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  • Access uploaded file in JSON encoded data

    - by okello
    I've encoded my form data into JSON. This has been achieved by the following ExtJS store configuration: Ext.define('XXX.store.Registration', { extend: 'Ext.data.Store', model: 'XXX.model.Registration', autoLoad: true, pageSize: 15, autoLoad: { start: 0, limit: 15 }, proxy: { type: 'ajax', api: { create: './server/registration/create.php', read: './server/registration/get.php', update: './server/registration/update.php', destroy: './server/registration/destroy.php' }, reader: { type: 'json', root: 'registrations', successProperty: 'success' }, writer: { type: 'json', writeAllFields: true, encode: true, root: 'registrations' } } }); My server side code has been implemented in PHP. I can access the encoded form fields by using the field name as a key, as exemplified below: $reg = $_REQUEST['registrations']; $data = json_decode(stripslashes($reg)); $registerNum = $data->registerNum; $folioNum = $data->folioNum; One of the fields in my form is a fileuploadfield. How can I access the uploaded file from the uploaded JSON. Any assistance will be highly appreciated.

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  • get foreign key objects in a single query - Django

    - by John
    Hi I have 2 models in my django code: class ModelA(models.Model): name = models.CharField(max_length=255) description = models.CharField(max_length=255) created_by = models.ForeignKey(User) class ModelB(models.Model): category = models.CharField(max_length=255) modela_link = models.ForeignKey(ModelA, 'modelb_link') functions = models.CharField(max_length=255) created_by = models.ForeignKey(User) Say ModelA has 100 records, all of which may or may not have links to ModelB Now say I want to get a list of every ModelA record along with the data from ModelB I would do: list_a = ModelA.objects.all() Then to get the data for ModelB I would have to do for i in list_a: i.additional_data = i.modelb_link.all() However this runs a query on every instance of i. Thus making 101 queries to run. Is there any way of running this all in just 1 query. Or at least less than the 101 queries. I've tried putting in ModelA.objects.select_related().all() but this didn't seem to have any effect. Thanks

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  • Handling file upload in a non-blocking manner

    - by Kaliyug Antagonist
    The background thread is here Just to make objective clear - the user will upload a large file and must be redirected immediately to another page for proceeding different operations. But the file being large, will take time to be read from the controller's InputStream. So I unwillingly decided to fork a new Thread to handle this I/O. The code is as follows : The controller servlet /** * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse * response) */ protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub System.out.println("In Controller.doPost(...)"); TempModel tempModel = new TempModel(); tempModel.uploadSegYFile(request, response); System.out.println("Forwarding to Accepted.jsp"); /*try { Thread.sleep(1000 * 60); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); }*/ request.getRequestDispatcher("/jsp/Accepted.jsp").forward(request, response); } The model class package com.model; import java.io.IOException; import java.util.concurrent.ExecutionException; import java.util.concurrent.Future; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.utils.ProcessUtils; public class TempModel { public void uploadSegYFile(HttpServletRequest request, HttpServletResponse response) { // TODO Auto-generated method stub System.out.println("In TempModel.uploadSegYFile(...)"); /* * Trigger the upload/processing code in a thread, return immediately * and notify when the thread completes */ try { FileUploaderRunnable fileUploadRunnable = new FileUploaderRunnable( request.getInputStream()); /* * Future<FileUploaderRunnable> future = ProcessUtils.submitTask( * fileUploadRunnable, fileUploadRunnable); * * FileUploaderRunnable processed = future.get(); * * System.out.println("Is file uploaded : " + * processed.isFileUploaded()); */ Thread uploadThread = new Thread(fileUploadRunnable); uploadThread.start(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } /* * catch (InterruptedException e) { // TODO Auto-generated catch block * e.printStackTrace(); } catch (ExecutionException e) { // TODO * Auto-generated catch block e.printStackTrace(); } */ System.out.println("Returning from TempModel.uploadSegYFile(...)"); } } The Runnable package com.model; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.nio.ByteBuffer; import java.nio.channels.Channels; import java.nio.channels.ReadableByteChannel; public class FileUploaderRunnable implements Runnable { private boolean isFileUploaded = false; private InputStream inputStream = null; public FileUploaderRunnable(InputStream inputStream) { // TODO Auto-generated constructor stub this.inputStream = inputStream; } public void run() { // TODO Auto-generated method stub /* Read from InputStream. If success, set isFileUploaded = true */ System.out.println("Starting upload in a thread"); File outputFile = new File("D:/06c01_output.seg");/* * This will be changed * later */ FileOutputStream fos; ReadableByteChannel readable = Channels.newChannel(inputStream); ByteBuffer buffer = ByteBuffer.allocate(1000000); try { fos = new FileOutputStream(outputFile); while (readable.read(buffer) != -1) { fos.write(buffer.array()); buffer.clear(); } fos.flush(); fos.close(); readable.close(); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println("File upload thread completed"); } public boolean isFileUploaded() { return isFileUploaded; } } My queries/doubts : Spawning threads manually from the Servlet makes sense to me logically but scares me coding wise - the container isn't aware of these threads after all(I think so!) The current code is giving an Exception which is quite obvious - the stream is inaccessible as the doPost(...) method returns before the run() method completes : In Controller.doPost(...) In TempModel.uploadSegYFile(...) Returning from TempModel.uploadSegYFile(...) Forwarding to Accepted.jsp Starting upload in a thread Exception in thread "Thread-4" java.lang.NullPointerException at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:512) at org.apache.coyote.http11.InternalInputBuffer.fill(InternalInputBuffer.java:497) at org.apache.coyote.http11.InternalInputBuffer$InputStreamInputBuffer.doRead(InternalInputBuffer.java:559) at org.apache.coyote.http11.AbstractInputBuffer.doRead(AbstractInputBuffer.java:324) at org.apache.coyote.Request.doRead(Request.java:422) at org.apache.catalina.connector.InputBuffer.realReadBytes(InputBuffer.java:287) at org.apache.tomcat.util.buf.ByteChunk.substract(ByteChunk.java:407) at org.apache.catalina.connector.InputBuffer.read(InputBuffer.java:310) at org.apache.catalina.connector.CoyoteInputStream.read(CoyoteInputStream.java:202) at java.nio.channels.Channels$ReadableByteChannelImpl.read(Unknown Source) at com.model.FileUploaderRunnable.run(FileUploaderRunnable.java:39) at java.lang.Thread.run(Unknown Source) Keeping in mind the point 1., does the use of Executor framework help me in anyway ? package com.utils; import java.util.concurrent.Future; import java.util.concurrent.ScheduledThreadPoolExecutor; public final class ProcessUtils { /* Ensure that no more than 2 uploads,processing req. are allowed */ private static final ScheduledThreadPoolExecutor threadPoolExec = new ScheduledThreadPoolExecutor( 2); public static <T> Future<T> submitTask(Runnable task, T result) { return threadPoolExec.submit(task, result); } } So how should I ensure that the user doesn't block and the stream remains accessible so that the (uploaded)file can be read from it?

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  • What is the proper way to check the previous value of a field before saving an object? (Using Django

    - by anonymous coward
    I have a Django Model with updated_by and an approved_by fields, both are ForeignKey fields to the built-in (auth) User models. I am aware that with updated_by, it's easy enough to simply over-ride the .save() method on the Model, and shove the request.user in that field before saving. However, for approved_by, this field should only ever be filled in when a related field (date_approved) is first filled in. I'm somewhat certain that I can check this logically, and fill in the field if the previous value was empty. What is the proper way to check the previous value of a field before saving an object? I do not anticipate that date_approved will ever be changed or updated, nor should there be any reason to ever update the approved_by entry. UPDATE: Regarding forms/validation, I should have mentioned that none of the fields in question are seen by or editable by users of the site. If I have misunderstood, I'm sorry, but I'm not sure how forms and validation apply to my question.

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  • How can I traverse a reverse generic relation in a Django template?

    - by user569139
    I have the following class that I am using to bookmark items: class BookmarkedItem(models.Model): is_bookmarked = models.BooleanField(default=False) user = models.ForeignKey(User) content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey() And I am defining a reverse generic relationship as follows: class Link(models.Model): url = models.URLField() bookmarks = generic.GenericRelation(BookmarkedItem) In one of my views I generate a queryset of all links and add this to a context: links = Link.objects.all() context = { 'links': links } return render_to_response('links.html', context) The problem I am having is how to traverse the generic relationship in my template. For each link I want to be able to check the is_bookmarked attribute and change the add/remove bookmark button according to whether the user already has it bookmarked or not. Is this possible to do in the template? Or do I have to do some additional filtering in the view and pass another queryset?

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  • Why does the check for an interface fail?

    - by chobo
    I have a class that implements an interface. In another area of the code I check if that class instance contains that interface, but it doesn't work. The check to see if the class contains the interface always fails (false) when it should be true. Below is a simple representation of what I am trying to accomplish. Example public interface IModel { bool validate(); } public class SomeModel : IModel { public SomeModel { } public bool Validate() { return true; } } // Dummy method public void Run() { SomeModel model = new SomeModel(); if (model is IModel) { string message = "It worked"; } else { string message = "It failed"; } }

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  • Rails Authlogic authentication method

    - by Rabbott
    Within Authlogic, is there a way that I can add conditions to the authentication method? I know by using the find_by_login_method I can specify another method to use, but when I use this I need to pass another parameter since the find_by_login_method method only passes the parameter that is deemed the 'login_field'. What I need to do is check something that is an association of the authentic model.. Here is the method I want to use # make sure that the user has access to the subdomain that they are # attempting to login to, subdomains are company names def self.find_by_email_and_company(email, company) user = User.find_by_email(email) companies = [] user.brands.each do |b| companies << b.company.id end user && companies.include?(company) end But this fails due to the fact that only one parameter is sent to the find_by_email_and_company method. The company is actually the subdomain, so in order to get it here I am just placing it in a hidden field in the form (only way I could think to get it to the model) Is there a method I can override somehow..?

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  • MVC Display Template for Generic Type

    - by Kyle
    I am trying to use the model ListModel as a generic list model. I would like to enter on the page @Html.DisplayForModel() However the MVC is not correctly finding the templated file "ListModel.cshtml". It must work differently for generic models. What should I name the templated file in order for it to correctly be located? public class ListModel<T> { public IEnumerable<T> Models {get;set;} public string NextPage {get;set;} } I would expect it to look for "Shared/DisplayTemplates/ListModel.ascx" but it doesn't. Does anyone know?

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  • Rails 2.3.5: How does one add an error when it doesn't make sense to put it in a validation?

    - by randombits
    I recently was trying to add errors.add_to_base code in the middle of some model logic and was wondering why it wasn't showing up in my view that was iterating over all errors. I then ran across this e-mail which explains why: http://groups.google.com/group/rubyonrails-talk/browse_thread/thread/e045ec1dead1ff06?pli=1 The question is then, how does one add errors with add_to_base if it doesn't make sense to put them into a validate method? I have some complex logic. The model needs to talk to a has_many relationship which has its own relationships that go through a myriad of conditionals to figure out if a request makes sense. It's nothing that can be tied to a validate method easily. How does one add errors then accordingly?

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  • problem using keil uvision 3

    - by Blossom
    I am trying to compile a C code using Keil uvision 3. The entire code gets compiled only if I use large memory model by choosing option xdata for target. To use this model I have to use external data RAM which is not possible for me due to some reasons. So I decided to go with pdata option. Can anybody please help me with the exact steps to be carried out for using pdata? I am using 89V51RD2. I am much confused with the options like BL51 MISC, BL51 Locate etc.

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  • Caching Models in rails

    - by jules
    I have a rails application, with a model that is a kind of repository. The records stored in the DB for that model are (almost) never changed, but are read all the time. Also there is not a lot of them. I would like to store these records in cache, in a generic way. I would like to do something like acts_as_cached, but here are the issue I have: I can not find a decent documentation for acts as cached (neither can I find it's repository) I don't want to use memcached, but something simpler (static variable, or something like that). Do you have any idea of what gems I could use to do that ? Thanks

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  • Html.ActionLink in a button

    - by Pomster
    I Am trying to connect to a method in my controller, with a button. I can connect though this link: @Html.ActionLink("Print", "Print", new { id = Model.SalesContractId}) But i Don't want a link, i want my button on my dialog to do it. I have tried the following: $('#btnDialogPrint').click(function () { location.href = '<%= Url.Action("Print", "Print", new { id = Model.SalesContractId}) %>'; }); But it just redirect me to a page that say bad request. namespace Contract.Controllers { public class ContractController : Controller { CompassEntities db = new CompassEntities(); public ActionResult Print(int id) { return View(""); // This can be removed and Print code may be added } Don't worry about the code inside i will get to that once i get inside this method. Could i maybe attach a link here? <input type="button" value="Print" id="btnDialogPrint" />

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  • Rails - inheritance hierarchy of classes where a subtype can play two roles

    - by Miquel
    I need to model Owners and Rentees in an application, so you have stuff that is always owned by someone and can be rented for someone else. I first approached this problem with Single Table Inheritance because both types of person will share all attributes, so you would have a model called Person associated to a table people with Owner and Rentee inheriting from Person. The problem is that Single type inheritance discerns subtypes using a field type and therefore a record in the table can represent either an Owner or a Rentee but not both at the same time, while in the real context you can have an Owner which is renting something from another Owner and therefore that person is at the same time an Owner and a Rentee. How would you approach this problem? Would you use separated tables for owners and rentees? Is there any other type of table inheritance in Rails?

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  • @ExceptionHandler doesn't handle the thrown exceptions

    - by Javi
    Hello, I have a method in my controller which will handle the exceptions thrown by the application. So I have a method like this one. @Controller public class ExceptionController { @RequestMapping(value="/error") @ExceptionHandler(value={Exception.class, NullPointerException.class}) public String showError(Exception e, Model model){ return "tiles:error"; } } And to try I if it works I throw a NullPointerException in another method in other method controller: boolean a = true; if(a){ throw new NullPointerException(); } After the exception is thrown it is printed in the JSP, but it doesn't go throw my showError() method (I've set a breakpoint there and it never enters). showError() method will catch the exception and will show different error pages depending on the exception type (though now it always shows the same error page). If I go to the url /error it shows the error page so the showError() method is OK. I'm using Spring 3. What can be the problem? Thanks.

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  • ASP.NET MVC2 TeplatedHelper doesn't render an ID of the HTML's markup

    - by Tony
    Hi, I have the code (snippet): The Model is the IEnumerable object of the Person's class: <% foreach (var item in Model) { %> <tr> <td><%= Html.DisplayFor(x=>item.Name) %></td> </tr> <% } %> it renders only labels like that: <td>Tommy</td> According to the link it should be rendering a HTML markup something like: but there is no the ID and the NAME property. Why ?

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  • ASP.NET MVC2 : DateTime modelbinding via HTTP GET

    - by mathieu
    I'm getting some trouble binding a date from QueryString : I have the following model public class QueryParms { public DateTime Date { get; set; } } And the following controller action : public ActionResult Search( QueryParms query ); I have a form, with a field where I can type my date. If the form is FormMethod.Post, everything is fine, my date is correctly bound to my model. If the form is FormMethod.Get, it is not working anymore. The date is left to the default value (01/01/0001) I think it is a culture issue : When i look into the value provider, the FormValueProvider has a culture property set for my date : {fr-FR}. The QueryStringValueProvider doesn't have the culture property set. Is there a way to set this property ?

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  • I want to select the distict value from models field and then update them (django)

    - by qulzam
    I have models... class Item(models.Model): name = models.CharField('Item Name', max_length = 30) item_code = models.CharField(max_length = 10) color = models.CharField(max_length = 150, null = True, blank = True) size = models.CharField(max_length = 30, null = True, blank = True) fabric_code = models.CharField(max_length = 30, null = True, blank = True) I have values in Item. in Item model name field has the similar values..(but the other values of record are change). I want to select the name field values distinctly(ie similar values select only ones). in one box(like combo box). What kind of form or views i use??

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  • mvc3 ActionResult does not reload page if is already on it

    - by senzacionale
    public ActionResult DeleteCategory(int id) { CategoryManager manager = new CategoryManager(); manager.DeleteCategory(id); TempData["IsDeleted"] = true; return RedirectToAction("CategoriesList"); } public ActionResult CategoriesList() { List<CategoryModel> model = new CategoryManager().GetAll(); return View(model); } public void DeleteCategory(int categoryId) { using (AsoEntities context = new AsoEntities()) { var categoryToDelete = (from c in context.Categories where c.Id == categoryId select c).SingleOrDefault(); if (categoryToDelete == null) return; context.Categories.DeleteObject(categoryToDelete); context.SaveChanges(); } } when i delete article i go back to CategoriesList but page is not reloaded if i am already on CategoriesList. What to do that page will be reloaded and data will be changed?

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  • Extending appengine's db.Property with caching

    - by Noio
    I'm looking to implement a property class for appengine, very similar to the existing db.ReferenceProperty. I am implementing my own version because I want some other default return values. My question is, how do I make the property remember its returned value, so that the datastore query is only performed the first time the property is fetched? What I had is below, and it does not work. I read that the Property classes do not belong to the instances, but to the model definition, so I guess that the return value is not cached for each instance, but overwritten on the model every time. Where should I store this _resolved variable? class PageProperty(db.Property): data_type = Page def get_value_for_datastore(self, model_instance): page = super(PageProperty, self).get_value_for_datastore(model_instance) self._resolved = page return page.key().name() def make_value_from_datastore(self, value): if not hasattr(self, '_resolved'): self._resolved = Page.get_by_name(value) return self._resolved

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  • how to don't store a repeated field of a Symfony form?

    - by user454760
    Hello everybody, I am working with Symfony 1.4 and Doctrine. I have a model A with a email field. The form of A, display an input in which the user should insert the email correctly. But as everybody know sometiemes they don't do it. To fix this i have insert an extra field in the model (and in the form), called *repeat_email* to prevent the misspellings. Then, in the validation process, after validates all the fields, i use a global validator to compare the data of the two fields. This works, but i don't want to have the email stored two times in the database (i don't want the *repeat_email*). Is there any mechanism to use it in the validation process, but not to store it in the database? Thanks,

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  • Avoiding sub-type selection in view code

    - by John Donoghue
    Hi, I have some code where the model contains some classes like (vb.net pseudocode, but could be any OO language): Enum AttributeType Boolean Date String End Enum MustInherit Class Attibute Must Override Function Type As AttributeType End Class Class BooleanAttribute: Attribute Function Type As AttributeType Return AttributeType.Boolean End Function End Class And the view contains some code like: Select Case AttributeType Case Boolean //Display checkbox control Case Date //Display date picker control Case String //Display textbox control End Select I don't really like the code in the view, for the hopefully obvious reasons (what happens when I get a new attribute type etc). My question is, how should I replace it? I could easily add a method to the concrete classes, but that pollutes the model with UI stuff so that's a horrible idea. I could move the select into a factory, but that seems to be just hiding the problem. Can anybody advise a better approach?

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  • Can I Use EF Across Multiple DBs in One SQLServer Instance?

    - by thomashubschman
    Hello, I have been searching the blogs and articles but I have not found much support for this scenario. I have been poking around EF and realized that I could create views that contained data from multiple databases and then build the EF object model off of those views. Although it works I am not sure about the usual issues of performance, scalability, maintainability. The way I am achieving the connection between databases is by creating associations in the EF model. Does anyone have any information about this type of implementation? Either another solution or commentary on this proposed solution? Thanks, Tom

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  • How to test that action uses argument?

    - by Caster Troy
    I am supposed to be using test-driven development but in this particular case, as I am having trouble, I implemented the action method first. It looks like this: public ViewResult Index(int pageNumber = 1) { var posts = repository.All(); var model = new PagedList<Post>(posts, pageNumber, PageSize); return View(model); } Both the repository and the PagedList<> have been tested already. Now I want to verify that when the action is given a page number that the page number is actually considered. private Mock<IPostsRepository> repository; private HomeController controller; [Test] public void Index_Doohickey() { var actual = controller.Index(2); // .. How do I test that the controller actually uses the page number here? }

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  • Rails: How to have dynamic association

    - by Aaron Dufall
    I'll use an example to explain what behaviour I would like to achieve. If you had a project management app and you added a task, but not all the contributors are users of the app. So when you adding contributors to the task you can enter a user name or email address. Here is the part that I'm finding a little tricky. The task model has many contributors which are linked through the user model, but from this point on I want to achieve 2 things. Store the non members email(this would obviously be quite simple) If that email address was to create an account it would then link that user to the task and remove the temporally saved email. This way, when that user creates an account all the related tasks will already be associated with their email. Is this something that i could achieve with a polymorphic association? or is there something else I should be looking at?

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  • I can't delete record in Codeigniter

    - by jomblo
    I'm learning CRUD in codeigniter. I have table name "posting" and the coloumns are like this (id, title, post). I successed to create a new post (both insert into database and display in the view). But I have problem when I delete my post in the front-end. Here is my code: Model Class Post_Model extends CI_Model{ function index(){ //Here is my homepage code } function delete_post($id) { $this->db->where('id', $id); $this->db->delete('posting'); } } Controller Class Post extends CI_Controller{ function delete() { $this->load->model('Post_Model'); $this->Post_Model->delete_post("id"); redirect('Post/index/', 'refresh'); } } After click "delete" in the homepage, there was nothing happens. While I'm looking into my database, my records still available. Note: (1) to delete record, I'm following the codeigniter manual / user guide, (2) I found a message error (Undefined variable: id) after hiting the "delete" button in the front-end Any help or suggestion, please

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