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  • Javascript Regex: Testing string for intelligent query

    - by Shyam
    Hi, I have a string that holds user input. This string can contain various types of data, like: a six digit id a zipcode that contains out of 4 digits and two alphanumeric characters a name (characters only) As I am using this string to search through a database, the query type is determined on the type of search, which i want to handle serverside using JavaScript (yes, I am using JavaScript serverside). Searching on StackOverflow, brought me some interesting information, like the .test-method, which seems perfect for my needs. The test-method returns either true or false based on the evaluation on the string using a regex object. I am using this page as a reference: http://www.javascriptkit.com/jsref/regexp.shtml So I am trying to determine the zipcode, by using the following very noobish regex. var r = /[A-Za-z]{2,2}/ As far I can understand, this should limit the amount of occurrences of alphanumeric characters to a maximum of two. See beneath the output of my JavaScript console. > var r = /[A-Za-z]{2,2}/ > var x = "2233AL" > r.test(x) true > var x = "2233A" > r.test(x) false > var x = "2233ALL" > r.test(x) true /* i want this to be false */ > A little help would be really appreciated!

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  • mysql with 3 group by and sum

    - by cyberfly
    Hi all I have this data in my table (tb_cash_transaction) I want to group the TYPE column, CURRENCY_ID column and AMOUNT column so it will become like below: **Currency** **Cash IN** **Cash OUT** **Balance** 14 40000 30000 10000 15 50000 40000 10000 Rule : 1.Group by currency 2.Then find the sum of cash in for that currency 3.Find the sum of cash out for that currency 4.Get the balance (sum cash in - sum cash out) How to achieve it using mysql? I try using group by but cannot get the desired output. Thanks in advance

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  • Django ForeignKey _set on an inherited model

    - by neolaser
    I have two models Category and Entry. There is another model ExtEntry that inherits from Entry class Category(models.Model): title = models.CharField('title', max_length=255) description = models.TextField('description', blank=True) ... class Entry(models.Model): title = models.CharField('title', max_length=255) categories = models.ManyToManyField(Category) ... class ExtEntry(Entry): groups= models.CharField('title', max_length=255) value= models.CharField('title', max_length=255) ... I am able to use the Category.entry_set but I want to be able to do Category.blogentry_set but it is not available. If this is not available,then I need another method to get all ExtEntryrelated to one particular Category Thanks

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  • mysql get last auto increment value

    - by Mick
    Hi I have a field in mySql table called jobnumber which auto increments with each new entry. What I want to do is when a user views my form, get the value of the next 'jobnumber' . But I want to do this before any entry is made to the table. IE so when a user looks at a form it will display something like 'this is job number 6954' I have tried $rr = mysql_insert_id() but this only work after I have made an entry Can anyone help please thanks

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  • 3-clique counting in a graph

    - by Legend
    I am operating on a (not so) large graph having about 380K edges. I wrote a program to count the number of 3-cliques in the graph. A quick example: List of edges: A - B B - C C - A C - D List of cliques: A - B - C A 3-clique is nothing but a triangle in a graph. Currently, I am doing this using PHP+MySQL. As expected, it is not fast enough. Is there a way to do this in pure MySQL? (perhaps a way to insert all 3-cliques into a table?)

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  • cakephp: how to make NOW() work in search condition ?

    - by kaklon
    I'm trying to get all records with date greater then now. I tried this but it doeasnt work: $all_dates = $this->TourDate->find('all', array('conditions' => array('TourDate.date >=' => 'NOW()'), 'order' => array('TourDate.date ASC'))); If I replace NOW() with the current date it works. Why's that?

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  • Is this the best way to make an API request using PHP CURL?

    - by Abs
    Hello all, I have a site that has a simple API which can be used via http. I wish to make use of the API and submit data about 1000-1500 times at one time. Here is their API: http://api.jum.name/ I have constructed the URL to make a submission but now I am wondering what is the best way to make these 1000-1500 API GET requests? Here is the PHP CURL implementation I was thinking of: $add = 'http://www.mysite.com/3rdparty/API/api.php?fn=post&username=test&password=tester&url=http://google.com&category=21&title=story a&content=content text&tags=Season,news'; curl_setopt ($ch, CURLOPT_URL, "$add"); curl_setopt ($ch, CURLOPT_POST, 0); curl_setopt ($ch, CURLOPT_COOKIEFILE, 'files/cookie.txt'); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 0); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); $postdata = curl_exec ($ch); Shall I close the CURL connection every time I make a submission? Can I re-write the above in a better way that will make these 1000-1500 submissions quicker? Thanks all

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  • MySQL temp table issue

    - by AmyD
    Hi folks! I'm trying to use temp tables to speed up my MySQL 4.1.22-standard database and what seems like a simple operation is causing me all kinds of issues. My code is below.... CREATE TEMPORARY TABLE nonDerivativeTransaction_temp (accession_number varchar(30), transactionDateValue date)) TYPE=HEAP; INSERT INTO nonDerivativeTransaction_temp VALUES( SELECT accession_number, transactionDateValue FROM nonDerivativeTransaction WHERE transactionDateValue = "2010-06-15"); SELECT * FROM nonDerivativeTransaction_temp; The original table (nonDerivativeTransaction) has two fields, accession_number (varchar(30)) and transactionDateValue (date). Apparently I am getting an issue with the first two statements but I can't seem to nail down what it is. Any help would be appreciated. Amy D.

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  • Help Me With This MS-Access Query

    - by yae
    I have 2 tables: "products" and "pieces" PRODUCTS idProd product price PIECES id idProdMain idProdChild quant idProdMain and idProdChild are related with the table: "products". Other considerations is that 1 product can have some pieces and 1 product can be a piece. Price product equal a sum of quantity * price of all their pieces. "Products" table contains all products (p EXAMPLE: TABLE PRODUCTS (idProd - product - price) 1 - Computer - 300€ 2 - Hard Disk - 100€ 3 - Memory - 50€ 4 - Main Board - 100€ 5 - Software - 50€ 6 - CDroms 100 un. - 30€ TABLE PIECES (id - idProdMain - idProdChild - Quant.) 1 - 1 - 2 - 1 2 - 1 - 3 - 2 3 - 1 - 4 - 1 WHAT I NEED? I need update the price of the main product when the price of the product child (piece) is changed. Following the previous example, if I change the price of this product "memory" (is a piece too) to 60€, then product "Computer" will must change his price to 320€ How I can do it using queries? Already I have tried this to obtain the price of the main product, but not runs. This query not returns any value: SELECT Sum(products.price*pieces.quant) AS Expr1 FROM products LEFT JOIN pieces ON (products.idProd = pieces.idProdChild) AND (products.idProd = pieces.idProdChild) AND (products.idProd = pieces.idProdMain) WHERE (((pieces.idProdMain)=5)); MORE INFO The table "products" contains all the products to sell that it is in the shop. The table "pieces" is to take a control of the compound products. To know those who are the products children. For example of compound product: computers. This product is composed by other products (motherboard, hard disk, memory, cpu, etc.)

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  • A SELECT statement for Mysql

    - by Hossein
    I have this table: id,bookmarkID,tagID I want to fetch the top N bookmarkIDs for a given list of tags. Does anyone know a very fast solution for this? the table is quite large(12 million records) I am using MySql

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  • which is better, creating a view or a new table?

    - by Carson
    I have some demanding mysql queries that are needed to grap same datasets from several mysql tables. I am thinking of creating a table or view to gather all demanding columns from other tables, so as to increase performance. If I create that table, I may need to do extra insert / update / delete operation each time other tables updated. if I create view, I am worrying if the performance can be greatly improved. Because data from other tables are changing very frequently. Most likely, the view may need to be created first everytime before selecting it. Any ideas? e.g. how to cache? other extra measures I can do?

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  • I've built a Windows service as "Any CPU". Why does it run in 32-bit mode on my 64 bit machine?

    - by Mark
    I've built a Windows service as "Any CPU". However, when I run it on my 64 bit machine it runs in 32 bit. How can I fix it? I'm using .NET and C#, and my operating system is Windows 2008 R2. If I build it in x64 it correctly loads in 64 bit mode. However, "Any Cpu" -- which is what I want -- loads in 32 bit, even though the machine it's running on perfectly supports 64 bit. Thanks for any help.

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  • Selecting More Than 1 Table in A Single Query

    - by Kamran
    I have 5 Tables in MS Access as Logs [Title, ID, Date, Author] Tape [Title, ID, Date, Author] Maps [Title, ID, Date, Author] VCDs [Title, ID, Date, Author] Book [Title, ID, Date, Author] I tried my level best through this code SELECT Logs.[Author], Tape.[Author], Maps.[Author], VCDs.[Author], Book.[Author] FROM Logs , Tape , Maps , VCDs, Book WHERE ((([Author] & " " & [Author] & " " & [Author] & " " & [Author]& " " & [Author]) Like "*" & [Type the Title or Any Part of the Title and Press Ok] & "*")); I want to select all of these fields in a single query. Suppose there is Adam as author of works in all tables. So when i put Adam in search box it should result from all tables. I know this can be done by having single table or renaming fields names but that's not required. Please help.

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  • Beginner having difficulty with SQL query

    - by Vulcanizer
    Hi, I've been studying SQL for 2 weeks now and I'm preparing for an SQL test. Anyway I'm trying to do this question: For the table: 1 create table data { 2 id int, 3 n1 int not null, 4 n2 int not null, 5 n3 int not null, 6 n4 int not null, 7 primary key (id) 8 } I need to return the relation with tuples (n1, n2, n3) where all the corresponding values for n4 are 0. The problem asks me to solve it WITHOUT using subqueries(nested selects/views) It also gives me an example table and the expected output from my query: 01 insert into data (id, n1, n2, n3, n4) 02 values (1, 2,4,7,0), 03 (2, 2,4,7,0), 04 (3, 3,6,9,8), 05 (4, 1,1,2,1), 06 (5, 1,1,2,0), 07 (6, 1,1,2,0), 08 (7, 5,3,8,0), 09 (8, 5,3,8,0), 10 (9, 5,3,8,0); expects (2,4,7) (5,3,8) and not (1,1,2) since that has a 1 in n4 in one of the cases. The best I could come up with was: 1 SELECT DISTINCT n1, n2, n3 2 FROM data a, data b 3 WHERE a.ID <> b.ID 4 AND a.n1 = b.n1 5 AND a.n2 = b.n2 6 AND a.n3 = b.n3 7 AND a.n4 = b.n4 8 AND a.n4 = 0 but I found out that also prints (1,1,2) since in the example (1,1,2,0) happens twice from IDs 5 and 6. Any suggestions would be really appreciated.

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  • SQL Server GROUP BY troubles!

    - by Lucas311
    I'm getting a frustrating error in one of my SQL Server 2008 queries. It parses fine, but crashes when I try to execute. The error I get is the following: Msg 8120, Level 16, State 1, Line 4 Column 'customertraffic_return.company' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause. SELECT * FROM (SELECT ctr.sp_id AS spid, Substring(ctr.company, 1, 20) AS company, cci.email_address AS tech_email, CASE WHEN rating IS NULL THEN 'unknown' ELSE rating END AS rating FROM customer_contactinfo cci INNER JOIN customertraffic_return ctr ON ctr.sp_id = cci.sp_id WHERE cci.email_address <> '' AND cci.email_address NOT LIKE '%hotmail%' AND cci.email_address IS NOT NULL AND ( region LIKE 'Europe%' OR region LIKE 'Asia%' ) AND SERVICE IN ( '1', '2' ) AND ( rating IN ( 'Premiere', 'Standard', 'unknown' ) OR rating IS NULL ) AND msgcount >= 5000 GROUP BY ctr.sp_id, cci.email_address) AS a WHERE spid NOT IN (SELECT spid FROM customer_exclude) GROUP BY spid, tech_email

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  • Working by group by for grouping data into string format

    - by Shantanu Gupta
    I have a table that contains some data given below. It uses a tree like structure i.e. Department SubD1, SubD2 ..... PreSubD1, PreSubD1... PreSubD2, PreSubD2... pk_map_id preferences ImmediateParent Department_Id -------------------- -------------------- -------------------- -------------------- 20 14 5 1 21 15 5 1 22 16 6 1 23 9 4 2 24 4 3 2 25 24 20 2 26 25 20 2 27 23 13 2 I want to group my records on behalf of department then immediate parent then preferences each seperated by ',' i.e. department Immediate Parent preferences 1 5,6 14,15,16 2 4,3,20,13 9,4,24,25,23 and this table also Immediate parent preferences 5 14,15 6 16 4 9 3 4 20 24,25 13 13 In actual scenario all these are my ids which are to be replaced by their string fields. I am using sql server 2k5

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  • Hibernate Criteria API: get n random rows

    - by hadrien
    I can't figure out how to fetch n random rows from a criteria instance: Criteria criteria = session.createCriteria(Table.class); criteria.add(Restrictions.eq('fieldVariable', anyValue)); ... Then what? I can't find any doc with Criteria API Does it mean I should use HQL instead? Thanx! EDIT: I get the number of rows by: int max = criteria.setProjecxtion(Projections.rowCount()).uniqueResult(); How do I fetch n random rows with indexes between 0 and max? Thx again!

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  • Would you allow this type of query?

    - by user564577
    I'm exploring using an ORM tool in our development shop, and in particular Entity Framework 4.0. Since we work with VERY large databases, I'm a bit concerned about the query's it generates. Doing something simple like getting clients with an address in a state looks like below. As a database developer or admin would you allow this? Is it as bad as it looks? Assume every join is on a clustered index. SELECT [Project2].[ClientKey] AS [ClientKey], [Project2].[FirstName] AS [FirstName], [Project2].[LastName] AS [LastName], [Project2].[IsEnabled] AS [IsEnabled], [Project2].[ChangeUser] AS [ChangeUser], [Project2].[ChangeDate] AS [ChangeDate], [Project2].[C1] AS [C1], [Project2].[AddressKey] AS [AddressKey], [Project2].[ClientKey1] AS [ClientKey1], [Project2].[AddressTypeCode] AS [AddressTypeCode], [Project2].[PrimaryAddress] AS [PrimaryAddress], [Project2].[AddressLine1] AS [AddressLine1], [Project2].[AddressLine2] AS [AddressLine2], [Project2].[City] AS [City], [Project2].[State] AS [State], [Project2].[ZIP] AS [ZIP] FROM ( SELECT [Distinct1].[ClientKey] AS [ClientKey], [Distinct1].[FirstName] AS [FirstName], [Distinct1].[LastName] AS [LastName], [Distinct1].[IsEnabled] AS [IsEnabled], [Distinct1].[ChangeUser] AS [ChangeUser], [Distinct1].[ChangeDate] AS [ChangeDate], [Extent3].[AddressKey] AS [AddressKey], [Extent3].[ClientKey] AS [ClientKey1], [Extent3].[AddressTypeCode] AS [AddressTypeCode], [Extent3].[PrimaryAddress] AS [PrimaryAddress], [Extent3].[AddressLine1] AS [AddressLine1], [Extent3].[AddressLine2] AS [AddressLine2], [Extent3].[City] AS [City], [Extent3].[State] AS [State], [Extent3].[ZIP] AS [ZIP], CASE WHEN ([Extent3].[AddressKey] IS NULL) THEN CAST(NULL AS int) ELSE 1 END AS [C1] FROM (SELECT DISTINCT [Extent1].[ClientKey] AS [ClientKey], [Extent1].[FirstName] AS [FirstName], [Extent1].[LastName] AS [LastName], [Extent1].[IsEnabled] AS [IsEnabled], [Extent1].[ChangeUser] AS [ChangeUser], [Extent1].[ChangeDate] AS [ChangeDate] FROM [Common].[Clients] AS [Extent1] INNER JOIN [Common].[ClientAddresses] AS [Extent2] ON [Extent1].[ClientKey] = [Extent2].[ClientKey] WHERE (( CAST(CHARINDEX(UPPER('D'), UPPER([Extent1].[LastName])) AS int)) > 0) AND ([Extent1].[IsEnabled] = 1) AND ([Extent2].[City] IS NOT NULL) AND ((UPPER([Extent2].[City])) = (UPPER('Colorado Springs'))) ) AS [Distinct1] LEFT OUTER JOIN [Common].[ClientAddresses] AS [Extent3] ON [Distinct1].[ClientKey] = [Extent3].[ClientKey] ) AS [Project2] ORDER BY [Project2].[ClientKey] ASC, [Project2].[FirstName] ASC, [Project2].[LastName] ASC, [Project2].[IsEnabled] ASC, [Project2].[ChangeUser] ASC, [Project2].[ChangeDate] ASC, [Project2].[C1] ASC

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