Search Results

Search found 15563 results on 623 pages for 'django model'.

Page 22/623 | < Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >

  • Architecting multi-model multi-DB ASP.NET MVC solution

    - by A. Murray
    I have an ASP.NET MVC 4 solution that I'm putting together, leveraging IoC and the repository pattern using Entity Framework 5. I have a new requirement to be able to pull data from a second database (from another internal application) which I don't have control over. There is no API available unfortunately for the second application and the general pattern at my place of work is to go direct to the database. I want to maintain a consistent approach to modeling the domain and use entity framework to pull the data out, so thus far I have used Entity Framework's database first approach to generate a domain model and database context over the top of this. However, I've become a little stuck on how to include the second domain model in the application. I have a generic repository which I've now moved out to a common DataAccess project, but short of creating two distinct wrappers for the generic repository (so each can identify with a specific database context), I'm struggling to see how I can elegantly include multiple models?

    Read the article

  • Django - need to split a table across multiple locations [closed]

    - by MikeRand
    Hi all, I have a Django project to track our company's restructuring projects. Here's the very simple model: class Project(models.Model): code = models.CharField(max_length=30) description = models.CharField(max_length=60) class Employee(models.Model): project = models.ForeignKey(Project) employee_id = models.IntegerField() country_code = models.CharField(max_length=3) severance = models.IntegerField() Due to regulations in some European countries, I'm not allowed to keep employee-level severance information in a database that sits on a box outside of that country. In Django, how do I manage the need to have my Employee table split across multiple databases based on an Employee attribute (i.e. country_code) in a way that doesn't impact anything else in the project (e.g. views, templates, admin)? Thanks, Mike

    Read the article

  • In Django, what's the best way to handle optional url parameters from the template?

    - by Thierry Lam
    I have the following type of urls which are both valid: hello/ hello/1234/ My urls.py has the following: urlpatterns = patterns('hello.views', url(r'^$', 'index', name='index'), url(r'^(?P<user_id>\d+)/$', 'index', name='index'), ) In my views.py, when I pass user_id to the template, it defaults to 0 if not specified. My template looks like the following, I'm using namespace hello for my hello app: {% url hello:index user_id %} If user_id is not specified, the url defaults to hello/0/. The only way I can think of preventing the default 0 from showing in the url is by an if stmt: {% if user_id %} {% url hello:index user_id %} {% else %} {% url hello:index %} {% endif %} The above will give me hello/ if there are no user_id and hello/1234/ if it's present. Is the above solution the best way to solve this issue?

    Read the article

  • Multi-thread conversation in django (like Reddit)

    - by dotty
    Hay, i have an app which essentially a conversation system (much like reddits) Where a post can have multiple replies, and a reply and have multiplies, and a reply to a reply can have multiple replies (etc) I've made the model like this class Discussion(models.Model): message = models.TextField() replies = models.ManyToManyField('self') and the view discussions = Discussions.objects.all() and the template looks like this {% for discussion in discussions %} {{ discussion.message }} {% endfor %} How would i go about making a system where i can output all replies like this discussion reply reply reply reply reply reply Which would go down as far as it needs to to ensure all replies are listed. Thanks

    Read the article

  • How to put an InlineFormSet into a ModelFormSet in Django?

    - by Jannis
    Hi, I'd like to display a number of forms via a ModelFormSet where each one of the forms displays in turn InlineFormSets for all objects connected to the object. Now I'm not really sure how to provide the instances for each ModelFormSet. I thought about subclassing BaseModelFormSet but I have no clue on where to start and would like to know whether this is possible at all before I go through all the trouble. Thanks in advance!

    Read the article

  • Trying and expand the contrib.auth.user model and add a "relatipnships" manage

    - by dotty
    I have the following model setup. from django.db import models from django.contrib.auth.models import User class SomeManager(models.Manager): def friends(self): # return friends bla bla bla class Relationship(models.Model): """(Relationship description)""" from_user = models.ForeignKey(User, related_name='from_user') to_user = models.ForeignKey(User, related_name='to_user') has_requested_friendship = models.BooleanField(default=True) is_friend = models.BooleanField(default=False) objects = SomeManager() relationships = models.ManyToManyField(User, through=Relationship, symmetrical=False) relationships.contribute_to_class(User, 'relationships') Here i take the User object and use contribute_to_class to add 'relationships' to the User object. The relationship show up, but if call User.relationships.friends it should run the friends() method, but its failing. Any ideas how i would do this? Thanks

    Read the article

  • How to isolate data per customer, Django powered website

    - by Sawwy
    I have recently started learning python and django and working on a project that includes building a website for collecting information from customers. I am currently trying to figure out best way to isolate the customer data (collected information is sensitive and should only be accessible by customer and the service provider). I found this post Postgresql - one database for everyone, or one-database per customer and my question is that can I automate the model inheritance with customer creation via admin? To be specific, when save() is called for adding customer via django admin, this should create the customer specific tables (create a new set of tables with 'company_name' -prefix). For more information of the environment, I have extended the basic user registration with custom UserProfile adding 'company' and 'role' fields for each user. Upon login, the 'company' of the user will be checked to filter out tables without the 'company_name' prefix. 'Role' will further filter the which company-specific tables and set rights (view, edit). will appreciate any suggestions if more elegant methods could be used to solve the data isolation problem than model inheritance.

    Read the article

  • Djangoo Foreign key queries

    - by Hulk
    In the following model: class header(models.Model): title = models.CharField(max_length = 255) created_by = models.CharField(max_length = 255) def __unicode__(self): return self.id() class criteria(models.Model): details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() class options(models.Model): opt_details = models.CharField(max_length = 255) headerid = models.ForeignKey(header) def __unicode__(self): return self.id() If there is a row in the database for table header as Id=1, title=value-mart , createdby=CEO How do i query criteria and options tables to get all the values related to header table id=1 Also can some one please suggest a good link for queries examples, Thanks..

    Read the article

  • Django: Can class-based views accept two forms at a time?

    - by Hooman
    If I have two forms: class ContactForm(forms.Form): name = forms.CharField() message = forms.CharField(widget=forms.Textarea) class SocialForm(forms.Form): name = forms.CharField() message = forms.CharField(widget=forms.Textarea) and wanted to use a class based view, and send both forms to the template, is that even possible? class TestView(FormView): template_name = 'contact.html' form_class = ContactForm It seems the FormView can only accept one form at a time. In function based view though I can easily send two forms to my template and retrieve the content of both within the request.POST back. variables = {'contact_form':contact_form, 'social_form':social_form } return render(request, 'discussion.html', variables) Is this a limitation of using class based view (generic views)? Many Thanks

    Read the article

  • How can I copy a queryset to a new model in django admin?

    - by user3806832
    I'm trying to write an action that allows the user to select the queryset and copy it to a new table. So: John, Mark, James, Tyler and Joe are in a table 1( called round 1) The user selects the action that say to "move to next round" and those same instances that were chosen are now also in the table for "round 2". I started trying with an action but don't really know where to go from here: def Round_2(modeladmin, request, queryset): For X in queryset: X.pk = None perform.short_description = "Move to Round 2" How can I copy them to the next table with all of their information (pk doesn't have to be the same)? Thanks

    Read the article

  • Django flatpages raising 404 when DEBUG is False (404 and 500 templates exist)

    - by Adam
    I'm using Django 1.1.1 stable. When DEBUG is set to True Django flatpages works correctly; when DEBUG is False every flatpage I try to access raises a custom 404 error (my error template is obviously working correctly). Searching around on the internet suggests creating 404 and 500 templates which I have done. I've added to FlatpageFallBackMiddleware to middleware_classes and flatpages is added to installed applications. Any ideas how I can make flatpages work?

    Read the article

  • Subclassed django models with integrated querysets

    - by outofculture
    Like in this question, except I want to be able to have querysets that return a mixed body of objects: >>> Product.objects.all() [<SimpleProduct: ...>, <OtherProduct: ...>, <BlueProduct: ...>, ...] I figured out that I can't just set Product.Meta.abstract to true or otherwise just OR together querysets of differing objects. Fine, but these are all subclasses of a common class, so if I leave their superclass as non-abstract I should be happy, so long as I can get its manager to return objects of the proper class. The query code in django does its thing, and just makes calls to Product(). Sounds easy enough, except it blows up when I override Product.__new__, I'm guessing because of the __metaclass__ in Model... Here's non-django code that behaves pretty much how I want it: class Top(object): _counter = 0 def __init__(self, arg): Top._counter += 1 print "Top#__init__(%s) called %d times" % (arg, Top._counter) class A(Top): def __new__(cls, *args, **kwargs): if cls is A and len(args) > 0: if args[0] is B.fav: return B(*args, **kwargs) elif args[0] is C.fav: return C(*args, **kwargs) else: print "PRETENDING TO BE ABSTRACT" return None # or raise? else: return super(A).__new__(cls, *args, **kwargs) class B(A): fav = 1 class C(A): fav = 2 A(0) # => None A(1) # => <B object> A(2) # => <C object> But that fails if I inherit from django.db.models.Model instead of object: File "/home/martin/beehive/apps/hello_world/models.py", line 50, in <module> A(0) TypeError: unbound method __new__() must be called with A instance as first argument (got ModelBase instance instead) Which is a notably crappy backtrace; I can't step into the frame of my __new__ code in the debugger, either. I have variously tried super(A, cls), Top, super(A, A), and all of the above in combination with passing cls in as the first argument to __new__, all to no avail. Why is this kicking me so hard? Do I have to figure out django's metaclasses to be able to fix this or is there a better way to accomplish my ends?

    Read the article

  • Django comments being spammed

    - by John
    Hi, I am using the built in comment system with Django but it has started to be spammed. Can anyone recommend anything I can use to stop this such as captcha for django etc. I'm looking for something that I can use along with the comment system rather than replacing it. Thanks

    Read the article

  • Django & google openid authentication with socialauth

    - by Zayatzz
    Hello I am trying to use django-socialauth (http://github.com/uswaretech/Django-Socialauth) for authenticating users for my django project. This is firs time working with openid and i've had to figure out how exactly this open id works. I have more or less understood it, by now, but there are few things that elude me. The authentication process starts when the request is put together in in django-socialauth.openid_consumer.views.begin. I can see that the outgoing authentication request is more or less something like this: https://www.google.com/accounts/o8/ud?openid.assoc_handle=AOQobUckRThPUj3K1byG280Aze-dnfc9Iu6AEYaBwvHE11G0zy8kY8GZ& openid.ax.if_available=fname& openid.ax.mode=fetch_request& openid.ax.required=email& openid.ax.type.email=http://axschema.org/contact/email& openid.ax.type.fname=http://example.com/schema/fullname& openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select& openid.identity=http://specs.openid.net/auth/2.0/identifier_select& openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0& openid.ns.ax=http://openid.net/srv/ax/1.0& openid.ns.sreg=http://openid.net/extensions/sreg/1.1& openid.realm=http://localhost/& openid.return_to=http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T11%3A19%3A44ZPZCjNc&openid.sreg.optional=postcode,country,nickname,email This is lot like 2nd example here: http://code.google.com/apis/accounts/docs/OpenID.html#Samples The problem is, that the request, i get back, is nothing like the corresponding example from code.google.com (look at the 3rd example in example responses. Response dict i get is like this: { 'openid.op_endpoint': 'https://www.google.com/accounts/o8/ud', 'openid.sig': 'QWMa4x4ruMUvSCfLwKV6CZRuo0E=', 'openid.ext1.type.email': 'http://axschema.org/contact/email', 'openid.return_to': 'http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T17%3A54%3A06ZHV4cqh', 'janrain_nonce': '2010-03-20T17:54:06ZHV4cqh', 'openid.response_nonce': '2010-03-20T17:54:06ZdC5mMu9M_6O4pw', 'openid.claimed_id': 'https://www.google.com/accounts/o8/id?id=AItOghawkFz0aNzk91vaQWhD-DxRJo6sS09RwM3SE', 'openid.mode': 'id_res', 'openid.ns.ext1': 'http://openid.net/srv/ax/1.0', 'openid.signed': 'op_endpoint,claimed_id,identity,return_to,response_nonce,assoc_handle,ns.ext1,ext1.mode,ext1.type.email,ext1.value.email', 'openid.ext1.value.email': '[email protected]', 'openid.assoc_handle': 'AOQobUfssTJ2IxRlxrIvU4Xg8HHQKKTEuqwGxvwwuPR5rNvag0elGlYL', 'openid.ns': 'http://specs.openid.net/auth/2.0', 'openid.identity': 'https://www.google.com/accounts/o8/id?id=AItOawkghgfhf1FkvaQWhD-DxRJo6sS09RwMKjASE', 'openid.ext1.mode': 'fetch_response'} The socialauth itself has been built to accept my email address this way: elif request.openid and request.openid.ax: email = request.openid.ax.get('email') And obviously this fails. Why i am asking all this is, that perhaps i am doing something wrong and my outgoing request is wrong? Or am i doing all correctly and should change the socialaouth module to accept info in a new way and then commit the change? Alan

    Read the article

  • Django & google openid authentication (openid.ax) with socialauth

    - by Zayatzz
    Hello I am trying to use django-socialauth (http://github.com/uswaretech/Django-Socialauth) for authenticating users for my django project. This is firs time working with openid and i've had to figure out how exactly this open id works. I have more or less understood it, by now, but there are few things that elude me. The authentication process starts when the request is put together in in django-socialauth.openid_consumer.views.begin. I can see that the outgoing authentication request is more or less something like this: https://www.google.com/accounts/o8/ud?openid.assoc_handle=AOQobUckRThPUj3K1byG280Aze-dnfc9Iu6AEYaBwvHE11G0zy8kY8GZ& openid.ax.if_available=fname& openid.ax.mode=fetch_request& openid.ax.required=email& openid.ax.type.email=http://axschema.org/contact/email& openid.ax.type.fname=http://example.com/schema/fullname& openid.claimed_id=http://specs.openid.net/auth/2.0/identifier_select& openid.identity=http://specs.openid.net/auth/2.0/identifier_select& openid.mode=checkid_setup&openid.ns=http://specs.openid.net/auth/2.0& openid.ns.ax=http://openid.net/srv/ax/1.0& openid.ns.sreg=http://openid.net/extensions/sreg/1.1& openid.realm=http://localhost/& openid.return_to=http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T11%3A19%3A44ZPZCjNc&openid.sreg.optional=postcode,country,nickname,email This is lot like 2nd example here: http://code.google.com/apis/accounts/docs/OpenID.html#Samples The problem is, that the request, i get back, is nothing like the corresponding example from code.google.com (look at the 3rd example in example responses. Response dict i get is like this: { 'openid.op_endpoint': 'https://www.google.com/accounts/o8/ud', 'openid.sig': 'QWMa4x4ruMUvSCfLwKV6CZRuo0E=', 'openid.ext1.type.email': 'http://axschema.org/contact/email', 'openid.return_to': 'http://localhost/social/gmail_login/complete/?janrain_nonce=2010-03-20T17%3A54%3A06ZHV4cqh', 'janrain_nonce': '2010-03-20T17:54:06ZHV4cqh', 'openid.response_nonce': '2010-03-20T17:54:06ZdC5mMu9M_6O4pw', 'openid.claimed_id': 'https://www.google.com/accounts/o8/id?id=AItOghawkFz0aNzk91vaQWhD-DxRJo6sS09RwM3SE', 'openid.mode': 'id_res', 'openid.ns.ext1': 'http://openid.net/srv/ax/1.0', 'openid.signed': 'op_endpoint,claimed_id,identity,return_to,response_nonce,assoc_handle,ns.ext1,ext1.mode,ext1.type.email,ext1.value.email', 'openid.ext1.value.email': '[email protected]', 'openid.assoc_handle': 'AOQobUfssTJ2IxRlxrIvU4Xg8HHQKKTEuqwGxvwwuPR5rNvag0elGlYL', 'openid.ns': 'http://specs.openid.net/auth/2.0', 'openid.identity': 'https://www.google.com/accounts/o8/id?id=AItOawkghgfhf1FkvaQWhD-DxRJo6sS09RwMKjASE', 'openid.ext1.mode': 'fetch_response'} The socialauth itself has been built to accept my email address this way: elif request.openid and request.openid.ax: email = request.openid.ax.get('email') And obviously this fails. Why i am asking all this is, that perhaps i am doing something wrong and my outgoing request is wrong? Or am i doing all correctly and should change the socialaouth module to accept info in a new way and then commit the change? Alan

    Read the article

  • How to unit test django middleware?

    - by luc
    I've implemented a django middleware for getting pages from the database (something similar to the flatpage subframework) Unfortunately it seems that it is not possible to test it with the django testing framework. Any suggestion? Thanks in advance Update: maybe a mistake in my test but I can't get an object that should be returned by a middleware. I'll inverstigate more. Does anybody have unit-tested a middleware code?

    Read the article

  • Unit Testing a Django Form with a FileField

    - by Jason Christa
    I have a form like: #forms.py from django import forms class MyForm(forms.Form): title = forms.CharField() file = forms.FileField() #tests.py from django.test import TestCase from forms import MyForm class FormTestCase(TestCase) def test_form(self): upload_file = open('path/to/file', 'r') post_dict = {'title': 'Test Title'} file_dict = {} #?????? form = MyForm(post_dict, file_dict) self.assertTrue(form.is_valid()) How do I construct the *file_dict* to pass *upload_file* to the form?

    Read the article

  • Filter Django Haystack results like QuerySet?

    - by prometheus
    Is it possible to combine a Django Haystack search with "built-in" QuerySet filter operations, specifically filtering with Q() instances and lookup types not supported by SearchQuerySet? In either order: haystack-searched -> queryset-filtered or queryset-filtered -> haystack-searched Browsing the Django Haystack documentation didn't give any directions how to do this.

    Read the article

  • Django-cms problem

    - by 47
    I'm setting up a website using django-cms and when I open up the add page view in the admin, I get this error: TemplateSyntaxError at /admin/cms/page/add/ Invalid block tag: 'csrf_token' What could be the problem? I'm using Django 1.1. BTW.

    Read the article

  • internationalisation in django

    - by ha22109
    Hello , I am doing internationalisation in django admin.I am able to convert all my text to the specific langauge.But i m not able to change the 'app' name suppose django-admin.py startapp test this will create a app called test inside my project.Inside this app 'test' i can create many classes in my model.py file.But when i register my app 'test' in settings.py file.I am convert all the text in the locale of my browser but my app heading 'test' is not getting changed.How to change that any idea?

    Read the article

  • django filebrowser extensions problem

    - by Borislav
    Hi, I've set django filebrowser's debug to True and wrote the extension restrictions in the model. pdf = FileBrowseField("PDF", max_length=200, directory="documents/", extensions=['.pdf', '.doc', '.txt'], format='Document', blank=True, null=True) In django admin it shows correctly with debug info. Directory documents/ Extensions ['.pdf', '.doc', '.txt'] Format Document But when I call the filebrowser, it allows all file extensions to be uploaded. How can I restrict filebrowser to upload only certain filetypes that I want? Thanks everyone

    Read the article

  • django admin site make CharField a PasswordInput

    - by Paul
    I have a Django site in which the site admin inputs their Twitter Username/Password in order to use the Twitter API. The Model is set up like this: class TwitterUser(models.Model): screen_name = models.CharField(max_length=100) password = models.CharField(max_length=255) def __unicode__(self): return self.screen_name I need the Admin site to display the password field as a password input, but can't seem to figure out how to do it. I have tried using a ModelAdmin class, a ModelAdmin with a ModelForm, but can't seem to figure out how to make django display that form as a password input...

    Read the article

< Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >