}) but I cant figure out how to get the current user there too, Thanks for any help!

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  • Nested Select in Rails

    - by James
    I am working on a Rails application which uses categories for items. My category model is self-joined so that categories can be nested: class Category < ActiveRecord::Base has_many :items # Self Join (categories can have subcategories) has_many :subcategories, :class_name => "Category", :foreign_key => "parent_id" belongs_to :parent, :class_name => "Category" ... end I have a form which allows a user to create an item which currently lists all categories in a select, but they are all listed together: <%= f.label :category_id %> <%= select :item, :category_id, Category.all.collect {|c| [ c.title, c.id ]} %> So the select looks something like this: Category1 Category2 Category3BelongsTo2 Category4BelongsTo1 But what I want is: Category1 - Category4BelongsTo1 Category2 - Category3BelongsTo2 Is there a helper for this (which would be awesome!)? If not, how could I accomplish this? Thanks!

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  • Oracle/c#: How do i use bind variables with select statements to return multiple records?

    - by twiga
    I have a question regarding Oracle bind variables and select statements. What I would like to achieve is do a select on a number different values for the primary key. I would like to pass these values via an array using bind values. select * from tb_customers where cust_id = :1 int[] cust_id = { 11, 23, 31, 44 , 51 }; I then bind a DataReader to get the values into a table. The problem is that the resulting table only contains a single record (for cust_id=51). Thus it seems that each statement is executed independently (as it should), but I would like the results to be available as a collective (single table). A workaround is to create a temporary table, insert all the values of cust_id and then do a join against tb_customers. The problem with this approach is that I would require temporary tables for every different type of primary key, as I would like to use this against a number of tables (some even have combined primary keys). Is there anything I am missing?

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  • How to order results based on number of search term matches?

    - by Travis
    I am using the following tables in mysql to describe records that can have multiple searchtags associated with them: TABLE records ID title desc TABLE searchTags ID name TABLE recordSearchTags recordID searchTagID To SELECT records based on arbitrary search input, I have a statement that looks sort of like this: SELECT recordID FROM recordSearchTags LEFT JOIN searchTags ON recordSearchTags.searchTagID = searchTags.ID WHERE searchTags.name LIKE CONCAT('%','$search1','%') OR searchTags.name LIKE CONCAT('%','$search2','%') OR searchTags.name LIKE CONCAT('%','$search3','%') OR searchTags.name LIKE CONCAT('%','$search4','%'); I'd like to ORDER this resultset, so that rows that match with more search terms are displayed in front of rows that match with fewer search terms. For example, if a row matches all 4 search terms, it will be top of the list. A row that matches only 2 search terms will be somewhere in the middle. And a row that matches just one search term will be at the end. Any suggestions on what is the best way to do this? Thanks!

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  • Allowing New Users to Invite Their Gmail Contacts

    - by John
    Hello, For my site, I would like to give new users the option to invite all of their Gmail contacts to join. What is the basic step-by-step process to set this up? (Also, is it necessary to buy an SSL for this?) Thanks in advance, John EDIT: My site has a basic login where users set up a username and password. I would like to give users the option to invite their Gmail contacts right after they create their new profile. I would also like to give them the option to invite their Gmail contacts anytime they want.

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  • Doubt in Stored Procedure MySql - how to return multiple values for a variable ?

    - by Eternal Learner
    Hi, I have a stored procedure below. I intend this procedure to return the names of all the movies acted by an actor. Create Procedure ActorMovies( In ScreenName varchar(50), OUT Title varchar(50) ) BEGIN Select MovieTitle INTO Title From Movies Natural Join Acts where Acts.ScreenName = 'ScreenName '; End; I make a call like Call ActorMovies(' Jhonny Depp',@movie); Select @move; The result I get is a Null set , which is not correct.I am expecting a set of movies acted by Jhonny Depp to be returned. I am not sure as to why this is happening?

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  • How do I list all non-system stored procedures?

    - by bubbassauro
    I want to create a query to list of all user defined stored procedures, excluding the ones that are system stored procedures, considering that: Checking the name like "sp_" doesn't work because there are user stored procedures that start with "sp_". Checking the property is_ms_shipped doesn't work because there are system stored procedures that have that flag = 0, for example: sp_alterdiagram (it is not MSShipped but appears under System Stored Procedures in SQL Server Management Studio). There must be a property, or a flag somewhere since you can see the "System Stored Procedures" in a separate folder in SQL 2005. Does anyone know? Edit: A combination of the suggestions below worked for me: select * from sys.objects O LEFT OUTER JOIN sys.extended_properties E ON O.object_id = E.major_id WHERE O.name IS NOT NULL AND ISNULL(O.is_ms_shipped, 0) = 0 AND ISNULL(E.name, '') <> 'microsoft_database_tools_support' AND O.type_desc = 'SQL_STORED_PROCEDURE' ORDER BY O.name

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  • Converting MySQL Resultset from Rows to Columns

    - by gms8994
    I have output from a select like this: 04:47:37> select * from attributes left outer join trailer_attributes on attributes.id = trailer_attributes.attribute_id; +----+--------------+----------+-----------+------------+--------------+-----------------+ | id | name | datatype | list_page | trailer_id | attribute_id | attribute_value | +----+--------------+----------+-----------+------------+--------------+-----------------+ | 1 | Make | text | 1 | 1 | 1 | Apple | | 1 | Make | text | 1 | 2 | 1 | sdfg | | 2 | Year | number | 1 | 1 | 2 | 2009 | | 2 | Year | number | 1 | 2 | 2 | sdfg | | 3 | Type | text | 0 | 1 | 3 | iPhone | | 3 | Type | text | 0 | 2 | 3 | sdfg | | 4 | Axles | text | 0 | 1 | 4 | asdf | | 4 | Axles | text | 0 | 2 | 4 | sdfg | | 7 | Size | text | 0 | 1 | 7 | asd1 | | 7 | Size | text | 0 | 2 | 7 | sdfg | | 8 | Frame | text | 0 | 1 | 8 | | | 8 | Frame | text | 0 | 2 | 8 | sdfg | | 9 | Height | text | 0 | 1 | 9 | | | 9 | Height | text | 0 | 2 | 9 | sdfg | | 10 | Dollies | text | 0 | 1 | 10 | | | 10 | Dollies | text | 0 | 2 | 10 | sdfg | | 11 | Tires/Wheels | text | 0 | 1 | 11 | | | 11 | Tires/Wheels | text | 0 | 2 | 11 | sdfg | | 12 | Condition | text | 1 | 1 | 12 | New | | 12 | Condition | text | 1 | 2 | 12 | sdfg | | 13 | Title | text | 0 | 1 | 13 | | | 13 | Title | text | 0 | 2 | 13 | sdfg | +----+--------------+----------+-----------+------------+--------------+-----------------+ I want to convert it to something more along the lines of: id, Make, Year, Type, Axles, Size, Frame (etc) 1, Apple, 2009, iPhone, ..... 2, sdfg, sdfg, sdfg, ..... Any suggestions?

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  • Exception handling in Linq to SQL for customers without orders

    - by stackoverflowuser
    I have the following code to retrieve customer name, total (orders ), sum (order details) for reach customer in Northwind database. The problem with below code is that it raises an exception since a few customers dont have any entry in orders table. I know using the query syntax (join) the exception can be avoided. I want to know if the same can be handled with the extension method syntax. var customerOrders = db.Customers .Select(c => new { CompanyName = c.CompanyName, TotalOrders = c.Orders.Count(), TotalQuantity = c.Orders .SelectMany(o => o.Order_Details).Sum(o=>o.Quantity) });

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  • Normalise this Table?

    - by Abs
    Hello all, I am creating a social bookmarking app. I am having a re-thought of the DB design in the middle of development. Should I normalise the bookmarks table and remove the tag columns that I have into a separate table. I have 10 tags per bookmark and therefore 10 columns per record (per bookmark). It seems to me that breaking the table into two would just mean I would have to do a join but the way I currently have it, its a straight select - but the table doesn't feel right...? Thanks all

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  • how to get the checked id's and unchekced ids using jquery

    - by kumar
    Hello friends using this code I am to get only checked id $('#PbtnSubmit').click(function(event) { $('#PricingEditExceptions input[name=PMchk]').each(function() { if ($("#PricingEditExceptions input:checkbox:checked").length > 0) { var checked = $('#PricingEditExceptions input[type=checkbox]:checked'); var PMstrIDs = checked.map(function() { return $(this).val(); }).get().join(','); $('#1_exceptiontypes').attr('value', exceptiontypes) $('#1_PMstrIDs').attr('value', PMstrIDs); } else { alert("Please select atleast one exception"); event.preventDefault(); } }); }); the beginForm <% using (Html.BeginForm("MassUpdate", "Pricing", FormMethod.Post, new { @id = "exc-"})) I am perfectly getting all my chekced id's to the controler but I need to get both checked as well as uncheked ids' using above code? thanks

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  • Insert query results into table in ms access 2010

    - by CodeMed
    I need to transform data from one schema into another in an MS Access database. This involves writing queries to select data from the old schema and then inserting the results of the queries into tables in the new schema. The below is an example of what I am trying to do. The SELECT component of the below works fine, but the INSERT component does not work. Can someone show me how to fix the below so that it effectively inserts the results of the SELECT statement into the destination table? INSERT INTO CompaniesTable (CompanyName) VALUES ( SELECT DISTINCT IIF(a.FIRM_NAME IS NULL, b.SUBACCOUNT_COMPANY_NAME, a.FIRM_NAME) AS CompanyName FROM (SELECT ContactID, FIRM_NAME, SUBACCOUNT_COMPANY_NAME FROM qrySummaryData) AS a LEFT JOIN (SELECT ContactID, FIRM_NAME, SUBACCOUNT_COMPANY_NAME FROM qrySummaryData) AS b ON a.ContactID = b.ContactID ); The definition of the target table (CompaniesTable) is: CompanyID Autonumber CompanyName Text Description Text WebSite Text Email Text TypeNumber Number

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  • How to sum up an array of integers in C#

    - by Filburt
    Is there a better shorter way than iterating over the array? int[] arr = new int[] { 1, 2, 3 }; int sum = 0; for (int i = 0; i < arr.Length; i++) { sum += arr[i]; } clarification: Better primary means cleaner code but hints on performance improvement are also welcome. (Like already mentioned: splitting large arrays). It's not like I was looking for killer performance improvement - I just wondered if this very kind of syntactic sugar wasn't already available: "There's String.Join - what the heck about int[]?".

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  • CSS Positioning

    - by Davey
    Trying to mess with this wordpress theme and can't figure out why the sidebar is stacking underneath the content block. Any help would be very appreciated. http://www.buffalostreetbooks.com/events CSS: body { font-family: Arial, Helvetica, Verdana, Sans-serif; font-size: 10pt; background-color: #692022; background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/repeatflower.png"); } body,h1#blog-title { margin: 0; padding: 0; } a { color: blue; } a:hover { color: #FF8C00; } a img { border: 0 none; } #wrapper { width: 960px; margin: 0 auto; background-color: #F4FBF4; border-left: 1px solid #ccc; border-right: 1px solid #ccc; } #header { background-image:url("http://www.buffalostreetbooks.com/wp-content/themes/autumn-leaves/images/headertime.png"); width:768px; height: 200px; } #inner-header { padding: 125px 1em 0; } h1#blog-title { font-size: 2em; } h1#blog-title a { color: #800000; } .entry-title a { color: #CD853F; } h1#blog-title a, .entry-title a, #footer a { text-decoration: none; } h1#blog-title a:hover, .entry-title a:hover, #footer a:hover { text-decoration: underline; } div.skip-link { display: none; } #menu { border-bottom: 1px solid #ccc; } #menu a { color: #000; } #menu a:hover { text-decoration: underline; } #menu li.current_page_item a, #menu li.current_page_item a:hover { background-color: #DFC28B; text-decoration: none; } #content { padding: 1em; width:600px; } .entry-title { font-size: 1.5em; margin: 1em 0 0 0; } abbr.published { color: #666; border: 0 none; } .entry-meta, .entry-date { color: #666; } #comments-list .avatar { float: left; margin-right: 1em; } #comments-list .n { font-weight: bold; } .entry-meta, .comment-meta { font-style: italic; } #comments-list p { clear: left; } #primary { padding-left: 1em; font-size: 0.9em; border-left: 1px solid #ccc; border-bottom: 1px solid #ccc; background-color: #FFFACD; } #footer { text-align: center; font-size: 0.8em; border-top: 1px solid #ccc; border-bottom: 1px solid #ccc; margin-bottom: 1em; } #inner-footer { padding: 1em 0; } .entry-meta, .entry-meta a, .comment-meta, .comment-meta a, .sidebar, .sidebar a, #footer, #footer a { color: #666; } /* LAYOUT: Two-Column (Right) DESCRIPTION: Two-column fluid layout with one sidebars right of content */ div#container { margin:0 0 0 0; width:960px; height:100%; } div#content { margin:0 0 0 0; } div.sidebar { overflow:hidden; width:280px; min-height:500px; clear:both; } div#secondary { clear:right; } div#footer { clear:both; width:100%; } /* Just some example content */ div#menu { height:2em; width:100%; } div#menu ul,div#menu ul ul { line-height:2em; list-style:none; margin:0; padding:0; } div#menu ul a { display:block; margin-right:1em; padding:0 0.5em; text-decoration:none; } div#menu ul ul ul a { font-style:italic; } div#menu ul li ul { left:-999em; position:absolute; } div#menu ul li:hover ul { left:auto; } .entry-title,.entry-meta { clear:both; } div#primary { } form#commentform .form-label { margin:1em 0 0; } form#commentform span.required { background:#fff; color:#c30; } form#commentform,form#commentform p { padding:0; } input#author,input#email,input#url,textarea#comme nt { padding:0.2em; } div.comments ol li { margin:0 0 3.5em; } textarea#comment { height:13em; margin:0 0 0.5em; overflow:auto; width:66%; } .alignright,img.alignright{ float:right; margin:1em 0 0 1em; } .alignleft,img.alignleft{ float:left; margin:1em 1em 0 0; } .aligncenter,img.aligncenter{ display:block; margin:1em auto; text-align:center; } div.gallery { clear:both; height:180px; margin:1em 0; width:100%; } p.wp-caption-text{ font-style:italic; } div.gallery dl{ margin:1em auto; overflow:hidden; text-align:center; } div.gallery dl.gallery-columns-1 { width:100%; } div.gallery dl.gallery-columns-2 { width:49%; } div.gallery dl.gallery-columns-3 { width:33%; } div.gallery dl.gallery-columns-4 { width:24%; } div.gallery dl.gallery-columns-5 { width:19%; } div#nav-above { margin-bottom:1em; } div#nav-below { margin-top:1em; } div#nav-images { height:150px; margin:1em 0; } div.navigation { height:1.25em; } div.navigation div.nav-next { float:right; text-align:right; } div.sidebar h3 { font-size:1.2em; } div.sidebar input#s { width:7em; } div.sidebar li { list-style:none; margin:0 0 2em; } div.sidebar li form { margin:0.2em 0 0; padding:0; } div.sidebar ul ul { margin:0 0 0 2em; } div.sidebar ul ul li { list-style:disc; margin:0; } div.sidebar ul ul ul { margin:0 0 0 0.5em; } div.sidebar ul ul ul li { list-style:circle; } div#menu ul li,div.gallery dl,div.navigation div.nav-previous { float:left; } input#author,input#email,input#url,div.navigation div { width:50%; } div.gallery *,div.sidebar div,div.sidebar h3,div.sidebar ul { margin:0; padding:0; }

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  • Type or namespace name could not be found

    - by Pandiya Chendur
    I use this: public IQueryable<MaterialsView> FindAllMaterials() { var materials = from m in db.Materials join Mt in db.MeasurementTypes on m.MeasurementTypeId equals Mt.Id select new MaterialsView { MatId = m.Mat_Name, MesName = Mt.Name, MesType = m.Mat_Type }; return materials; } It gives me the following errors: The type or namespace name MaterialsView could not be found (are you missing a using directive or an assembly reference?) Cannot implicitly convert type System.Collections.Generic.IEnumerable<MaterialsView> to System.Linq.IQueryable<MaterialsView>. An explicit conversion exists (are you missing a cast?) The type arguments for method System.Linq.Enumerable.ToList<TSource>(System.Collections.Generic.IEnumerable<TSource>) cannot be inferred from the usage. Try specifying the type arguments explicitly. I have googled it and found this SO question but it doesn't help. What's wrong?

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  • The use of GROUP BY in MySQL

    - by Gustav Bertram
    I'm fishing for a comprehensive and canonical answer for the typical "mysql group by?" question. Here is some sample data: TABLE A +------+------+----------+-----+ | id | foo | bar | baz | +------+------+----------+-----+ | 1 | 1 | hello | 42 | | 2 | 0 | apple | 96 | | 3 | 20 | boot | 11 | | 4 | 31 | unicorn | 99 | | 5 | 19 | pumpkin | 11 | | 6 | 88 | orange | 13 | +------+------+----------+-----+ TABLE B +------+------+ | id | moo | +------+------+ | 1 | 1 | | 2 | 99 | | 3 | 11 | +------+------+ Demonstrate and explain the correct use of the GROUP BY clause in MySQL. Touch upon the following points: The use of MIN, MAX, SUM, AVG The use of HAVING Grouping by date, and ranges of dates Grouping with an ORDER BY Grouping with a JOIN Grouping on multiple columns Bonus points for references to other great answers, the MySQL online manual, and online tutorials on GROUP BY.

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  • VendInvoiceJour.InvoiceAccount <- VendTable.AccountNum relation

    - by vukis
    Hi. I have following situation: I need to join VendInvoiceJour.InvoiceAccount <- VendTable.AccountNum and take VendTable.Vendgroup. In all cases (queries,or even views) Dynamics ax joins tables VendInvoiceJour.OrderAccount<- VendTable.AccountNum not VendInvoiceJour.InvoiceAccount <- VendTable.AccountNum. I`m trying to use this kind of query: qBdSVendJour = element.query().dataSourceTable(tablenum(VendInvoiceJour)); qBdSVendTbl = qBdSVendJour.addDataSource(tablenum(VendTable)); qBdSVendTbl.relations(true); qBdSVendTbl.joinMode(JoinMOde::InnerJoin); qBdSVendTbl.fetchMode(QueryFetchMode::One2One); qBdSVendTbl.addLink(FieldNum(VendInvoiceJour,InvoiceAccount),FieldNum(VendTable,AccountNum));//(Dynamics ax automaticaly corrects InvoiceAccount to orderaccount in reports if trying this link in morphx)

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  • SQL query not taking values more than 2100

    - by user175084
    SELECT MachineID, MachineName, count(ID) as Total, sum(Size) as TotalSize FROM Files join Machines on Files.MachineID = Machines.MachineID Where Files.MachineID In(sql.Append(string.Format("@MachineId{0}", i)); group by Files.MachineID,MachineName now when the machinId count is less than 2100 the query is performed and if it machines go above 2100 an error is thrown Error: The incoming tabular data stream (TDS) remote procedure call (RPC) protocol stream is incorrect. Too many parameters were provided in this RPC request. The maximum is 2100. how do i make increase the limit or just avoid getting this error.. and put values in gridview thanks..

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  • general things developer must know having 2+ years of exp?

    - by Salil
    Hi All, I have 2 years of experience in Ruby on Rails. I have basic knowledge (Very Basic) of mysql such as data insertion, join, select from more than one table. But now i want to know more about it cause my friends are having trouble in interview when ask questions like 1] What is the trigger. 2] which trigger call when 3] what's views in mysql? etc....... are this questions for developers?is it basic database? Also what other things developer should know having experience of 2 years or more. I am in double mind as i have over two years of exp. in ruby and i am learning new thing everyday in ruby only. if someone ask me to rate yourself i can't give more than 5 out of 10 in ROR only. So my question is What are the general things developer must know having 2+ years of exp? Regards, Salil Gaikwad

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  • Using Routing helpers in a Rake task

    - by trobrock
    I have a rake task that sends out the next 'x' invitations to join a beta it uses this code: desc "This will send out the next batch of invites for the beta" task :send_invites => :environment do limit = ENV['limit'] c = 0 invitation = Invitation.all(:conditions => { :sent_at => nil, :sender_id => nil }, :limit => limit).each do |i| Mailer.deliver_invitation(i, register_url(i.token)) c.increment! end puts "Sent #{c} invitations." end I need to pass in the 'register_url' to the Mailer in order for the link to show up in the email, but since this is running from a rake task and not from a request it does not have a access to the helper methods. What is the best way of achieving this?

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  • MySQL, how can I SELECT WHERE one field value doesn't occurs in another?

    - by Jules
    I'm trying to do a search on my test server, speed isn't so important. I want to find if a phrase, the whole contents of one field, occurs in any part (as a whole) doesn't occur in another field. Heres my current query which finds if the phrase does occur SELECT pads.padid, pads.programname, keywords.word FROM Pads JOIN keywords ON Pads.Padid = keywords.Padid WHERE pads.Programname = keywords.word AND RemoveMeDate = '2001-01-01 00:00:00' My problem is that the field word contains other words too. I need to produce a count of where there isn't a keywords record with keywords.word equal to pads.programname ? EDIT: So if I have these records Pads: PadID=3 ProgramName=my prog PadID=4 ProgramName=Bad prog PadID=5 ProgramName=Good prog PadID=6 ProgramName=other prog Keywords: PadID=3 word=fox prog PadID=3 word=pig prog PadID=4 word=big prog PadID=4 word=nice prog PadID=5 word=fox prog PadID=6 word=bad prog PadID=6 word=fox prog The query I want would retun a count of 3 and record 6 has bad prog

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  • Best way to construct this query?

    - by Andrew
    I have two tables set up similar to this (simplified for the quest): actions- id - user_id - action - time users - id - name I want to output the latest action for each user. I have no idea how to go about it. I'm not great with SQL, but from what I've looked up, it should look something like the following. not sure though. SELECT `users`.`name`, * FROM users, actions JOIN < not sure what to put here > ORDER BY `actions`.`time` DESC < only one per user_id > Any help would be appreciated.

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  • DataMapper: using auto_migrate! with many-to-many dependencies?

    - by pschuegr
    Hi, I'm trying to migrate my app from MySql to Postgresql, using Rails3-pre and the latest DataMapper. I have several models which are related through many-to-many relationships using :through = Resource, which means that DataMapper creates a join table with foreign keys for both models. I can't auto_migrate! these changes, because I keep getting this: ERROR: cannot drop table users because other objects depend on it DETAIL: constraint artist_users_owner_fk on table artist_users depends on table users constraint site_users_owner_fk on table site_users depends on table users HINT: Use DROP ... CASCADE to drop the dependent objects too. I have tried everything I can think of, and thought I had things working when I added :constraint = :skip to the field definition, but I keep getting that error back when I try and run auto_migrate. I thought that :skip meant that it would ignore the dependents, but maybe that only applies for deleting rows and not dropping tables? I should mention that I can run auto_migrate after i nuke the db once, but after that, errors. Any suggestions or advice much appreciated.

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  • I want to get 2 values returned by my query. How to do, using linq-to-entity

    - by Shantanu Gupta
    var dept_list = (from map in DtMapGuestDepartment.AsEnumerable() where map.Field<Nullable<long>>("GUEST_ID") == DRowGuestPI.Field<Nullable<long>>("PK_GUEST_ID") join dept in DtDepartment.AsEnumerable() on map.Field<Nullable<long>>("DEPARTMENT_ID") equals dept.Field<Nullable<long>>("DEPARTMENT_ID") select new { dept_id=dept.Field<long>("DEPARTMENT_ID") ,dept_name=dept.Field<long>("DEPARTMENT_NAME") }).Distinct(); DataTable dt = new DataTable(); dt.Columns.Add("DEPARTMENT_ID"); dt.Columns.Add("DEPARTMENT_NAME"); foreach (long? dept_ in dept_list) { dt.Rows.Add(dept_[0], dept_[1]); } EDIT In the previous question asked by me. I got an answer like this for single value. What is the difference between the two ? foreach (long? dept in dept_list) { dt.Rows.Add(dept); }

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  • Rails Metaprogramming: How to add instance methods at runtime?

    - by Larry K
    I'm defining my own AR class in Rails that will include dynamically created instance methods for user fields 0-9. The user fields are not stored in the db directly, they'll be serialized together since they'll be used infrequently. Is the following the best way to do this? Alternatives? Where should the start up code for adding the methods be called from? class Info < ActiveRecord::Base end # called from an init file to add the instance methods parts = [] (0..9).each do |i| parts.push "def user_field_#{i}" # def user_field_0 parts.push "get_user_fields && @user_fields[#{i}]" parts.push "end" end Info.class_eval parts.join

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