Search Results

Search found 3076 results on 124 pages for 'beginner'.

Page 22/124 | < Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >

  • Using a handle to collect output from CreateProcess()

    - by Stef
    Hi I am using CreateProcess() to run an external console application in Windows from my GUI application. I would like to somehow gather the output to know whether there were errors. Now I know I have to do something with hStdOutput, but I fail to understand what. I am new to c++ and an inexperienced programmer and I actually don't know what to do with a handle or how to light a pipe. How do I get the output to some kind of variable (or file)? This is what I have a the moment: void email::run(string path,string cmd){ WCHAR * ppath=new(nothrow) WCHAR[path.length()*2]; memset(ppath,' ',path.length()*2); WCHAR * pcmd= new(nothrow) WCHAR[cmd.length()*2]; memset(pcmd,' ',cmd.length()*2); string tempstr; ToWCHAR(path,ppath); //creates WCHAR from my std::string ToWCHAR(cmd,pcmd); STARTUPINFO info={sizeof(info)}; info.dwFlags = STARTF_USESHOWWINDOW; //hide process PROCESS_INFORMATION processInfo; if (CreateProcess(ppath,pcmd, NULL, NULL, FALSE, 0, NULL, NULL, &info, &processInfo)) { ::WaitForSingleObject(processInfo.hProcess, INFINITE); CloseHandle(processInfo.hProcess); CloseHandle(processInfo.hThread); } delete[](ppath); delete[](pcmd); } This code probably makes any decent programmer scream, but (I shouldn't even say it:) It works ;-) The Question: How do I use hStdOutput to read the output to a file (for instance)?

    Read the article

  • Python learner needs help spotting an error

    - by Protean
    This piece of code gives a syntax error at the colon of "elif process.loop(i, len(list_i) != 'repeat':" and I can't seem to figure out why. class process: def loop(v1, v2): if v1 < v2 - 1: return 'repeat' def isel(chr_i, list_i): for i in range(len(list_i)): if chr_i == list_i[i]: return list_i[i] elif process.loop(i, len(list_i) != 'repeat': return 'error'()

    Read the article

  • Converting from a string to boolean in Python?

    - by Joan Venge
    Does anyone know how to do convert from a string to a boolean in Python? I found this link. But it doesn't look like a proper way to do it. I.e. using a built in functionality, etc. EDIT: The reason I asked this is because I learned int("string"), from here. I tried bool ("string") but always got True.

    Read the article

  • convert bitset to string ??

    - by mr.bio
    Hi .. What is wrong with this code ? set<string> nk ; bitset<3> bs1(string("100")); nk.insert(bs1.to_string()); error: no matching function for call to `std::bitset<3u::to_string()' why?!

    Read the article

  • How I can get rid of None values in dictionary?

    - by Vojtech R.
    Something like: for (a,b) in kwargs.iteritems(): if not b : del kwargs[a] This code raise exception because changing of dictionary when iterating. I discover only non pretty solution with another dictionary: res ={} res.update((a,b) for a,b in kwargs.iteritems() if b is not None) Thanks

    Read the article

  • How to use sprintf instead of hardcoded values

    - by astha goyal
    I am developing a firewall for Linux as my project. I am able to capture packets and to block them. I am using IPTABLES. How can I use variables with sprintf instead of hardcoded values? sprintf(comm, "iptables -A INPUT -s $str -j DROP") // inplace of: sprintf(comm, "iptables -A INPUT -s 192.168.0.43 -j DROP")

    Read the article

  • Good beginners' level book about mobile telecommunication

    - by vito
    I've recently joined a company who specialize in the mobile telecommunication domain. I'm encountering a lot of jargons, and I'm feeling a bit lost in most of the conversations. Although I'm quickly searching for the new terms on the web and learning stuff on the job, I would like to read an introductory book that will take me through the basics of the mobile world. Thanks for your recommendations!

    Read the article

  • Using EclipseLink

    - by Ross Peoples
    I am still new to Java and Eclipse and I'm trying to get my application to connect to a database. I think I want to use EclipseLink, but all of the documentation on the matter assumes you already know everything there is to know about everything. I keep getting linked back to this tutorial: http://www.vogella.de/articles/JavaPersistenceAPI/article.html But it's basically useless because it doesn't tell you HOW to do anything. For the Installation section, it tells you to download EclipseLink and gives you a link to the download page, but doesn't tell you what to do with it after you download. The download page doesn't either. I used the "Install new software" option in Eclipse to install EclipseLink into Eclipse, but it gave me like 4 different options, none of which are explained anywhere. It gave me options JPA, MOXy, SDO, etc, but I don't know which one I need. I just installed them all. Everything on the web assumes you are already a Java guru and things that are second nature to Java devs are never explained, so it's very frustrating for someone trying to learn. So how do I install and USE EclipseLink in my project and what do I need to do to connect it to a Microsoft SQL server? Again, I am new to all of this so I have no clue what to do. Thanks for the help.

    Read the article

  • Running an allocation simulation repeatedly breaks after the first run.

    - by Az
    Background I have a bunch of students, their desired projects and the supervisors for the respective projects. I'm running a battery of simulations to see which projects the students end up with, which will allow me to get some useful statistics required for feedback. So, this is essentially a Monte-Carlo simulation where I'm randomising the list of students and then iterating through it, allocating projects until I hit the end of the list. Then the process is repeated again. Note that, within a single session, after each successful allocation of a project the following take place: + the project is set to allocated and cannot be given to another student + the supervisor has a fixed quota of students he can supervise. This is decremented by 1 + Once the quota hits 0, all the projects from that supervisor become blocked and this has the same effect as a project being allocated Code def resetData(): for student in students.itervalues(): student.allocated_project = None for supervisor in supervisors.itervalues(): supervisor.quota = 0 for project in projects.itervalues(): project.allocated = False project.blocked = False The role of resetData() is to "reset" certain bits of the data. For example, when a project is successfully allocated, project.allocated for that project is flipped to True. While that's useful for a single run, for the next run I need to be deallocated. Above I'm iterating through thee three dictionaries - one each for students, projects and supervisors - where the information is stored. The next bit is the "Monte-Carlo" simulation for the allocation algorithm. sesh_id = 1 for trial in range(50): for id in randomiseStudents(1): stud_id = id student = students[id] if not student.preferences: # Ignoring the students who've not entered any preferences for rank in ranks: temp_proj = random.choice(list(student.preferences[rank])) if not (temp_proj.allocated or temp_proj.blocked): alloc_proj = student.allocated_proj_ref = temp_proj.proj_id alloc_proj_rank = student.allocated_rank = rank successActions(temp_proj) temp_alloc = Allocated(sesh_id, stud_id, alloc_proj, alloc_proj_rank) print temp_alloc # Explained break sesh_id += 1 resetData() # Refer to def resetData() above All randomiseStudents(1) does is randomise the order of students. Allocated is a class defined as such: class Allocated(object): def __init__(self, sesh_id, stud_id, alloc_proj, alloc_proj_rank): self.sesh_id = sesh_id self.stud_id = stud_id self.alloc_proj = alloc_proj self.alloc_proj_rank = alloc_proj_rank def __repr__(self): return str(self) def __str__(self): return "%s - Student: %s (Project: %s - Rank: %s)" %(self.sesh_id, self.stud_id, self.alloc_proj, self.alloc_proj_rank) Output and problem Now if I run this I get an output such as this (truncated): 1 - Student: 7720 (Project: 1100241 - Rank: 1) 1 - Student: 7832 (Project: 1100339 - Rank: 1) 1 - Student: 7743 (Project: 1100359 - Rank: 1) 1 - Student: 7820 (Project: 1100261 - Rank: 2) 1 - Student: 7829 (Project: 1100270 - Rank: 1) . . . 1 - Student: 7822 (Project: 1100280 - Rank: 1) 1 - Student: 7792 (Project: 1100141 - Rank: 7) 2 - Student: 7739 (Project: 1100267 - Rank: 1) 3 - Student: 7806 (Project: 1100272 - Rank: 1) . . . 45 - Student: 7806 (Project: 1100272 - Rank: 1) 46 - Student: 7714 (Project: 1100317 - Rank: 1) 47 - Student: 7930 (Project: 1100343 - Rank: 1) 48 - Student: 7757 (Project: 1100358 - Rank: 1) 49 - Student: 7759 (Project: 1100269 - Rank: 1) 50 - Student: 7778 (Project: 1100301 - Rank: 1) Basically, it works perfectly for the first run, but on subsequent runs leading upto the nth run, in this case 50, only a single student-project allocation pair is returned. Thus, the main issue I'm having trouble with is figuring out what is causing this anomalous behaviour especially since the first run works smoothly. Thanks in advance, Az

    Read the article

  • Throw of a die in Java

    - by Arkapravo
    The throw of a die is a popular program in Java, public class Die { /* This program simulates rolling a die */ public static void main(String[] args) { int die; // The number on the die. die = (int)(Math.random()*6 + 1); System.out.println (die); } // end main() } // end class What I wish to do is make it repeat, 500 times. I have not been able to put this program into a loop of 500. I usually program in Python, thus I guess my Java has rusted ! Any help is most welcome !

    Read the article

  • Open Source Utilization Questions: How do you lone wold programmers best take advantage of open sour

    - by Funkyeah
    For Clarity: So you come up with an idea for a new program and want to start hacking, but you also happen to be a one-man army. How do you programming dynamos best find and utilize existing open-source software to give you the highest jumping off point possible when diving into your new project? When you do jump in where the shit do you start from? Any imaginary scenarios would be welcome, e.g. a shitty example might be utilizing a open-source database with an open-source IM client as a starting off point to a make a new client where you could tag and store conversations and query those tags at a later time.

    Read the article

  • VB.NET Folder location

    - by PandaNL
    Hello, My program uses some external programs that i included in the Files folder. In my code im reffering to Files/external_program.exe Windows Vista & Windows 7 knows how to handle this and starts the program on the same location as my program in the Files folder. But Xp doesnt know where it is, and Windows XP will think im reffering to the C:\Files folder. So im getting an error and the app crashes. How can i fix this? so windows xp will know that i'm reffering to the Files folder on the same location as my program.

    Read the article

  • Java : method to to print relative pathname?

    - by HH
    I am hesitant just to look at some env.vars and try to replace things with regexes. So is there a ready method to print relative pathnames system-independently? $ echo ~ /u/user $ pwd /u/user/OH/one/src $ echo "Like relative pathnames ~/OH/one/src, not /u/user/OH/one/src."

    Read the article

  • Awk: how to have backclashes in printf?

    - by HH
    Works: awk '{print $$1"\t&\t"$$2"\t\\\\"}' .file > file.tex Does not work, why? awk '{printf %.2f"\t&\t"\.2f"\t\\\\",$$1,$$2}' .file > file.tex Error: awk: {printf %.2f"\t&\t"\.2f"\t\\\\",$1,$2} awk: ^ backslash not last character on line

    Read the article

  • Convert string to decimal retaining the exact input format

    - by Brett
    Hi All, I'm sure this is a piece of cake but I'm really struggling with something that seems trivial. I need to check the inputted text of a textbox on the form submit and check to see if it's within a desired range (I've tried a Range Validator but it doesn't work for some reason so I'm trying to do this server-side). What I want to do is: Get the value inputted (eg. 0.02), replace the commas and periods, convert that to a decimal (or double or equivalent) and check to see if it's between 0.10 and 35000.00. Here's what I have so far: string s = txtTransactionValue.Text.Replace(",", string.Empty).Replace(".", string.Empty); decimal transactionValue = Decimal.Parse(s); if (transactionValue >= 0.10M && transactionValue <= 35000.00M) // do something If I pass 0.02 into the above, transactionValue is 2. I want to retain the value as 0.02 (ie. do no format changes to it - 100.00 is 100.00, 999.99 is 999.99) Any ideas? Thanks in advance, Brett

    Read the article

  • str is not callable error in python .

    - by mekasperasky
    import sys import md5 from TOSSIM import * from RadioCountMsg import * t = Tossim([]) #The Tossim object is defined here m = t.mac()#The mac layer is defined here , in which the communication takes place r = t.radio()#The radio communication link object is defined here , as the communication needs Rf frequency to transfer t.addChannel("RadioCountToLedsC", sys.stdout)# The various channels through which communication will take place t.addChannel("LedsC", sys.stdout) #The no of nodes that would be required in the simulation has to be entered here print("enter the no of nodes you want ") n=input() for i in range(0, n): m = t.getNode(i) m.bootAtTime((31 + t.ticksPerSecond() / 10) * i + 1) #The booting time is defined so that the time at which the node would be booted is given f = open("topo.txt", "r") #The topography is defined in topo.txt so that the RF frequencies of the transmission between nodes are are set lines = f.readlines() for line in lines: s = line.split() if (len(s) > 0): if (s[0] == "gain"): r.add(int(s[1]), int(s[2]), float(s[3])) #The topogrography is added to the radio object noise = open("meyer-heavy.txt", "r") #The noise model is defined for the nodes lines = noise.readlines() for line in lines: str = line.strip() if (str != ""): val = int(str) for i in range(0, 4): t.getNode(i).addNoiseTraceReading(val) for i in range (0, n): t.getNode(i).createNoiseModel() #The noise model is created for each node for i in range(0,n): t.runNextEvent() fk=open("key.txt","w") for i in range(0,n): if i ==0 : key=raw_input() fk.write(key) ak=key key=md5.new() key.update(str(ak)) ak=key.digest() fk.write(ak) fk.close() fk=open("key.txt","w") plaint=open("pt.txt") for i in range(0,n): msg = RadioCountMsg() msg.set_counter(7) pkt = t.newPacket()#A packet is defined according to a certain format print("enter message to be transported") ms=raw_input()#The message to be transported is taken as input #The RC5 encryption has to be done here plaint.write(ms) pkt.setData(msg.data) pkt.setType(msg.get_amType()) pkt.setDestination(i+1)#The destination to which the packet will be sent is set print "Delivering " + " to" ,i+1 pkt.deliver(i+1, t.time() + 3) fk.close() print "the key to be displayed" ki=raw_input() fk=open("key.txt") for i in range(0,n): if i==ki: ms=fk.readline() for i in range(0,n): msg=RadioCountMsg() msg.set_counter(7) pkt=t.newPacket() msg.data=ms pkt.setData(msg.data) pkt.setType(msg.get_amType()) pkt.setDestination(i+1) pkt.deliver(i+1,t.time()+3) #The key has to be broadcasted here so that the decryption can take place for i in range(0, n): t.runNextEvent(); this code gives me error here key.update(str(ak)) . when i run a similar code on the python terminal there is no such error but this code pops up an error . why so?

    Read the article

  • very quickly getting total size of folder

    - by freakazo
    I want to quickly find the total size of any folder using python. def GetFolderSize(path): TotalSize = 0 for item in os.walk(path): for file in item[2]: try: TotalSize = TotalSize + getsize(join(item[0], file)) except: print("error with file: " + join(item[0], file)) return TotalSize That's the simple script I wrote to get the total size of the folder, it took around 60 seconds (+-5 seconds). By using multiprocessing I got it down to 23 seconds on a quad core machine. Using the Windows file explorer it takes only ~3 seconds (Right click- properties to see for yourself). So is there a faster way of finding the total size of a folder close to the speed that windows can do it? Windows 7, python 2.6 (Did searches but most of the time people used a very similar method to my own) Thanks in advance.

    Read the article

  • Perl file test operator help

    - by Aaron Moodie
    This is a really basic issue, but I'm new to perl and cannot work out what the issue is. I'm just trying to isolate the files in a directory, but the -d operator keeps treating all the folder contents as files ... @contents is my array, and when I run this: foreach $item(@contents) { if (-d $item) { next; } print"$item is a file\n"; } I keep getting both folders and files. Alternatively, if I use -f, I get nothing. edit: this is the output - file01.txt is a file folder 01 is a file folder 02 is a file Screen shot 2010-04-18 at 1.26.17 PM.png is a file I'm running this on OSX

    Read the article

  • Implementing a linear, binary SVM (support vector machine)

    - by static_rtti
    I want to implement a simple SVM classifier, in the case of high-dimensional binary data (text), for which I think a simple linear SVM is best. The reason for implementing it myself is basically that I want to learn how it works, so using a library is not what I want. The problem is that most tutorials go up to an equation that can be solved as a "quadratic problem", but they never show an actual algorithm! So could you point me either to a very simple implementation I could study, or (better) to a tutorial that goes all the way to the implementation details? Thanks a lot!

    Read the article

  • Using singleton instead of a global static instance

    - by Farstucker
    I ran into a problem today and a friend recommended I use a global static instance or more elegantly a singleton pattern. I spent a few hours reading about singletons but a few things still escape me. Background: What Im trying to accomplish is creating an instance of an API and use this one instance in all my classes (as opposed to making a new connection, etc). There seems to be about 100 ways of creating a singleton but with some help from yoda I found some thread safe examples. ..so given the following code: public sealed class Singleton { public static Singleton Instance { get; private set; } private Singleton() { APIClass api = new APIClass(); //Can this be done? } static Singleton() { Instance = new Singleton(); } } How/Where would you instantiate the this new class and how should it be called from a separate class? EDIT: I realize the Singleton class can be called with something like Singleton obj1 = Singleton.Instance(); but would I be able to access the methods within the APIs Class (ie. obj1.Start)? (not that I need to, just asking) EDIT #2: I might have been a bit premature in checking the answer but I do have one small thing that is still causing me problems. The API is launching just fine, unfortunately Im able to launch two instances? New Code public sealed class SingletonAPI { public static SingletonAPI Instance { get; private set; } private SingletonAPI() {} static SingletonAPI() { Instance = new SingletonAPI(); } // API method: public void Start() { API myAPI = new API();} } but if I try to do something like this... SingletonAPI api = SingletonAPI.Instance; api.Start(); SingletonAPI api2 = SingletonAPI.Instance; // This was just for testing. api2.Start(); I get an error saying that I cannot start more than one instance.

    Read the article

  • Replace values in a dataframe based on another factor which contains NA's in R

    - by PaulHurleyuk
    I have a dataframe which contains (among other things) a numeric column with a concentration, and a factor column with a status flag. This status flag contains NA's. Here's an example df<-structure(list(conc = c(101.769, 1.734, 62.944, 92.697, 25.091, 27.377, 24.343, 55.084, 0.335, 23.280), status = structure(c(NA, NA, NA, NA, NA, NA, 2L, NA, 1L, NA), .Label = c("<LLOQ", "NR"), class = "factor")), .Names = c("conc", "status"), row.names = c(NA, -10L), class = "data.frame") I want to replace the concentration column with a string for some values of the flag column, or with the concentration value formatted to a certain number of significant digits. When I try this ifelse(df$status=="NR","NR",df$conc) The NA's in the status flag don't trigger either the true or false condition (and return NA) - as the documentation suggests it will. I could loop over the rows and use IF then else on each one but this seems inefficient. Am I missing something ? I've tried as.character(df$status) as well which doesn't work. My mojo must be getting low....

    Read the article

  • Android Scaled Drawing to ImageView

    - by user329999
    Newbie question, so there's probably a simple answer to this problem. I'm drawing some simple shapes using canvas.drawCircle(), canvas.drawLine() etc. I originally copied the code from: http://developer.android.com/resources/samples/ApiDemos/src/com/example/android/apis/graphics/DrawPoints.html Which extends a View and draws directly to a canvas. It doesn't load a pre-drawn bitmap because I need my application to turn data into a drawing and the user will enter the data. My changes work, but the drawing is too small (or big) and doesn't fill the screen using all the available screen. Ideally I'd rather use something like an ImageView in .XML like so: If that's possible. The documentation seems to imply that I want to set the scaleType as shown in the above .XML which seems like the simple way to do this. If using an ImageView in .XML is a good idea, then I'm lost on how to draw to the ImageView and could use some guidance on doing that task. If that won't work, then I'll need to do some more thinking about how to get my drawing scaled on the screen and basically I'm lazy and would rather have Android do the work for me. Feel free to suggest some other way that's completely different is this is the wrong solution path. :) Thanks.

    Read the article

< Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >