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  • How do I use a ListProperty(users.user) in a djangoforms.ModelForm on Google AppEngine?

    - by Gabriel
    I have been looking around a bit for info on how to do this. Essentially I have a Model: class SharableUserAsset(db.Model): name = StringProperty() users = ListProperty(users.User) My questions are: What is the best way to associate users to this value where they are not authenticated, visa vi invite from contacts list etc.? Is there a reasonable way to present a list control easily in a djangoforms.ModelForm? Once a user logs in I want to be able to check if that user is in the list for any number of SharableUserAsset class "records", how do I do that? Does user evaluate as a match to an email address or is there a way to look up a valid user against an email address?

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  • How do I make the following interaction with mySQL more efficient?

    - by Travis
    I've got an array that contains combinations of unique MySql IDs: For example: [ [1,10,11], [2,10], [3,10,12], [3,12,13,20], [4,12] ] In total there are a couple hundred different combinations of IDs. Some of these combinations are "valid" and some are not. For example, [1,10,11] may be a valid combination, whereas [3,10,12] may be invalid. Combinations are valid or invalid depending on how the data is arranged in the database. Currently I am using a SELECT statement to determine whether or not a specific combination of IDs is valid. It looks something like this: SELECT id1 FROM table WHERE id2 IN ($combination) GROUP BY id1 HAVING COUNT(distinct id2) = $number ...where $combination is one possible combination of IDs (eg 1,10,11) and $number is the number of IDs in that combination (in this case, 3). An invalid combination will return 0 rows. A valid combination will return 1 or more rows. However, to solve the entire set of possible combinations means looping a couple hundred SELECT statements, which I would rather not be doing. I am wondering: Are there any tricks for making this more efficient? Is it possible to submit the entire dataset to mySQL in one go, and have mySQL iterate through it? Any suggestions would be much appreciated. Thanks in advance!

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  • Handling data update/freshness issue in web-app in general (or GWT specifically)

    - by edwin.nathaniel
    In general, how do you guys handle user update/data freshness interaction with the user (UI issue) in web-apps? For example: Multi-users web-app (like project management) Login to a "virtual" space People can update project names, etc How to handle a situation such that: user-A and user-B load a project with title "Project StackOverflow" user-B updates the title to "Project StackExchange" user-A updates the title after user-B update operation to "Project Basecamp" The question I'm asking is from the user perspective (UI) and not about transactional operation. What do most people do in this situation? What would you do after user-B updates the title in user-A screen/view? What happened when user-A tries to update the title after user-B finished his/her update operation? do you inform user-A that the title has changed and he/she has to reload the page? do you go ahead and change the title and let user-B has old data? Do you do some sort of application-level "locking" mechanism? (if someone is updating, nobody else can?) Or fix the application workflow? (who has the access to be able to change things, etc). What would be the simplest solution, but at the same time not annoy the user with more dialog/warning messages. I've encountered this particular problem frequently in a GWT app specifically where domain models are being passed around and refreshing the whole app/client-side isn't the optimal solution in my mind (since it means the whole "loading"/initialization phase must be executed again in this specific environment). Maybe the answer is to stay away from GWT? :) Love to hear options, solutions, and advises from you guys. Thanks

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  • backbone.js Model.get() returns undefined, scope using coffeescript + coffee toaster?

    - by benipsen
    I'm writing an app using coffeescript with coffee toaster (an awesome NPM module for stitching) that builds my app.js file. Lots of my application classes and templates require info about the current user so I have an instance of class User (extends Backbone.Model) stored as a property of my main Application class (extends Backbone.Router). As part of the initialization routine I grab the user from the server (which takes care of authentication, roles, account switching etc.). Here's that coffeescript: @user = new models.User @user.fetch() console.log(@user) console.log(@user.get('email')) The first logging statement outputs the correct Backbone.Model attributes object in the console just as it should: User _changing: false _escapedAttributes: Object _pending: Object _previousAttributes: Object _silent: Object attributes: Object account: Object created_on: "1983-12-13 00:00:00" email: "[email protected]" icon: "0" id: "1" last_login: "2012-06-07 02:31:38" name: "Ben Ipsen" roles: Object __proto__: Object changed: Object cid: "c0" id: "1" __proto__: ctor app.js:228 However, the second returns undefined despite the model attributes clearly being there in the console when logged. And just to make things even more interesting, typing "window.app.user.get('email')" into the console manually returns the expected value of "[email protected]"... ? Just for reference, here's how the initialize method compiles into my app.js file: Application.prototype.initialize = function() { var isMobile; isMobile = navigator.userAgent.match(/(iPhone|iPod|iPad|Android|BlackBerry)/); this.helpers = new views.DOMHelpers().initialize().setup_viewport(isMobile); this.user = new models.User(); this.user.fetch(); console.log(this.user); console.log(this.user.get('email')); return this; }; I initialize the Application controller in my static HTML like so: jQuery(document).ready(function(){ window.app = new controllers.Application(); }); Suggestions please and thank you!

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  • Administrators vs Programmers: Who's got more people Interaction / Working hours?

    - by sanksjaya
    Well, I've heard programmers get to interact with other programmers quiet a lot. But, who gets to meet a lot of new people on a daily basis at work without getting the feeling "Goosh! I'm stuck with him/this for another year :(" - Admins or Coders? And what kind of people domain do each get to interact with? Secondly, I've had this myth for a long time that unlike programmers, Network/System/Security Admins get locked-up in a den and juiced up late nights and early mornings. Most of the time they had to slip out of work without being noticed. But recently one of my seniors from my grad school told he had to work late and on weekends for a product release. How true and often does this happen with programmers and admins?

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  • "Attach or Add an entity that is not new...loaded from another DataContext. This is not supported."

    - by sah302
    Similar error as other questions, but not quite the same, I am not trying to attach anything. What I am trying to do is insert a new row into a linking table, specifically UserAccomplishment. Relations are set in LINQ to User and Accomplishment Tables. I have a generic insert function: Public Function insertRow(ByVal entity As ImplementationType) As Boolean If entity IsNot Nothing Then Dim lcfdatacontext As New LCFDataContext() Try lcfdatacontext.GetTable(Of ImplementationType)().InsertOnSubmit(entity) lcfdatacontext.SubmitChanges() lcfdatacontext.Dispose() Return True Catch ex As Exception Return False End Try Else Return False End If End Function If you try and give UserAccomplishment the two appropriate objects this will naturally crap out if either the User or Accomplishment already exist. It only works when both user and accomplishment don't exist. I expected this behavior. What does work is simply giving the userAccomplishment object a user.id and accomplishment.id and populating the rest of the fields. This works but is kind of awkward to use in my app, it would be much easier to simply pass in both objects and have it work out what already exists and what doesn't. Okay so I made the following (please ignore the fact that this is horribly inefficient because I know it is): Public Class UserAccomplishmentDao Inherits EntityDao(Of UserAccomplishment) Public Function insertLinkerObjectRow(ByVal userAccomplishment As UserAccomplishment) Dim insertSuccess As Boolean = False If Not userAccomplishment Is Nothing Then Dim userDao As New UserDao() Dim accomplishmentDao As New AccomplishmentDao() Dim user As New User() Dim accomplishment As New Accomplishment() 'see if either object already exists in db' user = userDao.getOneByValueOfProperty("Id", userAccomplishment.User.Id) accomplishment = accomplishmentDao.getOneByValueOfProperty("Id", userAccomplishment.Accomplishment.Id) If user Is Nothing And accomplishment Is Nothing Then 'neither the user or the accomplishment exist, both are new so insert them both, typical insert' insertSuccess = Me.insertRow(userAccomplishment) ElseIf user Is Nothing And Not accomplishment Is Nothing Then 'user is new, accomplishment is not new, so just insert the user, and the relation in userAccomplishment' Dim userWithExistingAccomplishment As New UserAccomplishment(userAccomplishment.User, userAccomplishment.Accomplishment.Id, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(userWithExistingAccomplishment) ElseIf Not user Is Nothing And accomplishment Is Nothing Then 'user is not new, accomplishment is new, so just insert the accomplishment, and the relation in userAccomplishment' Dim existingUserWithAccomplishment As New UserAccomplishment(userAccomplishment.UserId, userAccomplishment.Accomplishment, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(existingUserWithAccomplishment) Else 'both are not new, just add the relation' Dim userAccomplishmentBothExist As New UserAccomplishment(userAccomplishment.User.Id, userAccomplishment.Accomplishment.Id, userAccomplishment.LastUpdatedBy) insertSuccess = Me.insertRow(userAccomplishmentBothExist) End If End If Return insertSuccess End Function End Class Alright, here I basically check if the supplied user and accomplishment already exists in the db, and if so call an appropriate constructor that will leave whatever already exists empty, but supply the rest of the information so the insert can succeed. However, upon trying an insert: Dim result As Boolean = Me.userAccomplishmentDao.insertLinkerObjectRow(userAccomplishment) In which the user already exists, but the accomplishment does not (the 99% typical scenario) I get the error: "An attempt has been made to Attach or Add an entity that is not new, perhaps having been loaded from another DataContext. This is not supported." I have debugged this multiple times now and am not sure why this is occuring, if either User or Accomplishment exist, I am not including it in the final object to try to insert. So nothing appears to be attempted to be added. Even in debug, upon insert, the object was set to empty. So the accomplishment is new and the user is empty. 1) Why is it still saying that and how can I fix it ..using my current structure 2) Pre-emptive 'use repository pattern answers' - I know this way kind of sucks in general and I should be using the repository pattern. However, I can't use that in the current project because I don't have time to refactor that due to my non existence knowledge of it and time constraints. The usage of the app is going to so small that the inefficient use of datacontext's and what have you won't matter so much. I can refactor it once it's up and running, but for now I just need to 'push through' with my current structure. Edit: I also just tested this when having both already exists, and only insert each object's IDs into the table, that works. So I guess I could manually insert whichever object doesn't exist as a single insert, then put the ids only into the linking table, but I still don't know why when one object exists, and I make it empty, it doens't work.

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  • What are potential reasons a user could be connected to a home network, but not to the internet?

    - by Matthew
    I have a friend that recently started using Ubuntu, and I've been answering his questions via the internet. However, I'm stuck on this one. He bought Linksys WPC11 wireless card, and says he was able to create a network connection, but was unable to ping or use a browser. I'm not quite sure where to start in figuring this out--what are some common causes of this sort of problem?

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  • Ubuntu - Automatically mount external drives to /media/LABEL on boot without a user logged in?

    - by endolith
    This question is similar, but kind of the opposite of what I want. I want external USB drives to be mounted automatically at boot, without anyone logged in, to locations like /media/<label>. I don't want to have to enter all the data into fstab, partially because it's tedious and annoying, but mostly because I can't predict what I'll be plugging into it or how the partitions will change in the future. I want the drives to be accessible to things like MPD, and available when I log in with SSH. gnome-mount seems to only mount things when you are locally logged into a Gnome graphical session.

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  • Can I stop the page from 'scrolling' back to the top when a user clicks on a tab (with Rails not Jav

    - by Jake
    Ive built a webpage with 'tabs' using rails. When a user clicks a tab, a new page loads. I want to format it so the tabs are always in the same place on the page as a user clicks them. This happens as long as the user has not scrolled down on the page. If a user has scrolled down, clicking on the tab will refresh the page and it is no longer scrolled down - which make clicking the tabs look bad. Is there a way to keep the spot on the page where the user has scrolled down, without using Javascript? If it must be done with Javascript, any suggestions? T

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  • How to rename dir under Mac (10.6.4) via super user?

    - by user56990
    This is my dir list on my NFS: macbook-pro-andrey-k:Download Andrey$ ls 1289816143_PL_t1181913 1289816171_PL_t1183807 1290117075_BFD_DVD02(Drums) I can't delete "1290117075_BFD_DVD02(Drums)" using sudo rm -Rf 1290117075_BFD_DVD02(Drums) because I get error message -bash: syntax error near unexpected token `(' Hlp plz, how can I either rename the dir so that the error message would not show up or delete the dir right away omitting rename procedure? Thank you.

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  • Knowledge and user generated content management system to track files, research, proposals, etc.?

    - by Eshwar
    I'll try keep it short. Here's the scenario: We have employees all over the world performing similar work i.e. research, generating powerpoint slides, word documents, graphics, etc. Many times a lot of this previous work can be reused for another future project. The current arrangement is email and phone calls which as you would agree is quick if you know where to look but otherwise archaic and very very inefficient. So I am looking for software that will allow me to do the following: Tag files e.g. an investor presentation on cellphone usage in kenya would be tagged investor, cellphone, kenya Manage references e.g. if we read something on the internet, should be able to paste that link in some fashion and tag it as above. Preferably cloud based so that it can be accessed by anybody and additionally would be nice (though NOT must) to have access levels (director, manager, everyone) A nice interface that non technically savvy folks can warm up to ;) A desktop app would be handy so that people don't always have to click upload or something A tree based system is inefficient in this case because content is usually linked across branches and also people might not quite agree on one format of a tree. Tagging works around this very nicely. What I have considered so far: Evernote (for its more professional look) Springpad (for its versatility with content) Mendeley (this is a research manager and in some ways ideal, but i fear its limited to PDFs) The goal is that when somebody wants to look for a document, they don't have to ask a colleague, they can just search with keywords and all relevant information shows up. Thanks!

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  • Is there any user-friendly way to deliver an In-app purchase subscription to multiple devices?

    - by mkvakin
    Hi everybody, Apple requires an in-app purchase subscription purchased on one device to be available on all devices associated with the user: “...subscriptions must be provided on all devices associated with a user. In App Purchase expects subscriptions to be delivered through an external server that you will provide. You must provide infrastructure to deliver subscriptions to multiple devices.” Is there any way to propagate a subscription to another device transparently without user having to create a server side user account and log in each time he needs to enable the subscription on another device? E.g. by reading a username from some kind of API and using it as a key on a server to store information about subscriptions. I tried to find an API for retrieving user account info but couldn't find any.

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  • Is Family Tree Maker 2011 the right upgrade for a FTM 11 user?

    - by bill weaver
    My father has used Family Tree Maker for years, but hasn't upgraded since version 11. It is difficult to tell from reviews at Amazon and other places whether upgrading to FTM 2011 is a good choice. File incompatibilities and upgrade woes sound like customer service is lacking, and i've read reports of it uploading your data to their database but then trying to sell you a download of data. Looking at the ancestry.com site makes me think it's solely about selling add-ons and upgrades. On the other hand, the feature set seems fairly rich and the software has a pretty strong following. I was able to get Gramps working on my system, but that's not going to work for my dad. Any advice on a good upgrade path?

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  • iPhone:How to find the control interaction under Touch?

    - by user187532
    Hello friends, I have a UILabel control in a view. I want to detect touch event occurred when this label touched. I added the following code, which should work whenever touch happens on the view. - (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event { // This should be called only when the label is touched, not all the time.. [ [UIApplication sharedApplication] openURL:[NSURL URLWithString:@"http://www.mywebsite.com"] ]; } Whenever that particular label is touched my code should do the process further, not when the touch is happening anywhere in the view. How do i find out the particular label (or) any control is touched under touchesEnded function ? Could someone guide me on this? Thank you.

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  • Question about the evolution of interaction paradigm between web server program and content provider program?

    - by smwikipedia
    Hi experts, In my opinion, web server is responsible to deliver content to client. If it is static content like pictures and static html document, web server just deliver them as bitstream directly. If it is some dynamic content that is generated during processing client's request, the web server will not generate the conetnt itself but call some external proram to genearte the content. AFAIK, this kind of dynamice content generation technologies include the following: CGI ISAPI ... And from here, I noticed that: ...In IIS 7, modules replace ISAPI filters... Is there any others? Could anyone help me complete the above list and elabrate on or show some links to their evolution? I think it would be very helpful to understand application such as IIS, TomCat, and Apache. I once wrote a small CGI program, and though it serves as a content generator, it is still nothing but a normal standalone program. I call it normal because the CGI program has a main() entry point. But with the recenetly technology like ASP.NET, I am not writing complete program, but only some class library. Why does such radical change happens? Many thanks.

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  • mysql subquery strangely slow

    - by aviv
    I have a query to select from another sub-query select. While the two queries look almost the same the second query (in this sample) runs much slower: SELECT user.id ,user.first_name -- user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); This query takes 1.2s Explain on this query results: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user index first_name 152 141192 Using where; Using index 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where The second query: SELECT -- user.id -- user.first_name user.* FROM user WHERE user.id IN (SELECT ref_id FROM education WHERE ref_type='user' AND education.institute_id='58' AND education.institute_type='1' ); Takes 45sec to run, with explain: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY user ALL 141192 Using where 2 DEPENDENT SUBQUERY education index_subquery ref_type,ref_id,institute_id,institute_type,ref_type_2 ref_id 4 func 1 Using where Why is it slower if i query only by index fields? Why both queries scans the full length of the user table? Any ideas how to improve? Thanks.

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  • SQLAlchemy & Complex Queries

    - by user356594
    I have to implement ACL for an existing application. So I added the a user, group and groupmembers table to the database. I defined a ManyToMany relationship between user and group via the association table groupmembers. In order to protect some ressources of the app (i..e item) I added a additional association table auth_items which should be used as an association table for the ManyToMany relationship between groups/users and the specific item. item has following columns: user_id -- user table group_id -- group table item_id -- item table at least on of user_id and group_id columns are set. So it's possible to define access for a group or for a user to a specific item. I have used the AssociationProxy to define the relationship between users/groups and items. I now want to display all items which the user has access to and I have a really hard time doing that. Following criteria are used: All items which are owned by the user should be shown (item.owner_id = user.id) All public items should be shown (item.access = public) All items which the user has access to should be shown (auth_item.user_id = user.id) All items which the group of the user has access to should be shown. The first two criteria are quite straightforward, but I have a hard time doing the 3rd one. Here is my approach: clause = and_(item.access == 'public') if user is not None: clause = or_(clause,item.owner == user,item.users.contains(user),item.groups.contains(group for group in user.groups)) The third criteria produces an error. item.groups.contains(group for group in user.groups) I am actually not sure if this is a good approach at all. What is the best approach when filtering manytomany relationships? How I can filter a manytomany relationship based on another list/relationship? Btw I am using the latest sqlalchemy (6.0) and elixir version Thanks for any insights.

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  • How to write a flexible modular program with good interaction possibilities between modules?

    - by PeterK
    I went through answers on similar topics here on SO but could't find a satisfying answer. Since i know this is a rather large topic, i will try to be more specific. I want to write a program which processes files. The processing is nontrivial, so the best way is to split different phases into standalone modules which then would be used as necessary (since sometimes i will be only interested in the output of module A, sometimes i would need output of five other modules, etc). The thing is, that i need the modules to cooperate, because the output of one might be the input of another. And i need it to be FAST. Moreover i want to avoid doing certain processing more than once (if module A creates some data which then need to be processed by module B and C, i don't want to run module A twice to create the input for modules B,C ). The information the modules need to share would mostly be blocks of binary data and/or offsets into the processed files. The task of the main program would be quite simple - just parse arguments, run required modules (and perhaps give some output, or should this be the task of the modules?). I don't need the modules to be loaded at runtime. It's perfectly fine to have libs with a .h file and recompile the program every time there is a new module or some module is updated. The idea of modules is here mainly because of code readability, maintaining and to be able to have more people working on different modules without the need to have some predefined interface or whatever (on the other hand, some "guidelines" on how to write the modules would be probably required, i know that). We can assume that the file processing is a read-only operation, the original file is not changed. Could someone point me in a good direction on how to do this in C++ ? Any advice is wellcome (links, tutorials, pdf books...).

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  • User not in the sudoers file. This incident will be reported

    - by Sergiy Byelozyorov
    I need to install a package. For that I need root access. However the system says that I am not in sudoers file. When trying to edit one, it complains alike! How I am supposed to add myself to the sudoers file if I don't have the right to edit one? I have installed this system and only administrator. What can I do? Edit: I have tried visudo already. It requires me to be in sudoers in the first place. amarzaya@linux-debian-gnu:/$ sudo /usr/sbin/visudo We trust you have received the usual lecture from the local System Administrator. It usually boils down to these three things: #1) Respect the privacy of others. #2) Think before you type. #3) With great power comes great responsibility. [sudo] password for amarzaya: amarzaya is not in the sudoers file. This incident will be reported. amarzaya@linux-debian-gnu:/$

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