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  • Saving form values to database after a user logs in

    - by redfalcon
    Hi. We have a form with ratings to submit for a certain restaurant. After the user has entered some values and wants to submit them, we check whether the user is logged in or not. If not, we display a login form and let the user put in his account data and redirect him to the restaurant he wanted to submit a rating for. The problem is, that after he successfully logged in himself, the submitted values are not saved to the database (which works fine if the user is already logged in). So I wondered if it is possible, to somehow save the data although the user is not logged in. I thought of maybe saving the filled values in a variable and have then automatically re-entered after we redirected the user. But I guess this wont work because we use before_filter :login_required, :only => [ :create ] So we couldnt even access the filled in values, since we display the login-form before the method has processed the values in the form, right? Any idea how we can make rails to save the values or at least have them automatically re-entered to the form? Thanks!

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  • Assigning values to the lable through database depending on listbox values

    - by SurajVitekar
    I want to assign the values of five labels from database regarding to values selected in listbox. The db query returns single column with multiple records. Please help. I'm working with C# 2010 and MS SQL. My current code is: private void listBox1_SelectedIndexChanged(object sender, EventArgs e) { try { String c1, c2; c1 = "NULL"; MessageBox.Show("LB index :"+listBox1.SelectedIndex.ToString()); //p = listBox1.SelectedItem.ToString(); SqlConnection con = new SqlConnection(); con.ConnectionString = "Data Source=localhost;Initial Catalog=eVoting;Integrated Security=True;Pooling=False"; con.Open(); MessageBox.Show("List bOx sect :"+listBox1.SelectedValue.ToString()); SqlCommand cmd = new SqlCommand("select Firstname from candidates where position ='" + listBox1.SelectedValue.ToString() + "'", con); int index = 0; SqlDataReader reader = cmd.ExecuteReader(); while(reader.Read()) { if (index == 0) { c1 = reader[index].ToString(); radioButton1.Text = c1; } if (index == 1) { c1 = reader[index].ToString(); radioButton2.Text = c1; } if (index == 2) { c1 = reader[index].ToString(); radioButton3.Text = c1; } if (index == 3) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 4) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 5) { c1 = reader[index].ToString(); radioButton5.Text = c1; } MessageBox.Show("c1 :" + c1); index++; } } catch (Exception E) { } }

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  • Create Dynamically table at runtime & save it in database

    - by user1548245
    I have written a code for creating table. It displays table structure on GUI form, but what I want is, when I enter values into table it should be stored in database table too. My code: <?php function display($column,$rows) { echo "<table border='1' align='center'>"; for ($iii = 0;$iii <$_POST['column'];$iii++) { echo "<tr>".$jjj."</tr>"; //display no. of <tr> for ($jjj = 0; $jjj <$_POST['rows'];$jjj++) { echo "<td>" ."<input type=\"text\" name='$iii'>"."</td>"; } } echo "</table>"; } ?>

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  • Problem with SqlLite database in Qt SDK 1.0.2

    - by Risino
    Hi I have a problem with SqlLite database. Here is my code: void incomeDialog::on_add_pushButton_clicked() { int a = ui->income_lineEdit->text().toInt(); int b = ui->other_lineEdit->text().toInt(); int c = (a+b); db = QSqlDatabase::addDatabase("QSQLITE"); db.setDatabaseName("money.db"); QSqlQuery query(db); query.exec("create table Income" "(Month TEXT, Payment NUMBER, Other NUMBER, Together NUMBER)"); query.prepare("INSERT INTO Income values (?,?,?,?)"); query.addBindValue(ui->comboBox->currentText()); query.addBindValue(ui->income_lineEdit->text().toInt()); query.addBindValue(ui->other_lineEdit->text().toInt()); query.addBindValue(c); query.exec(); } I use qt sdk 1.0.2. After building shows errors: Undefined reference to 'QSqlDatabase::addDatabase(QString const&, QString const&)... all errors is similar (Undefined reference to 'QSqlDatabase:: Do you have any idea how to repair it?

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  • codeigniter populate form from database

    - by Delirium tremens
    In the controller, I have... function update($id = null) { $this->load->database(); // more code $data = array(); $data = $this->db->get_where( 'users', array( 'id' => $id ) ); $data = $data->result_array(); $data = $data[0]; // more code $this->load->view('update', $data); } In the view, I have... <h5>Username</h5> <input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" /> <h5>Email</h5> <input type="text" name="email" value="<?php echo set_value('email'); ?>" size="50" /> <h5>Email Confirmation</h5> <input type="text" name="emailconf" value="<?php echo set_value('emailconf'); ?>" size="50" /> <h5>Password</h5> <input type="text" name="password" value="<?php echo set_value('password'); ?>" size="50" /> <h5>Password Confirmation</h5> <input type="text" name="passconf" value="<?php echo set_value('passconf'); ?>" size="50" /> set_value() isn't reading $data search for value="" at http://codeigniter.com/forums/viewthread/103837/ The poster uses only the set_value() function between "" in value="". I'm wondering how to do the same, but I can't get it to work. Help?

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  • fetching the label text from database in C#

    - by Yilmaz Paçariz
    private void button5_Click(object sender, EventArgs e) { SqlConnection conn = new SqlConnection("Data Source=MAZI-PC\\PROJECTACC;Initial Catalog=programDB;Integrated Security=True"); SqlCommand cmd = new SqlCommand("select label_sh from label_text where label_form='2' and label_form_labelID='1'", conn); conn.Open(); label1.Text = cmd.ExecuteReader().ToString(); conn.Close(); SqlConnection conn1 = new SqlConnection("Data Source=MAZI-PC\\PROJECTACC;Initial Catalog=programDB;Integrated Security=True"); SqlCommand cmd1 = new SqlCommand("select label_sh from label_text where label_form='2' and label_form_labelID='2'", conn1); conn1.Open(); label2.Text = cmd1.ExecuteReader().ToString(); conn1.Close(); SqlConnection conn2 = new SqlConnection("Data Source=MAZI-PC\\PROJECTACC;Initial Catalog=programDB;Integrated Security=True"); SqlCommand cmd2 = new SqlCommand("select label_sh from label_text where label_form='2' and label_form_labelID='3'", conn2); conn2.Open(); label3.Text = cmd2.ExecuteReader().ToString(); conn2.Close(); } I am developing a small project in C#... Using Visiual Studio 2010... I want to fetch the label texts from database in order to change the user interface language with a button... I wrote this code but there is a problem in SQLDATAREADER in label text parts it shows System.Data.SqlClient.SqlDataReader I cant fix, could you help me?

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  • LINQ to SQL - database relationships won't update after submit

    - by Quantic Programming
    I have a Database with the tables Users and Uploads. The important columns are: Users -> UserID Uploads -> UploadID, UserID The primary key in the relationship is Users -> UserID and the foreign key is Uploads -> UserID. In LINQ to SQL, I do the following operations: Retrieve files var upload = new Upload(); upload.UserID = user.UserID; upload.UploadID = XXX; db.Uploads.InsertOnSubmit(upload) db.SubmitChanges(); If I do that and rerun the application (and the db object is re-built, of course) - if do something like this: foreach(var upload in user.Uploads) I get all the uploads with that user's ID. (like added in the previous example) The problem is, that my application, after adding an upload an submitting changes, doesn't update the user.Uploads collection. i.e - I don't get the newly added uploads. The user object is stored in the Session object. At first, I though that the LINQ to SQL Framework doesn't update the reference of the object, therefore I should simply "reset" the user object from a new SQL request. I mean this: Session["user"] = db.Users.Where(u => u.UserID == user.UserID).SingleOrDefault(); (Where user is the previous user) But it didn't help. Please note: After rerunning the application, user.Uploads does have the new upload! Did anyone experience this type of problem, or is it normal behavior? I am a newbie to this framework. I would gladly take any advice. Thank you!

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  • database design - empty fields

    - by imanc
    Hey, I am currently debating an issue with a guy on my dev team. He believes that empty fields are bad news. For instance, if we have a customer details table that stores data for customers from different countries, and each country has a slightly different address configuration - plus 1-2 extra fields, e.g. French customer details may also store details for entry code, and floor/level plus title fields (madamme, etc.). South Africa would have a security number. And so on. Given that we're talking about minor variances my idea is to put all of the fields into the table and use what is needed on each form. My colleague believes we should have a separate table with extra data. E.g. customer_info_fr. But this seams to totally defeat the purpose of a combined table in the first place. His argument is that empty fields / columns is bad - but I'm struggling to find justification in terms of database design principles for or against this argument and preferred solutions. Another option is a separate mini EAV table that stores extra data with parent_id, key, val fields. Or to serialise extra data into an extra_data column in the main customer_data table. I think I am confused because what I'm discussing is not covered by 3NF which is what I would typically use as a reference for how to structure data. So my question specifically: - if you have slight variances in data for each record (1-2 different fields for instance) what is the best way to proceed?

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  • JQuery datepicker icon trigger broken after inserting data to database

    - by crisgine callano
    at first i got to load my icon for the JQuery datepicker but after i insert the value to my database the icon image is broken. im using Codeigniter framework. here's my html code: <!DOCTYPE HTML> <html lang="en-US"> <head> <meta charset="UTF-8"> <title>CRUD</title> <?php echo link_tag(base_url() . 'css/ui-lightness/jquery-ui-1.8.23.custom.css'); ?> </head> <body> <div> <?php echo form_label('BDay:', 'bday'); $data = array( 'name' => 'bday', 'id' => 'datepicker' ); echo form_input($data); ?> </div> </body> </html> and here's my jscript: <script> $(function() { $( "#datepicker" ).datepicker({ changeMonth: true, changeYear: true, showOn: "button", buttonImage: "<?php echo base_url() . '/images/icons/calendar_24.png' ?>", buttonImageOnly: true, onSelect: function(dateText, inst){ $("input[name='bday']").val(dateText); } }); }); am i missing something? thanks!

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  • inserting facebook app users details to database

    - by fusion
    i'm trying to insert user details, who authorize the app, into the database, but nothing seems to be happening. the data is null and no record is being inserted. is there something wrong with the code? function insertUser($user_id,$sk,$conn) { //$info = $facebook->api_client->users_getInfo($user_id, 'first_name, last_name', 'name', 'sex'); $info = $facebook->api_client->fql_query("SELECT uid, first_name, last_name, name, sex FROM user WHERE uid = $user_id"); for ($i=0; $i < count($info); $i++) { $record = $info[$i]; $first_name=$record['first_name']; $last_name=$record['last_name']; $full_name=$record['name']; $gender=$record['sex']; } $data= mysql_query("select uid from users where uid='{$user_id}'",$conn); if(mysql_num_rows($data)==0) { $sql = "INSERT INTO users (uid,sessionkey, active, fname, lname, full_name, gender) VALUES('{$user_id}','{$sk}','1', '{$first_name}', '{$last_name}', '{$full_name}', '{$gender}')"; mysql_query($sql,$conn); return true; } return false; }

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  • php import larg table to phpmyadmin database

    - by safaali
    hi, I am so worry :( I dropped one of the tables from the database accidentally. fortunately, I have back-up. (I have used the "Auto backup for mysql") The back-up of the table is stored as .txt file (56 Megabytes) on my PC. I tried to import it by PhpMyAdmin and the import failed because the file is too large to import. then I uploaded the file to /home/tablebk directory. I have some experiences in php. I know that I would import it with this code, but i don't know the sql statment for this import. what is have to put as $line variable? please help me :( :( <?php $dbhost = 'localhost'; $dbuser = 'mysite'; $dbpw = 'password'; $dbname = 'databasename'; $file = @fopen('country.txt', 'r'); if ($file) { while (!feof($file)) { $line = trim(fgets($file)); $flag = mysql_query($line); if (isset($flag)) { echo 'Insert Successfully<br />'; } else { echo mysql_error() . '<br/>'; } flush(); } fclose($file); } echo '<br />End of File'; ?>

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  • SharePoint 2007 - Content deployment and swapping content database

    - by Mel Lota
    Hi all, I'm currently working on a SharePoint 2007 site which is setup to allow clients to author content on a staging server and then this is automatically pushed up to the live environment via content deployment. The content deployment is setup in the 'Content deployment jobs and paths' in central admin. Now the problem I've got is that it seems that historically there have been a mixture of full and incremental deployments done to the live site collection which according to Stefan Goßner's best practices post (http://blogs.technet.com/stefan_gossner/pages/content-deployment-best-practices.aspx) is a bad idea due to the fact that things soon become out of sync. It's gotten to the point where the content deployment has just stopped working and incremental or full deployments are throwing errors in the logs. What I'm thinking is that I probably need to perform a full content deployment to an empty site collection and then somehow switch the new clean site collection with the current live one. I was wondering if anybody has any experience with this and could provide any pointers, I'm currently investigating the feasibility of performing the clean content deployment and then switching the live content database with the new one, however in my tests I've found that as soon as I switch content databases, the incremental deployment still fails. Any help much appreciated. (Note: I did post this on SharePoint Overflow as well, but thought I'd put it on here in case anybody else has any ideas) Cheers

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  • Multiple ID's in database

    - by eric
    I have a database that contains a few tables such as person, staff, member, and supporter. The person table contains information about every staff, member, and supporter. The information it contains is name,address,email, and telephone. I also created an id that is the primary key. My issue is that I also have an primary key ID for staff, member, and supporter. For instance, in the person table is John with id 1. He is a supporter so in the supporter table is pID(for person id)to reference back to John with all his information and ID(for supporter ID). pID references to the person table and every person has an ID incremented by 1 starting at 1. supporter ID is for every supporter and also starts at 1 and is incremented by 1. Is it possible to have in the supporter table pID = 1 and supporter ID = 1? Another person may have a pID = 26 and supporter ID = 5. Or will supporter ID have to be different than the pID and be something like "sup"? So you would have pID = 1 and supporter ID = sup1 or pID = 26 and supporter ID = sup5

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  • Create ImageButton programatically depending on local database records

    - by user2507920
    As i described in title, i have a local db in sqlite. I want to create ImageButton parametrically. How many times is local database loop executing? Please see code below : RelativeLayout outerRelativeLayout = (RelativeLayout)findViewById(R.id.relativeLayout2_making_dynamically); db.open(); Cursor c = db.getAllLocal_Job_Data(); if(c!=null){ if(c.moveToFirst()){ do { RelativeLayout innerRelativeLayout = new RelativeLayout(CalendarActivity.this); innerRelativeLayout.setGravity(Gravity.CENTER); ImageButton imgBtn = new ImageButton(CalendarActivity.this); imgBtn.setBackgroundResource(R.drawable.color_001); RelativeLayout.LayoutParams imageViewParams = new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT); imgBtn.setLayoutParams(imageViewParams); // Adding the textView to the inner RelativeLayout as a child innerRelativeLayout.addView(imgBtn, new RelativeLayout.LayoutParams( ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); outerRelativeLayout.addView(innerRelativeLayout, new RelativeLayout.LayoutParams(ViewGroup.LayoutParams.WRAP_CONTENT, ViewGroup.LayoutParams.WRAP_CONTENT)); } while (c.moveToNext()); } } db.close(); But when i run the project, i can see only one button created there. I think there are many buttons but here image button is creating on last created image button. I think i should use android:layout_toRightOf with previous created button but i cant find how to place it here. I have tried some ideas but it did not change any thing. So please anybody has any idea to solve my problem then please share it with me.

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  • Automatically update php loop with data pulled from database

    - by John Svensson
    SQL STRUCTURE CREATE TABLE IF NOT EXISTS `map` ( `id` int(11) NOT NULL AUTO_INCREMENT, `x` int(11) NOT NULL, `y` int(11) NOT NULL, `type` varchar(50) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ; http://localhost/map.php?x=0&y=0 When I update the x and y via POST or GET, I would like to pull the new data from the database without refreshing the site, how would I manage that? Could someone give me some examples, because I am really stuck here. <?php mysql_connect('localhost', 'root', ''); mysql_select_db('hol'); $startX = $_GET['x']; $startY = $_GET['y']; $fieldHeight = 6; $fieldWidth = 6; $sql = "SELECT id, x, y, type FROM map WHERE x BETWEEN ".$startX." AND ".($startX+$fieldWidth). " AND y BETWEEN ".$startY." AND ".($startY+$fieldHeight); $result = mysql_query($sql); $positions = array(); while ($row = mysql_fetch_assoc($result)) { $positions[$row['x']][$row['y']] = $row; } echo "<table>"; for($y=$startY; $y<$startY+$fieldHeight; $y++) { echo "<tr>"; for($x=$startX; $x<$startX+$fieldWidth; $x++) { echo "<td>"; if(isset($positions[$x][$y])) { echo $positions[$x][$y]['type']; } else { echo "(".$x.",".$y.")"; } echo "</td>"; } echo "</tr>"; } echo "</table>"; ?>

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  • Counting character count in Access database column ins SQL

    - by jzr
    Good Evening. My problem is possibly very easy, I just have spent some time researching now and probably have a brain lock and unable to solve this, help would be much appreciated. database structure: col1 col2 col3 col4 ==================== 1233+4566+ABCD+CDEF 1233+4566+ACD1+CDEF 1233+4566+D1AF+CDEF I need to count character count in col3, wanted result in from the previous table would be: char count =========== A 3 B 1 C 2 D 3 F 1 1 2 is this possible to achieve by using SQL only? at the moment I am thinking of passing a parameter in to SQL query and count the characters one by one and then sum, however I did not start the VBA part yet, and frankly wouldn't want to do that. this is my query at the moment: PARAMETERS X Long; SELECT First(Mid(TABLE.col3,X,1)) AS [col3 Field], Count(Mid(TABLE.col3,X,1)) AS Dcount FROM TEST GROUP BY Mid(TABLE.col3,X,1) HAVING (((Count(Mid([TABLE].[col3],[X],1)))>=1)); ideas and help are much appreciated, as being said this is probably very for some of your guys, I don't usually work with access and SQL. Thanks.

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  • Creating dynamic icons based on data entered into database from django forms

    - by John Hoke
    So I'm using Django to create a projects page with multiple forms for each project. Let's call them form 1, 2, 3, and 4. Once you create a project you can fill out any of these forms. I want to create "buttons" or links for each one of the forms that would show up on the main page. Now this is the part I need help with: Step 1. I want it so that if you click on a button for a form (say form 1) and none exists for that project yet a pop up would come up saying "This form does not exist yet, are you sure you want to create one?". And if you'd answer yes you would be directed to the form page. Step 2. But if that form does exist, I don't want any pop up to open and I want the link to take the user directly to that page. Step 3. My next problem is this. These forms are in order, so if you didn't create form 1 but created form 2, I don't want to give the user access to form 1. So in this scenario, if you click on form 1 I want a pop up to open and say "This form can no longer be created", and the link wouldn't function anymore. Basically the button will have 3 function. First it should look at the database and if data for that specific form exists it should do "Step 2", if data for that form and the proceeding forms don't exist it should do "Step 1", and if data for that form doesn't exist but data for proceeding form's does exist is should do "Step 3". Is this possible? Please help as I need to find a solution to this soon. Any help would be highly appreciated. Thank you

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  • Trigger alert when database entries are added, not when they are removed

    - by Jeremy
    I have a jQuery script running that makes a periodic AJAX call using the following code. var a = moment(); var dayOfMonth = a.format("MMM Do"); var timeSubmitted = a.format("h:mm a"); var count_cases = -1; var count_claimed = -1; setInterval(function(){ //check if new lead was added to the db $.ajax({ type : "POST", url : "inc/new_lead_alerts_process.php", dataType: 'json', cache: false, success : function(response){ $.getJSON("inc/new_lead_alerts_process.php", function(data) { if (count_cases != -1 && count_cases != data.count) { window.location = "new_lead_alerts.php?id="+data.id; } count_cases = data.count; }); } }); This is the PHP that runs with each call: $count = mysql_fetch_array(mysql_query("SELECT count(*) as count FROM leads")); $client_id = mysql_fetch_array(mysql_query("SELECT id, client_id FROM leads ORDER BY id DESC LIMIT 1")); echo json_encode(array("count" => $count['count'], "id" => $client_id['id'], "client_id" => $client_id['client_id'])); I need to change the code so that the alert only triggers when a new entry is added to the database, not when an existing entry is removed. As it stands, the alert fires on both events. Any help is greatly appreciated.

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  • get the right id of a record in database in each click on the edit button

    - by kawtousse
    hi every one, i am facing a big problem right now. I have a html table in each row i have a button called edit allowing user to relod the form with parameter that he has selected. for this i define a hidden type to get the id of the record in database to access to various colonne and to refresh the form with those parameters. My challenge now is how to get the right id in every click on the edit button to let me after to get the right record and to update it in the data base. I am preceeding like the following: retour.append("<td style=border-right:#FFF bordercolor=#FFFFFF>"); retour.append("<input type=\"hidden\" id=\"id_"+nomTab+"_"+compteur+"\" value=\""+object.getIdDailyTimeSheet()+"\" name=\"hd"+compteur+"\" />"); retour.append("<button id=edit name=edit type=button onClick= editarow()>"); retour.append("<img src=edit.gif />"); retour.append("</button>"); retour.append("</td>"); i realise the submit in javascript and i want to get the idDailyTimesheet everyonce the user click the submit button. thanks for help.

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  • How to store a captured image into MySQL database using JavaScript

    - by R J.
    I am capturing image using canvas and i want to store a captured image in MySQL Database using Javascript. This is my code: <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, maximum-scale=1.0"> <style> body {width: 100%;} canvas {display: none;} </style> <title>Instant Camera - Remote</title> <script> var video, canvas, msg; var load = function () { video = document.getElementById('video'); canvas = document.getElementById('canvas'); msg = document.getElementById('error'); if( navigator.getUserMedia ) { video.onclick = function () { var context = canvas.getContext("2d"); context.drawImage(video, 0, 0, 240, 320); var image1 = canvas.toDataURL("image/png"); document.write('<img src="' + image1 + '" />'); }; } else { msg.innerHTML = "Native web camera not supported :("; } }; window.addEventListener('DOMContentLoaded', load, false); </script> </head> <body> <video id="video" width="240" height="320" autoplay> </video> <p id="error">Click on the video to send a snapshot to the receiving screen</p> <canvas id="canvas" width="240" height="320"> </canvas> </body> </html>

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  • Page does update with details from the database after i hit a button

    - by swathi
    I have a code and the way it should work is,when they click on NEW CUSTOMER,it takes them to test1.php where in they enter the details and they hit submit.it saves all the details in properly in the database and when i go back and hit REFRESH ,it should come up with the customer details which they had entered in previously. But what happens is, when i click on the REFRESH,it refreshes the same old page which is empty.I wanted to find out where am i missing the logic.Thanks in advance. The sample code would be <tr> <td class="tdvisitbig" colspan="5">THIS IS A TEST</td> </tr> <tr> <td class='tdvisitbig' colspan="5"><input type="button" onClick="openVisit('test1.php?id=<?=$key?>&name=<?=$name?>');return false;" value="NEW CUSTOMER" class="submit">&nbsp;<input type="button" value="REFRESH" name="add_xyz" class="submit" onClick="document.add.target='_self';document.add.action='test3.php?redirect=visit&section=test page';document.add.submit();"></td> </tr> <? $q = "SELECT address,customernum,status FROM customer WHERE name='$name' ORDER BY customernum"; $r = mysql_query( $q , $Link ); while( $rw = mysql_fetch_assoc( $r ) ) { extract( $rw ); ?> <tr> <? } ?>

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  • How to compare date from database using C#?

    - by user1490374
    I would like to compare the date selected from the database (every entry in EndDate) and compare them with today date. Is there any way to do this programmatically? Like extracting the dates and comparing them individually? I need this because I need to update the status for the table. string username; username = HttpContext.Current.User.Identity.Name; string date = DateTime.Now.ToString("MM/dd/yyyy"); txtDate.Text = date; SqlConnection conn1 = new SqlConnection("Data Source=mydatasource\\sqlexpress;" + "Initial Catalog = Suite2; Integrated Security =SSPI"); SqlDataAdapter adapter; string end; end = "SELECT EndDate FROM Table_Message WHERE username = '" + username + "'"; adapter = new SqlDataAdapter(end, conn1); conn1.Open(); DataSet ds = new DataSet(); adapter.Fill(ds); //Execute the sql command GridView2.DataSource = ds; GridView2.DataBind(); conn1.Close();

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  • How to get my list of rows from database to show while using Zend-Paginator

    - by Matto
    I'm fairly new to the world of Zend-Framework, and have taken over a site that is in zend-framework. There is a bug on one of the pages right now and I can not figure it out. I think it has something to do with Zend Paginator, but not sure. This is the code in the controller for the section I am having a problem with: $currentPage = $this->_getParam('page'); $numWebsitesFullOnline = $websites->getWebsitesFullOnline(); $select = $websites->select(); $select->setIntegrityCheck(false); $select->from(array('w' => 'websites'), array('id', 'online', 'kw_adjective', 'kw_name', 'kw_location', 'url', 'email', 'address', 'ftp_server', 'ftp_username', 'ftp_password', 'ftp_folder', 'phone_number', 'indexed', 'youtube_position', 'twitter_user', 'facebook_id', 'video_made', 'image1_id', 'image2_id', 'image3_id', 'bg_color', 'dark_color', 'light_color', 'links_color', 'text_color', 'google_account', 'ganalytics', 'gmaps_status', 'google_position', 'gmap_position', 'hp1', 'hp2', 'hp3', 'hp4', 'hp5', 'hp6', 'hp7', 'hp8', 'hp9', 'hp10', 'about1_id', 'about2_id', 'about3_id', 'tip1_id', 'tip2_id', 'tip3_id', 'contact_texts_id', 'quote_texts_id', 'demographics_id')) ->join(array('d' => 'demographics'), 'w.demographics_id = d.id', array('total_population')) ->order(array('total_population DESC', 'kw_location')); $paginator = new Zend_Paginator(new Zend_Paginator_Adapter_DbSelect($select)); $paginator->setItemCountPerPage(50); $paginator->setCurrentPageNumber($currentPage); $paginator->setPageRange(($paginator->getTotalItemCount() / 50) + 1); $this->view->paginator = $paginator; $numWebsitesOnline = $websites->getWebsitesOnline(); On the php page I have this code to call the websites that are in the database to a list: <p class="red"> Websites online: <?php echo $this->numOnline; ?> </p> <?php print_r(count($this->paginator)); ?> <?php if(count($this->paginator)): ?> <table class="table-list"> <?php foreach($this->paginator as $item): ?> <tr> <?php if($this->userIsAllowedAction('websites', 'reload')): ?> <td class="center noborder w30"> <img class="hidden" src="<?php echo $this->baseUrl() . '/images/loader.gif' ?>" alt="Loading..."/><a class="reload" title="refresh" href="<?php echo $this->baseUrl(); ?>/utils/ui/refresh-website.php" rel="<?php echo urlencode('http://' . $item['url'] . '/install.php'); ?>,<?php echo urlencode($item['ftp_server']); ?>,<?php echo $item['ftp_username']; ?>,<?php echo $item['ftp_password']; ?>,<?php echo $item['ftp_folder']; ?>,<?php echo $this->baseUrl(); ?>,<?php echo $item['id']; ?>"><img src="<?php echo $this->baseUrl(); ?>/images/icon-refresh.png" alt="Refresh"/></a> </td> <?php endif; ?> <td class="center noborder w30"> <?php if($this->userIsAllowedAction('websites', 'edit')): ?><a title="Edit" href="<?php echo $this->url(array('controller' => 'websites', 'action' => 'edit', 'id' => $item['id'])); ?>"><img src="<?php echo $this->baseUrl(); ?>/images/icon-edit.png" alt="Edit"/></a><?php endif; ?> </td> <td class="center noborder w30"> <?php if($this->userIsAllowedAction('websites', 'remove')): ?><a title="Remove" href="<?php echo $this->url(array('controller' => 'websites', 'action' => 'remove', 'id' => $item['id'])); ?>"><img src="<?php echo $this->baseUrl(); ?>/images/icon-delete.png" alt="Remove"/></a><?php endif; ?> </td> <td> <?php if($item['online']): ?> <span class="hidden"><?php echo trim($this->escape($item['kw_adjective'] . $item['kw_name'])); ?></span><a class="goto-website" href="http://<?php echo $item['url']; ?>" target="_blank"><?php echo $this->escape($item['kw_location']); ?></a> <?php else: ?> <?php echo $this->escape($item['kw_location']); ?> <?php endif; ?> </td> <td class="center population"> <?php if($item['total_population'] >= 0) echo $item['total_population']; ?> </td> <td class="center"> <?php if(!empty($item['url'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['email'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['demographics_id']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['hp1'] && $item['hp2'] && $item['hp3'] && $item['hp4'] && $item['hp5'] && $item['hp6'] && $item['hp7'] && $item['hp8'] && $item['hp9'] && $item['hp10'] && $item['about1_id'] && $item['about2_id'] && $item['about3_id'] && $item['tip1_id'] && $item['tip2_id'] && $item['tip3_id'] && $item['contact_texts_id'] && $item['quote_texts_id']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(file_exists($_SERVER['DOCUMENT_ROOT'] . $this->baseUrl() . Zend_Registry::get('assets_base_path') . '/' . $item['id'] . '/header.jpg')): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(($item['bg_color'] != '' && $item['bg_color'] != 'e6e6e6') || ($item['dark_color'] != '' && $item['dark_color'] != '003e75') || ($item['light_color'] != '' && $item['light_color'] != '3073ad') || ($item['links_color'] != '' && $item['links_color'] != '255593') || ($item['text_color'] != '' && $item['text_color'] != '4f4f4f')): ?> <img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/> <?php endif; ?> </td> <td class="center"> <?php if($item['image1_id'] && $item['image2_id'] && $item['image3_id']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['twitter_user'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['facebook_id'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['phone_number'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['google_account']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['video_made']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['youtube_position']) { echo $item['youtube_position']; }; ?> </td> <td class="center"> <?php if(!empty($item['address'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['gmaps_status'] == 1): ?><img src="<?php echo $this->baseUrl(); ?>/images/icon-gmapspending.png" alt="Pending"/><?php elseif($item['gmaps_status'] == 2): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if(!empty($item['ganalytics'])): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark.png" alt="DONE"/><?php endif; ?> </td> <td class="center"> <?php if($item['online']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark_red.png" alt="Online!"/><?php endif; ?> </td> <td class="center"> <?php if($item['indexed']): ?><img src="<?php echo $this->baseUrl(); ?>/images/check_mark_red.png" alt="Online!"/><?php endif; ?> </td> <td class="center"> <?php if($item['gmap_position']) { echo $item['gmap_position']; }; ?> </td> <td class="center"> <?php if($item['google_position']) { echo $item['google_position']; }; ?> </td> </tr> <?php endforeach; ?> </table> <?php endif; ?> The print_r(count($this-paginator)); line is returning "0", and the $this-numOnline; line is returning 1. So it sees that there is one row in the websites table of the database, but it is not returning anything to page and listing out the rows in the websites table. Not sure if this is the paginator that is causing this cause it is returning 0 or something else I don't know about.

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  • php form-input validation

    - by fusion
    i have a html page in which i enter data which then submits and inserts in a database on a php page. how would i validate in php that the data received is not a duplicate of the data in the database? any help appreciated.

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  • mysqldump table names prefix

    - by Bogdan Gusiev
    I have two mysql databases that have almost the same structure and representing the data of the same web app but one of them represents the current version and second one was made long time ago. How can I create the database with both dumps inside but with old_ prefix for tables from the first and new_ prefix for tables from the second database? Is there any mysqldump options to setup the prefix or other solution?

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