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• How to setup Xcode 3.1.4 with Perforce ?

  - by Azeworai

  Hi everyone, I've been trying to setup Xcode with Perforce for about 7 hours now and managed to get the Perforce Repository Authenticated within Xcode. The problem I have is, within the repositories window, I don't see any directories for me to check out. I can see the p4root login and client are ok with the tick on the repository log. When I try to Import an xcode project directory within the Perforce root directory- the import fails with '/Users/jackson/p4root/alpha/MessageTapper' is not under the Perforce root. I have p4d running on the local machine, and have created a user and workspace. The workspace has the directories in view. I'm hoping for someone to give me some direction or maybe point me to a good reference to how to set perforce up with xcode. Thanks!

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• Need help with this Regex + UrlRewriter.NET please :)

  - by Pure.Krome

  Previously, on StackOverflow ... (Summarized) I need to capture all requests, for a particluar subdomain .. and rewrite their destination. Now, the trick to determining the host via regex was solved. Now, i need to make sure all requests to the root index page is rewritten, but i can't figure out the correct regex to find the 'homepage' / website root. this is what i have.... <if header="HTTP_HOST" match="^foo\.mydomain\.com\.au(?::\d+)?/?$"> <!-- snip some other rewrites, eg./buying/product -> ~/Pages/Foo/Bar.aspx --> <rewrite url="^/$" to="~/Pages/SomeWeirdFolder/Home.aspx" processing="stop"/> </if> Now if one of the rewrites were not found, then it falls through and continues. So .. can anyone please help?

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• log4j.xml not found

  - by Farid

  Hi , How can we specify were log4j has to look at when trying to find its xml configuration file ? It seems that by default, log4j looks into the root of a class folder, I can say that using the debug log4j functionality and running my application from the IDE. However, I don't have any class folder in my jar anymore. And the log4j.xml file is at the root of the jar. I have already tried to set the option -Dlog4j.configuration=log4j.xml but it doesn't work. Thanks !

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• Freebsd write access to group directory

  - by Nikolay Sergeev

  Hi. I'm confused. I have two users in system: u1 and u2, and group u1. both u1 and u2 belong to g1. I've created directory /opt/d with properties: drwxrwxr-x 2 u1 u1 512B May 26 17:55 d AFAIK, this configuration allows both users write to directory. But, from u2: touch /opt/d/x touch: /opt/d/x: Permission denied And same configuration on RHEL5 works fine. What i've missed? Thanks.

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• error in qemu monitor wavcapture with virsh

  - by Aniket Awati

  I have VM running on qemu-kvm. I am managing it with libvirt and command line tool virsh. I want to record the audio output of the VM. Here is what I am trying - virsh qemu-monitor-command -hmp VM_NAME wavcapture VM.wav This is the output I am getting : Failed to open wave file `vm.wav' Reason: Permission denied Failed to add wave capture I have tried to create a dummy vm.wav with 777 permissions. But I still get the same error.

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• Wicket app in embedded Jetty causes UnsupportedClassVersionError

  - by Ondra Žižka

  I've tried to run a Wicket app in an embedded Jetty, using this code: public static void main( String[] args ){ Server server = new Server(8080); Context root = new Context( server, "/", Context.SESSIONS ); FilterHolder filterHolder = new FilterHolder( new WicketFilter() ); filterHolder.getInitParameters().put("applicationClassName", cz.dw.test.WicketApplication.class.getName() ); root.addFilter( filterHolder, "/*" , Handler.ALL ); try { server.start(); } catch (Exception ex) { ex.printStackTrace(); } } But I got java.lang.UnsupportedClassVersionError: Bad version number in .class file. Switching the target class version for my app (1.6 - 1.5) did not help. I use Sun JDK 1.6.0_17, Wicket 1.4.8, Jetty 6.1.24. I tried to debug, but the JRE classes have no debug data. The stacktrace is of no use as it happens when loading the classes into JVM. Any ideas what could be wrong? How can I find which class is causing this? Thanks, Ondra

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• Parsing log files in a folder in ColdFusion

  - by Simon Guo

  The problem is there is a folder ./log/ containing the files like: jan2010.xml, feb2010.xml, mar2010.xml, jan2009.xml, feb2009.xml, mar2009.xml ... each xml file would like: <root><record name="bob" spend="20"></record>...(more records)</root> I want to write a piece of ColdFusion code (log.cfm) that simply parsing those xml files. For the front end I would let user to choose a year, then the click submit button. All the content in that year will be show up in separate table by month. Each table shows the total money spent for each person. like: person cost bob 200 mike 300 Total 500 Thanks.

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• Getting Bad file descriptor when running Tornado AsyncHTTPTestCase

  - by Will

  When running a test using the Tornado AsyncHTTPTestCase I'm getting a stack trace that isn't related to the test. The test is passing so this is probably happening on the test clean up? I'm using Python 2.7.2, Tornado 2.2. The test code is: class AllServersHandlerTest(AsyncHTTPTestCase): endpoint = AllServersHandler.endpoint # '/rest/test/' def test_server_status_with_advertiser(self): on_new_host(None, '127.0.0.1') response = self.fetch(self.endpoint, method='GET') result = json.loads(response.body, 'utf8').get('data') self.assertEquals(['127.0.0.1'], result) The test passes ok, but I get the following stack trace from the Tornado server. OSError: [Errno 9] Bad file descriptor INFO:root:200 POST /rest/serverStatuses (127.0.0.1) 0.00ms DEBUG:root:error closing fd 688 Traceback (most recent call last): File "C:\Python27\Lib\site-packages\tornado-2.2-py2.7.egg\tornado\ioloop.py", line 173, in close os.close(fd) OSError: [Errno 9] Bad file descriptor Any ideas how to cleanly shutdown the test case?

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• Drupal: installing it in a subfolder...

  - by Patrick

  hi, this is a question about drupal installation on server. I usually upload my drupal into a subfolder "drupal" and I ask my customers to check the website in such subfolders until when it is ready. Then I asl to change the default folder in Apache to the "drupal" one. Sometimes my customer cannot change Apache configuration, so I was wondering if I can use a php script to forward users from root folder to the drupal one, or I should move the website to the root folder (which I would prefer to avoid, because is time consuming). thanks

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• Starting synergy automatically on RHEL/CentOS

  - by Matt

  I have a Red Had Enterprise Linux 5 and a CentOS 5 box, both of which I am trying to configure to automatically connect to a synergy server on startup. I have followed the guide at http://synergy2.sourceforge.net/autostart.html and configured them the same way I configured previous Ubuntu 7.10 boxes, and this only seems to get me half way there. Currently, synergy connects at the login screen, but once I login, it doesn't come back up. I added the following lines to /etc/gdm/{Init,PostLogin,PreSession}/Default : /usr/bin/killall synergyc sleep 1 /usr/bin/synergyc fried-chicken # Init,PreSession only All files are owned by root:root with 755 permissions, I'm just not sure what I'm missing here.

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• Possible to mount an ext4 partition image via FUSE?

  - by Catskul

  I'm attempting to mount an ext4 partition image in userspace. (no sudo, no special config/permissions modification to /dev/loop0 or /etc/fstab etc). So I'm hoping FUSE will come to the rescue. However it seems that each file system mounted through the FUSE system needs to have a special FUSE driver, and I've not been able to find a linux read-write ext4 FUSE driver for linux. Is there a way to mount ext4 images via FUSE (with write permission)?

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• Mail Permissions on a File Server Resource Manager Server

  - by JohnyV

  In 2008 server the File resource manager can be set up to alert users when they go over their quota etc. This is all configured however the email notifications are not working. They have been configured but the event log shows that the user does not have permission to send to the exchange server. There isnt an option to chosse who to send the email from. Is there a way to get this to work? Thanks

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• how to embed flash that is trying to access xml in it's original folder.

  - by mkprogramming

  I've got various flash files stored on my server. For this exmaple - here is the directory structure: Files Example - example.swf - example.xml So then on a separate webpage stored in the root of my server.. i'm embeding the flash. ... <param name="movie" value="http://www.example.com/Files/Example/example.swf"> ... Now the issue comes. Because the .swf is trying to access example.xml ... which is NOT stored in the root directory. How can I fix this problem? (I'd rather not use an iframe)

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• using php to check if xml is atom or rss

  - by guest86

  i'm writing a php code which has to determine if given xml is in "atom" or "rss" format. After observing atom and rss xml files, i decided classify xml based on a root element. If root element is "<feed" it's an atom xml. If it's "<rss" it's not an atom. How can i perform that check using DOM? So far i have: $dom->loadXML($resp); $feed = $dom->getElementsByTagName("feed"); but it's not working quite right....

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• find . -exec grep -l 'string' {} \; -print 2>/dev/null

  - by 01010101

  it lists all files in "." that contain the string "string" but don't show dirs with permission denied. What would it be the equivalent of that but squeezing xargs in between?

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• Can the users can apply Windows update without local administrator rights?

  - by AAA-Super

  My users are running on windows XP 32bit. normally WSUS automatically download and notify them to select which update want to install in the past they were in local administrator rights,now I reduce them to user rights so now they can't see the yellow notification said updated are available. Is there a way to give users permission to see the yellow notification and they can select updates by hand without local admin rights or power users? Any advice would be appreciated Thanks

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• XPath: How to check multiple attributes across similar nodes

  - by Justin

  Hi, If I have some xml like: <root> <customers> <customer firstname="Joe" lastname="Bloggs" description="Member of the Bloggs family"/> <customer firstname="Joe" lastname="Soap" description="Member of the Soap family"/> <customer firstname="Fred" lastname="Bloggs" description="Member of the Bloggs family"/> <customer firstname="Jane" lastname="Bloggs" description="Is a member of the Bloggs family"/> </customers> </root> How do I get, in pure XPath - not XSLT - an xpath expression that detects rows where lastname is the same, but has a different description? So it would pull the last node above? Thanks a mill if you can help, been scratching at it for ages, and I can't find it by searching (apologies if it is) Cheers, J

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• Java xsd validation of xml without namespace

  - by Darkflare

  Hi, I want to validate an xml file against an xsd schema. The xml files root element does not have any namespace or xsi details. It has no attributes so just . I have tried the following code from http://www.ibm.com/developerworks/xml/library/x-javaxmlvalidapi.html with no luck as I receive cvc-elt.1: Cannot find the declaration of element 'root' SchemaFactory factory = SchemaFactory.newInstance("http://www.w3.org/2001/XMLSchema"); File schemaFile = new File("schema.xsd"); Schema xsdScheme = factory.newSchema(schemaFile); Validator validator = xsdScheme.newValidator(); Source source = new StreamSource(xmlfile); validator.validate(source); The xml validates fine with the namespace headers included etc (added via xmlspy), but I would have thought the xml namespace could be declared without having to manually edit the source file?

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• Why assign write and execute permissions to a group when executing web scripts?

  - by PeanutsMonkey

  If I have a script that is to be executed by the nobody user, why is there a need to assign group write and execute permissions. For example in the article at http://www.zzee.com/solutions/unix-permissions.shtml, it notes that the permission 755 should be assigned to scripts on a web server. I understand that the user nobody is treated as others and as the owner of the script I would like full permissions. Am I missing something?

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• How can I create the XML::Simple data structure using a Perl XML SAX parser?

  - by DVK

  Summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog—due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. I'm looking for an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is; e.g whether I need to call next_record() or give it a callback coderef accepting a record.

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• Show UIView for app presentation only once in iOS

  - by André Muniz

  I need to show an UIScrollView with some pages for present the app to user when launched for the first time. My slides are working correctly, lefting the logic to present it. Is a good practice to set the UIScrollViewController as root controller and set a NSUserDefault variable to control the presentation and redirect to main controller or set the main ViewController as root normally and call the presentation view if needed is a better approach? If there is a better way to do this can someone help? Thanks.

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• XSLT Transforming sequential XML to hierarchical XML

  - by Jean-Paul Smit

  I have a requirement to transform a sequential XML node list into a hierarchical, but I run into some XSLT specific knowledge gap. The input XML contains articles, colors and sizes. In the sample below 'Record1' is an article, 'Record2' represents a color and 'Record3' are the sizes. The number of colors and sizes (record2 and record3) elements can vary. <root> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record1>...</Record1> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record2>...</Record2> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> <Record3>...</Record3> </root> All fields are on the same hierarchical level, but still I have to create this structure as output: <root> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> <article> -> Record1 <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> <color> -> Record2 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 <size>...</size> -> Record3 </color> </article> </root> I've tried to iterate the nodes sequentially but for example the 'article' (=record1) node tag needs to remain unclosed while 'color' (=record2) nodes are processed. The same counts for processing 'size' (=record3) having 'color' unclosed, but that is not allowed by XSLT. My next idea was to call a template for every article, color and size level, but I don't know how to select for example all 'record3' nodes between the current 'record2' and the next article represented by 'record1'. I've also got a limitation on the XSLT version because I need this transformation in BizTalk Server which only supports XSLT 1.0 Can someone push me in the right direction?

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• Firefox why window.opener is defined even for a new tab

  - by jonny

  Hi! I am porting quite old corp application from IE to Firefox. Here is my situation. User goes away from computer for a while and his session becomes expired. When user tries to access something in popup, he is being redirected to login page (in popup window). In login page onload event popup window chain is being closed and root page refreshed (in root page tab user is redirected to login page). The guy before me wrote this like this: if window.top.opener is undefined, we're not in popup. That's why I am getting non-stoppable refresh in Firefox. Why in Firefox window.opener is still defined and points to same window, even if this is a new tab, not popup? How should I correctly determine that current window is popup?

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• Python, how to tell if screen is running.

  - by Joe Spoon

  Hello, I am very new to programming and am trying to run a python code to see if the screen program is running and if it is then to not run the rest of the code. This is what I have and it's not working. !/usr/bin/python import os var1 = os.system ('screen -r /root/screenlog/screen.log') fd = open("/root/screenlog/screen.log") content = fd.readline() while content: if content == "There is no screen to be resumed.": os.system ('/etc/init.d/tunnel.sh') print "The tunnel is now active." else: print "The tunnel is running." fd.close() I know there are probably several things here that don't need to be and quite a few that I'm missing. I will be running this program in cron. Thanks for any help.

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• how do i supply data to my gwt tree

  - by molleman

  Hello, So i need to create a tree with tree items for my gwt project. i am using the composite pattern to store all the information i need to be placed within a tree. A User has a root Folder that extends Hierarchy, this root Folder then has a list of Hierarchy objects, that can be FileLocations or Folders. Trouble i am having is building my tree based on this pattern. this data is all stored using hibernate in a mysql database How would i be able to implement this as a tree in gwt. Also the tree item that i create would have to reference back to the object so i can rename or move it.

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